The number of students who studied for less than 2 hours is 689.
What is the percentage?The Percentage is defined as representing any number with respect to the 100. It is denoted by the sign %.
From the table, we can see that
The percentage of the students who studied less than two hours:-
Less than one hour = 0.5%
One hour = 3%
1.5 hour = 38%
The number of the students will be:-
Less than one hour = 1942 X 0.5% = 1942 x (0.5 / 1000 = 10
One hour = 3% = 1954 x ( 3 / 100 ) = 58
1.5 hour = 38% = 1942 x ( 38 / 100) = 621
The total number of the students who studied for less than 2 hours will be
= 10 + 58 + 621
= 659
Therefore the number of students who studied for less than 2 hours is 689.
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Levi bought o oranges at the store. Each orange cost $0.29. Write an algebraic expression to represent how much Levi spent.
Answer:
0.29x
Step-by-step explanation:
let x be the number of oranges Levi bought
Which of the following inequality should be graphed with a dashed line? Select all that apply.
(I think B is one of the correct answers?)
Answer:
B, D
Step-by-step explanation:
Any inequality that does not include the "or equal to" case will be graphed with a dashed line.
ApplicationThe "or equal to" case is included when the inequality symbol is one of ≤ or ≥. When symbols > or < are used, the boundary line of the solution space is dashed (or the end point on the number line is an open circle).
The inequalities that will be graphed with a dashed line are ...
2x -4y < 12 . . . . choice Bx +7 > -1 . . . . . . .choice DA car accelerates from a resting position to 100 mi/hr in 7 seconds. What is the acceleration?
Can you identify what the polynomial is?
Answer:
are you sure its a polynomial
Step-by-step explanation:
A polynomial is a combination of terms separated by
+
or
−
signs. A polynomial does not contain variables raised to negative or fractional exponents, variables in the denominator or under a radical, or any special features such as trigonometric functions, or logarithms.
Polynomial
What is the Difference Between Adding and Subtracting Polynomials?
Answer: Adding and subtracting polynomials are both arithmetic operations used in algebra. The main difference between the two operations is the sign of the terms being combined.
Adding polynomials involves combining like terms by adding their coefficients. When adding polynomials, the terms being added have the same sign. For example, when adding the polynomials x^2 + 2x + 1 and 3x^2 + 4x + 2, we combine the like terms (x^2 terms, x terms, and constant terms) by adding their coefficients:
(x^2 + 2x + 1) + (3x^2 + 4x + 2) = 4x^2 + 6x + 3
Subtracting polynomials involves subtracting one polynomial from another by changing the sign of each term in the polynomial being subtracted and then adding the resulting polynomials. When subtracting polynomials, the terms being subtracted have opposite signs. For example, when subtracting the polynomial 3x^2 + 4x + 2 from the polynomial x^2 + 2x + 1, we first change the sign of each term in the polynomial being subtracted:
(x^2 + 2x + 1) - (3x^2 + 4x + 2) = x^2 + 2x + 1 - 3x^2 - 4x - 2
Then, we combine the like terms by adding their coefficients:
x^2 - x - 1
In summary, the main difference between adding and subtracting polynomials is that adding involves combining like terms with the same sign, while subtracting involves changing the sign of one polynomial and then adding the resulting polynomials.
Step-by-step explanation:
which of the following statements about mathematics teaching in elementary schools is true?
Mathematics is a fundamental subject in education that is essential in the development of an individual’s critical thinking and problem-solving skills. It is one of the primary subjects that are taught in elementary schools and must be taught appropriately for children to understand and gain the required skills. One true statement about mathematics teaching in elementary schools is that it should be student-centered.
Teachers should focus on the child's understanding, individual learning abilities and styles, and progress.The learning experience should not be centered on the teacher but on the students. Teachers should also make the subject engaging and interactive to enable students to grasp the content easily and maintain their interest in the subject. Besides, teachers should develop a personalized learning approach that allows students to learn and understand the subject at their own pace while creating opportunities for individual and group learning. Through such learning approaches, students can develop the required mathematical concepts and competencies such as critical thinking, problem-solving, and decision-making skills that will be beneficial in their future endeavors.
In elementary schools, mathematics teaching should be student-centered. It should be engaging and interactive to enable students to grasp the content easily and maintain their interest in the subject.
