Answer:
28
Step-by-step explanation: This should be 28. 42 divided by 3 is 14. Why would you divide it by 3? Because the full ratio is 2:3. So 42 divided by 3 is 14. Then you add fourteen twice, for the two in the ratio. Fourteen plus fourteen is 28.
Which equation is the inverse of y = 100-x²?
Answer:
To find the inverse equation, switch the x and y variables then solve for y.
Original equation: .
y = 100 - x²
Inverse:
x = 100 - y²
y² = 100 - x
y = + √(100 - x) or the first option
Step-by-step explanation:
Question 6 of 10
f(x) = 5x + 1) – 3
g(x) = 4
Find (f - g)(x).
Answer:
Answer:
5x + 6
Step-by-step explanation:
(f-g)(x) is nothing but f(x) - g(x)
f(x) is |5x + 1| - 3 and g(x) is 4 so the equation is [|5x+1| - 3] - [4]
Once this is solved, the answer is 5x - 6. Since there's absolute value, remove the negative and change it to a positive to get the answer 5x + 6.
What is the value of x
Answer:
52/3
Step-by-step explanation:
Use basic Thales therom,
\(\frac{3x}{4x}=\frac{3x+7}{5x-8}\\\\\frac{3}{4}=\frac{3x+7}{5x-8}\\\)
Cross multiply,
3*(5x-8)=4*(3x+7)
3*5x - 3*8 = 4*3x + 4*7
15x - 24 = 12x +28
Add 24 to both sides
15x = 12x + 28 + 24
15x = 12x + 52
Subtract 12x from both sides
15x-12x =52
3x = 52
Divide both sides by 3
x = 52/3
Jermaine and Monica will usually both run 4.5 miles each time they go running. This month, Jermaine ran an additional 27 miles. Which answer choice shows an expression that represents the total distance Jermaine and Monica ran this month if j = the number of times that Jermaine ran and m = the number of times that Monica ran?
Answer:
4.5 (j + m) + 27
Step-by-step explanation:
what is 13q - 9q + 5 = 17
the answer is: q=3
start by combining like terms (13q - 9q) which would leave you with 4q + 5 = 17. subtract 5 from both sides and you're left with 4q = 12. divide by 4 on both side and you get q = 3
Answer:
q=3
Step-by-step explanation:
13q - 9q + 5 = 17
13q - 9q = 17 - 5
4q = 12
4q/4 = 12/4
q = 3
from the given graph: state it's
a) amplitude
b) period
c) function of the graph:
Step-by-step explanation:
The amplitude is 2. Amplitude means height from the x-axis to the crest/trough.
The period is 2pi. It is from crest to crest (next crest) or trough to trough (next trough).
Note that crest are the highest points of a wave, and that troughs are the lowest points of a wave. (we are talking about transverse waves, but this is more of a physics thing).
Function of graph:
By playing around in a graphing calculator, I got the equation to be
2 (cos (x + pi/2)).
the 2 changes the amplitude, and the + pi/2 shifts the graph by pi/2 to the left.
A conductor is mapping a trip and records the distance the train travels over certain time intervals?
The speed that the train travels is given as follows:
45 miles per hour.
How to obtain the train's velocity?The train travels at a constant speed, hence the distance traveled by the train over time is modeled by the proportional relationship defined as follows:
d = vt.
In which the variables of the equation are defined as follows:
v is the train's velocity.t is the time.Since the velocity is constant, it's equation is defined as follows:
v = d/t.
One point on the table is given as follows:
(1,45).
Hence the constant velocity of the train is calculated as follows:
v = 45/1 = 45 miles per hour.
Missing InformationThe problem is given by the image shown at the end of the answer.
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Julius and Isaiah share a reward of 440 in a ratio of 2:3 . How much does Isaiah get?
Answer: if Isaiah gets two thirds than he'll get 293.333333334 but if he gets one third than he will get 146.666666667
Step-by-step explanation:
Which of the following values of f are solutions to the inequality below?
Select all that apply.
Answer:
-4 is your answer
Step-by-step explanation:
A shipping box is 36 inches by 24 inches by 18 inches
how many cubic feet can it hold
Answer:
To find the volume of the shipping box in cubic feet, we need to convert the dimensions from inches to feet and then calculate the volume.
Given:
Length = 36 inches
Width = 24 inches
Height = 18 inches
Converting the dimensions to feet:
Length = 36 inches / 12 inches/foot = 3 feet
Width = 24 inches / 12 inches/foot = 2 feet
Height = 18 inches / 12 inches/foot = 1.5 feet
Now, we can calculate the volume of the box by multiplying the length, width, and height:
Volume = Length * Width * Height
Volume = 3 feet * 2 feet * 1.5 feet
Volume = 9 cubic feet
Therefore, the shipping box can hold 9 cubic feet.
