use correct alternative to complete the indirect speech sentence​

Answers

Answer 1

Answer:

where a picture

Explanation:

a saan Ang picture


Related Questions

The work-energy theorem states that the change in the kinetic energy of an object is equal to what?

Answers

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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A 2.0-cm-tall object is 14 cm in front of a converging lens that has a 20 cm focal length. Calculate the image position. Express your answer to two significant figures and include the appropriate units. s′ = Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted. Express your answer to two significant figures and include the appropriate units.

Answers

The height and position of the image are both 2 cm. An upright, laterally inverted, identically sized, and distant behind the mirror as the item in front of it is generated by a plane mirror.

How to solve?

The image position is 14 cm and the image height is 2 cm.

The image size as the object, real and inverted.

Image distance:

The image distance is calculated using equations;

1/v=1/f-1/u

where;

f is the focal length

v is the image distance

u is the object distance

1/v= 1/20-1/14

1/v= -3/140

v=  140/-3

Magnification of the image,

m=v/u

m= 140/14x(-3)= 30

Thus, the image size as the object, real and inverted.

What is the image size formula?

1. To determine the total number of pixels in the image, multiply its width and height in pixels. 2. To determine the image size in bytes, multiply the total number of pixels by 3.

What are distance and position?

Distance is the distance covered by an object travelling in any direction or even changing direction. Position refers to an object's location inside a frame of reference. Positions can be displayed using a number line for motion in a straight line.

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Particles q₁ +8.0 μC, q₂ +3.5 μC, and
93 -2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Particles q +8.0 C, q +3.5 C, and93 -2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net electric force on particle 2 is -21.7 N.

What is the net force on particle q₂?

The net force on particle q₂ is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

k is coulomb's constantq is the magnitude of the charger is the distance between the charge

The force  between particle 2 and particle 1 is calculated as;

F = -( 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.1)²

F = - 25.2 N

The force  between particle 2 and particle 3 is calculated as;

F = ( 9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.15)²

F = 3.5 N

The net force on particle 2 = 3.5 N - 25.2 N = -21.7 N

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A pitcher throws a baseball from the pitcher's mound to home plate in 0.46 s. The
distance is 18.4 m. What was the average speed of the baseball?
a. 40 m/s
b. - 40 m/s
c. 0.03 m/s
d. 8.5 m/s

Answers

The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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Can someone help with my physics homework? please

A go cart engine applies a force of 888N and moves the cart forward 22m.

a) How much work is done?


b) What is doing the work?


c) If the driver wants to go further will the amount of work increase or decrease? Do you need a bigger engine to go

further?


d) We put on a bigger engine (1111N) but the cart still moves forward 22m. How much work is done now?


e) Why would you put on a bigger engine if you are still moving 22m?


f) Work requires a change in energy, which engine uses more gas to go 22m?


g) Even an empty semi truck uses much more gas than a car. Why?Find the soultions

Answers

Answer:

a) 19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options:  (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) 24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

Explanation:

a) If force applied in the cart is uniform, that is, constant in magnitude and direction and is parallel to distance travelled by the car, the work done on the cart is defined by the following equation:

\(W = F\cdot \Delta s\) (1)

Where:

\(F\) - Force applied by the cart, measured in newtons.

\(\Delta s\) - Distance travelled by the car, measured in meters.

\(W\) - Work done on the cart, measured in joules.

If we know that \(F = 888\,N\) and \(\Delta s = 22\,m\), then the work done on the cart is:

\(W =(888\,N)\cdot (22\,m)\)

\(W = 19536\,J\)

19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options:  (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) If we know that \(F = 1111\,N\) and \(\Delta s = 22\,m\) , then the work on the cart is:

\(W = (1111\,N)\cdot (22\,m)\)

\(W = 24442\,N\)

24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The gas consumption is directly proportional to the square of velocity and mass of the cart and, hence, to the work done on the cart. In consequence, we conclude that the bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

a. The amount of work done by the go cart engine is 19,536 Nm.

b. Work is being done by the go cart engine i.e the engine installed on the go cart.

c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.

d. The amount of work done when a bigger engine is used is 24,442 Nm.

e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.

g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.

Given the following data:

Force A = 888 NewtonDistance = 22 meterForce B = 1111 Newton

a. To determine the amount of work done by the go cart engine:

Mathematically, the work done by an object is given by the formula;

\(Work\;done = Force \times distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 888 \times 22\)

Work done = 19,536 Nm.

b. Work is being done by the go cart engine i.e the engine installed on the go cart.

c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.

d. To determine the amount of work done when a bigger engine is used:

\(Work\;done = Force \times distance\)

\(Work\;done = 1111 \times 22\)

Work done = 24,442 Nm.

e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.

g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.

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2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True

Answers

The statement that is NOT true is "the spaces between the particles increased.

option D.

What is effect of temperature on volume?

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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A stone is thrown straight upward and it rises to a maximum height of 20 m.
Determine with what speed was it thrown?

Answers

Answer:

5 m per second

Explanation:

Answer:

20 m/s hope this helps ! :) well that what I rounded to technically its 19.81 m/s.

Explanation:

1.How do we define electric potential at any point in space ?
2.How does the electric potential change along the direction of the net electric field?Explain them in details.

Answers

Answer:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point.

2.The electric potential varies radially by decreasing as the distance from the electric field increases.

Explanation:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point. It is defined mathematically as, V = W/q where V = electric potential, W = work done in moving charge q into electric field and q = charge. For the work done of moving a charge q into an electric field of charge q' at a distance r between them, W = kqq'/r and work done per unit charge in moving q in electric field is V = W/q = kqq'/r ÷q = kq'/r, Also, for an electric field, E, V = ∫E.dr where r is the direction moved by the charge in the electric field.

2. Since the electric potential V = kq'/r, V ∝ 1/r since k and q' are constant. So, the electric potential varies radially by decreasing as the distance from the electric field increases.

Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm are 160 cm apart. A 2.5 cm-tall object is 60 cm in front of the converging lens.
Calculate the image position. cm in front of the second lens.
Calculate the image height.

Answers

1.25 cm is the height of the image. 160 cm separates a converging lens with such a 40 cm focal length from a diverging lens with the a -40 cm focal length. The converging lens is 60 cm away from a 2.5 cm tall item.

What does a converging or diverging lens mean?

A lens that conforms a parallel source beam of light is known as a converging lens. One kind of converging lens is a double convex lens. Converging Lens A lens that separates a parallel light beam is known as a diverging lens. Diverging lenses include those that are double concave.

For the diverging lens, this image height corresponds to object height. We obtain h ′D=(20cm40cm)(5.0cm)=1.25cm again for diverging lens as a result.

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1. What is meant by the phrase, "a sound mind and a sound
body'?

Answers

Answer:

A sound mind in a sound body implies that you're capable of positive thinking for a better quality of life and physical functioning. When you exercise, your body releases endorphins, a chemical that triggers a positive response in the body. This shows that the more you sweat, the better you feel about yourself.

Explanation:

150 ml
Water at 22 °C
Iron at
125 °C

What is a possible
temperature of the
system after the iron
has been added to
the beaker?
A. 147 °C
B. 52°C
C. 125 °C
D. 19 °C

Answers

The possible temperature of the system after the iron has been added to the beaker is 52°C.

option B.

What is equilibrium temperature?

A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.

When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.

heat gained by the water = heat lost by the iron

The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.

Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.

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A 4.4 kg marble (really big heavy marble) is accelerating down an incline. When it reaches level ground it slows down to a stop in 1.27 seconds due to friction.



A. If the deceleration of the marble on level ground was 1.74 m/s/s, how much frictional force was present?


B. Calculate the velocity of the marble when it initially reached level ground. ​

Answers

#A

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

\(\\ \rm\longmapsto Force=ma\)

\(\\ \rm\longmapsto Force=4.4(-1.74)\)

\(\\ \rm\longmapsto Force=-7.656N\)

#B

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

\(\\ \rm\longmapsto a=\dfrac{v-u}{t}\)

\(\\ \rm\longmapsto u=v-at\)

\(\\ \rm\longmapsto u=0-(-1.74)(1.27)\)

\(\\ \rm\longmapsto u=1.74(1.27)\)

\(\\ \rm\longmapsto u=2.2m/s\)

A student wants to investigate the motion of a ball by conducting two different experiments, as shown in Figure 1 and Figure 2 above. In Experiment 1, the student releases a ball from rest and uses a slow-motion camera to film the ball as it falls to the ground. Using video analysis, the student is able to plot the ball’s horizontal position x and vertical position y as a function of time t . In Experiment 2, the student horizontally rolls the same ball off a table, and uses video analysis to plot the ball’s horizontal position x and vertical position y as a function of time t starting from the instant the ball leaves the table. The graphs from each experiment are shown above along with each graph’s best-fit curve line.

