The given statement "An Alpha of 0.95 means that more recent observations in a time series are given more weight than earlier observations" is true.
The given AR2 model output is as follows: Constant Coefficients 0.006503139 1.089593514 -0.09525277 Lag 1 Lag 2
Given that Lag 1 and Lag 2 are 1.0920 and 1.0910, respectively.
To find the predicted value of the y-variable, substitute the values of the coefficients and the lags in the following formula:
y-variable = Constant + Coefficient1 * Lag1 + Coefficient2 * Lag2
The predicted value of the y-variable is closest to 1.08927.
In a simple exponential smoothing (SES) model, the parameter α or Alpha is called the smoothing or decay factor.
An Alpha of 0.95 means that more recent observations in a time series are given more weight than earlier observations.
Therefore, This statement is True.
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Can someone please help me with this math problem it is so confusing? The math problem is located in the picture, Thanks!
Domain:
Range:
The domain is the set of all x-values (or inputs) used by the function. In a graph like this, you want to see how the graph lines up with the x-axis.
As an interval, the domain is [-4,-1], as shown on the domain graph.
(Remember to write intervals from lesser-to-greater.)
The range is the set of all y-values (or outputs) used by the function. In a graph like this, you want to see how the graph lines up with the y-axis.
As an interval, the range is [-4,-2].
(Again, remember to write intervals from lesser-to-greater.)
Given parallelogram L M N O below, LP = 81 If PN = -7x-3 solve for x
Answer:-12x
Step-by-step explanation:
just trust me on this
2) What is 2/5 of 15 ?
V
=15
pa help po
advance thx.
Answer:
2/5 of 15 is 6
Step-by-step explanation:
Multiply 2 and 15
2 × 15 = 30
Divide 30 by 5
30 ÷ 5 = 6
This equation shows a way to find a fraction equivalent to 2032
2
0
3
2
.
Enter numbers below to correctly complete the equation.
Answer:
Given Below.Explanation:
\(\sf \dfrac{20}{32} = \dfrac{20}{32} \ \div \ 1 = \dfrac{20\div 4}{32 \div 4} = \dfrac{5}{8}\)
Follow the sequence. and divide the multiply the following fraction.
32 ÷ ? = 8? = 4=======
20 ÷ 4 = 5Answer:
\(\sf \dfrac{20}{32}=\dfrac{20}{32} \div 1=\dfrac{20 \div 4}{32 \div 4}=\dfrac{5}{8}\)
Step-by-step explanation:
When reducing fractions to their simplest equivalent, we need to divide the numerator and denominator by their highest common factor.
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 32, 1, 2, 4, 8, 16, 32
Therefore, the highest common factor is 4.
\(\sf \dfrac{20}{32}=\dfrac{20}{32} \div 1=\dfrac{20 \div 4}{32 \div 4}=\dfrac{5}{8}\)
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1. 50μm2. Convert this to square meters.
Converting 1. 50μm² to square meters gives 1. 5 × 10 ^-11
What is conversion of units?Conversion of units is defined as the conversion of different units of measurement for the same quantity, mostly through multiplicative conversion factors.
From the information given, we are to convert micrometers to square meters
Note that:
1 micrometer ( μm²) = 10^-12m²
Given 1. 50μm² = xm²
cross multiply
x = 1. 50 × 10^-12
x = 1. 50 × 10^-12
x = 1. 50 × 10^-12
x = 1. 5 × 10 ^-11 square meters
Thus, converting 1. 50μm² to square meters gives 1. 5 × 10 ^-11
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A student makes the statement that air is not matter. He argues that you cannot see air and thus, it does not have volume or mass. Evaluate the student's claim. Justify why the student's claim is true or false.
He is false, because one of the first laws of the scientific method states that everything has mass, and volume, being made up of matter.
Hope this helps.
You want to plant a flower garden in your yard so that you can make a beautiful bouquet to put on the alter at church for easter sunday services. there are two types of flowers that you are going to be planting. you will be planting some tulips and daffodils. at the store tulips come in packs of 4 and daffodils come in packs of 6. what is the least amount of packs of daffodils and tulips you would need to buy to have the same amount of each?
The least amount of packs of daffodils and tulips you would need to buy to have the same amount of each = 20.5 $
What is Total Amount?
