True or False: the national fire protection association (nfpa) 704 diamond is a visual clue to the presence of hazardous materials.

Answer:

Percent Composition (C)  =  71.40%

Explanation:

To find the percent composition of carbon by mass, you need to (1) calculate the molar mass of C₂₀H₂₉FO₃ (using the atomic masses of each atom in the molecule), then (2) calculate the total amount of carbon in C₂₀H₂₉FO₃ (using the atomic mass of carbon), and then (3) calculate the percent composition of carbon.

(Step 1)

Atomic Mass (C): 12.011 g/mol

Atomic Mass (H): 1.008 g/mol

Atomic Mass (F): 18.998 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (C₂₀H₂₉FO₃):

20(12.011 g/mol) + 29(1.008 g/mol) + 18.998 g/mol + 3(15.999 g/mol)

=  336.447 g/mol

(Step 2)

Atomic Mass (C): 12.011 g/mol

Total Mass (C): 20(12.011 g/mol) = 240.22 g/mol

(Step 3)

                                                  mass of carbon
Percent Composition (C)  =  -----------------------------  x  100%
                                                 mass of molecule

                                                   240.22 grams
Percent Composition (C)  =  -----------------------------  x  100%
                                                  336.447 grams

Percent Composition (C)  =  71.40%

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer:

It travel's about 4,000 km through the Earth in 13 minutes.

Answer:

4,000 km is the correct answer!!!

Answer:

Organisms need to take food to get energy and perform life processes. A living organism undergoes many life processes like nutrition, respiration, digestion, transportation, excretion, circulation of blood, and reproduction. To perform all these life processes the organism needs energy and nutrients.

Explanation:

nnastarannnn his idea

Answer:

where are the statements?

Explanation:

By solving the equation we get:NaHCO3 has a molecular mass   84 g/mol.

Na2CO3 has a molecular weight of 0.02 mol.

Mass of Na2CO3 = **2.12 g**

Daltons or atomic mass (Da or u) are used to measure molecular mass, which is the mass of a certain molecule1. The molecular mass indicates a molecule's mass in relation to the 12 C atom, whose mass is assumed to be 12. The molar mass, which is stated in g/mol1, is the mass of a particular material divided by the amount of that substance. Hence, the molecular mass is the mass of a single particle or molecule, whereas the molar mass is the average of numerous particles or molecules

The equation below illustrates how heating causes sodium hydrogencarbonate to break down:

Na2CO3(s) + H2O(g) + CO2 = 2 NaHCO3(s) (g)

a) I The formula: can be used to determine how many moles of sodium hydrogencarbonate were utilised.

Molar mass = mass times the number of moles

NaHCO3 has a molecular mass of (23 + 1 + 12 + 48) g/mol, or 84 g/mol.

3.36 g of NaHCO3 divided by 84 grammes per mole yields 0.04 moles.

ii) Stoichiometry can be used to calculate the quantity of sodium carbonate produced:

We can deduce from the balanced equation that 2 moles of NaHCO3 result in 1 mole of Na2CO3.

Na2CO3 has a molecular weight of (0.04 mol 2 mol) 1 mol = 0.02 mol.

iii) The formula Mass = Number of moles Molar mass can be used to determine the mass of sodium carbonate produced.

molar volume of Na2CO3 = (23 × 2 + 12 + 48) g/mol = 106 g/mol

Mass of Na2CO3 = 0.02 mol × 106 g/mol = **2.12 g**

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Answer:

Is there any options?

For example :

1) Nervous system

2)....

3)...

and so on.

Answer:

53.5%

Explanation:

Step 1: Given data

Step 2: Calculate the mass corresponding to 0.00875 moles of KClO₃

The molar mass of KClO₃ is 122.55 g/mol.

0.00875 mol × 122.55 g/mol. = 1.07 g

Step 3: Calculate the percent by mass of KClO₃ in the mixture

We will use the following expression.

%m/m = mass of KClO₃/mass of the sample × 100%

%m/m = 1.07 g/2.00 g × 100%

%m/m = 53.5%

The percent by mass of KClO3 in the original mixture is 53.5%.

Since

The mass of the sample should be 2.00 g

Moles of KClO₃: 0.00875 mol

The molar mass of KClO₃ is 122.55 g/mol.

Now the mass is

= 0.00875 mol × 122.55 g/mol.

= 1.07 g

Now the percentage should be

= mass of KClO₃/mass of the sample × 100%

= 1.07 g/2.00 g × 100%

= 53.5%

hence, The percent by mass of KClO3 in the original mixture is 53.5%.

