The velocity of a bus increases from 27km/h to 30m/s in . Calculate its acceleration.

We must understand both inertia and gravity to find a solution.

What is inertia?

The matter has an attribute called inertia that makes it resist changes in velocity (speed and direction). Newton's first law of motion states that an object moving at a certain speed will stay there unless an outside force acts upon it.

What is gravity?

A planet or other body's gravitational field pulls objects toward its center. The force of gravity is what keeps every planet in its orbit around the sun.

A vertical circle spun while holding a bucket full of water prevents the water from spilling out due to inertia.

Keep the bucket in place as the water tries to fly off.

Therefore we can conclude that it is false.

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(a) The magnitude of the tangential acceleration of a point on the edge of the turntable is 0.290 m/s².

(b) The time it takes the turntable to come to rest is 48.3 s.

(c) The number of revolutions the turntable makes before stopping is 4.79 revolutions.

(d) The magnitude of the torque exerted on the turntable is 0.116 Nm.

(e) The magnitude of the frictional force is 0.116 N.

(f) The magnitude of the initial angular momentum of the turntable is 0.056 kg m²/s.

(a) The tangential acceleration can be calculated using the formula a = α × r, where α is the angular acceleration and r is the radius of the turntable. Given α = -0.580 rad/s² and r = 0.20 m (half of the diameter), we find a = 0.290 m/s².

(b) The time it takes for the turntable to come to rest can be determined using the equation vf = vi + at, where vf is the final velocity (zero in this case), vi is the initial velocity (28.0 rad/s), a is the acceleration (-0.580 rad/s²), and t is the time. Rearranging the equation, we have t = (vf - vi) / a = -28.0 rad/s / (-0.580 rad/s²) = 48.3 s.

(c) The number of revolutions the turntable makes before stopping can be found using the equation θ = ωi × t + 0.5 × α × t², where θ is the angle in radians, ωi is the initial angular velocity, t is the time, and α is the angular acceleration. Since ωi = 28.0 rad/s, α = -0.580 rad/s², and t = 48.3 s, we can calculate θ = 4.79 revolutions.

(d) The magnitude of the torque exerted on the turntable can be determined using the equation τ = I × α, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. The moment of inertia for a disk rotating about its axis is given by I = (1/2) × m × r², where m is the mass of the disk and r is its radius. Substituting the given values, we find τ = 0.116 Nm.

(e) The magnitude of the frictional force can be calculated using the equation f = m × a, where f is the force, m is the mass, and a is the acceleration. Substituting the given values, we find f = 0.116 N.

(f) The magnitude of the initial angular momentum of the turntable can be calculated using the equation L = I × ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Substituting the given values, we find L = 0.056 kg m²/s.

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TRUE. When air masses of different densities collide, the less dense air mass is forced to rise through frontal lifting.

In meteorology, a front is a transition area between two air masses of different densities. The atmosphere's temperature, moisture content, and wind direction are all influenced by these air masses. The types of fronts are warm, cold, stationary, and occluded fronts. The front types are determined by the characteristics of the air masses and the direction of their movement. The types of the front are Warm front: When a warm air mass replaces a cold air mass, it is called a warm front. Warm fronts typically move more slowly than cold fronts. Cold front: A cold front happens when a cold air mass replaces a warm air mass. They have steeper pressure gradients than warm fronts, and they travel faster. Rain, thunderstorms, and cold temperatures are all common with this type of front. Stationary front: This occurs when two air masses meet and neither advances. There is a lot of rain along the stationary front. Occluded front: This is a type of front that develops when a cold front overtakes a warm front. When the cool air catches up to the warm air, an occluded front forms. The fronts can cause precipitation to fall.

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Answer:

(A)

Set the initial height equal to gt2/2 and solve for t.

h0 = gt2/2

t = √(2h0/g)

h0 = 169.2 m

g = 9.8 m/s2

Plug in the numbers and get t in seconds.

(B)

x = vxt

vx = 5 m/s

t = result from part (A) in seconds

Plug in the numbers and get x in meters.

Answer:

a.) \(5 seconds\)

b.) \(9.5 m/s\)

Explanation:

Solution is attached.

Dual convex lenses follow a set of rules that govern their behavior when light passes through them. These rules include:

1. The incoming light rays are refracted (bent) at the first lens surface, causing them to converge towards the optical axis.

2. The converging light rays then pass through the second lens surface and are refracted again, causing them to diverge away from the optical axis.

3. The point where the refracted light rays converge or diverge is known as the focal point.

4. The distance between the lens and the focal point is known as the focal length.

5. The magnification of the image formed by the lens is determined by the ratio of the distance between the object and the lens (object distance) to the distance between the image and the lens (image distance).

Overall, dual convex lenses are powerful tools for bending and focusing light, and they play a crucial role in many fields, from medicine to astronomy.

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Answer:true

Explanation:

Displacement is the vector representation of a change in position. It is path independent and is equivalent to the straight line distance between the start and end locations. Distance is a scalar quantity that reflects the path traveled.

Answer:

The atom consists of a tiny nucleus surrounded by moving electrons. The nucleus contains protons, which have a positive charge equal in magnitude to the electron's negative charge. The nucleus may also contain neutrons, which have virtually the same mass but no charge.

Explanation:

To determine the number of half-lives that have elapsed, we need to compare the ratio of 14C to 14N atoms found in the hip bone fragment.

The ratio of 1 14C atom for every 31 14N atoms suggests that the hip bone fragment contains a smaller amount of 14C compared to the expected ratio found in a living organism. Since 14C undergoes radioactive decay with a half-life of approximately 5730 years, we can calculate the number of half-lives that have elapsed by observing how many times the ratio needs to double to reach the expected ratio.

In this case, if the expected ratio is 1:1, then the observed ratio of 1:31 would require five doublings to reach 1:1. Therefore, approximately five half-lives have elapsed since the death of the organism from which the hip bone fragment originated.

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If an early frost destroys most of the apple crop, the equilibrium price of an apple is likely to increase.

An early frost that damages a significant portion of the apple crop would result in a decrease in the supply of apples. When the supply decreases, while demand remains constant or even increases, it creates a situation where the quantity demanded exceeds the quantity supplied. This imbalance in the market typically leads to an increase in the equilibrium price of apples.

With a reduced supply of apples, consumers would still desire to purchase them at the same or even higher quantities, especially if there are no close substitutes available. As a result, buyers may be willing to pay a higher price to secure the limited supply of apples. This increased demand coupled with the decreased supply causes the equilibrium price to rise.

Moreover, the extent of the increase in price will depend on the severity of the frost damage and the elasticity of demand. If the damage is severe and there are no alternative sources of apples, the price increase may be significant. However, if there are other regions or countries with unaffected apple crops that can fulfill the demand, the price increase may be relatively moderate.

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The option with the smallest mass is e. 0.020 kg of Br2.Option E

To determine which option has the smallest mass, we need to compare the masses of each given quantity.

a. 10.0 mol of F2:

To find the mass, we can use the molar mass of F2, which is 38.0 g/mol. Therefore, the mass of 10.0 mol of F2 is:

10.0 mol * 38.0 g/mol = 380 g

b. 5.50 x 10^24 atoms of 12O:

To find the mass, we need to know the molar mass of 12O. However, the given molar mass is for F2, not for 12O. Therefore, we cannot determine the mass of this option.

c. 3.50 x 10^24 molecules of 12O:

Similarly, without the molar mass of 12O, we cannot determine the mass of this option.

d. 255 g of Cl2:

Since the molar mass of Cl2 is 70.9 g/mol, the number of moles in 255 g can be calculated as:

255 g / 70.9 g/mol = 3.59 mol

e. 0.020 kg of Br2:

The molar mass of Br2 is 159.8 g/mol. To convert 0.020 kg to grams, we multiply by 1000:

0.020 kg * 1000 g/kg = 20 g

Now we can determine the number of moles:

20 g / 159.8 g/mol ≈ 0.125 mol

Comparing the number of moles, we find that option d (255 g of Cl2) has the largest number of moles, indicating a larger mass compared to the other options. Among the remaining options, option e (0.020 kg of Br2) has the smallest mass. Option e

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Any projectile traveling along a horizontal route has a horizontal velocity. Any particle or object hurled into the air at an angle other than 90 degrees goes along the trajectory line, giving the curve a parabolic shape.

The settings provided;

Height of the net, h = 1 m Horizontal distance, x = 12 m

The time of motion is determined using the formula: h = u t + 1/2gt2 1 = 0 Plus (0.5 x 9.8)

t²\s1 = 4.9t²\st= 0.45s

The formula for the ball's horizontal velocity is X = ux t u = 27 m/s.

