There are a total of 15 small and large vases on a shelf. The number of large vases is 6 fewer than twice the number of small vases. Which system of equations can be used to find the number of large vases (g) and the number of small vases (s)?

Answer:14.42

How to get it:Use Pythagorean Theorem to solve this problem. Since a squared plus b squared =c squared and we have an and c we can work backwards. Start by squaring 17 (17x17) which would be 289. Then do 9 squared (9x9) to get 81. Subtract 289-81 to get 208, square root this for your answer 14.4222 round to 14.42. You can check this by doing 14.4222 squared plus 9 squared then square root it and you should get approximately, but not exactly 17.

The simplified form of the given expression is 41.216.

The given expression is (3.2)(3.22)4.

We have to solve the given expression.

We can solve this equation by multiplying the term to one another because we know that if there is no symbol between the term then there should be the symbol of multiplication.

So we can write the given expression as

(3.2) × (3.22) × 4

To simplify this expression we first multiply the 3.2 to the 3.22 or we can also multiply 3.2 to the 4 or we can also multiply 3.22 to the 4. After multiplying the two term then we multiply the result of two number multiplication to the third number.

In that way we can easily simplify the given expression. Now,

= 10.304 × 4

= 41.216

Hence, the simplified form of the given expression is 41.216.

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Answer:

m = 10

Step-by-step explanation:

3.142*4.5²=63.6255

Answer=63.63

Please see the attached picture for full solution

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Good luck on your assignment..

To determine which function grows at a faster rate, we can apply L'Hospital's rule to calculate the limits of the functions as x approaches infinity.

For f(x) = 2^(2x) - 3^(3x), as x approaches infinity, we have an indeterminate form of ∞ - ∞. Applying L'Hospital's rule:

lim(x→∞) (2^(2x) - 3^(3x))

= lim(x→∞) (ln(2) * 2^(2x) - ln(3) * 3^(3x)) / (1 / x)

= lim(x→∞) ((ln(2) * 2^(2x) * 4) - (ln(3) * 3^(3x) * 9)) / (1)

= lim(x→∞) (ln(2) * 4 * (2^x)^2 - ln(3) * 9 * (3^x)^3)

= ∞ - ∞

Similarly, for g(x) = ln(x) - 2^(2x), as x approaches infinity, we have an indeterminate form of -∞ + ∞. Applying L'Hospital's rule:

lim(x→∞) (ln(x) - 2^(2x))

= lim(x→∞) (1/x - ln(2) * 4^(2x) * ln(4)) / (1)

= lim(x→∞) (1/x - ln(2) * 4^(2x) * ln(4))

= -∞ + ∞

Since both f(x) and g(x) yield indeterminate forms when applying L'Hospital's rule, we cannot determine which function grows at a faster rate solely based on this information. The correct answer is: d) There is not enough information to determine which function grows at a faster rate.

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Answer:

5-12-13 is a Pythagorean Triple.

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

We can use the Pythagorean Theorem to prove that 5-12-13 is a right triangle:

5² + 12² = 13²

25 + 144 = 169

169 does equal 169.

Answer:

A rotation is a transformation that turns a figure about a fixed point called the center of rotation. • An object and its rotation are the same shape and size, but the figures may be turned in different directions. • Rotations may be clockwise or counterclockwise.

Step-by-step explanation:

Answer:it means the movitem of a figure to somewhere else

Step-by-step explanation:

If Jamal takes full advantage of the education benefit, the annual value of this job to him is $14,165.

The company will pay 1/4 of the cost of medical insurance, which is $400/4 = $400/4 =100 per month.

The company will pay 1/2 of the cost of dental insurance, which is $75/2 = $75/2 = 37.5 per month.

The full yearly cost of vision insurance is $150 per year, which is $150/12 = $150/12 = 12.5 per month.

The full monthly cost of life insurance is $20 per month.

The total cost of the insurance benefits is $100 + $37.5 + $12.5 + $20 = 170 per month.

The base salary is $850 per week, which is $850/4 = 212.5 per week.

The annual value of the base salary is $212.5 x 52 = $11,125 per year.

The annual value of the insurance benefits is $170 x 12 = 2,040 per year.

If Jamal takes full advantage of the education benefit, the annual value of this job to him is $11,125 + $2,040 + $1,000 = $14,165.

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The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated for different data sets, as specified in the given values.

The UCL and LCL are statistical control limits used in process control to determine if a process is in a stable and predictable state. These limits define the range within which data points should fall if the process is under control.

In each case provided (A, B, C, D, E), the UCL and LCL values are given. These values represent the calculated control limits for the respective data sets.

To calculate the control limits, a specific statistical method such as the ± 3σ (sigma) method may have been used. This method sets the UCL and LCL at three standard deviations above and below the mean.

