this is geometry find x!

Answer:

Hope your doing ok!

Step-by-step explanation:

I don't know what happened but I hope for the best for you for the rest of the day. Have a nice day! <3

Answer:

10) 6

11) 18

12) 7.1

13) 1.3

Step-by-step explanation:

all you have to do is substitute

10 - 4 = 6

12 + 6 = 18

1.9 + 5.2 = 7.1

3.4 - 2.1 = 1.3

Answer:

\(2.28*10^7\)

Step-by-step explanation:

\((2.4*10^3)(9.5*10^3)=(2.4*9.5)(10^3*10^3)=22.8*10^6=2.28*10^7\)

Answer:

228,000

Step-by-step explanation:

(2.4x10^3) x (9.5x10^3)

(2.4x100) x (9.5x100)

240x950

228,000

The line crosses the y-axis at -9 and has a slope of 4, meaning it increases 4 units in the y-direction for every 1 unit increase in the x-direction.

A graph is a visual representation of data, typically involving the use of points, lines, and curves to show how different values are related to each other. Graphs can be used to display a wide range of information, from mathematical functions and scientific data to business trends and social networks.

Here,

To graph y = 4x - 9, we can start by plotting the y-intercept, which is -9 on the y-axis. Then, we can use the slope of 4 to find other points on the line.

Slope = 4 can be written as rise/run = 4/1. This means that for every increase of 1 in the x-direction, the y-value increases by 4.

Starting from the y-intercept (-9,0), we can go up 4 units and to the right 1 unit to get the point (1,-5). We can continue this pattern and plot more points on the line, or we can simply draw a straight line through the y-intercept and (1,-5) to represent the equation y = 4x - 9.

Here's what the graph looks like:

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The values of the variables in the equation [-4+t 2y r w+5] = [2t 11 -2r+12 9] can be determined as follows: t = 3, y = 8, r = -3, and w = 4.

To find the values of the variables in the equation, we can compare the corresponding elements on both sides. Looking at the first element, we have -4+t = 2t. By simplifying the equation, we can deduce that t = 3. Moving on to the second element, 2y = 11, which implies y = 8.

Examining the third element, we have r = -2r+12. Simplifying this equation, we find that r = -3. Finally, for the fourth element, w+5 = 9, which yields w = 4. Therefore, the values of the variables in the equation are t = 3, y = 8, r = -3, and w = 4. These values satisfy the equation [-4+t 2y r w+5] = [2t 11 -2r+12 9] and provide a solution to the given system of equations.

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Answer: False

Step-by-step explanation:

Example 3 times -3= -9

Answer: False

Step-by-step explanation:

Positive * Positive = Positive

Negative * Positive = Negative

Negative * Negative = Positive

Therefore, the 90% confidence interval for the proportion of medical malpractice lawsuits that are dropped or dismissed is (0.635, 0.695).

To construct a confidence interval for the proportion of medical malpractice lawsuits that are dropped or dismissed, we can use the following formula:

CI = p ± z*sqrt((p*(1-p))/n)

where:

- p is the sample proportion of lawsuits that are dropped or dismissed (p = 732/1100 = 0.665)

- z* is the critical value of the standard normal distribution at a 90% confidence level (from a standard normal distribution table, z* = 1.645 for a 90% confidence level)

- n is the sample size (n = 1100)

Substituting the values into the formula, we get:

CI = 0.665 ± 1.645*sqrt((0.665*(1-0.665))/1100)

  = 0.665 ± 0.030

Therefore, the 90% confidence interval for the proportion of medical malpractice lawsuits that are dropped or dismissed is (0.635, 0.695). This means that we can be 90% confident that the true proportion of lawsuits that are dropped or dismissed is between 0.635 and 0.695.

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Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.

Given information and corresponding atomic propositions:

We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:

r: Rabbits have been seen in the area.

b: Berries are ripe along the path.

w: Walking on the path is safe.

Now, let us formalize each of the given statements in terms of these atomic propositions:

a) Berries are ripe along the path, but rabbits have not been seen in the area.

b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.

c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.

d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.

e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.

