Tides are strongest when the earth, moon and sun are in line.
What are tidal waves?A tidal wave is a periodically occurring shallow water wave brought on by the ocean's gravitational interactions with the Sun, Moon, and Earth. Despite the fact that tides have nothing to do with tsunamis, the phrase "tidal wave" is frequently used to describe them. A storm surge, storm flood, tidal surge, or storm tide is a tsunami-like occurrence of rising water that frequently occurs along coastlines during low-pressure weather systems like cyclones. It is calculated as the increase in water level over the average tidal level and excludes waves.
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Playing shortstop, you pick up a ground ball and throw it to second base. The ball is thrown horizontally with a speed of 13 m/s directly toward point A. When the ball reaches the second baseman 0,44 s later, it is caught at point B. How far were you from the second baseman? What is the distance of the vertical drop, the distance between point A and point B.
You were approximately 5.72 meters away from the second baseman. The vertical drop or distance between point A and point B was approximately 0.4576 meters.
To determine the distance between you (the shortstop) and the second baseman, we can use the formula for horizontal distance (d) traveled by an object moving at a constant horizontal velocity:
d = v * t
where:
- d is the horizontal distance traveled,
- v is the horizontal velocity of the ball,
- t is the time taken.
Given that the horizontal velocity (v) is 13 m/s and the time (t) is 0.44 s, we can calculate the horizontal distance (d) as follows:
d = 13 m/s * 0.44 s = 5.72 meters
So, you were approximately 5.72 meters away from the second baseman.
To find the vertical drop or the distance between point A and point B, we need to calculate the vertical component of the ball's motion. Since the ball is thrown horizontally, it will experience a constant vertical acceleration due to gravity.
The formula to calculate the distance (d) traveled vertically in free fall is:
d = 1/2 * g * t²
where:
- d is the vertical distance traveled,
- g is the acceleration due to gravity (approximately 9.8 m/s²),
- t is the time taken.
Given that the time (t) is 0.44 s, we can calculate the vertical distance (d) as follows:
d = 1/2 * 9.8 m/s² * (0.44 s)² = 0.4576 meters
So, the vertical drop or the distance between point A and point B is approximately 0.4576 meters.
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Electric charge can be built up on what material in the form of static electricity?
A. insulators
B. conductors
C. Semiconductors
D.Superconductors
Three capacitors are joined as represented in the figure (parallel series), C1 = 7.8 ?F, C2 = 13.2 ?F, C3 = 4.9 ?F. The battery has a voltage of 12 V
C1 = 7.8 ?F
C2 = 13.2 ?F
C3 = 4.9 ?F
50% Part (a) Calculate the numerical value of the total capacitance of the circuit, in microfarads.
50% Part (b) Calculate the numerical value of the total energy stored in the capacitors U, in microjoules.
Part (a) To find the total capacitance of the circuit, we need to use the formula for capacitors in parallel and series. In this case, the accelerationare in both parallel and series, so we need to break it down into steps.
First, we can find the equivalent capacitance of C1 and C2 in parallel: C12 = (C1 x C2) / (C1 + C2) = (7.8 ?F x 13.2 ?F) / (7.8 ?F + 13.2 ?F) = 4.96 ?F.
Then, we can find the total capacitance of C12 and C3 in series: C123 = 1 / ((1 / C12) + (1 / C3)) = 1 / ((1 / 4.96 ?F) + (1 / 4.9 ?F)) = 2.45 ?F.
Therefore, the total capacitance of the circuit is 2.45 ?F.
Part (b) To find the total energy stored in the capacitors, we can use the formula U = 0.5 x C x V^2, where U is the energy stored, C is the capacitance, and V is the voltage.
For C1, U1 = 0.5 x 7.8 ?F x (12 V)^2 = 673.92 ?J.
For C2, U2 = 0.5 x 13.2 ?F x (12 V)^2 = 1,411.2 ?J.
For C3, U3 = 0.5 x 4.9 ?F x (12 V)^2 = 352.8 ?J.
