Track and field is an individual sport. This statement is True.
What is Track and field ?Track and field is a sport which includes jumping, running, and throwing. it is also know as track and field athletics, or track. This sport is organized in a stadium in which there are running tracks, set up for high jump and long jump and field for throwing. Hence the name is track and field. In this sport different participant participate to get one winner from each game from each weight group. The International Association of Athletics Federations(IAAF) is the international governing body for track and field.
The two most prestigious international track and field competitions are the athletics competition at the Olympic Games and the World Athletics Championships. World Athletics, formerly known as the International Association of Athletics Federations (IAAF),
Hence Track and field is an individual sport.
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.Given the displacement vectors A = 6f-4j+8k B = 2î+4ƒ^ − 14k
Find the magnitude and the unit vector of the vector 0.5A + 0.5B
Answer:
Explanation:
A = 6i - 4j + 8k
B = 2i + 4j - 14k
A + B = (6+2)i + (-4+4)j + (8-14)k
A + B = 8i +0j -6k
A + B = 8i - 6k
(1/2)(A + B) = 4i - 3k
d = √ (4² + 3²) = 5
e = (4/5)i -(3/4)j
How long does it take the second hand of a clock to move through 3.57 rad?
Answer in units of s.
Answer:
Its angular velocity is
π
30
radians per second (about 0.105 radians/s.
Explanation:
Explanation:
Think of it like this:
There are
2
π
radians in one complete rotation, and that takes the second hand 60 seconds to complete.
So, the rate of rotation (the angular velocity) is
2
π
/60 = pi/30 radians per second# which is about 0.105 radians per second.
To solve the problem we will first calculate the time taken by the second arm to travel 1 rad.
Time taken by the second arm to travel 1 rad
We know that the arm of the second travels 2π radians in 60 seconds. therefore, the time is taken to travel 1 rad by the second arm,
\(1\rm\ rad = \dfrac{60}{2\pi}\)
Time taken by the second arm to travel 3.57 radTime taken by the second arm to travel 3.57 rad
\(=3.57\times \dfrac{60}{2\pi}\\\\= 34.09\rm\ sec\)
Hence, the time taken by the second arm to travel 3.57 rad is 34.09 sec.
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Which statement about electric charges is correct? (1 point)
*two objects with negative charges will attract each other
*an object with a negative charge and an object with a positive charge will attract each other
*an object with a positive charge and an object with a negative charge will repel each other
*two objects with positive charges will attract each other
Answer:The correct statement about electric charges is:
"An object with a negative charge and an object with a positive charge will attract each other."
Explanation:
*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.
What is charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.
Hence option B is correct.
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What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?
Answer:
Explanation:
The acceleration of an electron in an electric field is given by the equation:
a = qE/m
where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.
Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:
E = ma/q
E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)
E = -2.44 × 10^4 N/C
The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.
Calculate the rate of heat generation in kW due to the burning of the fuel when you drive a car rated at 34 MPG (miles per gallon) at a speed of 70 MPH (miles per hour), given that the heating value of gasoline, that is the heat generated when a unit mass of gasoline is burnt in air is 44 x 103 kJ/kg.
Answer:
Explanation:
Let us calculate gallon used in one hour .
It travels 70 miles in one hour
in 70 miles it uses 70 / 34 gallons of fuel
70 / 34 gallons = 70 / 34 x 3.7854 kg
= 7.8 kg
heat generated = 7.8 x 44 x 10⁶ J
= 343.2 x 10⁶ J
This is heat generated in one hour
heat generated in one second = 343.2 x 10⁶ / 60 x 60 J/s
= 95.33 x 10³ J /s
= 95.33 kW.
A 500 kg rocket sled is coasting in reverse at 10 m/s (to the left). It then turns on its rocket engines for 10.0 s, with a thrust of 1500 N (to the right). What is its final velocity? (Remember velocity has magnitude and direction)
Explanation:
F = ma
\(a = \frac{f}{m} \)
\(a = \frac{1500}{500} = 3\)
\(a = \frac{v2 - v1}{t} \)
\(3 = \frac{v2 - 10}{10} \)
v2 (final) = 40 m/s to the right direction
A car starts from rest and goes down a slope with a constant acceleration of 5 m/s2. After 5 seconds the car reaches the bottom of the hill. What is its speed at the bottom of the hill
Answer:
Ok I may not be correct but I figured I should practice for physics. Given that a=5 m/s^2, t=5 s, v_0=0, we want to find the final velocity. I would think that the equation v=v_0+a*t would work best, and plugging the numbers in, v=0+(5)(5) your answer for the final velocity would be 25 m/s.
