There are classes. (Type a whole number.) (b) The lower class limit for the first class is (Type an integer or a decimal. Do not round.) The upper class limit for the first class is (Type an integer or a decimal. Do not round.) (c) The class width is (Type an integer or a decimal. Do not round.) Speed (km/hr) 10-13.9 14-17.9 18-21.9 22-25.9 26-29.9 30-33.9 Number of Players 4 7 20 80 268 237 (a) und number of classes, (b) the class limits for the first class, and (c) the class width.

Answer:

what language is that??

Step-by-step explanation:

Answer:

\(10x^2-x+3\) miles.

Step-by-step explanation:

It is given that,

Total length of park trail = \(10x^2+4x+2\) miles

Total length traveled by hiker = \(5x-1\) miles

We need to find the length of trail hiker need to travel to get to the end of the trail.

Required length \(=10x^2+4x+2-(5x-1)\)

               \(=10x^2+4x+2-5x+1\)

               \(=10x^2+(4x-5x)+(2+1)\)

               \(=10x^2-x+3\)

Therefore, hiker need to travel \(10x^2-x+3\) miles to get to the end of the trail.

Answer:

b

Step-by-step explanation:

my teacher went over the same on with me

Answer:

false

Step-by-step explanation:

this is because there is no function of an unknown in this set

Answer:

Step-by-step explanation: Don't have an explanation except elimination.

Answer: 20

Step-by-step explanation: 7x+40=180

40-180=140

7x=140

140/70.

go with your heart if you think that your heart is telling you something just go with it trust your instinct

In this scenario, the shape of the sampling distribution of X-bar is approximately normal.

The sampling distribution of the sample mean, X-bar, can be determined by the Central Limit Theorem. In this case, since the sample size is large (n = 64) and the underlying distribution (X) is approximately normal, the sampling distribution of X-bar will also be approximately normal. The Central Limit Theorem states that regardless of the shape of the population distribution, as the sample size increases, the sampling distribution of X-bar tends to become more and more normal. Therefore, in this scenario, the shape of the sampling distribution of X-bar is approximately normal.

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To remove the single quotation marks ('') at the beginning and end of a string and remove the item at index 12, you can use Python's string manipulation methods and list slicing. First, you can use the strip() method to remove the surrounding single quotation marks. Then, you can convert the string into a list using the list() function, remove the item at index 12 using list slicing, and finally convert the list back into a string using the join() method.

To remove the single quotation marks at the beginning and end of a string, you can use the strip() method. This method removes any leading and trailing characters specified in the argument. In this case, you can pass the single quotation mark ('') as the argument to strip().

Here's an example:

string = "'example string'"

stripped_string = string.strip("'")

After executing this code, the value of stripped_string will be 'example string' without the surrounding single quotation marks.

To remove the item at index 12 from the string, you need to convert it into a list. You can use the list() function for this conversion. Then, you can use list slicing to remove the item at index 12 by excluding it from the list. Finally, you can convert the modified list back into a string using the join() method.

Here's an example:

string_list = list(stripped_string)

string_list.pop(12)

result_string = ''.join(string_list)

After executing this code, the value of result_string will be the modified string with the item at index 12 removed.

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Answer:

-5/6

Step-by-step explanation:

Use slope intercept form: \(\frac{y_2-y_1}{x_2-x_1}\)

\(\frac{-2-8}{20-8}\) = \(\frac{-10}{12}\) = -5/6

Answer:

0.325 hits per bat

Step-by-step explanation:

13/40=0.325

Answer:

\(\displaystyle 707\:ft.^2\)

Step-by-step explanation:

Split the diametre in half before proceeding:

\(\displaystyle \pi{r}^2 = A \\ \\ 15^2\pi = A \hookrightarrow 225\pi = A \hookrightarrow 706,85834706... = A \\ \\ \boxed{707 \approx A}\)

I am joyous to assist you at any time.

