Use properties of exponents to simplify the given expression. Express the answer in exponential form. (3^(7))/(3^(3))

Answers

Answer 1

Expressing the answer in exponential form we get 3⁴.

To simplify the expression (3⁷/(3³), we can apply the properties of exponents. When dividing two exponential expressions with the same base, we subtract the exponents.

In this case, we have 3⁷ divided by 3³, which can be simplified as:

3⁽⁷⁻³⁾

3⁴

Therefore, the simplified expression is 3⁴.

To understand why we subtract the exponents when dividing, we can break down the steps.

The expression 3⁷ represents 3 multiplied by itself seven times:

3 × 3 × 3 × 3 × 3 × 3 × 3.

The expression 3³ represents 3 multiplied by itself three times:

3 × 3 × 3.

When dividing these two expressions, we can cancel out common factors by subtracting the exponents:

(3 × 3 × 3 × 3 × 3 × 3 × 3) / (3 × 3 × 3)

This simplifies to:

3 × 3 × 3 × 3

Which is equivalent to 3⁴.

Thus, the answer in exponential form is 3⁴

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Related Questions

what is the ph for a titration of 25.0 ml of 25.0 ml of 0.365 m acetic acid 0.365 m acetic acid when 10.3 ml of 0.432 m when 10.3 ml of 0.432 m naoh have been added?

Answers

The pH for a titration of 25.0 mL of 0.365 M acetic acid when 10.3 mL of 0.432 M NaOH have been added is approximately 4.69.

The pH for a titration of 25.0 mL of 0.365 M acetic acid when 10.3 mL of 0.432 M NaOH have been added can be calculated using the following steps:

1. Calculate the moles of acetic acid (CH₃COOH) and sodium hydroxide (NaOH) before the reaction:

- Moles of CH₃COOH = volume × concentration

= 25.0 mL × 0.365 mol/L

= 9.125 mmol

- Moles of NaOH = volume × concentration

= 10.3 mL × 0.432 mol/L = 4.4456 mmol

2. Determine the moles of acetic acid and sodium hydroxide remaining after the reaction: Since acetic acid and sodium hydroxide react in a 1:1 ratio, the limiting reactant will be NaOH.

- Moles of CH₃COOH remaining = 9.125 mmol - 4.4456 mmol = 4.6794 mmol - Moles of NaOH remaining = 0 mmol (all NaOH is consumed in the reaction)

3. Calculate the concentration of acetic acid and acetate ion (CH₃COO-) after the reaction:

- [CH₃COOH] = moles of CH₃COOH remaining / total volume

= 4.6794 mmol / (25.0 mL + 10.3 mL)

= 0.12998 mol/L

- [CH₃COO-] = moles of NaOH consumed / total volume

= 4.4456 mmol / (25.0 mL + 10.3 mL)

= 0.12346 mol/L

4. Calculate the pH using the Henderson-Hasselbalch equation:

pH = pKa + log([CH₃COO-] / [CH₃COOH]) pKa of acetic acid is 4.76, so:

pH = 4.76 + log(0.12346 / 0.12998) ≈ 4.69

Therefore, the pH for a titration of 25.0 mL of 0.365 M acetic acid when 10.3 mL of 0.432 M NaOH have been added is approximately 4.69.



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What is the steps in converting moles liters and mass

Answers

To go from moles to liters, you can use the formula:

V = (nRT) / P

where n is the number of moles.

To go from moles to mass we can use:

mass = molar mass/Moles

What is the steps in converting moles liters and mass?

To convert between moles, liters, and mass, you need to use the appropriate conversion factors and formulas based on the substance you are working with. Here are the general steps for converting between moles, liters, and mass:

Determine the substance and its molar mass: Find the molar mass of the substance you are working with. The molar mass represents the mass of one mole of that substance and is typically expressed in grams per mole (g/mol). You can find the molar mass on the periodic table or calculate it by adding up the atomic masses of the constituent atoms in the molecule.

Convert moles to mass: To convert moles to mass, you can use the formula:

Mass (in grams) = Number of moles × Molar mass

Multiply the number of moles by the molar mass of the substance to obtain the mass in grams.

Convert mass to moles: To convert mass to moles, use the formula:

Moles = Mass (in grams) / Molar mass

mass = molar mass/Moles

Divide the mass in grams by the molar mass to obtain the number of moles.

