The weight, in grams, of plastic parts created in a blow molding operations is recorded. The tolerances for weight are 460 to 500 grams. The goal quality level is 100 NCPPM. During one production run of 6 hours, subgroups were collected periodically. The data are provided in the accompanying Excel file (tab labeled "Plastic"). The following notes were indicated during the run: (a) a new batch of raw material was started after Subgroup 6, (b) the operator took a break and was replaced by an inexperienced operator after Subgroup 12, and (c) The normal weighing scale was borrowed and replaced temporary with an older scale for Subgroup 20. Using the Xbar/s Charts, determine whether or not any of these events influenced the part weights, and, if so, state how they affected the process. Subgroup 1 2 3 4 5 6 7 8 9 10 11 12 Part 1 472.2 472.0 478.6 476.7 482.6 466.0 471.9 478.5 469.7 471.6 473.8 475.0 478.2 477.4 474.4 468.2 484.5 472.8 468.3 470.2 476.5 475.6 482.0 469.4 478.9 Part 2 472.0 470.2 477.4 472.9 476.9 478.9 459.2 480.6 471.9 472.7 472.2 472.8 480.8 475.2 473.7 470.9 471.6 472.4 474.4 467.7 475.9 475.0 471.9 478.7 470.2 Part 3 472.9 473.9 476.4 468.7 470.7 470.8 488.7 473.0 471.8 475.5 479.5 478.2 468.4 476.5 473.7 473.6 471.0 477.9 479.0 469.0 478.1 481.9 482.1 477.0 468.8 Part 4 474.5 481.0 475.0 474.3 466.4 473.2 474.1 468.6 472.3 470.9 478.9 474.4 478.2 477.3 468.5 471.0 467.3 477.0 471.3 465.1 478.7 475.7 479.8 481.2 480.2 13 In 14 15 16 17 18 19 20 21 22 23 24 25

The exercise involves finding the product C = AB, where matrix A is given by [2 9] and matrix B is given by [3 6 1]. We need to perform the matrix multiplication to obtain the resulting matrix C.

Let's calculate the matrix product C = AB step by step:

Matrix A has dimensions 2x1, and matrix B has dimensions 1x3. To perform the multiplication, the number of columns in A must match the number of rows in B.

In this case, both matrices satisfy this condition, so the product C = AB is defined.

Calculating AB:

AB = [23 + 912 26 + 94 21 + 95]

[103 + 612 106 + 64 101 + 65]

Simplifying the calculations:

AB = [6 + 108 12 + 36 2 + 45]

[30 + 72 60 + 24 10 + 30]

AB = [114 48 47]

[102 84 40]

Therefore, the product C = AB is:

C = [114 48 47]

[102 84 40]

In summary, the matrix product C = AB, where A = [2 9] and B = [3 6 1], is given by:

C = [114 48 47]

[102 84 40]

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Answer:

Step-by-step explanation:

To determine the number of tons of metal per year needed for Machine A to be favored over Machine B, we compare their costs. Machine A costs $323,000 with an annual operating cost of $2.40/ton, while Machine B costs $178,000 with an annual operating cost of $8.00/ton. The machines have useful lives of 10 years and 6 years, respectively, and the minimum attractive rate of return (MARR) is 18% per year.

By calculating the equivalent annual costs (EAC) for each machine using the given formula and comparing them, we can determine the point at which Machine A becomes more favorable. However, specific values for the discounting factors and the tons per year needed are missing, making it impossible to provide an exact answer.

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The number of paper newsletters the school needed is given by the equation A = 149.5

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of paper newsletters the school needed be A

Now , the equation will be

The percentage of parents who prefers newsletters electronically = 77 %

So , percentage of parents who prefers paper newsletters = 100 % - 77 %

The percentage of parents who prefers paper newsletters = 23 %

The total number of parents = 650

So , the number of paper newsletters the school A = percentage of parents who prefers paper newsletters x total number of parents

Substituting the values in the equation , we get

The number of paper newsletters the school A = ( 23/100 ) x 650

The number of paper newsletters the school A = 149.5

Therefore , the value of A is 149.5

Hence , the equation is A = 149.5

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Answer:

12.5\(\sqrt{3}\)

Step-by-step explanation:

30-60-90 triangles always have the height be    sqrt3 the base.

