The table (below) shows the amount of fuel left in your RV while driving. What type of function can you use to model the data? Estimate the amount of fuel left in your tank after driving for 90 minutes.

Im a lil confused someone help explain the problem please :)

Answer:

-17, -16, -14, -12, -7

q≥ -17

Step-by-step explanation:

Start by solving the inequality

4q≥ -68

q≥ -17

Now just select all the numbers that are greater than or equal to -17

-17, -16, -14, -12, -7

The equivalent inequality would be what was solved for

q≥ -17

Answer:

$16.5

Step-by-step explanation:

$30-$8-$3.85-$1-$1 = $16.5

The domain is all real numbers, and the range is all real numbers greater than or equal to -4. So, correct option is A.

The given function f(x) = (x + 2)(x + 6) is a quadratic function, and its graph is a parabola that opens upwards. We are given that the vertex of the parabola is at (-4, -4), and it passes through the points (-6, 0) and (-2, 0).

The domain of a function is the set of all possible input values for which the function is defined. Since this is a polynomial function, it is defined for all real numbers. Therefore, the domain of the function f(x) is all real numbers.

The range of a function is the set of all possible output values that the function can take. Since the parabola opens upwards and its vertex is at (-4, -4), the lowest point on the graph is at (-4, -4), and it extends infinitely upwards. Therefore, the range of the function f(x) is all real numbers greater than or equal to -4.

Hence, the correct option is A).

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Complete question is:

The graph of the function f(x) = (x +2)(x + 6) is shown below.

On a coordinate plane, a parabola opens up. It goes through (- 6, 0), has a vertex at (- 4, - 4), and goes through (- 2, 0).

What is true about the domain and range of the function?

A) The domain is all real numbers, and the range is all real numbers greater than or equal to –4.

B) The domain is all real numbers greater than or equal to

–4, and the range is all real numbers.

C) The domain is all real numbers such that –6 ≤ x ≤ –2, and the range is all real numbers greater than or equal to –4.

D) The domain is all real numbers greater than or equal to

–4, and the range is all real numbers such that –6 ≤ x ≤ –2.

the general equation of a graph is given by

y = mx + c

where m= slope

c=intercept

the equation given is

9x-5y=4

make y subject of formula

9x-4=5y

5y=9x-4

divide through by 5

y=9/5x-4/5

comparing with the general equation

mx=9/5x

m=slope=9/5

The output for given block of code will be as mentioned in option B) Three values of roots (b-)

Based on the provided code snippet, it appears to be MATLAB code. The code assigns the polynomial coefficients `[1 3 2]` to the variable `P` and then uses the `roots()` function to calculate the roots of the polynomial.

Let's execute the code and determine the output:

```matlab

P = [1 3 2];

r = roots(P);

disp(r);

```

The output will be:

```

-1

-2

```

Therefore, the correct answer is:

B) Three values of roots (b-)

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Answer:

7.1-7y

Step-by-step explanation:

5-4-7y+6.1

7.1-7y

Step-by-step explanation:

Circumference of a circle is 2piR

C=2piR and R=10

C=2(3.14)(10)

So the circumference is 62.8 cm

The number of cans required to paint an area of 2000 square units is equal to 5 cans.

As given in the question,

Total area to be painted is equal to 2000 square units.

Area covered by one can of paint is equal to 400 square units

400 square units = 1 can of paint

⇒ 1 square units = ( 1 / 400 ) cans of paint

⇒ 2000 square units =  ( 2000 / 400 ) cans of paint

⇒ 2000 square units = 5 cans of paint

Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.

The above question is incomplete, the complete question is:

How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?

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Answer:

9

Step-by-step explanation:

First, write an equation, since there are 12 months in a year, you can divide 12 by 4 because the rose bush grows 3 inches every 4 months.

The equation would be 3(3)=9

The correct answer is D) depreciate; appreciate. When a country experiences a high inflation rate, its currency loses its value relative to other countries with lower inflation rates.

