the two-way table shows the results of a recent study on the effectiveness of the flu vaccine. what is the probability that a randomly selected person who tested positive for the flu is vaccinated?

The value of f in the proportion is,

f = 20

We have to given that;

Proportion is,

⇒ 5 / 11 = f / 44

Now, We can simplify as;

⇒ 5 / 11 = f / 44

⇒ 5 x 44 / 11 = f

⇒ 5 x 4 = f

⇒ f = 20

Thus, The value of f in the proportion is,

f = 20

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The value of f from 5/11 = f/44 is 20.

We have,

5 /11 = f /44

Using proportion we get

5 x 44 = 11 x f

5 x 44 /11 = f

5 x 4 = f

f = 20

Thus, the value of f is 20.

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(1) Using the Black/Scholes Option Pricing Model, the value of the call option is $7.70.

(2) The intrinsic value of the call is the difference between the stock price and the strike price of the option. Therefore, it is $4.

(3) The stock price required to break-even is the sum of the strike price and the option premium. Therefore, it is $74.

(4) If volatility were to decrease, the value of the call would decrease.

(5) If the exercise price would increase, the value of the call would decrease.

(6) If the time to maturity were 3-months, the value of the call would decrease.

(7) If the stock price were $62, the value of the call would be zero.

(8) The maximum value that a call option can take is unlimited.

In the Black/Scholes option pricing model, the value of a call option can be calculated using the formula:

C = S*N(d1) - X*e^(-rT)*N(d2)

where S is the stock price, X is the exercise price, r is the risk-free rate, T is the time to maturity, and σ2 is the variance of the stock's return.

Using the given values, we can calculate d1 and d2:

d1 = [ln(S/X) + (r + σ2/2)T]/(σ2T^(1/2))

   = [ln(74/70) + (0.10 + 0.50/2)*0.5]/(0.50*0.5^(1/2))

   = 0.9827

d2 = d1 - σ2T^(1/2) = 0.7327

Using these values, we can calculate the value of the call option:

C = S*N(d1) - X*e^(-rT)*N(d2)

= 74*N(0.9827) - 70*e^(-0.10*0.5)*N(0.7327)

= $7.70

The intrinsic value of the call is the difference between the stock price and the strike price of the option. Therefore, it is $4.

The stock price required to break-even is the sum of the strike price and the option premium. Therefore, it is $74.If volatility were to decrease, the value of the call would decrease. This is because the option's value is directly proportional to the volatility of the stock.

If the exercise price would increase, the value of the call would decrease. This is because the option's value is inversely proportional to the exercise price of the option.

If the time to maturity were 3-months, the value of the call would decrease. This is because the option's value is inversely proportional to the time to maturity of the option.If the stock price were $62, the value of the call would be zero. This is because the intrinsic value of the call is zero when the stock price is less than the strike price.

The maximum value that a call option can take is unlimited. This is because the value of a call option is directly proportional to the stock price. As the stock price increases, the value of the call option also increases.

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Answer:

square root of 26

Step-by-step explanation:

Answer:

Vertical line that passes over 1 the x axis. (No y-intercept)

Step-by-step explanation:

The correct option is c) Easier interpretation. One of the main advantages of simple models is their ease of interpretation. Simple models tend to have fewer parameters and less complex mathematical equations, making it easier to understand and interpret how the model is making predictions.

This interpretability can be valuable in various domains, such as medicine, finance, or legal systems, where it is important to have transparent and understandable decision-making processes.

Complex models, on the other hand, often involve intricate relationships and numerous parameters, which can make it challenging to comprehend the underlying reasoning behind their predictions. While complex models can sometimes offer higher accuracy or make more detailed predictions, they often sacrifice interpretability in the process.

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Answer:

Here is the answer.