The UCL represents the upper threshold or upper boundary, while the LCL represents the lower threshold or lower boundary. These limits help identify any potential deviations or out-of-control situations in the data.

By applying the given values, the corresponding UCL and LCL for each data set can be calculated. These limits are important for quality control and process monitoring, ensuring that the data falls within acceptable ranges.

To calculate the UCL and LCL using ±3σ limits, we use the following formulas:

UCL = Mean + 3σ
LCL = Mean - 3σ

Here, σ represents the standard deviation of the data set. The ±3σ limits provide a range that encompasses most of the data points in a normal distribution, with approximately 99.7% of the data falling within this range.
A) For data set A:
UCL = 7.437
LCL = -2.237

B) For data set B:
UCL = 7.82
LCL = 0

C) For data set C:
UCL = 8.382
LCL = 0

D) For data set D:
UCL = 7.82
LCL = -2.22

E) For data set E:
UCL = 9.112
LCL = 0

The ±3σ limits are derived from the standard deviation (σ) of the data set. Unfortunately, the standard deviation is not provided in the given information. If you have the standard deviation available, we can proceed to calculate the UCL and LCL using the formulas UCL = Mean + 3σ and LCL = Mean - 3σ.

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Question - What are the upper control limit (UCL) and lower control limit (LCL) using a ±3σ limit for the given data sets?

A) For data set A, the UCL is 7.437 and the LCL is -2.237.
B) For data set B, the UCL is 7.82 and the LCL is 0.
C) For data set C, the UCL is 8.382 and the LCL is 0.
D) For data set D, the UCL is 7.82 and the LCL is -2.22.
E) For data set E, the UCL is 9.112 and the LCL is 0.

The Fourier coefficient C of the exponential series for the periodic function z(t) = cos(6t) + sin(8t) + et is zero.

To find the Fourier coefficient C of the exponential series for the periodic function z(t) = cos(6t) + sin(8t) + et, we need to compute the integral of the product of z(t) and the complex conjugate of the complex exponential function \(e^{-jwt\) over one period.

The Fourier coefficient C is given by the formula:

C = (1/To) * ∫[0,To] z(t) * \(e^{-jwt\) dt

In this case, the periodic function z(t) includes an exponential term, so we need to compute the integral for both the sinusoidal terms (cos(6t) and sin(8t)) and the exponential term (et) separately.

Let's start with the exponential term:

\(C_{exponential\) = (1/To) * ∫[0,To] et * \(e^{-jwt\) dt

Since the function et is not periodic, the integral over one period To will not result in a finite value. Therefore, the Fourier coefficient \(C_{exponential\) for the exponential term will be zero.

Now, let's compute the Fourier coefficients for the sinusoidal terms:

\(C_{cosine\) = (1/To) * ∫[0,To] cos(6t) * \(e^{-jwt\) dt

\(C_{sine\) = (1/To) * ∫[0,To] sin(8t) * \(e^{-jwt\) dt

To evaluate these integrals, we need to know the specific value of ω. Without this information, we cannot determine the exact values of \(C_{cosine\) and \(C_{sine\). The Fourier coefficients of the sinusoidal terms will depend on the frequency content of the function z(t).

In summary, the Fourier coefficient C of the exponential series for the periodic function z(t) = cos(6t) + sin(8t) + et is zero (\(C_{exponential\) = 0), while the Fourier coefficients of the sinusoidal terms (\(C_{cosine\) and \(C_{sine\)) cannot be determined without specifying the frequency ω.

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Answer: r = -3, t = -4

Step-by-step explanation:

6r-6t=6

3r-6t=15

Using the elimination method, you can get

3r=-9

r=-3

Substitute -3 for r, and you get

-9-6t=15

-6t=24

t=-4

r=-3,t=-4

Answer:

r,t=-3,-4

Step-by-step explanation:

[1]    6r - 6t = 6

  [2]    3r - 6t = 15

Using the concept of probability, the probability that the first experiment is successful is 70.97%

To calculate the probability that the first experiment is successful, we use the relation thus :

Inserting the values into the formula :

Therefore, the probability value is 70.97%

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Answer:

A = (5, 3), so the x-value is 5

Step-by-step explanation:

Answer:

(5, 3), so the x-value is 5

Step-by-step explanation:

Person above me right thank you person above me

Answer:

w = 3

Step-by-step explanation:

to solve for w, do the inverse operation to get w by itself. The inverse operation of multiplication is division. So divide -9 by -9 and divide -27 by -9. When dealing with multiplication and division of negative numbers, a negative and a positive are negative. two negative numbers are positive. -9 and -27 make positive 3 so:

w=3

hope this helps

9514 1404 393

Answer:

  D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

  y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

  xy = k . . . . . . multiply the above equation by x

  (10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

  y = 60/x

you can multiply them together to see if the product is 60.

