Use stoichiometry to determine how many moles of O2 are needed
to completely react with 2.25 moles of C3H8. Please show your work

Answer:

im going to go with the water is less dense than the glycerol

Explanation:

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

3.60 moles de CO₂

Explanation:

2CO(g) + O₂(g) → 2CO₂(g)

Para convertir moles de CO en moles de CO₂ debemos usar un factor de conversión con los coeficientes estequiométricos de la reacción, dejando las moles de CO en el denominador y las moles de CO₂ en el numerador:

Answer:

awdaef

Explanation:

The correct rate law of the reaction from the experimental data is k[NO]^2 [O2]. Option D

The rate of reaction is usually expressed in terms of the amount of reactant consumed or product formed per unit time, and is typically measured in units of moles per liter per second (mol/L/s) or similar units.

We have that;

For NO;

3.4 * 10^-5/8.4 * 10^-6 = 2 * 10^-4/ 2 * 10^-4

4 = 2^n

n = 2

For O2;

8.4 * 10^-6/2.8 * 10^-6 = 3 * 10^-4/ 1 * 10^-4

3 = 3^n

n = 1

Thus the rate law of the reaction is;

Rate = k[NO]^2 [O2]

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 22.5 mL

density = 0.23 g/mL

We have

mass = 0.23 × 22.5 = 5.175

We have the final answer as

Hope this helps you

Electrons are transferred from atoms of sodium to atoms of phosphorous The sodium atom looses electron and the phosphorus atoms gains electrons.

The electron is a subatomic particle with an elementary electric charge of -1. Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

This transfer causes the sodium atoms  to acquire positive charge and phosphorous to acquire negative charge .

Thus, the sodium and phosphorus atoms strongly attract with each other.

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Your question is incomplete, most probably, your question was

Complete the paragraph about the formation of sodium phosphide.

Electrons are transferred from atoms of

and the phosphorus atoms

to atoms of

C. This transfer makes the sodium atoms

As a result, the sodium and phosphorus atoms strongly

each other.

The carrying capacity of the area was reduced in the year 10 according to the graph that shows the number of foxes on the island over a span of 15 years.

The graph shows a population of foxes over a span of 15 years. The y-axis represents the number of foxes on the island, while the x-axis represents time. The study began with the earlier 0 and ran until the start of year 15. According to the graph, the carrying capacity of the area was reduced in the year 10.

In the graph, it is shown that the population of foxes on Sunday Gill island had a significant increase from year 0 to year 3. After year 3, the fox population started to decrease and then remained fairly constant until year 10. After year 10, the population of foxes on the island started to decline more rapidly until the end of the study in year 15

This decline in the population of foxes on the island is most likely due to the reduction in carrying capacity of the area. Carrying capacity refers to the maximum number of individuals that an environment can sustain. When the carrying capacity of an environment is reached, it means that the environment can no longer provide the necessary resources to sustain the population.  

There are various factors that can cause a reduction in carrying capacity, such as environmental degradation, competition for resources, or a natural disaster. In this case, it is not clear what caused the reduction in carrying capacity in year 10, but it is likely that it was due to some environmental factor that impacted the availability of resources for the fox population.
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Answer:

how was enacting the GI bill Like teaching someone how to fish

The balance chemical equation is 2H₃PO₄ + 3Mg(OH)₂ → Mg₃(PO₄)₂ + 6H₂O

This is an example of an acid and base neutralizing one another to create salt and water. The reaction is exothermic, emits heat, and can be balanced by adding balancing numbers in front, or molecules, to make sure that the sum of the atom counts for each element on the left and right sides of the equation is the equal.

The law of conservation of matter, which stipulates that matter cannot be generated or destroyed, must be taken into account in order to balance a chemical equation.

H₃PO₄ + Mg(OH)₂ → Mg₃(PO₄)₂ + H₂O

This law states that whatever is available on the reactant side must also be available on the product side.

We must count the atoms on each side of the equation to balance it, and we might also use the number of moles.

The equation is balanced when

2H₃PO₄ + 3Mg(OH)₂ → Mg₃(PO₄)₂ + 6H₂O

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Answer:

3,272,000

Explanation:

Find the number of molecules in 3.72 mol of sulfur dioxide: There are 78.54 g of nitrogen dioxide in 3.72 mol of sulfur dioxide, so there are 3,272,000 molecules in 3.72 mol of sulfur dioxide.

The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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Answer: with enough heat, pressure, and time, the original sedimentary or igneous rock is changed to metamorphic rock.

Explanation:

The heat of the reaction when 27.42 g of iron is reacted is -202.17 kJ.

To calculate the heat of the reaction, we need to first calculate the amount of iron reacted, which can be done using the molar mass of iron:

molar mass of Fe = 55.85 g/mol

moles of Fe = (27.42 g) / (55.85 g/mol) = 0.490 mol

Next, we need to use stoichiometry to determine the amount of Fe2O3 produced:

4Fe(s) + 3O2(g) --> 2Fe2O3(s)

moles of Fe2O3 = (0.490 mol Fe) / 4 * (2 mol Fe2O3 / 4 mol Fe) = 0.245 mol Fe2O3

Finally, we can use the heat of formation of Fe2O3 to calculate the heat of the reaction:

ΔH = n * ΔHf

where n is the number of moles of the product and ΔHf is the heat of formation.

ΔH = (0.245 mol Fe2O3) * (-826.0 kJ/mol) = -202.17 kJ

Therefore, the heat of the reaction when 27.42 g of iron is reacted is -202.17 kJ.

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Answer:

D.

Explanation:

The characteristics of the conservation of energy and momentum allow to find the result for the movement of the balls, the correct answer is:

      D. The mechanical energy of the ball on the left is transferred through

the other balls to the ball on the right.

Mechanical energy is the sum of the kinetic energy and the potential energies. In the case that there is no friction, the mechanical energy is conserved.

The momentum is defined by the product of the mass and the velocity of the body, in an isolated system the momentum is conserved and the shocks can be of two types:

In the case indicated, when removing the ball, it gains a height, therefore if the initial mechanical energy is

          Em₀ = mgh

When it reaches the lowest point, just before it hits the ball its energy is:

           \(Em_f\) = 1 / 2m v²

          Em₀ = Em_f

          v = \(\sqrt{2gh}\)  

collides with the other ball and transfers its momentum in an elastic collision, the balls do not stick, as all the energy of the ball is kinetic, this energy is transferred to each ball until it reaches the last one, where the kinetic energy is transformed into potential energy a increases its height.

Let's analyze the answers:

A. False. This is a collision of particles there are no waves.

B. False. At the lowest point the ball on the left has kinetic energy.

C. False. It is a collision of particles, there are no waves.

D. True. The energy from the elastic collisions is transferred through each ball until it reaches the last ball.

In conclusion, using the characteristics of the conservation of energy and momentum, we can find the result for the movement of the balls, the correct answer is:

      D.  The mechanical energy of the ball on the left is transferred through the other balls to the ball on the right

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Answer:  A, 1.98x10^24 atoms of H

Explanation:  39.0 g of sulfur = (79.0g/32.1 g/mole) = 2.46 moles S

The balanced equation promises we'll get 2 moles H2O for every 3 moles  ofS, a molar ratio of (2 moles H2O)/(3 moles S)

(2.46 moles S)*[(2 moles H2O)/(3 moles S)] = 1.64 moles H2O

(1.64 moles H2O)*(6.02x10^23 molecules H2)/mole H2O)*(2 H atoms/H2O molecule) =  1.97x10^24 atoms of H

Answer:

323.22 ml

Explanation:

Given that :

Diameter, d = 6.8cm

Height, h = 8.9cm

V = arh

Recall :

Volume, V = πr²h

Radius, r = diameter / 2 = 6.8 / 2 = 3.4cm

V = π * 3.4^2 * 8.9

V = 323.21961 cm³

Recall:

1ml = 1cm³

Hence,

323.21961 cm³ = 323.21961 ml

Volume = 323.22 ml

Answer: unlike, will not scatter

Explanation:

Colloids are unlike solutions because their dispersed particles are much larger than those of a solution. The dispersed particles of a colloid cannot be separated by filtration, but they scatter light, a phenomenon called the Tyndall effect.