Explanation:
is a bouncing ball an example of simple harmonic motion? explain
Answer:
no
Explanation:
because it cannot be represented by a sine or cosine curve.
Two cyclists start on a race between points A and D on two different routes. Cyclist X takes the route passing through the equidistant points A-B-C-D, each separated by a distance of 200 meters. Cyclist Y takes the direct route AD, which has a total length of 546.41 meters. Both cyclists reach the end point in 30 seconds. Calculate the displacement and average velocities of cyclists X and Y.
Answer:
Both cyclists have a displacement (vector) of 546.41 m
V(velocity) = 546.61 / 30 = 18.2 m/sec
Cyclist x travels 600 m / 30 = 20 m/sec average speed assuming 20 sec over each 200 m interval (total displacement of X = 600 m)
Cyclist Y travels 546.61 m / 30 = 18.2 m/s average speed
Answer:
For cyclist X, the displacement is 546.41 meters.
The velocity is the displacement ÷ time = 546.41 ÷ 30 = 18.21 meters/second.
For cyclist Y, the displacement is also 546.1 meters.
The velocity is displacement ÷ time = 546.1 ÷ 30 = 18.21 meters/second.
Although cyclist X and cyclist Y have traveled different distances in same time interval, their velocities and displacements are same.
Explanation: edmentum sample answer
Suppose a space vehicle with a rest mass of 150 000 kg travels past the International Space Station at a constant speed of 2.6 x 108 m/s with respect to the I.S.S. When an observer on the I.S.S. measures the moving vehicle, her measurement of the space vehicle length is 25.0 m. Determine the relativistic mass of the space vehicle. Determine the length of the space vehicle as measured by an astronaut on the space vehicle.
Answer:
m = 300668.9 kg
L₀ = 12.47 m
Explanation:
The relativistic mass of the space vehicle is given by the following formula:
\(m = \frac{m_{0}}{\sqrt{1-\frac{v^{2} }{c^{2}} } }\)
where,
m = relativistic mass = ?
m₀ = rest mass = 150000 kg
v = relative speed = 2.6 x 10⁸ m/s
c = speed of light = 3 x 10⁸ m/s
Therefore
\(m = \frac{150000kg}{\sqrt{1-\frac{(2.6 x 10^{8}m/s)^{2} }{(3 x 10^{8}m/s)^{2}} } }\)
m = 300668.9 kg
Now, for rest length of vehicle:
L = L₀√(1 - v²/c²)
where,
L = Relative Length of Vehicle = 25 m
L₀ = Rest Length of Vehicle = ?
Therefore,
25 m = L₀√[1 - (2.6 x 10⁸ m/s)²/(3 x 10⁸ m/s)²]
L₀ = (25 m)(0.499)
L₀ = 12.47 m
An acorn is about to fall from a tree. What type of energy does it have? A.GPE only B.KE onlyC.EPE onlyD.KE and GPE
We are given that an acorn is about to fall from a tree. This means that the acorn is not accelerated yet and is at a height "h" from the ground. The energy associated to ab object at a certain height is:
\(U=mgh\)Where:
\(\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ h=\text{ height} \end{gathered}\)The energy "U" is called Gravitational Potential Energy (GPE).
Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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How many protons are present in an atom
which has an atomic number of 47?
Answer in units of protons.
Explanation:
The atomic number of an atom represents the number of protons in its nucleus. Therefore, 47 means that there are 47 protons in the atom's nucleus. In this case the atom is that of silver (Ag).
Two trains ‘A’ and ‘B’ leave the same station on parallel lines. Train ‘A’ starts with a uniform acceleration of 1/6 m/s2 and attains the speed of 24 km/hr, then stem is reduced to keep the speed constant. Train ‘B’ leaves 40 seconds after, with uniform acceleration of 1/3 m/s2 to attain the maximum speed of 48 km/hr. When will it overtake the train ‘A’?
Answer:
Explanation:
Let's first convert the speeds of the trains from km/hr to m/s:
Train A: 24 km/hr = (24 x 1000) / (60 x 60) = 6.67 m/s
Train B: 48 km/hr = (48 x 1000) / (60 x 60) = 13.33 m/s
Now, let's find the distance covered by train A until it reaches its constant speed:
v = u + at
where
u = initial velocity = 0
a = acceleration = 1/6 m/s^2
t = time taken to reach constant speed
At constant speed, v = 6.67 m/s
So, 6.67 = (1/6)t + 0
t = 40 seconds
Using the formula for distance covered during uniform acceleration:
s = ut + (1/2)at^2
The distance covered by train A during the acceleration phase is:
s = (1/2)(1/6)(40^2) = 133.33 m
Now, let's find the equation of motion for train B:
s = ut + (1/2)at^2
where
u = initial velocity = 0
a = acceleration = 1/3 m/s^2
t = time taken to overtake train A
At the time of overtaking, both trains will cover the same distance. Let's call this distance "d". So we have:
d = 133.33 + 6.67t (distance covered by train A + distance covered by train B)
Setting the equations for both trains equal to each other, we get:
133.33 + 6.67t = (1/2)(1/3)t^2 + (1/3)t^2
Simplifying and solving for t, we get:
t = 180 seconds
Therefore, train B will overtake train A after 180 seconds or 3 minutes.
Which of the following sentences is true about the relationship between distance and gravitational force?
mark all correct answers
A. Smaller distance results in greater force.
b. Smaller mass results in greater force.
c. Greater distance results in no force.
d. Greater mass results in greater force.
The gravitational force between objects increases with an increase in mass and decreases with an increase in distance. So, a smaller distance and a greater mass result in a greater gravitational force.
Explanation:The correct answers to this question are 'A. Smaller distance results in greater force' and 'D. Greater mass results in greater force'. According to the universal law of gravitation, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This means that as the mass of one or both objects increases, the gravitational force also increases. Conversely, as the distance between the objects increases, the gravitational force decreases. Hence, a smaller distance would result in a greater force and a greater mass would also result in a greater force.
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It takes 20 Joules of Work to push 4 coulombs of charges Across the filament of a bulb.'find the potential difference Across the filament
Answer:
V = 5 Volts
Explanation:
Given the following data;
Work done = 20 Joules
Charge = 4 Coulombs
To find the potential difference;
Mathematically, the work done in moving a charge is given by the formula;
W = qv
Where;
W is the work done
q is the quantity of charge
v is the potential difference
Substituting we have;
20 = 4 * v
V = 20/4
V = 5 Volts
If you go into a store to buy a digital thermometer and there are 8 instruments of the same brand and model, at the same price, but they indicate different temperature values, explain which one you choose and why.
Answer: I would buy the thermometer with the most features because they all cost the same price so why not you getting more than what you are paying for than buying something the same but with less feature and things it can do for the same price.
Hope this helps :) If so brainliest would mean alot thanks!
Explanation:
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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write down the value of
920 kg in g
Answer:
920000
Explanation:
Each kg contains 1,000 grams
study 60cm ady the water the diagram Pressure at A, B and C. C B 30cm A ram and calculate the liquid pressure
To calculate the liquid pressure at points A, B, and C in the given diagram, we need to consider the height and density of the liquid.
Let's assume that the liquid in the container is water, which has a density of approximately 1000 kg/m³.
Given:
- Height of column AB = 60 cm = 0.6 m
- Height of column BC = 30 cm = 0.3 m
To calculate the pressure at each point, we can use the formula:
Pressure = density * gravity * height
where:
- Density = 1000 kg/m³ (density of water)
- Gravity = 9.8 m/s² (acceleration due to gravity)
Calculating the pressures:
At point A:
Pressure_A = density * gravity * height_AB
= 1000 kg/m³ * 9.8 m/s² * 0.6 m
= 5880 Pascal (Pa)
At point B:
Pressure_B = density * gravity * (height_AB + height_BC)
= 1000 kg/m³ * 9.8 m/s² * (0.6 m + 0.3 m)
= 8820 Pascal (Pa)
At point C:
Pressure_C = density * gravity * height_BC
= 1000 kg/m³ * 9.8 m/s² * 0.3 m
= 2940 Pascal (Pa)
Therefore, the liquid pressures at points A, B, and C are as follows:
- Pressure at point A = 5880 Pa
- Pressure at point B = 8820 Pa
- Pressure at point C = 2940 Pa
A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon weigh 150n with what force must the child pull on the handle if the handle is parallel to the incline?
Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
\(F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\\)
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
\(F = (150\ N)Sin\ 20^o\)
F = 51.3°
represent the reading of a vernier caliper with a diagram showing the reading 45.75mm
The reading on a vernier caliper can be represented as 45.75mm.
1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.
2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.
3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.
4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.
5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.
6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.
7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.
8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.
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What kind of model is shown below?
о
A. Experimental model
O B. Computer model
O C. Mathematical model
O D. Physical model
Answer:
.....where's the model-
The addition of 9.5×10^5 of thermal energy is required to convert a block of ice at −15° to water at 15°. What was the mass of the block of ice?
Answer:
2.2241 Kg
Explanation:
Given that it takes \(9.5 \times 10^5 \ J\) of energy to convert a block of ice at −15° to water at 15°. Find the mass of the block of ice. We'll call \(9.5 \times 10^5 \ J\) "\(Q_{melt}\)" which is the total energy taken to melt the block of ice.
\(\boxed{\left\begin{array}{ccc}\text{\underline{Heat energy formulas:}}\\Q=mc\Delta T\\Q=mL_f\\\end{array}\right}\)
The energy it takes to raise the temperature of the ice from −15° to 0°:
\(Q_1=m_b(2090)(-15\°-0\°)\\\\||Q_1||=\boxed{31350m_b}\)
The energy it takes to convert the ice to water:
\(Q_2=\boxed{3.33\times 10^5 m_b}\)
The energy it takes to raise the temperature of the water from 0° to 15°:
\(Q_3=m_b(4186)(0\°-15\°)\\\\||Q_3||=\boxed{62790m_b}\)
\(Q_{melt}=Q_1+Q_2+Q_3; \ Q_{melt}=9.5 \times 10^5 \\\\\Longrightarrow 9.5 \times 10^5=31350m_b+3.33\times 10^5 m_b+62790m_b\\\\\Longrightarrow 9.5 \times 10^5=(31350+3.33\times 10^5 +62790)m_b\\\\\Longrightarrow 9.5 \times 10^5=427140m_b\\\\\Longrightarrow \boxed{\boxed{m_b \approx 2.2241 \ kg}}\)
Thus, the mass is found.
A town requiring 2.0 m3/s of drinking water has two sources, a local well with 15 g/m3 nitrate (as N) and a distant reservoir with 5 g/m3 nitrate (as N). What flow rates of well and reservoir water are needed to meet the EPA drinking water standard and minimize the use of more expensive reservoir water
Explanation:
Drinking water requirement in town 2.0 m^3/s of water per second
nitrate in local well nitrate per 15 \(\mathrm{m}^{3}\) of water
nitrate in distant reservoir \(=5 \mathrm{~g} / \mathrm{m}^{3}\)
Let the flow rate of well
flow rate of reservoir \(=y m^{3} / s\)
Drinking water requirement is \(45 \mathrm{ppm}\) or \(45 \mathrm{~g} / \mathrm{m}^{3}\)
therefore, the total flow of drinking water
There is a current of 0.83 A through a light bulb in a 120.0v circuit. What is the
resistance of the light bulb?
Answer:
144.6ohms
Explanation:
v=IR
R =V/I=120/0.83
R=144.6
Name 1. Consider positive and negative charges of a copper wire all moving horizontally within the time interval 10 us. What can you say about the magnitude and direction of the current?
When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.
In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:
1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.
2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.
In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.
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Which is more dense a Large log, or a small pebble?
What four processes allow for the change of thermodynamics properties according to the first law
Answer:
The four types of thermodynamic process are isobaric, isochoric, isothermal and adiabatic.
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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