As a result, the exchange rate of the high inflation country's currency to the US dollar tends to decrease, i.e., depreciate. Conversely, when a country has a low inflation rate compared to the US, its currency gains value relative to the high inflation country's currency. Therefore, the exchange rate of the low inflation country's currency to the US dollar tends to increase, i.e., appreciate.

Inflation is a measure of the rate at which prices of goods and services are rising in an economy. A high inflation rate can lead to a loss of confidence in a country's currency, which can cause investors and businesses to withdraw their money from the country.

This reduction in demand for the currency leads to a decrease in its value relative to other currencies, resulting in a depreciating exchange rate. On the other hand, a low inflation rate signals economic stability and can increase confidence in a country's currency. This increased confidence leads to a rise in demand for the currency, causing an appreciation of the exchange rate.

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The correct answer is 2 (C) - 2 days is the total slack for activity F. To determine the total slack for activity F, we need to calculate the slack for each activity in the network. Slack refers to the amount of time an activity can be delayed without affecting the project completion time.

1. First, let's draw the network using the information provided:
  - A is the start node and G is the stop node.
  - Activity A has a duration of 5 days and has no predecessor.
  - Activities B, C, and D have durations of 8, 7, and 6 days respectively, and their predecessors are A.
  - Activity E has a duration of 9 days and its predecessors are B, C, and D.
  - Activity F has a duration of 10 days and its predecessors are B, C, and D.
  - Activity G has a duration of 5 days and its predecessors are E and F.

                 A
                /|\
               / | \
              /  |  \
             B   C   D
              \  |  /
               \ | /
                \|/
                 E
                 |
                 F
                 |
                 G

2. Now, let's calculate the slack for each activity:
  - Slack is calculated by subtracting the earliest start time of an activity from the latest start time without delaying the project completion time.
  - The earliest start time for activity F is 17 days.
  - The latest start time for activity F is 19 days (project completion time is 22 days).
  - Total slack for activity F = latest start time - earliest start time = 19 - 17 = 2 days.

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Answer:

It's where they meet! I can't really see the coordinate clearly, but if I could I would tell you already.

By using the principle of inclusion-exclusion, The number of people who said they liked both cats and dogs is 111.

Let's break down the given information:

Total number of respondents (n) = 350

Number of people who like dogs (A) = 186

Number of people who like cats (B) = 193

Number of people who don't like cats or dogs (Neither) = 42

To find the number of people who like both cats and dogs, we can use the principle of inclusion-exclusion. We add the number of people who like dogs (A) and the number of people who like cats (B), and then subtract the number of people who like neither cats nor dogs.

Number of people who like both cats and dogs = A + B - Neither

Number of people who like both cats and dogs = 186 + 193 - 42 = 337 - 42 = 111

Therefore, the number of people who said they liked both cats and dogs is 111.

Out of the 350 people surveyed, 111 of them said they liked both cats and dogs. This indicates that there is a subset of individuals who have an affinity for both types of pets.

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Answer:

not equivalent to meteorologists ratio

Step-by-step explanation:

meteorologists ratio is

rainy days : sunny days = 2 : 5

last months weather is

rainy days : sunny days

= 10 : 20 ( divide both parts by LCM of 10 )

= 1 : 2 ← not equivalent to 2 : 5

The G force for particles rotating at 2000 rpm when the distance from the axis of rotation to the particle is 0.1 m is 4,335.5.

