Unic Research and Find out two ways each in which
Programming language and used Form
& Scientific Application
A
Buisness
8
Application

Using the knowledge in computational language in JAVA it is possible to write the code that write a program whose input is: firstName middleName lastName, and whose output is: lastName, firstName middleInitial.

import java.util.Scanner;

import java.lang.*;

public class LabProgram{

public static void main(String[] args) {

String name;

String lastName="";

String firstName="";

char firstInitial=' ',middleInitial=' ';

int counter = 0;

Scanner input = new Scanner(System.in);

name = input.nextLine(); //read full name with spaces

int i;

for(i = name.length()-1;i>=0;i--){

if(name.charAt(i)==' '){

lastName = name.substring(i+1,name.length()); // find last name

break;

}

}

for(i = 0;i<name.length()-1;i++){

if(name.charAt(i)==' '){

firstName = name.substring(0, i); // find firstName

break;

}

}

for(i = 0 ;i<name.length();i++){

if(name.charAt(i)==' '){

counter++; //count entered names(first,middle,last or first last only)

}

}

if(counter == 2){

for(i = 0 ;i<name.length();i++){

if(Character.toUpperCase(name.charAt(i)) == ' '){

middleInitial = Character.toUpperCase(name.charAt(i+1));//find the middle name initial character

break;

}

}

}

firstInitial = Character.toUpperCase(name.charAt(0)); //the first name initial character

if(counter == 2){

System.out.print(lastName+", "+firstName+" "+middleInitial+".");

}else{

System.out.print(lastName+", "+firstName);

}

}

}

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Answer:

B. Operational-level systems monitor the elementary activities and transactions of the organization.

The information systems that monitor the elementary activities and transactions of the organizations are Operational-level systems. Thus, the correct option for this question is B.

An information system may be defined as a type of system that significantly consists of an integrated collection of components particularly for gathering, storing, and processing data and for providing information, knowledge, and digital products.

According to the context of this question, the management level system deals with managing the components of activities in a sequential manner. Knowledge level system works on influencing the source of information and data to the connected devices.

Therefore, the operational level system is the information system that monitors the elementary activities and transactions of the organizations. Thus, the correct option for this question is B.

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Answer:

#include <iostream>

#include <cmath>

using  namespace std;

int main() {

   int numCats;

   cin>>numCats;

   cout<<numCats<<endl;

Explanation:

The team is vulnerable due to a lack of risk assessment. Without risk understanding, they could be caught off guard by events. (PMI, 2020) Ineffective risk strategies leave teams vulnerable to potential impacts.

Inadequate contingency planning can hinder response and recovery from materialized risks. Vulnerability due to lack of contingency planning.

Poor Communication and Collaboration: Ineffective communication and collaboration within the team can make it difficult to address risks collectively.

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Answer:

So here are five easy steps to enhance your Linux security.

1. Choose Full Disk Encryption (FDE) No matter which operating system you are using, we recommend that you encrypt your entire hard disk.

2. Keep your software up-to-date.

3. Learn how to use Linux’s firewall.

4. Tighten up security in your browser.

5. Use anti-virus software.

Explanation:

Linux has five steps for enhanced security.

A Linux is an operating system and has a Linux kernel that is based on the system and consists of five-layer of enhanced security.

These are FDE that is chosen full disk encryption, followed by keeping software up to date and learning how to make use of a firewall. It also tightens the browser's security plus the use of anti-virus.

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Answer:

Explanation:

The following is a tictactoe game written in Java with all the necessary variables and methods needed for the game to function correctly. The game plays against the computer which randomly chooses a position to play every round. Due to technical difficulties the code was added as a txt file below and the output was added as a picture.

Given :

\(n_i=20\\t_i=35\ s\\n_f=100\)

To Find :

Expected time for :

a. O(N)

b. O(N + log N)

c. O(N^3)

d. O(2^N)

Solution :

a.

In O(N) relation is ,

t = kn

So ,

35 = k(20)

t = k(100)

t = 175 seconds .

b .

