In contrast, in a transverse wave, the movement of the particles is perpendicular to the direction of the wave's propagation.
The wavelength of a transverse wave can be measured as the distance between two adjacent crests or troughs. A transverse wave is a kind of wave that vibrates perpendicular to the direction of propagation. Water waves, light waves, and radio waves are all examples of transverse waves.
A transverse wave's wavelength can be measured by the distance between two adjacent crests or troughs. The distance between two adjacent crests or troughs in a transverse wave is known as the wavelength. It's also known as the distance travelled by one complete cycle of the wave.
Generally, waves are classified into two types: longitudinal waves and transverse waves. In a longitudinal wave, the motion of the particle is in the same direction as the wave's propagation. In contrast, in a transverse wave, the movement of the particles is perpendicular to the direction of the wave's propagation.
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The horizontal movement of air from an area of high pressure to an area of lower pressure
options:
wind
weather
heat
conduction
Answer:
Explanation:
A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere
Can u plz help me with my hw
Answer:
1) 4 x 25m = 100m
2) 0 because after 4 lengths, he's back at the starting block.
3) speed is distance over time so speed here is 100m/125s = 0.8m/s
4) ...
5) 100m / 1.25m/s = 80s
6.a) 100m / 0.5m/s = 200s
7.b) ... can't draw this now..
A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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A 2 kg hammer is 0.4 m above the ground. What is its PE?
What amount of charge passes through a 3. 0 amp television in 1. 3 hours?
The amount of charge that passes through a 3.0 amp television in 1.3 hours would be 14040 Coulombs.
I = Q / T
Let us first convert the time period of hours into seconds
1 hour = 3600 seconds
1.3 hours = 1.3 × 3600 seconds
= 4680 seconds
By using the above relation between electric current and electric charge
and by substituting the respective values of the charge and the time period
I = Q / T
3 = Q / 4680
Q = 3 × 4680
= 14040 Coulombs
A charge is a fundamental property of matter that describes the amount of electric charge a particle possesses. Charged particles, such as electrons and protons, interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. The charge can be either positive or negative, and opposite charges attract while like charges repel.
A charge is conserved, which means that the total amount of charge in a closed system remains constant. This conservation law is an essential principle in many areas of physics, including electromagnetism, quantum mechanics, and particle physics. The charge also plays a significant role in electrical phenomena, including circuits, electric fields, and electromagnetic radiation. It is essential to understand the charge and its properties to comprehend many aspects of the physical world around us.
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input data that directly affects glow plug operation is ____________. a) engine speed b) coolant temperature c) fuel temperature d) engine load
The correct answer to the given question is option b) coolant temperature. Input data that directly affects glow plug operation is coolant temperature.
A glow plug is a heating gadget that is intended to support the combustion process by heating the engine. It helps in starting the engine by providing heat that is required for combustion. Glow plugs are a crucial component of the diesel engine system. They help to begin the engine when it is cold by heating the air inside the cylinder. The glow plug comprises a heating element, generally a wire coil, that heats up when electricity is passed through it. It is a common sight in cold areas to see cars with thick smoke arising from the exhaust, and this happens because of the inability of the engine to warm up.In conclusion, we can say that coolant temperature is an input data that directly affects glow plug operation.
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A tone i thrown traight up. After three econd it reache the dropping point again. Find out how high it wa yeterday
H=132.3m and U=29.4ms−1 are height and velocity respectively.
What is motion?
Motion is a change in position of an object over time. It occurs when an object moves from one point to another. Motion can be described in terms of displacement, distance, speed, velocity, and acceleration. Motion can also be described using Newton's laws of motion which state that an object in motion will remain in motion unless acted upon by an external force. Motion also describes the motion of particles in a fluid or gas, as well as the motion of waves in a medium. Motion is an essential part of the physical world and is essential for understanding the fundamental laws of nature.
Motion in a straight line
Let,
u = Initial velocity of stone
H = Maximum height attained by the stone
v = final velocity at maximum height = 0
t = time taken to attain maximum height = 3s
a=−g= acceleration due to gravity
a. We know that,
V=u+at
0=u−g×3
U=3g=3×9.8ms−2
U=29.4ms−1
b. From the equations of motion, we know that,
S=ut+ ½ a t2
H=29.4×3+½ * 9.8 *32
H=88.2+44.1
H=132.3m
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help me please this assignment is due at 11:59 p.m.