Given,The diameter of the microcarrier = 250 μm

The density of the microcarrier = 1.02 g/cm3

The volume of the culture = 50 liters

The height of the culture = 1 m

The density of the culture solution without microcarrier = 1.00 g/cm3

The viscosity of the culture solution without microcarrier = 1.1 cP

To find,The time needed to settle the cells completely

Formula used,Vs = 2g(ρp - ρm)/9μ

Where,Vs = Settling velocity

g = acceleration due to gravityρ

p = density of particleρ

m = density of medium

μ = viscosity of medium

Calculation,

Volume of the microcarrier,V = 4/3πr3V

= 4/3 × π × (250 × 10-6/2)3

V = 8.68 × 10-12 m3

Mass of the microcarrier,

m = ρV = 1.02 × 8.68 × 10-12m

= 8.85 × 10-12 kg

Radius of the microcarrier,r = 250 × 10-6/2 =

125 × 10-6 m

Total mass of the system = Mass of microcarrier + Mass of culture solution without microcarrierM

= m + ρV

= 8.85 × 10-12 + 1.00 × 50 × 10-3M

= 8.9 × 10-11 kg

Density of the system,ρ = M/V = 8.9 × 10-11/(π/4 × 1 × 12)

= 1.2 kg/m3 (Approx)

Viscosity of the system,μ = 1.1 × 10-3 Pa.s

= 1.1 × 10-6 N.s/m2

Settling velocity,Vs = 2g(ρp - ρm)/9μ

= 2 × 9.81 (1200 - 1020)/(9 × 1.1 × 10-6)

Vs = 70.87 × 10-3 m/s

Height of the culture left after settling,

h = height of culture - height of the microcarrier

= 1 - (250 × 10-6) = 0.99975 m

Time taken to settle completely,

t = h/Vst = 0.99975/0.07087

t = 14091.2 sec = 3.91 hours (Approx)

Therefore, the time needed to settle the cells completely is 3.91 hours (Approx).

Given,Rotational speed, ω = 2000 rpm

= 209.44 rad/s

Distance from the axis of rotation to the particle, r = 0.1 m

To find,G force, G

Formula used,

G = rω2/G

Calculation,

G = rω2/G

= 0.1 × 209.442/9.81G

= 4,335.5

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The length of the Interior diagonal of the box is approximately 17.60 inches when rounded to the nearest hundredth.

The length of the interior diagonal of the box, we can use the Pythagorean theorem.

The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the base and height of the box form two sides of a right triangle, and the diagonal is the hypotenuse.

The base of the box is 10 in., the height is 14.5 in., and the diagonal is the unknown value we need to find.

Using the Pythagorean theorem, we can write the equation:

diagonal^2 = base^2 + height^2

Let's substitute the given values into the equation:

diagonal^2 = 10^2 + 14.5^2

diagonal^2 = 100 + 210.25

diagonal^2 = 310.25

To find the length of the diagonal, we take the square root of both sides of the equation:

diagonal = √310.25

Using a calculator, we find that the square root of 310.25 is approximately 17.60.

Therefore, the length of the interior diagonal of the box is approximately 17.60 inches when rounded to the nearest hundredth.

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a) There are 8,145,060 possible outcomes when drawing five balls numbered 1 to 43.

b) There are 23 possible outcomes when drawing one ball numbered 1 to 23.

c) The probability of hitting a jackpot guessing all 6 numbers correctly is 1/186,492,840.

a) In this case, we want to choose 5 balls from a set of 43 balls, so we can calculate the total number of possible outcomes as:

⁴³C₅ = 43! / (5! * (43-5)!) = 43! / (5! * 38!) = 8,145,060

b) In this case, we want to choose 1 ball from a set of 23 balls, so we can calculate the total number of possible outcomes as:

²³P₁ = 23! / (23-1)! = 23

c) To calculate the probability of hitting a jackpot by guessing all six numbers correctly, we need to calculate the probability of each individual event and then multiply them together.

The probability of correctly guessing all five balls numbered 1 to 43 is:

1/8,145,060

The probability of correctly guessing the single ball numbered 1 to 23 is:

1/23

Therefore, the probability of hitting the jackpot by correctly guessing all six numbers is:

(1/8,145,060) * (1/23) = 1/186,492,840

This means that the chances of winning the jackpot in this lottery are approximately 1 in 186.5 million.

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Answer:

D

Hope this helped!

