2x + 40 = 110
2x = 110 - 40
2x = 70
x = 35
Write a real-world problem involving perimeter that goes with the number sentence 2 x 18+ 2 x 15 = 66.
The real-world problem involving perimeter is that the perimeter of a rectangle of length 18 units and width 15 units is 66 units
How to determine the real-world problem
From the question, we have the following parameters that can be used in our computation:
2 x 18 + 2 x 15 = 66
The perimeter of a rectangle can be calculated using
Perimeter = 2 x Length + 2 x Width
Using the above as a guide, we have the following:
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The dimensions of a right rectangular prism are 3/2ft , 1/2 and 2ft
What is the volume of the prism?
Answer: 1 2/4 ft or 1.5 ft
Step-by-step explanation:
how is 7 square root 2 is equal to 49?
Answer:
Square root is how many times your multiply the number by itself. So 7 square root 2 is 7x7 which is 49.
The July bank statement sent by the bank to ABC company shows a balance of cash on deposit at July 31 of Br.4,964.47 Assume that on July 31, assume the on July 31, ABCs ledger shows a bank balance of Br. 4 173. 83. 1. A deposit of Br 410. 90 made after banking hours and doesnt appear in the bank statement2. A check drawn for Br. 79 had been erroneously charged by the bank Br.973. For checks issued in July have not yet been paid by the bank (outstanding checks). : Theses checks are;- Check No date amount 801 June 15 ---Br.100,00 888 July 24 ----Br. 10.25 890 July 27--- Br. 294.50 891 July 30 ---Br. 205.004. A check written for birr 210 had been incorrectly charged by the bank as birr 120 5. Proceeds from collection of a interest bearing note receivable from David. ABC Company had left this note with the banks collection department. The face amount of the note was birr 500 6. Br. 24.75 interest earned on average account balance during July7. A check for Br. 10 returned with the statement had been recorded in the check register as Br. 100. The check was for the payment of an obligation to Davis Equipment Company for the purchase of office supplies on account 8. Br. 5,00 fee charged by bank for handling collection of note receivable 9. Br. 50.25 check from customer John deposited by ABC company charged bank as Non sufficient fund (NSF) 10. Br. 12.70 service charged by bank for the month of July. 11. Check number 875 was issued July 20 in the amount of Br 85 but was erroneously recorded in the cash payment Journal as Br 58 for payment of telephone expense prepare bank reconcilation and journal entry
The bank reconciliation shows an adjusted bank balance of Br.5,301.42 and an adjusted ledger balance of Br.4,173.83.
To prepare the bank reconciliation and journal entry for ABC Company based on the given information, we need to compare the transactions recorded in ABC's ledger with the transactions shown in the bank statement. Here's the bank reconciliation:
1. Bank Statement Balance:
Cash on deposit at July 31: Br.4,964.47
2. Adjusted Bank Balance:
Bank Statement Balance: Br.4,964.47
3. Deposit not on the statement: + Br.410.90
(Adjusted Bank Balance: Br.5,375.37)
Erroneously charged check: + Br.79
(Adjusted Bank Balance: Br.5,454.37)
Outstanding checks:
Check 801: - Br.100.00
Check 888: - Br.10.25
Check 890: - Br.294.50
Check 891: - Br.205.00
(Adjusted Bank Balance: Br.4,844.62)
4. Incorrectly charged check: + Br.90
(Adjusted Bank Balance: Br.4,934.62)
5. Collection of interest-bearing note: + Br.500
(Adjusted Bank Balance: Br.5,434.62)
6. Interest earned: + Br.24.75
(Adjusted Bank Balance: Br.5,459.37)
7. Incorrectly recorded check: - Br.90
(Adjusted Bank Balance: Br.5,369.37)
8. Collection fee: - Br.5.00
(Adjusted Bank Balance: Br.5,364.37)
9. NSF check: - Br.50.25
(Adjusted Bank Balance: Br.5,314.12)
10. Service charge: - Br.12.70
(Adjusted Bank Balance: Br.5,301.42)
Adjusted Ledger Balance:
Bank Balance in ABC's Ledger: Br.4,173.83
Reconciled Bank Balance: Br.5,301.42
Reconciled Ledger Balance: Br.4,173.83
Journal Entry:
To record the bank reconciliation, we make the following journal entry:
Debit: Cash (Ledger Balance adjustment) - Br.5,301.42
Credit: Cash (Bank Statement Balance adjustment) - Br.4,964.47
Credit: Miscellaneous Income/Expense - Br.336.95 (the difference between the two balances)
This journal entry ensures that the ledger balance matches the reconciled bank balance by adjusting for the discrepancies identified during the reconciliation process.