Total refers to an entire or complete amount, and the verb "to total" means to combine two numbers or to destroy anything. In mathematics, you add integers to get the total; the outcome is the total. The result of adding 8 and 8 is 16.
Tulips come in packs of 4
And daffodils come in packs of 6.
To find Equal number of tulips & Daffodils we need to find LCM of 4 & 6
4 = 2 * 2
6 = 2 * 3
LCM = 2 * 2 * 3 = 12
12 Flower of each type
Packets of tulip = 12/4 = 3
Packets of Daffodils = 12/6 = 2
Total Packs = 3 + 2 = 5
The smallest number of packets of tulips and daffodils to purchase to get the same quantity of each is 5.
Each pack of tulips costs $3.50 and each pack of daffodils cost $5.75.
=> 3 * 3.5 + 2* 5.75
= 10.5 + 11.5
= 22 $
The sales tax is 6.5%.
=> Sales tax = (6.5/100)22 = 1.43$
Total price paid = 22 + 1.43 = 23.43 $
Discount coupon for $2.75 off before tax.
=> 22 - 2.75 = 19.25 $
Tax = (6.5/100)19.25 = 1.25 $
Total amount = 19.25 + 1.25 = 20.5 $
Money saved = 23.43 - 20.5 = 2.93 $
For detailed question see attachment
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help plz literally begging
An
i get scared to take screenshotes i feel like i wouldm get hacked
Step-by-step explanation:
11 POINTS! GEOMETRY!! Find the area of the composite function and explain how you broke the shape into pieces to find the area.
Answer:
370 mm²
Step-by-step explanation:
The area of this figure can be calculated by taking the whole figure as a full rectangle, and consider the part that is cut out from the middle of the shape as another rectangle.
Find the area of the cut-out part and subtract from the area of the full rectangular shape to get the area of the composite figure.
=>Area of full rectangular shape:
Length = 30 mm
Width = 15 mm
Area = L * B = 30*15 = 450 mm²
=>Area of the cut-out Rectangle part:
Length = 10 mm
Width = 8 mm
Area = 10*8 = 80 mm²
=>Area of composite figure = 450 mm² - 80 mm² = 370 mm²
If f(x)=16 then f(2)=
The value of f(2) when f(x) = 16 is 16.
When we have a function f(x) = 16, it means that the output (or the value of the function) is always 16, regardless of the input x. In other words, for any value of x, the function f(x) will always give us 16 as the result.
Therefore, when we evaluate f(2), it means we are substituting the value x = 2 into the function. Regardless of the specific value of x, the function f(x) will always yield 16. So, when we substitute x = 2 into the function, we get f(2) = 16.
In summary, when f(x) = 16, the value of f(2) is 16. This is because the function f(x) always outputs 16, regardless of the value of x.
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08 Multiple Choice
A figure is rotated 90° clockwise, then 270° counterclockwise. Which single rotation is equivalent to this?
Answer:
180 degrees.
Step-by-step explanation:
If you start at 0 degrees and move 90 degrees clockwise, you subtract (clockwise is subtracting) 90 degrees to 0 degrees which is 90 degrees. Moving it 270 degrees counterclockwise means that you are adding 270 degrees. -90+270=180 degrees.
Ashley was given $15 for mowing the
lawn. She now has $33. How much
money did she start with?
Answer:
$18
Step-by-step explanation:
x + 15 = 33
x = 33-15
x = 18
Please help me! thank you
Suppose an object is thrown upward with initial velocity of 48 feet per second from a high of 120 feet. The height of the object t seconds after it is thrown is given by h(t)=-16t^2+48t+120. Find the average velocity from t=2 to t=4.
Type your answer as a number with no units.
The average velocity from t = 2s to t = 4s would be - 48 ft/s.
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.
Given is that an object is thrown upward with initial velocity of 48 feet per second from a high of 120 feet. The height of the object t seconds after it is thrown is given by h(t) = - 16t² + 48t + 120.
