True/False: a normal distribution is generally described by its two parameters: the mean and the standard deviation.

Therefore solution to this question is slope at (0,-1) is negative at (-2,2) is negative at (1,-3) is negative & (0,4) is also negative.

A slope field, which displays the slope of a differential equation along specific vertical and horizontal axes of the x-y plane, can be used to estimate the tangent slope at a particular point on a curve, where the curve is one possible solution to the differential equation.

Here,

For figure 1 slope field=

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\)

For figure 2 slope field=

\(\frac{dy}{dx} = xy-3\\\)

For figure 1 a solution passing through the point (0,-1)

therefore,

slope=

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\\\frac{dy}{dx}=\frac{-17(0)-2(-1)}{-1}=-2\)

so slope comes out to be negative

For figure 1 a solution passing through the point (-2,2)

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\\\frac{dy}{dx}=\frac{-17(-2)-2(2)}{-1}=-30\)

so slope comes out to be negative

For the slope field in figure 2. a solution passing through the point (1.-3)

\(\frac{dy}{dx} = xy-3\\\\\frac{dy}{dx}=(1*-3)-3=-6\)

so slope comes out to be negative

\(\frac{dy}{dx} = xy-3\\\\\frac{dy}{dx}=(0*4)-3=-3\)

so slope comes out to be negative.

Therefore solution to this question is slope at (0,-1) is negative at (-2,2) is negative at (1,-3) is negative & (0,4) is also negative.

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The volume of the tetrahedron is approximately 43.333.

First, we need to find the vectors u, v, and w. We can choose any three vertices to determine them. Let's choose P, Q, and R.

u = Q - P = <2-(-6), 1-5, -3-0> = <8, -4, -3>

v = R - P = <1-(-6), 0-5, 1-0> = <7, -5, 1>

w = S - P = <3-(-6), -2-5, 3-0> = <9, -7, 3>

Next, we need to find the cross product of vectors v and w:

v x w = <(-5)(3)-(1)(-7), -(1)(3)-(7)(3), (7)(-7)-(5)(9)> = <-4, -22, -44>

Finally, we can use the formula to find the volume:

V = (1/6) * |u . (v x w)| = (1/6) * |<8, -4, -3> . <-4, -22, -44>| = (1/6) * |-260| = 43.333...

Therefore, the volume of the tetrahedron is approximately 43.333.

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The area of the computer monitor display is approximately 0.103 square meters, with three significant figures.

The area of the monitor display in square meters is found by converting the measurements from inches to meters and then calculate the area.

The conversion factor from inches to meters is 0.0254 meters per inch.

Width in meters = 14.60 inches * 0.0254 meters/inch

Height in meters = 10.95 inches * 0.0254 meters/inch

Area = Width in meters * Height in meters

We calculate the area:

Width in meters = 14.60 inches * 0.0254 meters/inch = 0.37084 meters

Height in meters = 10.95 inches * 0.0254 meters/inch = 0.27813 meters

Area = 0.37084 meters * 0.27813 meters = 0.1030881672 square meters

Now, we determine the number of significant figures.

The measurements provided have four significant figures (14.60 and 10.95). However, in the final answer, we should retain the least number of significant figures from the original measurements, which is three (10.95). Therefore, the answer should have three significant figures.

Thus, the area of the monitor display in square meters is approximately 0.103 square meters, with three significant figures.

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Those activities that enable a person to describe in the detail the system that solves the need is called "System design".

The method of defining the components of a system consists, modules, and components, the various interfaces of those components, and the data that flows through that system is known as system design.

Some key features regarding the system design are-

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The empirical norm therefore states that 68% of 7-year-old kids are between 47 and 51 inches tall.

A column in a table is a collection of cells which are arranged vertically. A field, like the received field, is a sort of element that contains only one item of data. A column in a table usually contains the values for just a single field.

The empirical rule states that in a normal distribution, 68% of the data fall within one average standard deviation. In this instance, the mean difference is 2 inches, while the average height of 7-year-old kids is 49 inches.

We must identify the range among heights that is within one average standard deviation in order to apply the scientific rule. To accomplish this, we can add and subtract the standard variance from the median as follows:

Mean ± (Standard Deviation) = 49 ± 2

As a result, the height range which falls within the standard deviation from the average is between 47 and 51 inches.

