Answer:
its 9
Step-by-step explanation:
19-1 divided by 2
so 19-1=18
18/2 equals 9
and thats your answer
What value of c makes the equation true? Assume x>0 and y>0 3√x^3/cy^4=x/4y(3√y) c = 12 c = 16 c = 81 c = 64
The value of c that makes the equation true is c = 64, when x = 6 and y = 3.
To find the value of c that makes the equation true, we can start by simplifying both sides of the equation using exponent rules and canceling out common factors.
First, we can simplify 3√(x^3) to x√x, and 3√y to y√y, giving us:
x√x/cy^4 = x/4y(y√y)
Next, we can simplify x/4y to 1/(4√y), giving us:
x√x/cy^4 = 1/(4√y)(y√y)
We can cancel out the common factor of √y on both sides:
x√x/cy^4 = 1/(4)
Multiplying both sides by 4cy^4 gives us:
4x√x = cy^4
Now we can solve for c by isolating it on one side of the equation:
c = 4x√x/y^4
We can substitute in the values of x and y given in the problem statement (x>0 and y>0) and simplify:
c = 4x√x/y^4 = 4(x^(3/2))/y^4
c = 4(27)/81 = 4/3 = 1.33 for x = 3 and y = 3
c = 4(64)/81 = 256/81 = 3.16 for x = 4 and y = 3
c = 4(125)/81 = 500/81 = 6.17 for x = 5 and y = 3
c = 4(216)/81 = 64 for x = 6 and y = 3
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Emarie invested $250. She earned a simple interest of 3% per year on the initial investment. If no money was added or removed from the investment, what was the amount of interest Emarie received at the end of four years? A $30 B $220 C $280 D) $336
Answer:
$30
Step-by-step explanation:
The required simple interest would be the amount of $30.
What is the simple interest?Simple interest is defined as interest paid on the original principal and calculated with the following formula:
S.I. = P × R × T,
Emarie invested $250 and earned a simple interest of 3% per year on the initial investment.
To calculate the interest earned, we can use the formula:
Interest = P × R × T
Where:
Principal P = $250
Rate R = 3% (expressed as a decimal)
Time T = 4 years
So, the interest earned would be:
Interest = $250 x 0.03 x 4 = $30
So the answer is A) $30.
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which of the following basic functions is equivalent to the piecewise-defined function f(x)= x if x≥0 −x if x<0 ? question content area bottom part 1 a. f(x)= 1 x b. f(x)=x c. f(x)=x2 d.
The basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.
The given piecewise-defined function f(x) has different expressions for different intervals. For x greater than or equal to zero, f(x) takes the value of x. For x less than zero, f(x) is equal to -x. We need to find a basic function that captures this behavior.
Among the options provided, f(x) = |x| is equivalent to the given piecewise function. The absolute value function, denoted by |x|, returns the positive value of x regardless of its sign. When x is non-negative, |x| equals x, and when x is negative, |x| is equal to -x, mirroring the conditions of the piecewise-defined function.
The function f(x) = |x| represents the absolute value of x and matches the behavior of the given piecewise-defined function, making it the equivalent basic function.
In summary, the basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.
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In may, seattle's daily high temperature has a mean of f and a standard deviation of f. the formula to convert degrees fahrenheit f to degrees celsius c is:_____.
The answer is : C = (F - 32) * 5/9.
To convert degrees Fahrenheit (F) to degrees Celsius (C), you can use the following formula:
C = (F - 32) * (5/9)
This formula is a commonly used conversion equation in which you subtract 32 from the temperature in Fahrenheit and then multiply the result by 5/9 to obtain the equivalent temperature in Celsius.
Let's break down the formula to understand how it works. Starting with the Fahrenheit temperature (F), subtracting 32 adjusts the temperature relative to the freezing point of water in Fahrenheit (32°F). This step ensures that 0°F in Celsius is equivalent to -17.78°C, which is the freezing point of water in Celsius.
After subtracting 32, we multiply the result by 5/9. This step converts the adjusted Fahrenheit temperature into the equivalent Celsius temperature. The multiplication by 5/9 accounts for the ratio of the size of a degree Fahrenheit to the size of a degree Celsius.
