The density of the other fluid is 1000 kg/m^3 - 0.1 kg/m^3 = 999.9 kg/m^3.
We can use the Archimedes' principle to solve this problem, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The buoyant force on the object in water is:
Buoyant force = Weight of water displaced by object = Density of water x Volume of object x g
We know that the weight of the object in water is 15 N, and its mass is 2 kg. Therefore, the gravitational force acting on the object is:
Force = mass x g = 2 kg x 10 m/s^2 = 20 N
The weight of the object in the other fluid is 18 N, which means that the buoyant force on the object in this fluid is:
Buoyant force = 18 N - 20 N = -2 N
The negative sign indicates that the buoyant force is acting in the opposite direction to the gravitational force.
Using Archimedes' principle, we can set the buoyant force equal to the weight of the fluid displaced by the object:
Buoyant force = Density of other fluid x Volume of object x g
Substituting the values we have:
-2 N = Density of other fluid x Volume of object x 10 m/s^2
We know the volume and density of the object (assuming it is the same in both fluids), so we can solve for the density of the other fluid:
Density of other fluid = -2 N / (Volume of object x 10 m/s^2)
Density of other fluid = -2 N / (2 kg / 1000 kg/m^3 x 10 m/s^2)
Density of other fluid = -0.1 kg/m^3 (Note: the negative sign indicates that the buoyant force is acting in the opposite direction to the gravitational force, but the density of the fluid cannot be negative)
Density of the other fluid is 1000 kg/m^3 - 0.1 kg/m^3 = 999.9 kg/m^3.
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When you pedal really fast on a bike, you can feel the wind slowing you down.
Which force causes this?
O
A. Strong nuclear force
B. Magnetic force
O
OD. Gravity
C. Air resistance
Answer:
the answer is the option C
When a 10-V battery is connected to a resistor, the current in the resistor is 2 A. What is the resistor's value
Answer:
5 ohms
Explanation:
V = IR
10 = 2 R
R = 5
If your liquid crystal mixture is iridescent at about 15 deg c, how could you change the method so that iridescence is observed at about 25 deg c?
To change the method so that iridescence is observed at about 25 degrees Celsius instead of 15 degrees Celsius, you would need to modify the liquid crystal mixture.
Here's a step-by-step explanation:
1. Understand the concept: Iridescence in liquid crystals occurs due to changes in their molecular arrangement. At a specific temperature, the molecules align in a way that causes light to be reflected and interfere, resulting in the iridescent effect.
2. Analyze the current situation: At 15 degrees Celsius, the liquid crystal mixture exhibits iridescence. This suggests that the molecular arrangement is suitable for iridescent reflection at this temperature.
3. Identify the desired change: To observe iridescence at 25 degrees Celsius, we need to modify the liquid crystal mixture's molecular arrangement so that it reflects light at this higher temperature.
4. Research suitable liquid crystal mixtures: Look for liquid crystal mixtures that exhibit iridescence at temperatures around 25 degrees Celsius. This may involve reviewing scientific literature, consulting experts, or conducting experiments.
5. Modify the mixture composition: Adjust the composition of the liquid crystal mixture based on the research findings. This could involve changing the types or ratios of liquid crystal molecules, additives, or solvents used in the mixture.
6. Experimental verification: Prepare samples of the modified liquid crystal mixture and test them at around 25 degrees Celsius. Observe the samples under appropriate lighting conditions to check for iridescence.
7. Analyze the results: If the modified mixture does not exhibit iridescence at 25 degrees Celsius, further adjustments may be necessary. You might need to repeat steps 4 to 6 until the desired effect is achieved.
8. Draw a conclusion: Once you have successfully modified the liquid crystal mixture to exhibit iridescence at 25 degrees Celsius, you can conclude that the method change was successful.
Remember, the details of the specific modifications required will depend on the nature of the liquid crystal mixture and its response to temperature.
It is important to consult relevant scientific resources and possibly collaborate with experts to ensure the accuracy and effectiveness of your modifications.
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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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Let a particle of charge q and rest mass m be released with zero initial velocity in a region of space containing an electric field E in the y direction and a magnetic field B in the z direction. (a) Describe the conditions necessary for the existence of a Lorentz frame in which (1) E = 0 and (2) B = 0.
