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Related Questions
Please help me with this question.
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With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
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Why is Rome warmer than New York in January
Answers
Answer:
The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.
Explanation:
Brainliest?
Which of these forms due to the force of compression?
A) Anticline
B) Normal Fault
C) Strike-Slip Fault
D) Fault-Block Mountain
Answers
Answer:
anticline
Explanation:
hope u will understand
Answer:
Got it right on edge 2020
Explanation:
anticline
I need helppp
What is the force applied to the small piston,f,in Lb that is required to deliver a working force,F, of 1000 lb? The area of the small piston,a, is 0.1963 sq in. and the area of the large piston,A, is 6.28 sq in.
Answers
The area of the small piston, a, is 0.1963 sq in. and the area of the large piston, A, is 6.28 sq in. The force applied to the small piston (f)= 31.21 lb that is required to deliver a working force (F)= 1000 lb
What is force?Force is a physical quantity that means if some kind of external or internal affair is happen on a object and the object is move a bit that means a force is act on it. Its a vector quantity.
How can we calculate the force?To calculate the force of the small piston f we are using the formula,
p=P
Or, f/a=F/A
Here we are given,
a= The area of the small piston = 0.1963 sq in
A= The area of the big piston = 6.28 sq in.
F= The force of the big piston = 1000 lb.
We have to calculate the force of the small piston = f
Now we put the values in above equation we get,
f / a = F / A
Or, f = a F/A
Or, f = \(\frac{0.1963 \times 1000}{6.28}\)
Or, f = 31.21 lb
Now from the calculation we can say that, The force applied to the small piston (f)= 31.21 lb
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The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x direction. A golfer hits his tee shot a distance of 300.0 m, corresponding to a displacement of r1 = 300.0 mi and then hits his second shot 189.0 m corresponding to a displacement of r2 = 172.0 mi + 80.3 mj. What is the final displacement of the golf ball from the tee? Give your answer as a resultant vector that incorporates horizontal and vertical components.The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x direction. A golfer hits his tee shot a distance of 300.0 m, corresponding to a displacement Δr⃗ 1=300.0miˆ,and hits his second shot 189.0 m with a displacement Δr⃗ 2=172.0miˆ+80.3mjˆ.What is the final displacement of the golf ball from the tee?
Answers
Answer:
(472i + 80.3j) m
Explanation:
Given the following :
Distance of tee shot = 300m
Distance of second shot = 189.0 m
Displacement r1 of tee shot :
r1 = 300 mi
Displacement r2 of second shot :
r2 = 172.0 mi + 80.3 mj
The final displacement of the golf ball from the tee:
r_final = r1 + r2
r_final = (300i)m + (172.0i + 80.3j) m
r_final = (300 + 172)i m + 80.3j m
r_final = (472i + 80.3j) m
how many males are color blind one in 50 1 and 10 one hundred one and 12
Answers
One in twelve males have color blindness whereas One in two-hundred females have color blindness. Thus, Option D is correct.
Color blindness is the ability to distinguish different colors. It is hard to differentiate the colors between the same color family. A person with color blindness can not able to see red and green, and can able to see grey, black, and white. It is often inherited.
A person with color blindness can not able to differentiate the colors between red and green. There are three types of color blindness they are Deuteranomaly (difficulty with red-green color blindness and it makes green look redder), Protanomaly(red look greener), Protanopia, and deuteranopia (difficulty in identifying red and green). It is cured by using proper contact lenses.
Thus, One in twelve males has color blindness. Hence, the ideal solution is option D.
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which quanities are scalars
Answers
Answer:
they are quantities with magnitude without direction e.g weight,
i have no question d d d d
Answers
Answer:
okay
Explanation:
why don't you have any question in this app?
In 1974 a large area of the surface of Mercury was photographed from varying distances and revealed cratering similar in degree to the Moon.
Answers
Landforms on surface of Mercury suggest that its crust may have shrunk. They are lobate scarps, which are long, sinuous cliffs.
As a result of collisions with meteoroids and comets, Mercury's surface bears similarities to the Moon of Earth. Even with the planet's close proximity to the Sun and its severe temperature changes, people may theoretically walk on its surface. Due to its sluggish rotation, Mercury takes 59 Earth days to complete one full rotation. Huge escarpments up to three kilometers high and hundreds of kilometers long can be found on Mercury's surface. Mercury contains a lot of craters, yet it also has areas with comparatively calm plains. Messenger examined Mercury's surface composition using X-ray fluorescence spectra. It discovered a high magnesium to silicon ratio and low calcium and aluminum to silicon ratios, indicating that the crust was not feldspar-rich like that of the Moon.
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How many shots does one get when he fouls a shooter? (basketball)
Answers
Answer:
Depends on where he was fouled
If it is beyond the 3 pt line, then it is 3
If it is within the 2 pt line, then it is 2
I hope that helps :)
Explanation:
Plz mark B R A I N L I E S T
A child at the beach digs a hole in the sand and, using a
pail, fills it with water having a mass of 1.20 kg. The mo-
lar mass of water is 18.0 g/mol. (a) Find the number of
water molecules in this pail of water. (b) Suppose the
quantity of water on the Earth is 1.32 1021 kg and re-
mains constant. How many of the water molecules in
this pail of water were likely to have been in an equal
quantity of water that once filled a particular claw print
left by a dinosaur?
Answers
Answer:
suppose the
quantity of water on the earth is 1.32 1021 kg and remains constant
the
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
Answers
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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Which exerts a greater pressure, a force of 2001
acting on 1.0 m², or the same force acting on 2.0m2
Answers
Answer:
the same force acting on 1.0m2
Explanation:
P1 Pressure=force/area =2001/1=2001 N/m2
& while P2 =2001/2=1000.5 N/m2
the pressure is inversely proportional with Area
P=F/A
If Sally could drive a Jetson's flying car at a constant speed of 530.0 km/hr across oceans and space, approximately how long (in years) would she take to drive to a solar system object 10.0 AU away
Answers
24 hours in a day...
365 days in a year...
If you are planning on a return trip plan on your 5 to 6x great grandchildren picking you up at the space port.
Three blocks are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box of mass M. There is friction between the surfaces of blocks 2M and 3M so the three blocks accelerate together to the right.
Which block has the smallest net force acting on it?
A) M
B) 2M
C) 3M
D) The net force is the same for all three blocks Submit
Answers
Answer:
A) M
Explanation:
The three blocks are set in series on a horizontal frictionless surface, whose mutual contact accelerates all system to the same value due to internal forces as response to external force exerted on the box of mass M (Newton's Third Law). Let be F the external force, and F' and F'' the internal forces between boxes of masses M and 2M, as well as between boxes of masses 2M and 3M. The equations of equilibrium of each box are described below:
Box with mass M
\(\Sigma F = F - F' = M\cdot a\)
Box with mass 2M
\(\Sigma F = F' - F'' = 2\cdot M \cdot a\)
Box with mass 3M
\(\Sigma F = F'' = 3\cdot M \cdot a\)
On the third equation, acceleration can be modelled in terms of F'':
\(a = \frac{F''}{3\cdot M}\)
An expression for F' can be deducted from the second equation by replacing F'' and clearing the respective variable.
\(F' = 2\cdot M \cdot a + F''\)
\(F' = 2\cdot M \cdot \left(\frac{F''}{3\cdot M} \right) + F''\)
\(F' = \frac{5}{3}\cdot F''\)
Finally, F'' can be calculated in terms of the external force by replacing F' on the first equation:
\(F - \frac{5}{3}\cdot F'' = M \cdot \left(\frac{F''}{3\cdot M} \right)\)
\(F = \frac{5}{3} \cdot F'' + \frac{1}{3}\cdot F''\)
\(F = 2\cdot F''\)
\(F'' = \frac{1}{2}\cdot F\)
Afterwards, F' as function of the external force can be obtained by direct substitution:
\(F' = \frac{5}{6}\cdot F\)
The net forces of each block are now calculated:
Box with mass M
\(M\cdot a = F - \frac{5}{6}\cdot F\)
\(M\cdot a = \frac{1}{6}\cdot F\)
Box with mass 2M
\(2\cdot M\cdot a = \frac{5}{6}\cdot F - \frac{1}{2}\cdot F\)
\(2\cdot M \cdot a = \frac{1}{3}\cdot F\)
Box with mass 3M
\(3\cdot M \cdot a = \frac{1}{2}\cdot F\)
As a conclusion, the box with mass M experiments the smallest net force acting on it, which corresponds with answer A.