The summary of the results is as follows:How many possible outcomes are there in the outcomes space.- 36 How many elements are in the event of getting different numbers without repetitions. - 30 How many elements are in the event of getting different numbers without repetitions but the second number must be a 4? - 6

There are six possible outcomes in the outcomes space. Let us solve each part of the question.How many possible outcomes are there in the outcomes space?The possible outcomes in the outcomes space for the given problem is calculated by multiplying the number of outcomes of the first roll by the number of outcomes of the second roll.Number of possible outcomes of each roll

= 6 (as there are six faces on a dice)Total possible outcomes in the outcomes space

= 6 × 6

= 36So, there are 36 possible outcomes in the outcomes space.How many elements are in the event of getting different numbers without repetitions?In this case, the two rolls are independent. This means the first roll doesn't affect the second roll. Thus, all possible outcomes with different numbers are 6 × 5

= 30. So, there are 30 elements in the event of getting different numbers without repetitions.How many elements are in the event of getting different numbers without repetitions but the second number must be a 4?In this case, we can have any one of the six numbers in the first roll. Then, only one number 4 is left for the second roll. Thus, there are 6 possible outcomes where the second number is a 4. Hence, there are 6 elements in the event of getting different numbers without repetitions but the second number must be a 4.The summary of the results is as follows:How many possible outcomes are there in the outcomes space.- 36 How many elements are in the event of getting different numbers without repetitions. - 30 How many elements are in the event of getting different numbers without repetitions but the second number must be a 4? - 6

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Answer:

A = 7 x 9.3

A = 65.1 yd²

Step-by-step explanation:

(I am assuming that either 7 or 9.3 refers to the height. It is unclear.)

A = bh

Answer:

i think its d

Step-by-step explanation:

y+4

The points y axis is increased by +4 if you look a the graph.

The z score associated with the highest 10% is closest to: option (c) 1.28

-To find the z score associated with the highest 10%, first determine the percentage that corresponds to the lower 90%, since the z score table typically represents the area to the left of the z score.

- Look up the 0.90 (90%) in a standard normal distribution  (z score) table, which will give you the corresponding z score.

-The z score closest to 0.90 in the table is 1.28, which corresponds to the highest 10% of values.

Therefore, the z score associated with the highest 10% is closest to 1.28.

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The initial graph shows \(f(x)= 2(3)^{x}\)

A function is a mathematical object that assigns a unique output (or "value") to each input in its domain. It is a rule that takes an input (or "argument"), performs some operations on it, and returns a corresponding output. Functions are often written using the notation f(x), where x is the input, and f(x) is the corresponding output. For example, the function f(x) = x^2 maps the input value x to its square. Functions are a key concept in mathematics and are used to model various phenomena in science, engineering, economics, and more.

The function provided is,

\(f(x)= 2(3)^{x}\)

making x = 1

\(f(x)= 2(3)^{1}=f(x)= 2(3)=6\)

The point (1, 6) that is (x, f(x)) must therefore satisfy the condition or be on the curve of the function.

The point (1, 6) only lies on the curve in the first graph.

As a result, the first graph accurately depicts the function.

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The population of birds to increase by 50% in 31.25 years.

The differential equation for the population of birds is:

dp/dt = 0.016P

where P is the population of birds and t is time in years.

To obtain the time it takes for the population to increase by 50%, we need to solve for t when P increases by 50%.

Let P0 be the initial population of birds, and P1 be the population after the increase of 50%.

Then we have:

P1 = 1.5P0 (since P increases by 50%)

We can solve for t by integrating the differential equation:

dp/P = 0.016 dt

Integrating both sides, we get:

ln(P) = 0.016t + C

where C is the constant of integration.