The journal entry reflects the necessary adjustments to reconcile the two balances, with a debit to Cash (Ledger Balance adjustment), a credit to Cash (Bank Statement Balance adjustment), and a credit to Miscellaneous Income/Expense to account for the difference.
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A man's gross income is R500 000. He worked at different places throughout the year
and a total of 17% of his earnings was deducted by his employers as PAYE throughout
the tax year. He qualifies for a rebate of R13 257. Calculate how much tax he still
owes. Information taken from the tax table shows that, for a taxable income between
R393 201 and R550 100, R93 135 + 36% above R393 200 needs to be paid.
O R101 678
O R71 774
O R33 326
O R25 191
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Previou
Next >
The man still owes R87,726 in taxes.
To calculate the tax amount the man still owes, we need to determine his taxable income first.
Gross income: R500,000
Less: PAYE deductions (17% of gross income): R500,000 * 0.17 = R85,000
Taxable income: R500,000 - R85,000 = R415,000
Next, we can use the tax table information provided to calculate the tax owed based on the taxable income.
Tax owed: R93,135 + 36% of (taxable income - R393,200)
Tax owed: R93,135 + 0.36 * (R415,000 - R393,200)
Tax owed: R93,135 + 0.36 * R21,800
Tax owed: R93,135 + R7,848
Tax owed: R100,983
Finally, we subtract the rebate amount of R13,257 from the tax owed to find the amount the man still owes.
Tax owed - Rebate: R100,983 - R13,257 = R87,726
Therefore, the man still owes R87,726 in taxes.
The correct option is not provided among the given answer choices.
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For the pyramid below draw the net and then calculate its total surface area using your net. ( picture is uploaded)
The total surface area of the pyramid from the net is 286 square cm
Calculating the total surface area from the netTo calculate the total surface area of a pyramid from its net, you need to add up the areas of all its faces.
The net of a pyramid is a two-dimensional representation of the pyramid, where the edges of the net represent the edges of the pyramid.
In this case, the nets are
Rectangle of: 10 by 7Pair of triangles of: 10 by 12.5, 7 by 13Using the above as a guide, we have the following:
Area = 10 * 7 + 2 * (1/2 * 10 * 12.5 + 1/2 * 7 * 13)
Evaluate
Area = 286
Hence, the surface area is 286 square cm
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Y=-3 Y=Ax2+4x-4 In the system of equations above, a and b are constants. For which of the following values of a and b does the system of equations have exactly two real solutions?
A) -4
B) -2
C) 2
D) 4
For constant A to be -4 (option 1) the system of equations have exactly one real solution.
NOTE: We are working with the problem statement: Y=-3 Y=Ax2+4x-4 In the system of equations above, a is constant. For which of the following values of a does the system of equations have exactly one real solution?
We have given, y=-3
y= Ax^2+4x-4
Therefore, -3= Ax^2+4x-4
or, Ax^2+4x-1=0
For second order equation of ax^2+bx+c=0 have a solution for
x= [-b± (√b^2-4ac)]/2a] [Ax2 + Bx + C = 0 is the Sridharacharya equation, where a, b, and c are real values and a 0. The Sridharacharya formula, which is stated as x = (-b (b2 - 4ac)) / 2a, provides the answer to the Sridharacharya equation.]
For single solution b^2-4ac=0
here, Ax^2+4x-1=0
4^2 - 4a(-1)=0
16+4a=0
a= -(16)/4
a= -4
option A is correct .
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This is only true equation when A is equal to -2. Therefore, the correct answer is B) -2.
B) -2
The given system of equations can be written as:
Y = A*x^2 + 4*x - 4
We can solve this equation by using the Quadratic Formula. The Quadratic Formula states that the solutions to the equation are given by:
x = [-b +/- sqrt(b^2-4ac)]/2a
where a, b, and c are the coefficients of the equation. In this case, a = A, b = 4, and c = -4.
Substituting these values into the equation, we get:
x = [-4 +/- sqrt(4^2-4*A*(-4))]/2A
Simplifying this, we get:
x = [-4 +/- sqrt(16 + 16A)]/2A
For the system of equations to have two real solutions, the value of the square root must be greater than or equal to zero. This means that 16 + 16A must be greater than or equal to zero.
This is only true when A is equal to -2. Therefore, the correct answer is B) -2.