Step-by-step explanation:

The total number of pairs sold by SoccerWorld is 57

From the question, we have the following parameters that can be used in our computation:

The above parameters means that

s = 3j

d = 5 + j

70(s + d + j) = 7000

Where

j = JP Sports

s = SoccerWorld

d = DirectSportz

Divide both sides of 70(s + d + j) = 7000 by 70

s + d + j = 100

Substitute s = 3j and d = 5 + j

3j + 5 + j + j = 100

Evaluate the like terms

5j = 95

Divide by 5

j = 19

Substitute j = 19 in s = 3j

s = 3 * 19

So, we have

s = 57

Hence, the number of pairs is 57

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Answer:

So the tax will be greater than $8

Step-by-step explanation:

50% of $160 = half of $160 = $80

80/10 = 8 so 50%/10 = 5%

Therefore, $8 is 5%

So the tax will be greater than $8

10)100000(10000

10

___

××0000

Answer:

5000

Step-by-step explanation:

1 score = 20

10 scores

= 10 x 20

= 200

100,000 / 10 scores

= 100,000 / 200

= 5000

The values of displacement, velocity, and acceleration are 2.68 m, 2.24 m/s, and -18.07 m/s2 respectively.

We know that the amplitude, A = 2 + T; the angular velocity, ω = 4 + U rad/s; and time, t = 1s. Here, the value of T = 1 and the value of U = 4 (as mentioned in the question).

Harmonic motion is a motion that repeats itself after a certain period of time.

Harmonic motion is caused by the restoring force that is proportional to the displacement from equilibrium.

The three types of harmonic motions are as follows: Free harmonic motion: When an object is set to oscillate, and there is no external force acting on it, the motion is known as free harmonic motion.

Damped harmonic motion: When an external force is acting on a system, and that force opposes the system's motion, it is called damped harmonic motion.

Forced harmonic motion: When an external periodic force is applied to a system, it is known as forced harmonic motion.Vectorial formVibrations of harmonic motion can be represented in a vectorial form.

A simple harmonic motion is a projection of uniform circular motion in a straight line.

The displacement, velocity, and acceleration of a particle in simple harmonic motion are all vector quantities, and their magnitudes and directions can be determined using a coordinate system.

Let's now calculate the values of displacement, velocity, and acceleration.

Displacement, s = A sin (ωt)

Here, A = 2 + 1 = 3 (since T = 1)and, ω = 4 + 4 = 8 (since U = 4)

So, s = 3 sin (8 x 1) = 2.68 m (approx)

Velocity, v = Aω cos(ωt)

Here, v = 3 x 8 cos (8 x 1) = 2.24 m/s (approx)

Acceleration, a = -Aω2 sin(ωt)

Here, a = -3 x 82 sin(8 x 1) = -18.07 m/s2 (approx)

Thus, the values of displacement, velocity, and acceleration are 2.68 m, 2.24 m/s, and -18.07 m/s2 respectively.

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In a Taylor series, a polynomial t3(x) refers to the third-degree Taylor polynomial of a function f(x). It is a polynomial approximation of f(x) centered at a given point x=a, and it is used to estimate the value of f(x) near x=a.

A Taylor series is a mathematical series that represents a function as an infinite sum of its derivatives evaluated at a given point. The series is centered at a point x=a, and it is used to approximate the value of the function f(x) near that point.

The third-degree Taylor polynomial, denoted as t3(x), is a polynomial approximation of the function f(x) up to the third degree. It is computed using the first three terms of the Taylor series expansion of f(x) centered at x=a. The formula for t3(x) is:

t3(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)*(x-a)^3/3!

Here, f'(a), f''(a), and f'''(a) are the first, second, and third derivatives of f(x) evaluated at x=a, respectively. The term (x-a)^2/2! is the second-degree term, and (x-a)^3/3! is the third-degree term.

The polynomial t3(x) provides a good approximation of f(x) near x=a, especially if f(x) is a smooth function with continuous derivatives. By adding higher-order terms, we can improve the accuracy of the approximation.  

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In a Taylor series, a polynomial t3(x) refers to the third-degree Taylor polynomial of a function f(x). It is a polynomial approximation of f(x) centered at a given point x=a, and it is used to estimate the value of f(x) near x=a.

A Taylor series is a mathematical series that represents a function as an infinite sum of its derivatives evaluated at a given point. The series is centered at a point x=a, and it is used to approximate the value of the function f(x) near that point.

The third-degree Taylor polynomial, denoted as t3(x), is a polynomial approximation of the function f(x) up to the third degree. It is computed using the first three terms of the Taylor series expansion of f(x) centered at x=a. The formula for t3(x) is:

t3(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)*(x-a)^3/3!

Here, f'(a), f''(a), and f'''(a) are the first, second, and third derivatives of f(x) evaluated at x=a, respectively. The term (x-a)^2/2! is the second-degree term, and (x-a)^3/3! is the third-degree term.

The polynomial t3(x) provides a good approximation of f(x) near x=a, especially if f(x) is a smooth function with continuous derivatives. By adding higher-order terms, we can improve the accuracy of the approximation.  

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The Cartesian equation for the particle's path is y = (1/3)(x - 1)^2, representing a parabolic curve. The particle moves in the positive x-direction as t increases.

To find the Cartesian equation, we eliminate the parameter t by isolating t in one of the equations and substituting it into the other equation:

From x = 3t + 1, we can solve for t as t = (x - 1)/3.

Substituting this value of t into y = 9t^2, we get y = 9[(x - 1)/3]^2.

Simplifying the equation, we have y = (3/9)(x - 1)^2, which simplifies further to y = (1/3)(x - 1)^2.

The Cartesian equation for the particle's path is y = (1/3)(x - 1)^2. This equation represents a parabolic curve.

To graph the Cartesian equation, plot the points on the graph where x and y satisfy the equation. The graph will show a parabolic curve. Since the parameter t ranges from negative infinity to positive infinity, the particle's path extends infinitely in both directions.

The direction of motion can be determined by analyzing the coefficient of t in the parametric equation for x. In this case, the coefficient is 3, indicating that as t increases, the particle moves in the positive x-direction.

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Since the object is in free fall the acceleration of the object is approximately

Answer:

in ratio 4:14

Step-by-step explanation:

Answer:

28 degrees and 62 degrees

Step-by-step explanation:

Set up your equation like this:

x+(x-34)=90

2x-34=90

2x=56

x=28

28+34=62

So the smaller angle is 28 degrees and the larger angle is 62 degrees.

Hope this helps!! :D

Answer:

x = -8

Step-by-step explanation:

I'm guessing you want the value for X given the value of y = -8

8x +6×8 =-16

8x = -64 so X = -8

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

In a square ABCD, if AB = (3x-8) and BC = (x+12), find the value of x. Also, find the length of each side of the square.

Note that all sides of a square are equal. Hence AB = BC for the square ABCD.

Given AB = (3x-8) and BC = (x+12), then AB = BC

3x-8 = x+12

collect like terms;

3x-x = 12+8

2x = 20

x = 20/2

x = 10

Substitute x = 10 into any of the side. Using side AB

AB = 3x-8

AB = 3(10)-8

AB = 30-8

AB = 22

BC = x+12

BC = 10+12

BC = 22

Hence x = 10 and the length of each side is 22

Answer: b

Step-by-step explanation:

Steps are shown in the attached document.

In regression, the equation that describes how the response variable (y) is related to the explanatory variable (x) is option (b) the regression model

The regression model describes the relationship between a dependent variable (also known as the response variable, y) and one or more independent variables (also known as explanatory variables or predictors, x). It is used to predict the value of the dependent variable based on the values of the independent variables.

The regression model can take different forms depending on the type of regression analysis used, such as linear regression, logistic regression, or polynomial regression.

The correlation model, on the other hand, refers to the correlation coefficient, which is a statistical measure that describes the strength and direction of the linear relationship between two variables. The correlation coefficient can be used to assess the degree of association between two variables, but it does not provide information on the nature or direction of the relationship, nor does it allow for the prediction of one variable from the other.

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The area of a circle as a function of its diameter is A(d) =  \(\frac{\pi d^2}{4}\).

We have to find the area of a circle as a function of its diameter.

Let the diameter of the circle be d.

We know the formula,

Area of circle = \(\pi r^2\)

Where,

r is the radius of the circle.

\(\pi\)  = constant.

We know that,

Radius is equal to half the diameter of a circle.

Hence, we can write

r = d/2

Where d is the diameter of the circle.

Hence, we can write,

Area of circle as a function of its diameter = A(d) = \(\pi (\frac{d}{2})^2 = \frac{\pi d^2}{4}\).

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Answer:

B) x + 4y = 7

Step-by-step explanation:

Hope this helps. Pls give brainliest.

Answer:

does not clearly describe a word or phrase in a sentence

Step-by-step explanation:

Not sure that this is math but...

Answer:

The answer is B

Step-by-step explanation:

B) does not clearly describe a word or phrase in a sentence

The statements for the function f( x) = 3x ²- 5 are

f( 5)< 1( false)

f( 0) = 1( false)

Statements for the function f(x) = 3x ²- 5

To find the true or false statement we have to substitute the value for x

First, x= 3

f(x) = 3x ²- 5

f(3)= 3( 5)²- 5

f(3) = 75- 5

f(3)= 70.

Thus, the statement" f( 5)< 1" is false.

Now, at x =0

f(x) = 3x ²- 5

f(0) = 3( 0)²- 5

f(0)= 0- 5

f(0)= -5.

Thus, the statement" f( 0) = 1" is false.

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If x and y are in direct proportion, when x is 4 the required value of y is 28.

When two mathematical expressions are equivalent to one another in a system of variables, the system is called an equation.

Given that,

x and y are in direct proportion,

Implies that,

x ∝ y

x = k.y    (1)

Here, k is constant.

According to given condition,

when x is 7, the value of y is 49

Substitute the values of x and y in equation (1),

49 = k × 7

k = 7

To find the value of y, when x is 4,

Substitute values x = 4 and k = 7 in equation (1),

y = 4 × 7

y = 28

The required value of y is 28, when x is 4.

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Your multiple-choice selection has a typo. Notice that choice b and d is the same answer.

For at most we use the (<) symbol.

$3 per apple = 3x.

$2 per orange = 2y.

Answer: 3x + 2y < 123

the value of F(9) is approximately 23.308.

To find the value of F(9) given that F(x) is an antiderivative of (ln x)^3/x and F(1) = 0, we can use the fundamental theorem of calculus.

According to the fundamental theorem of calculus, if F(x) is an antiderivative of a function f(x), then:

∫[a,b] f(x) dx = F(b) - F(a)

Since F(1) = 0, we can write:

∫[1,9] (ln x)^3/x dx = F(9) - F(1)

To evaluate the integral, we can make a substitution:

Let u = ln x, then du = (1/x) dx

The integral becomes:

∫[ln 1, ln 9] u^3 du

Integrating u^3 with respect to u:

[(1/4)u^4] | [ln 1, ln 9] = (1/4)(ln 9)^4 - (1/4)(ln 1)^4

Since ln 1 = 0, we have:

(1/4)(ln 9)^4 - (1/4)(ln 1)^4 = (1/4)(ln 9)^4

Therefore, F(9) - F(1) = (1/4)(ln 9)^4

Since F(1) = 0, we can conclude that F(9) = (1/4)(ln 9)^4.

Calculating this value:

F(9) = (1/4)(ln 9)^4 ≈ 23.308

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To find the area of the region bounded by the graph of the function f(x) = x(x-1)(\(x^3\)) and the x-axis on the interval [-3, 1], we need to calculate the definite integral of the absolute value of the function within that interval.

Let's break down the problem into smaller steps:

Step 1: Determine the critical points.

To find the critical points of the function, we set f(x) equal to zero and solve for x:

x(x-1)(\(x^3\)) = 0

From this equation, we can see that the critical points occur at x = 0, x = 1, and x = -3.

Step 2: Determine the intervals of interest.

We are given the interval [-3, 1]. We need to determine which portions of the interval are above or below the x-axis.

For x < -3, the function f(x) = x(x-1)(\(x^3\)) is negative.

For -3 < x < 0, the function f(x) = x(x-1)(\(x^3\)) is positive.

For 0 < x < 1, the function f(x) = x(x-1)(\(x^3\)) is negative.

For x > 1, the function f(x) = x(x-1)(\(x^3\)) is positive.

Step 3: Calculate the area.

We'll calculate the area in two parts: the area below the x-axis (negative area) and the area above the x-axis (positive area). The total area is the absolute value of the sum of these two areas.

Negative Area:

To find the negative area, we'll integrate the absolute value of the function from -3 to 0:

Negative Area = ∫[from -3 to 0] |f(x)| dx

Positive Area:

To find the positive area, we'll integrate the function itself from 0 to 1:

Positive Area = ∫[from 0 to 1] f(x) dx

Total Area:

The total area is the absolute value of the sum of the negative area and the positive area:

Total Area = |Negative Area| + Positive Area

Step 4: Calculate the integrals.

Now, we'll calculate the integrals to find the areas.

Negative Area:

∫[from -3 to 0] |f(x)| dx = -∫[from -3 to 0] f(x) dx

Positive Area:

∫[from 0 to 1] f(x) dx

By evaluating these integrals, we can find the respective areas.

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