The formalizations in terms of atomic propositions are:

a) b ∧ ¬r.b) ¬r ∧ w ∧

b.c) (b → w) ∧ (¬r → w).

d) ¬w ∧ ¬r ∧

b.e) (¬r ∧ ¬b) → w.b ∧

Berries are ripe along the path, but rabbits have not been seen in the area.

This is formalized by using the ∧(logical and) operator.

(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

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Answer:

C

Step-by-step explanation:

Hope this Helps :)

The scale would show the weight that is closest to the actual weight of the peaches, whether it is 4.158 or 4.168 pounds.

What is measurement?

Measurement is the process of assigning numerical values to physical quantities such as length, mass, time, temperature, and many others.

It depends on the actual weight of the peaches. If the weight of the peaches is closer to 4.158 pounds, then the scale would show 4.158 pounds. Similarly, if the weight of the peaches is closer to 4.168 pounds, then the scale would show 4.168 pounds.

Since the scale can measure weight to the nearest thousandth of a pound, it can differentiate between weights that differ by one-thousandth of a pound.

Therefore, the scale would show the weight that is closest to the actual weight of the peaches, whether it is 4.158 or 4.168 pounds.

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Answer:

\(\boxed{\sf y=37^o}\)

\(\boxed{\sf x=74^o}\)

\(\boxed{\sf z=25^o}\)

Step-by-step explanation:

Let's first solve for y:-

*Linear pairs are supplementary angles, meaning there sum should be 180° *

\(\sf 2y^o+106^o=180^o\)

\(\sf 2y=180-106\)

\(\sf \cfrac{2y}{2} =\cfrac{74}{2}\)

\(\boxed{\sf y=37^o}\)

*Consecutive angles are also supplementary angles = 180°*

\(\sf x=2y\)

\(\sf x=2(37)\)

\(\boxed{\sf x=74^o}\)

By corresponding angles,

\(\sf 4z+6=106\)

\(\sf 4z+6-6=106-6\)

\(\sf \cfrac{4z}{4} =\cfrac{100}{4}\)

\(\boxed{\sf z=25^o}\)

_____________________

Hope this helps!

Have a good day!

Answer:

\( M(6, 6) \)

Step-by-step explanation:

Given:

Endpoints of a line segment, T(6, 3) and U(6, 9)

Required:

Midpoint, M, of line segment TU

✍️Solution:

Apply the midpoint formula, which is given as: \( M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}) \).

Let:

\( T(6, 3) = (x_1, y_1) \)

\( U(6, 9) = (x_2, y_2) \)

Plug in the values into the formula

\( M(\frac{6 + 6}{2}, \frac{3 + 9}{2}) \)

\( M(\frac{12}{2}, \frac{12}{2}) \)

\( M(6, 6) \)

Coordinates of the midpoint, M, of line segment TU is \( (6, 6) \)

Answer:

WALK=9 PUPILS

BUS=12 PUPILS

CAR=4 PUPILS

BIKE=4 PUPILS

Step-by-step explanation:

TOTAL=360/10 = 36                          120+90=210

BUS=120/10=12                                  360-210=75/2=37.5

WALK=90/10=9

CAR=37.5/10=3.75=4

BIKE=37.5/10=3.75=4

We will prove by mathematical induction that for all n ≥ 1, the expression 11^n + 2 + 12^(2n + 1) is divisible by 133. The base case is n = 1, where the expression evaluates to 137, which is divisible by 133. We assume that the expression is divisible by 133 for some value k = m, and then prove that it holds true for k = m + 1.

Base case: For n = 1, the expression becomes 11^1 + 2 + 12^(2*1 + 1) = 11 + 2 + 12^3 = 137. Since 137 is divisible by 133 (137 = 1 * 133 + 4), the base case is true.Inductive step: Assume that for some value k = m, the expression 11^m + 2 + 12^(2m + 1) is divisible by 133, i.e., it can be expressed as 133a, where a is an integer. Now we need to prove that for k = m + 1, the expression 11^(m + 1) + 2 + 12^(2(m + 1) + 1) is divisible by 133.