In order for a Lorentz frame to exist in which E=0 and B=0, the particle's velocity must have a specific magnitude and direction relative to the fields.
For a Lorentz frame to exist in which E=0, the velocity of the particle must be in the x direction, perpendicular to the y-direction of the electric field. This means that the Lorentz transformation must have a y-component equal to zero, so that the electric field disappears in the transformed frame. Similarly, for a Lorentz frame to exist in which B=0, the velocity of the particle must be in the y direction, perpendicular to the z-direction of the magnetic field. This means that the Lorentz transformation must have a z-component equal to zero, so that the magnetic field disappears in the transformed frame. In both cases, the velocity of the particle must have a specific magnitude and direction relative to the fields in order for a Lorentz frame to exist in which the fields disappear.
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what is the total pressure on a diver at a depth of 20m in sea water with a density of 1.03g/cubic cm under normal atmospheric pressure
The total pressure experienced by the diver at the given depth is 201,880 Pa.
The given parameters:
Depth of the sea water, h = 20 mDensity of the water, ρ = 1.03 g/cm³What is pressure?Pressure is the force per unit area experienced by an object. Pressure increase with depth.The total pressure experienced by the diver at the given depth is calculated as follows;
\(P = \rho g h\)
where;
ρ is the density of the liquid (kg/m³)
g is acceleration due to gravity
1.03 g/cm³ = 1,030, kg/m³
P = (1030) x (9.8) x (20)
P = 201,880 N/m²
Thus, the total pressure experienced by the diver at the given depth is 201,880 Pa.
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7) Find F1 and F2
HELP PLEASEEE
The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.
If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.
The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.
F2 = 45 cos 30 = 38.9 N.
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What is the main difference between protons and neutrons?
Answer:
Protons are a type of subatomic particle with a positive charge. Protons are bound together in an atom's nucleus as a result of the strong nuclear force. Neutrons are a type of subatomic particle with no charge (they are neutral).
what is the magnitude of the acceleration experienced by an electron in an electric field of 750n/c? how does the direction of the acceleration depends on the direction of the field at that point?
The magnitude of the acceleration experienced by an electron in an electric field of 750 N/C is approximately 1.318 × 10¹⁴ m/s².
If the electric field is in the direction of positive x-axis, the electron will be accelerated in the negative x-axis direction. If the electric field is in the direction of positive y-axis, the electron will be accelerated in the negative y-axis direction, and so on.
The magnitude of the acceleration experienced by an electron in an electric field can be calculated using the formula:
a = F/m
where F is the force experienced by the electron in the electric field, and m is the mass of the electron.
The force experienced by an electron in an electric field is given by:
F = qE
where q is the charge of the electron, and E is the electric field strength.
The mass of an electron is approximately 9.11 × 10⁻³¹ kg, and the charge of an electron is -1.602 × 10⁻¹⁹ C.
Substituting these values, we get:
F = (-1.602 × 10⁻¹⁹ C) × (750 N/C) = -1.2015 × 10⁻¹⁶ N
a = F/m = (-1.2015 × 10⁻¹⁶ N) / (9.11 × 10⁻³¹ kg) ≈ -1.318 × 10¹⁴ m/s²
Therefore, the magnitude of the acceleration experienced by an electron in an electric field of 750 N/C is approximately 1.318 × 10¹⁴m/s².
The direction of the acceleration of the electron depends on the direction of the electric field at that point. By convention, the direction of the electric field is the direction in which a positive charge would experience a force. Since the charge of an electron is negative, the force experienced by an electron in an electric field is opposite in direction to the electric field.
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A spring is attached to the ceiling, and when a brick is suspended from the spring at rest, it stretches by 50 cm. If instead two identical copies of the same spring are placed side-by-side and both attached to the brick and the ceiling, how much will each of the springs stretch by
This question involves the concepts of the parallel combination of springs, Hooke's Law and equivalent spring constant.
Each spring will stretch by "25 cm".