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Examine the table, which represents the number of guests visiting a museum during a period of time.
If the relationship between hours and guests is proportional, what is the value of $h$ ?
Enter your answer as a number, like this: 42
Answer:
for me to stay with me every night for a few hours or two of the book ko and then we could use it for me and I believe
Step-by-step explanation:
ma and a couple ko of me who were texting me today so no idea what time I'll get back from work
Find the x and y components of the total electric field at point PP, which is located on the x axis at x=6.00 cmx=6.00 cm.Enter the values for ExEx and EyEy in newtons per coulomb separated by commas.
For the given information, the value of Eₓ and Ey is 20585 Newton/coulomb and 0 N/c respectively.
The electric field is a vector field that describes the force that a charged particle would experience if placed at a given point in space.
Distance between q₁-q₂ = 8cm
Distance between q₁-p = 10 cm
Distance between q₂-p = 6cm
Cos theta = 0.6
Eₓ = E₂ + E₁cos θ + E₃ cos θ
Eₓ = kq₂/(0.06)² + kq₁cos θ/(0.1)² + kq₂cos θ/(0.1)²
Eₓ = 9 × 10^9 × 5.75 × 10^-9[ 1/36×10^-4 + 2(0.6)/0.01]
Eₓ = 9 × 5.75 × [120 + 10000/36]
Eₓ = 20585 N/c
Ey = E₃sin θ - E₁sin θ = 0 N/c
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The length of a rectangle is 4 in longer than its width.
If the perimeter of the rectangle is 32 in, find its area.
Answer:
60 sq in
Step-by-step explanation:
Perimeter = 2l + 2w
If l = w+4
Perimeter = 2(w+4) + 2w
Perimeter = 4w+8
32 = 4w + 8
24 = 4w
6 = w
If w = 6, l = 6+4 = 10
Area = l * w
Area = 10 * 6
Area = 60
Please help me with this problem
Please answer and show how you got them
Answer:
Point form:
1:
(1,2)
Equation form:
1, y = 2
2:
Point form:
(3,0)
Equation form:
x = 3,y,=0
Step-by-step explanation:
On Monday, a middle-school
principal asked the first 100 students
who arrived at school if they walked
to school. The table below shows the results of the principal's survey.
Based on the results shown in the
table above, how many of the school's
850 students should the principal
expect to walk to school?
Answer:
697
Step-by-step explanation:
Hope It Helps!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A piece of electronic equipment is built with 3 cooling fans. The equipment will function only if at least 2 of the 3 fans are working. The lifetimes of the fans are subject to forces of mortality that are independent, constant, and identical. The force of mortality is equal to 0.098. Calculate the probability that the electronic equipment will work for at least 5 years. (Ans 0.66608)
Answer:
0.66608
Step-by-step explanation:
Equipment = 3 fans
Mortality = 0.098
We are required to find probability that equipment gets to work for 5years
The question says forces of mortality is constant and also equal to 0.098
To calculate p(x>5)
We will do this by calculating exponentially
e^-0.098x5
= 0.612626394
Probability that at least 2 fans out of 3 are working
3(0.612626394)²+(1-0.612626394)+(0.612626394)³
= 1.1259333x0.3873736+0.2299255
= 0.6660823470
This is approximately
0.6608
this is the probability that the equipment will work for at least 5years
What is the value of the sum?
Drag and drop the answer into the box to match the sum with its value.
-7/9+2/3
whoever knows what 9+10 is i will reward them
Answer:
19
Step-by-step explanation:
Solve for m.
- 3/7 m = 12
Answer:
-28
Step-by-step explanation:
Isolate m in the equation first: m = 12 / (-3/7)
Simplify and solve: m = -84/3 = -28
Answer:
-28
Step-by-step explanation:
3/7=0.4285714285714
0.4285714285714 × 28 equals 11.99 which is estimated to 12.
Identify the transformation shown by the 2 lines on the graph as a dilation or translation.
a) translation
b) dilation
Answer:
b) dilation
Step-by-step explanation:
Translation:
Figure has the same size, just in different positions.
Dilation:
FIgure has different size.
In this question:
We have function \(f(x) = x\).
And also, we have function \(g(x) = \frac{x}{4}\), that is, the figure f changes in size, is divided by 4. So it is a dilation.
Can someone please answer and provide an explanation for these problems?
The values of x for the tangent segments to the circles are: (25). x = 2 and (26). x = 4
What are the segments tangent to the circleA theorem of tangents to a circle states that if from one exterior point, two tangents are drawn to a circle then they have equal tangent segments.
(25). 2x - 1 = x + 1 {equal tangent segments}
2x - x = 1 + 1 {collect like terms}
x = 2
(26). 2x - 4 = x {equal tangent segments}
2x - x = 4 {collect like terms}
x = 4
Therefore, the values of x for the tangent segments to the circles are: (25). x = 2 and (26). x = 4
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Susan invests $Z at the end of each year for seven years at an annual effective interest rate of 5%. The interest credited at the end of each year is reinvested at an annual effective rate of 6%. The accumulated value at the end of seven years is $X. Lori invests $Z at the end of each year for 14 years at an annual effective interest rate of 2.5%. The interest credited at the end of each year is reinvested at an annual effective rate of 3%. The accumulated value at the end of 14 years is $Y.
Required:
Calculate Y/X.
Answer:
2.02955
Step-by-step explanation:
Given that:
Susan invests $Z as each year ends for seven years.
So we assume that Z = 1
Susan's accrued value comprises $7 invested each year at a 6 percent annual effective rate.
The cashflow interest:
The cashflow of Susan interest payments are:
Payments Time
0 1
0.05 2
2(0.05) 3
3(0.05) 4
4(0.05) 5
5(0.05) 6
6(0.05) 7
The accumulated value of this cash flow is:
\((0.05)I_{6\%} = (0.05) \dfrac{((1+0.06)_{6\%} - 6)}{0.06} \\ \\ \implies 1.1653\)
So Susan accumulated values is:
X = 7 + 1.1653
X = 8.1653
Lori's accumulated value is $14, which she has set aside to plan her cash flow for interest.
The cashflow of Lori interest payments are;
Payments 0 0.025 2(0.025) 3(0.025) ......... 13(0.025)
Time 1 2 3 4 .......... 14
The accumulated value of cash flow is:
\((0.025 )(I)_{3\%} =(0.025) \dfrac{(1+0.03)_{3\%}-13}{0.03}\\ \\= 2.5719\)
Now, Lori's accumulated value is:
Y = 14 + 2.5719
Y = 16.5719
Since; Susan value X = 8.1653
Lori's value Y = 16.5719
∴
\(\dfrac{Y}{X}= \dfrac{16.5719}{8.1653}\)
= 2.02955
Show that the set of functions from the positive integers to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} is uncountable. [Hint: First set up a one-to-one correspondence between the set of real numbers between 0 and 1 and a subset of these functions. Do this by associating to the real number 0.d1d2 . . . dn . . . the function f with f(n).
Answer:
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions
Step-by-step explanation:
set = {0,1,2,3,4,5,6,7,8,9}
setting up a one-to-one correspondence between the set of real numbers between 0 and 1
The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1
hence The power set of (n) is uncountable and is equivalent to the set of real numbers given
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions
I got a question! what is managing liquidity?
Answer:
Liquidity management refers to a set of processes, strategies, and supporting mechanisms/tools that ensure a business or bank is able to access cash when and where it is needed. This cash could be used to pay for goods and services, payroll, debt repayment, or new investment opportunities
Step-by-step explanation:
The area of a rectangular shaped pool is 64 squared meters. The width is 9 meters. Write and solve an equation to determine the length of the pool. Show work.
Answer:
7.11
Step-by-step explanation: Area=lengthxwdth
64=lengthx9
64/9=length
7.11=length
Given: The coordinates of rhombus WXYZ are W(0, 4b), X(2a, 0), Y(0, -4b), and Z(-2a, 0).
Prove: The segments joining the midpoints of a rhombus form a rectangle.
As part of the proof, find the midpoint of YZ.
The midpoint of segment YZ is (-a, -2b).
Given the coordinates of the rhombus WXYZ:
W(0, 4b)
X(2a, 0)
Y(0, -4b)
Z(-2a, 0)
Find the midpoint of YZ:The midpoint formula is given by:
Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)
Substituting the coordinates of Y and Z:
Midpoint of YZ = ((0 + (-2a)) / 2, (-4b + 0) / 2)
= (-a, -2b)
Therefore, the midpoint of segment YZ is (-a, -2b).
Show that the segments joining the midpoints are perpendicular:To demonstrate that the segments joining the midpoints of the rhombus are perpendicular, we need to prove that the slopes of these segments are negative reciprocals of each other.
