two carts of masses 1 kg and 2 kg travel together, as shown in Figure 1. At time t = 2s, a compressed spring inside the 2kg cart expands, and the carts seperate. Figure 2 shows a graph of the carts' velocities as a function of time. What is the magnitude of the change in linear momentum, if any, of the two cart system between t = 0s and t = 4s.

Answers

Answer 1

Between t = 0s and t = 4s, the amount of the change in linear momentum of the two cart system is 4 kgm/s.

How to calculate linear momentum?

Since the carts move together before time t = 2s, the initial momentum of the system is:

p₁ = (1 kg + 2 kg) v = 3v

where v = common velocity of the carts.

After the spring expands, the carts separate and move with different velocities. At t = 4s, the 1kg cart has a velocity of 6 m/s and the 2kg cart has a velocity of 2 m/s.

The final momentum of the system is:

p₂ = (1 kg)(6 m/s) + (2 kg)(2 m/s) = 10 kgm/s

The change in momentum of the system is:

Δp = p2 - p1 = 10 kgm/s - 3v

Find v to calculate the magnitude of Δp. From the graph in Figure 2, the velocity of the system is zero at t = 2s. Therefore, slope of the graph at t = 2s is the average acceleration of the system between t = 0s and t = 2s:

a = (0 m/s - v)/2s = -v/2

The velocity of the system at t = 4s is 2 m/s, so the acceleration between t = 2s and t = 4s is:

a = (2 m/s - 0 m/s)/(4 s - 2 s) = 1 m/s²

Using the kinematic equation v = v0 + at, we can find v at t = 4s:

2 m/s = 0 m/s + (1 m/s²)(2 s)

v = 2 m/s

Now calculate the magnitude of Δp:

Δp = 10 kgm/s - 3v = 4 kgm/s

Therefore, the magnitude of the change in linear momentum of the two cart system between t = 0s and t = 4s is 4 kgm/s.

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Related Questions

What is the displacement of a car that travels 20 km west and then 5 km east?

Answers

The answer would be 15km west

The displacement of a car that travels 20 km west and then 5 km east is 5 km west. Displacement is a measure of the change in position of an object, and it is calculated by taking the final position of the object and subtracting its initial position. In this case, the car starts at an initial position and travels 20 km west, so its final position is 20 km west of its starting point. Then, the car travels 5 km east, which brings it back to its starting point. Therefore, the displacement of the car is 5 km west, as it has moved 5 km west of its starting point during its journey.

how does the speed of the vertically launched sphere compare to the speed of the horizonally launched sphere as they hit the dloor

Answers

The speeds of the vertically launched sphere and horizontally launched sphere will not necessarily be the same when they hit the floor, even if they are launched from the same height and at the same initial speed.

When a sphere is launched vertically upwards, it will slow down due to the force of gravity acting against it, until it reaches the highest point of its trajectory and momentarily stops. Then, it will accelerate back downwards towards the ground, increasing in speed until it hits the floor. The speed at which it hits the floor will depend on its initial speed, the height it was launched from, and the acceleration due to gravity.

On the other hand, when a sphere is launched horizontally, it will continue to move at a constant speed in the horizontal direction, while also being accelerated downwards due to the force of gravity. The resulting motion is a projectile motion with a parabolic trajectory. The speed at which it hits the floor will depend on its initial horizontal speed, the height it was launched from, and the acceleration due to gravity.

Therefore, the speeds of the vertically and horizontally launched spheres when they hit the floor will depend on a variety of factors and cannot be determined without more information about the specific conditions of the launches.

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An object is NOT accelerating. Is its motion changing?
Yes or No?

Answers

nope because if it’s not accelerating that means it’s stationary

Answer:

Acceleration is 0. Acceleration is the change in velocity over time, so if acceleration is 0, the change in velocity is 0 no matter how much time passes. THIS DOES NOT MEAN VELOCITY IS 0. it only means that velocity is constant. In other words, the speed of motion will not change

Explanation:

if you changed the source wavelength to a longer wavelength, e.g. 600nm, how would the distance between the zero order maximum and the third order maximum change?

Answers

If you change the source of wavelength to a longer wavelength (e.g. 600 nm), the distance between the zero order maximum and the third order maximum will decrease, since the numerator (λ) has increased.

The distance between the zero order maximum and the third order maximum in a diffraction pattern depends on the wavelength of the light and the size of the diffraction grating.

If you change the source wavelength from a shorter wavelength to a longer wavelength, the distance between the zero order maximum and the third order maximum will decrease. This is because the distance between the maxima in a diffraction pattern is inversely proportional to the wavelength of the light.

In mathematical terms, if 'd' is the distance between the maxima, 'λ' is the wavelength, and 'n' is the order of the maximum, then the relationship between these quantities is given by:

d = λ / (n × sinθ)

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14. If we change how fast an object is going and change its mass then we
have changed its...