Consequently, the ball's horizontal speed is 27 m/s.

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When you are driving your motorcycle in a circle of radius 31 m on wet pavement,

the fastest you can go before you lose traction is given by the formula:

where: r = radius of the circle, g = acceleration due to gravity, μ = coefficient of static friction and v = speed of the             motorcycle.

v = sqrt(31 * 9.8 * 0.20)

v = 7.672 m/s.

v = 7.672 m/s × 2.2369

  = 17.168 mph.

Therefore, the fastest you can go before you lose traction is 17.168 mph.

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Answer:

According to the principle of the Conservation of Energy, energy can neither be destroyed or created, energy can be transformed from form to another

The forms of energy the car has at the different stages is given by virtue of either the position of the car, which is the car's potential energy, or the speed of the car, which gives the potential energy of the car

However, due to the frictional forces acting on the car, there is a frictional force which requires work to be done for the car to move between points in the roller coaster

Therefore, based on the Conservation of Energy principle, we have;

The total energy of the roller coaster, M.E. = m·g·\(h_{max}\)

Where;

m = The mass of the roller coaster = 4,500 kg

g = The acceleration due to gravity ≈ 9.81 m/s²

\(h_{max}\) = The maximum height = 30 m

Therefore, M.E.\(_A\) = 4,500 × 9.81 × 30 = 1,324,350 J

The energy at point B, \(M.E._B\) = 4,500×15×9.81 + (1/2) ×4,500×17.15² = 1,323,950.625

The energy at point B, \(M.E._B\) = 1,323,950.625 J

At point C, the total energy, \(M.E._C\) = (1/2)·m·v²

Where;

v = The velocity of the roller coaster at point c = 24.25 m/s

Therefore;

\(M.E._C\) = (1/2) × 4,500 × 24.25² = 1,323,140.625

At point C, the total energy, \(M.E._C\) = 1,323,140.625 J

Therefore, given that the energy at point A, M.E.\(_A\) is larger than the energy at point B, \(M.E._B\), is larger than the energy at point C, \(M.E._C\), the loss in energy can be explained by the presence of the friction which require energy for movement of the roller coaster between the points

Explanation:

Answer:

a

Explanation:

The 88 sectors into which astronomers today divide the celestial sphere (the whole sky) are called constellations.

A constellation is a group of stars that make an imaginary shape in the night sky.

They are usually named after mythological characters, people, animals and objects

Astronomers divided the entire sky into 88 sectors, or constellations; this international system codifies the naming of stars and star patterns that began in prehistoric times.

Thus, the 88 sectors into which astronomers today divide the celestial sphere (the whole sky) are called constellations.

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Answer:

The "distance" is the answer to the question,

Explanation:

Answer:

499.73 m

Explanation:

We'll begin by calculating the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = –20° C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = –20 – 25

ΔT = –45 °C

Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:

Length at 25°C (L₁) = 500 m

Coefficient of linear expansion (α) = 12×10¯⁶ /°C

Change in temperature (ΔT) = –45 °C

Length at –20 °C (L₂) =?

α = L₂ – L₁ / L₁ΔT

12×10¯⁶ = L₂ – 500 / (500 × –45)

12×10¯⁶ = L₂ – 500 / –22500

Cross multiply

L₂ – 500 = 12×10¯⁶ × –22500

L₂ – 500 = –0.27

Collect like terms

L₂ = –0.27 + 500

L₂ = 499.73 m

Therefore, the length on a cold day at –20° C is 499.73 m.

Answer:

1.33mph

Explanation:

Answer:

Acceleration of one cyclist=\(2.67m/s^2\)

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, \(a=\frac{v-u}{t}\)

Using the formula

\(a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2\)

Acceleration of one cyclist=\(2.67m/s^2\)

Acceleration of another cyclist, a'=\(\frac{30-0}{8}m/s^2\)

Acceleration of another cyclist, a'=\(3.75m/s^2\)

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.

The frequency of a wave is the speed of the wave divided by its wavelength. The frequency of the wave travelling through at 2.6 m/s with the wavelength of 1.3 meters is 2 Hz.

Frequency of a wave is the number of wave cycles travelling per unit time. It is the inverse of the time period thus has the unit of s⁻¹ which is equivalent to the unit Hz.

