In the drag race between Alison and Kevin, Alison wins by 1 second.Let's denote the total distance of the race as "d" and the constant accelerations of Alison and Kevin as "a" and "b," respectively. Since both drivers start from a standing position, their initial velocities are zero.
According to the given information, Alison covers the last 1/4 of the distance in 3 seconds, while Kevin covers the last 1/3 of the distance in 4 seconds.
Let's calculate the time it takes for Alison to cover the last 1/4 of the distance:
Since the distance covered is 1/4 of the total distance, we can write:
1/4 * d = (1/2) * a * (3^2)
d = 9a/2
Similarly, for Kevin, the time it takes to cover the last 1/3 of the distance is:
1/3 * d = (1/2) * b * (4^2)
d = 8b/3
Since both expressions represent the same total distance, we can equate them:
9a/2 = 8b/3
Simplifying the equation, we find:
27a = 16b
From this equation, we can see that Alison's acceleration is greater than Kevin's. Therefore, Alison reaches the finish line before Kevin, winning the race.
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Think back to when you were a kid riding in the backseat of the car. Maybe you once had a milkshake in your hand when your mom hit the brakes. You were secured by your seat belt, but you jer-ked forward and the milkshake splashed all over the front seat…and your mom. That situation probably never happened to you. But think about something that has happened to you physically—a fall, a jump, an accident, or something you may have done hundreds of times in your favorite sport. Analyze the action and describe it in terms of Newton’s laws. Identify the initial conditions and the forces involved. If the action is a sequence of events, analyze it step by step. The more complex the sequence of events, the better!
Answer:
In Newton’s first law, an object at rest remains at rest until an external force isapplied. When I play soccer, the soccer ball will be at rest on the field (the initial condition) andremain in that spot on the field until I kick it (my muscles applying an external force to the ball).According to Newton’s second law, force = mass x acceleration (F=ma). When I kick the resting soccer ball, which has a given mass, it will accelerate in the direction that I kick it. From the equation, acceleration = force divided by mass. Therefore, since the mass of the soccer ball is fixed, the stronger my leg is and the more force I can apply to the ball, the faster it willaccelerate.According to Newton’s first law, an object in motion remains in motion until an external force isapplied. After I kick the soccer ball, it will continue in motion in the direction that I kicked it,but its acceleration will gradually slow down due to the external forces of friction from the airand the surface of the field. According to Newton’s third law, for every action there is an equal and opposite reaction.When I kick the soccer ball forward, if I also kick it in an upward direction, such as a thirty-degree angle from the field, it will come down at an angle when it strikes the field. When theball lands and strikes the field, there will be an equal and opposite reaction whereby instead oftraveling downward it will bounce of the surface of the field and will then be travelling upward.
Assume we have an RC circuit and an RL circuit. The RC circuit has a capacitor C = 10 nF and a sensing resistor of R = 1, 200 Ohm. The RL circuit has a sensing resistor R = 1, 200 Ohm and an inductor with L = 15 mH and RL = 130 Ohm. The input voltage in both cases is a square wave. For the RC circuit, what is the value of the time constant τ? How about for the RL circuit? For the RC circuit and the RL circuit, assume that the period of the source square wave is much larger than the time constant for each. Make a sketch of vR(t) as a function of t for each of the circuits Starting from the equation for voltage, Equation (56), show that τ = t1/2/ln(2) = 1.443 t1/2.
For RC circuit: the value of the time constant τ is 12 μs.
For RL circuit: the value of the time constant τ is 0.115 ms.
It is proved that, τ = t1/2/ln(2) = 1.443 t1/2. This shows that the time constant is directly proportional to the square root of the half-life of the voltage decay.
For the RC circuit, the time constant τ is given by:
τ = RC = (10 nF)(1,200 Ω) = 12 μs
For the RL circuit, the time constant τ is given by:
τ = L/RL = (15 mH)/(130 Ω) = 0.115 ms
Now, for the RC circuit, the voltage across the capacitor can be given by:
vC(t) = Vmax(1 - e^(-t/τ))
where Vmax is the maximum voltage of the square wave, τ is the time constant, and t is the time. The voltage across the resistor is equal to vR(t) = vC(t), since the capacitor and resistor are in series.
For the RL circuit, the voltage across the resistor can be given by:
vR(t) = Vmax(1 - e^(-t/τ))
where Vmax is the maximum voltage of the square wave, τ is the time constant, and t is the time.
