Two teams are competing in a tug-of-war contest. Team A is pulling at 4000N and Team B is pulling at 4900N is the opposite direction.

Answers

Answer 1

Answer:

There is 8900N of force on the rope and team B wins

Explanation:


Related Questions

1. ____________is defined as the distance an object travels per unit of time.


2. _________ occurs when an object changes speed or direction or both.

3. The change in position of an object is called ____________
.


___________ is a measurement that has both a magnitude and direction.


_______________is measured using the SI unit of meters (m).

A measurement that has a magnitude is called ___________________
.


_________________is measured using the SI unit of seconds (s).


___________________ is a measurement of an object’s speed and it’s direction.

Answers

Answer:

1) Speed

2) X ( maybe acceleration)

3) Motion

4) Vector

5) Distance

6) Scaler

7) Second

8) Velocity

can someone help rn please!! thank you sm!!

can someone help rn please!! thank you sm!!

Answers

I think it’s weight
Mass is the measure of its resistance to acceleration when net force is applied
Pounds and Kilograms definitely cannot be the answer
So the only logical answer is weight
Hope this helps

Radioactive decay: (a) A radioactive sample is monitored with a radiation detector to have 5640 counts per minute_ Twelve hours later; the detector reads 1128 counts per minute. Calculate the decay constant and the half-life of the sample. (b) A 5.00 gram sample of charcoal from an ancient fire pit has a 14 a‚¬ activity of 63.0 disintegrationslminute_ living tree has a 14 C specific activity of 15.3 disintegrations/minutelgram: The half-life of 14 C is 5730 years. How old is the charcoal sample?

Answers

The decay constant of a radioactive sample can be determined by using the equation N = N0  ˣ e (e⁻λt) , and the half-life can be found using T1/2 = ln(2)/λ.

How can the decay constant and half-life of a radioactive sample be calculated based on count rates?

(a) To calculate the decay constant, we can use the formula N = N0  ˣ (e⁻λt), where N is the final count rate, N0 is the initial count rate, λ is the decay constant, and t is the time.

By substituting the given values, we can solve for λ. The half-life can be found using the formula T1/2 = ln(2)/λ.

(b) The age of the charcoal sample can be determined using the formula t = (ln(N0/N) ˣ T1/2) / ln(2), where N0 is the initial activity, N is the current activity, T1/2 is the half-life, and t is the age of the sample.

By substituting the given values, we can calculate the age of the charcoal sample.

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when an object at rest explodes into two parts that fly apart, under what conditions must the two parts (m1 and m2) move in exactly opposite directions?

Answers

When the total linear momentum is conserved, the parts M1 and M2 will move in opposite direction after explosion.

When the object is placed at any place, it is a single entity,

So all the particles inside it are a part of a single system.

We, according to conservation of Linear momentum,

When there is no external factor affecting the motion of the system, the total linear momentum remains conserved,

So,

Final momentum = Initial momentum

M₁V₁ + M₂V₂ = MV

Where,

M₁ is the mass of one piece,

M₂ is the mass of other piece,

V₁ is the velocity of one piece,

V₂ is the velocity of other piece,

M is the mass of unexploded particle,

V is the velocity of exploded particle, which is zero in this case,

So,

M₁V₁ + M₂V₂ = 0

M₁V₁ = -M₂V₂

Here,

This negative sign implies that the momentum of the other particle is in opposite direction of the first particle.

And we know, the direction of the momentum is same as that of the velocity.

So, we can conclude, both the particle will move in opposite direction.

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Protons
Neutrons
Electrons
Location
Charge
Size

ProtonsNeutronsElectronsLocationChargeSize

Answers

Protons are positive, and neutrons are negative, electrons are neutral. I’m not sure about the rest but I hope that helps for now

Alejandro has collected over 35 studies focusing on the impact of vitamin C on a person's cold duration. He hopes to combine these findings and draw a general conclusion regarding the usefulness of the vitamin. Alejandro is using the statistical tool of:

Answers

Since Alejandro hopes to combine the findings from the collected studies and draw a general conclusion regarding the subject, he is using statistical tool of inference.