Answers

The student can conclude that in Experiment 1, the ball is following a parabolic path, demonstrated by the best-fit curve line. In Experiment 2, the ball is following a linear path, demonstrated by the best-fit curve line.

What is curve?
A curve is a line in a two-dimensional plane that is bent or curved. It is often used to describe the shape of objects or mathematical functions. It is often used to study changes in data over time and to understand the behavior of functions and equations. Curves can be described using a variety of mathematical equations and equations can be used to predict the behavior of a curve. Additionally, curves can be used to describe the motion of physical objects and to help visualize the relationships between the objects.

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Two small Styrofoam balls that are separated (between their centers) by 4 cm experience a force of attraction of 15 N. If the balls are separated by 8 cm, the force between them would be ___ N.

Answers

Answer:

f = 15/4 = 3.75

Explanation:

George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution

Answers

the right answer for this question would be dispositional

Answer:

dispositional

Explanation:

plzzz help will mark the brainliest

plzzz help will mark the brainliest

Answers

Ciara is winging....etc
The answer is : 0.60 N, toward the center of the circle


A satellite....etc
The Answer is : 7400 m/s


What is the .....etc
The Answer is : 2.60 m/s

Which of the following is not a topographical feature?

Answers

well what are the options?

Who came up with the 3 Laws of Motion?

Answers

Answer:

Isaac Newton came up with the 3 Laws of Motion

Answer:

Isaac Newton came up with three laws of motion

Forensic Entomology


Forensic Entomology


The study of the life cycle of insects that feed on the flesh to the dead, to establish time of death and occasionally identify chemicals present in a person's body at the time of death.


Time since death


Arrive a few hours after a death and are active through decomposition process. They feed on larvae and other insects rather than the corpse itself.


Larvae that feed on human excrement and remains, and are found late in the decomposition process.

Answers

Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death

What is meant by Forensic Entomology?

The scientific study of the colonization of dead body by arthropods is called forensic entomology .

Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles

Time since death : postmortem Interval.

Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.

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A car is going 8 meters per second on an access road into a highway
and then accelerates at 1.8 meters per second squared for 7.2
seconds. How fast is it then going?

Answers

Answer:

20.96 m/s^2 (or 21)

Explanation:

Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

Then, we know the acceleration, which is 1.8 m/s/s

We also know the time, 7.2 second.

Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.

(final velocity - initial velocity) = time * acceleration

final velocity = time*acceleration + initial velocity

After plugging the found values in, we get 20.96 m/s/s, or 21 m/s

Which statement about the accuracy and precision of measuring tools is
true?
OA. A tool can be both accurate and precise.
о B. Tools that are precise must also be accurate.
о C. Tools cannot be both accurate and precise.
O D. A tool that is accurate lacks precision.

Answers

The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

What is accuracy?

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

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A tuba creates a 4th harmonic
of frequency 116.5 Hz. What is
the fundamental frequency of
the horn?
(Speed of sound = 343 m/s)
(Unit = Hz)

PLEASE HELP!!!!!

Answers

The frequency of the 4th harmonic of a tube closed on one end (like a tuba) is given by the formula:

f = (2n-1)c/4L

Where:

f is the frequency of the nth harmonic
c is the speed of sound
L is the length of the tube
In this case, we are given the frequency of the 4th harmonic as 116.5 Hz and the speed of sound as 343 m/s. We can solve for the fundamental frequency (1st harmonic) by rearranging the formula:

f1 = (2(1)-1)c/4L = c/4L

We need to find the length of the tube to calculate the fundamental frequency. However, we don't have enough information about the length of the tuba. Therefore, we cannot determine the fundamental frequency with the given information.

If we assume that the tuba is a standard B-flat tuba, we can estimate its length to be around 18 feet (5.5 meters). Using this length in the formula, we get:

f1 = c/4L = 343/(4*5.5) = 15.6 Hz

Therefore, if the tuba is a B-flat tuba, the fundamental frequency would be around 15.6 Hz. However, this is just an estimate and the actual length of the tuba could be different, which would affect the fundamental frequency.

Answer:29.1

Explanation:

acellus!!!!