To show that τ = t1/2/ln(2), we start with the equation for voltage across the capacitor in the RC circuit:
vC(t) = Vmax(1 - e^(-t/τ))
Let t = τ, then we have:
vC(τ) = Vmax(1 - e^(-1))
vC(τ) = 0.632 Vmax
Now, let t = t1/2, then we have:
vC(t1/2) = Vmax(1 - e^(-t1/2/τ))
vC(t1/2) = Vmax(1 - e^(-1/2))
vC(t1/2) = 0.393 Vmax
The voltage across the resistor at t = τ and t = t1/2 can be found using the same equations as above.
Now, the half-life t1/2 is defined as the time it takes for the voltage to decay to half of its initial value. Thus, we have:
t1/2/τ = ln(2)
Solving for τ, we get:
τ = t1/2/ln(2) = 1.443 t1/2
This shows that the time constant is directly proportional to the square root of the half-life of the voltage decay.
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A projectile of mass 0.419 kg is shot from
a cannon, at height 6.2 m, as shown in the
figure, with an initial velocity v; having a
horizontal component of 6.7 m/s.
The projectile rises to a maximum height
of 1.6 m above the end of the cannon's barrel
and strikes the ground a horizontal distance
past the end of the cannon's barrel.
Find the magnitude of the initial vertical
velocity vector of the cannon-ball at the end
of the cannon's barrel. The acceleration of
gravity is 9.8 m/s².
The projectile's top height is indicated by the number h. Max equals u squared x divided by 2 g. In this case, the initial horizontal velocity is maximized by u square at a rate of 6 meters per second square.
Find height?The projectile's top height is indicated by the number h. Max equals u squared x divided by 2 g. In this case, the initial horizontal velocity is maximized by u square at a rate of 6 meters per second square.
This rate is then multiplied by two to get 9.8 meters per second square, which equals 1.84 meters.
The projectile can only fly as high as this, then. Here, we already know that the projector is located at a distance of h from the ground, which is the height the projectile has reached from ground level. Please excuse the distance, the cannon is h feet above the ground.
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A car travels at a constant speed of 40 miles per hour down the street for around 0.25 hours. What is its acceleration?
Answer:
55
Explanation:
was moving at 25 miles per hour
An electron moves in an electric field. Does it move toward regions of higher potential or lower potential? explain.
The electric fields is always directed from higher potential to the lower potential.
An electron moves in an electric field. Does it move toward regions of higher potential or lower potential?
The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.
An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.
So we can conclude that the electric fields is always directed from higher potential to the lower potential.
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an object is executing simple harmonic motion. what is true about the acceleration of this object? (there may be more than one correct choice.)
The correct choices regarding the acceleration are: 1. The acceleration is a maximum when the object is instantaneously at rest, 4. The acceleration is a maximum when the displacement of the object is zero.
In simple harmonic motion (SHM), the acceleration of the object is directly related to its displacement and is given by the equation a = -ω²x, where a is the acceleration, ω is the angular frequency, and x is the displacement.
1. The acceleration is a maximum when the object is instantaneously at rest:
When the object is at the extreme points of its motion (maximum displacement), it momentarily comes to rest before reversing its direction. At these points, the velocity is zero, and therefore the acceleration is at its maximum magnitude.
2. The acceleration is a maximum when the displacement of the object is zero:
At the equilibrium position (where the object crosses the mean position), the displacement is zero. Substituting x = 0 into the acceleration equation, we find that the acceleration is also zero.
Therefore, the acceleration is a maximum when the object is instantaneously at rest and when the displacement of the object is zero.
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the complete question is:
An object is moving in a straightforward harmonic manner. What is accurate regarding the object's acceleration? Pick every option that fits.
1. The object is instantaneously at rest when the acceleration is at its maximum.
2. The acceleration is at its highest when the object's speed is at its highest.
3. When an object is moving at its fastest, there is no acceleration.
4-When the object's displacement is zero, the acceleration is at its highest.
5-The acceleration is greatest when the object's displacement is greatest.
HELP ASAP THANKS
What happens to the mass of an object when the parts are rearranged?
Answer:
The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.
Hope it helps!!!
Answer:
their will be no change in this..
The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.
Explain how the unbalanced force acting on a cyclist changes as
they accelerate and they are cycling at a constant speed
As a result, a constant speed means that there are equal and opposite forces acting on it. The phrase "consistent speed and direction" is preferable.
How can an unbalanced force alter an object's speed?Because of unequal power or strength delivered to one side of an item, an imbalanced force causes a change in motion, speed, direction, or movements. In the situation of unbalanced forces, one side has more energy than the other, despite the fact that opposing sides have forces working against them.
How is the bicycle being affected by an unbalanced force?The force of friction generated by a bicycle's tyres against the road is larger than the force of friction generated by the air in opposition. The bicycle advances.
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Which of the following is the best definition of lifestyle activity?
a
Recreational activities such as bowling or canoeing
b
Light or moderate activities you do as part of your daily life
c
Winter activities such as snowboarding
d
Vigorous activities like a HIIT workout
Help me as pleasessss help with 1,2 and 3
17. A 100 kg CAR TRAVELS AT 11 m/s. WHAT AMOUNT OF WORK WOULD BE REQUIRED TO
BRING IT TO A SPEED OF 5 m/s?
A. 1045 J
B. -1045 J
C. 4800 J
D. -4800 J
18. A 70 kg ICE SKATER GLIDES AT A SPEED OF 6 m/s ACROSS THE ICE. DETERMINE THE
SKATER'S KINETIC ENERGY.
A. 420 J
B. 1260 J
C. 210 J
D. 105 J
Explanation:
17) the amount of work needed in Joules will be equal to the change in Kinetic Energy (1/2 m v^2) of the car
1/2 (100 kg) ( 5 ^2 - 11^2 ) = -4800 J
18) K E = 1/2 m v^2 = 1/2 * 70 * 6^2 = 1260 J
What will be the extension of a spring with a spring constant of 3N/m if a 15N force is applied?
the lead nucleus has a diameter of 14.2 fm . what is the density of matter in a lead nucleus?
The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.
Lead nucleus is composed of protons and neutrons. The density of a nucleus is the mass of a nucleus divided by the volume occupied by the nucleus. The volume of a nucleus can be determined using the formula
(4/3)πr³,
where r is the radius of the nucleus. As the diameter of a lead nucleus is given as 14.2 fm, the radius of a nucleus can be calculated as follows:
radius = diameter/2
= 14.2 fm/2
= 7.1 fm
Hence, the volume of a lead nucleus can be calculated as:
(4/3)πr³ = (4/3)π(7.1 fm)³
= 1.57 x 10⁻⁴ fm³
As the mass of a lead nucleus is 3.15 x 10⁻²⁵ kg, the density of matter in a lead nucleus can be calculated as follows:
Density = Mass/Volume
= 3.15 x 10⁻²⁵ kg/1.57 x 10⁻⁴ fm³
= 2.82 x 10¹⁷ kg/m³
The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.
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A particle of mass m=5x10^-27 kg has an initial speed of 2x105 m/s. The particle travels in a straight line and its speed increases to 4x10^5 m/s on a distance of 10 cm. Assuming that the acceleration is constant, the
force exerted on the particle is:
3x10^-15 N
3x10^-20 N
8.65x10^-23N
1.73x10^-22 N
Answer:
Explanation:
Given:
m = 5·10⁻²⁷ kg
V₁ = 2·10⁵ m/s
V₂ = 4·10⁵ m/s
D = 10cm = 0.10m
_______________
a - ?
The change in kinetic energy is equal to the work:
Ek₂ - Ek₁ = F·D
m·V₂² / 2 - m·V₁² / 2 = F·D
(m/2)·(V₂² - V₁²) = F·D
Force:
F = (m/2)·(V₂² - V₁²) / D
F = m·(V₂² - V₁²) / (2·D)
F = (5·10⁻²⁷)·( (4·10⁵)² - (2·10⁵))/ (2·0.10) ≈ 3·10⁻¹⁴ N
chuyển động đều là gì
Answer:Chuyển động đều là chuyển động có vận tốc không thay đổi theo thời gian
Explanation:
what is the difference between reproducibility and repeatability
Answer:
Repeatability is how much variability in the measurement system is caused by the measurement device. Reproducibility is how much variability in the measurement system is caused by differences between operators.
PLEASE HELP I PAY 88 POINTS AND THANK YOU AND BRAINLIEST
Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
Answer: Down below is the answer in complete sentences!
Explanation:
PART A:
Gravity and Acceleration are two additional forces acting upon the sled.
PART B:
Gravity will affect the sled by pulling it down, since the slope of the hill is negative.
Acceleration will affect the sled by gradually increasing it's speed, since the slope is downwards, which in addition to the initial force exerted plus gravity increases the speed, thus the sled accelerates.
