the tire rod of the smaller train would be 3.6 inches long if the scale factor is 10.
What is the constant of proportionality?
The constant of proportionality is a term that is defined as the rate or the ratio of two proportional values which are known to be at the same value.
we can set up the following proportion:
(Larger train tire rod length) / (Larger train length) = (Smaller train tire rod length) / (Smaller train length)
Substituting the given values, we have:
36 / (Larger train length) = x / (Smaller train length)
Since we don't know the exact lengths of the larger and smaller trains, we cannot solve for x directly. However, we can use the fact that the smaller train is a scale drawing of the larger train to set up another proportion:
(Larger train length) / (Smaller train length) = (Scale factor)
Let the scale factor be s. Then we can rewrite the above proportion as:
(Larger train length) = s x (Smaller train length)
Substituting this expression into the first proportion, we have:
36 / (s x Smaller train length) = x / (Smaller train length)
Simplifying, we get:
x = 36 / s
x = 36 / 10 = 3.6 inches
In other words, the tire rod of the smaller train would be 3.6 inches long if the scale factor is 10.
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A. Saving money at the grocery store by using unit pricing.
a. Toilet paper A is 6 mega rolls for $4.59.
Toilet paper B is 12 mega rolls for $9.02
How to I find which one is the better deal?
Based on the calculations using unit pricing, Toilet paper B has a lower unit price and is the better deal between the two. Customers will save more money if they purchase toilet paper B rather than toilet paper A because the price per mega roll is lower. (option b)
Saving money while shopping is one of the best ways to reduce your expenses and have more disposable income for other things. Unit pricing is a pricing system that displays prices in standard units, allowing customers to compare prices across different brands and package sizes and save money. To determine which toilet paper deal is better, we can use the unit price method, which divides the price by the number of units in the package. The toilet paper with the lower unit price is the better deal.
The formula for unit pricing is as follows:
Unit price = total price ÷ number of units
Using the above formula, we can calculate the unit price of toilet paper A and toilet paper B as follows:
For Toilet paper A:
Unit price = $4.59 ÷ 6 mega rolls
Unit price = $0.765 per mega roll
For Toilet paper B:
Unit price = $9.02 ÷ 12 mega rolls
Unit price = $0.751 per mega roll
Therefore, based on the calculations, Toilet paper B has a lower unit price and is the better deal between the two. Customers will save more money if they purchase toilet paper B rather than toilet paper A because the price per mega roll is lower. (option b)
Unit pricing is a great way to compare prices, and consumers should always use it to determine the better deal between two products, as this will help them save money and stick to their budget.
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Find an autonomous differential equation with all of the following properties:
equilibrium solutions at y=0 and y=3,
y' > 0 for 0
y' < 0 for -inf < y < 0 and 3 < y < inf
dy/dx = ______
dy/dx = (y-3)(y+3) is the autonomous differential equation that satisfies all of the given properties.
The autonomous differential equation that satisfies all of the given properties is dy/dx = (y-3)(y+3). This equation has two equilibrium solutions at y = 0 and y = 3, and is positive for -inf < y < 0, and negative for 0 < y < 3, and positive for 3 < y < inf.
To demonstrate this, let's consider the equation at y=-3. Since y=-3 is less than 0, the equation can be simplified to dy/dx = 6. Since 6 is positive, y' is also positive, meaning that y is increasing. Similarly, if y=3, dy/dx = 0 which is neither positive nor negative, so y remains constant. Finally, for y>3, dy/dx = -6, which is negative, so y is decreasing.
Therefore, dy/dx = (y-3)(y+3) is the autonomous differential equation that satisfies all of the given properties.
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Keller Construction is considering two new investments. Project E calls for the purchase of earthmoving equipment. Project H represents an investment in a hydraulic lift. Keller wishes to use a net present value profile in comparing the projects. The investment and cash flow patterns are as follows: Use Appendix B for an approximate answer but calculate your final answer using the formula and financial calculator methods.
Based on the net present value profile, Project H has a higher NPV than Project E.
