Two students are measuring the Gravitational Attraction between each other. One student weighs 120 kg. The other student weighs 108 kg. Calculate the gravitational pull they have on each other.
Answers
Answer:
\(F=8.64\times 10^{-9}\ N\)
Explanation:
Given that,
Mass of student 1, m₁ = 120 kg
Mass of student 2, m₂ = 108 kg
Let they are at a distance of 10 m.
We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :
\(F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N\)
So, the gravitational pull between students is \(8.64\times 10^{-9}\ N\).
Related Questions
three balls are in water. ball 1 floats, with half of it exposed above the water level. ball 2, with a density less than the density of water is held below the surface by a cord anchored to the bottom of the container, so that it is fully submerged. ball 3, of same radius as ball 2, but of greater mass, is suspended from a rope so that it is fully submerged.
Answers
The correct statement about the ball 1 is the magnitude of buoyancy force is equal to that of ball's weight.
The upward force exerted on an object that is wholly or partially immersed in a fluid is called upthrust.
Ball 1 is floating on water.
Weight of the ball 1 is Fg = m₁g is acting vertically downward.
Force of buoyancy Fb = ρvg is acting vertically upwards
Net force acting on the ball is zero, Fg = Fb
As the ball 1 floats without sinking, it is in equilibrium.
This means that the net downward force is balanced by the net upward force.
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a. Discuss the 1) coastal engineering projects, 2) phases of a coastal engineering project. b. A wave is approaching perpendicular to the 500 m long breakwater. The incident wave is 1.5 m high and 30 m long. Estimate the height of the wave on 1) the back side of the breakwater at a distance of 250 m from one of the ends, 3) at a distance of 60 m from one of the edges along the time which is at a 60-degree angle with the breakwater. c. A wave in water that is 15 m deep has a period of 11 s and a height of 1.4 m. a) calculate the water particle velocity and the pressure at a point 0 m ahead of the wave crest and 2 m below the still water level, b) calculate the horizontal and vertical displacement of the water particle orbit at this point
Answers
Coastal engineering projects involve the design and construction of structures to manage and protect coastal areas from erosion, floods, and other natural hazards.
In a wave approaching perpendicular to a 500 m long breakwater, the height of the wave on the backside at a distance of 250 m from one of the ends can be estimated using wave transformation principles.
However, the height of the wave at a distance of 60 m from one of the edges along a 60-degree angle with the breakwater requires additional information, such as wave direction and wave transformation equations, to provide an accurate estimate.
For a wave in water that is 15 m deep with a period of 11 s and a height of 1.4 m, the water particle velocity and pressure at a point 0 m ahead of the wave crest and 2 m below the still water level can be calculated using wave theory equations. The horizontal and vertical displacement of the water particle orbit at this point can also be determined using the properties of wave motion and particle orbits.
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You are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. You instantly start running toward the still-open door at 6.1 m/s.
How long does it take for you to reach the open door and jump in?
What is the maximum time you can wait before starting to run and still catch the bus?
Answers
Given that you are 9.0 m from the door and the bus accelerates at 1.0 m/s², it will take you approximately 1.5 seconds to reach the open door. The maximum time you can wait before starting to run and still catch the bus is 2.5 seconds.
We can break down the problem into two parts: the time it takes for you to reach the open door and the maximum time you can wait before starting to run.
First, let's calculate the time it takes for you to reach the open door. We can use the equation of motion: distance equals initial velocity multiplied by time plus half the acceleration multiplied by the square of time (d = ut + 0.5at²).
Given:
Initial distance (d) = 9.0 m
Acceleration of the bus (a) = 1.0 m/s²
Running speed (u) = 6.1 m/s
Using the equation of motion, we can rearrange it to solve for time:
9.0 = 6.1t + 0.5(1.0)t²
0.5t² + 6.1t - 9.0 = 0
Solving this quadratic equation, we find that t ≈ 1.5 seconds (rounded to one decimal place). Therefore, it will take you approximately 1.5 seconds to reach the open door and jump in.
Next, let's determine the maximum time you can wait before starting to run and still catch the bus. In this case, we need to consider the distance the bus covers during the time it takes for you to reach the open door.
Using the equation of motion again, we can find the distance the bus covers (D) during the 1.5 seconds it takes for you to reach the door:
D = ut + 0.5at²
D = 0 + 0.5(1.0)(1.5)²
D = 0.5(1.0)(2.25)
D ≈ 1.125 m
Since the bus moves 1.125 meters during your 1.5-second sprint, you can wait for an additional 1.125 meters to be covered before you start running.