  (A) 12×5 = 60

  (B) 15×4 = 60

  (C) 25×2.4 = 60

  (D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

Answer:

x < −4

Step-by-step explanation:

Add 6 to both sides.

-5x> 14 + 6

Simplify  14+6  to 20.

-5x>20

Divide both sides by -5.

x<-20/5

​

Simplify  

x<−4

Answer:

5

Step-by-step explanation:

Let the number of the kitchen clock sold =a

Let the number of the cuckoo clock sold =b

Let the number of the two-foot high grandfather clocks sold =c

The new saleswoman sold at least two of each of the three models.

Therefore:

\(a\geq 2\\b \geq 2\\c \geq 2\)

In all, she collected $300 from selling these models alone

17a+31b+61c=300

17(2)+31(2)+61(2)=218

300-218=82

Next, we try to express the remainder (82) in terms of 17, 31 and 61

82=17(3)+31

Therefore, she sold:

She sold 5 $17 clocks.

CHECK:

17(5)+31(3)+2(61)=$300

The percentage of the students who wore a silly hat is 64 %.

The percentage is defined as a ratio expressed as a fraction of 100.

We have been given that Last Tuesday was a silly hat day at Aaron's school. 64 students wore a silly hats and 36 students did not.

We have to determine the percentage of the students who wore a silly hat

The total number of students = 64 students wore silly hats and 36 students did not.

The total number of students = 64 + 36 = 100

We have to determine the percentage of the students who wore a silly hat

The percentage of the students wore a silly hat = (64/ 100) × 100

The percentage of the students wore a silly hat = 0.64 × 100

The percentage of the students wore a silly hat = 64 %

Thus, the percentage of students who wore silly hats is 64 %.

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Answer: .5

hope thisi helps

plz mark brainliset

Step-by-step explanation:

185:370

divide both sides by185

you get the ratio is 1:2

The three conditions for a function to be continuous at a point x=a are:

a) The function is defined at x=a.

b) The limit of the function as x approaches a exists.

c) The limit of the function as x approaches a is equal to the value of the function at x=a.

The continuity of a function can be analyzed by observing its graph. However, as the graph is not provided, a specific discussion about its continuity cannot be made without further information. It is necessary to examine the behavior of the function around the point in question and determine if the three conditions for continuity are satisfied.

The function f(x) = { *** is not defined in the question. In order to discuss its continuity, the function needs to be provided or described. Without the specific form of the function, it is impossible to analyze its continuity. Different functions can exhibit different behaviors with respect to continuity, so additional information is required to determine whether or not the function is continuous at a particular point or interval.

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Answer:

18

Step-by-step explanation:

w varies directly with z, let k be the constant of proportionality, hence this can be represented by the equation:

w = kz

When z = 4, w = 12, hence we need to find the value of the constant of proportionality, substituting:

12 = 4k

Dividing both sides by 4:

12/4 = 4k/4

k = 3

Therefore the equation becomes:

w = 3z

The value of w when z = 6 is given as:

w = 3(6)

w = 18

The value of y at x = 121.9 for the expression y = 3x - 245 will be 120.7.

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication and division.

Given that the expression is y = 3x - 245. The value of x is 121.9.

The solution for the value of y will be calculated as:-

y = 3x - 245

y = ( 3 x 121.9 ) - 245

y = 365.7 - 245

y = 120.7

Therefore, the value of y for the given expression will be 120.7.

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The complete question is given below.

Find the value of y for the expression y = 3x - 245 at x = 121.9.

The statement “there exists a function f such that f(x) < 0, f’(x) > 0, and f”(x) < 0 for all x” is false.

To understand why this statement is false, we must first understand what the symbols mean. The symbol f(x) refers to a function of x, and the symbols f’(x) and f”(x) refer to the first and second derivatives of the function, respectively.

The statement is saying that for all x, the function f(x) will be less than 0, the first derivative f’(x) will be greater than 0, and the second derivative f”(x) will be less than 0.

To show that this statement is false, we need to find an example of a function where this is not the case. Let’s consider the function f(x) = x³. At x = 0, this function is equal to 0, and so f(x) < 0 is not true. Additionally, the first derivative at x = 0 is f’(0) = 0, which is not greater than 0. Thus, the statement is false.

We can also show that this statement is false by looking at the graph of the function f(x). A function with the properties given in the statement would have a graph that looks like a “U” shape, with a minimum point at the origin. However, this is not the case for the function f(x) = x³. The graph of this function is a parabola, which does not have the desired shape.

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Answer:

the answer is because u need trust me6

Answer:

3

Step-by-step explanation:

First, subtract 4 from both sides. When you do this, that leaves you with: 3x=9. Then, divide 9 by 3 to get x by itself. x=3

Answer:

Find out what X is (X = 3) , Multiply X times three, add your new number with 4.

3 x 3 + 4 = 13