In O( N + log N ) , N is dominating term . So the complexity is simplified in O(N) .

So , t = 175 seconds .

c .

The relation is given by :

\(t=kn^3\)

So ,

\(35=k(20)^3\\\\t=k(100)^3\\\\t=35(\dfrac{100}{20})^3\\\\t=4375\ seconds\)

d .

The relation is given by :

\(t=k(2)^n\)

So ,

\(35=k(2)^{20}\\\\t=k(2)^{100}\\\\t=35\times (2)^{80}\)

Hence , this is the required solution .

Answer:

False. in fact, the two main differences would have to be that memory is violate, meaning that data is lost when the power is turned off and also memory is faster to access than storage.

Answer:

Explanation:

import java.util.Scanner;

public class MadLibs {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       String word;

       int number;

       do {

           System.out.print("Enter a word: ");

           word = input.next();

           if (word.equals("quit")) {

               break;

           }

           System.out.print("Enter a number: ");

           number = input.nextInt();

           System.out.println("Eating " + number + " " + word + " a day keeps you happy and healthy.");

       } while (true);

       System.out.println("Goodbye!");

   }

}

In this program, we use a do-while loop to repeatedly ask the user for a word and a number. The loop continues until the user enters the word "quit". Inside the loop, we read the input values using Scanner and then output the sentence using the input values.

Make sure to save the program with the filename "MadLibs.java" and compile and run it using a Java compiler or IDE.

The term that describes a cloud provider allowing more than one company to share or rent the same server is known as Multitenancy.

A third-party business offering a cloud-based platform, infrastructure, application, or storage services is known as a cloud service provider.

Companies often only pay for the cloud services they use, as business demands dictate, similar to how a homeowner would pay for a utility like electricity or gas.

Data for each renter is separated and inaccessible to other tenants. Users have their own space in a multi-tenant cloud system to store their projects and data. Multi-tenant cloud system helps in the clouding of private and public sectors.

Thus, Multitenancy is the term used to describe a cloud service that permits many businesses to share or rent the same server.

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With regards to the human rights campaign, Amnesty International's campaign for freedom of expression plays a vital role, with successes, challenges, and room for improvement through collaboration and engagement.

1. The Organization is Amnesty International

  Human Right is Freedom of Expression

2. Objectives is Raise awareness, advocate for release of imprisoned individuals, lobby for protective laws, mobilize public support.

3. Actions is Join as member/volunteer, sign petitions, attend protests.

4. Evaluation is Successes include increased awareness and releases, challenges faced from governments and limited resources, failures in changing repressive laws.

5. Recommendations is Collaborate with organizations, engage influencers to amplify impact.

Conclusion - Amnesty International's campaign for freedom of expression plays a vital role, with successes, challenges, and room for improvement through collaboration and engagement.

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.CCP

Explanation:

this is the extension of C++

Answer: 1. The steps of opening the case of a working computer as follows:

2. power off the device.

3. unplug its power cable.

4. detach all the external attachments and cables from the case.

5. Remove the retaining screws of the side panel.

6. Remove the case's side panel.

Explanation:

1/67600 is the code to make a functioning program. For this exercise, sections of code are combined together.

Probability that the code is 43MZ:

Probability = (Total Required outcome / total possible outcomes)

Possible outcomes (digit) = (00,.............. ..., 99)

Possible outcomes (alphabet) = (A, B,............... .., Z)

P(43MZ) = P(43) × P(M) × P(Z)

P(43) = 1/100

P(M) = 1/26

P(Z) = 1/26

Therefore, P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600

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Answer:

Explanation:

crm

Answer:

storage

Explanation:

hope this helps

The function will output positive 1 to the console. This happens because we declare product as 1 inside our function and that value never changes because the while loop only works if the number is greater than 0.

Explanation:

The most reliable hard drives are those whose most common size is 3.5 inches, their advantages are their storage capacity and their speed and a disadvantage is that they usually make more noise.