There are basically 2 types of statistical tools:

Descriptive statistical toolsInferential statistical tools

Descriptive tools are used to describe data. They include the use of tables, graphs, measures of dispersion, measures of central tendencies, etc.

Inferential tools are used to deduce conclusions from data. They include measures of significant differences, probability, correlation and regression, etc.

In this case, Alejandro would need to subject the data collected from the 35 studies to inferential statistical analysis tools in order to be able to make relevant conclusions.

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what was the data transmission range of your bioradio unit? what factors may have had an influence on the transmission range of the bioradio?

Answers

The data transmission range of a bioradio unit was typically around 10 meters, and factors such as signal interference, obstacles, and antenna quality could have influenced its transmission range.

The data transmission range of a bioradio unit, which is used for wireless transmission of biological signals, can vary depending on several factors. Generally, the range can vary from a few meters up to several tens of meters.

Several factors can influence the transmission range of the bioradio unit, including the frequency of the signal, the power of the transmitter, the presence of obstacles between the transmitter and receiver, and the sensitivity of the receiver. Additionally, environmental factors such as interference from other devices and noise levels can also affect the transmission range.

Other factors that may influence the transmission range of the bioradio unit include the quality and type of antenna used, the quality and placement of the grounding system, and the specific characteristics of the biological signals being transmitted.

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The moon remains in orbit around earth because of the force of —.

Answers

The moon remains in orbit around earth because of gravitational energy

Data;

MoonGravity

Gravitational Energy

Moon and other centripetal bodies maintain a state of constant orbit or centripetal acceleration because of gravitational energy.

The gravitational energy acting on the moon keeps the body rotating. This is further elaborated by Einstein's theory of relativity.

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A child throws a ball into the air and then catches it when it comes down. What us the effect on the ball's potential energy?

A. Potential energy increases, then decreases to the original level.
B. Potential energy decreases, then increases to the original level.
C. Potential energy remains the same throughout the ball's trajectory.
D. The answer cannot be determined from the information provided.

Answers

Answer:a

Explanation:

name two parts (states) of the USA which are separated from the rest of the country​

Answers

Answer:

Alaska and Hawaii

Explanation:

ANSWER

hawaii & alaska

A student adds a tablespoon of sugar to a glass containing
tea and ice cubes. The mixture is then stirred until all the
sugar dissolves.
Which observation is a clue that the student's final mixture is heterogeneous?
A. Some ice cubes are floating in the tea.
B. Some water droplets form on the outside of the glass.
C. The mixture looks the same throughout.
D. The sugar crystals are no longer visible in the tea.

Answers

Answer:

\(\huge\boxed{\sf Option \ A}\)

Explanation:

When we stir the solution such that it forms a mixture and the sugar is completely dissolved, we still find some ice cubes floating in the tea which shows that it is a heterogeneous mixture.

A Heterogeneous Mixture:

It is a mixture which has two or more phases that can be separated by physical means.

\(\rule[225]{225}{2}\)

Hope this helped!

~AnonymousHelper1807

Answer: Some ice cubes are floating in the tea.

Explanation:

A. Some ice cubes are floating in the tea.

B. Some water droplets form on the outside of the glass.

C. The mixture looks the same throughout.

D. The sugar crystals are no longer visible in the tea.

A student adds a tablespoon of sugar to a glass containingtea and ice cubes. The mixture is then stirred

1. List a similarity between magnetic force and electrical force.

Answers

Answer:

Both are attractive as well as repulsive.

Explanation:

(Like poles repel, like charges repel; unlike poles attract, unlike charges attract).

There are two types of charges that form electric fields: positive and negative charges. Magnetic fields are formed by charges and are related with two magnetic poles, north and south (but moving charges).

The attraction and repulsion of electric charges produce both electric and magnetic fields.

The force released by magnets when they attract or repel each other is known as magnetism. An electric force is the attracting or repulsive interaction between any two charged things.

Similarities are as follows:

There are two types of charges that form electric fields: positive and negative charges. Magnetic fields are formed by charges and are related with two magnetic poles, north and south (but moving charges).The attraction and repulsion of electric charges produce both electric and magnetic fields.