Answers

Answer:

Momentum

Explanation:

If we change how fast an object is going and change its mass, then we have changed its momentum.

The momentum of body is the quantity of motion such a body can possess.

It is mathematically expressed as:

   Momentum  = mass x velocity

Therefore, if we vary mass and velocity or either of them, then, the momentum of the object will also change.

Mass and velocity is very crucial to the momentum of a body.

What causes the phenomena?

Answers

Answer:

Most pneumonia occurs when a breakdown in your body's natural defenses allows germs to invade and multiply within your lungs.

Explanation:

PLEASE HELP ASAP ILL GIVE U BRAINLIEST

An object is pulled to the left by a force of 100 N and to the right by a force of
80N. What is the net force acting on the object?

Answers

Answer: 20 N

Explanation: Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).

What two things affect the strength of gravity?
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Full answer please
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Best and most informative answer gets Brainliest and a thanks on your profile as well as a five-star review
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Thank you for your help <3

Answers

Answer: The size of an object and the distance between the objects.

Explanation: Gravity is affected by the size of an object and the distance between the objects. When the mass of an object increases the force of gravity increases as well. If an object's weight is greater than the other object's weight, then the object with the greater weight will land first.

Answer:

The factors that affect gravitation are

Mass of the bodiesDistance if seperation between them

Explanation:

Gravity is the force that gives weight to objects and causes them to fall to the ground when dropped. Two major factors, mass and distance, affect the strength of gravitational force on an object. You witness the first factor in everyday life - more massive objects are heavier. The second factor, distance, is less familiar, as it takes a distance of many thousands of kilometers to significantly weaken the pull of Earth's gravity. Newton's law of gravitation describes very accurately how mass and distance affect the force of gravity.

A person sitting on the outer edge of a merry-go-round travels _____________ a person sitting near the center.

Answers

Answer:

It’s fun

Explanation:

If a person sitting on the outer edge of a merry-go-round travels at a greater speed than a person sitting near the center because the linear velocity is a product of the angular velocity and the perpendicular distance from the center .

What is an uniform circular motion?

It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion .

Because the linear velocity is a function of the angular velocity and the perpendicular distance from the center .

Thus, the person seated on the outside edge of a merry-go-round will move more quickly than a person seated near the center .

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Write the importance of international bureau of weights and measurement.​

Answers

Answer:

The importance of international bureau of weights and measures are;

1. to bring unification of measurement system.

2. to establish and preserve fundamental international prototypes.

3. to verify national standards, etc.


What is the difference between physical and chemical changes?

Answers

Answer:

A

Explanation:

Chemical is a reaction between 2 things signs of that would be a new color, a new substance formed, or any sign of bubbles/smoke etc. while physical changes are done on purpose such as ripping a paper or cutting a log in half! hope that helped

a cheetah goes from standing still to running at 60 mph in 3 seconds. what is the cheetahs acceleration in standard international units?

Answers

Hang on...

Initial velocity (u) : 0mph = 0m/s (rest)
Final velocity (v) : 60mph = 26.822 m/s
Time taken (t) : 3 seconds

Now,

Acceleration= (v-u)/t

= 26.822 - 0 / 3
= 8.94

Therefore the acceleration is 8.94 m/s^2

The acceleration of the cheetahs in the standard international units would be 8.938 meters/second².

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem a cheetah goes from standing still to running at 60  miles per hour in 3 seconds

1 mile = 1609 meters

60 miles = 60×1609 meters

               =96540 meters

1 hour = 3600 seconds

       

the initial velocity of the cheetah = 0

the final velocity of the = 96540/3600

                                      =26.8166 meters/seconds

acceleration = (final velocity - initial velocity) /time period

                    =(26.8166 -0)/3

                    =8.938 meters/second²

Thus, the cheetah's acceleration would be 8.938 meters/second².

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PLEASE ANSWER QUICKLY
Which of the following best describes the make up of a star?
Answers
•a collection of particles held together by gravity
•a body in orbit
•a cloud of dust and gas
•a luminous ball of plasma

Answers

Answer:

a luminous ball of plasma

Elmo finds himself at a Coke machine on a hot and dusty Sunday. The Coke machine requires exact change—two quarters and a dime. No other combination of coins will make anything come out of the machine. No stores are open; no one is in sight. Elmo is so thirsty that the only thing he cares about is how many soft drinks he will be able to buy with the change in his pocket; the more he can buy, the better. While Elmo searches his pockets, your task is to draw some indifference curves that describe Elmo’s preferences about what he finds.

(a) If Elmo has 2 quarters and a dime in his pockets, he can buy 1 soft drink. How many soft drinks can he buy if he has 4 quarters and 2 dimes? 1

(b) Does Elmo have convex preferences between dimes and quarters?