Average velocity
Average rate of change of velocity with time is called average velocity. Mathematically -
v{avg.} = Δx/Δt .... Eq { 1 }
Δx = x(4) - x(2)
Δx = - 16(4)² + 48(4) + 120 - {- 16(2)² + 48(2) + 120}
Δx = - 96
Δt = 4 - 2 = 2
So -
v{avg.} = Δx/Δt = -96/2 = - 48 ft/s
Therefore, the average velocity from t = 2s to t = 4s would be - 48 ft/s.
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6 - 3x = -6 PLEASE ANSWER FAST I NEED HELP!!!
Answer:
4
Step-by-step explanation:
Subtract 6 to both sides so you can get -12. Next divide -3 from x and -12. Finally your answer should be positive 4. Mark me brainily please if it is correct
evaluate the integral ∫ ( 2 x 3 ) ( x 2 3 x 6 ) 5 d x by making the substitution u = x 2 3 x 6 .
Substituting u = x^(2/3x^6) in the integral ∫ (2x^3)(x^2/3x^6)^5 dx and arriving at the solution 3∫(x^3)(u^5) du.
To evaluate the integral ∫ (2x^3)(x^2/3x^6)^5 dx, we can simplify the expression by making the substitution u = x^(2/3x^6). This substitution allows us to transform the integral into a simpler form, making it easier to evaluate.
Let's make the substitution u = x^(2/3x^6). Taking the derivative of both sides with respect to x gives us du = (2/3x^6)(x^(-1/3)) dx. Simplifying this equation, we have du = (2/3)dx.
Now, we can rewrite the original integral in terms of u as follows:
∫ (2x^3)(x^(2/3x^6))^5 dx = ∫ (2x^3)(u^5) dx.
Using our substitution, we can also rewrite x^3dx as (3/2)du. Substituting these into the integral, we have:
∫ (2x^3)(x^(2/3x^6))^5 dx = ∫ (2x^3)(u^5) dx = 2∫(x^3)(u^5)dx = 2∫(x^3)(u^5)(3/2)du.
Simplifying further, we have:
∫ (2x^3)(x^(2/3x^6))^5 dx = 2(3/2) ∫ (x^3)(u^5) du = 3∫(x^3)(u^5) du.
Now, we can evaluate this integral with respect to u, which gives us a simpler expression to work with. Once we find the antiderivative of (x^3)(u^5) with respect to u, we can substitute u back in terms of x to obtain the final result.
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Complete question:
evaluate the integral ∫ (2x^3)(x^2/3x^6)^5 dx by making the substitution u = x^(2/3x^6)
Write an infinite geometric series that converges to 3 . Use the formula to evaluate the series.
The infinite geometric series that converges to 3 is 6 - 6 + 6 - 6 + 6 - ..., and its sum is 3.To write an infinite geometric series that converges to 3, we can use the formula for the sum of an infinite geometric series:
S = a / (1 - r)
where S is the sum of the series, a is the first term, and r is the common ratio.
Since we want the series to converge to 3, we can set S = 3. Let's choose a value for a, for example, a = 6.
Now, we can rearrange the formula to solve for r:
3 = 6 / (1 - r)
Multiplying both sides by (1 - r), we get:
3(1 - r) = 6
Expanding the left side:
3 - 3r = 6
Subtracting 3 from both sides:
-3r = 3
Dividing both sides by -3, we find:
r = -1
So, the infinite geometric series that converges to 3 is:
6 - 6 + 6 - 6 + 6 - ...
To evaluate the series, we can use the formula for the sum of an infinite geometric series:
S = a / (1 - r)
Plugging in the values, we get:
S = 6 / (1 - (-1))
= 6 / (1 + 1)
= 6 / 2
= 3
Therefore, the infinite geometric series that converges to 3 is 6 - 6 + 6 - 6 + 6 - ..., and its sum is 3.
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What are range, index of qualitative variation (IQV), interquartile range (IQR), standard deviation, and variance
Answer:
To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
Step-by-step explanation:
Question 8. Solve each recurrence relation. Show your work. (a) an=an−2+4;a1=3;a2=5 (Hint: You will need two different answers-one for when n is even and one for when n is odd.) (b) an=2an−1+1;a1=1
Answer:
The solution to the recurrence relation is given by an = 2^(n+1) - 1.
Step-by-step explanation:
(a) To solve the recurrence relation an = an-2 + 4, with initial conditions a1 = 3 and a2 = 5, we'll consider two cases: one for when n is even and one for when n is odd.