This means the maximum time you can wait is 2.5 seconds (1.125 meters / 0.45 m/s). Waiting any longer would result in you not being able to catch the bus.
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on level ground two tanks are engaged in a training exercise. the first tank fires a paint-filled training round with a muzzle speed of 250 m/s at 10.0o above the horizontal as it advances toward the second tank at 15.0 m/s relative to the ground. the second tank is retreating at a constant 35.0 m/s relative to the ground as it is hit by the shell. assume air resistance is negligible and that the shell hits the target tank at the same height from which it was launched. find the distance between the tanks when (a) when the round was first fired and (b) at the time of impact.
Answers
(a) The distance between the tanks when the round was first fired is 375 m. (b) The distance between the tanks at the time of impact is 562.5 m.
What is the effect of neglecting air resistance in the given question?Neglecting air resistance simplifies the analysis of the motion of the paint-filled training round, allowing us to use the kinematic equations to solve for the distance between the tanks.
The muzzle speed of the paint-filled training round is 250 m/s.
The angle of elevation of the round is 10.0 degrees.
The first tank is moving toward the second tank at a speed of 15.0 m/s.
The second tank is moving away from the first tank at a speed of 35.0 m/s.
Air resistance is negligible.
To find the distance between the tanks, we can use the following kinematic equations:
x = vt, which gives the distance traveled by an object moving at a constant speed v for a time t.
y = v0t + (1/2)at^2, which gives the vertical displacement of an object that is launched at an initial speed v0 and angle of elevation theta, neglecting air resistance.
Using these equations, we can find the distance between the tanks at different times:
(a) When the round was first fired, it has not traveled any distance horizontally. Therefore, the distance between the tanks is simply the initial distance between the tanks, which is the relative speed of the tanks multiplied by the time since they were at the same position. The time since they were at the same position is found by dividing the initial horizontal separation between the tanks by their relative speed: t = x0 / (v1 - v2) = 375 / (15 - (-35)) = 375 m.
(b) At the time of impact, we can use the fact that both tanks have traveled the same time t since they were at the same position. The horizontal distance traveled by the first tank is x1 = v1t, and the horizontal distance traveled by the second tank is x2 = -v2t (note the negative sign because the second tank is moving in the opposite direction). The distance between the tanks is then given by x = x1 + x2. To find the time t, we can use the vertical displacement of the round, which is zero at the time of impact. Using the equation for vertical displacement and solving for t, we get: t = (2v0 sin(theta)) / g = 50.88 s. Substituting this value into the equation for x, we get: x = v1t - v2t = (15 - (-35)) × 50.88 = 562.5 m.
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Select 3 examples of non-contract forced from the list below. Select all that apply. Static electricity Gravity A collision Magnetism Friction Air resistance
Answers
Answer:
Explanation:
The answers are Static electricity, gravity, and magnetism.
Static electricity:
This force is very similar to gravitational force, the main difference being that gravitational force acts between masses, and electrostatic force acts between two charged bodies.
This force can be generated by rubbing the comb against clothing and then holding it close to tiny pieces of paper. You can watch the pieces of paper standing on their ends being attracted to the comb.
Gravity:
Gravitational force is a type of attractive force that exists between all bodies of mass, and the gravitational force of the sun keeps the sun and all the other planets of the solar system in a fixed orbit. Gravitation force is not required to be contacted to excerpt its downward force.
Magnetism:
Remember that if you push the ends of the magnet together, the other magnet will bounce off due to the magnetic force. It is also responsible for attracting iron with the force of magnets. The magnetic force of a magnet decreases as the distance between magnets increases.
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The speed of a fishing boat is 15 km/hr. How far will the boat travel in 6 hours?
Answers
Answer: 90 Km
Explanation:
15 Km/hr X 6/hr = 90Km
There are two processes - let us call them P and Q. The similarity between P and Q is that both represent a change from liquid state to gas state. The difference is that in P, change to vapour occurs only at the liquid surface; in Q, it occurs throughout the liquid. What are P and Q respectively
Answers
1.concave lens
A.distance between two waves
B.can be captured on screen
C.light of a wavelength
D.scattered incident light
E.convex lenses
F. distance to the focal point
G.light swinging in one direction
H.heat radiation
Answers
What to do here tell please.......
Why do protons in a nucleus remain bound closely together? Select one: a. Gravity binds all particles tightly in the nucleus. b. The weak nuclear force forces the neutrons to attract the positive charges of theprotons to them. c. The protons are bound along with antiprotons in the nucleus and their repulsivecharges cancel out. d. The strong nuclear force is much stronger in the nucleus than electrostaticrepulsion.
Answers
The strong nuclear force is much stronger in the nucleus than electrostatic repulsion. The correct answer is d.
Protons in a nucleus remain bound closely together primarily due to the strong nuclear force. The strong nuclear force is one of the fundamental forces in nature and it is responsible for holding the nucleus together.
The strong nuclear force is much stronger than the electrostatic repulsion between protons, which would typically cause them to repel each other due to their positive charges. The strong nuclear force is able to overcome this electrostatic repulsion and bind the protons together in the nucleus.
The other options are not correct:
a. Gravity is a relatively weak force compared to the strong nuclear force and is not the primary force that binds particles in the nucleus.
b. The weak nuclear force is responsible for certain types of nuclear decays but does not play a significant role in binding protons closely together in the nucleus.
c. Antiprotons are not present in normal atomic nuclei, and the repulsive charges of protons are not canceled out by antiprotons.
Therefore, correct answer is d. the strong nuclear force being much stronger than electrostatic repulsion is the key factor in keeping protons bound closely together in the nucleus.
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Please someone help me.
is the block of wood at rest or in motion?
refer to the figure below draw the forces acting on the block of wood use the gas as the origin of the forces.
thank you very much for answering this.
Answers
Answer:
1) The block of wood is at rest.
2) Weight and Normal Reaction (see attached diagram).
Explanation:
Assumptions
The block of wood is a particle (a body whose mass acts at a point, so its dimensions don't matter).There are no other external forces involved.Question 1
"At rest" or "resting" means that the object isn't moving.
Therefore, the block of wood is at rest.
Question 2
Forces that are acting on the block of wood:
Weight (W): Due to the particle's mass, m, and the acceleration due to gravity, g: W = mg(Weight always acts downwards).Normal Reaction (R or N): The reaction from a surface.
(Normal Reaction is always at 90° to the surface).
See attached diagram.
How do motors use energy? Do they convert electrical energy into mechanical energy OR mechanical energy into electrical energy?
Plz help asap!
Answers
Answer:
Motors convert electrical energy into mechanical energy
Explanation:
A motor uses electrical energy to create mechanical energy by creating magnetic fields causing the motor to spin. A generator is the opposite and converts mechanical into electrical by spinning a motor in a magnetic field.
An electric motor can transforms electrical energy into mechanical energy. Therefore, option (1) is correct.
How do motors convert energy?Energy can be described as the ability of an object to do work. Energy can also be transformed to work and the work done on an object can be stored in the form of energy.
The energy contained by the object because of its motion is called kinetic energy. The energy contained by an object due to its position is called its potential energy. Mechanical energy can be defined as the sum between the kinetic energy and potential energy of a body according to the law of conservation of energy.
An electric motor is a machine that receives energy from electricity as electrical energy and transforms it into mechanical energy. Therefore, when electric energy is supplied to an electric motor it converts electrical energy into mechanical energy.
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Two forces of magnitude 10n and 20n acting at an angle of 30 degree. what will be the x component of their resultant force?
Answers
The resultant of the forces is 29 N. Option D
What is the resultant force?The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.
Thus;
Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))
Resultant = 29 N
Thus, the resultant of the forces is 29 N.
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Missing parts;
Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force
A.17N
B. 19N
C. 23N
D. 29N
E. 37N
The increase in resistant strains of insects to chemicals is a result of:
A. natural selection creating new organisms
B. evolution of new species
C. increase in those offspring who inherited resistant traits from their parents
D. all of the above
Answers
Answer:
answer D. all of the above
other quanto
Dalex when
the face
into that one dan
a Explains why fish can
Survive under
Horan
Answers
I'm not sure what you were trying to put here
A bike travels at a constant speed of 4.0 m/s for 5.0s. How far does it go?
Answers
Answer:
20 m
Explanation:
1 s = 4 m
5 s = ?
? = (4 x 5) = 20 meters
Answer:
distance = 0.8 m
Explanation:
given:
A bike travels at a constant speed of 4.0 m/s for 5.0s.
find:
How far does it go?
solution:
distance = speed / time
distance = 4.0 m/s
5 sec.
distance = 0.8 m
calculate the effective value of g , the acceleration of gravity, at 6100 m above the earth's surface.
Answers
7.79395 m/s² is the effective value of g . When the acceleration of gravity, at 6100 m above the earth's surface.
What does the gravitational acceleration at 6.4 * 10 6 m altitude equal?At the surface of the Earth, gravity's acceleration is 9.8 ms2. Near (Radius of earth =6.4106 m), the acceleration caused by gravity drops to 4.9 ms2 above its surface. Fear not!
m = Mass of the Earth = 5.972 × 10²⁴ kg
G = gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 km
a) at h = 6100 m
g = Gm/r^2
g= 6.67 × 10⁻¹¹ m³/kgs²* 5.972 × 10²⁴ kg / ( 6371000+6100)
g = 7.79395 m/s²
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help me daddyz Alice did an experiment to find the relationship between the angle at which a ray of light strikes a mirror and the angle at which the mirror reflects the light. She placed a ray box in front of a mirror. She changed the angle at which the light from the ray box struck the mirror and noted the corresponding angle at which the mirror reflected the light. Which of the following is the control variable in this experiment? The ray box used as the source of light The direction along which the light moves Angle at which the light from the ray box strikes the mirror Angle at which the mirror reflects the light from the ray box
Answers
Answer:
The ray box used as the source of light
Answer: its A
Explanation: i just did the test and got it right also known. The ray used as the source of light
Why do scientists include a disclaimer about the "actual" number of characteristics that quantify life? Choose the best answer.
There are still many factors about life being studied and discovered.
Some of the characteristics may not be true.
Answers
Answer:
this is the answer
Explanation:
There are still many factors about life being studied and discovered
Paula has 4 2/3 yards of ribbon. She cuts 4 inches off each end of the ribbon to remove the frayed ends. She divides the remaining ribbon into 16 equal pieces to make bows. What is the length of ribbon, in inches, used to make each bow?
Answers
Answer:
Each ribbon = 10 inches
Explanation:
Each yard = 36 inches
4 2/3 * 36 = 168 inches now cut off 8 inches
160 inches
now make 16 ribbons 160 / 16 = 10 inches
A spring that obeys Hooke's Law has an unstretched length of 10 cm. A load of 20 N is hung from the spring. The new length of the spring is 36 cm. What is the spring constant k of the spring? (a) 0.56 N/cm (b) 0.77 N/cm 8/12/2022 Physics (c) 1.3 N/cm (d) 1.8 N/cm (8) marks
Answers
A spring that obeys Hooke's Law has an unstretched length of 10 cm. A load of 20 N is hung from the spring. The new length of the spring is 36 cm, then the spring constant k of the spring would be 0.77 N/ cm.
What is the spring constant?The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.
Relation between force and the spring constant,
F = - Kx
F= 20 N and
x = 36 -10
= 26 cm
K = F/x
=20/26 N/ cm
=0.77 N / cm
Thus, the spring constant for the spring is 0.77 N/ cm, therefore the correct answer is option B.
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In simple harmonic motion, when is the speed the greatest? (more than one)
A) when the magnitude of the acceleration is a maximum
B) when the displacement is a maximum
C) when the magnitude of the acceleration is a minimum
D) when the potential energy is a maximum
E) when the potential energy is a zero
Answers
In simple harmonic motion, the speed is the greatest when: the magnitude of the acceleration is a maximum, the magnitude of the acceleration is a minimum.
In simple harmonic motion, the speed of the object undergoing the motion is greatest when the magnitude of the acceleration is at its maximum. At this point, the object is experiencing the highest rate of change in velocity, resulting in the greatest speed. This occurs when the object is passing through the equilibrium position.
Additionally, the speed is also greatest when the magnitude of the acceleration is at its minimum. At this point, the object is momentarily at the extremes of its displacement and changing direction. The object is momentarily at rest, and its speed is maximum at this instant.Therefore, both options A and C are correct: the speed is the greatest when the magnitude of the acceleration is a maximum and when the magnitude of the acceleration is a minimum.
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Which chemical in tobacco smoke may damage cilia in the respiratory
system?
tar
nitrogen
carbon monoxide
nicotine
Answers
Answer:
nicotine
Explanation:
A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answers
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
Describe how the pendulum concept is used in the pendulum clock.
Answers
The concept of the pendulum is used in pendulum clocks to keep time. The pendulum swings back and forth in a continuous motion at a fixed rate that is determined by the length of the pendulum and the force of gravity.