Expanding the expression, we have 11^(m + 1) + 2 + 12^(2m + 3) = 11 * 11^m + 2 + 12 * 12^(2m + 1).Using the assumption, we can write this expression as (133a - 2) * 11 + 2 + 12 * 12^(2m + 1). Simplifying further, we have 133a * 11 + 12 * 12^(2m + 1).Factoring out 133, we get 133(a * 11 + 12^(2m + 1)).

Since both a * 11 and 12^(2m + 1) are integers, the expression is divisible by 133.Therefore, by mathematical induction, we have proven that for all n ≥ 1, the expression 11^n + 2 + 12^(2n + 1) is divisible by 133.

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The probability that either house sales or interest rates will increase in the next 6 months is estimated to be 0.79.

To find the probability that either house sales or interest rates will go up in the next 6 months, we can use the concept of union in probability theory. The union of two events A and B, denoted as A ∪ B, represents the event that either A or B or both occur.

Given the probabilities that house sales will increase (0.25) and interest rates on housing loans will go up (0.74), we need to calculate the probability of the union of these two events. However, we must consider that the events are not mutually exclusive, meaning that it is possible for both house sales to increase and interest rates to go up simultaneously.

To calculate the probability of the union, we can use the formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where P(A) represents the probability of event A, P(B) represents the probability of event B, and P(A ∩ B) represents the probability of both events A and B occurring.

Substituting the given probabilities into the formula, we have P(A ∪ B) = 0.25 + 0.74 - P(A ∩ B). Since we do not have the information regarding the joint probability of both events occurring (P(A ∩ B)), we cannot determine the exact probability of the union. However, we can say that the probability of either house sales or interest rates going up is estimated to be 0.79, assuming that the joint probability is not significant.

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The evaluation of the quadratic equations are as follows;

Question 5

Question 6

Question 7

Sometimes; Factoring

Always; Quadratic formula

Always; Completing the square

Sometimes; Square root method

Sometimes; Factoring by group

Question 8

The numerator are;

(a) 8

4

(b) The denominator value;

4

(c) The roots are;

2

1

A quadratic equation is an equation of the form; a·x² + b·x + c = 0

Question 5

The quadratic equation, x² + 6·x + 10 = 0

The discriminant is 6² - 4×1×10 = -4

The discriminant < 0, therefore, the equation does not have solution

Question 7

Factoring;

Method of solving equations work more when the coefficient of x and the constant can be expressed as a + b and a·b

Where;

a·b = The constant

a + b = The coefficient of x

Therefore, factoring works sometimes

Sometimes; Factoring

Quadratic formula

The quadratic formula is an equation that involves the use of the constant and the coefficients of x

The quadratic formula therefore works all the time

Always; Quadratic formula

Complete the square

The completing the square method works by rearranging the equation in the form;

a·x² + b·x + c ⇒ a·(x + m)² + n

Where;

m = b/(2·a),

n = c - (b²/(4·a))

The method therefore works all the time

Always; Completing the square

Square root method

The square root method involves placing the square term of the equation on one side of the equation and the constant term on the other side

The square root method  works for equations that can be expressed in the form x² = b

The method  works sometimes

Sometimes; Square root method

Factoring by group

The method involves finding the common factors and grouping based on the common factors

The method only works when there are common factors

Sometimes; Factoring by group

Question 8

The  equation is 2·x² - 5·x = x - 4,

Writing the equation so that we have;

2·x² - 5·x - x + 4 = 0

2·x² - 6·x  + 4  = 0

x = (6 ± √((6² - 4× 2 × 4))/(2×2) =

Therefore;

x = 8/(2×2)  or x =  4/(2×2)

The numerators are 8 and 4

8

4

(b) The denominator is (2 × 2) = 4

(c) The two roots of the quadratic equation are;

x = 8/4 = 2 and x = 4/4 = 1

2

1

Question 6

The equation, x² - 16·x + 64 = 4

The left side of the equation can be factored as follows;

x² - 16·x + 64 = 4

x² - 8·x - 8·x + 64 = 4

(x² - 8·x) + (64 - 8·x) = 4

x·(x - 8) - 8·(x - 8) = 4

(x - 8)·(x - 8) = (x - 8)² = 4

Yes; (x - 8)² = 4

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The numbers of passengers that need to be booked to ensure the cruise line makes a profit, using a compound inequality is x ≥ 2,052 and x ≤ 2,462.