Step-by-step explanation:
First convert the units because it's asking for the cubic feet but they give us the measurements in inches.
To convert inches to feet we divide the number by 12.
36 ÷ 12 = 3
24 ÷ 12 = 2
18 ÷ 12 = 1.5
Now to find the volume, we multiply it all together.
3 × 2 × 1.5 = 9
It can hold 9 cubic feet.
Hope this helped!
Hewo
My question:
1/2÷4 but if you could! draw a model plsss
Answer:
0.125
Step-by-step explanation:
So since we have 1/2 we will convert that to half of a pie... (the half circle)
We need to divide by four so we take that half of a pie and slice it into four parts... each part is now equivalent to our answer...
Equation... (as follows)
0.50 / 4 = 0.125
to check our work 0.125 x 4 = 0.50...
Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!
If the present value of $400 paid one year from now is $320, what is the one-year interest rate? (Note: this number is also known as the discount rate.)
Answer:
0.2
Step-by-step explanation:
Present Value = $320
Before 1 One Year, Value =$400
Discount = $400-$320= $80
% Discount = (Discount/Amount Before 1 Year)*100
%D = (80/400)*100
.%D = 20% Or 0.2
Please help find the perimeter and area of the polygon
A mathematical hypothesis could be a guess at a _____ rule.options:inputvariablefunction
Given
A mathematical hypothesis could be a guess at a _____ rule.
To fill in the blanks.
Answer:
A mathematical hypothesis could be a guess at a function rule.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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y=-4x^2-8x-5 find the axis of symmetry and the vertex for the parabola
Answer:
x= -1 a x i s of s ym m et ry
(-1, -1) v e r t e x
Step-by-step explanation:
M a t h w a y step by step
Explain how the Distributive Property can be used to solve the equation. 3(x+4)=36
The following bar chart shows the distances run by Jay's family in a race.
Find the median distance in km.
The median of the distances is M = 6.5 kilometers
Given data ,
To find the median of a set of numbers, we arrange the numbers in ascending order and then locate the middle value. If there is an odd number of values, the median is the middle number. If there is an even number of values, the median is the average of the two middle numbers.
Arranging the given set of numbers in ascending order: {4, 5, 8, 11}
Since the set has an even number of values, the median is the average of the two middle numbers. In this case, the two middle numbers are 5 and 8. To find the average, we add these two numbers and divide by 2:
(5 + 8) / 2 = 13 / 2 = 6.5
Hence , the median of the given set {4, 5, 8, 11} is 6.5
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perform the division...please!
Answer:
-7/3x + 3
Step-by-step explanation:
Answer:
(9x-7)/3x or (3-7/3x)
Step-by-step explanation:
Divide each term of numerator by denominator.
-28x^5/12x^6 +36x^6/12x^6
-7/3x +3
10 points right now for right answer
Your answer is 200
Hope it helps:)
Answer:
D
Step-by-step explanation:
y = 15 so 2/3 times 15 equals 30/3, which equals to 10
so far, you have 1/5 - 10 = 30
10 plus 30 equals to 40 so basically you have to find what times 1/5 equals to 40
200 times 1/5 is 40
sorry if this is too hard to understand but I tried my best to make it sound easy
What is the value of the expression 3\cdot2+2^33⋅2+2
3
Answer:
14Step-by-step explanation:
Given the expression 3.2 + 2^3, we are to simplify and find the value of the expression.
Note that the dot means multiplication. The equation then becomes;
\(= 3*2 + 2^3\\\\= (3*2) + (2*2*2)\\\\= 6 + (4*2)\\\\= 6 + 8\\\\= 14\)
Hence the value of the expression is 14
Answer please will make first answer brainliest
Answer:
The last one: 70/100 = x/80
And 56 free throws.
Explanation:
70% is 70 out of 100. And if the player is free throwing a total of 80 times, then 80 is 100% of the free throws. Both of the values that represent 100% are the denominators in the fractions.
\(\frac{70}{100} = \frac{x}{80}\)
The equations are equal, and whatever you do to the bottom, you have to do to the top. 100 was multiplied by 4/5 to get 80. So 70 is multiplied by 4/5 to get x.
4/5 * 70 is 56
Find the probability of randomly choosing an ace or a club from a standard deck of cards. Remember that a standard deck consists of
52 cards, where each card is made up of a number or letter from {2, 3,4, 5, 6, 7, 8, 9, 10, J, Q, K, A} and a suit from {clubs, diamonds, hearts, spades
Answer: The probability of choosing an ace or a club is 16.
Step-by-step explanation:
NO LINKS!!! URGENT HELP PLEASE!!!
Solve ΔABC using the Law of Sines
1. A = 29°, C = 63°, c = 24
2. A = 72°, B= 35°, c = 21
Answer:
1) B = 88°, a = 13.1, b = 26.9
2) C = 73°, a = 20.9, b = 12.6
Step-by-step explanation:
To solve for the remaining sides and angles of the triangle, given two sides and an adjacent angle, use the Law of Sines formula:
\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Question 1Given values:
A = 29°C = 63°c = 24As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies B=180^{\circ}-A-C\)
\(\implies B=180^{\circ}-29^{\circ}-63^{\circ}\)
\(\implies B=88^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies a=\dfrac{24\sin 29^{\circ}}{\sin 63^{\circ}}\)
\(\implies a=13.0876493...\)
\(\implies a=13.1\)
Solve for b:
\(\implies \dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies b=\dfrac{24\sin 88^{\circ}}{\sin 63^{\circ}}\)
\(\implies b=26.9194211...\)
\(\implies b=26.9\)
\(\hrulefill\)
Question 2Given values:
A = 72°B = 35°c = 21As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies C=180^{\circ}-A-B\)
\(\implies C=180^{\circ}-72^{\circ}-35^{\circ}\)
\(\implies C=73^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies a=\dfrac{21\sin 72^{\circ}}{\sin 73^{\circ}}\)
\(\implies a=20.8847511...\)
\(\implies a=20.9\)
Solve for b:
\(\implies \dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies b=\dfrac{21\sin 35^{\circ}}{\sin 73^{\circ}}\)
\(\implies b=12.5954671...\)
\(\implies b=12.6\)
Multiply the following binomials (2x - 3y)(8x - y)
Answer:
16x + \(3y^{2}\) - 26xy
Step-by-step explanation:
PEMDAS
(2x - 3y)(8x - y)
= 16x - 2xy - 24xy + \(3y^{2}\)
= 16x + \(3y^{2}\) - 26xy
Does the table represent a
function? Explain.
x
-3 -2 0 -3 -2
y 9 4 0 -9 -4
keeping in mind that a function does not have any X-Repeats, that is, the 1st coordinate in every pair never repeats, Check the picture below.
How do you get from one number to the next using multiplication or division?
From 100 to 106
From 100 to 90
From 90 to 100
From 106 to 100
Answer:
You use decimal values. Like for the first one, multiply 100 by 0.01.
Step-by-step explanation:
The multiplication or division is 10^6/10^4
How to interpret integral multiplication?Suppose that there are two positive integer numbers( numbers like 1,2,3,.. ) as a and b
Then, their multiplication can be interpreted as:
\(a \times b = a + a + ... + a \: \text{(b times)}\\\\a \times b = b + b +... + b \: \text{(a times)}\)
For example,
\(5 \times 2 = 10 = 2 + 2 + 2 + 2 + 2 \: \text{(Added 2 five times)}\\or\\5 \times 2 = 10 = 5 + 5 \: \text{(Added 5 two times)}\)
Given;
From 100 to 10^6;
100 * 10^4 = 10^6
From 100 to 90;
100/10*9=90
From 90 to 100
90/9*10=100
From 10^6 to 100
10^6/10^4=100
Therefore, by multiplication or division will be 10^6/10^4
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If f(x) = 2x + 7 and g(x) = 3x - 6, then what is (f + g)(x)?
9514 1404 393
Answer:
(f+g)(x) = 5x +1
Step-by-step explanation:
Substitute the given expressions and simplify.
(f+g)(x) = f(x) +g(x)
(f+g)(x) = (2x +7) +(3x -6) = (2x +3x) +(7 -6)
(f+g)(x) = 5x +1
Help me please, the answer choices are on the pic
Answer:
104
Step-by-step explanation:
Let's say that the numbers are x and y. So, we know that....
x+y=186
y-x=22
Now we can use the substitution method to find the numbers. y-x=22 turns into y=22+x. And now we can substitute to the second equation into the first equation.
x+22+x=186
2x=164
x=82
y=22+82
y=104
Our numbers are 82 and 104 and the larger integer is 104, so that's the answer.
Answer:
I believe the answer is 104.
Step-by-step explanation:
Because 186 - 104 = 82 and 104 - 22 = 82.
1.5 m =_____ cm
a 15
b 0.015
c 1.5
d 150
Answer:
150
Step-by-step explanation:
Answer:
D.)150
Step-by-step explanation:
Hope I helped