Use the enthalpy of reaction value calculated above to determine how much heat is evolved when 34. 2 ml of 0. 100 m naoh is mixed with 22. 4 ml of 0. 08 m acetic acid?.

a) The total time in air is 34.1 s

b) The maximum height is 1428 m

c) The horizontal distance is 6343 m

d) The velocity after 5 s is 299 m/s

Let us note that the projectile has to do with any object that is moving along a parabolic path.

a) Time of flight = 2usinθ/g

u = initial velocity

g = acceleration due to gravity

θ = angle of projection

T = 2 * 250 sin 42/9.8

= 34.1 s

b) H = v^2sin^2θ/2g

H = (250)^2 sin^2(42)/2(9.8)

H = 27983/19.6

H  = 1428 m

c) R = v^2 sin2θ/g

R = (250)^2sin 2(42)/9.8

R = 6343 m

d) v = u + gt

v = 250 + (9.8 * 5)

v = 299 m/s

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Explanation:

antimatter - counterpart of ordinary matter; identical in every way except for charge. Examples are positrons (counter to electrons) and antiprotons (counter to protons). Direct contact between matter and antimatter results in total annihilation accompanied by huge radiation output.

dark matter - hypothesized as the non-visible or not directly observable kind of matter that could explain some of the unusual behavior of stars and galaxies.

dark energy - hypothesized to be some kind of a repulsive force like anti-gravity that could explain the apparent accelerated rate of expansion of the universe.

degenerate matter - a very dense form of matter made up of fermions (like protons and neutrons) only. Some stars are believed to be made of degenerate matter.

Answer:

Yes. Although the names sound vague and almost fictional, the types of matter called antimatter, dark matter, dark energy, and degenerate matter are all different, specific entities that really exist in our universe. ... Antimatter is just regular matter with a few properties flipped, such as the electric charge.

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Answer:

the number of times the crest of a wave hits a certain point

the more waves, the higher the frequency

Explanation:

Answer:

C, 1800kg/s

Explanation:

You multiply the mass (300) by the change in the two velocities (6-0=0). Then you’ll get 1800.. sorry if I’m wrong

Answer:

F=200 N

a=10m/s2

F=ma

m=F/a=200/10=20m

Explanation:

Given that the trench is 11.0 km deep and that saltwater has a constant density of 1029 kg/m3 throughout, the gauge pressure (in atm) due to the ocean at the bottom of the trench is 992.38 atm.

It is positive for pressures above atmospheric pressure and negative for pressures below atmospheric pressure; gauge pressure is the pressure as compared to atmospheric pressure. Any fluid that is not contained has its pressure increased by the atmospheric pressure. Density is defined as the ratio of mass to volume, or mass per unit volume. It is a way to quantify how much "stuff" an object has in relation to its volume (cubic metre or cubic centimeter). In essence, density is a measurement of how closely stuff is packed together.

P = 100552500/101325

P = 992.38atm

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With the weight formula, the magnitude of the weight on Pluto will be 20.85 N

Gravitational Field can simply be defined as the region of space where gravitational force can be experienced.

Given that on the surface of mercury the gravitational field is 0.38 times its value on earth. That is,

g on Mercury = 0.38 × 9.8

g on mercury = 3.724 m/s²

If the gravitational field on the surface of Pluto is 0.8 times that of mercury, that is,

g on Pluto = 0.8 × 3.724

g on Pluto = 2.9792 m/s²

7.0kg weight W on Pluto = mg

W = 7 × 2.9792

W = 20.85 N

Therefore, 7.0kg mass will weigh 20.85 N on Pluto.

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Answer:

The functionality of a body can be restored with the help of appropriate flexibility and strengthening. Once everything is in place, you can exercise those muscles specifically for balance to put them to the test. Your body may then adjust, improving your general stability as you get better at completing those activities.

Answer:

The stability of an object is increased when the lower the centre of gravity is.

So we should try to lower the centre of gravity.

The magnitude of the velocity of the 6.0 kg mass after the collision is approximately 1.7 m/s.

