The sound from a single source can reach point O by two different paths.One path is 20.0m long and the second path is 21.0m long.The sound destructively interferes at point O. What is the minimum frequency of the source if the speed of sound is 340m/s?
A. 340 Hz
B. 6800 Hz
C. 520 Hz
D. 170 Hz
Answers
The minimum frequency of the source if the sound destructively interferes at point O is 170 Hz. Therefore, option D is the correct answer.
When two sound waves of the same frequency encounter each other, they either amplify or cancel each other out based on the phase difference between them. The principle of superposition applies to waves; when two waves of the same frequency meet at a point, the displacement of the medium at that point is the sum of their individual displacements. When the displacements of the waves have the same magnitude but opposite directions, destructive interference occurs. For destructive interference to occur, the phase difference between the two waves must be 180°.
Destructive interference of two waves with equal amplitudes occurs when the path difference between the two waves is equal to an odd integer number of half-wavelengths (λ/2) of the waves. The shortest distance between two points is the straight line connecting them, so the difference in path length between the two waves can be calculated using the Pythagorean theorem. Using the values provided in the question:
Difference in Path Length = 21 m - 20 m = 1 m
For destructive interference, the difference in path length should be an odd integer multiple of half-wavelengths (λ/2) of the sound wave. The frequency of the sound wave can be calculated using the speed of sound and the wavelength of the wave: f = v/λ
Given:v = 340 m/s
λ/2 = 1 m ⇒ λ = 2 m
So, f = v/λ= 340 m/s / 2 m = 170 Hz
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Related Questions
1. The mass defect of iron-56 is 0.52875 amu. What is the energy equivalent of this mass?
2. Lead-208 has a mass defect of 1.75784 amu. What is the energy equivalent of this mass?
3. Uranium-238 has a mass defect of 1.93538 amu. What is the energy equivalent of this mass?
4. Having analyzed the three problems above, what is the relationship between mass and energy?
Answers
Answer:
Hello! Your answer is BELOW
Explanation:
1.About 91.754% of all iron is iron-56. Of all nuclides, iron-56 has the lowest mass per nucleon. With 8.8 MeV binding energy per nucleon, iron-56 is one of the most tightly bound nuclei.
2.The atomic weight of lead is quite variable in nature because the three heaviest isotopes are the stable end-products of the radioactive decay of uranium (238U to 206Pb and 235U to 207Pb) and thorium (232Th to 208Pb).
3.Mass defect for uranium-238 is 3.983 × 10-25 kg.
4.Energy and Mass Are Relative
The equation E = mc^2 states that the amount of energy possessed by an object is equal to its mass multiplied by the square of the speed of light.
Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥
!! i will mark as brainliest so pls answer quick !!
The student becomes negatively charged because of the friction between her socks and the carpet.
Explain why the friction causes the student to become charged
Answers
Answer:
A student becomes negatively charged because of the friction between his socks and the carpet. ... The electrons get rubbed and move towards the carpet so the carpets electrons move away and the student becomes negatively charged.
A 20 kg mass is hanging on one side of a pulley and a 5 kg mass is hanging on the other. Determine the acceleration of each mass.
Answers
Answer:
i believe it's 7
Explanation:
Low-energy lightbulbs currently cost $3.60, have a life of 9 years, and currently use $2.00 of electricity per year. Conventional lightbulbs are cheaper to buy; they currently cost only $0.60. On the other hand, they last only 1 year and currently use $7.00 of electricity per year. If the real discount rate is 4%, what are the EACs for each lightbulb? Which lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb? a. EAC( Low-energy lightbulb )=2.48 EAC( Conventional lightbulb )=7.62 Low-energy lightbulb is cheaper to operate b. EAC( Low-energy lightbulb )=3.60 EAC( Conventional lightbulb )=0.60 Conventional lightbulb is cheaper to operate c. EAC( Low-energy lightbulb) =2.00 EAC( Conventional lightbulb )=7.33 Low-energy lightbulb is cheaper to operate d. EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate
Answers
EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D
Energy cost calculationTo calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.
The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.