To obtain the value of C, we can use the initial condition that the population at t=0 is P0:

ln(P0) = C

Substituting this into the previous equation, we get:

ln(P) = 0.016t + ln(P0)

Taking the exponential of both sides, we get

:P = P0 * e^(0.016t)

Now we can substitute P1 = 1.5P0 and solve for t:

1.5P0 = P0 * e^(0.016t

Dividing both sides by P0, we get:

1.5 = e^(0.016t)

Taking the natural logarithm of both sides, we get:

ln(1.5) = 0.016t

Solving for t, we get:

t = ln(1.5)/0.016

Using a calculator, we get:

t ≈ 31.25 years

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Fingerprinting is a technique used by forensic experts and crime scene investigators to identify individuals based on their unique fingerprints. Fingerprints are unique to each individual and have distinct ridge patterns that are used to identify individuals.

It is an effective way of identifying people because fingerprints remain the same throughout a person's life, unlike other physical characteristics.

When fingerprinting a person who is missing fingers, two notations that should be used on the fingerprint card are "amputation" and "absent." The notations on the fingerprint card should indicate that the fingers are missing due to amputation or absence.

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When fingerprinting a person missing fingers, the two notations that should be used on the fingerprint card are tented arch for a missing middle finger and amputation notation for a completely missing finger.

When fingerprinting a person who is missing fingers, two notations should be used on the fingerprint card:

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Answer:

Total cost = $14464

Step-by-step explanation:

Step 1:  Multiply the discount percentage by the regular price to determine the discount amount:

0.20 * 16000 = 3200

Thus, the 20% discount lowers the regular price by $3200.

Step 2:  Subtract the discount amount from the regular price to determine the new price:

16000 - 3200 = 12800.

Thus, the subtotal is $12800

Step 3:  Multiply tax percentage by subtotal to determine tax:

0.13 * 12800 = 1664

Thus, the 13% tax rate would raise the subtotal by $1664.

Step 4:  Add the tax to the subtotal to find the cost price.

1664 + 12800 = 14464.

Thus, the total cost of the car is $14464.

Thus, the total cost of the car with the 20% discount and the 13% tax is 14464.

A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).

Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.

As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt

Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.

For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:

E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.

Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:

dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt

where M is a martingale with M(0) = 0.

Thus, X(t) can be represented as an Itô process on [0,T] of the form:

X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds

Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.

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Answer:

1)  \(\mathbf{5^{-3}=\frac{1}{125}}\)

2)  \(\mathbf{-5^{-3}=-\frac{1}{125}}\)

3)  \(\mathbf{(-5^{-3})^{-1}=-125}\)

4)  \(\mathbf{(-5^{-3})^0=1}\)

Step-by-step explanation:

We need to solve the exponents

1) \(5^{-3}\)

We know that: \(a^{-1}=\frac{1}{a}\)

\(5^{-3}\\=\frac{1}{5^3}\\=\frac{1}{125}\)

So, we get \(\mathbf{5^{-3}=\frac{1}{125}}\)

2) \(-5^{-3}\)

We know that: \(a^{-1}=\frac{1}{a}\)

\(-5^{-3}\\=-\frac{1}{5^3}\\=-\frac{1}{125}\)

So, we get \(\mathbf{-5^{-3}=-\frac{1}{125}}\)

3) \((-5^{-3})^{-1}\)

We know that: \((a^m)^n=a^{m*n}\)

Using this rule:

\((-5^{-3})^{-1}\\=-5^{-3*-1}\\=-5^{3}\\=-125\)

So, we get \(\mathbf{(-5^{-3})^{-1}=-125}\)

4)  \((-5^{-3})^0\)

We know that: \((a^m)^n=a^{m*n}\)

Using this rule:

\((-5^{-3})^0\\=-5^{-3*0}\\=-5^{0}\\We\:know\:a^0=1\\=1\)

So, we get \(\mathbf{(-5^{-3})^0=1}\)

Two shapes of the same size and shape are congruent. There are five conditions or rules for two triangles to be congruent. They are SSS, SAS, ASA, AAS, and RHS joint properties.

Triangle Congruence:

The congruence of two or more triangles depends on the measurements of their sides and angles. The three sides of a triangle determine its size, and its three angles determine its shape.

Two triangles are considered congruent if their pairs of corresponding sides and corresponding angles are equal.