We can solve this problem using conservation of momentum and conservation of kinetic energy. Conservation of momentum states that the total momentum of a system is conserved if there are no external forces acting on it. In this case, the system is the two masses.

Let p1 and p2 be the initial momenta of the 3.0 kg and 6.0 kg masses, respectively, and p1' and p2' be their final momenta after the collision. Since the 6.0 kg mass is initially at rest, we have:

p1 = m1v1 = (3.0 kg)(10 m/s) = 30 kg·m/s

p2 = m2v2 = (6.0 kg)(0 m/s) = 0 kg·m/s

After the collision, the 3.0 kg mass moves at an angle of 35° with a speed of 8.0 m/s. We can break its velocity into x- and y-components:

vx = v1' cos(35°) = 8.0 m/s cos(35°) ≈ 6.6 m/s

vy = v1' sin(35°) = 8.0 m/s sin(35°) ≈ 4.6 m/s

The total momentum of the system after the collision is:

p1' + p2' = m1v1' + m2v2'

We can use conservation of momentum to say that p1 + p2 = p1' + p2', so:

p1' + p2' = 30 kg·m/s

Substituting in the known values, we have:

(3.0 kg)(6.6 m/s) + (6.0 kg)v2' = 30 kg·m/s

Solving for v2', we get:

v2' = (30 kg·m/s - 19.8 kg·m/s) / 6.0 kg ≈ 1.7 m/s

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Answer:

45383838383833838383338838383838383388383884848484

Explanation:

I 8838383838338

some massive black dwarfs may eventually produce supernova explosions. These will occur if pycnonuclear (density-based) fusion processes much of the star to iron, which would lower the Chandrasekhar limit for some black dwarfs below their actual mass.

i think it goes fall the down winter and then the other seasons

In Activity 1-1, we will make a variety of observations to determine whether like or unlike charges attract each other. We will start by observing the behavior of objects with the same charge,

such as two positively charged balloons or two negatively charged balloons. If they repel each other, we can conclude that like charges repel. Similarly,

we will observe the behavior of objects with opposite charges, such as a positively charged balloon and a negatively charged balloon. If they attract each other, we can conclude that unlike charges attract.

We will also test these observations by changing the charges of the objects, such as by rubbing a balloon on a sweater to give it a charge. Through these observations, we will be able to determine the behavior of like and unlike charges and how they interact with each other.

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Answer:

a) The bullet will penetrate 0.375 meters into the bag of sand.

b) The average force exerted by the sand is 15 newtons.

Explanation:

The statement is incorrectly written. The correct form is presented below:

A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.

a) How far the bullet will penetrate into the bag of sand?

b) The average force exerted by the sand?

b) The average force exerted by the sand on the bullet (\(F\)), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:

\(F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}\) (1)

Where:

\(m\) - Mass of the bullet, measured in kilograms.

\(v_{o}\), \(v_{f}\) - Initial and final speeds of the bullet, measured in meter per second.

\(\Delta t\) - Impact time, measured in seconds.

If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(\Delta t = 0.05\,s\), then the average force exerted by the sand is:

\(F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}\)

\(F = -15\,N\)

The average force exerted by the sand is 15 newtons.

a) The distance travelled by the bullet (\(\Delta s\)), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:

\(\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }\) (2)

If we know that \(m = 0.05\,kg\), \(v_{o} = 15\,\frac{m}{s}\), \(v_{f} = 0\,\frac{m}{s}\) and \(F = -15\,N\), then the distance travelled by the bullet is:

\(\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}\)

\(\Delta s = 0.375\,m\)

The bullet will penetrate 0.375 meters into the bag of sand.

The order to answer this question, we need to use the formula for resolving power, which is given by d = 1.22 λ / NA
the diameter of the objective lens needed to resolve two objects only 400 nm apart using a microscope in air with light of wavelength 550 nm is approximately 5.38 mm.

where d is the smallest resolvable distance between two objects, λ is the wavelength of light, and NA is the numerical aperture of the objective lens. In this case, we are given that the smallest resolvable distance between two objects is 400 nm, the wavelength of light is 550 nm, and the focal length of the objective lens is 1.6 mm. We can solve for NA by rearranging the formula as follows: NA = 1.22 λ / d = 1.22 x 550 nm / 400 nm = 1.68 Now that we know the numerical aperture, we can use the formula for the diameter of the objective lens diameter = 2 x focal length x NA Substituting the given values, we get diameter = 2 x 1.6 mm x 1.68 = 5.38 mm Therefore, the diameter of the objective lens needed to resolve two objects only 400 nm apart using a microscope in air with light of wavelength 550 nm is approximately 5.38 mm.

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Explanation:

The conductivity of water can be increased by adding any solute that increases the number of ions in solution.

Hope this helps you.. Good luck

The conductivity of water can be incrased by adding to it anything that disolves and ionizes in it.

Examples:

-- sugar

-- coffee

-- tea

-- artificial sweetener  

-- baking soda

-- orange juice

-- corn starch

-- salt

Answer:

the answer is 3.8m/s in meters per second

ANSWER:

(a) 0.100 m^3

STEP-BY-STEP EXPLANATION:

We have that the force is equal to mass times gravity, therefore, we can calculate the mass, because the difference in force would be the volume of the stone.

Therefore

Now, we know that the density is equal to the quotient between the mass and the volume, therefore we can calculate the volume like this:

Therefore the volume of the piece is 0.100 cubic meters.

To find the maximum force that can be exerted horizontally on the wooden crate without moving it, we need to consider the maximum static friction force that can be applied.

The maximum static friction force can be calculated using the equation:

\(F_static_max\) = μ_s * N,

where \(F_static_max\)is the maximum static friction force, μ_s is the coefficient of static friction, and N is the normal force.

The normal force is equal to the weight of the crate, which can be calculated as:

N = m * g,

where m is the mass of the crate and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, the mass of the crate is given as 150 kg, so the normal force N is:

N = 150 kg * 9.8 m/s² = 1470 N.

Now, we can calculate the maximum static friction force:

\(F_static_max\) = 0.60 * 1470 N = 882 N.

Therefore, the maximum force that can be exerted horizontally on the wooden crate without moving it is 882 Newtons.

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Facilitated diffusion is a type of transport through a membrane protein channel. A substance moves across the membrane with the help of the channel; however, it moves from high to low concentration (down the concentration gradient) without any energy input. Facilitated diffusion can be described thermodynamically and kinetically.

According to thermodynamics, any chemical or physical process must follow the laws of thermodynamics. For facilitated diffusion, it must follow the second law of thermodynamics. The second law states that the entropy of the system will increase spontaneously. In facilitated diffusion, a substance moves from high to low concentration (down the concentration gradient). This movement follows the law of entropy. Hence, facilitated diffusion follows thermodynamics.

Kinetics refers to the study of the rate and speed of the reaction. In facilitated diffusion, the movement of the substance across the membrane depends on the concentration gradient. Hence, the rate of movement of the substance across the membrane is directly proportional to the concentration gradient. Moreover, the rate of movement of the substance across the membrane also depends on the number of channels available for transport. As the number of channels increases, the rate of transport also increases. Therefore, facilitated diffusion follows kinetics.

In summary, facilitated diffusion can be described thermodynamically and kinetically. It follows the second law of thermodynamics and the rate of transport is directly proportional to the concentration gradient and number of channels available.

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The magnitude of the force of static friction acting on the box is 75 N. Option D is correct.

What is static friction?

It is the frictional force between the two solid objects that are attached to each other.

It can be given by

\(F_s = mg \rm \ sin \theta\)

Where,

\(F_s\) - static friction

\(mg\) - gravitational force =  112. 1 N

\(\theta\) - inclined angle  = 42°

Put the values in the formula,

Fs = 112.1   x   sin42°

Fs = 75 N

Therefore, the magnitude of the force of static friction acting on the box is 75 N.