How does the presence of a nucleus provide a method of basic cell
classification? *

Answers

Answer:

The nucleus-containing cells are called eukaryotic cells. Eukaryote means having membrane-bound organelles.

Explanation:

I hope this is what you were looking for?!

Hope this helps!

Have a great day!

-Hailey!

The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

What is a nucleus?

The nucleus is the controlling center of the body. It performs all the major activities in the cell. The cell which possesses a nucleus is called a eukaryote. The cell which does not have a nucleus is called prokaryote.

A prokaryotic cell is a straightforward, one-celled (unicellular) organism that is devoid of a nucleus or any other organelle that is membrane-bound. The nucleoid, a dark area in the center of the cell, is where prokaryotic DNA is located.

Therefore, The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

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The engine of a racecar approaching at 40.0 m/s emits a frequency of 160 Hz. What
frequency does a stationary spectator hear as the car approaches? b) What is the
frequency as it moves away?

Answers

The stationary spectator hears a frequency of approximately 175 Hz as the car approaches, and the stationary spectator hears a frequency of approximately 146 Hz as the car moves away.

Frequency refers to the number of cycles of a periodic waveform that occur in a unit of time, usually measured in Hertz (Hz). It is a fundamental concept in physics and is used to describe a wide range of phenomena, from sound waves to electromagnetic radiation.

a) The frequency heard by a stationary spectator as the car approaches can be calculated using the formula:

f' = f * (v + v_s) / (v + v_source)

where f is the frequency emitted by the source (engine), v is the speed of sound in air (approximately 343 m/s), v_s is the speed of the spectator (assumed to be zero), and v_source is the speed of the source (engine).

Substituting the given values, we get:

f' = 160 * (343 + 0) / (343 + 40) ≈ 175 Hz

Therefore, the stationary spectator hears a frequency of approximately 175 Hz as the car approaches.

b) The frequency heard by a stationary spectator as the car moves away can also be calculated using the same formula:

f' = f * (v - v_s) / (v - v_source)

where v_s is still zero, but v_source is now negative since the car is moving away from the spectator. Substituting the given values, we get:

f' = 160 * (343 - 0) / (343 - (-40)) ≈ 146 Hz

So, the stationary spectator hears a frequency of approximately 146 Hz as the car moves away.

Therefore, When the car is coming closer, the stationary observer hears a frequency of about 175 Hz, and when it is leaving, they hear a frequency of about 146 Hz.

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A coil of N=15 turns and radius R=10cm surrounds a long solenoid of radius r=2cm and n=103 turns/m (fig.). The current in solenoid changes as I(t)=5sin(120)t , where I is in amperes and t is in seconds. Find the induced emf in the 15-turn coil as a function of time. You must not warry about who has produced the current in the solenoid with n=103 turns/m

Answers

Hi there!

Recall the equation for the magnetic field produced by a solenoid:

\(B = \mu_0 ni\)

B = Magnetic field (T)
n = number of turns per unit length (103 turns/m)

i = Current in solenoid (In this instance, changes with respect to time)

Using Faraday's Law:


\(\epsilon = -N\frac{d\Phi_B}{dt}\)

ε = Induced emf (V)
N = Number of loops in coil (15 turns)

\(\frac{d\Phi_B}{dt}\) = Change in magnetic flux with respect to time (Wb/s)

We know that magnetic flux is equal to:
\(\Phi_B = \oint B \cdot dA = B\cdot A\)

Since the cross-sectional area remains constant, we can take it out of the time-derivative. Since the current in the solenoid varies with time, we know that its magnetic field must also vary.

\(\frac{d\Phi_B}{dt} = A * \frac{dB}{dt}\)

Solving for dB/dt, since the solenoid's current is the only thing changing with respect to time:
\(\frac{dB}{dt} = \mu_0 n * \frac{di}{dt}\)

We must first differentiate I(t) using trig and chain derivative rules.