SSS (side-side-side) :

According to this criterion, two triangles are congruent if his three sides of one triangle are equal to the corresponding sides of the other triangle.

ASA ( Angle-Side-Angle ) :

According to the ASA criterion, two triangles are congruent if any two angles and the inner side of one triangle between them are equal to the corresponding angles and inner sides of the other triangle.

SAS (Side Angle Side)

According to this criterion, two triangles are congruent if two sides and included angles of one triangle are equal to the corresponding sides and included angles of the other corresponding triangle.

AAS ( Angle - Angle Side) :

According to the AAS standard, two triangles are congruent if any two angles and the excluded side of one triangle are equal to the corresponding angles and the excluded side of the other triangle

RHS (Right Angle Two-sided)

According to this criterion, two triangles are congruent if the hypotenuse and side of one right triangle are equal to the hypotenuse and corresponding side of another right triangle.

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To find the absolute maximum value of h(x) = -2x^2 + x over the interval [-3, 3], we need to identify critical points and evaluate the function at those points as well as the interval's endpoints.

First, find the critical points by taking the derivative of h(x) and setting it to 0:

h'(x) = -4x + 1

-4x + 1 = 0
4x = 1
x = 1/4

Now, evaluate h(x) at the critical point and the endpoints of the interval:

h(-3) = -2(-3)^2 + (-3) = -18
h(1/4) = -2(1/4)^2 + (1/4) = -1/8 + 1/4 = 1/8
h(3) = -2(3)^2 + 3 = -15

Comparing the values, we can see that the absolute maximum value is h(1/4) = 1/8.

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For the inference in part b to be valid, the conditions required are reasonable satisfaction.

To determine if the conditions for the inference in part b are reasonably satisfied, we need to consider the specific details of the inference.

However, in general, the conditions for a valid inference typically include logical reasoning, accurate data, reliable sources, and relevant contextual information.

These conditions ensure that the conclusion drawn from the inference is supported by evidence and does not contain logical fallacies or biases. It is important to evaluate the quality and reliability of the information used in the inference to determine if the conditions are reasonably satisfied.

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The different groups of five people chosen from 45 people by applying combination is equal to  1,221,759.

Total number of people = 45

Number of people chosen at random to receive door prize = 5

The number of different groups of five people that can be chosen out of 45 attendees,

we need to use the combination formula,

ⁿCₓ = n! / (x! × (n-x)!)

where n is the total number of attendees,

x is the number of people to be chosen,

and ! denotes factorial (e.g., 5! = 5 x 4 x 3 x 2 x 1).

Here, we have n = 45 and x = 5, so we can plug these values into the formula,

⁴⁵C₅

= 45! / (5! × (45-5)!)

= (45 x 44 x 43 x 42 x 41) / (5 x 4 x 3 x 2 x 1)

= 1,221,759

Therefore, there are 1,221,759 different groups of five people that can be chosen from a total of 45 attendees using combination.

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Answer:

\(= \frac{2m^2n^8}{3}\)

Step-by-step explanation:

Given expression is

\((\frac{4m^{-2}n^8}{9m^{-6}n^{-8}} )^{\frac{1}{2}\)

The correct simplified form is shown below:-

From the above equation, we will simplify

we will shift \(m^{-6}\) to the numerator and we will use the negative exponent rule, that is

\(= (\frac{4m^{-2}n^8m^6}{9n^{-8}} )^{\frac{1}{2}\)

now we will shift the \(n^{-8}\) to the numerator and we will use the negative exponent rule, that is

\(= (\frac{4m^{-2}n^8m^6n^8}{9} )^{\frac{1}{2}\)

here we will solve the above equation which is shown below

\(= (\frac{4m^4n^{16}}{9}) ^\frac{1}{2}\)

So,

\(= (\frac{(2)^2(m^2)^2(n^8)^2}{(3)^2} ^\frac{1}{2}\)

Which gives result

\(= \frac{2m^2n^8}{3}\)