to get dry ice to the triple point

PLEASE HELP !!

A given substance that has a melting point of -7C and a boiling point of 59C exists as a liquid at room temperature conditions.

The states of matter refer to the separation of the molecules of a given material in certain temperature conditions.

The states of the matter are three and include the gaseous state, liquid state and solid-state.

In conclusion, a given substance that has a melting point of -7C and a boiling point of 59C exists as a liquid at room temperature conditions.

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Answer:

approximately 1 week

Explanation:

Hope this helps, feel free to give feedback

1 to 2 weeks but if they smell a litte more stink then usually you better get rid of them or they my make you sick. i got sick for old boiled egg from the school cafeteria a long time ago.

Explanation:

The set(s) of magnetically non-equivalent protons are found in (ch3)2chch2ch2cl is A. 3

The protons in a molecule are considered magnetically equivalent if they generate the same NMR signal. There are three types of magnetically non-equivalent protons in the compound (CH3)2CHCH2CH2Cl. The proton signals come from the various types of protons that are not chemically equivalent.

The chlorine and methyl groups have the same chemical environment in the molecule, with only the two adjacent CH2 groups presenting a distinct chemical environment. The protons on these groups are non-equivalent magnetically. In general, the number of non-equivalent protons depends on the number of different chemical environments present in the molecule.

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Cooperative binding of oxygen occurs for hemoglobin.

Cooperative binding refers to the process whereby binding of one molecule of oxygen results in more binding of oxygen molecules due to increased affinity of oxygen by the ligand.

Cooperative binding of oxygen occurs in hemoglobin.

In conclusion, cooperative binding enables hemoglobin to carry oxygen efficiently.

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The MOST accurate statement is: Substances with large specific heats resist temperature changes much more than those with low specific heats.

option C.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a one degree Celsius or Kelvin.

The specific heat of a substance is an intensive property, which means that it is independent of the amount of the substance present.

The larger the specific heat of a substance, the more heat energy is required to raise its temperature by a certain amount.

This means that substances with larger specific heats resist temperature changes much more than those with lower specific heats.

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Answer:

Dark matter slows down the expansion of the universe, while dark energy speeds it up

Explanation:

Answer:

S=O

Explanation:

The bond energies of the given compounds are:

O-O bond energy = 142 kJ/mol

O=O bond energy = 495 kJ/mol

O-F bond energy = 190 kJ/mol

S=O bond energy = 523 kJ/mol

Therefore, the S=O bond has the highest bond energy at 523 kJ/mol.

175 milliliters of the aqueous solution of lead nitrate are needed to obtain 12.0 grams of the salt.

To determine the volume of an aqueous solution of lead nitrate needed to obtain a certain amount of the salt, we can use the molarity (M) and the formula weight of the salt.

Pb(NO₃)₂

Pb: 207.2 g/mol (atomic mass of Pb)

N: 14.0 g/mol (atomic mass of N)

O: 16.0 g/mol (atomic mass of O)

Formula weight of Pb(NO₃)₂ = (207.2 g/mol) + 2 × [(14.0 g/mol) + 3 × (16.0 g/mol)]

Formula weight of Pb(NO₃)₂ = 331.2 g/mol

Amount of Pb(NO₃)₂ = Mass of salt / Formula weight of Pb(NO3)2

Amount of Pb(NO₃)₂ = 12.0 g / 331.2 g/mol

Amount of Pb(NO₃)₂ = 0.0362 mol

Molarity (M) = Moles of solute / Volume of solution (in liters)

The volume of solution (in liters) = Moles of solute / Molarity (M)

Volume of solution (in liters) = 0.0362 mol / 0.207 mol/L

The volume of solution (in liters) = 0.175 L

Volume of solution (in milliliters) = 0.175 L × (1000 mL/1 L)

The volume of solution (in milliliters) = 175 mL

Therefore, approximately 175 milliliters of the aqueous solution of lead nitrate are needed to obtain 12.0 grams of the salt.

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Answer:

2 significant sigures

Explanation:

Answer: 1 significant figure

Explanation:

What are significant figures?

Significant firgues refer to the numbers following a decimal point. When undergoing addition, subtraction, multiplication, or division, this is determined by the limiting term.

The limiting term is the number that has the least amount of numbers after the decimal point.

This makes 2.2 the limiting term. Whatever answer is reported after the numbers are multiplied together, it must be rounded to where there is only 1 number following the decimal point.

480 meters

hope this helped!

Answer:

ionic, covalent, and metallic.

Explanation:

A example of ionic=Table salt A example of covalent =Water (H2O) A example of metallic=Sodium

Answer:

Ionic bonding

Definition: An ionic bond is formed when valence electrons are transferred from one atom to the other to complete the outer electron shell.

Example: A typical ionically bonded material is NaCl

Covalent bonding

Definition: A covalent bond is formed when the valence electrons from one atom are shared between two or more particular atoms.

Example: Many compounds have covalent bonding, such as polymers. Nylon rope is an example of a material that is made up of polymers. Polymer structures typically are long chains of covalently bonded carbon and hydrogen atoms in various arrangements.

Metallic bond:

Definition: A metallic bond is formed when the valence electrons are not associated with a particular atom or ion, but exist as a "cloud" of electrons around the ion centers.

Example: In the real and imperfect world, most materials do not have pure metallic, pure covalent, or pure ionic bonding; they may have other types of bonding as well. For example, iron has predominantly metallic bonding, but some covalent bonding also occurs.

Answer:

D probably

Explanation:

Answer:

Value for K would be too small. Less AgCl would dissolve due to the common ion effect due to the presence of Cl- in the water.

Explanation:

Think of this through the lenses of a shifting problem. Cl- ions are a product in this situation and increasing its concentration would shift the reaction back to the solid AgCl. In this specific case, due to Cl- ions, AgCl would dissolve less to maintain equilibrium and as a result, the concentrations of Ag+ and Cl- ions would be lower than normal making a smaller K value.

In the solution of AgCl in tap water, the dissociation constant K has been decreased.

The dissolution of silver chloride in water results in the formation of silver ions and chloride ions.

The dissociation constant has been the amount of compound that has been dissociated into the constituent ions at equilibrium.

The dissociation constant has been dependent on the number of ions in the solution that has been present.

The common ion effect has been defined as the change in the dissociation constant for the compound with the presence of common ions in the solution.

The dissociation of AgCl in tap water has been resulted with presence of Cl ions in the solution. There has been early reach to the equilibrium in tap water.

Thus, with the solution of AgCl in tap water, the dissociation constant K has been decreased.

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ΔH° = -67.9 kJ

ΔS° = 536.7 J/K = 0.5367 kJ/K

ΔG° = -227.8 kJ

The spontaneity of this reaction dependent on T .

Given ,

Temperature = 25.0 °C=298K

ΔH°f(glucose) = - 1274.5 kJ/ mol

ΔH°f(C2H5OH) = -277.7 kJ/mol

ΔH°f(CO2) = -393.5 kJ/mol

S°(glucose) = 212.1 J/ K)

S°(C2H5OH) = 160.7 J/K

S°(CO2) = 213.7 J/K

The given equation is ,

C6H12O6(s) → 2 C2H5OH(l) + 2 CO2(g)

As we know ,

ΔH°= ΔH°(product ) - ΔH°(reactant )

ΔH° = 2*ΔH°f(C2H5OH) + 2ΔH°f(CO2) - ΔH°f(glucose)

ΔH° = 2*(-277.7 kJ) + 2*(-393.5 kJ) - (-1274.5 kJ)

ΔH° = -555.4 kJ + (-787 kJ) +1274.5 kJ)

ΔH° = -67.9 kj

As we know ,

ΔS°=ΔS°(product ) - ΔS°(reactant )

ΔS° = 2*S°(C2H5OH)  + 2*S°(CO2) - S°(glucose)

ΔS° = 2*(160.7 J/K) + 2(213.7 J/K) - 212.1 J/K

ΔS° = 321.4 + 427.4 J/K - 212.1 J/K

ΔS° = 536.7 J/K = 0.5367 kJ/K

As we know ,

ΔG° =ΔH° - T×ΔS°

ΔG° = -67.9 kJ - 298K * 0.5367 kJ/K

ΔG° = -227.8 kJ

Since ΔS° is positive and  ΔH° is negative, ΔG° will be negative.

A negative ΔG° means the reaction is spontaneous and it is dependent on T .

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All chemicals harm the environment. Therefore, the correct option is option A among all the given options.

