The sodium emission spectrum
contains one visible, yellow line, with a λ = 5.90 x 10-7 m.
c = 3.00 x 108 m/s
h = 6.626 x 10-34 J.s
What is the frequency of this light?

Answer:

The correct statement is;

(B) Only II

Explanation:

I) The atomic mass unit or amu which is also known as daltons which is defined as 1/12 × the mass of a carbon-12 atom, which is therefore, 1.660538921 × ⁻²⁴ grams

Therefore, the mass of 1 atom of carbon-12 = 12 amu

II) The mass of one mole of oxygen-16 is 16 grams while the mass of one mole of carbon-12 is 12 grams

The mass of 4 atoms of carbon 12 = 4 × 12 amu = 48 amu

The mass of 1 atom of oxygen-16 = 15.99491461956 amu

Therefore, the mass of 3 atoms of oxygen-16 = 3 × 15.99491461956 = 47.9847438587 amu ≈ 48 amu

Therefore only II is correct.

Answer:

+1/2

Explanation:

spin up is always +1/2

Answer:

\(56 \times { \frac{01514344}{?} }^{2} 5566648443hffii51 \\ \div 232333\)

Answer:

write a letter to the presiding member of your district assessment telling him or her about two of the achievement of your community over the last five years and the plans for the future

sunlight gives energy to living things

Explanation:

sun is the main energy for the earth

Answer:

See explanation

Explanation:

The to main chemicals that lead to acid rain are SOx and NOx. The major source of oxides of sulphur are power plants while the major source of oxides of nitrogen is the combustion of fossil fuels.

B. There are two types of acid rain; wet and dry. Wet type acid rain occurs when NOx and SOx combine with water vapour in the atmosphere and fall as precipitation while in dry type, wind deposits these acidic gases/matter on the surfaces of buildings, cars, trees etc. Rain water washes off these acidic deposits and the runoff is more acidic than the rain water.

C. Natural rain water has a pH of about 5.5 due to the fact that water dissolve CO2 in the atmosphere. This means that natural rain water is also slightly acidic. Rain water that dissolves SOx or NOx is often more acidic than these hence the term 'enhanced acid rain' may be used.

Again, since precipitation could be solid or liquid, the term 'acid deposition' is better.

The appearance of a new broad peak around 3500-3600 cm^-1 in the IR spectrum would suggest that benzophenone has been converted to diphenylmethanol.

In the IR spectrum, the position and intensity of absorption peaks provide information about the functional groups present in a compound. Benzophenone has a carbonyl group (C=O) in its structure, which typically shows a sharp peak around 1700-1750 cm^-1. However, when benzophenone is converted to diphenylmethanol, the carbonyl group is reduced to a hydroxyl group (OH).

The hydroxyl group in diphenylmethanol gives rise to a broad peak in the IR spectrum around 3500-3600 cm^-1. This peak corresponds to the stretching vibration of the O-H bond. The broadness of the peak is due to hydrogen bonding interactions between the hydroxyl groups in the molecule.

The appearance of this new peak in the IR spectrum indicates the formation of diphenylmethanol and the conversion of the carbonyl group in benzophenone to a hydroxyl group. It provides evidence of the reduction reaction that has occurred.

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When benzophenone is converted to diphenylmethanol, the IR spectrum would show the disappearance of the strong carbonyl (C=O) stretch around 1700 cm-1 and the appearance of a new, broad absorption band for the alcohol (OH) group around 3200-3600 cm-1.

The question asks what change in the IR spectrum would suggest that benzophenone has been converted to diphenylmethanol. In the IR spectrum, different functional groups in molecules exhibit characteristic absorption frequencies. Benzophenone, a ketone, has a strong carbonyl (C=O) stretch in the IR spectrum around 1700 cm-1. However, when benzophenone is converted to diphenylmethanol, the carbonyl group is converted into an alcohol (OH) group. So, in the diphenylmethanol's IR spectrum, you would expect to see the disappearance of the absorption band around 1700 cm-1 which is characteristic of the carbonyl group, and the appearance of a new, broad absorption band around 3200-3600 cm-1 characteristic of the OH group in alcohols.

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Answer:

The way I just figured it out myself and made another acc to put the answer on :/

Explanation:

Explanation:

The molarity or molar concentration is can be calculated by dividing the number of moles of solute by the volume of solution in L.

molarity = moles of solute/volume of solution in L

We want to prepare 6.7 L of a 1.2 M solution of CuF₂. We can find the number of moles of CuF₂ that we have to dissolve in the solution.

molarity = 1.2 M

volume of solution in L = 6.7 L

molarity = moles of CuF₂/(volume of solution in L)

moles of CuF₂ = molarity * volume of solution in L

Answer:

Answer to the following question is as follows;

Explanation:

A millilitre is equal to the volume of a cube with 1 cm on each side. As a result, one millilitre equals one cubic centimetre. There are 1000 mL in a litre, that is the same as 1000 cm3 in a square metre.