Answer:

Using the estimate:

The car has to go for 1,200 miles but it consumes a gallon of gasoline for every 30 miles. The number of gallons it will need is therefore:

= 1,200 / 30

= 40 gallons

Each gallon costs $3.00 so the total cost is:

= 40 * 3

= $120

Without using the estimate:

The car has to go for 1,211 miles but it consumes a gallon of gasoline for every 29 miles. The number of gallons it will need is therefore:

= 1,211 / 29

= 41.76 gallons

Each gallon costs $3.40 so the total cost is:

= 41.76 * 3.40

= $‭141.98

Using the estimate provides a lower cost of gasoline for the trip.

Answer:

C. five samples.

Step-by-step explanation:

The largest value that f(4) can possibly be is 29.

The mean value theorem states that for a function f(x) that is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), there exists a number c in the open interval (a, b) such that:

f(b) - f(a) = f'(c)(b - a)

In this case, we are given that f(0) = -3 and that f'(x) ≤ 8 for all values of x. To determine how large f(4) can possibly be, we can use the mean value theorem with a = 0 and b = 4:

f(4) - f(0) = f'(c)(4 - 0)

Substituting the given values:

f(4) - (-3) = f'(c)(4)

f(4) + 3 = 4f'(c)

Since f'(x) ≤ 8 for all values of x, we can say that f'(c) ≤ 8. Therefore:

f(4) + 3 ≤ 4f'(c) ≤ 4(8) = 32

Therefore, we have:

f(4) ≤ 32 - 3 = 29

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Answer:

2x-y and 3x+y

Step-by-step explanation:

2x-y=3

3x+y=7

I'm not sure...

Answer:

The first one

Step-by-step explanation:

Do you really want an explanation  :v

Answer:

Can’t really see the end of the question but if it is 3/w it is most likely

c

Step-by-step explanation:

Answer:

208

Step-by-step explanation:

4*30 = 120

(15-4) * 8 = 88

88 + 120 = 208

Answer:

208 cm

Step-by-step explanation:

Solving right side first. 8*15=120

Take out 8cm from 30. 30 - 8 = 22

22*4= 88

88 + 120 = 208

Check work I found the total area and the white rectangle.

15*30=450 which in total area

15-4=11 11 is the left/right side of the white rectangle

30-8=22 22 is the top/bottom side of the white rectangle.

22*11= 242

208+242=450

Answer:

1/12 or 0.0833

Step-by-step explanation:

P(Coin) = 1/2

P(Dice) = 1/6

1/2 × 1/6 = 1/12

By using the simulated results and the law of large numbers, we can estimate that the probability of answering exactly 15 questions correct on a 30-question exam with a 35% chance of getting each question correct is approximately 7.2%.

Based on the simulated results, we can estimate the probability of answering exactly 15 questions correct on a 30-question exam with a 35% chance of getting each question correct. To do this, we first need to look at the histogram or table of the simulated results to see how many of the 1000 exams scored 15.

If we look at the histogram or table, we can see that there were 72 out of 1000 exams that scored exactly 15. This means that the proportion of exams that scored 15 is 72/1000 or 0.072.

Using the law of large numbers, we can estimate that this proportion is the same as the probability of answering exactly 15 questions correctly on a 30-question exam with a 35% chance of getting each question correct. Therefore, the estimated probability of answering exactly 15 questions correct is 0.072 or 7.2%.

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Linear expression has only first-order linear terms. The only expression from all the given expressions that is linear is 9x − 2.

A linear expression is an expression that can be put in the form of y=mx+c,

therefore, it has only one variable and is of the first order.

As we have discussed the linear expression, therefore, if the equation can be put in the form of y=mx+c then that expression will be a linear expression.

A.) 9x − 2

As the equation is of the first order and can be arranged as,

0 = 9x + (-2)

Thus, the expression is of the first order

B.) 3x² + 4x − 5

The expression given is not of the first order, therefore, it is not a linear expression.