By using this formula, you can convert any temperature from Fahrenheit to Celsius. For example, if the mean daily high temperature in Seattle in May is represented by f, you can substitute that value into the formula to calculate the mean temperature in Celsius.
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Which function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 5 f(x) = –(x – 4)2 5 f(x) = (x – 5)2 4 f(x) = –(x – 5)2 4.
The function f(x) = –(x – 4)² + 5 has a range of {y|y ≤ 5}.
The range of a function represents all the possible output values or y-values that the function can produce. In this case, we are looking for a function whose range is {y|y ≤ 5}.
Among the given options, the function f(x) = –(x – 4)² + 5 satisfies this condition. Let's analyze the function:
The term (x – 4)² represents the squared difference between x and 4. By subtracting this value from 5 and then negating the result with a minus sign, the function ensures that the output value y is less than or equal to 5.
Since the squared term is always non-negative, subtracting it from 5 and negating the result ensures that the maximum value for y is 5. Thus, the range of this function is {y|y ≤ 5}, meaning that all possible y-values produced by the function are less than or equal to 5.
Therefore, the function f(x) = –(x – 4)² + 5 has a range of {y|y ≤ 5}.
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Find an approximate value of m such that the equation cos x = mx has exactly two solutions. (round your answers to four decimal places.)
The answer is , an approx. value of m such that the equation cos(x) = mx has exactly two solutions is m = 1 and m = -0.3183
To find an approximate value of m such that the equation cos(x) = mx has exactly two solutions, we can use the fact that the graph of y = cos(x) intersects the line y = mx at exactly two points.
The graph of y = cos(x) is a periodic function with a maximum value of 1 and a minimum value of -1.
Since we want the line y = mx to intersect the graph of y = cos(x) at exactly two points, the slope m must satisfy the condition -1 ≤ m ≤ 1.
Furthermore, for the line y = mx to intersect the graph of y = cos(x) at exactly two points, the line must pass through the maximum and minimum points of the graph of y = cos(x).
These occur at x = 0 and x = π.
At x = 0, we have cos(0) = 1 and the equation cos(x) = mx becomes 1 = m(0), which simplifies to m = 1.
At x = π, we have cos(π) = -1 and the equation cos(x) = mx becomes -1 = m(π), which simplifies to m = -1/π.
Therefore, an approx. value of m such that the equation cos(x) = mx has exactly two solutions is m ≈ 1 and m ≈ -0.3183 (rounded to four decimal places).
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Brennan studies the relationship shown in the table. Which expression describes a method Brennan could use to determine the y-value when x equals 7?
Answer:
What is the long Division rhyme to help you solve?
What is the long Division rhyme to help you solve?
Step-by-step explanation:
Worth 10 points people!!
Answer:
5b - 0.9b is the equivalent expression and the distributive property is used.
Step-by-step explanation:
The price of bread is marked down 18%. She purchases 5 loaves of bread. We need to rewrite the above expression.
The expression that is used to find the price of 5 loaves of bread is 5(b-0.18b).
We can use the distributive property to solve it as follows:
a(b+c) = ab + ac
Here, a = 5, b = b and c = -0.18b
5(b-0.18b) = 5(b) + 5(-0.18b)
= 5b - 0.9b
So, the equivalent expression is 5b - 0.9b. The distributive property was used to rewrite the expression.
Bell Work
You Do
Camspite A is 5 miles north and 2 miles east of a ranger station.
Campsite B is 8 miles north and 6 miles east of the ranger station.
How far is Campsite A from Campsite B?
A 1 mi
B 5 mi
7 mi
25 mi
7 i do not feel like explaining tbh
Can someone please explain this question to me?
The image is attached.
Answer:
13
Step-by-step explanation:
Given the expression;
2 1/3 : 4 1/3 = 7 : x
Wea re to look for x;
Convert to improper fractions;
7/3 : 13/3 = 7:x
7/3 * 3/13 = 7/x
7/13 = 7/x
Cross multiply
7x = 13 * 7
7x = 91
x = 91/7
x = 13
Hence the unknown value is 13
Use an inverse matrix to solve each question or system.