For n even:
Substituting n = 2k (where k is a positive integer) into the recurrence relation, we get:
a2k = a2k-2 + 4
Now let's write out a few terms to observe the pattern:
a2 = a0 + 4
a4 = a2 + 4
a6 = a4 + 4
...
We notice that a2k = a0 + 4k for even values of k.
Using the initial condition a2 = 5, we can find a0:
a2 = a0 + 4(1)
5 = a0 + 4
a0 = 1
Therefore, for even values of n, the solution is given by an = 1 + 4k.
For n odd:
Substituting n = 2k + 1 (where k is a non-negative integer) into the recurrence relation, we get:
a2k+1 = a2k-1 + 4
Again, let's write out a few terms to observe the pattern:
a3 = a1 + 4
a5 = a3 + 4
a7 = a5 + 4
...
We see that a2k+1 = a1 + 4k for odd values of k.
Using the initial condition a1 = 3, we find:
a3 = a1 + 4(1)
a3 = 3 + 4
a3 = 7
Therefore, for odd values of n, the solution is given by an = 3 + 4k.
(b) To solve the recurrence relation an = 2an-1 + 1, with initial condition a1 = 1, we'll find a general expression for an.
Let's write out a few terms to observe the pattern:
a2 = 2a1 + 1
a3 = 2a2 + 1
a4 = 2a3 + 1
...
We can see that each term is one more than twice the previous term.
By substituting repeatedly, we can express an in terms of a1:
an = 2(2(2(...2(a1) + 1)...)) + 1
= 2^n * a1 + (2^n - 1)
Using the initial condition a1 = 1, we have:
an = 2^n * 1 + (2^n - 1)
= 2^n + 2^n - 1
= 2 * 2^n - 1
Therefore, the solution to the recurrence relation is given by an = 2^(n+1) - 1.
the amount of money spent by a customer at a discount store has a mean of and a standard deviation of . what is the probability that a randomly selected group of shoppers will spend a total of more than ? (hint: the total will be more than when the sample mean exceeds what value?)
The probability that a randomly selected group of shoppers will spend a total of more than is 7.86%.
Standard deviation = √n × σ
= √50 × 30
= 212.1320
P( Σx > 5300) = P( Σx - nu / √n * σ > 5300 - 5000/212.1320)
= P(z > 1.414)
= 1 - P( z< 1.414)
= 0.078621
= 7.86%
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Factorise
3x square +6x
Hey!!
Solution,
3x^2+6x
take the common,
3x(X+2)
hope it helps
Good luck on your assignment
What is the slope of the line in the graph? PLZ HELP
Answer:-3/4
Step-by-step explanation: Raises 3 units, goes to the left 4 units.
Answer:
-3/4
Step-by-step explanation:
Slope is rise over run. The line is negative as the line is falling, not rising. From one point to the next it falls 3, or rises -3. It runs 4, therefore the rise/run, or slope is -3/4.
Solve for X, please write an explanation.
Step-by-step explanation:
2x+20 and 2x-4 are supplementary angles...they form a straight line and thus = 180 degrees when added together
2x+20 + 2x-4 = 180 simplify
4x + 16 = 180 subtract 16 from both sides
4x = 164 divide both sides by 4
x = 41 degrees
17. A disposable camera costs $6.95. A party planner wants to buy 100 cameras for an
upcoming event. How much will they cost?
Answer:
$695
Step-by-step explanation:
So if each camera costs $6.95 snd he wants 100 you would multiply by 100. And that would be 6.95×100=695 and a good trick I've learnt is that you just move the numbers 1 column to the left for each zero so if it was 10 you'd move all the numbers 1 column to the left. It is abit hard to explain but you're answer is there just thought that'd help in future.
use the distance formula to find the distance between the two points (-3, 3) and (2, 2) give the exact length (leave in radical form if it is not a perfect square). but please show your work so i can understand. its ok if u cant show ur work tho thank you!