To compare the net present value (NPV) of Project E and Project H, we need to calculate the present value of cash flows for each project and determine which one has a higher NPV. The cash flow patterns for the two projects are as follows:
Project E:
Initial investment: -$100,000
Cash flows for Year 1: $40,000
Cash flows for Year 2: $50,000
Cash flows for Year 3: $60,000
Project H:
Initial investment: -$120,000
Cash flows for Year 1: $60,000
Cash flows for Year 2: $50,000
Cash flows for Year 3: $40,000
To calculate the present value of cash flows, we need to discount them using an appropriate discount rate. The discount rate represents the required rate of return or the cost of capital for the company. Let's assume a discount rate of 10%.
Using the formula method, we can calculate the present value (PV) of each cash flow and sum them up to obtain the NPV for each project:
For Project E:
PV = $40,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $60,000/(1 + 0.10)^3
PV = $36,363.64 + $41,322.31 + $45,454.55
PV = $123,140.50
For Project H:
PV = $60,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $40,000/(1 + 0.10)^3
PV = $54,545.45 + $41,322.31 + $30,251.14
PV = $126,118.90
Using the financial calculator method, we can input the cash flows and the discount rate to calculate the NPV directly. By entering the cash flows for each project and the discount rate of 10%, we find that the NPV for Project E is approximately $123,140.50 and the NPV for Project H is approximately $126,118.90.
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A teaching hospital in South-West Part of Nigeria receives on the average 5 pregnant women with high blood pressure per week. What is the probability that on a particular week, the teaching hospital will receive:
1.) No high BP pregnant woman
Answer:
The probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068
Step-by-step explanation:
We use the Exponential distribution,
Since we are given that on average, 5 pregnant women with high blood pressure come per week,
So, average = m = 5
Now, on average, 5 people come every week, so,
5 women per week,
so, we get 1 woman per (1/5)th week,
Hence, the mean is m = 1/5 for a woman arriving
and λ = 1/m = 5 = λ
we have to find the probability that it takes higher than a week for a high BP pregnant woman to arrive, i.e,
P(X>1) i.e. the probability that it takes more than a week for a high BP pregnant woman to show up,
Now,
P(X>1) = 1 - P(X<1),
Now, the probability density function is,
\(f(x) = \lambda e^{-\lambda x}\)
And the cumulative distribution function (CDF) is,
\(CDF = 1 - e^{-\lambda x}\)
Now, CDF gives the probability of an event occuring within a given time,
so, for 1 week, we have x = 1, and λ = 5, which gives,
P(X<1) = CDF,
so,
\(P(X < 1)=CDF = 1 - e^{-\lambda x}\\P(X < 1)=1-e^{-5(1)}\\P(X < 1)=1-e^{-5}\\P(X < 1) = 1 - 6.738*10^{-3}\\P(X < 1) = 0.9932\\And,\\P(X > 1) = 1 - 0.9932\\P(X > 1) = 6.8*10^{-3}\\P(X > 1) = 0.0068\)
So, the probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068
JKLM is a rhombus.
m/JMN = (-x+69)*
mZLMJ = (-6x +166)
K
N
M
Find the mZLKN.
label optional
The angle LKN in the rhombus is 62 degrees.
How to find angles in a rhombus?A rhombus is a quadrilateral that has 4 sides equal to each other. The sum of angles in a rhombus is 360 degrees.
Opposite angles are equal in a rhombus. The diagonals bisect each other at 90 degrees. Adjacent angles add up to 180 degrees.
Therefore, let's find ∠LKN as follows:
m∠JMN = (-x + 69)
m∠LMJ = (-6x + 166)
Therefore,
1 / 2 (-6x + 166) = -x + 69
-3x + 83 = -x + 69
-3x + x = 69 - 83
-2x = -14
x = -14 / -2
x = 7
Therefore,
∠LKN = 1 / 2 (-6x + 166)
∠LKN = 1 / 2 (-6(7) + 166)
∠LKN = 1 / 2 (-42 + 166)
∠LKN = 62 degrees
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Which property can be used to show that if 3a = 4b, then 4b = 3a?
Multiple choice question.