[-6 0 7 1]
[-12 -6 17 9]
The inverse of the given matrix is: A^-1 = [ 3/2 -7/4][ 1/2 -3/4][ -1 1][1/2]
Given matrix is: A = [-6 0 7 1][ -12 -6 17 9]
To find inverse matrix, we use Gauss-Jordan elimination method as follows:We append an identity matrix of same order to matrix A, perform row operations until the left side of matrix reduces to an identity matrix, then the right side will be our inverse matrix.So, [A | I] = [-6 0 7 1 | 1 0 0 0][ -12 -6 17 9 | 0 1 0 0]
Performing the following row operations, we get,
[A | I] = [1 0 0 0 | 3/2 -7/4][0 1 0 0 | 1/2 -3/4][0 0 1 0 |-1 1][0 0 0 1 |1/2]
So, the inverse of the given matrix is: A^-1 = [ 3/2 -7/4][ 1/2 -3/4][ -1 1][1/2]
Multiplying A^-1 with A, we should get an identity matrix, i.e.,A * A^-1 = [ 1 0][ 0 1]
Therefore, the solution of the system of equations is obtained by multiplying the inverse matrix by the matrix containing the constants of the system.
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Find the
slope of the line that passes through the points (2, 0) and (2, 4).
Answer:
The slope is undefined.
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-0)/(2-2)
m=4/0
undefined
If it costs $300 to tile a 420 square foot room, how much will it cost to tile a
room with 1,050 square feet?
Answer:
750$
Step-by-step explanation:
\(Amount= 300*\frac{1050}{420} =750\)
It will cost approximately $750.01 to tile a room with an area of 1,050 square feet.
To find out how much it will cost to tile a room with 1,050 square feet, we can set up a proportion using the given information.
Cost₁: The cost to tile the first room with an area of 420 square feet, which is $300.
Area₁: The area of the first room, which is 420 square feet.
Cost₂: The cost to tile the second room with an unknown area, which we want to find.
Area₂: The area of the second room, which is 1,050 square feet.
We can set up the proportion:
Cost₁ / Area₁ = Cost₂ / Area₂
Substituting the known values:
$300 / 420 sq ft = Cost₂ / 1,050 sq ft
Now we can solve for Cost₂:
Cost₂ = ($300 / 420 sq ft) * 1,050 sq ft
Calculating:
Cost₂ = $0.7143 * 1,050 sq ft
Cost₂ ≈ $750.01
Therefore, it will cost approximately $750.01 to tile a room with an area of 1,050 square feet.
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Plss can someone help me out with thissss!!!!!!!!!!!
Jane, kevin, and hans have a total of in their wallets. kevin has less than jane. hans has times what jane has. how much does each have?
Based on the given conditions, Jane has $31, Kevin has $25, and Hans has $50 in their wallets.
Let's solve the problem step by step.
First, let's assume that Jane has X dollars in her wallet. Since Kevin has $6 less than Jane, Kevin would have X - $6 dollars in his wallet.
Next, we're given that Hans has 2 times what Kevin has. So, Hans would have 2 * (X - $6) dollars in his wallet.
According to the information given, the total amount of money they have in their wallets is $106. We can write this as an equation:
X + (X - $6) + 2 * (X - $6) = $106
Simplifying the equation:
4X - $18 = $106
4X = $124
X = $31
Now we know that Jane has $31 in her wallet.
Substituting this value into the previous calculations, we find that Kevin has $31 - $6 = $25 and Hans has 2 * ($25) = $50.
To find the total amount they have, we sum up their individual amounts:
Jane: $31
Kevin: $25
Hans: $50
Adding these amounts together, we get $31 + $25 + $50 = $106, which matches the total amount stated in the problem.
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The complete question is:
Jane, kevin and hans have a total of $106 in their wallets. kevin has $6 less than Jane. hans has 2 times what kevin has. how much do they have in their wallets?
Find the length of ac , if ar=3x-12 and db=8x - 40
The length of AC is represented by -5x + 28. Distribute the negative sign to the terms within the parentheses AC = 3x - 12 - 8x + 40.
To find the length of AC, we need to determine the value of AC by subtracting the lengths of the segments AR and DB.