The total energy stored in the capacitors is U = U1 + U2 + U3 = 2,437.92 ?J.
Therefore, the numerical value of the total capacitance of the circuit is 2.45 ?F and the numerical value of the total energy stored in the capacitors is 2,437.92 ?J.
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PLSS HELP
A car collides with a wall. Compare the forces exerted by the car on the wall and by the wall on the car.
According to Newton's third law of motion the force exerted by the car on the wall and the force by the wall on the car are equal and opposite. But there will be no displacement for the wall.
What is collision?Collison is a short time force acting between two objects. There are both elastic and inelastic collision. In elastic collision, the kinetic energy and momentum of the colliding system is conserved whereas in inelastic collision, the kinetic energy is not conserved.
For any type of collision, we can apply Newton's third law of motion. This law states that, for every action there is an equal and opposite reaction. Therefore, in a collision, the force exerted by each object will be equal and opposite in direction.
Therefore, the force exerted by the car on the wall and the force by the wall on the car are equal and opposite. But there will be no displacement for the wall.
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Determine the kinetic energy of a 1000 kg roller coaster car that is moving with speed of 40.0 m/s
Answer:
KE=800,000
Explanation:
The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2
so 1000 is the mass and 40 is the velocity
KE=0.5*1000*40^2
KE=0.5*1,000*1,600
KE=800,000 Joules
Two identical charges, both 30 μμc, are located on the y-axis at y=5 cm and y=-5 cm. What is the magnitude of the electric field on the x-axis at x=12 cm? round your answer to 3 significant digits.
We will see that the electric field in that point is:
Ex = 31.598 N/μc
How to find the electric field?
Remember that for a charge Q, the electric field is given by:
\(E = k*\frac{Q}{r^2} (n_x, n_y)\)
Where the versor is in the direction of r, k is a constant, and r is the distance to the charge.
In this case, we have two charges, one at (0cm, 5cm) and the other at (0cm, -5cm). Because of the symmetry on the y-axis, we know that the y-component will be canceled, so we only have the x-component.
\(E_x = k*(\frac{30 \mu C}{(12cm)^2 + (5cm)^2} + \frac{30 \mu C}{(12cm)^2 + (-5cm)^2} )\\\\E_x = k*(\frac{60 \mu C}{169cm^2})\)
Now we know that the value of k, the Coulomb's constant is:
k = 8,9*10^9 N*m^2/C^2
Writing this in cm and μc (multiplying by 10^4 and dividing by 10^12 we get)
k = 8.9*10^9*(10^4*10^-12) N*cm^2/μc^2
k = 8.9*10 N*cm^2/μc^2
Now we use that in our equation:
\(E_x = (8.9*10 N*cm^2/\mu c^2)*(\frac{60 \mu C}{169cm^2}) = 31.598N/\mu c\)
This is the electric field on the point (12cm, 0cm).
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how does an atom change if all of its electons are removed
a. the atom’s volume increases
b. the atom’s mass increases
c. the atom becomes positively charged
d. the atom becomes negatively charged
Answer:
c
Explanation:
Have a nice day
answer is c
(c)
Explanation:
is (c)
it is c
Write one claim about this graph
Answer: Carbon dioxide is the primary greenhouse gas emitted through human activities. In 2019, accounted for about 80 percent of all U.S. greenhouse gas emissions from human activities. Carbon dioxide is naturally present in the atmosphere as part of the Earth's carbon cycle (the natural circulation of carbon among the atmosphere, oceans, soil, plants, and animals. Human activities are altering the carbon cycle–both by adding more to the atmosphere, and by influencing the ability of natural sinks, like forests and soils, to remove and store from the atmosphere. While emissions come from a variety of natural sources, human-related emissions are responsible for the increase
Explanation:
the paper dielectric in a paper-and-foil capacitor is 8.10*10^-2 mm thick. it's dielectric constant is 2.10, and it's dielectric strength is 50.0 MV/m. assume that the geometry is that of a parallel-plate capacitor, with the metal foil serving as the plates.