A)
Symmetric Property of Equality
B)
Reflexive Property of Equality
C)
Substitution Property of Equality
D)
Transitive Property of Equality
Answer:
Hello your answer should be A symmetric property
Step-by-step explanation:
hope this helps
Symmetric property of equality to show that 3a = 4b, then 4b = 3a?
What is symmetric property of equality?The symmetric property of equality is a simple property that says we can interchange the sides of an equation without changing the truth-value of the equation. That is, if a = b, then b = a. Each side of the equation can be thought of as the mirror image of the other
We have the following information available from the question is:
We have to determine the which property can be used to show that if 3a = 4b, then 4b = 3a
Now, According to the question:
3a = 4b
4b = 3a (both are equal)
This property is used to simplify the equations, to reverse the equations, and also for proofs in numerical and non-numerical logic.
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need help with this ASAP
!!!!!!!!!!!!!!!!!!!!!!!!
The fence in dead center is about 399 feet from the third base.
What is the Pythagorean Theorem?The Pythagorean Theorem states that in the case of a right triangle, the square of the length of the hypotenuse, which is the longest side, is equals to the sum of the squares of the lengths of the other two sides.
Hence the equation for the theorem is given as follows:
c² = a² + b².
In which:
c > a and c > b is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.For the triangle in this problem, we have that:
The sides are d ft and 90 ft.The hypotenuse is of 409 ft.Hence the distance is obtained as follows:
d² + 90² = 409²
\(d = \sqrt{409^2 - 90^2}\)
d = 399 ft.
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Robert's book bag is weighing him down. His bag alone weighs 4 pounds. His library book
weighs 2 pounds. The math book is 4 times the weight of the library book, and his science
book is 2 times the weight of the math book. How much does his book bag weigh with all
these books? What is the heaviest book in his book bag?
Answer:
1) 30 pounds is the weight of the bag all together
2) science book is the heaviest book
Step-by-step explanation:
bag=4 pounds
library book=2 pounds
maths book=2×4=8 pounds
science book=8×2=16 pounds
4+2+8+16=30 pounds all together
heaviest book= science book (16 pounds)
solve 2x-5=7
SUUUCHHH AN EASYYY QUESTION ANYONE WANT TO HELP?!?!?
Answer:
( ~ Sure, But i'm slow <3 ~ )
Is it....
x = 6
Step-by-step explanation:
(( Sorry if i got it wrong- im Dumb. <3 ))
(( But here's a nice picture for u. ^^ ))
Answer: x = 6
Step-by-step explanation: 2x-5=7
+5 +5
2x = 12 divide by 2 on both sides
x = 6
the speed of the current in a creek is 2 mph. A person can kayak 4 mi upstream in the same time that it takes him to kayak 8 mi downstream. What is the speed of the persons kayak in still water?
Answer:
I think 6 mph
Step-by-step explanation:
I needore characters so ingnor this sentence.
Rumus suatu fungsi di nyatakan dengan f (x) = 2x + 5. Jika f(a) = 7, nilai a adalah
Step-by-step explanation:
As my previous answer got deleted for being wrong (in which it was right), I will answer again.
The answer is 1. Why? Just plug it into the equation. F(1) = 2(1) + 5 = 7.
This is proof that it is right, and that there are some corrupt admins on brainly.
How to get to this solution?
Well notice how we are given what f(a) is. It is 2a + 5. So plug this in for f(a).
If we do so, we get 2a + 5 = 7.
Solving this equation, we get a = 1.
Express 80 as the product of its prime factors Write the prime factors in ascending order.
Answer:
2×2×2×2×5
Step-by-step explanation:
Express 80 as the product of its prime factors Write the prime factors in ascending order.
2 × 2 × 2 × 2 × 5
2×2×2×2×5 = 80
What is (f−g)(x)? f(x)=3x5+6x2−5 g(x)=2x4+7x2−x+16
Answer: We have f(x)=3x⁵+6x²-5 and g(x)= 2x⁴+7x²-x+16
(f-g)(x)= 3x⁵-2x⁴-x²+x-21
Step-by-step explanation:
Here we have,
Given : f(x)=3x⁵+6x²-5 and g(x)= 2x⁴+7x²-x+16
We know,
(f-g)(x)= f(x)-g(x)
= (3x⁵+6x²-5 ) - ( 2x⁴+7x²-x+16)
On subtracting g(x) from f(x) we get,
(f-g)(x)= (3x⁵+6x²-5 - 2x⁴-7x²+x-16)
On simplify,
(f-g)(x) =3x⁵-2x⁴-x²+x-21
Hence,
(f-g)(x) = f(x) - g(x) = 3x⁵-2x⁴-x²+x-21
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An exercise machine with an original price of $890 is on sale at 24% off.
a. What is the discount amount?
b. What is the exercise machines sale price?
The discount amount is $213.6
The sale price for the exercise machines is $676.4
How to calculate the discount amount ?The first step is to calculate the discount amount
890 × 24/100
= 890 × 0.24
= 213.6
The next step is to calculate the sale price
890(1-0.24)
890(0.76)
676.4
Hence the discount amount is $213.6 and the sale price of the exercise machine is $676.4
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Lee watches TV for 3 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (18 cents)/(1 kilowatt-hour). How much does Lee's TV cost to operate for a month of 30 days?
Lee's TV costs $4.05 to operate for a month of 30 days.
To calculate the cost of operating Lee's TV for a month, we need to find out the total number of kilowatt-hours (kWh) of electricity consumed by the TV during that time.
First, let's find out how many watts Lee's TV consumes in a day:
250 watts/hour x 3 hours/day = 750 watts/day
To convert this to kilowatts, we divide by 1000:
750 watts/day ÷ 1000 = 0.75 kilowatts/day
Now, we can calculate the total number of kilowatt-hours consumed by the TV in a month:
0.75 kilowatts/day x 30 days = 22.5 kilowatt-hours
Finally, we can calculate the cost of operating the TV for a month:
22.5 kilowatt-hours x 18 cents/kilowatt-hour = $4.05
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Maria started an account with an initial deposit of $47.00 on week 1. She then deposited $18.50 into the account each week thereafter for a total of 40 weeks. How much was the balance of the account after 40 weeks?
Answer:
$121.00
Step-by-step explanation:
y = 18.50x + 47.00
y = the total amount in the account
x = the number of weeks
y = 18.50(4) + 47.00
y = 74.00 + 47.00
y = 121
Triangle PQR has vertex coordinates at P(4, 0), Q(5, 4), R(5, 1). If the triangle is translated so that Q′(0, 4), determine the translation direction and number of units.
5 units down
5 units up
5 units to the right
5 units to the left
The translation direction is 5 units to the left.
To determine the translation direction and number of units, we can compare the original coordinates of point Q (Q(5, 4)) with the new coordinates of Q' after the translation (Q'(0, 4)).
By comparing the x-coordinates, we can see that the x-coordinate of Q' is smaller than the x-coordinate of Q, which means the triangle was translated to the left.
By comparing the y-coordinates, we can see that the y-coordinate of Q' is the same as the y-coordinate of Q, which means there was no vertical translation.
Therefore, the translation direction is 5 units to the left.
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An exam has four multiple choice problems, each with five possible answers. If you guess on each problem, what is the probability of getting at least one answer correct? Round your answer to the nearest whole percent.
1/2 is the probability of getting at least one answer correct
How to find the probability of getting at least one answer correct?
Given that: the exam has 4 multiple choice with 5 possible answers. This means there are 20 possible choices ( 5×4 = 20).
That means each problem has a probability of 1/20 correct answer. The probability of getting at least one answer means you either get one, two, three or four correct answers. Thus:
P (at least one correct) = P(1) + P(2) + P(3) + P(4)
= 1/20 + 2/20 + 3/20 + 4/20
= (1+2+3+4)/20
= 10/20
= 1/2
Therefore, the probability of getting at least one answer correct is 1/2
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The probability of getting at least one answer correct is equal to 7
How to calculate for the probabilityThat I guess at least one answer correctly means that I could get all four answers correct or three answers correct or two answers correct or only one answer correct. The probability of getting any one answer is 1/4 and probability of not getting an answer is 1 - 1/4=3/4. Or implies addition.