For static condition of spring:
Weight of Brick = Extension Force
using Hooke's Law:
\(mg = kx\)
Consider the following data for a single spring:
K₁ = spring constant of single spring = K
x₁ = stretch in single spring = 50 cm
m = mass of brick
g = acceleration due to gravity
Therefore,
\(mg = k_1x_1\\mg = K(50\ cm) ---- eqn(1)\)
Now, for the second scenario, where two identical copies of the single spring are placed side by side in a parallel combination:
K₂ = Equivalent spring constant of the parallel combination of springs
K₂ = K + K = 2K
x₂ = stretch in each spring in the parallel combination of springs = ?
m = mass of brick
g = acceleration due to gravity
Therefore,
\(mg = k_1x_1\\mg = 2K(x_2) ---- eqn(2)\)
dividing eqn (1) and eqn(2), we get:
\(1 = \frac{50\ cm}{2x_2}\\\\\)
x₂ = 25 cm
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The attached picture illustrates Hooke's Law.
A train goes forward for 50 m, then backward for 25 m, and finally forward again for 40 m. This took place in 4.5 minutes. What was the magnitude of the average velocity of the train?
The magnitude of the average velocity of the train is 0.426 m/s.
What is average velocity?Average velocity can be defined as the ratio of the total dfistance covered by a body to the total time.
To calculate the average velocity of the of the train, we use the formula below.
Formula:
V = D/t.......... Equation 1Where:
V = Average velocity of the trainD = Total Distance traveled by the traint = Total timeFrom the question,
Given:
D = 50+25+40 = 115 mt = 4.5 minutes = 4.5×60 = 270 sSubstitute these values into equation 1
V = 115/270V = 0.426 m/sHence, the magnitude of the average velocity of the train is 0.426 m/s.
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You have a 1.0-m-long copper wire. You want to make an
N-turn current loop that generates a 1.0 mT magnetic field at the
center when the current is 1.0 A. You must use the entire wire.
'What will be the diameter of your coil?
If the coil is needed to generate a 1.0 mT magnetic field at the center with a 1.0 A current, the diameter of your coil will be approximately 8.14 cm.
To determine the diameter of the coil needed to generate a 1.0 mT magnetic field at the center with a 1.0 A current, follow these steps:
1. First, we need to find the number of turns (N) in the coil. Use the formula for the magnetic field at the center of a current loop: B = (μ₀ * N * I) / (2 * R), where B is the magnetic field, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns, I is current, and R is the radius of the coil.
2. Rearrange the formula to find the radius: R = (μ₀ * N * I) / (2 * B).
3. Next, we need to find the length of the wire required to make N turns. The length (L) of the wire is equal to the circumference of the coil (2πR) multiplied by the number of turns (N): L = N * 2πR.
4. Rearrange this formula to find N:
N = L / (2πR).
5. Substitute this expression for N in the formula for R from step 2:
R = (μ₀ * (L / (2πR)) * I) / (2 * B).
6. Solve this equation for R, using the given values of L = 1.0 m, I = 1.0 A, and B = 1.0 mT (or 0.001 T): R ≈ 0.0407 m.
7. Finally, find the diameter of the coil by multiplying the radius by 2:
Diameter = 2 * R ≈ 0.0814 m, or approximately 8.14 cm.
So, the diameter of your coil will be approximately 8.14 cm.
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A capillary tube 2mm in diameter is immersed in a beaker of mercury,
The mercury level inside the tube is found to be 0.5cm below the level
of the reservoir.
Determine the contact angle between the mercury
and the glass. (Tm=0.4N/m, Pm 13.6 x 103kg/m3).
Calculate the density of paraffin oil, if a glass capillary of diameten
offin oil of the curface tension 0245N/m rises
7.3
The contact angle between the mercury and the glass is approximately 19.3 degrees. The density of the paraffin oil is approximately 840 kg/m³.
Contact Angle with Mercury:
To determine the contact angle between mercury and the glass, we need to use the Young-Laplace equation:
P = Tm * (1/R1 + 1/R2) * cos(theta)
Where:
P is the pressure difference between the inside and outside of the capillary,
Tm is the surface tension of mercury,
R1 and R2 are the principal radii of curvature of the meniscus,
and theta is the contact angle.
In this case, the pressure difference is given by the hydrostatic pressure difference due to the height difference of the mercury column inside the capillary.