Part A: What area of each plate is required for for a 0.300 uF capacitor? In m^2
Part B: If the electric field in the paper is not to exceed one-half the dielectric strength, what is the maximum potential difference that can be applied across the compactor? In V
a. Part A: The area of each plate is required for for a 0.300 uF capacitor is 1.56 × \(10^{-4}\) m².
b. Part B: If the electric field in the paper is not to exceed one-half the dielectric strength, the maximum potential difference that can be applied across the compactor is 2025 V.
To find the area of each plate required for a 0.300 uF capacitor, use the formula:
C = ε₀εrA/d
where C is the capacitance, ε₀ is the vacuum permittivity (8.85 × \(10^{-12}\) F/m), εr is the relative permittivity (dielectric constant), A is the area, and d is the distance between the plates. In this case,
C = 0.300 uF
εr = 2.10
d = 8.10 × \(10^{-5}\) m.
Rearrange the formula to find A:
A = Cd / (ε₀εr)
A = (0.300 × \(10^{-6}\) F)(8.10 × \(10^{-5}\) m) / (8.85 × \(10^{-12}\) F/m × 2.10)
A ≈ 1.56 × \(10^{-4}\) m²
Thus, the area of each plate required for a 0.300 uF capacitor is approximately 1.56 × \(10^{-4}\) m².
To find the maximum potential difference that can be applied across the capacitor, use the formula:
V = Ed
where E is the electric field and d is the distance between the plates. In this case, E is half the dielectric strength (50.0 MV/m / 2 = 25.0 MV/m), and d = 8.10 × \(10^{-5}\) m:
V = (25.0 × 10^6 V/m)(8.10 × 10^-5 m)
V ≈ 2025 V
Thus, the maximum potential difference that can be applied across the capacitor without exceeding one-half the dielectric strength is approximately 2025 V.
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Help!
6. Assume a position vs time graph displays a horizontal line, what does this represent?
A. Constant Velocity
B. 0 Acceleration
if it is horizontal line, that means position is same but time is increasing.
velocity=0 . particle is not even moving
The chart shows data for four moving objects. Which object has the greatest acceleration?
Answer:
Y
Explanation:
Acceleration = (v-u)/t
W = (29-11)/6 = 3
X = (34-10)/12 = 2
Y = (40-12)/7 = 4
Z = (28-20)/8 = 1
So the answer is Y = 4.
Hope this will help. Please mark me brainliest.
assume obj1 and obj2 are object references. which of the following best describes when the expression obj1 == obj2 is true?
The reference equality is tested using the == operator. True. If obj1 and obj2 refer to same object, then obj1 == obj2 is true. True. A String object cannot be changed.
What is a string, exactly?In programming, a string is a form of data that is used to data type rather than integers. Letters, numbers, symbols, and even spaces can all be found in a string, which is a collection of characters. In order for it to recognized as a string, it needs to be encapsulated in quotation marks.
Is string a datatype or an object?A string is frequently implemented as just an array data structure of bits (or words) that records a sequence of elements, usually characters, using some text encoding. Typically, a string is considered to be a data type.
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Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
a. -0.321 T
b. -0.653 T
c. -0.231 T
d. -0.293 T
Answer:
its most definitely c. trust me
Explanation:
When is the object traveling at a constant velocity?
A
B
C
D
It is moving at a constant velocity the entire time
d
I think the most common way of doing it was for the first
1.
How do the individual forces compare when the rider experiences a normal
sensation of weight? What is the acceleration value when this occurs?
Answer:
The rider experiences weight or does not experience weight depends upon the direction of the elevator in which it moves and its acceleration.
Explanation:
Consider the mass of a rider as m. So its actual weight is mg and it acts vertically downward. The apparent weight of the rider is depended on the acceleration of the elevator and its direction of movement.
When elevator moves with a constant speed i.e. its acceleration is zero, the apparent weight of the rider is equal to the actual weight. Thus the rider's sensation is normal.
If the elevator is moving upward with an acceleration a, then the apparent weight of the rider will be more and the rider will experience an increase in weight or the sensation is heavy.
Or when the elevator moves downward with an acceleration a, the apparent weight of the rider is less. And the rider sensation is lighter.
The acceleration will become "0 (zero)". A further solution to the question is provided below.
Individual pressures neutralize or negate each other out if somehow the riding experiences stable weight, implying that perhaps the rider's cumulative acceleration will be zero,Now,
→ \(mg= W+F\)
or,
→ \(g= a+g\)
then,
→ \(a =0\)
This means that the rider isn't moving. Thus the response above is appropriate.
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determine the moment of inertia of a 5.00 kg sphere of radius 0.741 m when the axis of rotation is through its center.
The moment of inertia of a 5.00 kg sphere of radius 0.741 m when the axis of rotation is through its center is 0.777 kg·m².
The moment of inertia of an object is a measure of its resistance to rotational motion around a given axis. For a solid sphere rotating around an axis through its center, the moment of inertia can be calculated using the formula I = (2/5) * m * r², where I is the moment of inertia, m is the mass of the sphere, and r is the radius of the sphere.
Applying the given values, we have I = (2/5) * 5.00 kg * (0.741 m)². Simplifying the equation yields I = 0.777 kg·m².
This means that when the sphere rotates around an axis passing through its center, it has a moment of inertia of 0.777 kg·m². The moment of inertia quantifies how the mass is distributed around the axis of rotation, and a larger moment of inertia indicates greater resistance to changes in rotational motion.
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A ball is launched from a slingshot. As the ball travels along its trajectory, what force(s) are acting on it? Select all that apply.
Group of answer choices
Force of air and gravitational force are acting on the ball when launched from the slingshot.
When a ball is launched from a slingshot, during its travel force of air as well as gravitational force are acting on the ball because there is air which moves opposite to the motion of a ball whereas the force of gravity attracts the ball downward.
The force of air slows down the motion of the ball while on the other hand, the force of gravity brings the ball to the ground due to attraction. If these two forces are not present then the ball continues its motion forever so we can conclude that force of air and force of gravity are acting on the ball when launched from the slingshot.
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An automobile cooling system holds 16 l of water. the specific heat of water is 4186 j/kg⋅c∘. How much heat does it absorb if its temperature rises from 17C to 87C?
The amount of heat that the water absorbs in cooling system of the automobile is 4688320 Joules.
The water holding capacity of the cooling system of the automobile s 16L.
The density of water is 1000Kg/m³. The specific heat of water is 4.186 J/KgC°.
The temperature of the water rises to 87°C from 17°C.
Now, the amount of heat that the water absorbs is,
Q = mcT
Where,
Q is the heat absorbed,
m is the mass of the water,
c is the specific heat of water,
T is the change in temperature of water.
Putting values,
Q = 1000 x 16 x 4.186 x 70
Q = 4688320 Joules.
So, the amount of heat absorbed is 4688320 Joules.
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When the apple fall towards tje earth tje earth move up to meet the apple.Os it true.If yes why is the earth motion not noticeable
Answer:
Explanation:
It was Newton's genius that saw that it was true. He also realized that if it was true, the motion the earth experience would be unmeasurably small, especially in his time. Their instruments were just not good enough: crude and too approximate would be better descriptions.
Suppose a spaceship heading straight towards the Earth at 0.750 c can shoot a canister at 0.500 c relative to the ship.
What is the velocity of the canister relative to the Earth,
(a) if it is shot directly at the Earth?
(b) if it is shot directly away from the Earth?
The velocity of the canister relative to the Earth when shot directly away from the Earth is approximately 0.9091c.
We'll be using the terms "spaceship," "velocity," "canister," "relative to the ship," and "relative to the Earth" in our answer. We'll also be using the relativistic velocity addition formula: (u + v) / (1 + uv/c^2).
(a) If the canister is shot directly at the Earth, we have:
u = 0.750c (velocity of spaceship relative to Earth)
v = -0.500c (velocity of canister relative to spaceship, negative sign because it's shot towards Earth)
c = speed of light
Using the relativistic velocity addition formula:
(0.750c - 0.500c) / (1 - 0.750 * -0.500) = (0.250c) / (1 + 0.375) = 0.250c / 1.375 ≈ 0.1818c
So, the velocity of the canister relative to the Earth when shot directly at the Earth is approximately 0.1818c.
(b) If the canister is shot directly away from the Earth, we have:
u = 0.750c (velocity of spaceship relative to Earth)
v = 0.500c (velocity of canister relative to spaceship)
Using the relativistic velocity addition formula:
(0.750c + 0.500c) / (1 + 0.750 * 0.500) = (1.250c) / (1 + 0.375) = 1.250c / 1.375 ≈ 0.9091c
So, the velocity of the canister relative to the Earth when shot directly away from the Earth is approximately 0.9091c.
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Steel bars each of length 3m at 28°C are to be used for constructing a rail line. If the linear expansivity of steel is 1.0 x 10^-5K^-1, what is the safety gap that must be left between successive bars, if the highest temperature expected is 40°C?
Answer:
The formula for calculating the length change due to a temperature change is:
ΔL = α * L * ΔT
where α is the linear expansivity, L is the original length of the bar, and ΔT is the change in temperature.
So in this case, the length change of each bar would be:
ΔL = 1.0 x 10^-5 K^-1 * 3m * (40°C - 28°C)
Converting the temperatures to Kelvin (28°C = 28 + 273 = 301 K and 40°C = 40 + 273 = 313 K), we get:
ΔL = 1.0 x 10^-5 K^-1 * 3m * (313 K - 301 K)
ΔL = 1.0 x 10^-5 * 3 * 12
ΔL = 0.00036 m
So each bar will increase in length by approximately 0.00036 meters when the temperature changes from 28°C to 40°C. To allow for this increase in length, a safety gap of 0.00036 meters should be left between each bar.
A 9.0-g bullet travels at 720 km/h. If at a particular time the bullet's position can be specified to within ±±0.10 mm, what is the uncertainty in the velocity of the bullet?A : 6.6 x 10-34 m/sB : None of the choices are correct.C : 1.1 x 10-34 m/sD : 7.4 x 10-28 m/sE : 1.2 x 10-28 m/s
Answer:
E
Explanation:
the uncertainty in the velocity of the bullet is 5.87 × 10^-29 m/s, which corresponds to answer choice E.
1. a uniform pressure of 7.0 X 10^5 N/m^2 is applied to all six sides of a copper cube. what is the percentage change in volume of the cube? (for copper B= 14x 10^10 N/m^2
B) How large a force is necessary to stretch a 2.0mm diameter steel wire by 1%? ( Y= 2.0x10^11 N/m^2) Hint: the cross sectional area of a circular wire is pir^2
A. The percentage change in volume of the copper cube is 3%.
B. The force necessary to stretch a 2.0 mm diameter steel wire by 1% is approximately 25.1 N.
A.
To find the percentage change in volume of the copper cube, we can use the formula:
ΔV/V = 3BΔP/Β
Where ΔV/V is the fractional change in volume,
B is the bulk modulus of the material (given as \(14\times10^{10}\: N/m^2\) for copper), and ΔP is the change in pressure.
Since the pressure is the same on all six sides of the cube,
ΔP = \(7.0\times10^5 \:N/m^2.\)
Substituting the values into the formula, we get:
ΔV/V = \(3(14\times10^{10}\: N/m^2)(7.0\times10^5 N/m^2)/(14\times10^{10}\: N/m^2)\)
ΔV/V = 0.03 or 3%
B.
To find the force necessary to stretch a 2.0 mm diameter steel wire by 1%, we can use the formula:
F = AΔL Y/L
Where F is the force required,
A is the cross-sectional area of the wire (given as πr^2, where r = 1.0 mm = 0.001 m),
ΔL is the change in length (given as 1% of the original length, or 0.01 x 2.0 mm = 0.02 mm = 0.00002 m),
Y is the Young's modulus of the material (given as 2.0x10^11 N/m^2), and L is the original length of the wire (which we will assume to be 1 meter for simplicity).
Substituting the values into the formula, we get:
F = \(\pi(0.001 m)^2 (0.00002 \:m) (2.0\times10^{11}\: N/m^2) / 1 m\)
F ≈ 25.1 N
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what type of quantity is measured by the following units: joules, volts, ev
Joules, volts, and electron volts (eV) are units used to measure different types of physical quantities related to energy and electricity.
Joules (J) measure energy, which can be in various forms such as potential, kinetic, or thermal energy. It is a derived unit in the International System of Units (SI) and is defined as the amount of work done when a force of one newton displaces an object by one meter in the direction of the force.Volts (V) measure electric potential difference, also known as voltage, between two points in an electric circuit. It indicates the amount of work needed to move a unit of electric charge between these points. One volt is equivalent to one joule of energy per coulomb of charge.Electron volts (eV) measure energy on a smaller scale, typically at the atomic or subatomic level. It is the amount of kinetic energy gained or lost by a single electron when it is accelerated through an electric potential difference of one volt. It is commonly used in particle physics and quantum mechanics to express the energies of particles, atoms, and other small-scale phenomena.In summary, joules measure energy, volts measure electric potential difference, and electron volts measure energy on a smaller scale, particularly for atomic and subatomic particles.
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draw a block diagram of the components for an elevator-position control. indicate how you would measure the position of the elevator car. consider a combined coarse and fine measurement system. what accuracies do you suggest for each sensor?
In feedback control, the variable being controlled is measured and compared with a target value.
what accuracies do you suggest for each sensor?
The accuracy of the sensor is the maximum difference that will exist between the actual value (which must be measured by a primary or good secondary standard) and the indicated value at the output of the sensor. Again, the accuracy can be expressed either as a percentage of full scale or in absolute terms.For example, if a pressure sensor with a full scale range of 100 psi reports a pressure of 76 psi – and the actual pressure is 75 psi, then the error is 1 psi, and when we divide this by the full scale and express it as a percentage, we say that accuracy (or error) of the sensor is 1%.For the classification of a force sensor in accuracy class 0.5, the temperature-induced drift of the zero signal over a temperture range of 10 ° C should be less than 0.5% of the characteristic value of the sensor. With a characteristic value of 1 mV/V (FS, "Full Scale"), this means a maximum drift of 0.005 mV/V/10°C.To learn more about sensor refers to:
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S_I_L_
_O_T_A_L
P_W_R
J_M_
S_E_D_
_A_S_N_
K_C_
Answer:
Football
Power
Jamm
Steady
Kick
If the strength of the magnetic field at B is 6 units, the strength of the magnetic field at A is _____.
A. 1.5 units
B. 0.75 units
C. 24 units
D. 10.6 units
Answer:
I think its c but am not quite sure
Explanation:
pls mark me as brainlist
Answer:
24 units
Explanation:
hope this helps :)
4. A truck travels a curve of radius 10 m at 18 km/hr on a force of 15000 N. What is the mass of the truck?
Answer:
The mass of the truck is 1500 Kg.
Explanation:
Given;F = 15000 NWe know that,
F = mg
g = acceleration due to gravity = 10m/s²m = F/g
m = 15000/10
m = 1500 Kg
m = 1500 KgThus, The mass of the truck is 1500 Kg.
What is the position and kind of image produced by the lens below?
Complete the ray diagram to support your answer.
A Sodium ion has a positive charge because it has
Answer:
This is because the 11 positive protons and 10 negative electrons end up with an overall charge of +1.
Explanation:
Answer:
One electron in it's outer shell