The variance of a Gaussian distribution curve is 0.02. This is the maximum height of this curve: 1.59 2.82 19.95 None of the above

Based on the given algorithm, we can analyze the recurrence relation for the running time of the algorithm on inputs of arrays of n elements.

Let's denote the running time of the algorithm for an input of size n as t(n).

For n = 1, the algorithm computes f(g) for a single entry in the array, which costs a constant time, let's say C1. Therefore, we have:

t (1) = C1

For larger values of n, the algorithm splits the array into two subarrays of size 2n/3 each and runs recursively on each subarray. This step incurs a running time of t(2n/3) for each subarray.

Additionally, the algorithm performs the computation g(x, y) on the resulting ordered set of two integers, which costs a constant time, let's say C2.

Considering these factors, we can write the recurrence relation for the running time as:

t(n) = 2t(2n/3) + C2

Therefore, the correct option among the given recurrence relations that seems to fit the running time of the algorithm is:

c. t(1) = C, and t(n) = 2t(2n/3) + C2, for some positive constants C, C2

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The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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L x W = A

25 x W = 125

So now you dived 125 by 25

125 ÷ 25 = 5

The value of x is equal to 15°

In Mathematics and Geometry, the sum of the exterior angles of both a regular and irregular polygon is always equal to 360 degrees.

Note: The given geometric figure (regular polygon) represents a pentagon and it has 5 sides.

By substituting the given parameters, we have the following:

3x + 4x + 8 + 5x + 5 + 6x - 1 + 5x + 3 = 360°.

3x + 4x + 5x + 6x + 5x + 8 + 5 - 1 + 3 = 360°.

23x + 15 = 360°.

23x = 360 - 15

23x = 345

x = 345/23

x = 15°.

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Answer:

0.108

Step-by-step explanation:

A 1x25 Playfair matrix results in a substitution system called the "Playfair Cipher."

This cipher is a digraph substitution cipher, where pairs of letters are encrypted using a 5x5 matrix created from a keyword. The matrix is filled with unique letters of the alphabet, and "I" and "J" are typically combined into one slot. The Playfair Cipher encrypts pairs of letters by following specific rules: if the letters are in the same row or column, they're replaced by the letters to their immediate right or below, and if they form a rectangle, they're replaced by the letters on the same row but in the opposite corners. This cipher provides a more secure encryption compared to simple substitution ciphers, as it encrypts pairs of letters instead of single characters.

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To find an equation of the plane tangent to the surface 8xy + 5yz + 7xz − 80 = 0 at the point (2, 2, 2), we need to find the gradient vector of the surface at that point.

The gradient vector is given b

grad(f) = (df/dx, df/dy, df/dz)

where f(x, y, z) = 8xy + 5yz + 7xz − 80.

Taking partial derivatives,

df/dx = 8y + 7z

df/dy = 8x + 5z

df/dz = 5y + 7x

Evaluating these at the point (2, 2, 2), we get:

df/dx = 8(2) + 7(2) = 30

df/dy = 8(2) + 5(2) = 26

df/dz = 5(2) + 7(2) = 24

So the gradient vector at the point (2, 2, 2) is:

grad(f)(2, 2, 2) = (30, 26, 24)

This vector is normal to the tangent plane. Therefore, an equation of the tangent plane is given by:

30(x − 2) + 26(y − 2) + 24(z − 2) = 0

Simplifying, we get:

30x + 26y + 24z − 136 = 0

So the equation of the plane to the surface at the point (2, 2, 2) is 30x + 26y + 24z − 136 = 0.

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Answer:

The largest side is OP.

Step-by-step explanation:

ΔNOP, m∠N = 110° and m∠O = 38°

According to he property of the triangle, the sum of all the angles of the triangle is 180°,  

So,

m∠N +  m∠O + m∠P = 180°

110° + 38° + m∠P = 180°

m∠P  =  32°

The side opposite to the largest angle is largest.

Here the largest angle is m∠N  so the largest side is OP.

The function representing the same preferences as function U is function W. Function U(x, y) represents the preference for the minimum between 3 times x and y.

Similarly, function W(x, y) represents the preference for the minimum between 6 times x and y. Both functions U and W prioritize the smaller value between the two variables. This is evident from their definitions: U(x, y) = min(3x, y) and W(x, y) = min(6x, y). While functions Z, L, G, and H also involve the concept of minimum values, they differ in terms of their weights and relationships between the variables. Function Z prefers the minimum between x and 2y, which is distinct from the preferences represented by function U. Function L takes the minimum between 6x and 2y and subtracts a constant value, which introduces an offset and does not align with the preferences of function U. Functions G and H have different denominators and weights for x and y, making them different from function U as well. Therefore, the correct answer is function W, which represents the same preferences as function U by prioritizing the smaller value between 6 times x and y.

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Therefore, the surface defined by the equation 3x^2 - 12y^2 + z^2 = 12 is a combination of a parabolic cylinder, a pair of hyperbolic paraboloids, and an elliptic cross-section.

The given equation 3x^2 - 12y^2 + z^2 = 12 can be rewritten as:

z^2 = 12 - 3x^2 + 12y^2

Taking the square root of both sides, we get:

z = ±sqrt(12 - 3x^2 + 12y^2)

To sketch the surface, we can take different values of x and y and plot the corresponding z values. However, it is easier to use traces.

If we set x = 0, we get:

z = ±sqrt(12 + 12y^2)

This is a pair of hyperbolic paraboloids opening up and down, one for the positive square root and one for the negative square root.

If we set y = 0, we get:

z^2 = 12 - 3x^2

This is a parabolic cylinder that opens along the x-axis.

Finally, if we set z = 0, we get:

3x^2 - 12y^2 = 12

Dividing both sides by 12, we get:

x^2/4 - y^2/1 = 1

This is the equation of an ellipse centered at the origin with semi-major axis of length 2 along the x-axis and semi-minor axis of length 1 along the y-axis.

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Answer:V x 80 = 36      Original value is $0.45

Step-by-step explanation:  V is the original value and your x it by 80

Answer:

day=56

week=285

months=1140

year=13680

Answer:

cubic polynomial

Step-by-step explanation:

3 is highest exponent and 3 is cubic

there are more than 3 terms, so it's polynomial (poly=many)

According to the provided scenario, if you weigh 160 pounds, then 3 drinks in four hours would make you definitely illegal.

If a person weighs 160 pounds and drinks alcohol at a moderate rate, then after 3 drinks in four hours, their BAC (blood alcohol concentration) would be around 0.08, which is considered legally impaired and definitely illegal. However, it is important to note that this estimate is based on various factors such as the person's gender, age, and metabolism, and can vary from person to person.

Therefore, it is always advisable to drink responsibly and not drive after consuming alcohol.

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Answer:

7/10 or 0.7 or 70%

Step-by-step explanation:

I would use a venn diagram, and fill it in! Then there are 7 do A &B and 3 who just do A. That as a probaility, your answer!

ANSWER

EXPLANATION

We want to write the ratio of hits to innings.

This means that we want to write the numbers in the form:

There were 6 hits in 9 innings. Hence, the ratio of hits to innings (in simplest form) is:

That is the answer.

The answer fam is......

The ellis weight is heavier and by 7.23 lbs.

We are given that;

Weight= 5pounds

Now,

To convert Ed’s weight from kilograms to pounds, we can multiply by the conversion factor of 2.20462262185. We get:

Ed’s weight in pounds = 50 kg * 2.20462262185 lbs/kg Ed’s weight in pounds = 110.2311310925 lbs

To convert Ellis’s weight from stones and pounds to pounds, we can multiply the number of stones by 14 and add the number of pounds. We get:

Ellis’s weight in pounds = 7 stones * 14 lbs/stone + 5 lbs Ellis’s weight in pounds = 98 + 5 Ellis’s weight in pounds = 103 lbs

To compare the weights, we can subtract them and see which one is larger. We get:

Ed’s weight - Ellis’s weight = 110.2311310925 lbs - 103 lbs Ed’s weight - Ellis’s weight = 7.2311310925 lbs

Therefore, by unitary method the answer will be 7.23 lbs.

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The slope of the line is zero beacuse it is a straight line.

The slope is the ratio of the vertical changes to the horizontal changes between two points of the line.

The slope of the line is calculated as follows:

m = Δy/Δx

Given that the line that passes through the points (-1, -2) and (3, -2)

To find the slope of the line that passes through points (-1, -2) and (3, -2)

Therefore, the slope of the line is;

m = Δy/Δx

m = (-2 + 2)/(3 - 1)

m = 0

Hence, the slope of the line is zero beacuse it is a straight line.

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Step-by-step explanation:

Simple interest=principal x rate x time÷100

amount borrowed=$500

I=$500x7x6÷100

I=$210

therefore you will pay

amount borrowed+interest

$500+$210

$710

hope this is helpful

Answer: if ur looking for an equation then y = -4 + 6

Step-by-step explanation:

Since the y intercept is 6 and it’s going 4 units down and 1 to the left

Answer:

148.7804878

Step-by-step explanation:

All you have to do is divide!