Given data:
Tm (surface tension of mercury) = 0.4 N/m,
Height difference = 0.5 cm
= 0.005 m,
Diameter of the capillary = 2 mm
= 0.002 m.
The radius of the capillary (r) = diameter/2
= 0.001 m.
The radius of curvature (R1 or R2) = r/2
= 0.0005 m.
The pressure difference (P) is given by the hydrostatic pressure difference:
P = rho_m * g * h
Where:
rho_m is the density of mercury,
g is the acceleration due to gravity,
h is the height difference.
Given data:
rho_m (density of mercury) = 13.6 x 10³ kg/m³,
g (acceleration due to gravity) = 9.8 m/s².
Substituting the values into the equation, we get:
P = (13.6 x 10³ kg/m³) * (9.8 m/s²) * (0.005 m)
= 0.6668 kPa.
Now, we can rearrange the Young-Laplace equation to solve for the contact angle (theta):
cos(theta) = (P * R1) / Tm
Substituting the values, we get:
cos(theta) = (0.6668 kPa * 0.0005 m) / 0.4 N/m
= 0.8335.
Taking the inverse cosine (arccos) of both sides, we find:
theta = arccos(0.8335)
= 19.3 degrees.
Therefore, the contact angle between the mercury and the glass is approximately 19.3 degrees.
Density of Paraffin Oil:
To calculate the density of paraffin oil, we can use the same principle as the previous calculation.
Given data:
Surface tension of paraffin oil (Tpo) = 0.245 N/m,
Rise in the glass capillary (hpo) = 7.3 cm
= 0.073 m.
Using the Young-Laplace equation:
Ppo = Tpo * (1/R1 + 1/R2) * cos(theta)
As before, the pressure difference (Ppo) is given by the hydrostatic pressure difference:
Ppo = rho_po * g * hpo
Where:
rho_po is the density of paraffin oil.
Substituting the values, we get:
rho_po * g * hpo = Tpo * (1/R1 + 1/R2) * cos(theta)
Rearranging the equation to solve for the density of paraffin oil, we have:
rho_po = (Tpo * (1/R1 + 1/R2) * cos(theta)) / (g * hpo)
Substituting the known values, we get:
rho_po = (0.245 N/m * (2/0.002 m⁻¹ + 2/0.001 m⁻¹) * cos(0.8335)) / (9.8 m/s² * 0.073 m)
Calculating the expression, we find:
rho_po ≈ 840 kg/m³.
Therefore, the density of paraffin oil is approximately 840 kg/m³.
The contact angle between the mercury and the glass capillary is approximately 19.3 degrees. Additionally, the density of paraffin oil is approximately 840 kg/m³. These calculations were made using the Young-Laplace equation and considering the hydrostatic pressure difference due to the height difference.
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what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake
The medium for an ocean wave is the ocean water which involves movement on the water body.
What is a Medium?This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.
The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.
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An object 0.1 m tall is placed 0.4 m from a convex mirror with a focal length of 0.3 m. What is the height of the image?
Answer: no exact answer
=
Explanation:
when electromagnetic radiation (e.g., light) is doppler-shifted by motion of the source away from the detector the
When electromagnetic radiation is Doppler-shifted by motion away from the detector, the observed wavelength increases.
What causes Doppler shift effect?When an object emitting electromagnetic radiation, such as light, is moving away from an observer (detector), the wavelengths of the observed radiation are stretched or increased.
This phenomenon is known as the Doppler shift. It occurs because the motion of the source affects the perceived frequency or wavelength of the radiation. When the source is moving away, the observed wavelength is longer compared to the emitted wavelength.
This effect can be observed in various contexts, such as the redshift observed in the light from distant galaxies, indicating their recession from us due to the expansion of the universe.
Additionally, it is relevant in understanding the behavior of stars, galaxies, and other astronomical objects. By analyzing the Doppler shift, scientists can infer important information about the motion and velocity of celestial objects.
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3x+5=40 solve for x to get the answer.
This is question isnt real i just need to talk
with someone
Explanation:
3x=40-5
3x=35
x=35/3
x=11.66 or x=11 2/3
BRAINLIEST AND 100 POINTS
What are some of the challenges for manned space exploration associated with the differences in gravity?