Calculate the average speed of Terri's trip.
Answer:
please provide more information about the question so that I can help you
box is moving at a constant velocity static friction is 0.35 what does it take to accelate it at 1.2
If the net force on an object is zero, it will slide down an inclined plane at a constant velocity. This knowledge can be used to calculate the coefficient of kinetic friction between two objects.
The kinetic friction on a slope is denoted as f k = k m g cos. The change in velocity (v) over the change in time (t) is expressed by the equation a = v/t. This enables you to calculate how quickly velocity varies in meters per second squared (m/s2). The coefficient of friction (fr) is a quantity that represents the ratio of the frictional resistive force (Fr) divided by the normal or perpendicular force (N) pushing the objects together.
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i need the answer to this question
Answer:
You need to provide the question and (if it has them) answer options for the question. Once you have done that, delete my response so I may be able to answer your question faster than normal.
Explanation:
Aball is thrown upward and outward from a height of 6 feet. The height of the ball, f(x), in feet, can be modeled by f(x) = — 0.1x2 +1.4x+ e where x is the ball's horizontal distance, in feet, from where it was thrown. Use this model to solve parts (a) through (c). O M a. What is the maximum height of the ball and how far from where it was thrown does this occur? The maximum height is 10.9 feet, which occurs 7 feet from the point of release. .(Round to the nearest tenth as needed.) . b. How far does this ball travel horizontally before hitting the ground? El feet (Round to the nearest tenth as needed.)
The given equation, f(x) = -0.1x^2 + 1.4x + e, models the height of a ball thrown upward and outward from a height of 6 feet, where x represents the horizontal distance in feet from where the ball was thrown. Let's solve parts (a) through (c) using this model.
To find the maximum height of the ball and the distance from where it was thrown, we need to determine the vertex of the quadratic equation. The vertex can be found using the formula x = -b / 2a. In this case, a = -0.1 and b = 1.4.
\(x = -1.4 / (2 * -0.1) = 7\)
The maximum height occurs at x = 7. Substituting this value into the equation gives us:
\(f(7) = -0.1(7)^2 + 1.4(7) + e\)
=\(-0.1(49) + 9.8 + e\)
=\(-4.9 + 9.8 + e\)
= \(4.9 + e\)
So, the maximum height of the ball is 4.9 feet + 6 feet (initial height) = 10.9 feet. It occurs 7 feet from where the ball was thrown.
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Helpppp!! I will make you a brainlist Calculate the force exerted on
this test dummy with a mass of 75 kg hits an airbag accelerating at 12m/s2??
Answer:
900 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question is we have
force = 75 × 12
We have the final answer as
900 NHope this helps you
please help ill give you 100 points
Answer:
\(ke = \frac{1}{2} mv {}^{2} \)
A student walks 160m in 150s. the student stops for 30s and then walks 120m father in 140s what is the average speed of the entire walk?
Answer:
Explanation:
Average speed is always: ( total distance traveled ) / ( time elapsed )
The time for the walk is +150+%2B+30+%2B+140+=+320+ s
The distance traveled is +160+%2B+210+=+370+ m
( total distance traveled ) / ( time elapsed ) = +370+%2F+320+=+1.156+ m/s
Autotransformers are especially practical if the difference between the primary and secondary voltages is _____.
Autotransformers are especially practical if the difference between the primary and secondary voltages is realtively small.