1 ml = 1 cm³

1000 ml = 1 liter

The University of North Texas (UNT) Chemistry Department offers various scholarships to support undergraduate and graduate students who are pursuing degrees in chemistry or biochemistry.

These scholarships are intended to provide financial assistance to students who have demonstrated academic excellence, leadership potential, and a commitment to the field of chemistry.

The scholarships offered by the UNT Chemistry Department vary in terms of eligibility requirements, award amounts, and application procedures. Some scholarships are open to all chemistry and biochemistry majors, while others are more specific in their requirements, such as being a Texas resident, a U.S. citizen or permanent resident, or having a particular area of research interest.

The application typically includes information about the student's academic record, research experience, community involvement, and financial need. Some scholarships may require additional materials, such as letters of recommendation, a personal statement, or a research proposal.

Students who are awarded scholarships from the UNT Chemistry Department can use the funds to pay for tuition, fees, books, and other educational expenses.

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The correct answer is a. 1.62 g/L.

To solve this problem, we can use the ideal gas law equation:
PV = nRT

Where P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature.

We can rearrange this equation to solve for density, which is mass per unit volume:
density = (molar mass * P) / (R * T)

Since we are given the pressure and temperature of the argon gas sample, we just need to find the molar mass of argon.

The molar mass of argon is approximately 39.95 g/mol.

Plugging in the values, we get:
density = (39.95 g/mol * 866 mmHg) / (0.0821 L atm/mol K * 343 K)

Simplifying, we get:
density = 1.62 g/L

Therefore, the correct answer is a. 1.62 g/L.

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No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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The total negative charge on the electrons in 1.32 mol of helium is 7.95 kc.

To find the magnitude of the total negative charge on the electrons in 1.32 mol of helium, we need to know the number of electrons in 1.32 mol. Since helium has an atomic number of 2, it means it has 2 electrons per atom. Therefore, 1.32 mol of helium contains (1.32 mol) * (\(6.022 x 10^2^3\) atoms/mol) * (2 electrons/atom) = \(1.59 x 10^2^4\) electrons.  

Each electron has a charge of \(1.6 x 10^-^1^9\) coulombs.

Multiplying the number of electrons by the charge of each electron, we get

(\(1.59 x 10^2^4\)electrons) * (\(1.6 x 10^-^1^9\) C/electron)

= \(2.54 x 10^5\) coulombs.  

To convert this into kc, we divide by 1000 to get the answer in thousands of coulombs. Therefore, the magnitude of the total negative charge on the electrons in 1.32 mol of helium is \(2.54 x 10^2\) kc, which is equivalent to 7.95 kc.

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Answer:

A) In aldehydes, the carbon is always joined to at least one hydrogen atom.

Explanation:

Aldehydes and Ketones are organic compounds.

The main difference between them is that aldehydes have the carbon atom attached to at least one hydrogen atom.

In ketones, the carbon is attached to another carbon.

To reiterate, the striking difference between the two families is that in alkanals, a hydrogen atom is directly attached to the carbonyl group while in alkanones, no hydrogen atoms is attached to the carbonyl group but two bulky alkyl groups.

Answer:

option a is not correct

Segments are an important concept in geometry, and they are defined as a portion of a line that has two endpoints. Without more information about the context in which these segments are located, we cannot definitively say why one is shorter than the other. However, we can use these examples to illustrate the importance of considering the endpoints and context when comparing segment lengths in geometry.

To start, we need to consider the endpoints of each segment. Segment BC has endpoints B and C, while segment DE has endpoints D and E. Next, we can look at the location of these endpoints in relation to each other.

One possibility is that segment DE is simply longer than segment BC because the distance between points D and E is greater than the distance between points B and C. However, this may not be the case since we are given no information about the relative positions of these points.

Another possibility is that the segments are located in different parts of a larger figure, and the surrounding geometry affects their lengths. For example, if segment DE is part of a triangle with a longer base than the triangle containing segment BC, then segment DE would be longer even if the endpoints D and E were closer together than the endpoints B and C.

Complete question - Explain why the segment bc is significantly shorter than segment de in a triangle?

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Answer:

Molar Mass: 138.9818 g/mol

Explanation:

In radioactive decay, with each successive half-life, half the remaining sample decays to form another element.

In most cases, a new element is created from the destroyed nuclei with each new half-life.

The same element is created during the decay of an isotope since the daughter nucleus has the same amount of protons (same atomic number).

A new element is created when a daughter nucleus has the same number of neutrons as the parent nucleus, or an isotone (new atomic number)

Isobar: daughter nucleus has identical mass number; this might be an example of beta decay; the decayed nucleus retains its mass number but adds a proton in place of a lost electron, resulting in the formation of a new element with an increased atomic number by one.

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The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;

P1V1/T1 = P2V2/T2

Where;

According to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.