Answer:
\(\sqrt{26}\)
Step-by-step explanation:
Calculate the distance d using the distance formula
d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)
with (x₁, y₁ ) = (- 3, 3) and (x₂, y₂ ) = (2, 2)
d = \(\sqrt{(2+3)^2+(2-3)^2}\)
= \(\sqrt{5^2+(-1)^2}\)
= \(\sqrt{25+1}\)
= \(\sqrt{26}\)
#20,21,22
T 2 Hint: use even & odd function 1+X6 Sind #10 Evaluate Stano sec? o do #11 Evaluate 1 x?sinx dx ( - 7 T- #12 Evaluate sa x Na?x? dx #13 Evaluate Sot 1x-4x+31dx #14 Find F'(X) if F(x) = So I dt () st
The values of all sub-parts have been obtained.
(10). Even function, \(\[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sec^6(x) \, dx\]\)
(11). Odd function, \(\[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sec^6(x) \, dx\]\)
(12). Odd function,\(\(\int \frac{\sin(x)}{x} \, dx\).\)
(13). \(\[\int \frac{1}{(x - 1)(x - 3)} \, dx\]\)
(14). \(\[F'(x) = \frac{d}{dx}\left(\int_0^x t \, dt\right) = x\]\)
What is integral calculus?
Integral calculus is a branch of mathematics that deals with the study of integrals and their applications. It is the counterpart to differential calculus, which focuses on rates of change and slopes of curves. Integral calculus, on the other hand, is concerned with the accumulation of quantities and finding the total or net effect of a given function.
The main concept in integral calculus is the integral, which represents the area under a curve. It involves splitting the area into infinitely small rectangles and summing their individual areas to obtain the total area. This process is known as integration.
#10
Evaluate\(\(\int_0^\pi \sec^6(x) \, dx\).\)
To evaluate this integral, we can use the properties of even and odd functions. Since \(\(\sec(x)\)\) is an even function, we can rewrite the integral as follows:
\(\[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sec^6(x) \, dx\]\)
Now, we can use integration techniques or a calculator to evaluate the integral.
#11
Evaluate \(\(\int_0^\pi x \sin(x) \, dx\).\)
This integral involves the product of an odd function, \((\(x\))\) and an odd function\((\(\sin(x)\)).\) When multiplying odd functions, the resulting function is even. Therefore, the integral of the product over a symmetric interval\(\([-a, a]\)\) is equal to zero. In this case, the interval is \(\([0, \pi]\)\) , so the value of the integral is zero.
#12
Evaluate\(\(\int \frac{\sin(x)}{x} \, dx\).\)
This integral represents the sine integral function, denoted as
\(\(\text{Si}(x)\).\) The derivative of \(\(\text{Si}(x)\)\) is \(\(\frac{\sin(x)}{x}\).\)
Therefore, the integral evaluates to \(\(\text{Si}(x) + C\)\), where \(\(C\)\)is the constant of integration.
#13
Evaluate\(\(\int \frac{1}{x^2 - 4x + 3} \, dx\).\)
To evaluate this integral, we need to factorize the denominator. The denominator can be factored as\(\((x - 1)(x - 3)\).\)Therefore, we can rewrite the integral as follows:
\(\[\int \frac{1}{(x - 1)(x - 3)} \, dx\]\)
Next, we can use partial fractions to split the integrand into simpler fractions and then integrate each term separately.
#14
Find \(\(F'(x)\) if \(F(x) = \int_0^x t \, dt\).\)
To find the derivative of \(\(F(x)\)\), we can use the
Fundamental Theorem of Calculus, which states that if a function \(\(f(x)\)\) is continuous on an interval \(\([a, x]\),\) then the derivative of the integral of \(\(f(t)\)\) with respect to \(\(x\)\) is equal to \(\(f(x)\).\) Applying this theorem, we have:
\(\[F'(x) = \frac{d}{dx}\left(\int_0^x t \, dt\right) = x\]\)
Therefore, the derivative of \(\(F(x)\)\) is \(\(x\)\).
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a line, y=mx+b, passes through the point (1, 6) and is parallel to y=4x+6. What is the value of B?
Answer:
B = 2
Step-by-step explanation:
I used Desmos to get a visual representation to help.
The equation y = 4x + 6 has a y - intercept at (6,0).
The equation y = 4x + 2 has a y - intercept at (2,0) and passes through (1,6).
Hope this helps!
The value of B = 2 when a line, y=mx+b, passes through the point (1, 6) and is parallel to y=4x+6.
What is an equation?
The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.
The equation y = 4x + 6 has a y - intercept at (6,0).
The equation y = 4x + 2 has a y - intercept at (2,0) and passes through (1,6).
Therefore the value of B = 2 when a line, y=mx+b, passes through the point (1, 6) and is parallel to y=4x+6.
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A business recently ran a campaign where their roi was 3. they ran a second campaign where their roas was 4. did they do better on the second campaign?
Yes, the business did better on the second campaign. Since a higher ROI or ROAS value indicates better performance, the business did better on the second campaign.
ROI stands for Return on Investment, which is a measure of profitability. It is calculated by dividing the net profit by the total investment and expressing it as a percentage.
In this case, the ROI for the first campaign was 3, indicating that the business generated three times the profit compared to the investment.
ROAS stands for Return on Advertising Spend, which is a measure of the effectiveness of advertising campaigns. It is calculated by dividing the revenue generated by the advertising campaign by the cost of that campaign.
In this case, the ROAS for the second campaign was 4, indicating that the business generated four times the revenue compared to the advertising cost.
Since a higher ROI or ROAS value indicates better performance, the business did better on the second campaign. The ROAS value of 4 is higher than the ROI value of 3, indicating that the second campaign was more effective in terms of generating revenue compared to the investment made.
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The ROI (Return on Investment) measures the profitability of an investment and is calculated by dividing the net profit by the cost of the investment.
The ROAS (Return on Advertising Spend) measures the effectiveness of an advertising campaign and is calculated by dividing the revenue generated by the advertising campaign by the cost of the campaign. Based on the information provided, it can be concluded that the business did better on the second campaign.
In this case, the business had an ROI of 3 for the first campaign and a ROAS of 4 for the second campaign.
To compare the two campaigns, we can look at the ratios.
For the first campaign, the ROI was 3, meaning that for every dollar invested, the business received 3 dollars in profit.
For the second campaign, the ROAS was 4, meaning that for every dollar spent on advertising, the business generated 4 dollars in revenue.
Comparing these two ratios, we can see that the second campaign had a higher return on advertising spend (ROAS) compared to the first campaign's return on investment (ROI). This suggests that the second campaign performed better in terms of generating revenue in relation to the advertising cost.
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an environmental agency is analyzing soil samples from 50 farms for lead contamination. eight of the farms have dangerously high levels of lead. ten farms are randomly selected from the sample. using technology, how many ways could two contaminated farms and eight noncontaminated farms be chosen?
Number of ways , two contaminated and 8 non- contaminated farms be choosen is 3,304,845,180.
Permutation and Combination
Combination is a mathematical way to arranging the set of values randomly.
ⁿCᵣ = n! / r! (n-r)!
we have given that ,
total number of farms for lead contamination = 50
Number of farms have dangerously high level of lead = 8
so, number of non- containmated farms ( no high level of lead ) = 50-8 = 42
We have to find the number of ways to choose two contaminated farms and eight non- contaminated farms. Two containmated farms are selected from 8 containated farms and 8 non- contaminated farms are selected from 42 farms .
Number of ways for selecting two containmated farms = ⁸C₂ = 8!/2!×6! = 8×7/2 = 28
Number of ways for selecting eight non-containmated farms from 42 farms = ⁴²C₈
= 42! / 8! 34! = 42×41×---×35/8×7×----×1
= 118013185
The total number of ways to obtain 2 containmated farms and 8 non- contaminated farms in 10 farms selected is then product of number of ways to select the 2 containmated farms and number of ways to select 8 non-containmated farms .
= 118030185× 28 = 3,304,845,180
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Please help me with this question I don’t need an explanation either I will give brainliest
Answer:
(1) 25
Step-by-step explanation:
a1 => 121 =11²
10
9
a3=>64= 8²
7
6
a5=>25= 5²
can someone help me on this one!
Answer: Pay less sells the lowest price per marker.
Step-by-step explanation:
To get to one marker divide 10 by 10 and do same to other side. EX. 10/10=1, 2.50/10=0.25
To get to one marker divide 20 by 20 and do same to other side. EX. 20/20=1, 4.00/20= 0.2