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4y - 56 is the equivalent expression for 8(1/2y - 7)​​

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we substitute the same value(s) for the variable(s).

Given: 8(1/2y - 7)​​

In order to write an equivalent expression, clear the parenthesis:

8(1/2y - 7)​​ = 8(1/2y ) -  8(7)

                = 4y - 56

Therefore, the equivalent expression for 8(1/2y - 7)​​ is 4y - 56

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Answer:

11%

Step-by-step explanation:

I think that's the answer just check first

Answer: Multiply the centimeters number by 10.

Step-by-step explanation: There are 10 millimeters in every centimeter.

For each of the given functions, let's analyze the returns to scale.

A. Q = K + L:
This function represents a linear relationship between the inputs of capital (K) and labor (L) and the output (Q). In this case, the returns to scale can be described as constant. If both K and L are increased by a certain proportion, the output Q will increase proportionally. For example, if K and L are both doubled, the output Q will also double. Thus, function A exhibits constant returns to scale.

B. Q = K^(1/2) * L^(3/4):
This function represents a non-linear relationship between the inputs of capital (K) and labor (L) and the output (Q). Here, the returns to scale can be described as increasing. If both K and L are increased by a certain proportion, the output Q will increase more than proportionally. For instance, if K and L are both doubled, the output Q will increase by a factor greater than 2. Therefore, function B exhibits increasing returns to scale.

C. Q = K^2 * L:
This function also represents a non-linear relationship between the inputs of capital (K) and labor (L) and the output (Q). In this case, the returns to scale can be described as decreasing. If both K and L are increased by a certain proportion, the output Q will increase less than proportionally. For example, if K and L are both doubled, the output Q will increase by a factor less than 4. Hence, function C exhibits decreasing returns to scale.

function A exhibits constant returns to scale, function B exhibits increasing returns to scale, and function C exhibits decreasing returns to scale.

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Answer: 166 Soft Drinks

Step-by-step explanation:

250 ÷ 1.50 = 166

Answer:

Step-by-step explanation:

-4

Answer:

3x

Step-by-step explanation:

because if f is -5, -5=-3x-4, -5+4, -1=-3 divide and get 3=x

Rent, insurance, commissions, and other expenses could be added to the operating costs of a service-based business. Most of these expenses are regular daily expenses.

A continuing cost for maintaining a system, a business, or a product is known as an operating expense, operating expenditure, operational expenditure, operational expenditure, or OPEX.

The expense of creating or providing non-consumable pieces for the system or product is known as capital expenditure (capex).

For instance, the annual costs of paper, toner, power, and maintenance for a photocopier are opex, while the cost of the photocopier itself is capex.

Additional running costs for a service-based business could include rent, insurance, commissions, and other costs.

The majority of these costs are routine daily spending.

Costs that weren't directement necessary for those activities are referred to be non-operating expenses.

Therefore, rent, insurance, commissions, and other expenses could be added to the operating costs of a service-based business. Most of these expenses are regular daily expenses.

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Correct question:

A service business may have some additional operating expenses like rent, insurance, commissions, and so on. Most of these expenses are incurred on a ___ basis.

The contour integral of f(z) = e^(1/z^4) along the circle centered at the origin is 0.

To find the contour integral of the function f(z) = e^(1/z^4) along a circle centered at the origin, we can use the Cauchy's Integral Formula for Contour Integrals. The formula states that if a function is analytic inside and on a simple closed contour C, then the contour integral of the function along C is given by 2πi times the sum of the residues of the function at its isolated singularities inside C.