Let's consider the segments joining the midpoints:
Segment joining the midpoints of WX and YZ:
Midpoint of WX: ((0 + 2a) / 2, (4b + 0) / 2) = (a, 2b)
Midpoint of YZ: (-a, -2b)
Slope of WX = (2b - 4b) / (a - 0) = -2b / a
Slope of YZ = (-2b - (-4b)) / (-a - 0) = 2b / a
The slopes of WX and YZ are negative reciprocals of each other, indicating that these segments are perpendicular.
Conclusion:We have shown that the segments joining the midpoints of a rhombus are perpendicular to each other and have equal lengths. Therefore, these segments form a rectangle.
Additionally, the midpoint of segment YZ is (-a, -2b).
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What is the length of the midsegment of a trapezoid with bases of length 18 and 28?
The length of the midsegment of a trapezoid with the given bases is.
Answer:
midsegment = 23
Step-by-step explanation:
the midsegment is half the sum of the bases, that is
midsegment = \(\frac{18+28}{2}\) = \(\frac{46}{2}\) = 23
A jar contains 24 blue marbles, 16 red marbles, and 14 white marbles. Find the simplified ratio of total marbles to red marbles.
The simplified ratio of total marbles to red marbles is 27 to 8
How to determine the ratio of the marbles?In this question, we have the following parameters
Blue marbles = 24
Red marbles = 16
White marbles = 14
The above parameters mean that
Total marbles = sum of the individual marbles
Substitute the known values in the above equation, so, we have the following representation
Total marbles = 24 + 16 + 14
Evaluate
Total marbles = 54
The ratio is then represented as
Ratio = Total : Red
This gives
Ratio = 54 : 16
Simplify ratio
Ratio = 27 : 8
Hence, the simplified ratio is 27 : 8
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The slope of the line below is 2, use the labeled point to find a point slope equation of the line
(the point is (1,9))
Answer: y-9 = 2(x-1)
Step-by-step explanation:
What is the intermediate step in the form
(x+a)^2=b as a result of completing the square for the following question
The intermediate step in completing the square is\($x^2 + 2ax + (a^2) = b - a^2 + (a^2)$\)
To complete the square for the equation \($(x+a)^2=b$\), we can follow these steps:
1. Expand the left side of the equation: \($(x+a)^2 = (x+a)(x+a) = x^2 + 2ax + a^2$\).
2. Rewrite the equation by isolating the squared term and the linear term: \($x^2 + 2ax = b - a^2$\).
3. To complete the square, take half of the coefficient of the linear term, square it, and add it to both sides of the equation:
\($x^2 + 2ax + (a^2) = b - a^2 + (a^2)$\).
4. Simplify the right side of the equation: \($x^2 + 2ax + (a^2) = b$\).
This step can be represented as: \(\[x^2 + 2ax + (a^2) = b - a^2 + (a^2)\]\)
This intermediate step helps us rewrite the equation in a form that allows us to factor it into a perfect square.
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An AP has first term as 3 and Common difference of 2 how many terms are needed to make the sum to 99
Answer:
9
Step-by-step explanation:
The \(n\)term is \(2n+1\).
\(S_n=\frac{3+2n+1}{2}(n)=99 \\ \\ \frac{n(2n+4)}{2}=99 \\ \\ n(n+2)=99 \\ \\ n^2+2n-99=0 \\ \\ (n+11)(n-9)=0 \\ \\ n=9 \text{ } (n>0)\)
The number of terms that needed to make the sum to 99 is 9
The first term of the arithmetic progression = 3
The common difference = 2
The sum of n term is = (n/2) [2a+(n-1)d]
Where a is the initial term
d is the common difference
Substitute the values in the equation
(n/2) [2(3)+(n-1)2] = 99
(n/2) [6 + 2n - 2] = 99
(n/2)[4+2n] = 99
n(2 + n) = 99
2n + \(n^2\) = 99
\(n^2\) + 2n - 99 = 0
Split the terms
\(n^2\) - 9n +11n - 99 =0
n(n -9) + 11(n - 9) = 0
(n + 11)(n - 9) = 0
n = -11 or 9
Since n cannot be a negative number, therefore n = 9
Hence, the number of terms that needed to make the sum to 99 is 9
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Which is longer 5 meters or 400 millimeters?
a. 400 millimeters
b. 5 meters
c. both a and b are correct.
d. both a and b are incorrect
Answer:
b. 5 meters
Step-by-step explanation:
1 meter = 1000 millimeters
5 meter = 5000 millimeters
Which is longer 5 meters or 400 millimeters?
5000 > 400
So, the answer is b. 5 meters.