This motion is used to regulate the movement of the clock's gears, which control the hands on the clock face.The mechanism of a pendulum clock is such that when the pendulum swings in one direction, it pushes a toothed wheel or gear, which in turn moves the other gears, causing the clock's hands to move forward.
When the pendulum swings back in the opposite direction, it again pushes the gear, causing the hands to move further forward. This cycle continues, with each swing of the pendulum causing the hands to move forward by a set amount. The length of the pendulum determines the rate at which the hands move forward, with longer pendulums causing the hands to move more slowly.
In a pendulum clock, the pendulum swings back and forth in a continuous motion at a fixed rate that is determined by the length of the pendulum and the force of gravity. This motion is used to regulate the movement of the clock's gears, which control the hands on the clock face. The pendulum clock is an improvement on the original verge escapement clocks, which were prone to errors due to the uneven force of the mainspring.The pendulum is a simple yet effective device that can keep accurate time. Its motion is governed by the law of conservation of energy, which states that energy cannot be created or destroyed, only transferred from one form to another.
When the pendulum is pulled to one side and released, it swings back and forth, converting potential energy into kinetic energy and back again. The period of the pendulum, or the time it takes to complete one full swing, is determined by the length of the pendulum and the force of gravity. By adjusting the length of the pendulum, the rate at which it swings can be altered, allowing it to keep accurate time.
To keep the pendulum clock running accurately, it needs to be adjusted periodically. This is done by altering the length of the pendulum, either by moving a weight up or down along the pendulum rod or by turning a screw at the bottom of the pendulum bob. This alters the period of the pendulum, which in turn changes the rate at which the clock runs.
The pendulum clock is a testament to the ingenuity of humanity. By using the simple yet effective concept of the pendulum, clockmakers were able to create accurate timepieces that revolutionized the way we keep time. Today, the pendulum clock may have been superseded by more advanced technologies, but its legacy lives on in the modern clocks and watches we use every day.
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I wish to use a positively charged rod to charge a ball by induction. Which statement is correct? a. The ball must be an insulator that is connected temporarily to the ground. b. The ball must be a conductor. c. The ball is charged as the area of contact between the two increases d. The charge on the ball will be positive.
Answers
When a positively charged rod is used to charge a ball by induction, the charge on the ball will be positive. This is the main answer to the question.
Here is an explanation of why the other options are not correct:a. The ball must be an insulator that is connected temporarily to the ground. This statement is not correct. A ball that is an insulator and temporarily connected to the ground will not be charged by induction. This is because when an insulator is temporarily grounded, the charges will flow to the ground and it will return to its original neutral state. Therefore, it won't gain any charge. b. The ball must be a conductor. This statement is not correct. The ball does not have to be a conductor to be charged by induction. It can be an insulator or a conductor. c. The ball is charged as the area of contact between the two increases.This statement is not correct.
The ball is charged by induction when a positively charged rod is brought near it. The charge is transferred to the ball from the rod without any physical contact between them. The charge transfer occurs due to the electric field created by the charged rod. d. The charge on the ball will be positive.This statement is correct. The charge on the ball will be positive when a positively charged rod is used to charge a ball by induction. This is because when a positively charged rod is brought near an object, it attracts electrons to one side of the object and repels protons to the other side, creating a separation of charge. As a result, the side of the ball that is closest to the rod will become negatively charged and the side farthest from the rod will become positively charged.
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Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
Answers
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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is scientific law and scientific theory the same?
True or false??
PLEASE HELP ME
Answers
TRUE
How much power is used by a 120 V circuit using 6 amps?
Answers
Answer:
P= 720 watt
Explanation:
P= IV
P= (6)(120)
P= 720 watt
what is the frequency of light emitted when the electron in a hydrogen atom
Answers
The frequency at which light is emitted; v=hΔE=6. 6×1010, when a hydrogen atom possesses an electron.
What is the sound frequency?The number of per second that a high noise wave repeats itself is known as frequency, often known as pitch. A bullfrog cry is significantly lower in frequency than a whistles, while a cricket is much lower in frequency than a drumbeat. The oscillations are reduced with decreasing frequency.
What does a wave's frequency mean?Frequency. Frequency is a unit of measurement for how frequently a recurrent event, like a wave, takes place over a specified period of time. A cycle is a single instance of the pattern's repetition. Only moving waves that relocate over time can exhibit frequency. The frequency of a wave can be used to estimate its speed. to describe the speed at which a wave is moving.
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what is science? Illustrate Ur views?
Answers
Answer:
Science is
Explanation:
he intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.