Given that AR = 3x - 12 and DB = 8x - 40, we can calculate AC as follows:
AC = AR - DB
AC = (3x - 12) - (8x - 40)
To simplify, distribute the negative sign to the terms within the parentheses:
AC = 3x - 12 - 8x + 40
Combine like terms:
AC = (3x - 8x) + (-12 + 40)
AC = -5x + 28
Therefore, the length of AC is represented by -5x + 28.
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What is 3.457 rounded to the nearest tenth
Hilbert axioms changed Euclids geometry by
Hilbert axioms changed Euclid's theorem by identifying and explaining the concept of undefined terms
What was Hilbert's Axiom?These were the sets of axioms that were proposed by the man David Hilbert in the 1899. They are a set of 20 assumptions that he made. He made these assumptions as a treatment to the geometry of Euclid.
These helped to create a form of formalistic foundation in the field of mathematics. They are regarded as his axiom of completeness.
Hilbert’s axioms are divided into 5 distinct groups. He named the first two of his axioms to be the axioms of incidence and the axioms of completeness. His third axiom is what he called the axiom of congruence for line segments. The forth and the fifth are the axioms of congruence for angles respectively.
Hence we can conclude by saying that Hilbert axioms changed Euclid's theorem by identifying and explaining the concept of undefined terms.
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complete question
Hilbert’s axiom’s changed Euclid’s geometry by _____.
1 disproving Euclid’s postulates
2 utilizing 3-dimensional geometry instead of 2-dimensional geometry
3 describing the relationships of shapes
4 identifying and explaining the concept of undefined terms
Let n ≥ 3 . Use strong induction on n to prove that every n -vertex simple graph with at least n edges contains a cycle.
Every graph with at least n edges and n ≥ 3 contains a cycle, proven by strong induction on the number of vertices.
We will proceed with a proof by strong induction.
Base case: For n = 3, the graph must have at least 3 edges to satisfy the condition. In this case, the graph forms a triangle, which is a cycle.
Inductive step: Assume that the statement holds for all values up to some k ≥ 3, where k is an arbitrary positive integer. We want to prove that the statement holds for k + 1 as well.
Consider an (k + 1)-vertex graph G with at least k + 1 edges. Remove any edge from G, resulting in a graph G' with k edges. By the induction hypothesis, G' contains a cycle.
If the removed edge connects two vertices within the cycle, then adding it back creates a cycle in G.
If the removed edge connects a vertex outside the cycle to a vertex within the cycle, then the resulting path combined with the cycle forms a larger cycle in G.
In both cases, we have shown that G contains a cycle. Therefore, by strong induction, every n-vertex simple graph with at least n edges contains a cycle.
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yeah, uhm can someone help me with this?
Answer:
-24
Step-by-step explanation:
\(x/4 + 8 = 2\\x/4 = 2 - 8\\x/4 = -6\\x = -6 *4\\x = -24\)
a sample correlation r = .40 indicates a stronger linear relationship than r = -.60.
The magnitude of the correlation coefficient, regardless of the sign, provides information about the strength of the linear relationship between variables.
The sample correlation coefficient, r, ranges between -1 and 1. A value of 1 or -1 indicates a perfect linear relationship, where all data points lie precisely on a straight line. On the other hand, a value close to 0 indicates a weak or no linear relationship.
In the given scenario, r = .40 indicates a moderate positive linear relationship. Although the correlation is not perfect (not equal to 1), it still suggests a moderate degree of association between the variables. The positive sign indicates that as one variable increases, the other tends to increase as well, but not necessarily in a strictly linear fashion.
On the other hand, r = -.60 indicates a stronger linear relationship, albeit in the negative direction. The negative sign signifies an inverse relationship, meaning that as one variable increases, the other tends to decrease, but again, not necessarily in a perfectly linear manner. The magnitude, which is the absolute value of the correlation coefficient, indicates a stronger relationship compared to r = .40.
Therefore, it is important to consider both the magnitude and the sign of the correlation coefficient to assess the strength and direction of the linear relationship between variables.
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a normal distribution has a mean of 50, and a standard deviation of 3. what is the probability of a score above 56?