For the low-energy lightbulb:
EAC = Cost of bulb + Present value of annual electricity cost
= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)
≈ $18.47
For the conventional lightbulb:
EAC = Cost of bulb + Present value of annual electricity cost
= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)
≈ $7.33
Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.
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Electricity is produced by the movement of which?
Answers
Answer:
Electrons is your answer
Explanation:
Answer:
Electrons!
Explanation:
Electricity is the energy generated by the movements of electrons (negative charge) and positrons (positive charge) within conductive materials.
Hope this helps! <3
Make A CER about this Question --> as an asteroid collided with Earth in the ancient past and what were the effects of this collision? PLEASE HELP PLEASE PLEASE PLEASE PLEASE PLEASE !
Answers
It is widely believed that an asteroid impact was responsible for the extinction of the dinosaurs and many other species, which took place approximately 65 million years ago.
What are the effects of collision of the asteroids?The exact effects of this collision would have been massive, including:
A massive shockwave that would have caused widespread destruction and firesA tsunamis that would have flooded coastlinesA massive release of dust and debris into the atmosphere, blocking out the sun and causing a cooling of the planetA release of massive amounts of heat and energy, which would have caused massive fires and further atmospheric disruption.These events likely had a significant and long-lasting impact on the Earth's environment and ecology, and led to one of the largest mass extinctions in Earth's history.
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a string that is under 49.0 n of tension has linear density 4.70 g/m . a sinusoidal wave with amplitude 2.50 cm and wavelength 1.50 m travels along the string.
Answers
A string that is under 49.0 n of tension has linear density 4.70 g/m . a sinusoidal wave with amplitude 2.50 cm and wavelength 1.50 m travels along the string is Vmax = 10.675.
To find the maximum velocity, the given values are,
Density = 4.70 g/m
Amplitude = 2.50 cm
Wavelength = 1.50 m
Force = 49 N.
What is sinusoidal wave?Sinusoidal wave in graphical representation of linear projection of an object moving with SHM. Sine Wave Characteristics are, Amplitude Period or frequencyPhaseAmplitude Represents strength or magnitude of vibration over time.Period and Frequency are Inversely related - as period increases (gets longer), frequency decreases (gets lower) - as period decreases (gets shorter), frequency increases (gets higher)velocity of wave v = √t/μ
v = √49/√4.7 * 10^-3
= 102.1 m/s
w = 2 π f
= 2 π (v/λ)
= 2 π (102.1/1.5)
= 427.04
Max speed Vmax = Aw
Vmax = 2.50 * 10^-2 *427.04
Vmax = 10.675
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Yuki is studying the diet of owls. While dissecting owl pellets, she takes detailed notes about the bones that she finds. She organizes the bones she finds into different types of animals. When she finishes, she creates a food web to show what she has learned. Which scientific skills did Yuki use?
Check all that are true.
A. classifying
B. observing
C. evaluating
D. making models
Answers
A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the coefficient of kinetic friction between the block and the surface?
Answers
Answer:
The coefficient of kinetic friction between the block and the surface is 0.127.
Explanation:
Given that,
The mass of a block, m = 4 kg
The acceleration of the block, a = -1.25 m/s²
We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :
\(F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127\)
So, the coefficient of kinetic friction between the block and the surface is 0.127.
Jeriah places two metal cubes in contact with each other. Energy and heat flow from Cube A to Cube B. What conclusion can be drawn regarding Cube A?
It is cooler than Cube B.
It is smaller than Cube B.
It is warmer than Cube B.
It is larger than Cube B.
Answers
Answer:
C. It is warmer than Cube B.
Explanation:
Option C would be correct because energy as heat flows from warmer objects to cooler objects. If heat flows from Cube A to Cube B, then Cube A must be warmer than Cube B.
Reasoning behind the other option being incorrect:
D: This is incorrect because the direction of heat flow does not depend on the relative size of the cube.
A: This is incorrect because energy as heat would flow from Cube B to Cube A if Cube A is cooler than Cube B.
B: This is incorrect because the direction of heat flow does not depend on the relative sizes of the cubes also.
servicing mvac systems on hybrid and electric vehicles requires
Answers
Servicing MVAC (Mobile Air Conditioning) systems on hybrid and electric vehicles typically requires specialized knowledge and equipment due to the unique characteristics of these vehicles.
Training and Certification: Technicians should undergo specific training and obtain relevant certifications for working on hybrid and electric vehicles.Safety Precautions: Hybrid and electric vehicles have high-voltage systems that pose potential risks.System Knowledge: Hybrid and electric vehicles may have different MVAC system designs and components compared to traditional gasoline-powered vehicles. Equipment: Specialized tools and equipment may be required to service MVAC systems on hybrid and electric vehicles. Software and Diagnostics: Hybrid and electric vehicles often rely on complex control systems, which require diagnostic software and tools to identify and address MVAC-related issues. Environmental Considerations: Hybrid and electric vehicles are designed to be environmentally friendly, so it's crucial to handle refrigerants properly. Manufacturer Guidelines: Each hybrid and electric vehicle manufacturer may have specific service guidelines and procedures for their MVAC systems.Learn more about electric vehicle here : brainly.com/question/30714733
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A Motorcyclist Who Is Moving Along An X Axis Directed Toward The East Has An Acceleration Given By A = (6.1 - 2.0t) M/S2 For 0 T 6.0 S. At T = 0, The Velocity And Position Of The Cyclist Are 3.1 M/S And 7.3 M. (A) What Is The Maximum Speed Achieved By The Cyclist And What Total Distance Does He Travel Between 0 And 6.0s?
A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.1 - 2.0t) m/s2 for 0 t 6.0 s. At t = 0, the velocity and position of the cyclist are 3.1 m/s and 7.3 m. (a) What is the maximum speed achieved by the cyclist and what total distance does he travel between 0 and 6.0s?
Answers
The total distance traveled by the cyclist between 0 and 6.0 s is 37.435 m.
A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.1 - 2.0t) m/s2 for 0 t 6.0 s. At t = 0, the velocity and position of the cyclist are 3.1 m/s and 7.3 m. We can use the following kinematic equations of motion to solve the problem: v = u + at
Here, v, u, a and t represent final velocity, initial velocity, acceleration, and time, respectively. s = ut + 0.5 at²Here, s, u, a, and t represent displacement, initial velocity, acceleration, and time, respectively.
(a)To find the maximum speed of the cyclist, we first need to find the time at which the acceleration becomes zero. Therefore, 6.1 - 2.0t = 0⇒ t = 3.05s
Now, we can find the maximum speed using the kinematic equation: v = u + at= 3.1 + (-2.0 × 3.05)= -3.8 m/s
Therefore, the maximum speed achieved by the cyclist is 3.8 m/s.(b)Total distance covered by the cyclist between 0 and 6.0 s is given by the area under the velocity-time graph in the given interval.
The velocity of the cyclist as a function of time is given by the following equation: v = 3.1 + (6.1 - 2.0t)⇒ v = 3.1 + 6.1 - 2.0t⇒ v = 9.2 - 2.0t
So, we can draw a velocity-time graph using the above expression. We have, Taking the area under the curve between 0 to 6.0 s, we get the total distance traveled by the cyclist between the time interval of 0 to 6.0s. We can find this area by breaking it down into two areas.
Area 1: It is a rectangle of width 3.05 s and height 3.8 m/s.
Area 2: It is a trapezium with the following parameters: Height = (9.2 - (-3.8)) m/s = 13 m/s Width = (6 - 3.05) s = 2.95 s Area of trapezium = 0.5 × (3.8 + 13) × 2.95= 25.575 m²
Total distance traveled = area of rectangle + area of trapezium= 3.05 × 3.8 + 25.575= 37.435 m
Therefore, the total distance traveled by the cyclist between 0 and 6.0 s is 37.435 m.
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4. A wave with a frequency of 30 Hz has a wavelength of 5 meters. At what speed will the
wavelength travel?
Answers
Answer:
6 m/s
Explanation:
A boat travels between two cities that are 15 miles apart. When going downstream, with the current, the trip takes (3)/(4) hour (s). Returning upstream, against the current, the boat covers the same distance in (3)/(2) hour (s).
Answers
The speed of the boat in still water is (10)/(3) miles per hour, and the speed of the current is (5)/(6) miles per hour.
Let's denote the speed of the boat in still water as V and the speed of the current as C. We can use the formula Distance = Speed × Time to solve this problem.
When going downstream, the effective speed of the boat is V + C. The distance traveled is 15 miles, and the time taken is (3)/(4) hour. So we have the equation 15 = (V + C) × (3)/(4).
When going upstream, the effective speed of the boat is V - C. Again, the distance traveled is 15 miles, and the time taken is (3)/(2) hours. This gives us the equation 15 = (V - C) × (3)/(2).
We now have a system of equations:
(1) 15 = (V + C) × (3)/(4)
(2) 15 = (V - C) × (3)/(2)
We can solve this system of equations to find V and C. By solving the equations, we find that V = (10)/(3) miles per hour and C = (5)/(6) miles per hour.
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The potential energy of an apple is 6.0 Joules. The apple is 1.22m high. What is the mass of the apple?
Answers
Answer:
The mass of the apple is 0.49kg
Explanation:
Potential energy=mgh
P=mgh
6=m×1.22×10
6=12.2m
divide both sides by 12.2
m=6/12.2
m=0.49kg
When a solid compound dissolves in water
Answers
Answer:
The solid separates and disperse uniformly throughout the solution.
how far does an object move in 1 second
Answers
It accelerates at about 32 feet per second every second, so it starts falling at zero feet per second and, one second later it is traveling at 32 feet per second. That means that its average speed is 16 feet per second, so it will fall 16 feet in the first second.
The velocity, v streamline flow depends on the radius r of the tube, the density,d and viscosity coefficient n. Use dimension analysis to obtain the expression for v
Answers
The expression for v in terms of r, d, and n is:
v = k * r^2 * √(d) * n, where k is a dimensionless constant.
How do we calculate?The dimensions of velocity are length/time, the dimensions of radius are length, the dimensions of density are mass/volume, and the dimensions of viscosity coefficient are mass/(length*time).
Applying this dimensions, we have the following equation:
v = k * (r^a) * (d^b) * (n^c)
Find the values of a, b, and c, we can equate the dimensions on both sides
On the left-hand side, the dimensions of velocity are [L]/[T].
On the right-hand side, the dimensions of k are dimensionless, the dimensions of r^a are [L]^a, the dimensions of d^b are [M]/[L]^3, and the dimensions of n^c are [M]/([L]*[T])^c.
So, equating the dimensions, we get:
[L]/[T] = k * [L]^a * [M]^b / [L]^(3b) * [M]^(c/[T]^c
[L]/[T] = k * [M]^b * [L]^(a-3b) * [T]^(-c)
Equating the dimensions on both sides, we can form the following system of equations:
a - 3b = 1 (for length dimension)
b = 1/2 (for mass dimension)
-c = -1 (for time dimension)
Solving for a, b, and c, we get:
a = 2
b = 1/2
c = 1
we then have it as :
v = k * r^2 * √(d) * n
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PLS HELP MEH!!!!
Sound travels fastest in
a) air
b) water
c) glass
d) diamond
WILL MARK BRAINLIEST IF ANSWER
Answers
Answer:
hope this helps
Explanation:
Of the three phases of matter (gas, liquid, and solid), sound waves travel the slowest through gases, faster through liquids, and fastest through solids
so your answer would be B.
A 2 kg block is at rest on the top of a 20 m long rough ramp inclined at 20° with a
coefficient of kinetic friction of 0.6. If an albino Alabaman accordion player does 40 J of
work on the block down the ramp over 12 nm, how far down the ramp does the block
slide?
Answers
The block slides 2.37 meters down the ramp.
What is friction?The force preventing solid surfaces, fluid layers, and material components from sliding past one another is known as friction.
The mass of the block: m = 2 kg.
Height of the ramp: h = 20 meter.
Angle of the ramp: α = 20°
coefficient of kinetic friction: μ = 0.6
Hence, frictional force f= μmg cosα = 0.6 × 2 × 9.8 × cos20° N = 10.18 N.
Total work done in sliding a distance l is = mglsinα + fl
= ( 2 × 9.8 × sin20° + 10.18) l
= 16.88 l joule.
But work done is 40 J.
Hence, the distance slides by the ramp = 40/16.88 meter = 2.37 meters.
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The proportion between the friction force and the normal force that a body travelling on a dry, uneven surface experiences is known as the kinetic friction coefficient (k). A very clever process may be used to determine k with a high degree of accuracy.
What role of coefficient of kinetic friction?We may use the equation for work to determine how far the block travels down the ramp. Which is W = Fd, where W is the amount of work completed, F is the amount of force used, and d is the length of time the force was used.
The equation can be used to determine the force in this situation, which is the force of kinetic friction. The formula for kinetic friction is kinetic friction = uk * N, where N is the normal force and uk is the coefficient of kinetic friction.
The normal force is equal to the weight of the block, which is mg, where m is the mass of the block and g is the acceleration due to gravity.
Substituting these values into the equation for work and rearranging to solve for d, we get:
d = W / (kinetic friction× cos(θ))
= 40 J / [(0.6 × 2 kg * 9.8 m/s^2) * cos(20°)]
= 40 J / [(11.76 N) * cos(20°)]
= 40 J / 10.45 N
= 3.84 m
Therefore, the block slides a distance of approximately 3.84 meters down the ramp.
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A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Answers
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
From the scattering of sunlight, J.J. Thomson calculated the classical radius of the electron as having the value 2.82 × 10⁻¹⁵m . Sunlight with an intensity of 500 W / m² falls on a disk with this radius. Assume light is a classical wave and the light striking the disk is completely absorbed.(a) Calculate the time interval required to accumulate 1.00eV of energy.
Answers
The time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.
To calculate the time interval required to accumulate 1.00 eV (electron volt) of energy from sunlight with an intensity of 500 W/m² falling on a disk with a radius of 2.82 × 10⁻¹⁵ m, we can use the equation:
Energy = Power * Time
Given:
Intensity (I) = 500 W/m²
Radius (r) = 2.82 × 10⁻¹⁵ m
Energy (E) = 1.00 eV
First, we need to calculate the total power received by the disk. Since the light is completely absorbed, we can assume that all the power is absorbed by the disk. The power can be calculated using the formula:
Power = Intensity * Area
The area of the disk can be calculated as follows:
Area = π * (radius)²
Substituting the values into the equation:
Area = π * (2.82 × 10⁻¹⁵ m)²
Next, we can calculate the power:
Power = Intensity * Area
= 500 W/m² * [π * (2.82 × 10⁻¹⁵ m)²]
Now we can solve for time:
Time = Energy / Power
= (1.00 eV) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]
To convert eV to joules, we use the conversion factor:
1 eV = 1.602 × 10⁻¹⁹ J
Substituting this conversion and the numerical values:
Time = (1.602 × 10⁻¹⁹ J) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]
Therefore, the time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.
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A toy car is placed at 0 on a number line. It moves 9 cm to the left, then 4 cm to the right, and then 6 cm to the left. What is the total distance the toy car traveled?
1 cm
5 cm
11 cm
19 cmis the displacement of an object during a specific unit of time.
Answers
The total distance the toy car traveled is D. 19cm
Calculations and ParametersThe total distance of the toy car traveled in cm would be calculated
We would add the sum:
D = 9 + 4 + 6 cm
D = 19 cm
Therefore, the total distance the toy car traveled in cm is 19 cm.
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No Attempt How long, in seconds, must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains. )
Answers
Zorch must push with the force of 1.8 x 10^6 N for 62.5 seconds to accomplish his goal of moving the moon out of Earth's orbit.
To calculate the time Zorch must push with the given force, we use the formula: Work = Force x Distance.
The work required to move the moon out of Earth's orbit is the gravitational potential energy difference between the moon and Earth. This is calculated as:
Work = G x Mm x Me / R
where G is the gravitational constant, Mm is the mass of the moon, Me is the mass of Earth, and R is the distance between the centers of the two bodies.
Solving for R, we get R = 3.83 x 10^8 m.
