U Question 8 10 pts An object of mass 6.641 kg is on a bathroom scale on the equator of a planet. If the planet was not rotating, the acceleration of gravity would be 2.482 m/s2. However, the planet o

Explanation:

Sound travels more quickly through solids than through liquids and gases because the molecules of a solid are closer together and, therefore, can transmit the vibrations faster. Sound travels most slowly through gases because the molecules of a gas are farthest apart.

Answer:

no

Explanation:

the world will never end it will live untill the sun don't shine

Answer:

Visible light when all put together is white. When objects appear to be, lets say, red, it would be the only color not absorbed by that object. same goes with all other colors. So black objects absorb all colors (not 100%) and that is why black clothing gets hotter, it simply absorbs all incoming light, as apposed to white that will reflect the colors back, making all of them together appear white. Hope this helps, not the best at explaining things.

Answer:

Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.

Explanation:

Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.

Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.

This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.

Answer:

first one is for the assignment second is for the quiz

Explanation:

Assignment - C.

Quiz - D.

Answer:

The Earth spins on its axis once a day.

Explanation:

In simple words,The Earth revolves on its axis once every 24 hours and circles the sun once every 365 days. The Earth's rotation on its axis, not its orbit throughout the sun causes day as well as night. The word 'one day' refers to the period it requires the Earth to spin entirely on its axis, which involves both day as well as night.

A ball is thrown directly upward at 19.6 m/s. 2 seconds passes before the ball reaches the top of its motion.

When a ball is thrown directly upward at 19.6 m/s, the time taken for the ball to reach the top of its motion is determined by calculating the time required to reach the maximum height. To solve the problem, we use the following kinematic equation: y = vit + 0.5at².

Here, y represents the displacement, vi is the initial velocity, t is the time taken, and a is the acceleration. Since the ball is moving vertically, we use the acceleration due to gravity (g = 9.81 m/s²) as the acceleration value. The initial velocity of the ball is 19.6 m/s (positive because the ball is moving upwards).

The maximum height is reached when the final velocity of the ball becomes zero. So, we can use the final velocity value (vf = 0) in the equation above to find the time required to reach the maximum height. Hence:0 = 19.6 - 9.81tt = 19.6/9.81t = 2 seconds.

Therefore, it takes 2 seconds for the ball to reach the top of its motion.

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Q3. By using Newton's Divided Difference interpolation, the value of y when x=3 can be determined.

Q4. Using Lagrange's Interpolation method, the value of y can be determined for x=13 from the given data.

Interpolation methods are used to estimate the value of a dependent variable (in this case, y) when the independent variable (x) falls between two known data points. Newton's Divided Difference interpolation and Lagrange's Interpolation method are two commonly used techniques for this purpose.

To find the value of y when x=3 using Newton's Divided Difference interpolation, we can use the given table of data points and interpolate a polynomial function that fits the data. The coefficients of this polynomial can be determined using the divided difference formula. By substituting x=3 into the interpolated polynomial, we can calculate the corresponding value of y.

using Lagrange's Interpolation method, we can also determine the value of y for x=13. This method involves constructing a polynomial function that passes through the given data points. By using the Lagrange interpolation formula, which is based on weighted averages, we can calculate the value of y for the desired x=13.

Interpolation methods are valuable tools in data analysis, curve fitting, and prediction. They allow us to estimate values within a range based on known data points. By utilizing these techniques, we can make informed predictions and fill in missing information between data points.

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Answer:

A

Explanation:

A vector is a physical quantity that has magnitude and direction, so with A having a magnitude of 2.0km and a direction pointing north⬆️

Hope its helps

Answer: chicken nuggy

Explanation:

because chicken muggy

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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One British horsepower (550 ft⋅lb/s) is equal to 746 W. The horsepower rating of a 150-W lightbulb would be 0.20 British horsepower.
Determining the horsepower rating of a lightbulb:
Step 1: Identify the given value and the conversion factor:
Given value: 150 W
Conversion factor: 1 British horsepower = 746 W

Step 2: Set up the conversion equation: (150 W) × (1 British horsepower / 746 W)

Step 3: Cancel out the W (watts) unit: (150 / 746) British horsepower

Step 4: Calculate the result and round it to two significant figures:
0.201 British horsepower (unrounded)
0.20 British horsepower (rounded to two significant figures)

So, the horsepower rating of a 150-W lightbulb is approximately 0.20 British horsepower.

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Answer:

the foce aplied to make the net force be 0 is 5n force pushing downward on the object becasue it will cancel it out

Explanation:

Answer:

40KJ

Explanation:

m=200g

V=20m/s

Ek=?

Ek=(m*V²)/2

Ek=(200*20²)/2

Ek=(200*400)/2

Ek=80 000/2

Ek=40 000 J =40KJ

The purpose of the prefixes in the metric system is to signifies the multiples of tens for each unit.

A prefix is a word that precedes a basic unit to indicate the multiple or fraction of that basic unit.

Thus, the prefixes in the metric system are used to signify multiples of ten for each unit.

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Answer: Option A- They signify the multiples of ten for each unit.

Explanation:

Just got it correct on test :)

Before the block stops, it travels approximately 12 meters of distance. The correct answer is E) 12 m

To answer this question, we need to determine the distance the block travels before it stops. We can use the work-energy principle to find the distance. The terms we need to include in our explanation are:

1. Force of friction
2. Work done by friction
3. Kinetic energy
4. Initial speed
5. Mass of the block

Calculate the initial kinetic energy of the block.
Initial kinetic energy (KE) = (1/2) * mass * initial speed²
KE = (1/2) * 8 kg * (6 m/s)^2 = 144 J

Calculate the work done by friction.
Since the force of friction is acting against the motion of the block, the work done by friction will be negative.
Work done by friction = -force of friction * distance

Use the work-energy principle.
The work-energy principle states that the net work done on an object is equal to the change in its kinetic energy.
Final kinetic energy - Initial kinetic energy = Work done by friction
0 - 144 J = -12 N * distance

Solve for distance.
144 J = 12 N * distance
distance = 144 J / 12 N = 12 m

So, the block travels approximately 12 meters before it stops. The correct answer is E) 12 m.

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Centripetal acceleration: a= (2.844 m/s)²/0.35 m = 20.199 m/s² Speed of mass: v= 2.844 m/s Radius of circular path: r= 0.35 m.

The magnitude of the centripetal acceleration can be calculated using the formula a = (v²)/r, where v is the velocity of the mass and r is the radius of the circular path. In this case, the mass has a mass of 0.37 kg, the length of the pendulum is 0.70 m, the angle is 13°, and the radius is 0.35 m. Therefore, the centripetal acceleration is (2.844 m/s)2/0.35 m = 20.199 m/s². The speed of the mass is 2.844 m/s.

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Answer: greater than

Explanation:

An earth satellite is in an elliptical orbit. The satellite travels fastest when it is nearest to the earth.

A satellite is an object which revolves around a planet, and an elliptical orbit is one where the distance from the central body varies from time to time.

The satellite covers the maximum distance from the central body at the endpoints of the major axis and it covers the minimum distance at the endpoints of the minor axis.

When an earth satellite is in an elliptical orbit, the gravitational force varies with distance from the earth's surface. Therefore, the speed of the satellite varies with distance.

Therefore, the option "nearest to the earth" is correct.

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The peak wavelength (λmax ) of the star naos with a temperature of 42,400k is 68nm

We can use Wien's displacement law to calculate the peak wavelength (λmax) of a blackbody radiator at a given temperature:

λmax = b/T

where b is Wien's displacement constant, equal to 2.89777 x 10^-3 m K.

Converting the temperature of the star Naos to kelvin, we get:

T = 42,400 K

Substituting these values into the equation, we get:

λmax = (2.89777 x 10^-3 m K) / (42,400 K)

Simplifying this expression, we get:

λmax = 6.84 x 10^-8 m

Converting meters to nanometers, we get:

λmax = 684 nm

Therefore, the answer is (b) 68 nm.

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Answer:

20.4375 seconds.

Explanation:

Wattage = Work / time

Work = f * d

F = mass * acceleration

mass = 5000 kg

acceleration = force of gravity

acceleration = 9.81

Force = 5000 * 9.81

Force = 49050 N

Work = F * d

d = 2.5

Work = 49050 * 2.5

Work = 122625 Joules

Wattage = Work / time

time = work / wattage

wattage = 6000 watts

time = 122625 / 6000

time = 20.4375 seconds.

(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.

(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.

(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.

(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.

The distance traveled by the object is calculated as follows;

Distance From A to B to M to N

From A to B to M to N = 3 + 18 + 1 = 22

Distance From C to A to G to D

= 5 + 13 + 6

= 24

Distance From J to I to E to H

= 1 + 8 + 7

= 16

Distance from F to B to K to F

= 8 + 16 + 8

= 32

The displacement of the object is calculated as follows;

displacement = final position - initial position

Displacement From A to B to M to N

= 11 - (-11)

= 22

Displacement from C to A to G to D

= D - C

= - 4 - (-6)

= 2

Displacement from J to I to E to H

= H - J

= 5 - 7

= - 2

Displacement From F to B to K to F

= F - F

= 0

The speed of the object is calculated as follows;

speed = total distance/total time

Speed of the object from A to B to M to N

= 22/5 = 4.4 m/s

Speed of the object from C to A to G to D

= 24/5

= 4.8 m/s

Speed of the object from J to I to E to H

= 16/5

= 3.2 m/s

Speed of the object from F to B to K to F

= 32/5

= 6.4 m/s

The average velocity of the object is calculated as follows;

Average velocity from A to B to M to N

= 22/5

= 4.4 m/s

Average velocity of the object from C to A to G to D

= 2/5

= 0.4 m/s

Average velocity of the object from J to I to E to H

= -2/5

= -0.4 m/s

Average velocity of the object from F to B to K to F

= 0

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Some of the most important elements in the internal environment of an organization are the organizational structure, the organizational culture, and the leadership style.

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Answer:

100 L

Explanation:

10 dL =  1 L

The maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body, F = mv²/r = 61.7* v²/11.5 = 5.37 v²

Gravitational force acting on her is

F = mg = 61.7* 9.81 = 605.28 N

Equating the summation of centripetal force and gravitational force with total capable force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Thus, the maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

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Let's call the length of the race track as "x".

To solve for "x", we can use the formula:

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

Since the race ends in a tie, we know that Jan and Mary both took the same amount of time to run the race. Let's call this time "t".

\(\implies \text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x - 25}{7.5}\)

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x}{8.0}\)

Since both expressions represent the same time, we can set them equal to each other and solve for "x":

\(\implies \dfrac{x - 25}{7.5} = \dfrac{x}{8.0}\)

Multiplying both sides by 60 (the least common multiple of 7.5 and 8.0) to get rid of the decimals:

\(\implies 8(x - 25) = 7.5x\)

\(\implies 8x - 200 = 7.5x\)

\(\implies 0.5x = 200\)

\(\implies x = 400\)

\(\therefore\) The length of the race track is 400 meters.

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The graphs display the function solution y = ex and three numerical solutions -Euler, Improved Euler, and Runge-Kutta- at different intervals. The Relative Deviation on the right measures the difference between the numerical solutions and the exact function solution.

The analysis of each set of graphs involves comparing the numerical solutions (Euler, Improved Euler, and Runge-Kutta) with the exact function solution y = ex. The Relative Deviation provides an indication of how closely the numerical solutions approximate the exact solution.

To analyze each set of graphs, follow these steps:

By examining the graphs and assessing the Relative Deviation, one can analyze the accuracy and performance of the numerical solutions -Euler, Improved Euler, and Runge-Kutta- in approximating the exact function solution y = ex at different intervals or iterations.

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Answer:

Mass is an substance which occupies space

Explanation:

Answer: a coherent, typically large body of matter with no definite shape.

Explanation:

We observe a demonstration of Newton's third law of motion in microgravity. Astronaut Mark Vande Hei, who has a mass of 60 kg, pushes a basketball that has a mass of 0.6 kg. The basketball moves away from him at a speed of 2 m/s. According to the law of action and reaction, the astronaut also moves in the opposite direction, but with a much smaller speed due to his larger mass.

Newton's third law is one of the laws of motion put forward by Sir Isaac Newton in 1686. This law states that for every action force exerted by an object on another object, there is an equal and opposite reaction force exerted by another object on first thing .

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The magnitude of the resulting angular acceleration of the pulley is 8.0 rad/s².

To find the magnitude of the resulting angular acceleration of the pulley, we can use the formula:

α = τ / I

Where α is the angular acceleration, τ is the torque applied to the pulley, and I is the moment of inertia of the pulley.

First, we need to find the torque applied to the pulley. The force applied to the string (12 N) creates a torque by pulling on the pulley, which can be calculated using the formula:

τ = rF

Where τ is the torque, r is the radius of the pulley (0.10 m), and F is the force applied to the string (12 N).

τ = (0.10 m)(12 N) = 1.2 N·m

Now we can use this torque and the moment of inertia of the pulley (0.15 kg·m²) in the formula for angular acceleration:

α = τ / I

α = (1.2 N·m) / (0.15 kg·m²)

α = 8.0 rad/s²

Therefore, the pulley will have an angular acceleration of 8.0 rad/s².

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