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What are the common sedimentation tanks found in waste treatment
plants and what is the purpose of each tank

Answers

In waste treatment plants, there are several common types of sedimentation tanks .some of the most common sedimentation tanks and their purposes: Primary Sedimentation Tank , Secondary Sedimentation Tank ,Tertiary Sedimentation Tank:

1. Primary Sedimentation Tank: The primary sedimentation tank, also known as a primary clarifier or primary settling tank, is designed to remove settleable solids and heavy particles from wastewater. It allows the heavier particles to settle at the bottom of the tank, forming sludge, while the lighter particles float to the top and are skimmed off. The primary sedimentation tank helps in the removal of large suspended solids and organic matter.

2. Secondary Sedimentation Tank: The secondary sedimentation tank, also called a secondary clarifier or final settling tank, is used in biological treatment processes. It receives the treated wastewater from the biological reactor, such as an activated sludge process or a trickling filter, and allows the remaining suspended solids, microorganisms, and flocs to settle. This tank separates the treated wastewater from the biological sludge or biomass before the water is discharged or subjected to further treatment.

3. Tertiary Sedimentation Tank: Tertiary sedimentation tanks, also known as tertiary clarifiers or polishing basins, are used for additional treatment after the secondary sedimentation tank. These tanks further remove fine suspended solids, residual organic matter, and nutrients, such as phosphorus or nitrogen, from the wastewater. Tertiary treatment is often required to meet strict effluent quality standards before the wastewater is discharged into the environment.

4. Imhoff Tank: An Imhoff tank is a type of sedimentation tank used for the treatment of sludge or sewage solids. It consists of two chambers: an upper chamber for settling and a lower chamber for anaerobic digestion of the settled sludge. The Imhoff tank allows for the natural decomposition of organic solids in the lower chamber, reducing the volume of sludge and producing biogas.

These sedimentation tanks play a crucial role in wastewater treatment by allowing the separation and removal of solids from the wastewater, improving the overall quality of the treated effluent. The specific design and purpose of each tank may vary depending on the treatment process and the requirements of the wastewater treatment plant.

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A fullback (86.0 kg) and a defensive back (81.6 kg) collide in mid-air. The fullback is moving south at 7.03 m/s. The defensive back is moving east at 8.71 m/s. a. Determine the pre-collision momentum of the fullback. b. Determine the pre-collision momentum of the defensive back. c. Determine the total momentum of the system of two players before the collision. d. Determine the total momentum of the system of two players after the collision. e. If the two players entangle together and move at the same speed and direction after the collision, then determine the speed at which they move.

Answers

a. To determine the pre-collision momentum of the fullback, we use the formula:

Momentum = mass * velocity

The mass of the fullback is given as 86.0 kg, and the velocity is 7.03 m/s (moving south). Therefore, the pre-collision momentum of the fullback is:

Momentum = 86.0 kg * 7.03 m/s

b. Similarly, to determine the pre-collision momentum of the defensive back, we use the same formula:

Momentum = mass * velocity

The mass of the defensive back is given as 81.6 kg, and the velocity is 8.71 m/s (moving east). Therefore, the pre-collision momentum of the defensive back is:

Momentum = 81.6 kg * 8.71 m/s

c. To determine the total momentum of the system of two players before the collision, we sum up their individual momenta:

Total Momentum = Momentum of Fullback + Momentum of Defensive back

d. After the collision, the total momentum of the system of the two players is still the same. This is known as the conservation of momentum principle. Therefore, the total momentum of the system after the collision is the same as the total momentum before the collision.

Total Momentum = Total Momentum (before the collision)

e. If the two players entangle together and move at the same speed and direction after the collision, then their total mass would be the sum of their individual masses. We can use the conservation of momentum principle to determine their common speed:

Total Momentum (before collision) = Total Momentum (after collision)

(mass of Fullback * velocity of Fullback) + (mass of Defensive back * velocity of Defensive back) = (Total mass * final speed)

Substituting the given values, we can solve for the final speed.

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A 0.3-kg object with half the density of human fatty tissue is placed in water. Ignoring the atmospheric pressure, what percentage of the mass will be submerged

Answers

Ignoring the atmospheric pressure, 45 percentage of the mass will be submerged if a 0.3-kg object with half the density of human fatty tissue is placed in water.

How does the weight of the displaced water compare to the buoyant force acting on a submerged object?

The weight of the fluid displaced determines the buoyant force acting on a submerged item. By comparing an object's mass in air and its effective mass when submerged in water (density = 1 gramme per cubic centimetre), this concept can be used to determine the volume and, consequently, the density of an irregularly shaped object.

Percentage of the mass will be submerged will be equal to (density of object /density of fluid)*100%

Density of object is 0.45kg/L

Density of fluid is 1kg/L

Percentage of the mass will be submerged will be 0.45/1 *100% i.e. 45%

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Radiation is spontaneously emitted from hydrogen-3 nuclei, but radiation is not spontaneously emitted from hydrogen-1 nuclei or hydrogen-2 nuclei. Which hydrogen nuclei are stable?.

Answers

Nuclei of H1 and nuclei of H2 are the only stable nuclei oh hydrogen.

Hydrogen is the first and most basic of all elements in the universe.

It is also the lightest element in the periodic table and 90% of all atoms in the universe are hydrogen atoms.It is represented by the symbol 'H'

Radiation is spontaneously emitted from nuclei of H3 because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H1 and nuclei of H2.

The nucleus of H3 also called as tritium contains one proton and two neutrons, while the nucleus of the common isotope H-1 (protium) contains one proton and zero neutrons, and the nucleus of H-2 (deuterium) contains one proton and one neutron.

Therefore H1 and H2 have much stable nucleus as compared to nuclei of H3.

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a sled is initially moving on a straight track at 3.5 m/s. what is its velocity two seconds later, if the sled's recorded acceleration is 2.0 (m/s)/s?

Answers

A sled is initially moving on a straight track at 3.5 m/s. The final velocity of the sled will be 3.75m/s. When the acceleration is 2.0 m/s².

What is acceleration?

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on an item determines the direction of its acceleration.

Given parameters:

Initial velocity  = 3.5m/s

Final velocity  = ?

Time taken  = 2s

acceleration = 2m/s²

\(a = v_f - v_i/t\)

2 = x - 3.5/2

x = 3.75 m/s

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Which force controls the size of an atomic nucleus?
1electromagnetic force
2weak nuclear force
3strong nuclear force
4gravitational force

Answers

Answer:

Strong nuclear force

Explanation:

A____test instrument is a device that is installed in a process or at a bench to continually measure and display quantities.

Answers

The device that is installed in a process or at a bench to continually measure and display quantities is a permanent test instrument.

What is a measuring instrument?

A tool for measuring a physical quantity is a measuring instrument. Measurement, in the physical sciences, quality control, and engineering, is the process of gathering and contrasting the physical amounts of things that actually happen in the real world. As units, pre-defined standard things and occurrences are used, and the measuring procedure yields a number that connects the subject-matter under investigation to the used unit of measurement. These numerical relationships are attained through the employment of measuring devices and formal test methodologies that specify the device's use. The instrument error and measurement uncertainty that affect all measuring devices varies in severity. From basic tools like stopwatches and rulers to electron microscopes and particle accelerators, these instruments can be used for various purposes.

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According to the Law of Universal Gravitation, when the distance between the centers of two objects is doubled and the masses remain constant, the force between the objects is multiplied by a factor of Multiple Choice
a. 1 b. 4
c. 2
d. 0.5. e. 0.25.

Answers

The correct answer is e. 0.25. According to the Law of Universal Gravitation, the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This means that when the distance between the centers of two objects is doubled, the force between them is reduced to 1/4 of its original value.

Therefore, if the distance between the centers of two objects is doubled and the masses remain constant, the force between the objects is multiplied by a factor of 1/4, or 0.25. This is because the inverse square law states that the force decreases exponentially as the distance between the objects increases.

Understanding this law is important in many fields, including astronomy, physics, and engineering, as it helps to explain the behavior of celestial bodies and the forces that govern their motion.
According to the Law of Universal Gravitation, the gravitational force (F) between two objects with masses (m1 and m2) and a distance (r) between their centers is given by the equation:

F = G * (m1 * m2) / r^2

where G is the gravitational constant.

When the distance between the centers of the objects is doubled (2r), the new gravitational force (F') can be calculated as follows:

F' = G * (m1 * m2) / (2r)^2

Now, we can simplify this equation:

F' = G * (m1 * m2) / (4 * r^2)

From the original equation, we know that F = G * (m1 * m2) / r^2. Therefore, we can rewrite the new equation as:

F' = (1/4) * F

This shows that when the distance between the centers of two objects is doubled, the force between the objects is multiplied by a factor of 1/4 (0.25).

So, the correct answer is e. 0.25.

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An indefinitely long solid cylindrical insulator of radius 18.0 cm (R) has a non-uniform volume charge density of rho=4*r^(2) C/m^3. Calculate the magnitude of the electric field at a distance of 25.00 cm (r) from the axis of the cylinder. (in N/C)

Answers

The magnitude of the electric field is 1.77 x 10⁶ N/C, under the condition that the  distance is  25.00 cm

The electric field at a distance of 25 cm from the axis of the cylinder can be calculated using Gauss's law. The electric field at a point outside a uniformly charged cylinder is given by

E = (ρ × r) / (2 × ε0),

here

ρ = charge density,

r = distance from the axis of the cylinder

ε0 = permittivity of free space.

Now, we have a non-uniform volume charge density of

ρ = 4 × r²C/m³

r = 25 cm

= 0.25 m

Staging these values in the above equation

E = (ρ × r) / (2 × ε0) = (4 × r³) / (2 × ε0)

= (2 × r³) / ε0

E = (2 × (0.25 m)³) / ε0

= 1.77 x 10⁶ NN/C

Therefore, the magnitude of the electric field at a distance of 25 cm from the axis of the cylinder is 1.77 x 10⁶ N/C.

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Brianna is rowing a small boat across a pond. The air is calm; there is no wind
blowing.
a. What type of friction is resisting her motion?

b. If two friends join her in the boat, will the friction force change? Why or why not?

PLEASE I NEEEED HEEEEEEEEEEEELP.

Answers

An air bubble of volume 20 cm³ is at the bottom of a lake 40 m deep, where the temperature is 4.0°c. the bubble rises to the surface, which is at a temperature of 20°c. take the temperature of the bubble’s air to be the same as that of the surrounding water. just as the bubble reaches the surface

A. Fluid Friction B. Yes, there is more mass on the boat.

Explanation:

Not very sure about B but goodluck.

A car travels from point A to point B in 3.991 hours and returns back to point A in 4.109 hours. Points A and B are 134.2 miles apart along a straight highway. What was the car's average speed and average velocity over this time period?

Answers

Answer:

gjsgjdcjpdcojdcoj gud gud gud gud gud gud gud gud gud gud gud gud gud gud get home h hum h hum hth hai h h g c b c b v g c h x corolla

The average speed of the car over this time period is 38.6 miles per hour. The average velocity of the car over this time period is 0 miles per hour.

The average speed of an object is the total distance traveled divided by the total time taken to travel that distance. In this case, the car travels a total distance of 134.2 miles in a total time of 3.991 + 4.109 = 8.1 hours. This means that the car's average speed is 134.2 miles / 8.1 hours = 38.6 miles per hour.

The average velocity of an object is the total displacement of the object divided by the total time taken to make that displacement. In this case, the car returns to its starting point, so its displacement is 0 miles. This means that the car's average velocity is 0 miles / 8.1 hours = 0 miles per hour.

Average speed and average velocity are not the same thing. Average speed only takes into account the distance traveled, while average velocity takes into account the displacement of the object. In this case, the car's displacement is 0, so its average velocity is 0.

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Where would you find the sun on this HR diagram?


A


B


C


D

The Answer Was (A) I Chose It And Got It Correct! I Have Proof For You In The Attachment, Your Welcome! ^_^

Where would you find the sun on this HR diagram? A B C DThe Answer Was (A) I Chose It And Got It Correct!
Where would you find the sun on this HR diagram? A B C DThe Answer Was (A) I Chose It And Got It Correct!

Answers

Answer:

C

Explanation:

That is where the most heat and light is showing on this diagram.

The sun on this HR diagram is placed at region A. The correct option is A.

What is an HR diagram?

The Hertzsprung-Russell (HR) diagram is a plot of stars that shows their luminosity (or brightness) versus their temperature or spectral type. The HR diagram is divided into several main parts:

Main sequence: This is the prominent diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The main sequence represents stars that are fusing hydrogen in their cores and is where most stars, including the Sun, spend the majority of their lives.

Giants and supergiants: These are stars that are much larger and more luminous than main-sequence stars, and are found above and to the right of the main sequence. Giants and supergiants are typically older stars that have exhausted the hydrogen fuel in their cores and are in the later stages of their evolution.

White dwarfs: These are the small, dense remnants of stars that have exhausted their nuclear fuel and have shed their outer layers. White dwarfs are found at the lower left of the HR diagram and are the final stage of evolution for stars like the Sun.

Instability strip: This is a narrow region of the HR diagram that includes some of the most variable stars, such as Cepheid variables and RR Lyrae variables. These stars pulsate in size and brightness over a regular period of time, making them useful for measuring distances to other galaxies.

By studying the position of stars on the HR diagram, astronomers can learn about their size, age, temperature, and luminosity, and use this information to develop models of stellar evolution and the history of the universe.

In this question,

The Sun is a main-sequence star, meaning it is in the phase of its life cycle where it is fusing hydrogen in its core to form helium.

On an HR diagram, the Sun falls near the center of the main sequence, which is a diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The temperature of the Sun is about 5,500°C, which places it in the spectral class G2V.

Therefore, The sun resides in the region of A.

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Where would you find the sun on this HR diagram? A B C DThe Answer Was (A) I Chose It And Got It Correct!

Weather is best defined as

Answers

Answer:

Weather is the state of atmosphere,temperature atmospheric pressure, wind.It differs from climate which is all weather conditions for a location averaged over about 30 years

A jet airplane travelling at the speed of 500 km / hr ejects its products of combustion at the speed of 1500 km / hr relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?​

Answers

given:

\(v{j} = 500\)

\(vpj = - 1500\)

solution:

\(vpj = vp - vj\)

\( - 1500 = vp - 500\)

\(vp = - 1000\)

= 1000 km/h

Speed of ejection of combustion products observed from ground is 1000km/h in direction opposite to the direction of motion of the jet airplane.

An astronaut hits a golf ball on the Moon. Which of the following quantities, if any, remain constant as a ball travels through the vacuum there? (a) speed (b) acceleration (c) horizontal component of velocity (d) vertical component of velocity (e) velocity

Answers

Option c is correct. In the vacuum of space on the Moon, the horizontal component of velocity remains constant as a golf ball travels.

When a golf ball is hit on the Moon, it experiences a vacuum environment without any air resistance. In this scenario, the only force acting on the golf ball is the force applied when it is hit. According to Newton's first law of motion, an object will continue to move at a constant velocity unless acted upon by an external force. Since there is no force acting on the golf ball in the horizontal direction, the horizontal component of velocity remains constant throughout its travel.

On the other hand, the vertical component of velocity is affected by the gravitational force on the Moon. The acceleration due to gravity on the Moon is about 1/6th of that on Earth, which means the vertical component of velocity will change due to the gravitational pull. The speed of the ball may also change depending on the angle and force with which it was hit, as well as the distance it has travelled.

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Tony completed a 720 km journey with an average speed of 90 km for the first 285 km he travel about an average speed of 95 km what was the average speed for the remaining journey

Answers

Answer:

87 km/h

Explanation:

720/90=8 8 Hours

285/95=3 3 hours

720-285=435 436 km left

8-3=5 5 hours left

435/5=87

87 km/H

Please help thank you!

Please help thank you!

Answers

Answer:

mass, weight

Explanation:

mass is constant, and weight is dependant on your location

Answer:

I think d

Explanation:

because distance j

has to be the last one that's the only one with distance

Suppose someone slides a 2kg physics book across the desk. At point A the book is sliding at 3m/s, and it encounters a constant 4N frictional force as it slides 1.5m across the desk to point B. What is the speed of the book at point B?

Will pay to who gets it right

Answers

Vf (final speed) = 4m/s to one sig dig (rounded up from 3.87...)
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