Select all correct answers.
1. Cardiovascular deterioration
2. Dementia
3. Bone deterioration
4. Muscle deterioration
What must be true about a surface in order for diffuse reflection to occur?
Answer:
carpet
Explanation:
Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.
The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.
what is the primary reason that we cannot observe galaxies that are 60 billion light years away from us?
The primary reason we cannot observe galaxies that are 60 billion light years away from us is that the age of the universe is approximately 13.8 billion years, which means that the light from those galaxies has not had enough time to reach us.
The speed of light is approximately 299,792 kilometers per second (or about 186,282 miles per second). Since the distance light travels in one year is defined as a light year, we can calculate the distance that light can travel in 13.8 billion years as follows:
Distance = Speed of light × Time
Distance = 299,792 km/s × 13.8 billion years × (365 days/year) × (24 hours/day) × (3600 seconds/hour)
Performing the calculation:
Distance = 299,792 km/s × 13.8 × 10^9 years × 365 days/year × 24 hours/day × 3600 seconds/hour
Distance ≈ 13.07 × 10^9 light years
The calculated distance is approximately 13.07 billion light years. Since the distance of galaxies 60 billion light years away exceeds this value, it means that the light from those galaxies has not had enough time to reach us yet. Therefore, we cannot observe galaxies that are 60 billion light years away from us due to the limited age of the universe.
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the objective lens of the yerkes telescope (the largest functioning refracting telescope in the world) has a focal length of 19.4 m. if its eye piece has a focal length of 2.5 cm, what is the magnitude of the magnification?
To calculate the magnification of the Yerkes Telescope, we can use the following the formula:
Magnification = (-) Focal Length of Objective Lens / Focal Length of Eyepiece
Since the objective lens has a focal length of 19.4 m and the eyepiece has a focal length of 2.5 cm (or 0.025 m), we can plug these values into the formula:
Magnification = (-) 19.4 m / 0.025 m
Magnification = - 776
Therefore, the magnitude of the magnification of the Yerkes Telescope is 776, which means that it can magnify the objects 776 times their original size. Note that the negative sign indicates that the image is inverted.
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a bullet of mass m subscript b is fired horizontally with a speed v subscript i at a wooden block of mass m subscript w resting on a frictionless table. the bullet hits the block and becomes completely embedded in it. after the bullet has come to rest relative to the block, the block with the bullet in it is traveling at speed v subscript f. which quantities, if any, are conserved during this collision?
(A) The collision is fully inelastic based on the provided information, (B) and only momentum is preserved in this situation (C). Following the impact, the bullet system's speed is \(v_{f} = m_{b} v_{i} / m_{b} + m_{w}\)
How does science define speed?Velocity is the pace and orientation of an item's movement, whereas speed is the forecasting that an thing is travelling along a route. In other words, mobility is a vector, whereas frequency is still a scalar number.
What components make up speed?Flexibility, proper form and technique for racing, stride frequency, and stride frequency are these. Reflexes, acceleration, stamina, and horsepower are other factors. We will just pay attention to the first four major elements of speed. Enhancing one's flexibility is essential for accelerating one's speed.
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The complete question is-
A bullet of mass mb is fired horizontally with speed via a wooden block of mass mw resting on a frictionless table. The bullet hits the block and becomes completely embedded within it. After the bullet has come to rest within the block, the block, with the bullet in it, is traveling at speed.vf
A). Which of the following best describes this collision?
B). Which of the following quantities, if any, are conserved during this collision?
Which of the following quantities, if any, are conserved during this collision?
kinetic energy only
momentum only
kinetic energy and momentum
neither momentum nor kinetic energy
C). What is the speed of the block/bullet system after the collision?
Express your answer in terms of vi, mw, and mb.
write a statement that declares a prototype for a function named add which has two int parameters and returns an int.
A prototype for a function named add, which takes two int parameters and returns an int can be declared in the following way:
int add(int num1, int num2); This statement declares a function prototype named "add" that takes two int parameters named "num1" and "num2". The function returns an int value representing the sum of the two parameters. This prototype can be used to define the function later in the program, or it can be used to declare the function for use in other parts of the program before it is defined. By declaring a prototype for the function, the compiler knows the signature of the function, which enables it to correctly call the function and pass the correct number and type of arguments.
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A train decelerates uniformly at a rate of 2 m/s2 and comes to a stop in 10 seconds. Find the initial velocity of the train.
The initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2. It means that initially, at time = 0 seconds, the train was moving with a velocity of 20m/s.
We know that,
v = u +at
where, v = final velocity
u = initial velocity
a = acceleration
t = time taken
In this case, as the train is decelerating we will use a negative sign with acceleration.
Substituting the values we get,
v = u + (-2)(10)
v will be equal to zero, as the train comes to a stop.
0 = u - 20
u = 20 m/s
Hence, the initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2 and comes to a stop in 10 seconds.
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A vector d has a magnitude of2.6 m and points north. What are the magnitudes and directions of the vectors (a) - d, (b) d/2.0, (c) - 2.5d, and (d) 5.0d?
Solution :
A vector is defined as an element that has magnitude of some measure and direction.
It is given there is vector 'd' which has magnitude 2.6 m and its direction is towards north.
a). -d
The magnitude of the vector '-d' is 2.6 m and its direction is reversed, i.e. its direction is towards south.
b). d/2.0
The magnitude of the vector 'd/2.0' is 1.3 m and its direction is towards north.
c). - 2.5d
The magnitude of the vector increases by 2.5 times i.e. 2.5 x 2.6 = 6.5 m and the direction is towards south.
d). 5.0d
The magnitude of the vector increases by 5 times i.e. 5 x 2.6 = 13 m and the direction is towards north.
If I push against a static wall with a Normal force of 25 Newtons, what is the opposing force due to the wall
The opposing force due to the wall when pushing against it with a normal force of 25 Newtons is also 25 Newtons.
When you push against a wall, the wall exerts an equal and opposite force on you according to Newton's third law of motion. This means that the force you apply on the wall (25 Newtons) is countered by an equal and opposite force exerted by the wall on you. Therefore, the opposing force due to the wall is also 25 Newtons.
This opposing force prevents you from moving through the wall because it provides an equal and opposite resistance to the force you exert. It is important to note that the wall exerts this force on you because it is rigid and can resist external forces. If the wall were not rigid, it would not be able to exert an opposing force, and you would be able to pass through it.
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please help me im struggling
Answer:
right
Explanation:
a cart of weight 32 n is accelerated across a horizontal smooth surface at 0.42 m/s2. what net force acts on the cart?
The net force acting on the cart can be calculated using Newton's second law, which states that force is equal to mass multiplied by acceleration.
The mass of the cart is not provided, so we cannot calculate the net force accurately without that information. The net force can be determined by multiplying the mass of the cart (in kilograms) by the acceleration (in meters per second squared). Once the mass is known, the net force can be calculated using the formula:
Net force = mass × acceleration
In this case, we are given the acceleration (0.42 m/s^2) but not the mass of the cart. Without the mass value, it is not possible to calculate the net force accurately.
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How many week are in .62 years?
Answer:
32.32857
Explanation:
Searched on the web
The volume of a piece of metal of a mass 6 gram is 15cm3. What is the density of the metal piece?
Answer:
0.4 g/cm^3
Explanation:
The density of an object can be found using the following formula.
d= m/v
where m is the mass and v is the volume.
The mass of the metal is 6 grams and the volume is 15 centimeters^3
m=6 g
v= 15 cm^3
Substitute these into the formula.
d= 6 g/ 15 cm^3
Divide 6 g by 15 cm^3 (6/15=0.4)
d= 0.4 g/ cm^3
The density of the metal is 0.4 grams per cubic centimeter.
Density = (mass) / (volume)
Density = (6 g) / (15 cm³)
Density = (6/15) (g/cm³)
Density = 0.4 g/cm³
This 'metal' has less than half the density of water, and it floats on water ! It cannot be of Earthly origin, and must have been dropped here by aliens.
Either that, or else the metal has been hammered and stretched and beaten out and shaped so that it has an artificially large volume ... something like the way sailing ships are made out of thick plates of steel.