Answer:

Oxygen-16 has 8 protons and 8 neutrons, and a mass number of 16. Oxygen-17 has 8 protons and 9 neutrons, and a mass number of 17. Oxygen-18 has 8 protons and 10 neutrons, and a mass number of 18.

Explanation:

Answer:

Cu2+ and ClO3 1-

Ga3+ and S-2

Pb4+ AsO3 3-

then balance them as you check my numbers to be sure they are right

Explanation:

Cu2+ and 2ClO3 1-

2Ga3+ and 3S-2

3Pb4+ 4AsO3 3-

Answer:

No, the metal is not pure gold because density is equal to mass divided by volume and in this case we end up with about 15.3, making this metal less dense than gold.

Explanation:

The definition of density allows to find the answer of whether the metal is gold:

Density is defined as the mass of a body divided by its volume, it is a very important physical characteristic of the body since it is invariant.

           \(\rho = \frac{m}{V}\)

Where ρ is the density, m the mass and V the volume

They indicate that the object's mass is 980 g and it has a volume of 64 cm³, ask if it is made of pure gold.

The systems of units are systems of measurements to exchange magnitude without inconveniences, the most used system is the intentional system of measurements (SI), we re-educate the magnitudes to this system

                m = 980 gr (\(\frac{1kg}{1000g}\) ) = 0.980 kg

                V = 64 cm³  \(( \frac{1m}{100 cm} )^3\) = 64 10⁻⁶ m³

let's find the density of the object

            ρ = \(\frac{0.980 }{64 \ 10^{-6} }\)  

            ρ = 15.3 10³ kg/m³

The tabulated gold density  is 19.3 10³ kg/m³

We can see that the density for the body is less than the gold density.

In conclusion with the definition of density we can find the answer for if the metal is gold is:

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Answer:

50 ml

Explanation:

n = moles

c = concentration

v = volume

n = c × v

HCl + NaOH --> NaCl + H2O

HCl:

50 ml = 50 cm³ = 0.05 dm³

n = 0.05 × 0.1

n = 0.005

Ratio of HCl to NaOH:

HCl : NaOH

Based on reaction equation:

1 : 1

0.005 : x

x = 0.005

NaOH:

0.005 = 0.1 × v

v = 0.05

0.05 dm³ = 50 cm³ = 50 ml

Answer:

Flowing water

Explanation:

Flowing water have formed the channel on Mars because the evidence card flowing water formed by water showed the channel formed by water on Earth have a curved and branching similar shape of the channel on Mars.

Flowing of water on the land makes channels on the planet Mars.

The flowing of water is the geologic process that could have formed the channel on Mars. According to the image we can say that flowing of water on the land made the channels on the Mars just like on the earth. When the water flows for a long time from the same area, it takes the sediments and make channels so we can say that the flowing of water makes the channels on the Mars.

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Answer:

The answer is Evolution.

Evolution is a process that results in changes in the genetic material of a population over time. Evolution reflects the adaptations of organisms to their changing environments and can result in altered genes, novel traits, and new species.

Answer:

The atomic is 6, the mass number is 12

Explanation:

The element being described is Carbon.

The number of protons in the nucleus of an atom is called its atomic number, Z.

The number of protons pluss the number of neutronsin the nucleus of an atom gives the atom's mass number, A.

to prevent the glucose undergoing isomerization to an aldehyde, or fructose to alpha-hydroxy-ketone form.