The probability of a score above 56 is 0.025.
Define probability.The probability of an event occurring is defined by probability. Probability is the unit of measurement for an event's likelihood. It is the proportion of successful outcomes to all possible outcomes. For instance: (1) Throwing a die and getting the numbers 3 and 5 (2) Throwing a die and getting both an even and an odd number
Given,
A normal distribution has a mean of 50, and a standard deviation of 3.
P( x > 56)
= P(X - mean/standard deviation > 56-50/3)
= P(Z > 6/3)
= P( Z > 2)
= 1 - P(Z<2)
= 1 - 0.9772
= 0.0228
0.025 (Approximately)
The probability of a score above 56 is 0.025.
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8x + y + 4x + 2y
The answer to simplifying the above expression is
blank one:
Blank two:
ANSWER ASAP
Answer:
12x + 3y
Step-by-step explanation:
Not sure what the blanks are, but here is what I did
8x + y + 4x + 2y
(combine like terms)
8x + 4x + 3y
(combine like terms)
12x + 3y
whats the perimeter and area?
Answer:
Step-by-step explanation:
Perimeter = 3 + 1 + 1 + 1 + 2 + 2 = 10 cm
Area = area of rectangle 1 and area of rectangle 2
Rectangle 1:
length = 3; width = 1
Area = 3*1 = 3 cm²
Rectangle 2:
length = 2 cm ; width = 1 cm
Area = 2*1 = 2 cm²
Area = 2+ 3 = 5 cm²
Show that the given functions are orthogonal on the indicated interval f1(x) e, f2(x) sin(x); T/4, 5n/4] 5п/4 5T/4 f(x)f2(x) dx T/4 (give integrand in terms of x) dx TT/4 5T/4 T/4 Need Help? Read It Watch It Talk to a Tutor II
The inner product interval of f1(x) = e^(x) and f2(x) = sin(x) is not equal to zero. So the given functions are not orthogonal on the indicated interval [T/4, 5T/4].
To show that the functions f1(x) = e^(x) and f2(x) = sin(x) are orthogonal on the interval [T/4, 5T/4], we need to show that their inner product over that interval is equal to zero.
The inner product of two functions f(x) and g(x) over an interval [a,b] is defined as:
⟨f,g⟩ = ∫[a,b] f(x)g(x) dx
So, we need to evaluate the integral:
⟨f1,f2⟩ = ∫[T/4, 5T/4] e^(x)sin(x) dx
Using integration by parts with u = e^(x) and dv/dx = sin(x), we get:
⟨f1,f2⟩ = e^(x)(-cos(x))∣[T/4, 5T/4] - ∫[T/4, 5T/4] e^(x)cos(x) dx
Evaluating the first term using the limits of integration, we get:
e^(5T/4)(-cos(5T/4)) - e^(T/4)(-cos(T/4))
Since cos(5π/4) = cos(π/4) = -sqrt(2)/2, this simplifies to:
-e^(5T/4)(sqrt(2)/2) + e^(T/4)(sqrt(2)/2)
To evaluate the second integral, we use integration by parts again with u = e^(x) and dv/dx = cos(x), giving:
⟨f1,f2⟩ = e^(x)(-cos(x))∣[T/4, 5T/4] + e^(x)sin(x)∣[T/4, 5T/4] - ∫[T/4, 5T/4] e^(x)sin(x) dx
Substituting in the limits of integration and simplifying, we get:
⟨f1,f2⟩ = -e^(5T/4)(sqrt(2)/2) + e^(T/4)(sqrt(2)/2) + (e^(5T/4) - e^(T/4))
Now, we can see that the first two terms cancel out, leaving only:
⟨f1,f2⟩ = e^(5T/4) - e^(T/4)
Since this is not equal to zero, we can conclude that f1(x) = e^(x) and f2(x) = sin(x) are not orthogonal over the interval [T/4, 5T/4].
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Surface area of triangular prisms 7th grade math
The surface area of a triangular prism can be found by adding the areas of all the faces. To do this, we need to identify the faces of the triangular prism.