probability of getting all four answers correct = 1/4 +1/4 + 1/4 + 1/4 = 4/4 = 1
probability of getting three answers correct = 1/4 +1/4 + 1/4 + 3/4 = 6/4 = 3/2
probability of getting two answers correct = 1/4 +1/4 + 3/4 + 3/4 = 8/4 = 2
probability of getting all four answers correct = 1/4 +3/4 + 3/4 + 3/4 = 10/4 = 5/2
The probability of getting at least one answer correct = 1 + 3/2 + 2 + 5/2
The probability of getting at least one answer correct = (2 + 3 + 4 + 5)/2
The probability of getting at least one answer correct = 14/2
Thefore, the probability of getting at least one answer correctly is the whole number 7
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Help ASAP giving BRAINLIEST! Am i correct?
Answer:
You are correct
Step-by-step explanation:
x - 8 < 23
Add 8 to both sides
x - 8 + 8 < 23 + 8
Simplify
x < 31
Yes, you are correct.
Part b c and d please help
Answer:
b) Y =5.73X +4.36
C) =5.73225*(21)X +4.359
124.73625
D) 163.728 = 5.73X +4.36
X = (163.728 - 4.36)/5.73
X = 27.81291449
Year would be 2027
Step-by-step explanation:
x1 y1 x2 y2
4 27.288 16 96.075
(Y2-Y1) (96.075)-(27.288)= 68.787 ΔY 68.787
(X2-X1) (16)-(4)= 12 ΔX 12
slope= 5 41/56
B= 4 14/39
Y =5.73X +4.36
A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer. Test whether there is a difference between these proportions at α = 0.05. What is the test statistic value? Group of answer choices
Answer:
Step-by-step explanation:
Step(i):-
Given first random sample size n₁ = 500
Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.
First sample proportion
\(p^{-} _{1} = \frac{65}{500} = 0.13\)
Given second sample size n₂ = 700
Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.
second sample proportion
\(p^{-} _{2} = \frac{133}{700} = 0.19\)
Level of significance = α = 0.05
critical value = 1.96
Step(ii):-
Null hypothesis : H₀: There is no significance difference between these proportions
Alternative Hypothesis :H₁: There is significance difference between these proportions
Test statistic
\(Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }\)
where
\(P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165\)
Q = 1 - P = 1 - 0.165 = 0.835
\(Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }\)
Z = -2.76
|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance
Null hypothesis is rejected at 0.05 level of significance
Alternative hypothesis is accepted at 0.05 level of significance
Conclusion:-
There is there is a difference between these proportions at α = 0.05
According to the question,
Women,
\(\hat p_1 = \frac{65}{500}\)\(= 0.13\)
Men,
\(\hat p_2=\frac{300}{700}\)\(= 0.19\)
Now,
The pooled estimate of the proportion will be:
→ \(\hat p=\frac{x_1+x_2}{n_1+n_2}\)
By substituting the values,
\(= \frac{65+133}{500+700}\)
\(= 0.165\)
then,
→ \(\hat q = 1- \hat p\)
\(= 1- 0.165\)
\(= 0.835\)
hence,
The test statistics:
→ \(Z = \frac{\hat p_1- \hat p_2}{\sqrt{\hat p\times \hat q\times (\frac{1}{n_1} +\frac{1}{n_2} )} }\)
By putting the values, we get
\(= \frac{0.13-0.19}{\sqrt{0.165\times 0.835\times (\frac{1}{500} +\frac{1}{700} )} }\)
\(= -2.76\)
Thus the above response is right.
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solve the system of equations below
5x+2y=9
2×-3y=15
Answer:
The solution is (3, -3)
Step-by-step explanation:
5x + 2y = 9
2x - 3y = 15
Use elimination by addition/subtraction. Multiply the first equation by 3 and the second by 2, obtaining:
15x + 6y = 27
4x - 6y = 30
----------------------
19x = 57
This yields x = 3.
Substituting 3 for x into 5x + 2y = 9, we get 5(3) + 2y = 9, or
15 + 2y = 9, or
2y = -6
This yields y = -3.
The solution is (3, -3)
In a proposed business venture, Serena estimates there is a 65% chance she will make
$70,000 and a 35% chance she will lose $30,000. Determine Serena's expected value.
Answer:
$35,000
Step-by-step explanation:
In a proposed business venture, Serena estimates that there is a 65% chance that she will make $70,000
And also a 35% chance that she will loose $30,000
Therefore the expected value can be calculated as follows
E= 65/100 × 70,000 + 35/100 × (-30,000)
= 0.65 × 70,000 + 0.35(-30,000)
= 45,500 - 10,500
= $35,000
Hence the expected value is $35,000
Based on the probability of the payoffs, we can calculate that the expected value is $35,000.
The expected value is calculated as:
= ∑(Probability of payoff x Payoff)
The expected value here is therefore:
= (65% x 70,000) + (35% x -30,000)
= 45,500 - 10,500
= $35,000
In conclusion, the expected value is $35,000.
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Calculus chapter7 (Transcendental Functions)
Answer:
1) \(\int\limits^{16}_{2} {\frac{dx}{2\cdot x \cdot \sqrt{\ln x}} } \approx 1.665\)
2) \(\frac{dy}{dx} = \pm \frac{1}{\sqrt{4\cdot x^{2}+7\cdot x +3}}\)
3) \(\int\limits^{2\sqrt{3}}_{0} {\frac{dx}{\sqrt{4 + x^{2}}} } \approx 1.317\)
Step-by-step explanation:
1) \(\int\limits^{16}_{2} {\frac{dx}{2\cdot x \cdot \sqrt{\ln x}} }\)
This integral can be solved easily by using algebraic substitutions:
\(u = \ln x\), \(du = \frac{dx}{x}\)
Then, the integral can rewritten as follows:
\(\int {\frac{dx}{2\cdot x\cdot \sqrt{\ln x}} } = \frac{1}{2}\int {\frac{du}{u^{1/2}} } = \frac{1}{2}\int {u^{-1/2}} \, du\)
\(\int {u^{-1/2}} \, du = 2\cdot u^{1/2} + C = 2\cdot \sqrt{\ln x} + C\)
Where \(C\) is the integration constant.
\(\int\limits^{16}_{2} {\frac{dx}{2\cdot x \cdot \sqrt{\ln x}} } = F(16) - F(2)\)
\(F(16) - F(2) = 2\cdot (\sqrt{\ln 16}-\sqrt{\ln 2})\)
\(F(16) - F(2) \approx 1.665\)
2) Let be \(y = \cosh^{-1} (2\cdot \sqrt{x+1})\), then we obtain the expression by the definition of the derivative for the inverse hyperbolic cosine and the chain rule:
\(\frac{dy}{dx} = \pm\frac{1}{\sqrt{4\cdot x + 3}}\cdot \left(\frac{1}{\sqrt{x+1}} \right)\)
\(\frac{dy}{dx} = \pm \frac{1}{\sqrt{(4\cdot x + 3)\cdot (x+1)}}\)
\(\frac{dy}{dx} = \pm \frac{1}{\sqrt{4\cdot x^{2}+7\cdot x +3}}\)
3) \(\int\limits^{2\sqrt{3}}_{0} {\frac{dx}{\sqrt{4 + x^{2}}} }\)
This integral can be solved by the following trigonometric substitutions:
\(\frac{2}{\sqrt{4 + x^{2}}} = \cos \theta\)
\(\frac{1}{\sqrt{4+x^{2}}} = \frac{\cos \theta}{2}\)
\(\frac{x}{2} = \tan \theta\)
\(x = 2\cdot \tan \theta\)
\(dx = 2\cdot \sec^{2}\theta \,d \theta\)
\(\int {\frac{dx}{\sqrt{4+x^{2}}} } = \int {\left(\frac{\cos \theta}{2} \right)\cdot (2\cdot \sec^{2}\theta)} \, d\theta = \int {\sec \theta} \, d\theta\)
\(\int {\sec \theta}\,d\theta = \ln |\sec \theta + \tan \theta| + C\)
\(\ln \left|\frac{\sqrt{4+x^{2}}}{2} + \frac{x}{2} \right| + C\)
Where \(C\) is the integration constant.