Convert moles to liters (for gases): If you are working with a gas, you can use the ideal gas law to convert moles to liters. The ideal gas law is expressed as:

PV = nRT

Where P is the pressure, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin.

Rearrange the equation to solve for V:

V = (nRT) / P

Substitute the values for n, R, T, and P to calculate the volume in liters.

These steps can be modified depending on the specific context and units you are working with, but they provide a general framework for converting between moles, liters, and mass.

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for an electron in the 1s1s state of hydrogen, what is the probability of being in a spherical shell of thickness 5.00×10−3 abab at distance 12ab12ab

Answers

The probability of finding an electron in a spherical shell of thickness 5.00 × 10⁻³ ab at a distance of 12ab from the nucleus in the 1s state of hydrogen is 0.053 or 5.3%.

To calculate the probability of finding an electron in a spherical shell of thickness 5.00 × 10⁻³ ab at a distance of 12ab from the nucleus in the 1s state of hydrogen, we can use the radial probability density function. This function describes the probability of finding an electron at a particular distance from the nucleus.

For the 1s state of hydrogen, the radial probability density function is given by:

P(r) = 4πr² |R(1,0)(r)|²

where P(r) is the probability density at distance r from the nucleus, and R(1,0)(r) is the radial wave function for the 1s state of hydrogen.

Using this formula, we can calculate the probability of finding the electron in the spherical shell of thickness 5.00 × 10⁻³ ab at distance 12ab from the nucleus by integrating the probability density over the thickness of the shell:

P(shell) = ∫[P(r)dr] from 12ab - 2.50 × 10⁻³ ab to 12ab + 2.50 × 10   ab

where the limits of integration represent the inner and outer radii of the spherical shell.

Plugging in the values, we get:

P(shell) = ∫[4πr²|R(1,0)(r)|² dr] from 11.9975ab to 12.0025ab

where we have used the fact that the thickness of the shell is 5.00 × 10⁻³ ab and the distance from the nucleus is 12ab.

Evaluating this integral numerically, we get:

P(shell) ≈ 0.053

Therefore, the probability of finding the electron in the spherical shell of thickness 5.00 × 10⁻³ ab at distance 12ab from the nucleus in the 1s state of hydrogen is approximately 0.053 or 5.3%.

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A solution with a concentration higher than the solubility is __________. A. is supersaturated B. is not possible C. is supercritical D. is unsaturated E. is saturated

Answers

A solution with a concentration higher than the solubility is supersaturated. The correct answer is option is A.

A supersaturated solution is a solution that contains more solute than it can normally dissolve at a given temperature. In other words, it has a concentration higher than its solubility.

Solubility refers to the maximum amount of solute that can dissolve in a solvent under specific conditions, such as temperature and pressure. It is often expressed in terms of grams of solute per 100 grams of solvent.

When a solution is unsaturated, it means that the concentration of the solute is below its solubility limit, and there is still room for more solute to dissolve. In an unsaturated solution, if additional solute is added, it will continue to dissolve until the solubility limit is reached.

On the other hand, a saturated solution is one where the concentration of the solute has reached its solubility limit. At this point, any additional solute added will not dissolve and will settle at the bottom of the container.

A supersaturated solution occurs when a solution is prepared at a higher temperature and then cooled down rapidly. This process allows the solute to stay dissolved in a higher concentration than its normal solubility limit. It is a metastable state where the solute remains dissolved even though the conditions are not favorable for its dissolution.

In conclusion, a solution with a concentration higher than the solubility is classified as a supersaturated solution.

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the element radium has a mass number of 226 and an atomic number of 88. how many neutrons does an atom of radium have?(1 point)

Answers

An atom of radium has 138 neutrons in its nucleus.

Radium is a radioactive element with a mass number of 226 and an atomic number of 88. The atomic number of an element is the number of protons in its nucleus, which is also equal to the number of electrons in its neutral state. Therefore, radium has 88 protons and 88 electrons.

The mass number of an element is the sum of the number of protons and neutrons in its nucleus. Since radium has a mass number of 226, we can calculate the number of neutrons by subtracting the atomic number (number of protons) from the mass number.

Thus, the number of neutrons in an atom of radium can be calculated as:

Number of neutrons = Mass number - Atomic number
= 226 - 88
= 138

Therefore, the number of neutrons present in an atom of radium is 138.

Neutrons are neutral particles found in the nucleus of an atom alongside positively charged protons. The presence of neutrons is essential for the stability of the nucleus and can also affect the chemical properties of an element. In the case of radium, the high number of neutrons in its nucleus contributes to its radioactivity and unstable nature.

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How many grams are in 0.75 moles of Fe

Answers

Answer:

41.88375 g Fe

Explanation:

Using stoichiometry, we can do this problem. First, we put our given. Then we create an equation using the molar mass of Fe (found on the periodic table, which was 55.845 g Fe), and the resulting equation is:

\(0.75 mol Fe * \frac{55.845 g Fe}{1 mol Fe}\)

The mol Fe's cancel, and leave us with:

41.88375 g Fe

Good luck.

What is the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution?

Answers

Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Explanation:

Given: Volume of solute = 120 mL

Volume of solvent = 350 mL

Now, total volume of the solution is as follows.

\(V_{total} = V_{solute} + V_{solvent}\\= 120 mL + 350 mL\\= 470 mL\)

Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.

\(\frac{V_{solute}}{V_{total}} \times 100 mL\\\frac{120 mL}{470} \times 100 mL\\= 25.53 mL\)

Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.

\(Percent (v/v) = \frac{25.53 mL}{100 mL}\\= 25.5%\)

Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Exactly 10.0 L of air -25°C is heated to 100.0°C. What is the new volume if the pressure is kept constant?

Answers

Answer: V2= 15.0403226 Liters

Explanation:

Use V1/T1=V2/T2

Make sure you change the degrees Celsius to Kelvin. (Kelvin = degrees Celsius +273)

10.0L / 248 K = V2/ 373 K

Cross multiply V1 and T2 and divide by T1

(10.0 L)( 373K)/ 248 K = V2

V2= 15.0403226 Liters (Kelvin cancels out)

Exactly 10.0 L of air -25C is heated to 100.0C. What is the new volume if the pressure is kept constant?



Which type(s) of solute dissolve readily in water?

A. polar

B. ionic

C. nonpolar

D. colloidal

Answers

\( \huge {\tt {\green{\fbox{\pink{ANSWER}}}}} \\ \)

➥ \( \: \sf {Both \: \: \: a. \: \blue{ Polar} \: \: and \: \: \: b. \: \blue{Ionic}}\)

Explanation:

The molecules of water are polar in nature due to the presence of a positive end as oxygen and a negative end as hydrogen.

Due to its polar nature, the molecules of water are attracted towards the ionic molecules. This electrostatic force of attraction called ion-dipole attraction that makes the ionic compounds readily soluble in water.

Therefore, the polar and ionic solutes are readily dissolvable in water .

ᥫ᭡

I think polar and ionic

Which variable is unknown until the experiment is performed?

Answers

The variable that is unknown until the experiment is performed is the dependent variable.

In a scientific experiment, variables are classified into two main categories: independent variables and dependent variables. The independent variable is the variable that is intentionally manipulated or changed by the experimenter. It is under the control of the experimenter and is deliberately altered to observe its effect on the dependent variable.

On the other hand, the dependent variable is the variable that is measured or observed as the outcome or response in the experiment. It is the variable that is expected to change in response to the manipulation of the independent variable. The value or behavior of the dependent variable depends on the value or behavior of the independent variable.

Typically, before conducting an experiment, researchers have a hypothesis or an expectation about how the independent variable will affect the dependent variable. However, the actual outcome or result of the experiment, which is observed through the measurement of the dependent variable, remains unknown until the experiment is performed.

The purpose of conducting the experiment is to gather empirical data and observe the changes in the dependent variable to analyze the relationship between the independent and dependent variables.

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ou measured the proportions of a radioactive parent atom and its daughter product and found a ratio of 25% parent, and 75% daughter. How many half-lives have passed? O A. 100 OB. 1 O C.2 O D. 1/2

Answers

One half-life has passed since the measurement was taken. This implies that the radioactive parent atom has decreased by 50%, and the daughter product has increased by 50%. Answer is option (B) 1.

The parent atom's half-life can be determined by using the equation given below:

Final percentage = (1/2)^n x 100%

where n is the number of half-lives elapsed. After we have rearranged this formula to solve for n, we get:

n = log (final percentage/100%) / log (1/2)

Given the initial ratio of parent to daughter as 25:75, we can assume that 25% of the original parent has remained after n half-lives. As a result, the percentage of the daughter that has been produced is 100 percent minus the percentage of the parent that is remaining.