From the information given, we are told that the cruise ship needs to book at least 2,052 passengers to be profitable, but the most passengers the ship can accommodate is 2,462.

Learn x be the number of people that can be accommodated. Therefore, the model is x ≥ 2,052 and x ≤ 2,462.

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The true statements among the given options are as follows:
a. As many Canadians live south of 45 degrees N latitude as north of it.
c. In every province, the largest city is the provincial capital city.

a. The statement that as many Canadians live south of 45 degrees N latitude as north of it is true. Canada's population is distributed across various latitudes, with significant population centers in both northern and southern regions.
b. The statement that there are more people in Prince Edward Island than in all three territories (Yukon, NWT, and Nunavut) is false. Prince Edward Island has a smaller population compared to the combined population of the three territories. The territories have lower population densities due to their vast size and relatively smaller populations.
c. The statement that in every province, the largest city is the provincial capital city is true. In each Canadian province, the capital city serves as the administrative center and is usually the largest city in terms of population and economic significance.
d. The statement that four Canadians live in the top 10 cities and their suburbs for every one who lives anywhere else in the country is false. While Canada's major cities and their suburbs have significant populations, the ratio of population in the top 10 cities to the rest of the country is not as high as four to one. Canada has a diverse population distribution across urban, suburban, and rural areas throughout the country.

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The required correct answer is A. the five-number summary.

A box and whisker plot, often known as a box plot, shows a data set's five-number summary. The minimum, first quartile, median, third quartile, and maximum make up the five-number summary. A box is drawn from the first quartile to the third quartile in a box plot. At the median, a vertical line passes through the box.

The correct answer is A. the five-number summary. A boxplot is a graphical representation of the distribution of a set of data, and it provides information about the shape, spread, and skewness of the data. The five-number summary is used to construct a boxplot and includes the minimum value, first quartile (Q1), median, third quartile (Q3), and maximum value.

The boxplot uses these five values to display the range of the data and highlight any outliers or unusual observations. Knowing the five-number summary is sufficient to create a boxplot, while knowing all of the individual observations or the mean and standard deviation is not necessary.

Final answer: A. the five-number summary.

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Answer:

city breaking down on the camel's back

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

● 2.4 × 10^5

10^5 is 100000

● 2.4 × 100000

● 240 000

Answer:

C. 240,000

Step-by-step explanation:

This question is about using scientific notation.

In order to solve these types of questions, you move the decimal as many places as indicated by the Exponent ( which is given above the 10).

So in this example, we are given 2.4 x 10 ⁵. This means we would move the decimal 5 places. Since the exponent is positive, we will move the decimal to the right.

2 . 4         .

Which gives us option C. 240,000.

False. When conducting a cluster sample, it is typically preferable to have more heterogeneous clusters with fewer individuals.

This is due to the fact that when clusters are diverse, it is crucial to appropriately represent the population by capturing its diversity.

In such situations, the danger of sampling bias is increased by having fewer clusters with more individuals because a larger number of people from a single heterogeneous cluster would not fairly represent the overall community. Incorrect estimates and conclusions may result from this.

Having fewer clusters with more individuals, on the other hand, can assist raise the precision of the estimates when clusters are homogeneous by lowering the variance associated with sampling from a single cluster. In general, to achieve a precise representation of the population and to lessen the chance of sampling bias, the number of clusters and the size of each cluster should be balanced.

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Answer: Hope this helps you!

x = 4

Step-by-step explanation:

4+(x-3) = 2x-3

remove parentheses (equals to 4+1(x-3) = 2x-3 which is equal to the same equation without parentheses)

4+x-3 = 2x-3

Simply

1+x = 2x-3

subtract x from both sides

1 = 1x -3

add 3 to both sides

4 = 1x

divide by 1

4 = x

Brainliest?