(c) Does Elmo always prefer more of both kinds of money to less?

(d) Does Elmo have a bliss point?

(e) If Elmo had arrived at the Coke machine on a Saturday, the drugstore across the street would have been open. This drugstore has a soda fountain that will sell you as much Coke as you want at a price of 4 cents an ounce. The salesperson will take any combination of dimes and quarters in payment. Suppose that Elmo plans to spend all of the money in his pocket on Coke at the drugstore on Saturday. Draw one or two of Elmo’s indifference curves between quarters and dimes in his pocket. Describe these new indifference curves in words.

Answers

The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.

(d) No bliss point. and, (e) Steeper indifference curves.

(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.

(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.

(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.

(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.

(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.

In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.

These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.

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What is the weight of a 5.5kg bowling ball

Answers

Answer:

2.205 pounds

Explanation:

5.5 kg is 2.205 lbs. hope this helps!

GIVING BRAINLIEST
In addition to having a blue color, what other characteristic do Neptune and Uranus share?

no rings
27 moons
no axis tilt
cold temperatures

Answers

Answer:

Cold temps. . .

Explanation:

Hope it helps!

A 2130 kg car, moving at 21.5 m/s, runs into a car that has a mass of 2240 kg
and is moving at 11.4 m/s in the same direction. The cars stick together after
the collision. Assuming momentum is conserved, what is their final velocity?
OA. 14.1 m/s
OB. 12.5 m/s
O C. 16.3 m/s
O D. 19.4 m/s

Answers

Answer:

  C.  16.3 m/s

Explanation:

You want to know the final velocity of the combined mass of a 2130 kg car at 21.5 m/s after collision with a 2240 kg car at 11.4 m/s in the same direction. Momentum is conserved.

Momentum

The momentum of each object is the product of its mass and velocity. When momentum is conserved, the momentum of the mass after the collision is the same as that before the collision.

  m1·v1 +m2·v2 = (m1 +m2)·v3

Then the velocity after the collision is ...

  v3 = (m1·v1 +m2·v2)/(m1 +m2)

You may recognize this as the weighted average of the initial velocities, where the weights are the respective masses of the objects.

  v3 = (2130·21.5 +2240·11.4)/(2130 +2240) ≈ 16.3

The final velocity is 16.3 m/s, matching choice C.

A 2130 kg car, moving at 21.5 m/s, runs into a car that has a mass of 2240 kgand is moving at 11.4 m/s

QUESTION 1
Describe the motion of the car in the following picture.
The car is slowing down.
The car is not moving.
The car is speeding up
The car is moving at a constant velocity

QUESTION 1Describe the motion of the car in the following picture.The car is slowing down.The car is

Answers

Answer:the car is speeding up

Explanation:

Help pls Important!!!!

Help pls Important!!!!

Answers

No,plate motion would not take place on that planet.

A car starts from rest and accelerates at a rate of 5 m/s2 for 5 seconds. What is the velocity of the car?

Answers

Please find attached photograph for your answer.

A car starts from rest and accelerates at a rate of 5 m/s2 for 5 seconds. What is the velocity of the

The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz

Answers

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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a 12.0 v battery is placed across a 4.00 ω resistor. if the current through the resistor is 2.80 a, what is the terminal voltage of the battery?

Answers

If the current through the resistor is 2.80 A the terminal voltage of the battery is 23.2 V.

We can use Ohm's law to find the voltage drop across the resistor:

V = IR

Where V is the voltage drop, I is the current through the resistor, and R is the resistance.

Substituting the given values, we get:

\(V = (2.80)*(4.00) = 11.2 V\)

This is the voltage drop across the resistor. The voltage across the battery terminals will be higher than this by the amount of the battery's internal resistance, which we can assume to be negligible. Therefore, the terminal voltage of the battery is:

\(V_{Ter} = V + V_r\)

Where \(V_r\) is the voltage drop across the resistor.

\(V_{Ter}= 11.2 V + 12.0 V = 23.2 V\).

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How do you calculate velocity?
a) Distance divided by time.
b) Displacement dided by time.
c) Speed multiplied by
time.
d) Displacement divided by velocity.

Answers

Answer:

A

Explanation:

Answer:

Distance divided by time

Explanation:

What is the magnitude of the gravitational force between an electron and a proton separated by a distance of 1.0 x 10-10 meter?

Answers

A proton and electron separated by 1.0 x 10-10 meters exert 1.0 x 10-47N of gravitational force on each other.

What exactly is gravitational, in simple terms?

The gravitational force will bring together any two mass-containing objects. The gravitational force is described as attracting because it consistently tries to draw masses together and never tries to push them apart. In reality, you and every other item in the universe are pulling toward one another.

What is the origin of gravity?

All of the mass on Earth is what creates gravity. The cumulative gravitational attraction of all of its mass exerts pressure on all of the body's mass. Your weight is determined by that. Furthermore, your weight would be lower if you were on a planet with a lower mass than Earth.

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Consider the ideal Otto, Stirling, and Carnot cycles operating between the same temperature limits. How would you compare the thermal efficiencies of these three cycles?

Answers

The efficiencies of the Carnot and the Stirling cycles would be the same, but the efficiency of the Otto cycle would be less.

The Carnot cycle is a theoretical thermodynamic cycle that is often used as a benchmark for the efficiency of heat engines. It was developed by French physicist Sadi Carnot in the early 19th century and is based on the idea of a reversible engine, which can be thought of as an idealized engine that operates with no energy losses.

The Carnot cycle consists of four reversible processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. The cycle operates between two heat reservoirs, one at a higher temperature and one at a lower temperature. The engine absorbs heat from the high-temperature reservoir during the isothermal expansion process, converts some of the heat to work during the adiabatic expansion process, rejects heat to the low-temperature reservoir during the isothermal compression process, and finally converts some of the remaining heat to work during the adiabatic compression process.

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listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence of dark energy. rank each model from left to right based on the ratio of its actual mass density to the critical density, from smallest ratio (mass density much smaller than critical density) to largest ratio (mass density much greater than critical density).

Answers

Open, flat, and closed universes are the three forms of expanding universes that are theoretically possible. The universe would always grow if it were open.

What long-term expansion universe in lack of dark energy?

If the universe were flat, it would also continue to expand indefinitely, but the rate of growth would eventually reduce to zero.

One is the red-shift phenomenon, which shows that the cosmos is expanding. Cosmic microwave background radiation is the second type. The universe's abundance of various elements is the third.

The majority of astronomers think that dark energy is a type of substance with an inverse gravity that repels matter from its vicinity.

Therefore, According to scientific theories, this is what is causing the universe to expand and to push stars, planets, and galaxies apart.

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Calculate the gravitational force of the Earth and Moon. The Earth has a mass of 5.972x 1024 kg and the Moon has a mass of 7.348x 1022 kg. They are an average of 384 million meters apart.

Answers

Answer:

The force of gravitation is 1.98×10^(20) m.

Explanation:

Note: The value of m1, m2, r, and G is taken to be 5.97×10^(24) kg, 7.348×10^(22) kg, 3.84×10^(8) m, and 6.67×10^(-11) N m^2/ kg^2 respectively.

The force of gravitation F acting between two masses is calculated using the formula,

F=Gm1m2/ r^2

where G is the gravitational constant.

Hence force F is

F=6.67×10^(-11)×5.97×10^(24)×7.348×10^(22)/ (3.84×10^(8))^2

F=1.98×10^(20) N

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Identify the following major moons of Jupiter.
A. Europa
B. Ganymede
C. Io
D. Callisto

Answers

These are the four largest moons of Jupiter and are collectively known as the Galilean moons. They were discovered by Galileo Galilei in 1610 and are named after characters from Greek mythology. Europa, Ganymede, Io, and Callisto are all fascinating celestial bodies with unique features and scientific significance

Europa is known for its subsurface ocean that may harbour conditions suitable for life, Ganymede is the largest moon in the solar system, Io is the most volcanically active object in the solar system, and Callisto is heavily cratered and geologically diverse. These moons have been studied extensively by spacecraft missions such as NASA's Galileo and Juno missions, providing valuable insights into the nature of Jupiter's moons and their geological processes. The major moons of Jupiter are Europa, Ganymede, Io, and Callisto. The major moons of Jupiter are Europa, Ganymede, Io and Callisto.

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A submarine is 58.8 m from a whale. The sub sends out a sonar ping to locate the whale. The speed of sound underwater is 1520 m/s. How much time does it take for the sound wave to travel to the whale and back? (Unit = s)

Answers

Answer:

0.08

Explanation:

this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.

The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this

t = 2d/v

t = 2*58.8/1520

t = 117.6/1520

t = 0.077368 s

t ≈ 0.08 s (less then 1 s)

Answer:

0.0774s

Explanation:

The formula to find the time of an echo is time = (2)(distance) / (velocity)

So plug in the numbers to the formula

(2)(58.8) / (1520)

= 0.0774s

please answer!! If an object has a mass of 22.3 kg and is accelerating at 8 km/hr°2, what is its force? (Be sure
to label your answer.)

Answers

Answer:

49.06 Newtons

Explanation: Using Newton's Second Law of Physics, F=ma

the mass of the car is 22.3kg and the acceleration of the object is 2.2m/s^2 then you would multiply the two and get 49.06 Newtons. You want the acceleration to be in m/s^2

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