The frequency of a wave is inversely proportional to the wavelength of the wave. The speed of the wave is related to its frequency and wavelength as:

c = νλ

given, c = 2.6 m/s

wavelength, λ = 1.3 m.

then, frequency ν = c/λ

ν  = 2.6 m/s / 1.3 m

   = 2 Hz.

Therefore, the frequency of the wave is 2 Hz.

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Answer:

I think its the second law..

Explanation:

Answer:

its the second law.

hope this helps! :)

Because they sit high up, truck drivers have excellent visibility (option c) forward.

The statement suggests that truck drivers have a good view of the road and surroundings in the direction they are moving, which is forward.

The high position of the driver's seat in trucks provides an advantageous vantage point, allowing them to see the road ahead clearly and have a better perspective of the traffic conditions.

Sitting higher than most vehicles on the road, truck drivers benefit from an elevated position that enhances their field of vision.

This elevated viewpoint allows them to have a broader and clearer view of the road, enabling them to anticipate and react to potential hazards or obstacles in advance.

The improved visibility from the elevated seat position helps truck drivers make informed decisions while driving and enhances overall safety.

In conclusion, the phrase "truck drivers have excellent visibility because they sit high up" suggests that the excellent visibility is primarily in the forward direction, providing them with a clear view of the road and surroundings ahead.

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The statements that accurately describe how physicists view the role of mathematics is: equations represent relationships between measurements; option 1

Mathematics is a branch of science that deals with numbers, formulas and related structures, shapes and spaces as well as the changes that occur in them.

Physics is a branch of science that studies matter, its constituents, motion and behavior through space and time, and their relation with energy and force.

The branches of Physics include:

Mathematics plays a very important role in physics as the equations of mathematics helps to explain relationship between measurements.

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The total work done on the system of two equal-mass pucks on frictionless ice pushed towards each other by two equal but opposite forces is negative.

When two equal but opposite forces act on two equal-mass pucks on frictionless ice, the pucks will accelerate towards each other with equal magnitude but in opposite directions.

Since the two forces are equal and opposite, the net force on the system is zero. Therefore, the acceleration of the system is zero, and the velocity of the pucks remains constant.

The work done on an object is defined as the force applied to the object multiplied by the distance over which the force acts. When the two pucks are pushed towards each other by the equal but opposite forces, each puck experiences a force over a certain distance. However, the force and the displacement are in opposite directions for each puck, resulting in negative work done on each puck separately.

However, since we are considering the system of both pucks together, the total work done on the system is the sum of the work done on each puck. Since the work done on each puck is negative, the total work done on the system is also negative.

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The physical characteristic of matter that causes it to feel a force when exposed to an electromagnetic field is called electric charge. The two types of electric charges that protons and electrons most frequently carry are positive and negative charges.

Find the force experienced by a particle with a charge of (3x10^-8 c) when it is a distance of (2x10^-2 m) away from a second particle with a charge of (6x10^-7 c)

Each fee = -Q

L is the length between charges.

decreased force =

As seen above, two particles, each with a charge of Q, are locked at a distance L apart. A net electric force F acts on every atom. The initial two particles are now locked on either side of a particle with a charge of +q.

Having said that,

The pressure at either end is

...(I)

If the charge q is positioned in the middle, then

Each end charge is under a force of

....(II)

We must determine the value of q.

Equation use (II)

Fill out the formula using the value of F.

Consequently, q is valued at q/8

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Answer:

The change in time for the first quarter is  seconds.  = 2.07

The change in time for the second quarter is  seconds.

=1.09

The change in time for the third quarter is  seconds.

=0.95

The change in time for the fourth quarter is  seconds.=0.81

Explanation:

Hope this helped.

Answer:

To the right

Weight

Explanation:

Aeronautical maps are usually meant to be used by pilots and air aviation professionals in other to navigate or traverse though the sky. With various elements such as vegetation, hills, valleys being depicted by color coded keys or legend. Hence, the absence of color on an aeronautical map make the representation of elements very difficult.

Visual map interpretation is usually aided by the use of legends. The legend hold the key to the elements which are represented on the map. Usually, a combination of colors and shapes makes up the legend and makes map interpretation easy.

Therefore, the absence of various color palletes for representation on a black and white aeronautical map will make it difficult to use.

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