What is Autotransformer?An autotransformer is a type of electrical transformer that has just one winding. The word "auto" refers to a single coil that runs autonomously, not to a system that runs without human intervention. The primary winding and secondary winding sides of an autotransformer are distinct portions of the same winding. While there is no metallic conducting channel between the primary and secondary windings of a normal transformer, they are separate. The autotransformer winding has at least three taps that are utilized to connect electrical appliances. In terms of size, weight, and cost, autotransformers usually outperform conventional dual-winding transformers, but they also have the disadvantage of lacking electrical isolation between the primary and secondary circuits. Autotransformers also have advantages in terms of reduced leakage reactance, fewer losses, lower excitation current, and higher VA rating for a given size and mass.Learn more about the Autotransformer with the help of the given link:
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Consider the polynomial
() = −0. 14 − 0. 153 − 0. 52 − 0. 25 + 1. 2
The true value of its derivative at x=0. 5 is ′
(0. 5) = −0. 9125. Use backward, forward, and centered
first finite differences to estimate the derivative numerically if the step size ∆ = 0. 25, and determine
the percent error between the true value and each of the estimated values (percent error is given by
= −
converted to a percentage. ) What value of ∆ would you have to use for the backward and forward
finite differences to get the same percent error as the centered finite difference (hint: it should be less
than 0. 25. )
The backward finite difference method for estimating the derivative at x=0.5 is:
(f(0.5) - f(0.25)) / (0.5 - 0.25) = (-0.14 - (-0.4025)) / (0.5 - 0.25) = 0.2625 / 0.25 = 10.5
The percent error between this estimate and the true value is:
|(10.5 - (-0.9125)) / (-0.9125)| * 100% = |11.4125 / (-0.9125)| * 100% = 12.48%
The forward finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.5)) / (0.75 - 0.5) = (-0.6275 - (-0.14)) / (0.75 - 0.5) = -0.4875 / 0.25 = -1.95
The percent error between this estimate and the true value is:
|(-1.95 - (-0.9125)) / (-0.9125)| * 100% = |-1.0375 / (-0.9125)| * 100% = 1.14%
The centred finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.25)) / (0.75 - 0.25) = (-0.6275 - (-0.4025)) / (0.75 - 0.25) = -0.225 / 0.5 = -0.45
The percent error between this estimate and the true value is:
|(-0.45 - (-0.9125)) / (-0.9125)| * 100% = |0.4625 / (-0.9125)| * 100% = 0.51%
To get the same percent error as the centred finite difference, we would have to use a step size of ∆ = 0.125.
This is because a smaller step size means a smaller difference between the estimates and the true value, and therefore a smaller percent error.
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What will be the change in "velocity" of a 991 kg car if a force of 31,770 N is applied to it for 0.4 seconds?
Answer: \(12.82\ m/s\)
Explanation:
Given
Mass of car \(m=991\ kg\)
Force applied \(F=31,770\ N\)
time period \(t=0.4\ s\)
Acceleration associated with car
\(\Rightarrow a=\dfrac{F}{m}\\\\\Rightarrow a=\dfrac{31770}{991}\\\\\Rightarrow a=32.05\ m/s^2\)
Acceleration is the change in velocity w.r.t time
\(\Rightarrow a=\dfrac{\Delta v}{\Delta t}\\\\\Rightarrow 32.05=\dfrac{\Delta v}{0.4}\\\\\Rightarrow \Delta v=12.82\ m/s\)
thus, the change in velocity is \(12.82\ m/s\)
Which scientific activities will Juno conduct on its trip to Jupiter? Check all that apply.
a. measuring the amount of water in Jupiter’s atmosphere
b. landing on the planet surface to collect rock samples
c. taking images of the planet using infrared cameras
d. taking chemical “fingerprints” of Jupiter’s gases
e. mapping Jupiter’s gravitational and magnetic field
f. transporting astronauts to the planet
Explanation:
Hope this helps,
Juno entered a polar orbit of Jupiter on July 5th 2016 UTC, to begin a scientific investigation of the planet. After completing its mission, Juno will be intentionally deorbited into Jupiters atmosphere. Junos mission is to measure Jupiters composition, gravitational field, magnetic field, and polar magnetosphere.
Answer:
1
3
4
5
or
a
c
d
e
Explanation:
7 I'LL GIVE BRAINLIST!!!
Make a list of the 10 highest mountains in the world, and indicate what kind of mountains they are
type of mountains like folded, etc. and not the kind of mountain.
Answer:
Below
Explanation:
1. Everest
2. Godwin Austen
3. Kangchenjunga
4. Lhotse
5. Makalu
6. Cho Oyu
7. Dhaulagiri
8. Manaslu
9. Nanga Parbat
10. Annapurna
Sorry I don't know anything about their types :(
I hope this helps you :)
Answer:
the 10 tallest mountains are Mount Everest, K2, Kangchenjunga, Lhotse, Makalu, Cho Oyu, Dhaulagiri, Manaslu, Nanga Parbat, and finally annapurna 1 and they are all fold
Explanation:
they are all in the himalayas And the Himalayan mountains are all folded mountains I think
GIZMO
A. Does the car's mass alone determine whether the egg breaks?
B. Does the car's speed alone determine whether the egg breaks?
C. Does the car's momentum determine whether the egg breaks?
D. Does the car's kinetic energy determine whether the egg breaks?
A box is sitting stationary on a long level ramp on level ground. The coefficient of static friction is (1.0). One end of the ramp is slowly lifted higher and higher. What is the angle of the ramp with respect to the ground when the box begins slidig?