In this case, the function f(z) = e^(1/z^4) has a singularity at z = 0. To find the residue at this singularity, we can expand the function in a Laurent series around z = 0. The Laurent series representation of f(z) is given by:

f(z) = Σ[ n = -∞ to +∞ ] (a_n * z^n)

where a_n = (1/(2πi)) * ∮[ C ] (f(z) / (z - z_0)^(n+1)) dz

In our case, since the contour is a circle centered at the origin, the contour integral becomes:

∮[ C ] f(z) dz = 2πi * a_{-1}

To find the residue a_{-1}, we need to determine the coefficient of the term (z - 0)^(-1) in the Laurent series of f(z). By expanding the function f(z) = e^(1/z^4) in a Taylor series, we can compute the coefficient a_{-1}.

f(z) = Σ[ n = 0 to +∞ ] (a_n * z^n)

To find the coefficient a_{-1}, we look for the term with n = -1 in the Taylor series. However, in this case, all the terms in the Taylor series expansion of f(z) have non-negative powers of z, so there is no term with n = -1.

Therefore, the coefficient a_{-1} is 0, which means there is no residue at the singularity z = 0.

As a result, the contour integral of f(z) = e^(1/z^4) along the circle centered at the origin is also 0.

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ANSWER

B. 10 laps in 205 seconds

EXPLANATION

If we write the rate of laps to seconds as a fraction we have:

I simplified the fraction and got 2/41. An equivalent rate must give the same simplified fraction. For option B:

We can reduce both rates to the same rate: 2 laps every 41 seconds. Therefore, these two rates are equivalent.

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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The volume of the cone is1527.1 cm³

And the correct answer is an option (c)

We know that he formula for the volume of the cone is:

V = 1/3(π × r² × h)

Here, the diameter of the base of the cone is 15 cm

so, the radius of the cone would be,

r = 15/2 cm

r = 7.5 cm

And the slant heihgt of the cone is l = 27 cm

Using Pythagoras theorem the height h of the cone would be,

h = √(l² - r²)

h = √(27² - 7.5²)

h = √(672.75)

h = 25.94 cm

Using above formula, the volume of the cone would be,

V = 1/3(π × r² × h)

V = 1/3(π × (7.5)² × 25.94)

V = 1527.99 cm³

V = 1527.1 cm³

Therefore, the correct answer is an option (c)

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Find the complete question below.

Answer:

large

Step-by-step explanation:

The 90% confidence interval for the difference in the population means is -2.51 to 0.31

From the question, we have the following parameters that can be used in our computation:

xˉ₁ = −17.1

s₁² = 8.4

n₁ = 22

​xˉ₂ = −16.0

s₂² = 8.7

n₂ = 24

Calculate the pooled variance using

P = (df₁ * s₁² + df₂ * s₂²)/df

Where

df₁ = 22 - 1 = 21

df₂ = 24 - 1 = 23

df = 22 + 24 - 2 = 44

So, we have

P = (21 * 8.4 + 23 * 8.7)/44

P = 8.56

Also, we have the standard error to be

SE = √(P/n₁ + P/n₂)

So, we have

SE = √(8.56/22 + 8.56/24)

SE = 0.86

The z score at 90% CI is 1.645, and the CI is calculated as

CI =  (x₁ - x₂) ± z * SE

So, we have

CI = (-17.1 + 16.0) ± 1.645 * 0.86

This gives

CI = -1.1 ± 1.41

Expand and evaluate

CI = (-2.51, 0.31)

Hence, the confidence interval is -2.51 to 0.31

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To prove that the function f: Z → Z given by f(x) = x^3 is bijective, we need to show that it is both injective (one-to-one) and surjective (onto).

1. Injective (One-to-One): A function is injective if for any x1, x2 in the domain Z, f(x1) = f(x2) implies x1 = x2. Let's assume f(x1) = f(x2). This means x1^3 = x2^3. Taking the cube root of both sides, we get x1 = x2. Thus, the function is injective.

2. Surjective (Onto): A function is surjective if, for every element y in the codomain Z, there exists an element x in the domain Z such that f(x) = y. For this function, if we let y = x^3, then x = y^(1/3). Since both x and y are integers (as Z is the set of integers), the cube root of an integer will always result in an integer. Therefore, for every y in Z, there exists an x in Z such that f(x) = y, making the function surjective.

Since f(x) = x^3 is both injective and surjective, it is bijective.

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Answer:

C and E

Step-by-step explanation:

Answer:

Step-by-step explanation:

divide them both by 2

which is 3/ 9

divide them both by 3

whic is 2/6

and finally divide them both by 6

which is 1/3

you can multiply them both by an number as well

take care

A time series refers to an ordered sequence of numerical data obtained at equidistant time intervals. These data can be analyzed and interpreted to identify significant trends and patterns. For instance, a centered moving average is one of the most commonly used time series techniques in statistics.