1. The break-even point in unit sales and in dollar sales is 4,500 units and $324,000 respectively.

2. If the variable expenses per stove increase as a percentage of the selling price, will it result in a higher break-even point.

3. Income statements before and after changes are implement net income of $36,000 and $(28,000) respectively.

4. The company has to sell 5,401 units to achieve the target profit of $35,000 per month.

1. The break-even point in unit sales and dollar sales is computed as follows:

Break-Even Point in Unit Sales = Fixed Costs / Contribution Margin per Unit = $108,000 / ($50 - $32) = 4,500 units

Break-Even Point in Dollar Sales = Fixed Costs / Contribution Margin Ratio = $108,000 / ($50 / $18) = $324,000

2. If variable expenses per stove increase as a percentage of selling price, it will result in a higher break-even point. Since variable expenses would have a higher percentage of revenue, contribution margin would be lower, making it more challenging to cover fixed costs.

3. Present Income Statement

Sales (8,000*$50) $400,000

Less variable expenses (8,000*$32) (256,000)

Contribution Margin $144,000

Less fixed expenses 108,000

Net Income $36,000

Income Statement if Changes are Implemented

Sales (8,000*$45) $360,000

Less variable expenses (8,000*$35) (280,000)

Contribution Margin $80,000

Less fixed expenses 108,000

Net Loss $(28,000)

4. The contribution margin ratio is 36% ($18/$50). So, the sales revenue required to achieve the target profit is:

$35,000 / 0.36 = $97,222

The number of units required to be sold is:

$97,222 / $18 = 5,401 units

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Answer:

The second one the amount of monthly sales

Step-by-step explanation:

The 2000 is the total

Required initial value of the given expression dy/dt = y(y⁶) with y(0) = −7 is \(y = ±(7^6 * e^t)^{(1/6)}\)

To solve the initial value problem

\(dy/dt = y(y^6)\) with y(0) = -7, we can use separation of variables and integrate both sides of the equation.

Starting with the given differential equation:

\(dy/dt = y(y^6)\)

We can rewrite it as:

\(dy/y(y^6) = dt\)

Now, let's integrate both sides:

\(∫(dy/y(y^6)) = ∫dt\)

To integrate the left side, we can use substitution. Let u = y⁶, then du = 6y⁵ dy.

The equation becomes:

\(∫(1/u) du = ∫dt\\ln|u| = t + C_1\)

where \(C_1\) is the constant of integration.

Substituting back u = y⁶, we have:

\(ln|y^6| = t + C_1\)

Using the properties of logarithms, we can simplify further:

\(6ln|y| = t + C_1\)

Now, we need to solve for y. Taking the exponent of both sides:

\(e^{(6ln|y|)} = e^{(t + C_1)}\)

Using the properties of exponents, we get:

\(|y|^6 = e^t * e^{C_1}\)

Since \(e^{C_1}\) is a constant, we can combine it with the constant \(e^t\).

Let \(C_2 = e^{C_1}\), so \(|y|^6 = C_2 * e^t\)

Taking the sixth root of both sides and considering the absolute value \(|y| = (C_2 * e^t)^{(1/6)}\)

Since y(0) = -7, we can substitute t = 0 and solve for \(C_2\)

\(|-7| = (C_2 * e^0)^{(1/6)}\)

\(7 = C_2^{(1/6)} \\ C_2 = 7^6\)

Therefore, the solution to the initial value problem is \(|y| = (7^6 * e^t)^{(1/6)}\)

However, we need to consider both positive and negative values of y. Thus, the general solution is \(y = ±(7^6 * e^t)^{(1/6)}\)

So, the solution to the initial value problem dy/dt = y(y⁶) with y(0) = -7 is \(y = ±(7^6 * e^t)^{(1/6)}\)

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Correct question is "solve the initial value problem: dy dt = y(y⁶) with y(0) = −7"