C.) 5x³ + 6x² − 7x + 8

The expression given is not of the first order, therefore, it is not a linear expression.

D.) 4x⁴ − 5x³ + 6x² − 7x + 8

The expression given is not of the first order, therefore, it is not a linear expression.

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Answer:

9x-2

Step-by-step explanation:

I got it right and the guy up top is right :)

hope this helps ~~~~Wdfads~~~``

A fraction is a smaller part of a whole number.

A whole number is defined as the number that is natural and it includes numbers such as 0, 1,2,3,4,5,6,7,8,9, 10. This means that is doesn't contain numbers that has decimal points or fractions such as. 1.5 or 1½ respectively.

A fraction is defined as the part of a whole value such as 1/4 which is 25% of 1. This means that it is the smaller part of a whole number.

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For the given problem, The probability of getting a number greater than 2 or less than 2 on the spinner, rounded to the nearest tenth, can be given by 83.3%.

The given spinner will have four numbers larger than two, i.e. 3, 4, 5, and 6.

While, there is only one number on the given spinner that is less than 2, i.e. 1.

So, the total number of favorable outcomes (numbers greater than 2 or less than 2) is 4 + 1 = 5.

Since there are a total of 6 equally likely possible outcomes (numbers 1 through 6 on the spinner), the probability of getting a number greater than 2 or less than 2 would be 5 out of 6 as:

\(Probability = \text{(Number of favorable outcomes / Total number of possible outcomes) * 100}\\\\Probability = (5 / 6) * 100\\\\Probability = 83.3\%\)

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The answer is 100%, rounded to the nearest tenth.

What is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.

If the spinner has equally likely outcomes, then the probability of getting a number greater than 2 or less than 2 is 1, since every number on the spinner is either greater than 2 or less than 2.

When we spin a spinner with equally likely outcomes, each possible outcome has the same chance of occurring. In this case, the spinner has numbers from 1 to 4, and half of these numbers are greater than 2 and half are less than 2.

Therefore, if we want to find the probability of getting a number that is greater than 2 or less than 2, we simply add up the probabilities of these two events, which gives us 1 (or 100% as a percentage).

So, the answer is 100%, rounded to the nearest tenth.

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We can conclude that the special tutoring session seems to have had a positive impact on the students' performance, as their mean score increased from below 60% to 70%.

We can conclude that the special tutoring session has been effective since the students' mean score increased from 60 percent to 70 percent on the second test.

The students who scored less than 60 percent on the first test were given a special tutoring session, which resulted in their mean score increasing to 70 percent on the second test.

Therefore, we can conclude that the special tutoring session has been effective in improving the students' performance on the second test.

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(a) The Null And Alternate hypothesis are stated below,

(b) The value of test-statistic is 3,

(c) The "p-value" is 0.0013,

(d) The hypothesis is rejected because p-value is less than 0.025.

Part (a) : The appropriate null and alternative hypotheses are:

Null hypothesis (H₀): The average LSAT score at the University of Pennsylvania is equal to or less than the national average of 1,300.

Alternative hypothesis (Hₐ): The average LSAT score at the University of Pennsylvania is significantly higher than the national average of 1,300.

Part (b) : To calculate the test-statistic, we use formula : t = (x' - μ)/(s / √n),

where x' = sample mean, μ = hypothesized population mean, s = sample standard deviation, and n = sample size.

Substituting the given values,

We get,

t = (1375 - 1300)/(125 / √25) = 3;

So, the value of the test statistic is 3.

Part (c) : To calculate "p-value", we need to find the probability of getting a t-value as extreme or more extreme than 3, assuming that the null hypothesis is true.

We know that for a two-tailed test at a significance level of 0.03, the p-value is approximately 0.0013.

Part (d) : To test the hypotheses using the p-value, we compare it to the significance-level.

Since the p-value is less than 0.025 (half of the significance level for a two-tailed test), we reject the null hypothesis and conclude that there is sufficient evidence to support the claim.