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Answer:

-  40.66

-  9.91

Explanation:

For the first question:

Our theoretical compound is MR₂

1 mol of MR₂ contains 1 mol of M and 2 moles of R

Let's find out the molar mass:

9.45 g/mol + 18.12 g/mol . 2 = 45.69 g/mol

We can solve this, by an easy rule of three:

1 mol of MR₂ weighs 45.69 grams

Then, 0.89 moles may weigh 40.66 g

For the second question:

Our theoretical compound is D₂G

Let's determine the molar mass:

11.45 g/mol . 2 + 44.57 g/mol = 67.47 g/mol

1 mol of anything contains 6.02×10²³ molecules. By this definition we can say that 6.02×10²³ molecules weigh 67.47 grams. Let's solve by the rule of three:

6.02×10²³ molecules weigh 67.47 g

8.84×10²² molecules may weigh (8.84×10²² . 67.47 ) / 6.02×10²³ = 9.91 g

Plasma or cell membrane is the membrane that surrounds the cell, separating the external environment from the cytoplasm and controlling what enters and leaves the cell.

The models of both the plant and animal cells is attached in diagram below. The shaded dark area is the plasma or cell membrane.

From the model given, the plasma membrane is located at the outer part of the cell. Therefore, it controls what enters and leaves the cell.

This is because is the membrane is made up of lipid bilayer.

This allows only the movement of non polar small substances across the membrane in a direction against their concentration gradient.

Therefore, plasma membrane contributes to how the cell function as a whole by controlling the materials that are transported in and out of the cell.

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Answer:

11.1 moles of CO2

Explanation:

2C2H6(g) + 7O2(g)⟶4CO2(g)+6H2O(g)

To find the number of moles of CO2 produced when 5.55 mol of ethane is burned in an excess of oxygen, use the stoichiometry of the reaction.

5.55 mol C2H6 x (4 mol CO2/2 mol C2H6) = 11.1 mol CO2

Therefore, 5.55 mol of ethane is burned in an excess of oxygen produces 11.1 moles of CO2.

Answer:

Within smokestacks and tailpipes

Explanation:

this is where manmade ozone is usually produced

Answer:

109.5º

Explanation:

The leftmost carbon has four bonds and no lone pairs attached to it. According to the VSEPR model, this carbon has a tetrahedral geometry. Thus, each bond angle is 109.5º

1.761 moles NO will be made from 30g of NH3.

The balanced reaction is:

4 NH₃(g) + 5 O₂(g) → 4 NO (g) + 6 H₂O

By stoichiometry of the reaction, we have

Recall that

Number of moles = Mass/ Molar Mass

We first Find the number of moles in 30g of NH3 ,

Number of moles=30/17.031 g/mol=1.761moles

Now we can say  if by stoichiometry

IF 4 moles of NH3 produces 4 moles of NO,

then  1.761 moles of aNH3  will produce = ( 1.761 moles NH3 x 4 moles of NO)/ 4 moles of NH3

= 1.761 moles NO

Therefore, 1.761 moles NO will be made from 30g of NH3.

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Answer:

\(m_w=439.2g\)

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

\(\%m/m=\frac{m_{solute}}{m_{solution}} *100\%\)

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

\(m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\)

Thus, by plugging in the data, we obtain:

\(m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g\)

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

\(m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g\)

Best regards!

Answer:

1.55 × 10²⁵ atoms of H  

Explanation:

3.21mol C₃H₈ × 8mol H × (6.022×10²³)

Answer:

177.3 meters per second

Explanation:

Assuming that both gases are at the same temperature, we can use Graham's law to calculate the ratio of the average speeds of N2 and He molecules:

(ratio of speeds) = sqrt(molar mass of He/molar mass of N2)

The molar mass of N2 is 28.02 g/mol, and the molar mass of He is 4.00 g/mol. Therefore:

(ratio of speeds) = sqrt(4.00/28.02) = 0.379

We know that the average speed of N2 molecules is 468 m/s. Therefore:

(average speed of He molecules) = (ratio of speeds) x (average speed of N2 molecules) = 0.379 x 468 m/s = 177.3 m/s

Therefore, the average speed of He molecules at the same temperature is approximately 177.3 meters per second.

Answer:0.226 gram

Explanation:you can get the answer in two steps calculate 3.40 . 10^22 atoms =

Answer:

4.2 × 10²² ÷ 6.022× 10²³

4.2 × 10²² equals 0.069 moles (approx)

weight of 1 mole of iron = 56g

therefore, 0.069 moles = 56 × 0.069 = 3.9 g

Sorry for lazy work.. :P

Faults and problems in three routes of compound Br(bromide) synthesis, and the most feasible route, addressing competition, compatibility, and timing.

The main course includes a nucleophilic replacement of A with MeOH within the sight of HCl, trailed by parchedness with CS₂/Mel/heat. The fundamental issue with this course is the opposition between the replacement and end responses, which could prompt low yields of the ideal item.

The subsequent course includes a comparative nucleophilic replacement of A with MeOH within the sight of TsOH, trailed by a decrease with LiAlH₄. The fundamental issue with this course is the similarity between the acidic TsOH and the diminishing specialist, which could bring about the development of undesirable side items.

The third course includes an immediate buildup of A with ethyl oxalate within the sight of K₂CO₃, trailed by a decarboxylation with H₂SO₄. The fundamental issue with this course is the planning of the decarboxylation step, which could prompt the arrangement of undesirable side items because of overcompensation.

Generally speaking, the most possible course is by all accounts the first, with cautious advancement of the response conditions to limit the opposition among replacement and disposal responses.

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Answer:

oxide triioide

Explanation:

its a dangerous substant that melts on contact

Entropy is a notion that essentially refers to the universe's propensity for chaos or the spontaneous changes that take place in everyday happenings. Here the standard entropy change for the given reaction is -233.

Entropy is typically referred to as a measurement of a system's randomness or disorder. In the year 1850, a German physicist by the name of Rudolf Clausius first proposed this idea. Entropy is a thermodynamic property that is used to characterize how a system behaves in terms of temperature, pressure, entropy, and heat capacity.

Here the standard entropy change is:

Entropy of products - entropy of reactants

ΔS = 230 - (201 + 2 ( 131)) = -233

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Answer:

The balanced reactions are:

C₂ + 2B → B₂C₂

Ag₄ + 2SO₂ → 4AgO + S₂

Explanation:

The Law of Conservation of Matter postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends. In other words, then the mass before the chemical reaction is equal to the mass after the reaction.

In other words, the law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts .

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  

You have:

C₂ + B → B₂C₂

Left side: 2 C and 1 B.

Right side: 2 C and 2 B.

Carbon C is balanced since you have the same amount of the element on each side of the reaction, but boron B is not balanced. So, balancing the reaction:

C₂ + 2B → B₂C₂

Left side: 2 C and 2 B.

Right side: 2 C and 2 B.

Now you have the same amount of each element on each side of the reaction, so the reaction is balanced.

Now you have:

Ag₄ + SO₂ → AgO + S₂

Left side: 4 Ag, 1 S and 2 O.

Right side: 1 Ag, 2 S and 1 O.

Balancing the Ag:

Ag₄ + SO₂ → 4AgO + S₂

Left side: 4 Ag, 1 S and 2 O.

Right side: 4 Ag, 2 S and 4 O.

Balancing the O:

Ag₄ + 2SO₂ → 4AgO + S₂

Left side: 4 Ag, 2 S and 4 O.

Right side: 4 Ag, 2 S and 4 O.

You have the same amount of each element on each side of the reaction, so the reaction is balanced.

The Balanced Eqn is 2CO+O2→2CO2.

A chemical reaction is a method wherein one or more materials, also called reactants, are transformed into at least one or more special substances, called merchandise. Materials are both chemical elements or compounds.

A few synthesis reactions can result in more than one product. Photosynthesis is one of the maximum important chemical reactions on earth. It allows plants and a few microbes to transform water and carbon dioxide gas into storable sugar and oxygen.

Chemical compounds are made from atoms of different elements, joined collectively through chemical bonds. A chemical synthesis normally involves the breaking of existing bonds and the formation of recent ones.

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The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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We gain oxygen from trees through the process of photosynthesis. Photosynthesis is the biochemical process in which green plants, including trees, use sunlight, water, and carbon dioxide to produce oxygen and glucose (a form of sugar).

Trees have specialized cells called chloroplasts, which contain a pigment called chlorophyll. Chlorophyll absorbs sunlight energy.

The tree's leaves capture sunlight and use it to convert carbon dioxide (CO2) from the air and water (H2O) from the roots into glucose (C6H12O6) and oxygen (O2).

During photosynthesis, the chlorophyll in the chloroplasts helps to split water molecules into hydrogen ions (H+) and oxygen atoms (O). The oxygen atoms then combine to form O2 molecules.

The oxygen produced during photosynthesis is released into the atmosphere through tiny pores called stomata found on the surface of the tree's leaves. From there, it mixes with the surrounding air and becomes available for us to breathe.

In summary, trees produce oxygen as a byproduct of photosynthesis. They play a crucial role in maintaining the balance of oxygen and carbon dioxide in the atmosphere, providing us with the oxygen we need for respiration.

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Answer:

Atom is the smallest particle of pure sustance which can take part in a chemical reaction.A chrged atom is called an ion.

A molecule of an element or compound is the smallest particle of it that is stable and capable of independent existence. The molecules of element and compound are different.

Answer:

C6H5S^-

Explanation:

This is because you are removing the hydrogen to make it a conjugate base.

The formula for conjugate base of C6H5SH is C6H5S⁻.

Conjugate base is defined as the substance which is formed when an acid liberate its protons.

The acid donate protons and the acid changes into base.

Conjugate acid is defined as the pair of compound that differs by its protons by gaining protons.

Conjugate acid and base are based in acid base theory.

Thus, the formula for conjugate base of C6H5SH is C6H5S⁻.

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NH3 is the chemical compound produced as a product in the given balanced chemical equation.

With the formula NH3, ammonia is a nitrogen and hydrogen inorganic chemical. A Lewis base is urea. Ammonia is a colourless, extremely unpleasant gas that has a strong, suffocating stink when it is present at room temperature. It is hygroscopic and known as anhydrous ammonia in its pure state (readily absorbs moisture). Ammonia is corrosive and has alkaline qualities.

Water molecules' shared dipoles and development of hydrogen bonds with one another account for this. As a consequence, the molecules of water and ammonia are both made up of dipoles that exert significant electrostatic forces on one another.

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