Two like charges of the same magnitude are 1 mm apart. If the force of repulsion they exert upon each other is 5 N, what is the magnitude of each charge? (The constant of proportionality for the Coulombic force is 9.0 x 109 N m2/C2)

Answer:

A pump draws water from reservoir A and lifts it to reservoir B as shown in Figure 4-10. The loss of head from A to 1 is 3 times the velocity head in the 150-mm pipe and the loss of head from 2 to B is 20 times the velocity head in the 100-mm pipe. Compute the horsepower output of the pump and the pressure heads at 1 and 2 when the discharge is: (a) 12 L/s; (b) 36 L/s.

Explanation:

Paki-check po kung tama, thank you :)

The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.

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Answer:

a = 2.25 m/s^2

Explanation:

The solution is in the image. Also, knowing this picture is from a Schoology assessment page, if this is a test, try to solve the question yourself before asking for help. Also, specify which part you need help on.

Answer: If i'm not mistaken I think it A) potential

The magnitude of Margaret's total displacement is approximately 0.5828 miles.

Since Margaret walked 0.370 miles towards the north direction, the y-component of her displacement is 0.370 miles.

Thus:

y-component = 0.370 miles

We can now find the magnitude of the displacement using the Pythagorean theorem.

The magnitude of displacement is given by:d = √(x² + y²)

Where,x is the x-component of the displacement, and y is the y-component of the displacement.

Substituting the values:

x = -0.450 m and y = 0.370 m

d = √((-0.450)²+ (0.370)²)

d = √(0.2025 + 0.1369)

d = √(0.3394)

d = 0.5828

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Among the variables mentioned, the most important factor that influences drag on an object in the experiments conducted is the object's area.

Drag is the force that opposes the motion of an object through a fluid (such as air or water). It depends on several factors, including the object's area, shape, speed, and the properties of the fluid. However, in the context of the experiments conducted, the area of the object is the most significant factor.

The larger the surface area of an object facing the fluid flow, the greater the drag force it experiences. This is because a larger area creates more resistance to the fluid, resulting in higher drag. Other variables mentioned, such as the length, roughness, specific gravity, material, and density of the object, may indirectly influence drag by affecting the object's shape or ability to streamline, but they are not as directly correlated to drag as the area.

By controlling the area of the object in the experiments, researchers can investigate the impact of drag on the object's motion. Altering the object's area allows for comparative analysis to understand how changes in surface area affect the drag force experienced, providing insights into fluid dynamics and the relationship between objects and their environment.

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In a downward direction, the magnitude of the acceleration is negative and velocity is zero.

Here,

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Answer:

C

Explanation:

Earth would be the answer. pluto is slowest. then Saturn, Jupiter, mars

Answer:

:))

The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling is:  F = μs * mg

To derive an expression for the minimum horizontal force (F) that must be applied to the block to keep it from falling to the ground, we will use the following terms: cart, roll without friction, coefficient of static friction (μs), and minimum horizontal force.

Assuming that the cart is free to roll without friction and the coefficient of static friction between the block and the cart is μs, we can analyze the forces acting on the block.

There are two forces acting on the block: gravitational force (mg) acting vertically downward and the static friction force (fs) acting horizontally opposite to the applied force. To keep the block from falling, the static friction force must balance the gravitational force.

Using Newton's second law of motion, we can write the equations for the horizontal and vertical components:

1) fs = μs * N (where N is the normal force)
2) N = mg (since there is no vertical acceleration)

Substituting equation (2) into equation (1), we get:

fs = μs * mg

The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling. Therefore:

F = μs * mg

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Answer:

Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.

Explanation:

Answer:

I guess it's force hope this answer helps

The velocity after two minutes is v = 616.67 m/s

Using the equation final velocity = beginning velocity + acceleration * time, the final velocity of this bus after two minutes is determined. Symbolically, v is represented as follows: vi = 60 km/h, a = 5 m/s2, and t = 2 minutes. First, we must translate 60 km/h into m/s. 50/3 m/s is equal to 60 km/h or 60,000 m/36 seconds.

When determining the final velocity, v

v = vi + a * t

120 seconds at v = 50/3 m/s + 5 m/s2

v = 50/3 m/s + 600 m/s

v = 16.67 m/s + 600 m/s

v = 616.67 m/s

After two minutes, the bus's speed is 616.67 m/s. For a bus, it is a pretty implausible velocity. The speed of this object is 2,220 km/h, exceeding the speeds of both air and jet aircraft. Your acceleration time should have been capped at 20 seconds or less.

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If a source of sound is traveling toward you, the speed of the sound waves reaching you is higher than the speed the sound waves would have had if the source were stationary.

The speed of sound waves in a medium is determined by the properties of the medium itself, such as its density and elasticity. In general, sound waves travel at a specific speed in a given medium, regardless of the motion of the source.

However, when the source of sound is in motion, there is an additional component to consider: the relative motion between the source and the observer. This relative motion affects the perceived frequency of the sound waves, known as the Doppler effect.

If the source of sound is moving towards the observer, the sound waves get compressed, resulting in a higher frequency and shorter wavelength. As a result, the speed of the sound waves relative to the observer appears higher than it would be if the source were stationary.

It's important to note that the actual speed of sound in the medium remains constant. It is the perceived speed or apparent speed of the sound waves reaching the observer that is affected by the motion of the source.

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Answer:

the particles that heat up the gas become more active (vibrating around)

The magnetic moment of a current distribution can be calculated by multiplying the current flowing through the loop by the area enclosed by the loop. In this case, for a pipe made of a superconducting material with a given length, radius, and uniformly distributed current of 3.4 x 10^3 A, the magnetic moment can be determined.

The magnetic moment of a current distribution is a measure of its magnetic strength. It can be calculated by multiplying the current flowing through the loop by the area enclosed by the loop.

In this scenario, the current flowing around the surface of the pipe is uniformly distributed. To calculate the magnetic moment, we need to determine the area enclosed by the current loop. For a cylindrical pipe, the enclosed area can be approximated as the product of the length of the pipe and the circumference of the circular cross-section.

Given that the length of the pipe is 0.36 m and the radius is 3.5 cm (or 0.035 m), the circumference of the cross-section can be calculated as 2πr, where r is the radius. Thus, the area enclosed by the loop is approximately 2πr multiplied by the length of the pipe.

Using the given values, the area enclosed by the loop is approximately 2π(0.035 m)(0.36 m).

Finally, to determine the magnetic moment, we multiply the current flowing through the loop by the area enclosed. Using the given current of 3.4 x 10^3 A, the magnetic moment can be calculated as 3.4 x 10^3 A multiplied by 2π(0.035 m)(0.36 m).

Calculating this expression will yield the value of the magnetic moment for the given current distribution in the superconducting pipe.

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Answer:

13

Explanation:

The mass of an atom= number of protons + number of neutrons

Answer:

It depends on 2 factors

the nature of the materials

the normal force.

Explanation:

It depends on 2 factors

the nature of the materials that are in friction and the treatment that they have followed. This factor is expressed by a numerical value called the coefficient of friction or friction.

the force exerted by one body on the other, that is, the normal force.

Answer:

use newtons gravity of law by launching a watermelon in frot of the wagon

Explanation:

The magnetic field at a distance of 7.1 cm from the jumper cable is 0.034 T.

We can use the Biot-Savart law to calculate the magnetic field at a distance of 7.1 cm from the jumper cable. The Biot-Savart law states that the magnetic field, B, at a point due to a current-carrying wire is given by:

B =\((μ₀/4π) * (I * dl x r) / r^2\)

where μ₀ is the permeability of free space, I is the current in the wire, dl is a small length element of the wire, r is the distance from the wire, and x represents the cross product.

Assuming the jumper cable is straight, we can simplify the formula to:

B = (μ₀/4π) * (I / r)

Substituting the given values, we get:

B = \((4π * 10^-7 T*m/A) * (49 A / 0.071 m)\)

Simplifying, we get:

B = 0.034 T

Therefore, the magnetic field at a distance of 7.1 cm from the jumper cable is 0.034 T.

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The organelle that is large in plant cells but small or absent in animal cells is A large vacuole. So, option C. is correct.

Plant cells typically have a single, large central vacuole, which takes up a significant portion of the cell's volume. This central vacuole serves various functions, such as storing nutrients, and waste materials, and maintaining turgor pressure (cellular rigidity) in the cell. The presence of a large central vacuole allows plant cells to maintain their shape and structure.

In contrast, animal cells usually have smaller vacuoles or, in some cases, do not have vacuoles at all. Animal cells rely on other organelles for the functions performed by the large vacuole in plant cells.

It is important to note that option D includes B. A cell wall is not considered an organelle but rather a structural component that is present in plant cells and absent in animal cells.

The cell wall provides extra support and protection for plant cells, made primarily of cellulose. This characteristic is not directly related to the size difference of the organelle in question between plant and animal cells.
So, option C. is correct.

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Answer:

light is an example of a wave that is not mechanical .

it is different as it does not need material medium for its propagation

Answer:

Knowing the moon weighs approximately 7x10^22 kg and is orbiting at 1 km/s, it would take roughly 7x10^25 joules to slow its orbit down enough to crash it into earth.

Explanation:

The centripetal acceleration of the rubber stopper is 0.34 N. The explanation is as follows.

An object’s position relative to the center of a circle is given by the position vector, r. As the object moves, the length of the vector remains constant, but the direction changes. Velocity is displacement over time. So, displacement would be Δr. Recall that average velocity is Δd/Δt, so for circular motion

Given,

m = 13g

T = ?

r = 0.93m

Calculations:

\(a=4\pi ^{2} r/T\)

\(a=4(3.14)^{2} (0.93m) / (1.18s)^2=26m/s^{2}\)

T= ma= (0.013kg) (26 m/\(s^{2}\))

T = 0.34 N

* Note for force in N, mass must be in kg.

If forces come in pairs, is there an “outwardforce” causing the stopper to stay out there at the end of the string? When a car turns left sharply, is there a force causing a passenger to move toward the door? NO! Newton’s first law says an object in motion continues… This outward motion is simply the inertia of the object and this “centrifugal force” is FICTITIOUS!

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