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The given question is incomplete, the complete question is

The admissions officer for the graduate programs at the university of Pennsylvania believes that the average score on the LSAT exam at his university is significantly higher than the national average of 1,300. an accepted standard deviation for LSAT scores is 125. random sample of 25 scores had an average of 1,375.

(a) State the appropriate null and alternative hypotheses.

(b) Calculate the value of the test statistic

(c) Calculate the p-value.

(d) Use the p-value to test the hypotheses and conduct the test at the 0.025 level.

The values of p, q, and r are p = 2, q = 5, and r = 3, respectively.

Given that the lowest common multiple (LCM) of A and B is 2250, and the prime factorization of A is A = 2 × p × q¹, and the prime factorization of B is B = 2 × p² × q², we can compare the prime factorizations to determine the values of p, q, and r.

From the prime factorization of 2250 (2 × 3² × 5³), we can observe the following:

The prime factor 2 appears in both A and B.

The prime factor 3 appears in A.

The prime factor 5 appears in A.

Comparing this with the prime factorizations of A and B, we can deduce the following:

The prime factor p appears in both A and B, as it is present in the common factors 2 × p.

The prime factor q appears in both A and B, as it is present in the common factors q¹ × q² = q³.

From the above analysis, we can conclude:

p = 2

q = 5

r = 3.

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Answer:

A = 20

B = 12.5

C = 10.2

Step-by-step explanation:

A = (10 + 20 + 30)/3 = 20

B = (5 + 10 + 15 + 20) = 12.5

C = (1 + 5 + 10 + 15 + 20) = 10.2

The grammar S → ab|aS|aaS can be converted into Greibach normal form as follows: S → ab|AS|AAS

Start by eliminating left recursion: In the original grammar, the production aS introduces left recursion. To eliminate it, we replace aS with a new non-terminal symbol A and rewrite the grammar as follows:

S → ab|AS|AAS

A → ε|S

Remove the ε-production: The non-terminal A in the above grammar has an ε-production, which can be removed by introducing a new non-terminal symbol B and rewriting the grammar as follows:

S → ab|AS|AAS

A → BS

B → S

Eliminate right recursion: The production A → BS introduces right recursion. We can eliminate it by introducing a new non-terminal symbol C and rewriting the grammar as follows:

S → ab|AS|AAS

A → CS

B → SC

C → ε

Convert to Greibach normal form: Finally, we can convert the grammar to Greibach normal form by replacing the occurrences of terminals in the right-hand side of the productions with new non-terminal symbols, and rewriting the grammar as follows:

S → AB|AC|AAC

A → CC

B → CA

C → ε

Therefore, the grammar S → ab|aS|aaS can be converted into Greibach normal form as shown above.

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Step-by-step explanation:

x³×15-6

15x³-6

2. Let the number be y, then

(4×y)+(5/3)

4y+5/3

The percentage increase of last year's attendance is 24%

In this year, There are 558 people went to the performance.

Last year, There are 450 theatre-goers attended a performance at St. Lawrence Centre.

We have to find the increase as a percentage of last year's attendance.

Now, According to the question:

Subtract from In this year's people to last year's people.

=> 558 - 450

=> 108 people more attended from the last year.

Now, Find the increment of percentage.

We know that, For calculation in percentage multiply by 100

=> 108 / 450 × 100 = 24

The percentage increase of last year's attendance is 24%

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Comparing rates, the greater the kilometer per hour, the faster the flight as well as the least minute spent on a kilometer, the faster the flight

Distance between two points is the length of the line segment that connects the two given points. Distance between two points in coordinate geometry can be calculated by finding the length of the line segment joining the given coordinates.

However, in this case, we are not only considering distance but as well comparing the speed or time taken to travel from point A to point B.

We have several rates in which we can use or aid us in this comparison and the two in which Lebron needs to consider are

In determining the speed using least km/hr, the greater the kilometer covered in an hour, the faster the flight.

In the second option, the lower the minute spent on a kilometer, the fast the flight.

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this is simplify? I think it's simplify so I can give you an answer