75 percent = 100% – 25 percent

Let's use this information to determine the number of half-lives that have elapsed:

n = log (75%/100%) / log (1/2)

  = 1

Therefore, one half-life has passed since the measurement was taken. This implies that the radioactive parent atom has decreased by 50%, and the daughter product has increased by 50%.

Answer is option (B) 1.

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How are ionic bonds formed?

Multiple choice question.

A)
loss of electrons by atoms

B)
sharing of electrons between atoms

C)
electrostatic forces between ions

D)
gain of electrons by atoms

Answers

Answer:

c

Explanation:

Answer:

Same type of question from quizlet

But the answer is C

I hope you got it right :)

Which of the following statements about the properties of elements related to an atomic emission spectrum are true? Select all that apply.

Answers

A limited number of distinct, thin lines of light make up an element's emission, which results in a distinct pattern known as the element's atomic emissions spectrum.

Which of the following claims regarding an emission spectrum is accurate?

The wavelengths of light that are emitted when electrons jump from higher energy levels to lower energy levels are called the emission spectrum, while the wavelengths of light that are absorbed by the electrons as they jump from lower energy levels to higher energy levels are called the absorption spectrum.

A spectrum of atomic emission is what kind of property?

The range of electromagnetic radiation (light) frequencies that are emitted by electrons as they go from higher to lower energy levels is known as the atomic emission spectrum, and it is specific to each element.

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As ice cools from 273 K to 263 K, the average kinetic energy of its molecules (1) decreases (2) increases (3) remains the same

Answers

As ice cools from 273 K to 263 K, the average kinetic energy of its molecules decreases. So option (1) is correct.

The average kinetic energy of a substance is the energy associated with the random motion of its molecules. The motion of the molecules is determined by their temperature, which is a measure of the average kinetic energy of the molecules.

As the temperature of ice decreases from 273 K to 263 K, the average kinetic energy of its molecules decreases. This is because the kinetic energy of a molecule is directly proportional to its temperature. When the temperature decreases, the average kinetic energy of the molecules also decreases.

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Select the correct answer.
What is the ability to move body parts quickly with a significant amount of force?
A agility
B.
balance
power
OD. speed

Answers

The answer is power. Power is the only answer here that relates to force.

Answer:

Power

Explanation:

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write formulas for the compounds formed from sr and each of the following polyatomic ions: clo4− , co32− , po43−

Answers

The formulas for the compounds formed from strontium and the polyatomic ions chlorate, carbonate, and phosphate are Sr(ClO₄)₂, SrCO₃, and Sr₃(PO₄)₂, respectively.

When forming compounds between strontium (Sr) and the polyatomic ions chlorate (ClO₄⁻), carbonate (CO₃²⁻ ), and phosphate ( PO₄³⁻), we need to balance the charges of the cation (Sr) and the anion (polyatomic ion).

1. Strontium chlorate (Sr(ClO₄)₂):
- The chlorate ion has a charge of -1, so we need two of them to balance the charge of the strontium cation (+2).
- The formula for chlorate ion is ClO₄⁻.
- Therefore, the formula for strontium chlorate is Sr(ClO₄)₂

2. Strontium carbonate (SrCO₃):
- The carbonate ion has a charge of -2, so we need one of them to balance the charge of the strontium cation (+2).
- The formula for carbonate ion is CO₃²⁻
- Therefore, the formula for strontium carbonate is SrCO₃.

3. Strontium phosphate (Sr₃(PO₄)₂):
- The phosphate ion has a charge of -3, so we need two of them to balance the charge of the strontium cation (+2).
- The formula for phosphate ion is PO₄³⁻.
- Therefore, the formula for strontium phosphate is Sr₃(PO₄)₂.

In summary, the formulas for the compounds formed from strontium and the polyatomic ions chlorate, carbonate, and phosphate are Sr(ClO₄)₂, SrCO₃, and Sr₃(PO₄)₂, respectively.

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What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)

Answers

The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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True or false?
Cadmium is in the mixture because they both contain spectral lines at 625nm.

Answers

true

We describe the luminescence spectral properties of CdS nanoparticles with multiphoton excitation. Three types of CdS nanoparticles were examined which were a CdS/dendrimer composite which displays high anisotropy, Cd2+-enriched nanoparticles which display two emission maxima, and polyphosphate-stabilized nanoparticles which display long wavelength emission. Illumination with long wavelengths near 700−790 nm resulted in two-photon excitation. Essentially the same emission spectra and intensity decays were observed with one-photon and two-photon excitation. Comparison with fluorescein indicates the NPs display large two-photon cross sections near 100 GM. The CdS/dendrimer and Cd2+-enriched CdS nanoparticles displayed large anisotropy values with two-photon excitation, substantially larger than with one-photon excitation. It appears that semiconductor nanoparticles are comparable to organic fluorophores which display the same spectral properties with one-photon and two-photon excitation.

If the price of music lessons falls to
$
20
$20dollar sign, 20, which of the following best describes the income and substitution effects?

Answers

If the price of music lessons falls to $20, the statement which best describes the income and substitution effects is: C. The income effect is that she now can spend more on both goods. The substitution effect is that the price of music lessons relative to socks has decreased so she will definitely buy more music lessons.

What is price?

Price can be define as an amount of money which is primarily set by the seller of a good (product), and it must be paid by a buyer to the seller, so as to enable the acquisition of this good (product).

What is an income effect?

Income effect can be defined as a phenomenon which causes an individual (consumer) to adjust his or her consumption of a product due to an increase in its price and change in the level of income.

In conclusion, we can reasonably infer and logically deduce that for each music lesson Emily had purchased before, there is an extra $40 to spend on either music lessons or socks, and as such she might buy more of both due to the income effect.

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Complete Question:

Emily is a rational consumer who gets utility from socks and music lessons, and she considers both of these goods normal goods. Her marginal utility from socks is 50 utils and the price of socks is $5 per pair. Her marginal utility from music lessons is 600 utils and the price of music lessons is $60.

If the price of music lessons falls to $20, which of the following best describes the income and substitution effects?

A. The income effect is that she got a raise from her employer. The substitution effect is that music lessons are now relatively cheaper so she will buy more music lessons.

B. The income effect is that she effectively has more money to spend on either good. The substitution effect is that she will only buy socks now.

C. The income effect is that she now can spend more on both goods. The substitution effect is that the price of music lessons relative to socks has decreased so she will definitely buy more music lessons.

D. The income effect is that she will no longer buy socks because she has more income to spend on music lessons, so she will only buy music lessons.

E. The substitution effect is that she now can spend more on either good. The income effect is that the price of music lessons relative to socks has decreased so she will definitely buy more music lessons.

Which energy output objects work with the solar panels?

Answers

Answer:

The energy output objects that work with solar panels include solar inverters, charge controllers, batteries, and electric grid systems.

Explanation:

A sample containing 27. 0 moles of propane gas at a temperature of 25. 0 °C is stored in a 12. 5 liter cylinder. What is the pressure of the gas inside the cylinder?

Answers

The pressure of the gas inside the cylinder is 52.90 atm

Given is the number of moles of gas, the temperature and the volume of the gas and we need to find the pressure of the gas inside the cylinder, for this we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure of the gas (in units of pressure, such as atm)

V = Volume of the gas (in liters)

n = Number of moles of the gas

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature of the gas (in Kelvin)

First, let's convert the temperature from Celsius to Kelvin:

T = 25.0 °C + 273.15 = 298.15 K

Now we can substitute the values into the ideal gas law equation:

P × 12.5 L = 27.0 moles × 0.0821 L·atm/(mol·K) × 298.15 K

Simplifying the equation:

P × 12.5 L = 661.2587 L·atm

Dividing both sides by 12.5 L:

P = 661.2587 L·atm / 12.5 L

P ≈ 52.90 atm

Therefore, the pressure of the gas inside the cylinder is approximately 52.90 atm.

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We can use the ideal gas law equation to determine the pressure of a gas within a cylinder:

PV = nRT

Where:

P is the pressure of the gas (in units of pressure, such as atm)

V is the volume of the gas (in units of volume, such as liters)

n is the number of moles of the gas

R is the ideal gas constant (0.0821 L·atm/(mol·K))

T is the temperature of the gas (in units of temperature, such as Kelvin)

we need to convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 25.0 °C + 273.15

T(K) = 298.15 K

Now we can plug the data into the ideal gas law equation as follows:

P * 12.5 L = 27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K

Simplifying the equation:

P = (27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K) / 12.5 L

Calculating the pressure:

P ≈ 5.046 atm

As a result, the gas inside the cylinder is under a pressure of about 5.046 atm.

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How can erosion on a floodplain be reduced?? Help!!

Answers

A large drainage canal contained a number of little check dams that prevented erosion in older, higher-lying areas.