A glider of length 12.4 cm moves on an air track with
constant acceleration (Fig P2.31). A time interval of 0.628 s
elapses between the moment when its front end passes a
fixed point A along the track and the moment when its
back end passes this point. Next, a time interval of 1.39 s
elapses between the moment when the back end of the
glider passes the point A and the moment when the front
end of the glider passes a second point B farther down the
track. After that, an additional 0.431 s elapses until the
back end of the glider passes point B. (a) Find the average
speed of the glider as it passes point A. (b) Find the acceleration
of the glider. (c) Explain how you can compute the
acceleration without knowing
the distance between points A
and B.
Answers
\(19.7cm/s and 4.70 cm/s^2\) are the average speed and acceleration of the glider.
(a) As the glider's front end crosses point A, start a timer at t=0. The instantaneous speed at t=0.314s, halfway through the time interval, is \(12.4cm/(0.628s)=19.7cm/s\), which equals the glider's average speed for the interval between t=0 and t=0.628s.
(b) The instantaneous speed at the point \(t=(2.02+2.45)/2=2.23s\). is equal to \(12.4cm/(0.431s)=28.8cm/s\), which is the average speed of the glider for the time span between \(0.628+1.39=2.02s\) and \(0.628+1.39+0.431=2.45s\).
Now that we are aware of the velocities at two points, we can calculate the acceleration using the formula \([(28.8-19.7)cm/s]/[(2.23-0.314)s]=4.70cm/s2\).
(c) The average velocity over a predetermined period of time is determined using the glider's length rather than the distance between points A and B.
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What causes an object to slowdown or speed up
Answers
Answer:
A force can speed up or slow down an object. A force can change the direction in which an object is moving. A bigger force on an object will produce a bigger change in the motion. A heavier object requires a larger force than a lighter object in order to undergo the same change in motion.
Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticable, but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of 668 km and traveled a distance of 3180 km in 4.81 h. (a) What was the speed (in m/s) of the wave
Answers
Answer:
215.5 m/s
Explanation:
Given that:
the wavelength λ = 668 km
distance (d) = 3180 km
time t = 4.81 hr
\(a) speed (v) =\dfrac{distance}{time}\)
\(speed (v) =\dfrac{3180}{4.1}\)
\(speed (v) =775.61 \ km/h\)
\(speed (v) =(\dfrac{775.61\times 1000 }{3600}) \ m/s\)
\(speed(v) = 215.5 \ m/s\)
The frequency is:
\(f = \dfrac{v}{\lambda}\)
\(f = \dfrac{215.5 }{668 \times 1000}\)
\(f = 3.226 \times 10^{-4} \ Hz\)
c)
The period:
\(T = \dfrac{1}{f}\)
\(T = \dfrac{1}{3.226 \times 10^{-4}}\)
T = 3099.8 seconds
5 When a salmon swims up a river to breed, it often has to jump up waterfalls. Fig. 3.1 shows a salmon jumping above the surface of the water. On this occasion the salmon falls back down into the river. waterfall Fig. 3.1 river salmon The salmon has a mass of 2.0 kg. (a) The salmon leaves the water vertically with a kinetic energy of 16.2J. (i) Calculate the speed of the salmon as it leaves the water.
speed=
Answers
Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.
Thus, A fundamental idea in physics known as kinetic energy quantifies the work done by an object as a result of its motion. It is essential to our comprehension of many commonplace actions like walking, jumping, and throwing as well as more complicated events like falling.
We shall examine the definition, units of measurement, examples, and transformations of the notion of kinetic energy in this article. Additionally, we will develop the kinetic energy equation and look at how it relates to other types of energy.
We'll also look at the many kinds of kinetic energy and talk about the difference between kinetic and potential energy.
Thus, Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.
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Please help me out! I will pay real money to whoever solves this
Answers
Answer:
I KNOW THE ANSWER IT WILL COST 30$
Explanation:
Why do people calculate net force and make force diagrams?
O It allows us to calculate speed of an object
It allows us to predict the mass of objects
It allows us to predict motion and changes in motion
It allows us to calculate mass and weight
Answers
I think.
What are the characteristics of a realistic fiction story?
Answers
The fictional people and circumstances in realistic literature are meant to represent our society and reality. Growing up and facing personal and societal issues are the main topics.
Which is better, fiction or nonfiction?In a word, the primary distinction between fiction and non-fiction is that fiction is the product of imagination, whereas non-fiction is entirely founded on facts and truth. To better grasp the two genres, let's now get in-depth with them.
Describe what fiction is.While it may be based on a factual tale or circumstance, fiction is literature that was formed from the author's imagination and is not meant to be taken seriously as truth. Novels, short stories, and novellas are examples of literature in the fiction category.