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Answer: (d)

Explanation:

Given

Mass of the first ram \(m_1=49\ kg\)

The velocity of this ram is \(v_1=-7\ m/s\)

Mass of the second ram \(m_2=52\ kg\)

The velocity of this ram \(v_2=9\ m/s\)

They combined after the collision

Conserving the momentum

\(\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]\)

Momentum after the collision will be

\(\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}\)

Therefore, option (d) is correct

A) To calculate the energy absorbed by the cancerous growth, we can use the equation:

E = Dose × mass

Where:

E is the energy absorbed (in joules),

Dose is the radiation dose (in rads), and

mass is the mass of the cancerous growth (in kilograms).

Substituting the given values:

Dose = 230 rads

mass = 0.19 kg

E = 230 rad × 0.19 kg

E = 43.7 J

Therefore, the cancerous growth absorbs approximately 43.7 joules of energy.

B) To determine the increase in temperature of the cancerous growth assuming it has the specific heat of water, we can use the equation:

Q = mcΔT

Where:

Q is the energy absorbed (in joules),

m is the mass of the cancerous growth (in kilograms),

c is the specific heat capacity of water (approximately 4,186 J/kg·K), and

ΔT is the change in temperature (in kelvin).

We already calculated the energy absorbed (E) to be 43.7 J, and we know the mass (m) is 0.19 kg. Rearranging the equation, we can solve for ΔT:

ΔT = Q / (mc)

ΔT = 43.7 J / (0.19 kg × 4,186 J/kg·K)

ΔT ≈ 56.3 mK (millikelvin)

Therefore, the cancerous growth would experience an increase in temperature of approximately 56.3 millikelvin (mK) assuming it has the specific heat capacity of water.

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Answer:

A

Explanation: The hotter things get the more thermal energy they have

Also don't ever take pictures like this again

Answer:A

Explanation:

1  kg of boiling water is hot enough to melt a block of ice more quickly

Explanation:

Density = Mass / Volume

Denisty of Ethanol = 3.9 g / 5.0 mL

                               = 0.78 g/mL

Density of Benzene = 44 g / 5.0 mL

                                 = 8.8 g/mL

∴ Benzene is Denser.

Assume that the coefficient of kinetic friction among all surfaces is 0. 400.

The newton is the unit of pressure inside the international machine of devices. it is described as 1 kg⋅m/s², the pressure which gives a mass of one kilogram and an acceleration of one meter according to 2nd in step with 2d.

The newton is the standard worldwide unit of pressure. In physics and engineering documentation, the time period newton is generally abbreviated N. One newton is the force required to cause a mass of one kilogram to boost up at a fee of 1 meter per 2nd squared within the absence of other force-producing consequences.

A newton is the international unit of measure for pressure. One newton is equal to a 1-kilogram meter consistent with 2d squared. In simple English, 1 newton of pressure is the force required to boost up an item with a mass of 1 kilogram 1 meter in keeping with 2nd in step with 2d.

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The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

The physical force used to apply pressure to an object is defined as such. Per square inch of an object, a force is applied perpendicularly to its surface. For pressure, the fundamental formula is F/A. (Force per unit area). The Pascal is the unit of pressure (Pa).

The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

            = 50 × 30

            = 1500 cm²

Pressure A = 150/1500

                  = 0.1 N/cm³

                    0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

            = 30 × 15

            = 450 cm²

Pressure A = 150/450

                  = 0.3 N/cm³

                    0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

            = 50 × 15

            = 750 cm²

Pressure A = 150/750

                  = 0.2 N/cm³

                    0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

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The given sequence does converge. It converges to 4. To determine if the given sequence converges, we need to analyze its pattern.

The sequence is defined as {4- (3)}** n=0, where n represents the index of the term in the sequence. The expression within the braces, 4- (3), suggests that each term is obtained by subtracting 3 multiplied by the previous term from 4.

Let's calculate a few terms to observe the pattern:

Term 0: 4 - (3)* = 4 - 0 = 4

Term 1: 4 - (3)4 = 4 - 12 = -8

Term 2: 4 - (3)(-8) = 4 + 24 = 28

Term 3: 4 - (3)*28 = 4 - 84 = -80

From the calculations, it is clear that the sequence does not converge to a specific value. Instead, it oscillates between positive and negative values, never settling down to a single value. Therefore, the given sequence does not converge.

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