Briefing:

A check dam is a tiny structure built over a drainage ditch to slow down water flow and prevent erosion. In first-developed areas, check dams and wide grassy slopes prevent erosion.

What kind of erosion results from a large floodplain?

Water erodes curves on the outside and deposits eroded material on the interior, creating meanders. The positions of the curves change throughout time. A floodplain is produced as meanders erode in different directions. On both sides of a river, there is a large, flat region.

What causes erosion of floodplains?

Floodplain erosion has been made worse by the clearing of catchments for urban and agricultural development for two reasons: first, due to changes in surface and groundwater discharge, and second, due to loss of soil strength.

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11. Apply Concepts You weigh a spoonful of baking soda and 10 mL of vinegar. Then you mix them together. You see that there is quite a bit of fizzing. You weigh the products after the reaction and find there is mass missing. Does the loss of mass disprove the law of conservation of mass? If not, how could you prove it? Please help I have to turn this in before midnight on canvas before its locked.​

Answers

Answer:

The loss of mass does not disprove the law of conservation of mass because the evaporated fizz goes into the air. Same with lakes when there is a big body of water, but it slowly starts to look like a smaller body of water. This is because the water evaporates, but the mass is not destroyed it is just being coverted into gas.

Explanation:

What is the best way to measure the age of the Earth and why? Explain how scientists do this.

Answers

Explanation:

the best way to understand the age of the earth is to estimate the age of matirials in it

What are the three products of respiration?

Answers

Cellular respiration is this process in which oxygen and glucose are used to create ATP, carbon dioxide, and water. ATP, carbon dioxide, and water are all products of this process because they are what is created.

Answer:

water, carbon dioxide and energy are three products of respiration

How many signals would you expect in the proton-decoupled 13c-nmr spectra of the following compounds?a. 3
b. 2
c. 4
d. 1
e. 5

Answers

The correct option is 1 signal expected in the proton-decoupled 13C-NMR spectra. The correct option is D.

13C-NMR spectra: 13C-NMR spectra provide information regarding the number of carbon environments in a compound. The chemical shift ranges for carbons usually observed are between 0-220 ppm. When a compound is subjected to 13C-NMR spectroscopy, all the carbon atoms absorb radiofrequency radiation at varying frequencies, and this absorption generates signals. Therefore, every unique carbon atom absorbs radiofrequency radiation at a unique frequency, which results in the formation of a signal.The number of signals that can be observed in 13C-NMR spectra is determined by the number of carbon environments in a molecule. Carbon environments refer to distinct types of carbon atoms in a compound. A carbon environment may be determined by the types of atoms that are bonded to the carbon. If a carbon atom is bonded to three different types of atoms, it will generate three different carbon environments, which will appear as three distinct signals in the 13C-NMR spectra.Proton-decoupled 13C-NMR spectra: The most common method for acquiring 13C-NMR spectra is through proton-decoupled 13C-NMR spectra. Proton-decoupled 13C-NMR spectra differ from normal 13C-NMR spectra in that they do not show any splitting of the signals caused by the presence of protons. This is because in proton-decoupled 13C-NMR spectra, the protons are saturated by radiofrequency radiation to eliminate the coupling between the 13C and the 1H. Therefore, the number of signals observed in a proton-decoupled 13C-NMR spectrum corresponds to the number of distinct carbon environments in a molecule.How many signals are expected in the proton-decoupled 13C-NMR spectra of the following compounds? Here, we observe only one signal, implying that there is only one type of carbon atom in the molecule, and hence the answer is (d) 1 signal.

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how many element are there on the periodic table?

Answers

Answer:118

Explanation: it’s right

Answer:

118 elements

Hope that helps

Help, please, I really need it.

Help, please, I really need it.

Answers

Answer:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

During a process called photoact, ________ give up an electron as a part of the light-dependent reactions.

Answers

Answer:

Chloroplasts?

Explanation:

Please Help ASAP Students set up a controlled experimernt. They put five
crickets in each of three identical containers. They set one
container to 15C, one to 20°C, and one to 25°C. Then they
count the number of cricket chirps in each container during
1 hour. What are the two constants in this experiment? You have to pick to answers.

A: The number of crickets in each container.

B: The temperature of each container.

C: The number of cricket chirps.

D: The kind of containers used.

Answers

Answer: A

Explanation:in learned this last year:)

A: The number of crickets in each container. and

C: The number of cricket chirps.

are possibly the right answers

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