Chemicals may contaminate the environment, including the food we consume, the water we drink, and the air we breathe. They may have infiltrated lakes and woods, wiping off fauna and altering the ecosystems. Not all chemicals are equally dangerous. Some dangerous substances are especially harmful to your health because of how prevalent they are in the environment and how poisonous they are.  All chemicals harm the environment.

Therefore, the correct option is option A.

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The half-life of the reaction is approximately 24.82 days.

In a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant. The half-life is the time it takes for half of the initial concentration of the reactant to be consumed. To determine the half-life, we can use the integrated rate equation for a first-order reaction:

ln([A]t/[A]0) = -kt

Where [A]t is the concentration at time t, [A]0 is the initial concentration, k is the rate constant, and t is the time.

We can rearrange the equation to solve for t:

t = ln(2)/k

Since the rate constant (k) is the same for the entire reaction, we can use the given initial rate and the rate at 25.0 days to determine the value of k. From the given data, we have:

0.0200 mol L^(-1) s^(-1) = k[A]0

6.25 x 10^(-4) mol L^(-1) s^(-1) = k([A]0/2)

Dividing the two equations, we get:

0.0200 mol L^(-1) s^(-1) / (6.25 x 10^(-4) mol L^(-1) s^(-1)) = 2

This tells us that the initial concentration [A]0 is twice the concentration at 25.0 days, or [A]0 = 2[A]t.

Substituting this into the equation for t, we have:

t = ln(2) / k

t = ln(2) / (0.0200 mol L^(-1) s^(-1) / 2[A]t)

Simplifying, we find:

t ≈ ln(2) / (0.0100 mol L^(-1) s^(-1) / [A]t)

t ≈ ln(2) / (0.0100 mol L^(-1) s^(-1) / (6.25 x 10^(-4) mol L^(-1) s^(-1)))

t ≈ ln(2) / 16

Using a calculator, we can determine:

t ≈ 0.693 / 16 ≈ 0.0433 days

Since the given time is in days, the half-life is approximately 24.82 days.

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Answer:

45 km

Explanation:

To find the distance Tylee walked, multiply her speed by the time.

\(d=10(4.5)\)

\(d =45\)

The distance Tylee walked is 45 kilometers.

I hope this helped :)

Tylee walked 45 km from her parents' farm into town .

Speed can be understood as the measure of  how fast an object is moving.

It is the rate at which an object covers certain distance in fixed amount of time.

It is scalar quantity and its S.I. unit is m/sec .

\(\rm Speed = \dfrac{distance}{time}\)

It is given in the question speed = 10 km/h and time = 4.5 hr

So,

\(\rm Distance = Speed\; \times\;time\)

\(\rm Distance = 10\; \times\;4.5\\\\\rm Distance = 45 \;km\\\)

Therefore Tylee walked 45 km from her parents' farm into town .

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Answer: a)

Explanation:

definition : The niche of an organism is the functional role that it plays within an ecosystem

A dirty pipette that consistently causes volume measurements to be off by 0.01 ml would be an example of a systematic error, which can be minimized or eliminated by ensuring proper calibration and maintenance of equipment, as well as accurate and consistent measurement techniques.

A dirty pipette that consistently causes your volume measurements to be off by 0.01 ml would be an example of a systematic error. Systematic error is a type of error in which the measured values are consistently offset from the true values by a fixed amount in the same direction.

It is caused by a flaw in the experimental design or equipment, such as an improperly calibrated instrument, malfunctioning equipment, or poor measurement techniques.Systematic errors can be minimized by ensuring that equipment is properly calibrated and maintained, and that measurement techniques are accurate and consistent. It is important to identify and correct systematic errors in order to obtain accurate and reliable data.

In the case of a dirty pipette, the error can be eliminated by thoroughly cleaning the pipette and ensuring that it is properly calibrated before use. If the pipette is damaged or malfunctioning, it may need to be repaired or replaced to eliminate the systematic error.

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The half-life of the reaction is 101.9 min

When a reaction's pace and reactant concentration are inversely correlated, the process is known as a first-order reaction. To put it another way, the reaction rate doubles when the concentration does. One or two reactants can be present in a first-order reaction, as in the case of the decomposition process.

The amount of time it takes for the initial concentration of the reactant(s) to decrease by half is known as the half-life of a chemical reaction (abbreviated as "t1/2").

a→b

25% reacted means 75% remains

t=42 min

Rate constant

k=(2.303/t)(log a/a-x)

k=(2.303/42)(log 100/100-25 )

k=(0.054) (log 100/75)

k=(0.054)(0.1249)

k=0.0068 per min

half life

t1/2=(0.693/k)

     =(0.693/0.0068)

     =101.9 min

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The reaction quotient, Qp, is calculated as 3.7, which is greater than the equilibrium constant, Kp, of 2.7.  The system will reach a new equilibrium where the ratio of partial pressures satisfies the new equilibrium constant.

The reaction quotient compares the partial pressures of the reactants and products at a specific moment to the equilibrium constant, which represents the ratio of their partial pressures at equilibrium.

When Qp is larger than Kp (Qp > Kp), it indicates an excess of products compared to the equilibrium prediction. As a result, the reaction will shift in the opposite direction to restore equilibrium, favoring the formation of reactants.

In this case, the excess of products suggests that the forward reaction (CO + H2O ⇌ CO2 + H2) will be driven backward, favoring the formation of CO and H2O. As the reaction progresses to the left, the concentrations of CO and H2O will increase, while the concentrations of CO2 and H2 will decrease. Eventually, the system will reach a new equilibrium where the ratio of partial pressures satisfies the new equilibrium constant.

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Many of the men may believe that they are fair and unbiased against women.

Many of the women may already believe that they face biases.

The propensity to seek for, understand, favor, and remember information that supports or confirms one's preexisting opinions or values is known as confirmation bias. People exhibit this bias when they choose facts that support their opinions while rejecting those that contradict them or when they interpret ambiguous facts as supporting their preexisting beliefs. Although confirmation bias cannot be completely avoided, it can be controlled, for instance, by critical thinking education and training.

Confirmation bias has been linked to poor decisions in the scientific, organizational, financial, and political spheres. These biases can preserve or reinforce views in the face of contradictory data and contribute to overconfidence in personal opinions.

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Answer:

Many of the men may believe that they are fair and unbiased against women.

Many of the women may already believe that they face biases.

Explanation:

Answer:

Continental polar

Explanation:

Answer:

Polar air masses!

Explanation:

They form between 50 and 60 degrees latitiude, Siberia and Northern Canada are the most commonplace for these to form!

The standard reaction entropy of N2(g) + 3 H2(g) → 2 NH3(g) is -196.3 J/K·mol.

What do you mean by standard reaction entropy?

Standard reaction entropy (ΔS°) is a measure of the disorder or randomness of a chemical reaction at a constant temperature and pressure. It is defined as the change in the entropy of the system when a reaction occurs under standard conditions. The standard state for a substance is its pure form at a pressure of 1 bar and a temperature of 25°C (298 K).

The standard reaction entropy (ΔS°) of a reaction can be calculated using the standard molar entropies (S°) of the reactants and products. The formula to calculate the standard reaction entropy is:

ΔS° = ΣS° (products) - ΣS° (reactants)

To calculate the standard reaction entropy for the reaction: N2(g) + 3 H2(g) → 2 NH3(g)

S° (N2) = 191.8 J/K·mol

S° (H2) = 130.6 J/K·mol

S° (NH3) = 192.5 J/K·mol

ΔS° = [2(S° (NH3)) - (S° (N2) + 3(S° (H2))]

ΔS° = [2(192.5) - (191.8 + 3(130.6))] J/K·mol

ΔS° = -196.3 J/K·mol

Hence, the standard reaction entropy of N2(g) + 3 H2(g) → 2 NH3(g) is -196.3 J/K·mol.

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Rutherford said that the atom is mostly empty space, with a small, dense positively charged nucleus located at the center.

Ernest Rutherford conducted the famous gold foil experiment, which involved bombarding a thin sheet of gold with alpha particles. He observed that most of the alpha particles passed straight through the gold foil, but some were deflected at angles, and a few bounced back in the direction they came from.

This led him to conclude that the atom was mostly empty space, with a small, dense nucleus at the center that was positively charged and contained most of the atom's mass. The negatively charged electrons were located in the space surrounding the nucleus, but they were much smaller and lighter than the nucleus itself.

In conclusion, Rutherford's discovery of the atomic nucleus revolutionized our understanding of the structure of the atom. It provided a more accurate picture of the atom than the previous plum pudding model, which suggested that the atom was a uniform blob of positive charge with electrons embedded throughout. Rutherford's model showed that the atom was a complex structure with a small, but incredibly dense nucleus at its center, surrounded by electrons in a cloud-like arrangement.

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