For greater speed, it is ideal to opt for two smaller hard disks, since large disks are slower, but are partitioned so that there are no problems with file loss.

For a person who needs to use content creation programs, it is ideal to opt for a hard drive that has reliability.

Answer:

   public static boolean is_weekend(List week){

       if(week.contains("Saturday")||week.contains("Sunday"))

       {

           System.out.println("List has a weekend");

           return true;

       }

       else{

           System.out.println("List has no weekend");

           return false;

       }

   }

Explanation:

import java.util.ArrayList;

import java.util.List;

public class Car {

   public static void main(String[] args) {

       List<String> daysOfWeek = new ArrayList<>();

       daysOfWeek.add("Sunday");

       daysOfWeek.add("Moday");

       daysOfWeek.add("Tuesday");

       daysOfWeek.add("Wednesday");

       daysOfWeek.add("Thursday");

       daysOfWeek.add("Friday");

       daysOfWeek.add("Saturday");

       is_weekend(daysOfWeek);

   }

   public static boolean is_weekend(List week){

       if(week.contains("Saturday")||week.contains("Sunday"))

       {

           System.out.println("List has a weekend");

           return true;

       }

       else{

           System.out.println("List has no weekend");

           return false;

       }

   }

}

The program based on the given question prompt is given below:

Beginning

 // initiate variables

 largest = -999999999

 smallest = 999999999

 interruption = false

 while not interruption do

   // reset variables for fresh set of numbers

   hugest_set = -999999999

   pettiest_set = 999999999

   // input cycle for gathering of numbers

   duplicated

     output "Input a number (0 to cease collection):"

     input figure

     if figure != 0 then

       if figure > hugest_set then

         hugest_set = figure

       end if

       if figure < pettiest_set then

         pettiest_set = figure

       end if

     end if

   until figure = 0

   // examine whether this bunch of figures accommodates new boundaries

  if hugest_set > largest then

     largest = hugest_set

   end if

   if pettiest_set < smallest then

     smallest = pettiest_set

   end if

   // produce the hugest and pettiest aspects for this set of numbers

   output "Foremost number within this set:", hugest_set

   output "Minimum number within this set:", pettiest_set

   // solicit whether the user wants to persist

   output "Do you wish to insert a new swarm of figures? (Y/N):"

   input answer

   if answer = "N" or answer = "n" then

     interruption = true

   end if

 end while

 // deliver grand total hugest and least parts

 output "Complete most extensive amount:", largest

 output "Overall minimum magnitude:", smallest

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Answer: Digital Communications Specialist

Explanation:

Took The Test Myself

Students might earn either a Master of Arts (M.A.) or a Master of Science (M.S.) degree with an emphasis in digital communications, in order to become a: Digital Communications Specialist.

A bachelor's degree can be defined as an academic degree that is formally awarded by a tertiary institution (university or college) to a student after the successful completion of his or her high school, and it usually takes about 4 or 5 years to complete a bachelor's degree.

A master's degree can be defined as an academic degree that is formally awarded by a tertiary institution (university or college) to a student after the successful completion of his or her bachelor's degree programme.

In conclusion, students are required to earn either a Master of Arts (M.A.) or a Master of Science (M.S.) degree in digital communications, in order to become a Digital Communications Specialist.

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Answer:

bjdjdindbdubduf kndjnxjxjfujdjbdjbd bzjbd djbdibdu jdjdidnidndi xubdubdufjksk. xud ufbsjjdi djneibdudbdujfjfbjbdj fu. fjfjjdubdjjdbjd jdbdinkdkdnd. djjdibnfjdkndindundi jdudjbdubd djbdu bdudjdjjd djidndud dudbid anís us dj

Answer:

####Bash Script Start###################################

#######Please check the permissions on the folders inorder to make sure the script works

#!/bin/bash

if [ ! -d NEW ]; then

mkdir -p NEW;

fi

df > "NEW/Free_Space_Content.txt"

touch "NEW/OLD_Content.txt" | ls -l OLD > "NEW/OLD_Content.txt"