The force required to move the moon is the gravitational force between the moon and Earth, which is calculated as:
Force = G x Mm x Me / R^2
Substituting the values we get, Force = 1.8 x 10^6 N.
Finally, using the formula Time = Work / Power, with Power = Force x Velocity, and assuming constant velocity, we get the time as 62.5 seconds. Therefore, Zorch must push with a force of 1.8 x 10^6 N for 62.5 seconds to accomplish his goal.
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90. An uranium nucleus (at rest) undergoes fission and splits into two fragments, one heavy and the other light. Which fragment is moving faster after the fission?
Answers
Answer:
Explanation:
No external force is acting on uranium nucleus so we can apply law of conservation of momentum . If M and m be the mass of bigger and smaller fragments respectively and V and v be their velocity after fission , Total momentum after fission = total momentum before fission
MV - mv = 0 , since the nucleus was at rest , its momentum before fission is zero . negative sign of mv is taken because smaller fragment will move in opposite direction to that of bigger fragment .
MV = mv
M / m = v / V
M > m
Hence,
v > V
So velocity of smaller fragment will be higher .
how to know give reason of force
Answers
If you double the distance between you and the center of Earth, what happens to the strength of the gravitational field you experience?
Answers
Answer:
The strength of gravity decreases.
An example of that would be if you were in space; you float around because there's no gravity.
Which one is series and which one is parallel ( i give 20 points who answer )
Answers
Answer:
figure (a) L1 is series and L2 is parallel to L3
figure (b) L2 and L3 are parallel to L1
7) Find F1 and F2
HELP PLEASEEE
Answers
The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.
If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.
The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.
F2 = 45 cos 30 = 38.9 N.
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Model Universes Table 5.1 Curved, matter-dominated universes. Density Curvature Ultimate fate 20 <1 20 = 1 20 > 1 x= -1 K=0 * = +1 Big Chill (a « 1) Big Chill (a o 12/3) Big Crunch ensity is less than or density, the universe will end in a fiery Big Crunch; if the density is les equal to the critical density, the universe will end in an icy Big Chill. In a curved universe containing only matter, the scale factor act) computed explicitly. The Friedmann equation can be written in the form ä? 20 + (1 - 920), Наа (5.88) so the age of the universe at a given scale factor a is given by the integral da Hot=1 (5.89) Jo [20/a + (1 -20)]1/2 When 20 + 1, the solution to this integral is most compactly written in a para- metric form. The solution when S20 > 1 is (0) = 20 2:20 - 1 009) (5.90) and f(0) = 2H (20 - 1) 2H. (20 - 1)3/2 (0 - sine), (5.91) where the parameter 8 runs from 0 to 27. Given this parametric form, the time that elapses between the Big Bang ate = 0 and the Big Crunch at 8 = 27 can be computed as - 20 crunch = (5.92) H. (20 - 1)3/2 A plot of a versus t in the case S20 = 1.1 is shown as the dotted line in Figure 5.4. The a o 1/3 behavior of an 20 = 1 universe is shown as the solid line. The solution of Equation 5.89 for the case 20 < 1 can be written in paramet- ric form as a(n) = 21 - (cosh n-1) (5.93) and t(n) = (n) = 2H. (1-52 1 2 2H (1 – 2 3/2 (sinh 7 - 7), (5.94)
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The age of the universe in the cases where the curvature parameter (K) is equal to 0, less than 1, or greater than 1.
How they can be predicted based on their density and curvature parameters?If the density of the universe is greater than or equal to the critical density, the universe is said to be "closed" or "overdense," and its ultimate fate will be a "Big Crunch" - a fiery collapse into a singularity.
If the density is less than the critical density, the universe is said to be "open" or "underdense," and its ultimate fate will be a "Big Chill" - a gradual cooling and expansion until all matter becomes too diffuse to support further structure formation.
The passage goes on to describe how the age of the universe at a given scale factor (a measure of how the universe has expanded or contracted over time) can be calculated using the Friedmann equation.
The specific equations given in the excerpt allow for the calculation of the age of the universe in the cases where the curvature parameter (K) is equal to 0, less than 1, or greater than 1.
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