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A. y= -4/5x+ 5/4
B. y= -4/5x+ 3/2
C. y= -5/4x+ 3/2
D. y= -5/4x+ 5/4
what are all the units to algebra 1 ?
Answer:
Your question doesn’t make sense homie
Step-by-step explanation:
given that s(x)=−1x 8 9x−4, what is the antiderivative of s(x)? (do not include the constant c in your answer.)
Answer:
The antiderivative of s(x) without the constant of integration is:
-1/9 * x^9 - 3x^-3
Each flag is in the shape of an isosceles triangle. To give the fabric support, a ribbon needs to be sewn around the outside edges of the flag. The base of each triangle is 1.25 feet. Eleonore has ordered 500 feet of ribbon and is hoping to make at least 75 flags. What is the maximum length possible for each leg of the triangles? (Round your answer to the nearest tenth)
The maximum length possible for each leg is
feet.
Answer:
no its 2.7
Step-by-step explanation:
i just took the test its 2.7 duh !
The length of each leg can be found from an expression and an equation that gives the length of ribbon Eleonore has.
The maximum length possible for each leg is approximately 2.7 feet.
Reasons:
The shape of the flag = Isosceles triangle
Length of the base of each triangle = 1.25 feet
Length of ribbon available = 500 feet
Number of flags to make = 75 flags
Required:
Maximum possible length for each leg of the triangle
Solution:
Let L represent the length of each leg, we have;
The expression for the perimeter of one flag = 2·L + 1.25
For the 75 flags, the equation is as follows;
75 × (2·L + 1.25) = 500
Which gives;
\(\displaystyle 2 \cdot L + 1.25 = \mathbf{\frac{500}{75}} = \frac{20}{3}\)
\(\displaystyle L = \frac{\frac{20}{3} - 1.25}{2} = \frac{65}{24} \approx \mathbf{2.708\overline 3}\)
The maximum possible length for each leg, by rounding to the nearest tenth, is L ≈ 2.7 feet
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A hotdog coats $2.50 more than a soda. Together they cost $6.50.
Answer:
Step-by-step explanation:
The hotdog costs $4.50
The soda costs $2.00
Question 6 A box contains 7 green marbles and 6 white marbles. If you pick one marble out of the box, what is the probability of choosing a white marble? Express your answer as a decimal number roundeR
The probability of choosing a white marble from the box can be determined by dividing the number of white marbles by the total number of marbles.
In this case, the box contains 7 green marbles and 6 white marbles, so the total number of marbles is 13.
To find the probability, we divide the number of white marbles (6) by the total number of marbles (13):
Probability of choosing a white marble = 6 / 13
To express this as a decimal number, we divide 6 by 13:
Probability of choosing a white marble ≈ 0.4615 (rounded to 4 decimal places)
The probability of choosing a white marble from the box is approximately 0.4615.
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4x^2 = − 9x − 4 quadratic
Answer:
Yes, see the explanation.
Roots:
x = \(\frac{63}{8}\), or x= -10
Step-by-step explanation:
A quadratic fomrual in standard form is;
ax^(2) + bx + c = 0
The given equation:
4x^2 = -9x - 4
Maniplate the equation using inverse operations
4x^2 = -9x - 4
-4x^2 -4x^2
0 = -4x^2 - 9x - 4
Yes, this is a quadratic equation, because it fits the requirement of being able to be written in standard form.
Now find its roots:
-4x^2 -9x - 4 = 0
remember,
x = \(\frac{(-b) +- (\sqrt{b^{2} - 4ac }) }{2a}\)
Substitute in the given values
x= \(\frac{(-(-9)) +- (\sqrt{(-9)^{2} - 4(-4)(-4)}) }{2(-4)}\)
Simplify,
x = \(\frac{9 +- (\sqrt{5184}) }{-8}\)
x = \(\frac{9 +- 72}{-8}\)
x = \(\frac{63}{8}\)
or
x= -10
Find the Principal unit normal for r(t) = sintit cost; + tk Evaluate it at t = Tyz Sketch the situation
We can plot the vector r(t) and the vector N(T) at the given value of t = T.
To find the principal unit normal for the vector-valued function r(t) = sin(t)i + tcos(t)j + tk, we need to compute the derivative of r(t) with respect to t and then normalize it to obtain a unit vector.
First, let's find the derivative of r(t):
r'(t) = cos(t)i + (cos(t) - tsin(t))j + k
Next, we'll normalize the vector r'(t) to obtain the unit vector:
||r'(t)|| = sqrt((cos(t))^2 + (cos(t) - tsin(t))^2 + 1^2)
Now, we can find the principal unit normal vector by dividing r'(t) by its magnitude:
N(t) = r'(t) / ||r'(t)||
Let's evaluate the principal unit normal at t = T:
N(T) = (cos(T)i + (cos(T) - Tsin(T))j + k) / ||r'(T)||
To sketch the situation, we can plot the vector r(t) and the vector N(T) at the given value of t = T.
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Emma pays $2,600 for a washer/dryer combo. Each year, the appliance loses 15% of its resale value. How much will it be worth in 4 years?
If necessary, round your answer to the nearest cent.
The value for the washer/dryer combo after 4 years is 1,357.2 dollars.
How much will it be worth in 4 years?We know that Emma pays $2,600 for a washer/dryer combo. Each year, the appliance loses 15% of its resale value, then the value after x years is modeled by the exponential decay.
V(x) = 2,600*(1 - 0.15)ˣ
The value after 4 years is what we get when we evaluate this in x = 4, we will get:
V(4) = 2,600*(1 - 0.15)⁴
Simplify that:
V(4) = 1,357.2
The value is after 4 years of the washer/dryer is 1,357.2 dollars.
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Please Please help ME! i need help !
Triangle ABD is congruent to triangle BCD
What are congruent triangles?Congruent triangles are triangles with thesame corresponding sides and also with thesame corresponding angles.
To show that triangle ABD is congruent to triangle BCD
It has been shown that line AD is equal to line DC
i.e AD = DC
angle BMA = BMC = 90°
Therefore AB = BC
And line BD is common to both triangles
Therefore ;
AB = BC
AD = DC
Therefore we can say that triangles ABD is congruent to triangle BCD.
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which statement gives a unit rate? a. for every cup, trey's cat ate for 0.75 of a day. b. for every day, trey's cat ate 1.5 cups. c. for every cup, trey's cat ate for 1.5 days. d. for every day, trey's cat ate 0.75 of a cup.
The statement that gives a unit rate is "for every day, Trey's cat ate 1.5 cups". So correct answer is option B).
This statement represents the amount of cat food consumed per unit of time, which is 1.5 cups per day. A unit rate is a comparison of two measurements in which one of the numbers is 1, making it easier to compare different rates. So, the correct option is B).
In this case, the unit rate would be 1.5 cups per day. Option A and C are not unit rates because they express the amount of cat food consumed over a varying number of days, while option D is not a unit rate because it expresses the amount of cat food consumed in a fractional amount of a day.
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Help is much needed. You will get lots of point too!
A firm breaks even if the average cost is equal to the price it charges. Suppose the price is $38. If C=11Q+9Q
2
is the firm's cost function, then how many units must the firm sell in order to break even?
The firm must sell 2 units in order to break even.
To determine the break-even point, we need to find the quantity at which the average cost is equal to the price. The average cost is calculated by dividing the total cost (C) by the quantity (Q). In this case, the cost function is given as C = 11Q + 9Q^2.
To find the average cost, we divide the cost function by the quantity: AC = (11Q + 9Q^2) / Q.
Simplifying the expression, we have AC = 11 + 9Q.
Since the average cost is equal to the price, we set AC equal to the given price of $38: 11 + 9Q = 38.
Subtracting 11 from both sides, we have 9Q = 27.
Dividing by 9, we find Q = 3.
Therefore, the firm must sell 3 units in order to break even.
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The following group of values was entered into the TVM solver on a graphing calculator
N=108; I%= 6.6 PV =; PMT=-620 FV =0; P/Y = 12; C/Y=12; PMT:END which of theses expressions with return the same value for PV
Based on the entries into the TVM solver, the expression that will return the same value for PV is \(\frac{(620) (( 1 + 0.066)^{108} - 1) }{(0.066) (1 + (0.066))^{108}}\).
Which formula will give the same Present Value?The formula for present value for this series of cashflows is:
= \(\frac{(Payment) (( 1 + Interest rate)^{Number of years} - 1) }{(Periodic interest) (1 + (Periodic interest))^{Number of years}}\)
Based on the P/Y and the C/Y being 12, the number of periods given in the graphing calculator will be the same in the formula, which is 108 periods.
The interest rate of 6.6% will also be the same in the formula.
The best option is therefore option B which has all these figures and so will give the same present value.
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Answer: 0.0055 and 108
aka ($620) ((1+0.0055)^108 -1 / (0.0055) (1+0.0055)^108
Step-by-step explanation: Just did it, Good luck! :)
Please help me with this homework
Answer:
Step-by-step explanation:
the 0-1 point is divided into 6 sections. you have to click three of the sections in the 6 sections.
Answer:
Click to the point that says 1
Step-by-step explanation:
3/6 is equivalent to 1/2. Half of the map is 1 because the whole map is 2.
Hope this Helps! Pls, let me know if my answer is incorrect or correct!
Have a nice day!
-kiniwih426
. Assume that the annual percentage rate increases by 5%, 10%, 20%, 40%, and 60%. [30 marks] a. Calculate the approximate doubling time (Dappx) b. Calculate the exact doubling time (Dexact) c. Calculate the percentage error in calculating the doubling time for each case.
a) Approximate Doubling Time Dappx = 70/r, where r is the annual interest rate in percentage terms.Assuming that r = 5%, 10%, 20%, 40%, and 60%Doubling time for 5% = 70/5 = 14 yearsDoubling time for 10% = 70/10 = 7 yearsDoubling time for 20% = 70/20 = 3.5 yearsDoubling time for 40% = 70/40 = 1.75 yearsDoubling time for 60% = 70/60 = 1.1667 yearsb) Exact Doubling Time Dexact = ln2/r where r is the annual interest rate in decimal terms.
Assuming that r = 5%, 10%, 20%, 40%, and 60%For 5%: ln2/0.05 ≈ 13.86 yearsFor 10%: ln2/0.1 ≈ 6.93 yearsFor 20%: ln2/0.2 ≈ 3.47 yearsFor 40%: ln2/0.4 ≈ 1.73 yearsFor 60%: ln2/0.6 ≈ 1.16 yearsc)
The percentage error is given by:(Dexact − Dappx)/Dexact × 100%For 5%: (13.86 - 14)/13.86 x 100% ≈ 1.18%For 10%: (6.93 - 7)/6.93 x 100%
≈ 1.15%For 20%: (3.47 - 3.5)/3.47 x 100%
≈ -0.86%For 40%: (1.73 - 1.75)/1.73 x 100%
≈ -1.15%For 60%: (1.16 - 1.1667)/1.16 x 100%
≈ -0.60%Note that the percentage error is small for lower values of interest rates but increases as the interest rate increases.
Also, the percentage error is negative for 20%, 40%, and 60%, which means that the approximate doubling time is actually larger than the exact doubling time.
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PLEASE HELP ME ANSWER ASAP
L = k/f, where k is the variational constant, is the formula for the inverse variation.
Inverse proportionsA mathematical relationship between two variables in which they vary in opposing directions is referred to as an inverse proportion, also known as an inverse relationship. When one variable increases while the other decreases, this is known as having inverse proportions.
Using the variables length of violin 'l' and frequency of vibration 'f'
If the length of violin 'l' is inversely proportional to the frequency of vibration 'f', this is expressed as:
l α 1/f
l = k/f
Hence the formula for the inverse variation is l = k/f where k is the constant of variation.
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Select the correct answer from each drop-down menu. triangle abc is represented. points d and f are marked on side ab and points e and g are marked on side ac. segments de and fg are drawn. if , then line segment is parallel to line segment .
If points d and f are on side ab and points e and g are on side ac then line segments de and fg are parallel
What are parallel lines?
Parallel lines are those lines that do not meet at any point. If we draw a triangle ABC and plot points d and f are marked on side ab and points e and g are marked on side ac then the line segment fg is parallel to de because both the line segments are drawn from the points which are on the sides opposite to each other. We have assumed a simple triangle because no description is given for the triangle
Hence the line segment fg is parallel to de if drawn points d and f marked on ab and points e and g are marked on ac.
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Help me solve this image please!!!
Based on the information, Christian would have $5525.5 of an annuity.
How to calculate the annuity?According to the given information, the number of coffees per week is 3 then, per month is 3x4 = 12
Each coffee is $4.5. Then monthly expenditure for coffees is 12 x 4.5 = $54
Rate of interest r = 1.6% = 1.6/100 = 0.016 and for monthly compounding r = 0.016/12 = 0.00133
n = number of payments = 8 x 12 = 96
We can use the formula for finding the future value as below
FV = C x [ ( 1 + r )n-1 ] / ( r )
FV = 54 x [ ( 1 + 0.00133 )96 – 1 ] / (0.00133)
= 54 x [ (1.13609 - 1)] / (0.00133)
= 54 x 0.13609 / (0.00133)
= 54 x 102.3233
= 5525.5
Therefore Christian would have $5525.5 of the annuity.
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A city planner wants to build a road perpendicular to D Street. What should be the slope of the new road?
The slope of the new road is zero.
What is Slope?A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the change in y coordinate with respect to the change in x coordinate as,
m = Δy/Δx where, m is the slope
Given:
Take points from the Graph (5, 0) and (5, 4).
Slope of a line = m = tanθ
where θ is the angle made by the line with the x−axis.
For a line parallel to y−axis ,θ= π/2.
∴m = tan π/2 = undefined
The new road will therefore have 0° of inclination if it is perpendicular to D street because if they are perpendicular and D street is vertical, the new road is level and has 0° of inclination.
An horizontal line now has zero slope.
The new road has a zero slope as a result.
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SQL (no data required)
Show a list of product names and unit prices ranked by unit
price into three categories based on price: 1, 2, 3. The
highest-priced products will be marked with a 1, the second
To generate a list of product names and unit prices ranked by unit price into three categories (1, 2, 3) based on price, you can use a SQL query with the RANK() function.
The highest-priced products will be marked with a 1, the second-highest-priced products with a 2, and so on.
In SQL, you can use the RANK() function along with the ORDER BY clause to rank the products based on their unit prices. The RANK() function assigns a rank to each row in the result set based on the specified ordering criteria. Here's an example SQL query to achieve this:
In this query, products is the name of the table containing the product information. We select the product_name and unit_price columns from the table. The RANK() OVER (ORDER BY unit_price DESC) part ranks the rows based on the unit_price column in descending order, with the highest prices receiving a rank of 1.
The result of this query will include the product names, unit prices, and the assigned price ranks. You can then filter the results based on the price ranks to categorize the products into three categories (1, 2, 3) based on their price rankings.
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Martin drew a scale drawing of an arcade. The scale he used was 1 inch : 3 feet. If the actual length of an air hockey table is 9 feet, how long is the air hockey table in the drawing?
Answer: 3 inches
Step-by-step explanation: 9 divided by 3 is 3
-3m=-9
use inverse operations to solve
Answer: +3
Step-by-step explanation: divide by -3 which you get is +3
and you can check by doing +3 times -3= -9
Consider a sequence of payments made annually in advance over a period of ten years. Suppose that each of the payments in the first year is of amount M100, each of the payments in the second year is of amount M200, each of the payments in the third year is of amount M300 and so on until the tenth year in which each monthly payment is amount M1,000. Calculate the present value of these payments assuming an interest rate of 8% pa effective.
A sequence of payments is made annually in advance over a period of ten years, such that the payments made in the first year are of amount M100, payments made in the second year are of amount M200, payments made in the third year are of amount M300, and so on until the tenth year in which each payment is of amount M1,000.
The present value of these payments can be calculated as follows:
Let P be the present value of the payments made over 10 years. Then, according to the compound interest formula, the present value of each payment made in the first year can be given by:
PV of M100
\(= M100/(1 + 0.08)¹\)
\(= M92.59\)
Similarly, the present value of each payment made in the second year can be given by:
PV of M200
\(= M200/(1 + 0.08)²\)
\(= M165.29\)
Similarly, the present value of each payment made in the third year can be given by:
PV of M300
\(= M300/(1 + 0.08)³\)
\(= M231.23\)
Similarly, the present value of each payment made in the tenth year can be given by:
\(PV of M1000 = M1000/(1 + 0.08)¹⁰ = M923.41\)
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