Answer:
45 degrees
Explanation:
Given that the coefficient of friction, \(\mu=1.0\)
Let the angle of the ramp be \(\theta\).
The gravitational force acting downward \(=mg\)
The normal reaction by the ramp on the box, \(N=mg\cos\theta\)
So, the maximum frictional force that can act on the box, \(f= \mu N\)
The force along with the plane in the direction of sliding, \(F = mg\sin\theta\)
When the box begins sliding, the F must have to overcome the frictional force,f.
So, F=f
\(mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\\)
Putting the value of \mu, we have
\(\theta=\tan^{-1}1\)
\(\theta=45\) degrees.
Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.
Seth and Diana were asked to be the leaders for a game of tag during recess at school. Seth and Diana can ensure that all interested students get a chance to participate equally regardless of ability to run fast by having the: Tagged players sit out until the next game starts Tagged players perform a fitness activity then return to the game Two youngest students be the taggers Two fastest students be the taggers
Answer:
B
Explanation:
did this yesterday with my friend
Answer: Tagged players perform a fitness activity
Explanation: Proof of validity is shown below.
An object is traveling at a velocity of 96 m/s North. After 23 seconds, what distance has the object traveled?
Radar waves of wavelength 50 mm are emitted from two aerials and create a fringe pattern 1 kilometer from the aerials. Calculate the distance between the aerials if the fringe spacing is 80 cm.
If the fringe spacing is 80 cm, the distance between the aerials is 6.25 meter.
What is interference?In physics, interference refers to the combined result of two or more wave trains travelling along intersecting or converging trajectories. The result is the result of adding the individual wave amplitudes at each place that is influenced by multiple waves.
Given: wavelength = 50 mm = 50 × 10⁻⁴ m
the fringe spacing is = 80 cm = 0.80 m.
x = λD/d
d = λD/x
= 50 × 10⁻⁴ × 1000/0.80 m
= 6.25 meter.
Hence, the distance between the aerials is 6.25 meter.
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Does kinetic energy stay the same at all heights? pls help I have 12 minutes to finish the project and the teacher won't help me :(
Answer:
Kinetic energy does not stay the same at all heights
Explanation:
Well as the height and wind increase so does the kinetic energy it's like when you fall as you are about to hit the floor you speed increases
HOPE THIS HELPS YA :)
Can you explain for me Colomb's Torsion Balance Experiment
The two experiments that Coulomb's to show the relationship between electrostatic force and that law carries Coulomb's name today to include this relationship as a fundamental component.
Torsion balance is used to study the repulsion and attraction forces of charged particles and found that the strength of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
A bar is suspended from the centre of the torsion balance by a thin fibre. The fibre functions as a flimsy torsion spring.
The torsion balance in Coulomb's experiment was a suspended metal-coated ball attached to one end of an insulating rod.
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find the kinetic energy of 5 litre of a gas at STP given standard pressure is 1.013 into 10 to the power 5 Newton per metre square
Answer:
1.52 kJ
Explanation:
Total kinetic energy in gas K = 3NkT/2 where N = number of molecules, K = Boltzmann constant and T = temperature.
Also from the ideal gas law, PV = NkT
substituting PV into K above
K = 3PV/2 where P = pressure = 1.013 × 10⁵ N/m² and V = volume of gas = 5 litres = 5 dm³ = 5 × 10⁻³ m³
K = 3 × 1.013 × 10⁵ N/m² × 5 × 10⁻³ m³/2
= 1519.5 J
= 1.5195 kJ
≅ 1.52 kJ
which of the following properties of materials does NOT affect resistance?
A. Length
B. Thickness
C. Temperature
D. Strength of the material
Answer:
B thickness
Explanation:
thickness
what effect does an unbalanced force have on an object?
Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.