\(\int\limits^{2\sqrt{3}}_{0} {\frac{dx}{\sqrt{4 + x^{2}}} } = F(2\sqrt{3}) - F(0)\)
\(F(2\sqrt{3}) - F(0) = \ln \left|2+\sqrt{3}\right|-\ln \left|1\right|\)
\(F(2\sqrt{3}) - F(0) \approx 1.317\)
A supermarket had bags of red grapes for $13.00 for 5 bags. They also had bags of green grapes priced at $5.08 for 2 bags. Which type of grape is most expensive?
Answer:
Red grapes.
Step-by-step explanation:
If you find how much one bag of each grape cost which is:
$13.00 ÷ 5 = 2.60 (1 bag of red grapes)
$5.08 ÷ 2 = $2.54 (1 bag of green grapes)
See the price and you'll know it is red grapes.
It’s takes an aero plane 3.2 hours to fly from Mumbai to Seoul. It takes the same aero plane 1 1/3 hours to fly from Seoul to Tokyo. How many hours does it take the aero plane to travel from Mumbai to Tokyo if it flies through Seoul?
To find the total time it takes for the airplane to travel from Mumbai to Tokyo via Seoul, we need to add the time taken for the Mumbai-Seoul leg and the Seoul-Tokyo leg.
The airplane takes 3.2 hours to fly from Mumbai to Seoul.
The airplane takes 1 1/3 hours to fly from Seoul to Tokyo, which is equivalent to 1.33 hours.
To find the total time, we add the two durations:
3.2 hours + 1.33 hours = 4.53 hours
Therefore, it takes approximately 4.53 hours for the airplane to travel from Mumbai to Tokyo if it flies through Seoul.
Which rational number is the opposite of 1.7? Select all that apply.
-1 7/10
-1.7
1 7/10
Answer:
-1 7/10 and -1.7
Step-by-step explanation:
After a 35% reduction, you purchase a new bike for $282.75. What was the price of the bike before the reduction?
A) First write an equation you can use to answer this question. Use x as your variable and express any percents in decimal form in the equation.
B) Solve your equation in part [A] to find the original price of the bike.
The equation to represent this situation is given by 0.65x = 282.75 .
In the various mathematical formulas that are used, the equals sign is used to show that two expressions on either side of the equal sign are equal. The meaning of the word equation and its cognates might vary slightly depending on the language.
Finding the exact values of the unknown variables that result in the given equality is the very first step in the solving of a variable equation. The values of the unknown variables that fulfil the equality are the equation's solutions, also known as the variables for which the equation must be solved. There are two sorts of equations.
Le t the original cost of the bike be x dollars.
After 35% reduction the new cost is x - (35% of x) = 0.65 x
Therefore 0.65 x = 282.75
or, x = 435
Therefore the cost of the bike is $435.
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Hello please, I did not understand this exercise. In the plane referred to an orthonormal reference (o, i, j) place the points A, B, C and D defined by: A(6; 4); B(3; 7); C(12; -2); D(9; 7).
Show that C is the image of A by dilation with center B and ratio 3.
We have shown that C is the image of A by dilation with center B and ratio 3.
Now, To show that C is the image of A by dilation with center B and ratio 3, we need to follow these steps:
Firstly, Find the vector AB by subtracting the coordinates of B from the coordinates of A:
AB = A - B = (6 - 3, 4 - 7) = (3, -3)
Multiply the vector AB by the dilation ratio of 3:
3 AB = 3 (3, -3) = (9, -9)
Add the resulting vector to the coordinates of the center B:
BC = B + 3 AB = (3, 7) + (9, -9)
BC = (12, -2)
Hence, Compare the resulting point BC to the coordinates of C to show that they are the same:
BC = (12, -2) = C
Therefore, we have shown that C is the image of A by dilation with center B and ratio 3.
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HURRY!!! 3 1/6 divided by 5/6
Find the quotient
Answer: 3.8
Step-by-step explanation: