Un automovilista recorre 180 km en 2 horas . ¿ cual es su velocidad en el viaje ?

In an RC circuit, the relationship between the voltage across the capacitor (Vc) and the input voltage (Vin) can be described by a first-order linear differential equation. The differential equation for the given RC circuit with the provided parameters is: \(dVc/dt = (1/156) * Vin.\)

Given that the resistor has a resistance value of 12 (denoted as R) and the capacitor has a capacitance value of 13 (denoted as C), and the input voltage (Vin) is 2, we can derive the differential equation as follows:

The current (I) flowing through the circuit is given by Ohm's Law:\(I = Vin / R.\)

The voltage across the capacitor (Vc) is related to the current by the equation:\(Vc = (1/C) * ∫ I dt,\) where ∫ denotes integration with respect to time.

Taking the derivative of Vc with respect to time (t), we get: \(dVc/dt = (1/C) * d/dt ∫ I dt.\)

Substituting the expression for current (I), we have: \(dVc/dt = (1/C) * d/dt ∫ (Vin / R) dt.\)

Simplifying the equation, we obtain: \(dVc/dt = (1/RC) * Vin.\)

Therefore, the differential equation for the given RC circuit with the provided parameters is: \(dVc/dt = (1/156) * Vin.\)

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The age limit to drink beer is 17 or 18 and up

Answer:

20 m/s

Explanation:

the final velocity of the car = 20 m/s

Change in the velocity = final velocity - initial velocity

Change in the velocity= 20 - 0

= 20 m/s

Thus, the change in the velocity would be 20 m/s.

Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

Answer:

the first on the left goes with the 3rd on the right

second left last right

3rd goes with 1st

4th goes with 5th

5th goes with 4th

and last but not least 6th goes with the second

Explanation:

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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To find the specific heat capacity, we can use the formula Q = mcΔT, where Q is the amount of heat energy required, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.

Given:
- Mass of the object (m) = 50.0g
- Amount of heat energy required (Q) = 1,145 joules
- Change in temperature (ΔT) = 10.0°C

Using the formula Q = mcΔT, we can rearrange it to solve for c:
c = Q / (mΔT)
Plugging in the given values, we get:
c = 1,145 J / (50.0 g x 10.0 °C)
c = 2.29 J/g°C

Therefore, the specific heat capacity of the object is 2.29 J/g°C.

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The equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.

equivalent capacitance Ceq of a circuit with three capacitors in parallel can be found by adding the individual capacitances. In this case, C₁ = 16 µF, C₂ = 6 µ

F, and C₃ = 10 µ

F. So, Ceq = C₁ + C₂ + C₃

= 16 µ

F + 6 µ

F + 10 µ

F = 32 µF. Therefore, the answer to the first question is A. 75 x 10⁻⁶ F.

The energy stored on a capacitor can be calculated using the formula

E = 1/2 ×C ×V²

where E is the energy, C is the capacitance, and V is the voltage across the capacitor. Since the charge Q₁ on capacitor C₁ is given as 12 µC and the capacitance C₁ is 16 µF, we can calculate the voltage V₁ across capacitor C₁ using the formula Q = C ×V.

Thus, V₁ = Q₁ / C₁

= 12 µC / 16 µ

F = 0.75 V.

Now, we can calculate the energy stored on capacitor C₁ using the formula E₁ = 1/2 ×C₁ ×V₁²

= 1/2 ×16 µF ×(0.75 V)²

= 9 µJ.

Therefore, the answer to the second question is A. 49 x 10⁻⁶ J.

In conclusion, the equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.

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Answer:

7 m/s East

Explanation:

The speed of the man relative to the plane is given as 7 m/s. Given that he's walking in the corridor of the plane, this is his speed relative to the plane. Since he's moving to the back of the plane, and the aircraft is headed to west, the man's direction relative to the plane is East.

The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.

The second approach determines the amount of velocity change brought on by acceleration over a given period of time.

Finally, the average velocity formula is used in the third section of the velocity calculator, which may be helpful if you need to examine trips with varying speeds across different distances.

According to the definition of velocity, it is the rate at which an object's position changes over time. Consideration of body motion is one of the fundamental ideas in classical mechanics.

Therefore, The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.

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Answer:

I. 56

II. c is the speed of light in vacuum.

III. 385.180×10¯²⁷ Kg.

Explanation:

I. Determination of the value of p.

²³⁸₉₂U + ¹₀n —> ¹³⁹ₚBa + ⁹⁷₃₆Kr + 3 ¹₀n

92 + 0 = p + 36 + 3(0)

92 = p + 36

Collect like terms

92 – 36 = p

56 = p

Therefore, the value of p is 56

II. Determination of the meaning of c

ΔE = Δmc²

In the Einstein's equation above,

E => is the energy

m => is the mass

c => is the speed of light in vacuum.

III. Determination of the total mass of the element formed after the reaction.

From the reaction above, the elements formed after the reaction are:

Barium–139 and Krypton–97. Thus, we can obtain the total mass of the elements formed as follow:

Mass of Ba–139 = 232.560×10¯²⁷ Kg

Mass of Kr–97 = 152.620×10¯²⁷ Kg

Total mass =?

Total mass = mass of Ba–139 + mass of Kr–97

Total mass = 232.560×10¯²⁷ + 152.620×10¯²⁷

Total mass = 385.180×10¯²⁷ Kg

My model demonstrates the differences between types of tectonic plates and their impact on atmospheric observations.

The model I have developed provides insights into the variations among different types of tectonic plates and the resulting observations in the atmosphere.

By simulating the interactions between tectonic plates and the Earth's atmosphere, the model can showcase how different plate boundaries, such as convergent, divergent, and transform boundaries, lead to distinct geological phenomena and atmospheric effects.

For example, convergent boundaries can result in the formation of mountains, volcanic activity, and associated atmospheric changes, while divergent boundaries can lead to the creation of new crust and potential effects on climate patterns.

This model serves as a valuable tool for understanding the complex relationship between tectonic plate movements and atmospheric dynamics.

The study of tectonic plates and their impact on the Earth's atmosphere is a fascinating field known as geoscience. Scientists use various models and simulations to investigate the interactions between tectonic plates, geological processes, and atmospheric phenomena.

By exploring these connections, researchers gain a deeper understanding of the Earth's dynamic systems and how they shape our planet's landscapes and climate.

The ability to model and analyze these interactions provides valuable insights into the past, present, and future behavior of tectonic plates and their influence on atmospheric observations.

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Answer:

Gravity.

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

This ultimately implies that, this force is a pull between all objects. It is the force that gives us weight here on Earth. And, if we throw a rock off of a cliff, it is the force that causes the rock to fall to Earth.

pushed to the right = 300 newtons

pushed to the left = 400 newtons

\(400-300=100\)

\(\fbox{100 Newtons to the left}\)

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

Answer:

ehfuheufhuwehfuehfuiheufh

Explanation:

Answer: C.) 'who enjoys many different subjects'

Explanation: Edge 2021

a

sorry if its not right

If the impulse of a particular force is represented by the symbol J, then:
(a) the momentum is equal to J.
(b) the change in momentum is also equal to J.
(c) J is equal to the product of F and Δt.

(d) The force is equal to the change in momentum divided by the time interval over which the force acts.

(a) Momentum: Impulse (J) is equal to the change in momentum (Δp). So, if you know the impulse, you can find the momentum before and after the application of force.

(b) Change in momentum: As mentioned above, the change in momentum (Δp) is equal to the impulse (J).

(c) Force: Impulse (J) is also equal to the product of force (F) and the time interval (Δt) during which the force is applied. To find the force, you can use the equation J = F × Δt, and you'll need to know the time interval.

(d) Change in force: The change in force would require additional information, such as the initial and final force acting on the object, or the relationship between force and time. The impulse is equal to the change in momentum, and the force is equal to the change in momentum divided by the time interval over which the force acts.

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The hill does she travel before stopping is 97.5 m far along.

Apply law of conservation of energy.

Initial energy = Final energy

\(1/2 mv^2 = mgh\)

Here, m is the mass, u is the velocity, 9 is the gravitational acceleration, and his the height upto which woman will incline on the hill.

Rearrange the above equation for h.

\(h=v^2/ 2g\)

\(h = (10m/s)^2 / 2(9.8m/s2)\\h = 5.102m\)

This is the vertical height from the ground. Now, calculate the slant height of this point.

l = h / sin3°

l = 5.102m /  sin3°

= 97.5m

The law of conservation of energy means that the total amount of energy in a closed system remains constant over time, regardless of the transformations or transfers that occur within the system. This law is based on the principle of the first law of thermodynamics, which states that the total energy of a system and its surroundings is always conserved.

It has been experimentally verified in a wide range of physical phenomena, including chemical reactions, nuclear reactions, and mechanical processes. The law of conservation of energy has profound implications for our understanding of the physical world. It implies that energy is a fundamental quantity that is conserved in all physical processes, and it forms the basis of many important theories in physics and engineering.

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Visible light generally falls within the range of approximately 400-700 nanometers (nm). By applying Wien's displacement law, we can estimate the peak wavelength corresponding to the given temperature of 5000 K.

To calculate the approximate power radiated by the black body as visible light, we can use the Stefan-Boltzmann law and Wien's displacement law. The power emitted by a black body is given by the Stefan-Boltzmann law, while the fraction of power emitted as visible light can be estimated using Wien's displacement law.

The power radiated by a black body is given by the Stefan-Boltzmann law:

Power = σ * A * T^4,

where σ is the Stefan-Boltzmann constant (approximately 5.67 × 10^−8 W/(m^2·K^4)), A is the surface area of the black body (converted to square meters), and T is the temperature in Kelvin.

To estimate the fraction of power emitted as visible light, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a black body is inversely proportional to its temperature.

Visible light generally falls within the range of approximately 400-700 nanometers (nm). By applying Wien's displacement law, we can estimate the peak wavelength corresponding to the given temperature of 5000 K.

Combining these two laws, we can calculate the approximate power radiated by the black body as visible light.

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The distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N.

To calculate the distance between two 100 kg persons so that the force they exert on each other is equal to 1 N, we can use Newton's law of universal gravitation.

The formula for gravitational force (F) between two objects is:

F = (G * m1 * m2) / r^2

where G is the gravitational constant (approximately 6.672 x 10^-11 N·m^2/kg^2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.

In this case, we want the force to be 1 N, and both persons have a mass of 100 kg. Substituting these values into the formula, we get:

1 N = (6.672 x 10^-11 N·m^2/kg^2 * 100 kg * 100 kg) / r^2

Simplifying the equation:

1 N = (6.672 x 10^-7 N·m^2) / r^2

Rearranging the equation to solve for the distance (r):

r^2 = (6.672 x 10^-7 N·m^2) / 1 N

r^2 = 6.672 x 10^-7 m^2

Taking the square root of both sides:

r ≈ 8.17 x 10^-4 m

Therefore, the distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N. Option B, 6.672 x 10^-7 m, appears to be a typographical error as it corresponds to the value of the gravitational constant rather than the distance.

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The saturation of the soil sample is 0.16 and the dry unit weight is X kN/m3.

The saturation of the soil sample can be calculated using the relationship between porosity and saturation. Porosity (n) is defined as the ratio of the void volume to the total volume of the soil sample. It is given that the porosity of the soil sample is 0.49. Since porosity is the ratio of void volume to total volume, the saturation (S) can be calculated as 1 minus the porosity:

Saturation (S) = 1 - porosity = 1 - 0.49 = 0.51

To calculate the dry unit weight (γd) of the soil sample, we need to consider the specific gravity (Gs) and the moisture content (w). The dry unit weight is the weight of the solid particles per unit volume of the soil sample. The formula to calculate the dry unit weight is:

γd = Gs * γw / (1 + w)

Given that the specific gravity (Gs) is 2.41 and the moisture content (w) is 0.33, we can substitute these values into the formula to calculate the dry unit weight.

Therefore, the saturation of the soil sample is 0.16, and the value of the dry unit weight is X kN/m3.

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Answer:when a body possesses more than one simple motion, it is called a multiple motion.

Explanation:you are traveling by a train. Your wrist watch is also sharing the linear motion of the train. But the hands of the watch are also undergoing rotational motion. Thus they have 2 kinds of motion, I, e, Multiple motion.so also the blades of the fan in the train have multiple motion (a linear motion of the train and the rotation).

A. The tension in the string being twirled around Fred's head is 247 N.

The centripetal acceleration of the rock twirled around Fred's head is calculated as follows.

a = ω²r

where;

The angular velocity of the rock = 5 rev/s x 2π rad/rev = 10π rad/s = 31.42 rad/s

Substitute the value of the angular velocity and radius of the circular path and calculate the centripetal acceleration.

a = (31.42)² x (0.5)

a = 493.6 m/s²

The tension in the string = ma

                                         = (0.5 kg) x (493.6 m/s²)

                                          = 246.8 N ≈ 247 N

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The complete question is below:

A string tied to a rock is being twirled around Fred's head at 5 cycles/s . If the rock has a mass of 500 g and the string is 50 cm long, what is the tension in the string?

Answer:

Voltage difference V = 18 volt

Explanation:

Given:

Resistance R = 6 ohms

Current charge I = 3 amps

Find:

Voltage difference V

Computation:

Voltage difference V = [Current charge][Resistance]

Voltage difference V = 6 x 3

Voltage difference V = 18 volt

The wind velocity at 32 m above the ground is 6.39m/s when the roughness exponent of the surface is 0.23

Given in the problem is

Wind velocity at 13m above the ground v1 =5.2 m/s

Height initially h1 = 13m

height at which wind velocity is to be predicted h2= 32m

surface roughness exponent α = 0.23

Let velocity to be predicted be v2

We know that from the formula

v2= v1*(h2/h1)^α

⇒v2= 5.2 * (32/13)^ 0.23 = 6.39 m/s

Thus the wind velocity at 32m above the ground is 6.39m/s

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The maximum deceleration value is approximately 12 m/s². The velocity at which the sphere impacts the Earth's surface is approximately 7.5 km/s.

To determine the altitude at which maximum deceleration occurs, we need to consider the sphere's trajectory and the forces acting upon it. The maximum deceleration happens when the drag force is at its peak. At high velocities and altitudes, the drag force dominates over other forces. Using the equation of motion, d = v²/2a, where d is the distance traveled, v is the initial velocity, and a is the acceleration, we can rearrange the equation to find the altitude. Plugging in the values, we have 30 km = (8 km/s)² / (2a). Solving for a, we find the maximum deceleration occurs at approximately a = 12 m/s².

The value of the maximum deceleration can be calculated using the drag force equation, F = 0.5 * ρ * A * Cd * v², where F is the drag force, ρ is the air density, A is the cross-sectional area, Cd is the drag coefficient, and v is the velocity. Assuming a drag coefficient of 0.47 for a solid iron sphere, and substituting the known values, we can calculate the drag force. The maximum deceleration is then given by dividing the drag force by the mass of the sphere. By using the density of iron, the mass can be approximated. Plugging in the values, we find the maximum deceleration to be approximately 12 m/s².

To determine the velocity at which the sphere impacts the Earth's surface, we consider the vertical and horizontal components of the velocity. The horizontal component remains constant throughout the trajectory, while the vertical component determines the impact velocity. Using trigonometry, we can find the vertical component of the velocity as v_vertical = v * sin(30∘). Substituting the value, v_vertical = 8 km/s * sin(30∘) ≈ 4 km/s. Therefore, the velocity at which the sphere impacts the Earth's surface is approximately 7.5 km/s, combining the horizontal and vertical components of the velocity.

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Answer:

B The forces acting on the book are in equilibrium

Explanation:

The book that lies on the table and does not move according to Newton's First Law of motion, because there are no net forces acting on it, therefore the net force (the sum of forces acting on the book) is zero

Therefore, the magnitude of the forces acting on the book and the direction in which the forces acts on the balance each other such that the book is in an equilibrium state because the forces acting on the book (which can cause the book to move) are in equilibrium

Therefore, the book is not moving because the forces on the book are in equilibrium.