The technique of transcranial magnetic stimulation employs strong magnetic pulses at a particular site on the scalp. When it is used on the scalp near Area V1, the effect is
Answers
When transcranial magnetic stimulation (TMS) is used on the scalp near Area V1 (primary visual cortex), the effect is the modulation or disruption of visual perception.
TMS involves the use of strong magnetic pulses to induce electrical currents in specific regions of the brain. By targeting the scalp near Area V1, which is responsible for processing visual information, TMS can influence the functioning of this brain region.
The specific effects of TMS on visual perception can vary depending on the parameters of stimulation, such as the intensity, duration, and frequency of the magnetic pulses.
TMS can transiently disrupt or modulate the activity of neurons in Area V1, leading to alterations in visual processing.
Some of the effects that have been observed with TMS near Area V1 include:
Phosphene induction: Phosphenes are brief flashes of light or visual sensations experienced without external visual stimulation. TMS near Area V1 can elicit phosphenes, indicating the direct activation of visual cortical neurons.
Visual suppression: TMS can temporarily suppress visual perception by interfering with the normal processing of visual information in Area V1. This can lead to a reduction or loss of visual awareness or impairments in visual discrimination tasks.
Disruption of visual processing: TMS near Area V1 can interfere with specific aspects of visual processing, such as motion perception, object recognition, or spatial attention.
This disruption can provide insights into the functional organization of the visual cortex and its contribution to visual perception.
It's important to note that the effects of TMS can be highly localized and depend on the precise targeting of the magnetic pulses. Researchers and clinicians use TMS as a tool to study the functioning of the brain, investigate neural circuits, and explore the relationship between brain activity and perception.
To learn more about disruption, refer below:
https://brainly.com/question/26496230
#SPJ11
Related Questions
When you whirl a can at the end of a string in a circular path, what is the direction of the force you exert on the can?.
Answers
When you whirl a can at the end of a string in a circular path, the direction of the force you exert on the can will be towards the center .
A force that acts on a body moving in a circular path and directed towards the center around which the body is moving is called Centripetal force.
The force is toward the center of the circle. Because of one force named centripetal force , can is maintaining a circular motion , which is acting towards the center .
To learn more about centripetal force here :
https://brainly.com/question/14249440
#SPJ4
BROADCASTING Interference occurs when two waves pass through the same space at the same time. It is destructive if the amplitude of the sum of the waves is less than the amplitudes of the individual waves. Determine whether the interference is destructive when signals modeled by y=20sin (3t+45∘) and y=20sin(3t+225∘) are combined.
Answers
The interference is not destructive, the interference is constructive.
Interference can be constructive or destructive. When two waves pass through the same space at the same time, it is known as interference. If the amplitude of the sum of the waves is less than the amplitudes of the individual waves, then interference is destructive.
Hence, we have to determine whether the interference is destructive when signals modeled by y=20sin (3t+45∘) and y=20sin(3t+225∘) are combined.
In this case, the amplitude of both signals is the same. Hence, we can ignore the amplitude term and consider only the angle component.
The two signals can be rewritten in terms of the angle component as follows:
y1=3t+45°y2=3t+225°
To find the resultant of the two signals, we add the two signals:
yR=y1+y2=y1=3t+45°+y2=3t+225°=6t+270°
We know that the sine function repeats itself every 360 degrees. Hence, we can rewrite the above equation as:
yR=6t+270°=6t+360°−90°=6t−90°
From the above equation, the resultant signal can be written as: yR=20sin(6t−90°)To determine whether the interference is destructive or not, we check if the amplitude of the resultant wave is less than the individual waves.
Since the amplitude of each signal is 20, the amplitude of the resultant wave is also 20. Hence, the interference is constructive. This is because the two signals are exactly out of phase, and they interfere to create a stronger signal. Therefore, the interference is not destructive.
For more such question on interference visit:
https://brainly.com/question/23202500
#SPJ8
Which of the following is a location with a high probability of containing an electron?
O orbital
O proton
O Bohr
Answers
Answer:
The answer is orbitial! :))
Answer:
it's orbitial
Explanation:
A car starts from rest on a curve with a radius of 130m and tangential acceleration of 1.3m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 2.2m/s2 ?
Answers
A car starts to rest on a bend with a radius of 130 m and a tangential acceleration of 1.3. When the total acceleration of the car is 2.0m/s2, the car will move through an angle of 22.5°.
The turning radius is the distance required by the car to turn or turn around. Because of this, calculations are made from the moment the car makes a turn until it rotates in a semicircle or 180 degrees. Then, the distance from the diameter will be measured and used as the turning radius of the vehicle.
Radial acceleration (a') = √2² - √1.3²
Radial acceleration (a') = √4 - √1.69
Radial acceleration (a') = √2.31
Radial acceleration (a') = 1.5 m/s²
v = \(\sqrt{a' . r}\)
v = \(\sqrt{1.5 x 130}\)
v = \(\sqrt{195}\)
v = 14 m/s
Now,
d = v²/2a'
d = 14²/2(1.5)
d = 154/3
d = 51.3 m
Expression for circle central angular is:
θ = d/r
θ = 51.3/130
θ = 0.394 rad
θ = 22.5°
Learn more about tangential acceleration at https://brainly.com/question/11476496
#SPJ4
using hubble's law, what is the distance to a galaxy with a recession velocity of 25252 km/s in mpc? hubble's constant is 70 km/s/mpc. (round to the nearest whole number. answer with only the number, no units.)
Answers
The distance to the galaxy with a recession velocity of 25252 km/s is 17,67,640 km.
Distance is the length between two points or things, and it is directionless. Distance solely considers the entire magnitude and disregards the start and finish locations because it is a scalar attribute. Being a scalar attribute, distance can only be positive or zero; it cannot be the opposite. Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most common unit of measurement for distance (mm).
Given that,
Speed = 25252 km/s
Hubble's constant = 70 km/s/mpc
We know,
Speed = Distance/constant
Distance = Speed × constant
Distance = 25252 × 70
Distance = 17,67,640 km
To know more about distance:
https://brainly.com/question/29762130
#SPJ4
A 56.0 kgkg ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 1.50 turns each second. The distance from one hand to the other is 1.5 mm. Biometric measurements indicate that each hand typically makes up about 1.25 % of body weight.
a) What horizontal force must her wrist exert on her hand? Express your answer in newtons.
b) Express the force in part (a) as a multiple of the weight of her hand. Express your answer as a multiple of weight.
Answers
A ice skater making 1.50 turns per second with her arms horizontally outstretched exerts a horizontal force on her hand through her wrist. The force required was calculated to be approximately 667 N. This force is equivalent to about 156.9 times the weight of one hand.
a) The force required to maintain circular motion is given by:
F = mv²/r
where m is the mass of the ice skater, v is the speed of the ice skater, and r is the radius of the circular path. In this case, the radius is half the distance between the hands, or 0.75 m. The speed of the ice skater is equal to the circumference of the circular path divided by the period of one revolution:
v = 2πr/T = 2π(0.75 m)/(1.5 s) ≈ 9.42 m/s
The force required is therefore:
F = (56.0 kg)(9.42 m/s)²/(0.75 m) ≈ 667 N
b) To express the force in terms of the weight of her hand, we first need to calculate the weight of one hand:
weight of one hand = (1.25/100)(56.0 kg)/2 ≈ 0.4375 kg
Then, we can express the force as a multiple of the weight of one hand:
F = 667 N ÷ (0.4375 kg x 9.81 m/s²) ≈ 156.9 weight of one hand
Therefore, the horizontal force exerted by her wrist on her hand is approximately 667 N, and this force is equivalent to about 156.9 times the weight of one hand.
To know more about force, visit:
brainly.com/question/31046192
#SPJ11
a 0.313-kg mass is attached to a spring with a force constant of 51.7 n/m.
Answers
The period of oscillation of the system is 0.038 s.
The angular frequency of the system and the period of oscillation of a 0.313-kg mass attached to a spring with a force constant of 51.7 N/m are given as follows:
Angular frequency:
Angular frequency is defined as the ratio of the spring constant to the mass of an object and is denoted by the symbol ω. Mathematically, angular frequency, ω = k/mHere, the spring constant k = 51.7 N/m, and mass m = 0.313 kg. Substitute the values in the formula and solve for ω.ω = k/m = 51.7/0.313 = 165.1 rad/Therefore, the angular frequency of the system is 165.1 rad/s.Period of oscillation: The period of oscillation is defined as the time taken by the object to complete one full oscillation and is denoted by the symbol T. It is given by the formula: T = 2π/ωHere, ω = 165.1 rad/s.Substitute the values in the formula and solve for T.T = 2π/ω = 2π/165.1 = 0.038
Therefore, the period of oscillation of the system is 0.038 s.
know more about Angular frequency.
https://brainly.com/question/3654452
#SPJ11
Why can't you hear a sound in space ?
Answers
Answer:
As the vibrations of the particles reach your ear, your ear drum receives the vibrations which the brain then interprets as sound. In the vacuum of space, there are no (or very, very few) particles to vibrate, so sound cannot travel through this medium.
Explanation:
You are going to construct a new optical observatory, and money is no object. Other than putting it into space, what factors will affect your decision for its location on Earth?
Answers
Answer:
When choosing a location for a new optical observatory on Earth, there are several factors to consider. Some of the key factors include:
Atmospheric Conditions: The observatory must be located in an area with stable, clear, and dry atmospheric conditions. This is because atmospheric turbulence and water vapor can affect the clarity of the images obtained by the telescope.Light Pollution: The observatory should be located far away from sources of light pollution such as cities, airports, and highways. Light pollution can interfere with the ability of the telescope to capture clear images of the night sky.Altitude: Higher altitudes are generally better for astronomical observations, as the air is thinner and there is less atmospheric distortion.Accessibility: The observatory should be easily accessible for the transportation of personnel, equipment, and supplies. It is also important to consider factors such as the availability of electricity, water, and other resources.Stability: The observatory must be located in an area that is geologically stable, with minimal seismic activity, to avoid any damage to the telescope and its support structures.Taking into account these factors, some of the best locations for optical observatories on Earth are high-altitude sites in remote, dry, and mountainous areas, like Mauna Kea in Hawaii, Cerro Paranal in Chile, or Roque de los Muchachos Observatory in Spain!
A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
Answers
42000 kilometers
Explanation:
distance is velocity × time
28000 ×1.5
42000
remember to match units
thats why i wrote 1.5 hours instead of 90minutes
what is one limitation of using a saltwater aquarium to model the ocean?
A. It can show only a small part of the actual ocean.
B. It can show how different ocean animals interact with each other.
C. It can show how certain plants grow in the ocean.
D. It can show how light affects ocean organisms.
Answers
Using a saltwater aquarium to model the ocean has limitations, such as showing only a small part of the actual ocean and being unable to replicate the vastness and complexity of the ocean ecosystem.
Explanation:One limitation of using a saltwater aquarium to model the ocean is that it can only show a small part of the actual ocean. Since an aquarium is confined and limited in size, it cannot realistically replicate the vastness and complexity of the ocean ecosystem. For example, it may not have the space to accommodate large marine animals like whales or the turbulent currents that exist in the open ocean. Therefore, it is important to recognize that while a saltwater aquarium can provide some insights into the ocean, it cannot fully capture the dynamic nature and diverse interactions found within the entire ocean ecosystem.
Learn more about limitations of using a saltwater aquarium to model the ocean here:https://brainly.com/question/34788704
#SPJ2
Work is a _______ acting upon an object for a given ______. The amount of work done is equal to the change in ________ of the object.
Answers
Answer:
Work is a FORCE acting upon an object for a give DISTANCE. The amount of work done is equal to the change in KINETIC ENERGY of the object.
Explanation:
The answer is from the definition and equations for work:
Work = force*distance = change in kinetic energy
Answer:
energy
Explanation:
i took the quiz
what part of the electromagnetic spectrum lies between the ultraviolet region and the gamma ray region?
Answers
The part of electromagnetic spectrum lying between the ultraviolet region and the gamma ray region is x-rays.
The smallest known wavelengths and greatest frequency are found in gamma rays. They are the most piercing waves because they have high energy and can travel great lengths through air. X-rays have shorter wavelengths than UV radiation, but longer wavelengths than gamma radiation, making them more energetic.
The electromagnetic energy known as ultraviolet has a frequency of 30 PHz to 750 THz and a wavelength of 10 nm to 400 nm. These particles have wavelengths that are both shorter than visible light and longer than X-rays.
Thus, the x-ray area of the electromagnetic spectrum is located between the ultraviolet and gamma ray regions.
To know more about electromagnetic spectrum:
https://brainly.com/question/10737014
#SPJ4
A vehicle is traveling at a velocity of 30 meters per second. Exactly 5 seconds later, its velocity has changed by a factor of 0.6. What was the vehicles average acceleration over that time period?
Answers
Answer:
-2.4 m/s²
Explanation:
avg accel = Δv/Δt
v-i = 30 m/s
v-f = (30 m/s)(0.60) = 18 m/s
Δt = 5.0 sec
avg accel = (18 m/s - 30 m/s) / 5.0 s = (- 12 m/s) / 5 s = -2.4 m/s²
negative sign means it's slowing down
A 0. 820 kg mass is attached to a horizontal 2620 N/m spring. The mass is pulled 0. 340 m from its equilibrium position and acts as a simple harmonic oscillator. What is the period of the oscillations?
Answers
The period of oscillations for the given mass-spring system is approximately 0.350 seconds.
To find the period of oscillations for a mass-spring system, we can use the formula:
T = 2π * √(m / k)
Where:
T is the period of oscillation
π is the mathematical constant pi (approximately 3.14159)
m is the mass of the object (0.820 kg)
k is the spring constant (2620 N/m)
Plugging in the values, we have:
T = 2π * √(0.820 kg / 2620 N/m)
Calculating the square root and simplifying:
T = 2π * √(0.000313) ≈ 2π * 0.017686 ≈ 0.1113π
Learn more about period here:
https://brainly.com/question/29813582
#SPJ11
Explain how P and S waves reflect and refract at horizontal
layers where velocity increases and where velocity decreases.
Answers
Seismic waves, including P and S waves, exhibit distinct behaviors when encountering horizontal layers with changing velocity. P waves reflect and refract at such layers, while S waves reflect and are unable to pass through them, explaining why only P waves can be detected from earthquakes on the other side of the Earth.
Seismic waves are mechanical waves that propagate through the Earth's crust. They are created by earthquakes, explosions, and other types of disturbances that cause ground motion. There are two types of seismic waves, namely P and S waves. These waves behave differently when they encounter horizontal layers where the velocity changes.
P waves reflect and refract at horizontal layers where the velocity increases and decreases. When a P wave enters a layer with an increasing velocity, its wavefronts become curved, and it refracts downwards towards the normal to the interface. The opposite happens when a P wave enters a layer with a decreasing velocity. Its wavefronts become curved, and it refracts upwards away from the normal to the interface. When a P wave encounters a horizontal boundary, it reflects and undergoes a 180° phase shift.
S waves reflect and refract at horizontal layers where the velocity increases, but they cannot pass through layers where the velocity decreases to zero. When an S wave enters a layer with an increasing velocity, it refracts downwards towards the normal to the interface. However, when an S wave encounters a layer with a decreasing velocity, it cannot pass through and reflects back. Therefore, S waves cannot pass through the Earth's liquid outer core, which is why we can only detect P waves from earthquakes on the other side of the Earth.
In summary, P and S waves behave differently when they encounter horizontal layers where the velocity changes. P waves reflect and refract at such layers, while S waves reflect and cannot pass through them.
Learn more about Seismic waves
https://brainly.com/question/19578626
#SPJ11
What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 20.5 A and the bottom one carries 12.0 A
Answers
The magnitude of the magnetic field at a point midway between them if the top one carries a current of 20.5 A and the bottom one carries 12.0 A is 0.00306 T (Tesla).
Given, The current in the top wire is I1 = 20.5 A
The current in the bottom wire is I2 = 12.0 A
The distance between the wires is d = 2r = 2 × 0.05 m = 0.1 m
The formula for magnetic field is given by the Biot-Savart Law which states that the magnetic field at a point P due to a current element dl carrying current I is given by,
B=μ0I4π∣r∣r
where,
μ0=4π×10−7 T⋅m/A is the permeability of free space, and r is the distance from the current element to the point P.
Since the wires are infinitely long, the magnetic field due to each wire at point P will be in the horizontal direction.
As both wires carry current in the same direction, the magnetic field will add up in the vertical direction.
At the midpoint, the magnetic field due to each wire will be in the same direction and will add up.
Therefore, the magnetic field at the midpoint is given by,
|B| = μ0I1I22πd|B|
= 4π×10−7×20.5×12.02π×0.1|B|
= 0.00306 T (Tesla)
Therefore, the magnitude of the magnetic field at a point midway between them if the top one carries a current of 20.5 A and the bottom one carries 12.0 A is 0.00306 T.
To know more about magnetic field, visit:
https://brainly.com/question/19542022
#SPJ11
Is it possible to get more work out of a machine then you put in yes or no?
Answers
Answer:
i think its possible yes
Explanation:
-50 1/2 + 12.3
What's answer
Answers
Answer:
-12.7
Explanation:
Answer: -38.2
Explanation: -50 1/2 + 10 = -40 1/2 + 2 = 38 1/2 + 0.3 = 38.2
explain about 3 pulley sytem and 4 pulley system and both of their uses.
Answers
Answer:
Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...
Movable Pulleys are yet another type of pulley. ...
Compound Pulley Systems are a combination of both movable and fixed pulleys.
Explanation:
there are three different types of pulleys:
Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...
Movable Pulleys are yet another type of pulley. ...
Compound Pulley Systems are a combination of both movable and fixed pulleys.
A 2280 kg car, moving at 24.2 m/s, runs into a car that has a mass of 2180 kg
and is moving at 15.3 m/s in the same direction. The cars stick together after
the collision. Assuming momentum is conserved, what is their final velocity?
OA. 18.6 m/s
OB. 17.2 m/s
O C. 19.8 m/s
OD. 16.7 m/s
Answers
Answer:
The answer is C.19.8 m/s because it's their common velocity after the collision of the two cars.
Explanation:
Hello !
look at the attachment above ☝️ and if you have any questions you're welcome.
nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. what force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure of (this high pressure is possible because the hammer striking the nail is brought to rest in such a short distance.)
Answers
2.18X103 N force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure.
diameter, d = 0.95 mm = 0.95x10-3m
P = 3.1X10^9 Pa
r = d/2 = 0.95/2 x 10^-3 m
= 0.475 x 10^-3 m
Area = \(\pi\) r2
= 3.14 x ( 0.475 x 10^-3 m)2
= = 3.14 x 0.225 x 10^-6
= 0.706 × 10-6 m2
Force = PXA
= 3.1 x 10^9 x 0.70 6 × 10^-6
F = 2.18X103 N
Pressure , within the physical sciences, the perpendicular force in step with unit per area , or the stress at a factor inside a restricted fluid.
A easy instance of pressure can be seen by retaining a knife to a bit of fruit. In case you keep the flat part of the knife towards the fruit, it might not reduce the area. The force is spread out of a massive vicinity (low strain).
The SI unit of pressure is pascal (represented as Pa) which is identical to one newton in line with rectangular metre (N/m2 or kg m-1s-2).
Learn more about pressure here:- https://brainly.com/question/28012687
#SPJ4
A student examining a flashlight observes that it uses a traditional incandescent light bulb. The power rating of the bulb is 60 W, and the bulb is connected to 36 V. What is the current moving through the bulb?
Answers
The current moving through the traditional incandescent light bulb in the examined flashlight is 1.67A.
Electric PowerElectric power is simply the rate at which electrical energy is transferred by an electric circuit per unit time. It is equal to the voltage difference across the element multiplied by the current.
It can be expressed as;
P = V × I
Given the data in the question;
Power = 60WVotage V = 36VCurrent I = ?To determine the current moving through the bulb, we substitute our given values into the expression above.
P = V × I
60W = 36V × I
I = 60W / 36V
I = 1.67A
Therefore, the current moving through the light bulb is 1.67A.
Learn more about electric power here: https://brainly.com/question/19339003
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on the cart?
Answers
Answer:
The total frictional force equals 60 N
Explanation:
We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.
Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.
So F - f = ma
F - f = m(0) = 0
F - f = 0
So, F = f
From the above, we see that the frictional force equals the applied force which is equal to 60 N.
So, f the total frictional force equals 60 N
Where is the greatest Moment of Inertia for a spinning object with changing radius?
Answers
The greatest moment of inertia for a spinning object with changing radius occurs at the furthest point from the center of rotation, where the radius is at its maximum.
What is rotation?Rotation is a type of motion where an object or a body spins around its center or an axis. It is an essential part of the universe and can be seen in everyday life. Its properties surface in a variety of physical phenomena, including the spinning of planets, the precession of a spinning top, and the orbital motion of stars and planets. Rotation can be regular and periodic, or chaotic and random. It can also be linear or angular. In linear rotation, the object moves in a straight line around a fixed point, while in angular rotation, the object moves around a circle or an ellipse. Rotation is caused by an external force and is studied in fields such as physics, astronomy, and engineering.
To learn more about rotation
https://brainly.com/question/30698261
#SPJ4
a crane uses a block and tackle to lift a 2000 N flagstone to a height of 30 m. How much work is done on the flagstone
Answers
The block and tackle system reduces the force required to lift the flagstone, while increasing the distance through which the rope must be pulled. The amount of force reduction depends on the number of pulleys in the system. Assuming that the block and tackle has a mechanical advantage of 4 (meaning that the force required to lift the flagstone is 1/4 of the weight of the flagstone), the tension in the rope will be:
Tension = Force required / Mechanical advantage
Tension = 2000 N / 4
Tension = 500 N
The work done on the flagstone by the crane is then:
Work = Force x Distance
Work = 500 N x 30 m
Work = 15,000 J
Therefore, the crane does 15,000 joules of work on the flagstone.
Match the type of norm with the corresponding example. stealing food from the grocery store ✓ Choose folkway taboo more not wearing shoes inside a restaurant incest Choose
Answers
The type of norm with the corresponding example are Stealing food from the grocery store is an example of a folkway norm, while not wearing shoes inside a restaurant is an example of a taboo norm.
Norms are social expectations or rules that guide behavior in a society. Folkways are informal norms that govern everyday behavior and are based on customs and traditions. Stealing food from the grocery store is a violation of the folkway norm as it goes against the expected behavior of respecting private property and paying for goods. Taboos, on the other hand, are strong societal norms that are deeply ingrained and carry severe social sanctions. Not wearing shoes inside a restaurant is considered a taboo norm as it violates the hygiene and etiquette standards associated with dining in public spaces.
Stealing food from the grocery store is a violation of a folkway norm, which is a less serious societal expectation, while not wearing shoes inside a restaurant is a violation of a taboo norm, which carries stronger social consequences. Understanding and following these norms helps maintain social order and cohesion within a society.
To know more about type of norm click here:
https://brainly.com/question/17147193
#SPJ11
*
Which of these answers does not reflect a benefit of being hydrated?
Sleepy
Lubricate Joints
Regulate temperature
Nourish the brain and spinal cord
Answers
A police car is driving north with a siren making a frequency of 1038 hz. Moops is driving north behind the police car at 12 m/s and hard a frequency of 959hz. How fast is the police car going?
Answers
Answer:
The police car is moving at 41.24 m/s.
Explanation:
To find the speed of the police car we need to use the Doppler equation:
\( f = f_{0}(\frac{v + v_{r}}{v + v_{s}}) \)
Where:
v: is the speed of the sound = 343 m/s
\(v_{r}\): is the speed of the receiver = 12 m/s
\(v_{s}\): is the speed of the source =?
f: is the observed frequency = 959 Hz
f₀: is the emitted frequency = 1038 Hz
Both terms are positive in the fraction because the velocity of the sound is in the opposite direction to both velocities of the police car and the other car.
By solving the above equation for \(v_{s}\) we have:
\( v_{s} = \frac{f_{0}(v + v_{r})}{f} - v = \frac{1038(343 + 12)}{959} - 343 = 41.24 m/s \)
Therefore, the police car is moving at 41.24 m/s.
I hope it helps you!
A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter
Answers
let the bowling ball initially is moving along the x-axis,
The whole process can be represented as,
Before the collision the net kinetic energy of the balls is,
\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)where the values of the variables are given as,
\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)As the value of cos(90) is zero.
Substituting the known values,
The value of the net kinetic energy with the velocity along the y-axis before the collision is,
\(K_{iy}=0\)The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.
After the collision of the balls, the net kinetic energy is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)Negative sign here indicating the direction of the final balls motion will be opposite to the each other.
The values of the variables are given as,
\(v^{\prime}_2=14.8ms^{-1}\)Substituting the known values,
The value final kinetic enegry of the balls with velocity along the y-axis is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)Here 360 degree is used because the pin ball direction is downward of the positive x-axis.
Then by the law of conservation of energy along the y-axis,
\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.