The inverse Laplace transform of F(s) is:

\(f(t) = e^(-t)\)

To find the inverse Laplace transform of each function, we need to express them in terms of known Laplace transforms. Here are the solutions for each function:

a)

\(F(s) = \large{\frac{2e^{-0.5s}}{s^2-6s+9}}\)

To find the inverse Laplace transform, we first need to factor the denominator of F(s). The denominator factors as (s - 3)². Therefore, we can rewrite F(s) as:

\(F(s) = \large{\frac{2e^{-0.5s}}{(s-3)^2}}\)

Now, we know that the Laplace transform of eᵃᵗ is 1/(s - a). Therefore, the inverse Laplace transform of

\(e^(-0.5s) \: is \: e^(0.5t).\)

Applying this, we get:

\(f(t) = 2e^(0.5t) * t \\

b) F(s) = \large{\frac{s-1}{s^2-3s+2}}\)

We can factor the denominator of F(s) as (s - 1)(s - 2). Now, we rewrite F(s) as:

\(F(s) = \large{\frac{s-1}{(s-1)(s-2)}}\)

Simplifying, we have:

\(F(s) = \large{\frac{1}{s-2}}\)

The Laplace transform of 1 is 1/s. Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(2t) \\

c) F(s) = \large{\frac{s-1}{s^2+s-2}}

\)

We factor the denominator of F(s) as (s - 1)(s + 2). The expression becomes:

\(F(s) = \large{\frac{s-1}{(s-1)(s+2)}}\)

Canceling out the (s - 1) terms, we have:

\(F(s) = \large{\frac{1}{s+2}}\)

The Laplace transform of 1 is 1/s. Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(-2t) \\

d) F(s) = \large{\frac{e^{-s}(s-1)}{s^2+s-2}}\)

We can factor the denominator of F(s) as (s - 1)(s + 2). Now, we rewrite F(s) as:

\(F(s) = \large{\frac{e^{-s}(s-1)}{(s-1)(s+2)}}\)

Canceling out the (s - 1) terms, we have:

\(F(s) = \large{\frac{e^{-s}}{s+2}}\)

The Laplace transform of

\(e^(-s) \: is \: 1/(s + 1).\)

Therefore, the inverse Laplace transform of F(s) is:

\(f(t) = e^(-t)\)

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Answer:

Here is the answer

Step-by-step explanation:

If b to the power x is equal to 7 and b is a positive number, then 7 / b must equal b to the power (x-1).

We can see this by applying the definition of an exponent: b to the power x is equal to b multiplied by itself x times. For example, if b is 2 and x is 3, then 2 to the power 3 is equal to 2 * 2 * 2 = 8.

If we divide both sides of this equation by b, we get:

7 / b = (b * b * ... * b) / b = b * b * ... * b = b to the power (x-1)

Therefore, if b to the power x is equal to 7 and b is a positive number, then 7 / b must equal b to the power (x-1). The answer is therefore a) b to the power (x-1).

Step-by-step explanation:

the equation of the line simplify your answer type using integers are fraction indication points are the graph this is that what is the answer is

The explicit formula for the sequence is aₙ=(-4).(-4)ⁿ⁻¹ and the 8th term is 65536

The given sequence is -4, 16, -64, 256,...

If we observe the sequence it is a geometric sequence

aₙ=a.rⁿ⁻¹

a is the first term and r is the common ratio

From the sequence the first term is -4 and common ratio is -4

aₙ=(-4).(-4)ⁿ⁻¹

Plug in the value n as 8

a₈=(-4).(-4)⁷

The value of minus four power seven is minus sixteen thousand three hundred eighty four

a₈=(-4)(-16384)

When four is multiplied with sixteen thousand three hundred eighty four we get sixty five thousand five hundred thirty six

a₈= 65536

Hence, the explicit formula for the sequence is aₙ=(-4).(-4)ⁿ⁻¹ and the 8th term is 65536

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d = vt

a. 48 min = 0.8 h

slower = -

(x - y).0.8 = 6

x-y = 7.5 (i)

b. 36 min = 0.6 h

faster = +

(x+y).0.6 = 6

x+y = 10 (ii)

c. x - y = 7.5

   y = x - 7.5

substitute into the second equation (ii)

x + (x-7.5) = 10

2x = 17.5

x = 8.75 km/h

time at usual speed x = 8.75:

\(\tt t =\dfrac{6}{8.75}=0.686 h = 41.16\:minute\)

Answer:

$13.73 with tax

tax is 0.73 cents

Step-by-step explanation:

We simply just multiply 13 by 5.6 and get 0.728. Since we are rounding to the nearest CENT we get 0.73!

Answer:

The total would be $13.73

Step-by-step explanation:

Convert percent to a decimal: 5.6% = \(\frac{5.6}{100}\) =0.056

Percent formula: a(1+r)

13(1+0.056)

13(1.056)

13.728

and then if you round that to the nearest cent it would be 13.73