> "NEW/Time_File.txt" | date +"%B %c" > "NEW/Time_File.txt"

cp "OLD"/*.txt "BACKUP"

rename OLD BACKUP "BACKUP"/*.txt

mv "NEW"/*.txt "BACKUP"

#############Bash Script End##################################

########Script_Assessment.txt#####################

Commands which were used to create files:

touch filename

command > filename

> filename

Directory and its contents:

NEW: Contained the newly created file

OLD: Contained sample files with OLD suffix

BACKUP: Contains all the files moved from NEW and OLD directories

Free_Space_Content.txt contains the disk info such as used and free space

OLD_Content.txt contains the directory contents info of OLD directory

Time_File.txt : Contais the current month, day and time info

Explanation:

Another PowerPoint question? I got you!

Applying a design template can be applied when you have a slide. You can't apply one without a new slide.

Answer:

I guess if there is experiment going on in absence one of those furniture then the experiment isn't successful

Answer:

connection

Explanation:

connection between each device

To use the database documenter, follow these steps -

This is the suggested sequence of steps to use the database documenter based on the given options.

By selecting "Database Tools" (2), choosing "Analyze" (3), and clicking on "OK" (5), you can initiate the documenter and generate the desired reports and documentation. Following these steps will help you utilize the database documenter effectively and efficiently.

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A flowchart exists as a graphic illustration of a function. It's a chart that displays the workflow needed to achieve a task or a set of tasks with the help of characters, lines, and shapes.

A flowchart exists as a graphic illustration of a function. It's a chart that displays the workflow needed to achieve a task or a set of tasks with the help of characters, lines, and shapes. Flowcharts exist utilized to learn, enhance and communicate strategies in different fields.

Step Form Algorithm:

Start.

Declare the required variables.

Indicate the user to enter the coefficients of the quadratic equation by displaying suitable sentences using the printf() function.

Wait using the scanf() function for the user to enter the input.

Calculate the roots of the quadratic equation using the proper formulae.

Display the result.

Wait for the user to press a key using the getch() function.

Stop.989

Pseudo Code Algorithm:

Start.

Input a, b, c.

D ← sqrt (b × b – 4 × a × c).

X1 ← (-b + d) / (2 × a).

X2 ← (-b - d) / (2 × a).

Print x1, x2.

Stop.

Flowchart:

A flowchart to calculate the roots of a quadratic equation exists shown below:

import math

days_driven = int(input("Days driven: "))

while True:

code = input("Choose B for class B, C for class C,D for class D, or Q to Quit: ")

# for class D

if code[0].lower() == "d":

print("You chose Class D")

if days_driven >=8 and days_driven <=27:

amount_due = 276 + (43* (days_driven - 7))

elif days_driven >=28 and days_driven <=60:

amount_due = 1136 + (38*(days_driven - 28))

else:

print("Class D cannot be rented for less than 7 days")

print('amount due is $', amount_due)

break

elif code[0].lower() == "c":

print("You chose class C")

if days_driven \gt= 1 and days_driven\lt=6:

amount_due = 34 * days_driven

elif days_driven \gt= 7 and days_driven \lt=27:

amount_due = 204 + ((days_driven-7)*31)

elif days_driven \gt=28 and days_driven \lt= 60:

amount_due = 810 + ((days_driven-28)*28)

print('amount due is $', amount_due)  

# for class b

elif code[0].lower() == "b":

print("You chose class B")

if days_driven >1 and days_driven<=6:

amount_due = 27 * days_driven

elif days_driven >= 7 and days_driven <=27:

amount_due = 162 + ((days_driven-7)*25)

elif days_driven >=28 and days_driven <= 60:

amount_due = 662 + ((days_driven-28)*23)

print('amount due is $', amount_due)  

break

elif code[0].lower() == "q":

print("You chose Quit!")

break

else:

print("You must choose between b,c,d, and q")

continue

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