A time series refers to an ordered sequence of numerical data obtained at equidistant time intervals. These data can be analyzed and interpreted to identify significant trends and patterns.

For instance, a centered moving average is one of the most commonly used time series techniques in statistics.

It involves computing the average of a specific number of adjacent data points, known as a window size, centered on the data point under investigation.
For example, in the question above, the centered moving average for Q4-2020 can be calculated as follows:
Step 1: Add the Q3, Q4 of 2019, and Q1 of 2020.
116 + 319 + 240 + 284 = 959
Step 2: Add the Q1, Q2, and Q3 of 2020.
127 + 346 + 235 = 708
Step 3: Compute the centered moving average of Q4-2020.
Centered Moving Average = (959 + 708 + 284)/3 = 650.33
Therefore, the centered moving average for Q4-2020 is 650.33.

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A rectangle that is not a square has two pairs of sides of different lengths.

When it is rotated counterclockwise about its center, the longer sides will eventually become the shorter sides, and vice versa.

The minimum positive number of degrees it must be rotated until it coincides with its original figure is 180 degrees.

This is because after a rotation of 180 degrees, the longer sides will become the shorter sides and vice versa, and the rectangle will be in the exact same position and orientation as it was originally.

Any rotation less than 180 degrees will result in a mirror image of the original rectangle.

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Answer:

No

Step-by-step explanation:

Each output can only have one input ( 2 and 10 both go into 2)

A Negative correlation coefficient means that as one variable increases, the other decreases (i.e., an inverse relationship).

The answer of the given question based on the triangle is , - 15.75 ,  this is not possible as the length cannot be negative.

We are given:

In ΔCDE, the measure of ∠E = 90°, CD = 9.2 feet, and DE = 8.3 feet.

To find:

The measure of ∠C to the nearest tenth of a degree.

Solution:

In ΔCDE, applying Pythagoras theorem:

CE² + CD² = DE²CE² + (9.2)² = (8.3)²

CE² = (8.3)² - (9.2)²CE²

= 68.89 - 84.64CE²

= - 15.75

This is not possible as the length cannot be negative.

Hence, the given values are not possible.

So, there is no such triangle ΔCDE, which satisfies the given conditions.

Hence, we cannot find the measure of ∠C.

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Using the z-distribution, as we are working with a proportion, it is found that the margin of error for a 95% confidence interval would be of 0.0008.

A confidence interval of proportions is given by:

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which:

The margin of error is given by:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In this problem, we have a 95% confidence level, hence\(\alpha = 0.95\), z is the value of Z that has a p-value of \(\frac{1+0.95}{2} = 0.975\), so the critical value is z = 1.96.

Considering the 99% confidence interval, which has z = 2.575, the estimate and the sample size are given by:

\(\pi = \frac{0.67 + 0.74}{2} = 0.705\)

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

\(0.74 - 0.705 = 2.575\sqrt{\frac{0.705(0.295)}{n}}\)

\(0.035 = 2.575\sqrt{\frac{0.705(0.295)}{n}}\)

\(0.035\sqrt{n} = 2.575\sqrt{0.705(0.295)}\)

\(\sqrt{n} = \frac{2.575\sqrt{0.705(0.295)}}{0.035}\)

\((\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.705(0.295)}}{0.035}\right)^2\)

\(n = 1126\)

Hence, the margin of error is given by:

\(M = 1.96\sqrt{\frac{0.705(0.295)}{1126}} = 0.0008\)

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Answer:

Option 2

 x     y

−3     0

−1      3

 0     4

 3     0

4 3

Step-by-step explanation:

For a relation x →  y to be a function, there can be one and only one value of y for a value of x

Looking at the tables we see that option 1 is out since all x values are 2 andthere are multiple values of y

The last option is out because for x = 0 there are two values of y=-2 and y = 2

Correct choice is the second option which has a unique y value for each value of x

Answer:

option 2 im doing it rn

Step-by-step explanation: