The total charge that a tow truck driver charges to tow a vehicle can be represented by the graph below.
Which Equation best represents this situation?

Answer:

6m + 3n.

Step-by-step explanation:

The area of a trapezoid = h/2 (a + b), where h = altitude  and a and b are the lengths of the opposite parallel sides.

So here:

h =  6, a =  m and b = m+n.

So area =  6/2(m + m + n)

= 6/2(2m + n)

= 3(2m + n)

= 6m + 3n.

The solution to the equation is x = 5.24

Expressions are mathematical statements that are represented by variables, coefficients and operators

The equation is given as

(x - 3)^2 = 5

Take the square root of both sides

So, we have

x - 3 = 2.24

Add 3 to all sides of the equation

So, we have

x = 5.24

Hence, the solution is x = 5.24

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Answer: Let's start by using algebra to solve the problem.

Let's call the width of the rectangle "w". Then we know that the length of the rectangle is twice the width, or "2w".

The formula for the perimeter of a rectangle is:

P = 2l + 2w

where P is the perimeter, l is the length, and w is the width.

We know that the perimeter is 18 inches, so we can substitute the values we have:

18 = 2(2w) + 2w

Simplifying:

18 = 4w + 2w

18 = 6w

Dividing both sides by 6:

w = 3

So the width of the rectangle is 3 inches.

To find the length, we can use the fact that it is twice the width:

l = 2w = 2(3) = 6

So the length of the rectangle is 6 inches.

Therefore, the rectangle is 6 inches long and 3 inches wide.

enjoy!

50) The number of people started the rumor is 50.

51) Number of people have heard the rumor after 3 days is 48.52

50. The equation to find the number of people in a town who have heard a rumor after t days is given by N(t)= 1+49e^(−0.7t/500).

Here, we can see that the initial number of people who started the rumor is 1 + 49 = 50.

Hence, the number of people who started the rumor is 50.

Therefore, the answer is 50.

51. The equation to find the number of people in a town who have heard a rumor after t days is given by N(t)= 1+49e^(−0.7t/500).

To find the number of people who will have heard the rumor after 3 days, we have to substitute t = 3 in the given equation.

We get:

N(3) = 1 + 49e^(-0.7 × 3/500) = 1 + 49e^(-0.021) = 1 + 49 × 0.979 = 48.03 ≈ 48

Therefore, the number of people who will have heard the rumor after 3 days (to the nearest whole number) is 48.

Hence, the answer is 48.52.

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Answer:

6.25π

Step-by-step explanation:

area = πr^2

A total of 55.86 minutes have gone by since Greg started his run on the treadmill.

If Greg has completed 57% of his run, it means he has 43% of his run remaining.

To find out how many minutes have gone by, we can use proportions.

Let's say x is the total number of minutes Greg needs to complete his run:

x = 57% * 98 minutes

Evaluate

x =  minutes

Therefore, approximately 55.86 minutes have gone by since Greg started his run on the treadmill.

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a. The probability of success (hitting the target) is constant for each trial (88% or 0.88).

b. The probability of hitting the 6th target is:

P(X = 1) = C(1, 1) * 0.88^1 * (1 - 0.88)^(1 - 1) = 0.88

c. Using the binomial probability formula as before, with p = 0.88 and n = 3:

P(X = 1) = C(3, 1) * 0.88^1 * (1 - 0.88)^(3 - 1)

P(X = 2) = C(3, 2) * 0.88^2 * (1 - 0.88)^(3 - 2)

P(X = 3) = C(3, 3) * 0.88^3 * (1 - 0.88)^(3 - 3)

a) The three characteristics of this scenario that indicate we are working with Bernoulli trials are:

The experiment consists of a fixed number of trials (eight shots).

Each trial (shot) has two possible outcomes: hitting the target or missing the target.

The probability of success (hitting the target) is constant for each trial (88% or 0.88).

b) To find the probability of hitting the 6th target (considered as a single trial), we can use the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where:

P(X = k) is the probability of getting exactly k successes,

C(n, k) is the binomial coefficient or number of ways to choose k successes out of n trials,

p is the probability of success in a single trial, and

n is the total number of trials.

In this case, k = 1 (hitting the target once), p = 0.88, and n = 1. Therefore, the probability of hitting the 6th target is:

P(X = 1) = C(1, 1) * 0.88^1 * (1 - 0.88)^(1 - 1) = 0.88

c) To find the probability that the first time hitting the target is not until the 4th shot, we need to consider the complementary event. The complementary event is hitting the target before the 4th shot.

P(not hitting until the 4th shot) = P(hitting on the 4th shot or later) = 1 - P(hitting on or before the 3rd shot)

The probability of hitting on or before the 3rd shot is the sum of the probabilities of hitting on the 1st, 2nd, and 3rd shots:

P(hitting on or before the 3rd shot) = P(X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

Using the binomial probability formula as before, with p = 0.88 and n = 3:

P(X = 1) = C(3, 1) * 0.88^1 * (1 - 0.88)^(3 - 1)

P(X = 2) = C(3, 2) * 0.88^2 * (1 - 0.88)^(3 - 2)

P(X = 3) = C(3, 3) * 0.88^3 * (1 - 0.88)^(3 - 3)

Calculate these probabilities and sum them up to find P(hitting on or before the 3rd shot), and then subtract from 1 to find the desired probability.

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The value of x which is the length of the base of the triangle in the question is; 29 meters

A triangle is a three sided polygon, with three interior angles.

Please find attached the possible diagram in the figure, (created with MS Word), which is a question from a mathematics textbook posted on the internet

The diagram indicates that the altitude or height of the triangle = 8 meters

The specified area of the triangle is; A = 261 square meters

The base length of the triangle = x

The formula for the area of a triangle, A, is; A = (1/2) ×Base length × Height

Therefore;

A = 261 m² = (1/2) × x × 18 m

x = 261 m² ÷ ((1/2) × 18 m) = 29 m

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Answer:

400,000km is represented as 8cm on the map!!!

Step-by-step explanation:

1cm=50000km

8cm=x

Criss cross

1cmx=8cm×50000km

divide both side with 1cm

x=8×50000km

x=400,000km

Answer:

At least means... From 45$ above or It should be equal to 45 or More...

7x≥45

x≥45/7

He need to Move at least 7 lawns.

Answer: 8

56-(n+4)

56-(44+4)

56-48

8

Step-by-step explanation:

can i have brainliest plz

To find the area of an oblique triangle there are different formulae. The first formula to calculate the area of a triangle is area A = (1/2) * a * b * Sin(C), where a and b are the lengths of the two sides of the triangle and C is the value of the angle of the triangle that lies in between the two sides a, b.

It is the triangle that does not consider the right triangle. The formula for the area of an oblique triangle should be considered as the \(A = (1/2) \times a \times b \times Sin(C)\).

It is the triangle that does not consider as the right triangle. It could be treated as the acute triangle where all three angles should be lower than the right angles or at the same time.  

It should be an obtuse triangle where one of the three angles should be more than the right angle.

The above formula defines that

a and b are the two sides lengths of the triangle

and C is the value of the angle of the triangle.

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Arun's mistake is that for the multiplication of 24 by 1, he should have added only one zero, instead of two zeros.

The correct result of the product is of 288.

The multiplication operation for this problem is given as follows:

24 x 12.

Then the two separate products are given as follows:

To the (n - 1)th product, we add a zero, and then add each product, hence the result is given as follows:

48 + 240 = 288.

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It will take the town 21 years 4 months to reach 4600 in population

a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate.

initial population = 3000

population increase every year = 2.5% of 3000

which is 2.5/100 x 3000 = 75

let the time taken to reach 4600 be d

increment for d number of years = 75d

Total population after d years is 75d + 3000

so 75d + 3000 = 4600

75d = 4600  - 3000

75d = 1600

d = 1600/75

d = 21.33 years which is 21 years 4 months

In conclusion 21 years 4 months is the time taken for the ton tto get tto 4600

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Answer:

(1) - \(\dfrac{dh}{dt}=-\dfrac{1}{100 \pi} \ cm/s\)

(2) - \(\dfrac{dA}{dt}=-2 \ cm^2/min\)

Step-by-step explanation:

To solve this problem, we can use the concept of related rates and the formulas for the volume and surface area of a sphere. Let's denote the radius of the ice layer as "r" and the thickness of the ice layer as "h."\(\hrulefill\)

Given:

Radius of the copper ball, r = 20 cm

Rate of ice melting, dV/dt = -25 cm^3/min

Find:

(1) - The rate at which the thickness of the ice layer is decreasing, dh/dt when it is 5 cm thick.

(2) - The rate at which the outer surface area of the ice layer is decreasing (dA/dt).\(\hrulefill\)

The volume of the ice layer can be expressed as the difference between the volume of the outer sphere (with the ice layer) and the volume of the inner sphere (without the ice layer):

\(V = \dfrac4\pi \Big[(r + h)^3 - r^3\Big]\)

Differentiate this with respect to time, t.

\(V = \dfrac43\pi\Big[(r + h)^3 - r^3\Big]\\\\\\\Longrightarrow \dfrac{dV}{dt} =\dfrac{d}{dt} \Big[ \dfrac43\pi\Big[(r + h)^3 - r^3\Big]\Big]\\\\\\\Longrightarrow \dfrac{dV}{dt} =\dfrac43\pi \Big[(3(r + h)^2)(\dfrac{dh}{dt} ) - 0\Big]\\\\\\\Longrightarrow \boxed{\dfrac{dV}{dt} =4\pi(r + h)^2\dfrac{dh}{dt}}\)

Plug in dV/dt, r, and h and solve for dh/dt

\(\dfrac{dV}{dt} =4\pi(r + h)^2\dfrac{dh}{dt}\\\\\\\Longrightarrow -25 \ cm^3/min =4\pi(20 \ cm + 5 \ cm)^2\dfrac{dh}{dt}\\\\\\\Longrightarrow \dfrac{-25}{4\pi} =(25)^2\dfrac{dh}{dt}\\\\\\\Longrightarrow \dfrac{-25}{4\pi} =625\dfrac{dh}{dt}\\\\\\\therefore \boxed{\dfrac{dh}{dt}=-\dfrac{1}{100 \pi} \ cm/s}\)

Thus, the first part is solved. The negative shows that the thickness is decreasing with time. The question may ignore that negative.

The outer surface of the ball is given as:

\(SA = 4\pi(r + h)^2\)

Differentiate the function with respect to time, t.

\(SA = 4\pi(r + h)^2\\\\\\\Longrightarrow \dfrac{dA}{dt}=\dfrac{d}{dt}\Big[4\pi(r + h)^2\Big] \\\\\\\Longrightarrow \boxed{\dfrac{dA}{dt}=8\pi(r + h)\dfrac{dh}{dt} }\)

Substitute in our known values.

\(\dfrac{dA}{dt}=8\pi(r + h)\dfrac{dh}{dt} \\\\\\\Longrightarrow \dfrac{dA}{dt}=8\pi(20 + 5)(-\dfrac{1}{100 \pi} )\\\\\\\Longrightarrow \dfrac{dA}{dt}=-\dfrac{200}{100 } \\\\\\\therefore \boxed{\dfrac{dA}{dt}=-2 \ cm^2/min}\)

Thus, the second part is solved. Once again, the question may want you to disregard the negative.

Answer:

6.68, 13.37, 14.95

Step-by-step explanation:

One of the legs is twice as long as the other.

b = 2a

The perimeter is 35.

35 = a + b + c

The triangle is a right triangle.

c² = a² + b²

Three equations, three variables.  Start by plugging the first equation into the second and solving for c.

35 = a + 2a + c

c = 35 − 3a

Now plug this and the first equation into the Pythagorean theorem:

(35 − 3a)² = a² + (2a)²

1225 − 210a + 9a² = a² + 4a²

1225 − 210a + 4a² = 0

Solve with quadratic formula:

a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)

a = (210 ± √24500) / 8

a ≈ 6.68 or 45.82

Since the perimeter is 35, a = 6.68.  Therefore, the other sides are:

b ≈ 13.37

c ≈ 14.95

Answer:

The slope is \(\frac{2}{8}\)

Step-by-step explanation:

Take the general equation of a straight line \(y = mx+c\)

Here \(m\) is the slope of the line.

So let's get the equation of the line in the question in the same form.

\(-48 = 2x-8y\)

Add \(8y\) to both sides: \(8y - 48 = 2x\)

Add \(48\) to both sides: \(8y = 2x + 48\)

Divide by \(8\) to get it into the general equation: \(y = \frac{2}{8} x + 6\)

Now compare it to the general equation to find the value of \(m\). The value of \(m\) is the coefficient of \(x\) which we can see is \(\frac{2}{8}\)

Answer:

∠ C = 100°

Step-by-step explanation:

since 2 sides of the triangle are congruent then the triangle is isosceles with base angles congruent.

consider the angle inside the triangle to the left of 140°

this angle and 140° are a linear pair and sum to 180°

angle + 140° = 180° ( subtract 140° from both sides )

angle = 40°

then the angle on the left of the triangle = 40° ( base angles congruent )

the sum of the angles in a triangle = 180° , so

∠ C + 40° + 40° = 180°

∠ C + 80° = 180° ( subtract 80° from both sides )

∠ C = 100°

To determine if a function crosses the horizontal asymptote, analyse the behavior of the function as it approaches the asymptote and on either side of it.

1. Identify the horizontal asymptote of the function. The horizontal asymptote is a horizontal line that the function approaches as the independent variable (usually denoted as x) goes to positive or negative infinity. It is often denoted by a horizontal line y = a, where "a" is a constant.

2. Examine the behavior of the function as x approaches positive infinity. Evaluate the limit of the function as x goes to positive infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. However, if the limit does not equal the asymptote, move to the next step.

3. Examine the behavior of the function as x approaches negative infinity. Evaluate the limit of the function as x goes to negative infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. If the limit does not equal the asymptote, proceed to the next step.

4. Investigate the behavior of the function around critical points or points where the function changes its behavior. These points may include the x-intercepts or vertical asymptotes. Determine if the function crosses the asymptote around these points by analyzing the behavior of the function in their vicinity.

If, at any point in this process, the function crosses the horizontal asymptote, then it does not have a true horizontal asymptote. However, if the function approaches the asymptote and does not cross it at any point, then it has a horizontal asymptote.

It's important to note that some functions may have multiple horizontal asymptotes or no horizontal asymptote at all. The steps outlined above are a general guideline, but the specific behavior of the function needs to be analyzed to make a conclusive determination.

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(i) The dynamic programming matrix with the min cost entries for the given strings is as follows: ''1 2 1 2 3; 2 1 2 1 2; 3 2 1 2 3; 4 3 2 1 2''.  (ii) The min cost solutions by tracing back the matrix entries from bottom right are: Substitute 'a' at position 2 with 'b', Substitute 'a' at position 1 with 'a'.

(i) To create the dynamic programming matrix for string edit, we can use the Levenshtein distance algorithm. The matrix will have the alphabets of string X along the rows and the alphabets of string Y along the column entries.

First, let's create the initial matrix:

```

     ''  b   a   b   b

  ---------------------

'' |  0   1   2   3   4

a  |  1

b  |  2

a  |  3

b  |  4

```

In this matrix, the blank '' represents the empty string.

To calculate the min cost entries, we will use the following rules:

1. If the characters in the current cell match, copy the cost from the diagonal cell (top-left).

2. If the characters don't match, find the minimum cost among three neighboring cells: the left cell (insertion), the top cell (deletion), and the top-left cell (substitution). Add 1 to the minimum cost and place it in the current cell.

Let's calculate the min cost for two entries in the matrix:

1. For the cell at row 'a' and column 'b':

 The characters 'a' and 'b' don't match, so we need to find the minimum cost among the neighboring cells.

     - Left cell: The cost is 2 (from the previous row).

  - Top cell: The cost is 1 (from the previous column).

  - Top-left cell: The cost is 0 (from the previous row and column).

  The minimum cost is 0. Since the characters don't match, we add 1 to the minimum cost. Thus, the min cost for this cell is 1.

2. For the cell at row 'b' and column 'b':

  The characters 'b' match, so we copy the cost from the top-left diagonal cell.

  The min cost for this cell is 0.

We can continue calculating the min cost entries for the rest of the cells in a similar manner.

(ii) To trace back the matrix entries from the bottom right and calculate the min cost solutions, we start from the bottom-right cell and move towards the top-left cell.

Using the matrix from part (i), let's trace back the entries:

Starting from the cell at row 'a' and column 'b' (cost 1), we compare the neighboring cells:

- Left cell: Cost 2

- Top cell: Cost 3

- Top-left cell: Cost 0

The minimum cost is in the top-left cell, so we choose that path. We have performed a substitution operation, changing 'a' to 'b'. We move to the top-left cell.

Continuing the process, we compare the neighboring cells of the current cell:

- Left cell: Cost 1

- Top cell: Cost 2

- Top-left cell: Cost 0

Again, the minimum cost is in the top-left cell. We have performed a substitution operation, changing 'b' to 'a'. We move to the top-left cell.

We repeat this process until we reach the top-left cell of the matrix.

The complete sequence of operations to transform string X into string Y is as follows:

1. Substitute 'a' at position 2 with 'b': "a b a b" → "a b b b"

2. Substitute 'a' at position 1 with 'a': "a b b b" → "b a b b"

By following this sequence, we achieve the transformation from string X to string Y with the minimum cost.

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We are unable to establish causation or cause-and-effect correlations using observational data. Observational studies are fantastic for describing a particular group, contrasting groups, or looking at the patterns or relationships between variables.

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Given the expression

Answer:

2/5

Step-by-step explanation:

2/5=4/10

Answer:

2/5 is great because it's 40%

3/10 is 30%

so 2/5 is greater

The pair that best represents the double recombinant classes is a bc and b c b.

To determine the pair that represents the double recombinant classes, we look for combinations of alleles that are different from the parental genotypes. In the given data, the pair a bc has a count of 30, which represents a double recombinant class. Similarly, the pair b c b also has a count of 30, indicating another double recombinant class.

These double recombinant classes arise from the recombination events that occurred between the parental genotypes. The allele combinations in these classes differ from both the original parental genotypes, indicating that two crossing-over events have taken place.

It is worth noting that the counts for the other allele combinations (a b c, a a b c, and a b c a) do not match the counts for the double recombinant classes. Therefore, the pairs a bc and b c b best represent the double recombinant classes based on the given data.

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Answer: rational

Step-by-step explanation:

16/5=

(160/5)/10=

32/10=3.2 ==> rational since it has a finite number of digits before and after the decimal.

Answer:

A

Step-by-step explanation:

5/8=0.625

0.42=0.42^2

Answer:

Step-by-step explanation:

cannot see pic

The measure of the angle will be 60° = tan⁻¹(√3).

The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.

The trigonometric functions, also known as circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.

The measure of angle will be,

BC = √3AC

tanθ = BC / AC

θ = tan⁻¹ ( BC / AC )

θ = tan⁻¹ (√3 x AC ) / ( AC )

θ = tan⁻¹ (√3)

60° = tan⁻¹ (√3)

Therefore, the angle will be 60° = tan⁻¹(√3).

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Answer:

x=11

Step-by-step explanation:

Your equation is:

35 = 14x+1-85/2

70=14x-84

154=14x

11=x

Answer:

Step-by-step explanation:

Angle between tangent and secant is half the difference of intercepted arcs:

Answer:

x=8

Solution: 80=106

Step-by-step explanation:

I did the math and checked. Your welcome :)

Answer:

Step-by-step explanation:

The area of a trapezoid

A = 1/2(A+B)h

A=1/2(10.5+21.1)9.28

A=1/2(31.6)9.28

A = 293.248/2

A = 146.624