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A light year is the amount of time it takes for light from the Sun to reach the Earth.
True
False
Answers
A cheetah runs at a constant velocity of 7 m/s. What is it’s acceleration in m/s/s
PLEASE HELP
Answers
Answer:
0 m/s²
Explanation:
Acceleration is the change in velocity over change in time. If the velocity is constant, then the acceleration is 0.
Nuclear power is generated by a. calcium enrichment. b. the conversion of heat into mass. c. fusion of uranium. d. heating water to high-pressure steam that drives a turbine.
Answers
Nuclear power is generated by heating water to high-pressure steam that drives a turbine. It is a main source of energy.
What is nuclear energy?Nuclear energy refers to the different sources of energy that depend on the properties of atomic nuclei.
The main types of nuclear energy can be divided into nuclear fusion and nuclear fission.
Nowadays, nuclear plants around the world use nuclear fission to produce a huge amount of energy.
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To whom does the vha provide care for today ?
Answers
Answer:
The Veterans Health Administration (VHA) is the largest integrated health
care system in the United States, providing care at 1,255 health care
facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care
of varying complexity ( VHA outpatient clinics) to over 9 million Veterans
enrolled in the VA .
The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the elevator, if upward is the positive direction. Write the numerical value only with 2 decimal places. Do not write the unit. If the acceleration is negative (downward) include the negative sign in your answer.
Answers
Answer: 1
Explanation:
Given
Tension is the string \(T=44\ N\)
mass of object \(m=4\ kg\)
Tension is greater than the weight of the object i.e. elevator is moving upward
we can write
\(\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2\)
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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In Denver, children bring their old jack-o-lanterns to the top of a tower and compete for accuracy in hitting a target on the ground. Suppose that the tower is 9.0 m high and that the bull's-eye is a horizontal distance of 3.5 m from the launch point. If the pumpkin is thrown horizontally, what is the launch speed needed to hit the bull's-eye? m/s
Answers
The launch speed needed to hit the bull's-eye is 5.9 m/s. We can solve this problem by using the kinematic equations of motion.
We know that the pumpkin is thrown horizontally, which means its initial vertical velocity is zero. Therefore, we can use the following kinematic equation to solve for the initial horizontal velocity of the pumpkin:
Δx = v₀x t
where Δx is the horizontal distance traveled by the pumpkin (which is 3.5 m), v₀x is the initial horizontal velocity, and t is the time it takes for the pumpkin to reach the ground.
We can use the following kinematic equation to solve for the time it takes for the pumpkin to reach the ground:
Δy = v₀y t + 1/2 a t²
where Δy is the vertical distance traveled by the pumpkin (which is 9.0 m), v₀y is the initial vertical velocity (which is zero), a is the acceleration due to gravity (which is -9.8 m/s²), and t is the time it takes for the pumpkin to reach the ground.
Solving for t in the second equation, we get:
t = √(2Δy/a)
Substituting this expression for t into the first equation, we get:
Δx = v₀x √(2Δy/a)
Solving for v₀x, we get:
v₀x = Δx / √(2Δy/a)
Substituting the given values, we get:
v₀x = 3.5 m / √(2×9.0 m / 9.8 m/s²)
Simplifying this expression, we get:
v₀x = 5.9 m/s (rounded to one decimal place)
Therefore, the launch speed needed to hit the bull's-eye is 5.9 m/s.
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QUESTION #1:if there were no gravity a ball thrown upward at an angle would follow a straight-line path. Due to gravity, however, at the end of 1 s it is?a.) 5 m below the straight lineb.) 10 m below the straight linec.) 15 m below the straight lined.) 20 m below the straight line QUESTION #2:if there were no gravity a cannonball fired upward at an angle of 45 degrees would follow a straight-line path. Due to gravity, however, at the end of 3 s it is?a.) 5 m below the straight lineb.) 10 m below the straight linec.) 20 m below the straight lined.) more than 20 m below the straight line
Answers
Q1.
The acceleration of the gravity is 9.81 meters per second per second. Assuming is falling from rest then it will have fallen from the straig light approimately:
\(\begin{gathered} y=-\frac{1}{2}gt^2 \\ y=-\frac{1}{2}(9.81)(1)^2 \\ y=-4.905 \end{gathered}\)Therefore the answer is a.
Q2.
In this case the time is 3 s. then we have:
\(\begin{gathered} y=-\frac{1}{2}(9.81)(3)^2 \\ y=-44.145 \end{gathered}\)Therefore the answer is d.