A triangular prism has three rectangular faces and two triangular faces. The rectangular faces are identical and have a length and width equal to the base and height of the triangle. The two triangular faces have the same base as the rectangular faces but have a height equal to the height of the triangular prism.
To find the surface area, we can use the formula:
Surface area = (2 × area of the base) + (perimeter of the base × height)
Where the area of the base is equal to the area of the triangle, which can be found using the formula:
Area of a triangle = (base × height) ÷ 2
Therefore, the formula for the surface area of a triangular prism is:
Surface area = 2 × [(base × height) ÷ 2] + (perimeter of the base × height)
Simplifying this equation, we get:
Surface area = base × height + (perimeter of the base × height)
So, to find the surface area of a triangular prism, we need to know the base and height of the triangle and the height of the prism. We also need to find the perimeter of the base, which can be found by adding up the lengths of all the sides of the triangle.
Once we have these measurements, we can plug them into the formula and calculate the surface area of the triangular prism.
The equation of the line tangent to the differentiable and invertible function f(x) at the point (-1,3) is given by y = –2x + 1. Find the equation of the tangent line to f-1(x) at the point (3, -1).
The equation of the tangent line to f-1(x) at the point (3, -1) is y = 1/(-2) x - 1/2.
This is because the slope of the tangent line to f(x) at (-1,3) is -2, and since f(x) and f-1(x) are inverse functions, the slopes of their tangent lines are reciprocals.
Therefore, the slope of the tangent line to f-1(x) at (3,-1) is -1/2. To find the y-intercept, we can use the fact that the point (3,-1) is on the tangent line. Plugging in x=3 and y=-1 into the equation y = -1/2 x + b, we get b = 1/2. Therefore, the equation of the tangent line to f-1(x) at (3,-1) is y = 1/(-2) x - 1/2.
In summary, to find the equation of the tangent line to f-1(x) at a point (a,b), we first find the point (c,d) on the graph of f(x) that corresponds to (a,b) under the inverse function.
Then, we find the slope of the tangent line to f(x) at (c,d), take the reciprocal, and plug it into the point-slope formula to find the equation of the tangent line to f-1(x) at (a,b).
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Which function increases the fastest?
A statistical analysis of 1,000 long-distance telephone calls made by a company indicates that the length of these calls is normally distributed, with a mean of 290 seconds and a standard deviation of 30 seconds. Complete parts (a) through (c).
a. What is the probability that a call lasted less than 230 seconds?
The probability that a call lasted less than
23 seconds is ?
(Round to four decimal places as needed.)
b. What is the probability that a call lasted between 230 and 330 seconds?
The probability that a call lasted between
230 and 330 seconds is
(Round to four decimal places as needed.)
c. What is the probability that a call lasted more than 330 seconds?
The probability that a call lasted more than
330 seconds is
(Round to four decimal places as needed.)
To find the probability of the call lasting less than 230 seconds, we have to find P(X<230). Here X follows normal distribution with mean = 290
The given data: Meanμ = 290 seconds
Standard deviation σ = 30 seconds
Sample size n = 1000a) and
standard deviation = 30.
We get the value of 0.0228, which represents the area left (or below) to z = -2. Therefore, the probability that the call lasted less than 230 seconds is 0.0228 (or 2.28%). By using z-score formula;
Z=(X-μ)/σ
Z=(230-290)/30
= -2P(X<230) is equivalent to P(Z < -2) From z-table,
0.6384 (or 63.84%) P(230330) is equivalent to 1 - P(X<330)Here X follows normal distribution with mean = 290 and standard deviation = 30.From part b,
We already have P(X<330).Therefore, P(X>330) = 1 - 0.9082 = 0.0918, which is equal to 9.18%. Therefore, the probability that the call lasted more than 330 seconds is 0.1356 (or 13.56%).Answer: 0.1356 (or 13.56%). In parts a, b, and c, the final probabilities are rounded off to four decimal places as needed, as per the instructions given. However, these values are derived from the exact probabilities and can be considered accurate up to that point.
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Point D is the in center of triangle ABC. Write an expression for the length x in terms of the three side lengths AB,
AC, BC
Answer:
\(x = \frac{2(A_T) }{(AB) + (AC) + (BC)} \)