However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:

2 × 12.3/300 = 2 × V2/900

0.082 = 2V2/900

73.8 = 2V2

V2 = 73.8 ÷ 2

V2 = 36.9L

Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

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Answer:

Explanation:

it's 18.45, my sister just got the guestion right! hope it helps :)

The compound dibromobis(ethylenediamine)cobalt(III) sulfate, there are 3 individual ions per formula unit: one cobalt(III) complex ion [Co(en)2Br2]+3, one sulfate ion (SO4)^2-, and three water molecules as each formula unit contains three waters of hydration.

For Dibromobis(ethylcuediamine)cobalt(III) sulfate, the number of individual ions per formula unit and the coordination number of the metal ion are: - Number of individual ions per formula unit: There are a total of 6 ions per formula unit.

The compound has the following formula: [Co(ethylenediamine)2Br2]SO4. This means that there are two ethylenediamine ligands, each contributing 2 nitrogen atoms for a total of 4 nitrogen atoms.

Each nitrogen atom has a lone pair of electrons that can coordinate with the cobalt ion. There are also 2 bromide ions and 1 sulfate ion in the formula.

So, the total number of individual ions per formula unit is 4 nitrogen atoms + 2 bromide ions + 1 sulfate ion = 6 ions. - Coordination number of the metal ion: The metal ion in this compound is cobalt(III). Cobalt(III) has a coordination number of 6, which means that it can coordinate with 6 ligands. In this compound, there are 2 ethylenediamine ligands, each contributing 2 nitrogen atoms for a total of 4 nitrogen atoms.

The coordination number of the metal ion (cobalt) in this compound is 6, as there are two ethylenediamine (en) ligands, each with two nitrogen atoms coordinating to cobalt, and two bromine atoms also coordinating to cobalt (2x2 + 2 = 6).

The 4 nitrogen atoms coordinate with the cobalt ion, leaving 2 open coordination sites. These sites are occupied by the 2 bromide ions, giving a coordination number of 6 for the cobalt ion.

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Answer:

a ) 13.5 ml

Explanation:

It seems to be 14 ml just because of the movement of water but when it is still, It's actually 13.5 ml

Answer:

Molecular substances are made when two or more atoms join together by covalent bonds.

Explanation:

I hope this helps. I took the same class.

If 13 % of the carbon-14 in a sample of cotton cloth remains, what's the approximate age of the cloth?

To solve a half-life problem we usually use this formula:

amount remaining = initial amount (1/2)^n

Where n is the number of half-lives. We can replace n for T/Thalf:

amount remaining = initial amount (1/2)^(T/Thalf)

Where t is the age or time elapsed and Thalf is the half-life or our isotope. The half life of C-14 is 5730 years. Then:

Thalf = 5730 years

Let's supose that the cotton cloth originally had 100 g of C-14. If 13 % remains, the amount remaining is 13 g. So:

amount remaining = 13 g initial amount 100 g

Rearranging the formula we get:

amount remaining = initial amount (1/2)^(T/Thalf)

amount remaining/initial amount = (1/2)^(T/Thalf)

ln (amount remaining/initial amount) = ln [(1/2)^(T/Thalf)]

ln (amount remaining/initial amount) = (T/Thalf) *ln (1/2)

T = Thalf * ln (amount remaining/initial amount) /ln (1/2)

Now we can replace the given values:

T = 5730 years * ln(13 g/100g) / ln(1/2)

T = 5730 years * ln(0.13)/ln(0.5)

T = 5730 years * 2.94

T = 16825 years

Answer: the approximate age of the cloth is 16825 years.

The three (3) examples from the sword fighting scene that showed Inigo and the masked man's similarities are:

Inigo Montoya was one of the fictional character in the novel titled "The Princess Bride" and written by William Goldman's in 1973. Inigo hails from the village called Arabella and he was raised by his father Domingo Montoya, who was a master craftsman that makes sword.

In The Princess Bride, Inigo had a swordfight with a man in black (masked man) and they have the following things in common:

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Answer:

YES.

Explanation:

The atomic number is the number of protons. Because the number of protons is EQUAL to the number of electrons, they're basically equal.

Answer:

1. Is false

2. Is true

3. B, D, and C represents the release of Carbon Dioxide.

4. is Arrow E

Explanation:

1. is false because arrow C is coming up from the mechanical energy.

2. is true because the sun is known as solar energy and it's giving the plants chemical energy known as food for photosynthesis.

3. arrow C represents the release of carbon dioxide because factories make carbon dioxide to vent outside. B also represents the release of Carbon Dioxide because it is coming out of the clouds and into the tree. D is also representing this because it is coming out of the clouds and into the water.

4. is arrow E because dead organisms die and the carbon seeps into the ground to reach the fossils and fossil fuels.

hope it helps. I will write 5 later.

Answer:

They both orbit the sun

Explanation:

They are both celestial bodies orbiting our Sun.

Answer: granitic rocks

Explanation: Continental crust is composed of granitic rocks which are made up of relatively lightweight minerals such as quartz and feldspar. By contrast, oceanic crust is composed of basaltic rocks, which are much denser and heavier.

Answer:

Granites

Explanation:

Continental plates are made from different type of granites as well.

:)