If:
\(f(x) = \alpha sin(\beta t)\\\\f'(x) = (\alpha * \beta) cos(\beta t)\)

Therefore:
\(\frac{di}{dt} = (5 * 120)cos(120t)\\\\\frac{di}{dt} = 600cos(120t)\)

So, dB/dt equals:

\(\frac{dB}{dt} = \mu_0 n\frac{di}{dt}\\\\\frac{dB}{dt} = (4\pi * 10^{-7})(103)(600cos(120t))\\\\\frac{dB}{dt} = 0.0777cos(120t)\)

Now, substituting this expression into the equation for Faraday's Law:
\(\epsilon = -N_{coil} * A * \frac{dB}{dt} \\\\\epsilon = -15 * \pi(0.02^2) * 0.0777cos(120t)\\\\\epsilon = \boxed{-0.001464cos(120t) \text { V}}\)

**For 'A', I used the cross-sectional area of the solenoid because there is no magnetic field produced by the solenoid in the exterior of its opening. Thus, the magnetic field remains confined to an area of A = π(0.02²) = 0.00126 m², which is the value used to calculate the magnetic flux rather than the cross-sectional area of the coil.

**Also, the (-) sign in front of the function of the induced emf simply shows how the induced E-field and consequentially emf opposes the change in the solenoid's current.

A 1369.4 kg car is traveling at 28.9 m/s when the driver takes his foot off the gas pedal. It takes 5.1 s for the car to slow down to 20 m/s. How large is the net force slowing the car

Answers

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

Explain why force, acceleration, and velocity are vectors.

Answers

Answer:

simply because they all have direction

Explanation:

vector quantities are quantities which have both magnitude and direction.Force,acceleration and velocity have both magnitude and direction.

During which type of change should you expect to see different chemical
symbols before and after the change?
A. Chemical
B. Phase
C. Nuclear
D. Physical

Answers

During the nuclear change we can expect to see different chemical symbols before and after the change

Chemical and nuclear reactions are quite different from one another. Atoms can share electrons with other atoms or participate in an electron transfer to increase their stability in chemical reactions. In nuclear reactions, the atom's nucleus stabilizes itself by going through some sort of alteration. Compared to the energies involved in chemical reactions, the energies produced in nuclear reactions are many orders of magnitude higher. Environmental factors like temperature or pressure do not significantly affect nuclear reactions like they do with chemical ones.

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei

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A blue car of length 4.52 m is moving north on a roadway
that intersects another perpendicular roadway. The width of the intersection from near edge to far edge is 28.0 m. The blue car has a constant acceleration of magnitude 2.10 m/s2 directed south. The time interval required for the nose of the blue car to move from the near (south) edge of the intersection to the north edge of the intersection is 3.10 s. (a) How far is the nose of the blue car from the south edge of the intersection when it stops? (b) For what time interval is any part of the blue car within the boundaries of the intersection? (c) A red car is at rest on the perpendicular
intersecting roadway. As the nose of the blue car enters the intersection, the red car starts from rest and accelerates east at 5.60 m/s2. What is the minimum distance
from the near (west) edge of the intersection at which the nose of the red car can begin its motion if it is to enter the intersection after the blue car has entirely left the intersection? (d) If the red car begins its motion at the position given by the answer to part (c), with what speed does it enter the intersection?

Answers

The distance of the blue car from the edge of the intersection, when it stops, is 35.9 m, the time interval of the blue car within the boundaries of the intersection is 4.04 s, the minimum distance is 45.8 m, and the speed of the car is 22.6 m/s.

From the given,

A) the distance of the blue car from the south edge of the intersection when it stops =?

The width of the intersection = 28m

Acceleration = -2.10 m/s²

time interval = 3.10 s

By using the equation

x = x₀ + v₀t + 1/2 (at²)

28 = 0 + v₀(3.10) + 1/2 (-2.10 ×(3.10)²)

v₀ = 12.3 m/s

v² = v₀² + 2a (x-x₀)

(x-x₀) = Δx = v²-v₀² / 2a

  Δx  = 35. 9m

B) the time interval=?

distance covered by the blue car = 4.52 + 28 = 32.52 m

By using the relation,

x = x₀ + v₀t + 1/2 (at²)

32.52 = 0 + (12.3)t + 1/2 (-2.10)t²

-1.05t²+12.3t-32.52 = 0

This is the quadratic equation. By solving it, time t= 4.04s,7.66s. The desired time is t = 4.04 s, and the tail of the blue car leaves the intersection.

C) the minimum distance is=?

x = x₀ + v₀t + 1/2 (at²)

  = 0 + 0 + 1/2 (5.60 (4.04)²)

 = 45.8 m

The minimum distance of the blue car is 45.8m

D) speed of the car=?

the velocity equation

v = v₀ + at

= 0 + (5.60 ×4.04)

= 22.6 m/s

The velocity of the car is 22.6 m/s.

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