Happy Halloween!

Answer:

3/5

Explanation:

-

Answer:

2^4 or 4^2

Step-by-step explanation:

2^4= 2x2x2x2=16

4^2= 4x4=16

Step-by-step explanation:

Integrate with respect to 't'  the accel function to get the velocity function:

velocity =   v/7  t   + c1       when t = 0     this =1    so  c1 = 1

velocity =  v/7  t  +  1         integrate again to find position function

s =  v/14 t^2 + t + c2     when t = 0   this equals 2   so   c2 = 2

s = v/14  t^2  + t  + 2

( Let me know if this is incorrect and I will re-evaluate)

No, a fraction is not a term. The distributive property can be applied to fractions because it is a general mathematical principle.

A fraction is not considered a term in the traditional sense. It is a mathematical expression that represents division. However, the distributive property can still be applied to fractions because the property itself is a fundamental rule of arithmetic that extends beyond specific types of expressions.

The distributive property states that for any real numbers a, b, and c:

a × (b + c) = (a × b) + (a × c).

When working with fractions, we can apply the distributive property as follows:

Let's consider the expression: a × (b/c).

We can rewrite this as: (a × b)/c.

Now, let's distribute the 'a' to 'b' and 'c':

(a × b)/c = (a/c) × b.

In this step, we applied the distributive property to the fraction (a/c) by treating it as a whole.

Although fractions represent division, we can still use the distributive property because it is a general mathematical principle that allows for manipulating expressions involving addition, subtraction, multiplication, and division.

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Answer:

the least common denominator is 12

Answer:

a = -1
b = -9

Step-by-step explanation:

when x = -2 put -2 for x in the equation:

a(3- (-2)) = -2*(-2) + b and then solve
a(3+2) = 4+b
5a = 4+b

then look at the numbers in the box and try for which number this equation will work. when you put a = -1 and b = -9 you will see it is equal on both sides because each side is -5

Answer:

Step-by-step Solution:

Hence, Option D is correct.

The number of square feet that the seed cover per pound is given as follows:

168 square feet per pound.

The number of square feet that the seed covers per pound is obtained applying the proportions in the context of this problem.

The term proportion is used because the number of square feet that the seed covers per pound is given by the division of the total area by the number of pounds in the bag.

The parameters for this problem are given as follows:

Hence the  number of square feet that the seed cover per pound is calculated as follows:

56/(1/3) = 56 x 3 = 168 square feet per pound.

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Answer:

Step-by-step explanation:

Pieces = 40/n

Pieces =  the number of pieces each student will get

n = the number of students in the class.

n

n has an upper limit of 40. Each student will get exactly 1 piece of candy

Other values of n could be

1 2 4 8 5 10 20 40

Answer:

2 candie each because if there 20 and 40 candie it well be 2:)`

Without yield management, the theatre's revenues would be $176,100.

To calculate the theatre's revenues without yield management, we need to determine the number of tickets sold for each fare class and multiply it by the corresponding ticket price. The number of low fare class tickets sold is not provided in the information, so we cannot determine the exact revenue for that fare class. However, since there is ample demand for the low fare class, it is reasonable to assume that all 1761 seats are sold at the discounted price of $75. Therefore, the revenue from the low fare class would be 1761 seats × $75 = $132,075. For the high fare class, the demand is normally distributed with a mean of 1200 and a standard deviation of 150. To maximize revenues, the theatre should sell as many high fare class tickets as possible. Assuming all remaining seats (1761 - number of low fare class tickets) are sold at the high fare of $100, the revenue from the high fare class would be (1761 - number of low fare class tickets) × $100. To calculate the exact number of high fare class tickets sold, we need to know the cutoff point for the demand distribution that separates high fare demand from low fare demand. Since this information is not provided, we cannot determine the exact revenue from the high fare class. However, the only answer option that is close to the estimated revenue considering all high fare class tickets sold is $176,100.

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