A beaker of water is sitting on a sensitive spring scale. If you dip your finger into the water, but do not touch the side of the beaker, and the beaker does not overflow, what happens to the reading of the scale? (part of your finger is completely underwater. ) 1. It depends on just how much of your finger is submerged. Unless we are told, we can't answer. 2. The reading of the scale increases because of the extra pressure. 3. The reading of the scale remains precisely the same, of course. 4. It depends on how deep the water is. In some cases, the scale reading might increase, in other cases it might decrease. 5. The reading of the scale decreases
The reading of the scale will increase.
Our fingers push away the water in the cup which requires a lot of force. The scale should apply the same force to your finger. This force increases the reading on the scale. The scale display will rise. When a finger is submerged, the water exerts an upward buoyant force on the finger.
According to Newton's third law fingers exert equal and opposite forces on water. The spring scale reading decreases until the object is completely submerged. The reading, therefore, shows the apparent weight of the stone, which is less than its actual weight. Heavy metals are denser than water and will sink in water, so putting heavy metals in water will change the reading on the spring scale.
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When a baseball is hit, it travels around 65 mps (meters per second). the mass of the baseball is 0.145 kg. what is the kinetic energy of the baseball?
Answer:
306J
Explanation:
The formula for kinetic energy is given as ½mv².
Using this, we get our answer by substituting the values into the formula.
½ × 0.145kg × 65m/s
= 306.31J
can be rounded off to 306J
therbligs are: the smallest unit of time used in methods time measurement exercises. the largest unit of time used in methods time measurement exercises. basic physical elements of motion as used in methods time measurement exercises. the full range of motions required to complete a job as used in methods time measurement exercises. the smallest amount of time required to complete a job.
Therbligs are basic physical elements of motion used in methods time measurement exercises to analyze and measure work processes. They represent the smallest unit of time and the full range of motions required to complete a job.
Therbligs were introduced by Frank B. Gilbreth, an industrial engineer, as a means to analyze and improve work processes. They are used in methods time measurement exercises to break down a task or job into its fundamental motions. Each therblig represents a specific basic physical element of motion, such as grasp, position, release, search, transport, and so on. These elements can be combined in different sequences to represent the full range of motions required to complete a job. Therbligs are used to measure the time required to perform each individual motion, and by summing up the times for all therbligs involved, the total time to complete a job can be determined. By analyzing the therbligs involved in a task, engineers can identify inefficiencies, eliminate unnecessary motions, and streamline work processes to increase productivity and reduce fatigue or strain on workers.
Therefore, therbligs serve as a standardized method for measuring and evaluating work processes, allowing for improvements in efficiency and productivity. They represent both the smallest unit of time used in methods time measurement exercises (individual motions) and the largest unit of time (the full range of motions required to complete a job).
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A football field is 52 yards wide by 112 yards long. What is the area
Answer:
5824 yards^2
Explanation:
area = length x width
area = 112 x 52
area = 5824
Answer:
5824 squared yards
Explanation:
a physics instructor conducts a projectile motion demonstration. The device used will drop one steel ball and horizontally launch another. If no air resistance is presented which steel ball, the one launced or the one dropped, striked the ground first?
(a) The launched ball
(b) The dropped ball
(c) both hit a the same time
(d) neither hit the ground
Answer:
Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory. The motion of falling objects, as covered in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of projectile motion in which there is no horizontal movement. In this section, we consider two-dimensional projectile motion, such as that of a football or other object for which air resistance is negligible.
Explanation:
B the dropped ball
A pogo and rider of 80 kgkg total mass at the high point of a 2.0 mm jump will drop 1.5 mm before the pogo plunger touches the ground, slowing to a stop over an additional 0.40 mm as the elastic bands stretch. What approximate average force does the pogo stick exert on the ground during the landing
The approximate average force exerted by the pogo stick on the ground during the landing is 1960 N.
To calculate this force, we can use the principle of conservation of mechanical energy. The potential energy at the high point of the jump is converted into kinetic energy as the pogo stick descends.
The potential energy at the high point is given by the formula:
PE = m * g * h,
where m is the mass (80 kg), g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height (2.0 mm = 0.002 m).
PE = 80 kg * 9.8 m/s² * 0.002 m.
Next, we calculate the change in potential energy as the pogo stick descends:
ΔPE = PE_initial - PE_final,
where PE_initial is the potential energy at the high point and PE_final is the potential energy at the lowest point.
ΔPE = (80 kg * 9.8 m/s² * 0.002 m) - (80 kg * 9.8 m/s² * 0.0015 m).
The change in potential energy is converted into work done by the average force exerted on the ground. Since work is the product of force and distance, we can write:
ΔPE = F_avg * d,
where F_avg is the average force and d is the distance over which the force is applied.
Substituting the values:
(80 kg * 9.8 m/s² * 0.0015 m) = F_avg * (0.004 m).
Solving for F_avg:
F_avg = (80 kg * 9.8 m/s² * 0.0015 m) / (0.004 m).
F_avg ≈ 1960 N.
Therefore, the approximate average force exerted by the pogo stick on the ground during the landing is 1960 N.
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A plane is coming in to taxi at an airport. It lands parallel to the surface at 480m/s and takes exactly one minute to come to a complete stop. What is its acceleration?
The acceleration of the plane will be −8 m/s²
How to find the acceleration of a plane?
Acceleration is the rate of change in velocity over time (Δv/t).
Given, that the initial velocity of the plane u=480 m/s
The final velocity of the plane is zero after landing, v= 0 m/s
t= 1 minute= 60 seconds
we know, v=u + at
0= 480 + 60a
a=\(\frac{-480}{60}\) = -8m/s²
Thus, the acceleration of the plane is -8 m/s²
(negative acceleration implies that the object is slowing down)
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. ASSERTION: WHEN ASTRONAUTS THROW SOMETHING IN SPACE, THAT OBJECT WOULD CONTINUE MOVING IN THE SAME DIRECTION AND WITH THE SAME SPEED. REASON: THE ACCELERATION OF AN OBJECT PRODUCED BY A NET APPLIED FORCE IS DIRECTLY RELATED TO THE MAGNITUDE OF THE FORCE, AND INVERSELY RELATED TO THE MASS OF THE OBJECT.
Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.
The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.
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What is final velocity
Answer:
Final velocity is the velocity which the body has at the end of the given time period.
Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be:
A. the only remaining protoplanet in our solar system.
B. a planetesimal leftover from the solar system's formation.
C. a fragment of Mars.
D. one of the remnants of the planet that broke up to form the asteroid belt.
E. one of the dwarf planets in our solar system.
Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be: D. one of the remnants of the planet that broke up to form the asteroid belt.
Based on observations by the Dawn spacecraft, scientists have concluded that Vesta might be a planetesimal leftover from the solar system's formation. Vesta is one of the largest asteroids in the asteroid belt between Mars and Jupiter. Its unique characteristics and composition provide insights into the early stages of our solar system.
Dawn's data reveals that Vesta is differentiated, meaning it has distinct layers and a core, which is consistent with its formation as a planetesimal. The spacecraft detected evidence of volcanic activity, impact craters, and the presence of basaltic lava flows on Vesta's surface. These features suggest that Vesta experienced a significant amount of geologic activity in the past.
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Does the moon control the waves in the ocean?
Answer:
no don't think so
Explanation:
JESUS CHRIST controls everything 100IQ
No, the moon does not directly control the waves in the ocean. The primary factors that influence the formation of waves in the ocean are wind and the interaction between wind and the water's surface.
The moon, however, does play a significant role in influencing the tides, which are the periodic rise and fall of the ocean's surface.
The gravitational force exerted by the moon, as well as the sun to a lesser extent, creates tidal bulges on the Earth. As the Earth rotates, these tidal bulges move around the planet, resulting in the daily cycle of high tides and low tides.
The gravitational pull of the moon is stronger on the side of the Earth facing the moon, causing a high tide, while on the opposite side, a high tide also occurs due to the centrifugal force resulting from the Earth's rotation. The areas in between experience low tides.
While tides can affect the height and intensity of ocean waves near the coastlines, the actual formation and behavior of waves are primarily driven by wind patterns, water depth, and other factors such as underwater topography.
Waves are generated when the wind transfers its energy to the water's surface, creating oscillations that propagate as waves. These waves can travel vast distances across the ocean, even in the absence of tidal influences.
In conclusion, while the moon's gravitational pull influences the tides, it does not directly control or generate the waves in the ocean.
Waves are primarily driven by wind and other factors, whereas tides are the result of gravitational forces acting on the Earth's oceans.
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A force of 15 n is applied to a spring, causing it to stretch 0.3 m. what is the spring constant for this particular spring? n/m
Answer:
-50N/m
Explanation:
Force , F = 15N
Displacement , x = 0.3m
Spring constant , K = ?
K = -F/x
K = -15N/0.3m
K = -50N/m
Answer: 50 N/m
Explanation:
Edge 2022
Name two things that Arjun and Diya did to get accurate measurements of the angles in their experiment
Answer:
i dont know them
Explanation: