Use the ideal gas law equation to find the molar mass of a 98.2 g sample of gas that fills a 50.0-liter container at stp.

multiple choice question.

a)
32.0 g/mol

b)
44.0 g/mol

c)
4.00 g/mol

d)
1.48 g/mol

When only 1 mol of oxygen was intended to be produced, a process instead yields 4.93 L of oxygen. The percent yield of the reaction is 493%.

Percent yield is a measure of how much of the desired product is produced in a chemical reaction. It is calculated by comparing the actual yield of a product to the theoretical yield, which is the amount of product that would be produced if the reaction were 100% efficient.

To calculate the percent yield, you can use the formula:

= percent yield

= (actual yield / theoretical yield) x 100%

The theoretical yield of a reaction is calculated by multiplying the number of moles of reactant used by the stoichiometry of the reaction. In this case, the reaction is supposed to produce 1 mol of oxygen, which is the theoretical yield. To calculate the actual yield, we can use the Ideal gas law PV = nRT, where P is the pressure, V is the volume, n is the number of mol. Since we know that V = 4.93 L, we can use this information to find n:

= n

= (PV) / RT

The actual yield is 4.93 L of O2 or 4.93 L of any gas at STP (Standard Temperature and Pressure) is equivalent to 4.93 moles of O2.

Then we can use this information to calculate the percent yield:

= percent yield

= (actual yield / theoretical yield) x 100%

= (4.93 moles O2 / 1 mole O2) x 100%

= 493%

So, the percent yield of the reaction is 493%.

It's important to note that a percent yield of greater than 100% is usually an indication of an error in the measurement or calculation of the actual yield, or it could be an indication that the theoretical yield is incorrect.

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The increased variation in thorn size could lead to some individuals having thorns that are too large for Ostrilopes to handle, reducing the availability of food resources.

The impact of changing the thorn palm's average thorn size and increasing thorn size variation on the Ostrilopes population would depend on various factors such as the number of thorn palms in the area, the availability of other food sources, and the Ostrilope's ability to adapt to the changes.

Additionally, the relationship between thorn palms and Ostrilopes is complex, and changes in one can have cascading effects on the other and the entire ecosystem. Therefore, more research is needed to understand the specific effects of the thorn palm modifications on the Ostrilope population.

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A. Attenuation is used to control transcription of some anabolic pathways involved in amino acid biosynthesis. Attenuation is a regulatory mechanism in bacteria where the transcription of a gene is terminated prematurely in response to the presence or absence of certain amino acids.

This mechanism is commonly used to regulate the expression of genes involved in amino acid biosynthetic pathways, as it allows the cell to adjust its production of these compounds in response to its immediate needs.

Attenuation involves the formation of a hairpin loop in the nascent RNA transcript that can cause premature termination of transcription, thereby preventing the synthesis of the downstream gene product. By regulating the formation of this hairpin loop, the cell can control the amount of gene product produced, allowing for fine-tuned regulation of anabolic pathways involved in amino acid biosynthesis.

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Answer:

I believe it 3

Answer:nucleus protons nuetrons electrons

Explanation:

The smallest partical into which an element can be divied and still be the smallest element

.( A basic unit o f matter)

Answer:

Nucleus, electrons, and protons

Explanation:

Multiple experiments and results accumulated over the years. Dalton is credited through his ray cathode tube experiments, and Rutherford's Gold Foil experiment led to the discovery of the positively charged nucleus and protons. His student Chadwick continued his studies and discovered the neutron.

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

86.34 g CO₂

Step 2: Identify Conversion

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

\(86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} )\) = 1.18141 × 10²⁴ molecules CO₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

The independent variable, also known as manipulated, is the one that changes and causes an effect on the depenedent variable. The manipulated variable is temperature. Option D.

Independent variables are those modified or changed by the researcher to study how this change affects another variable (the dependent one) and hence the results.

It also receives the name of the manipulated variable because the researcher alters its value or state to analyze its effect. These variables are voluntarily manipulated by the researcher.

In the exposed example,

Goal: To determine the effect of temperature on reaction rates.

Independent (manipulated) variable: Temperature

Dependent variable: time it takes the tablet to dissolve.

Temperature is what affects the time in which the tablet dissolves. The researcher changes temperature levels to analyze how much the time changes.  

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Complete question,

A group of students conducts an experiment to determine the effect of temperature on reaction rates. They perform three separate trials in this experiment.

In the first trial, they drop an antacid tablet into a beaker of water at a temperature of 40 °C and record how long it takes the tablet to completely dissolve.

In the second and third trials, they use the same type and amount of antacid, but they change the temperature of the water to 25 °C for the second trial and 5 °C for the third trial.

The manipulated variable in this experiment is the

A. type of antacid used

B. amount of antacid used

C. time it takes for the reaction to occur

D. temperature at which the reaction occurs

Answer:

27.0833 feet

Explanation:

Answer:

An isochrone map in geography and urban planning is a map that depicts the area accessible from a point within a certain time threshold. An isochrone is defined as "a line drawn on a map connecting points at which something occurs or arrives at the same time".

Explanation:

Answer:

An isochrone (iso = equal, chrone = time) is defined as "a line drawn on a map connecting points at which something occurs or arrives at the same time". In hydrology and transportation planning isochrone maps are commonly used to depict areas of equal travel time.

Explanation:

BRAINLIEST plz

The resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m² is 0.000425 Ω (or 4.25 × 10⁻⁴ Ω).

The formula for calculating the resistance of a wire is:R=ρL/ATo find the resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m², we will need to use the formula.

R = ρL/A

Where R is resistance, ρ is resistivity, L is the length of the wire, and A is the cross-sectional area.

We are also given the following constants:

Resistivity of nickel silver = 8.5 × 10⁻⁸ Ωm

Length of wire = 25 cm

= 0.25 m

Cross-sectional area of wire = 0.05 m²

Now we can substitute the given values into the formula and solve for R:

R = (8.5 × 10⁻⁸ Ωm) × (0.25 m) / (0.05 m²)R

= 0.000425 Ω or 4.25 × 10⁻⁴ Ω

Therefore, the resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m² is 0.000425 Ω (or 4.25 × 10⁻⁴ Ω) (to 3 significant figures).

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The correct option is (d). The correct statement is "The mixture of solvents should allow the substance to crystallize out when cooled." This is because crystallization is a separation technique that is primarily utilized to purify solid organic compounds that are contaminated.

The correct statement is "The mixture of solvents should allow the substance to crystallize out when cooled."This is because crystallization is a separation technique that is primarily utilized to purify solid organic compounds that are contaminated. In order to achieve effective crystallization, the solvents selected must have suitable characteristics. When the solvent is heated, it dissolves the impure compound. The mixture is then cooled until it solidifies in the form of crystals. If the substance is very soluble in solvent 1 but has low solubility in solvent 2, then solvent 1 will be the ideal solvent for dissolving the impure sample so that it can be separated from the mixture as a pure substance. If the two solvents chosen are both organic, they are more likely to dissolve the impure sample than an inorganic solvent would. However, the substance to be purified should be very soluble in the solvent in both solvents and the two solvents chosen should not be miscible. Therefore, the mixture of solvents should allow the substance to crystallize out when cooled.

Crystallization is a separation technique that is primarily utilized to purify solid organic compounds that are contaminated. In order to achieve effective crystallization, the solvents selected must have suitable characteristics. When the solvent is heated, it dissolves the impure compound. The mixture is then cooled until it solidifies in the form of crystals. If the substance is very soluble in solvent 1 but has low solubility in solvent 2, then solvent 1 will be the ideal solvent for dissolving the impure sample so that it can be separated from the mixture as a pure substance. If the two solvents chosen are both organic, they are more likely to dissolve the impure sample than an inorganic solvent would. However, the substance to be purified should be very soluble in the solvent in both solvents and the two solvents chosen should not be miscible. Therefore, the mixture of solvents should allow the substance to crystallize out when cooled.

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Answer:

yes

Explanation:

because density is determined by an objects mass and volume

The Coase theorem is an economic concept that suggests that, under certain conditions, private parties can efficiently resolve externalities through bargaining without the need for government intervention. It was developed by economist Ronald Coase.

First, property rights must be well defined, allowing individuals to negotiate and make agreements.

Second, transaction costs, such as the costs of gathering information and enforcing agreements, should be low.

Overall, the Coase theorem highlights the potential for private bargaining to efficiently resolve externalities when certain conditions are met.

It emphasizes the importance of well-defined property rights and low transaction costs in facilitating voluntary agreements between parties.

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To calculate the volume of concentrated hydrochloric acid needed, we can use the formula:

Volume = Mass / Density

Given:
Mass = 45.17 g
Density = 1.19 g/mL

Let's calculate the volume:

Volume = 45.17 g / 1.19 g/mL
Volume ≈ 37.90 mL

Since the volume is given in milliliters (mL), we can convert it to cubic centimeters (cm^3) because they are equivalent:
Volume = 37.90 mL = 37.90 cm^3
Therefore, approximately 37.90 cm^3 of concentrated hydrochloric acid should be used for the experiment.experiment.

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Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

= 152.00g - 128.10g = 23.90g.

Mass of water loss during heating

= 152.00g - 147.60g = 4.40g.

Molar mass of H2O = 18g/mol

Moles of H2O in sample

= 4.40g / (18g/mol) = 0.244mol.

Mass of anhydrous sample (CuSO4)

= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

= 0.122mol : 0.244mol = 1:2, n = 2.

Hence we have CuSO4 * 2H2O.

Answer:

Copper(II) Sulphate (CuSO4.7H2O) is generally present in a hydrated form.

Mass of the CuSO4.7H2O sample before heating

(152.00-128.10)g = 23.90 grams

Mass of the water loss due to heating

(152.00-147.60)g = 4.40 grams

The formula of compound x is FeCl2.

First, we need to determine the moles of iron used in the reaction:

Moles of Fe = 2.24 g / 56 g/mol = 0.04 mol

Next, we need to determine the moles of chlorine that reacted with the iron. Since the compound contains both iron and chlorine, the difference in mass before and after the reaction can be used to determine the mass of chlorine that reacted.

Since the reaction involves a 1:2 ratio of Fe to Cl2, we can see that all of the iron reacted with the chlorine to form FeCl2. Thus, the formula of compound x is FeCl2.

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All of the following will lead to a homogeneous mixture except mud and water, because,

When the elements that make up a combination are equitably spread throughout the mixture, the mixture is termed to be homogenous. The combination has a constant composition throughout. In a homogenous combination, just one phase of matter would be visible.

Clay, soil, sand, as well as other materials that have been allowed to disintegrate in water, make up mud. As a result of the uneven distribution of its components, we can plainly distinguish them through our eyes in this situation. These factors lead to the classification of mud as a heterogeneous mixture.

Hence, Mud and water does not dissolves in water and not leads to homogenous mixture.

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Answer: electricity energy

Explanation:

Answer:

electricity

Explanation: took the test

The rate of reaction increases by a factor of 320 when the concentration of A is increased 8 times and the concentration of B is increased 10 times.

The given reaction is A + 2B -> products, with the reaction being first-order to A and second-order to B. The rate law can be written as: rate = k[A]^1[B]^2. Now, the concentration of A increases to 8 times its initial value, and the concentration of B increases to 10 times its initial value.

Plugging in these new concentrations into the rate law: rate' = k(8[A])^1(10[B])^2. Simplify this expression to find the ratio of rate' to the initial rate: rate'/rate = (8)(10)^2 = 800/2.5 = 320. Therefore, the rate of reaction increases by a factor of 320 when these concentration changes occur.

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Answer:

double replacement ...i think ^^

i hopefully its right

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

The differences between grasses and legumes are,

The advantage and disadvantage of grasses are given below.

Advantage:

Grasses helps to keep air clean, trap carbon dioxide , reduce erosion from storm water runoff , improve soil , decreases noise pollution and reduce temperature.

Disadvantage:

The advantage and disadvantage of legumes are given below.

Advantage:

Disadvantage:

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The interaction that would form between a polar and a nonpolar molecule is known as a dipole-induced dipole interaction.

This interaction is also called an induced dipole moment. The induced dipole moment is the interaction between a polar and a nonpolar molecule.

The dipole moment arises when an electronegative atom with a partial negative charge interacts with a nonpolar molecule with a partially positive charge. The dipole moment of the polar molecule induces a temporary dipole moment in the nonpolar molecule. Therefore, a temporary dipole is formed in the nonpolar molecule due to the dipole of the polar molecule.

This interaction is one of the two main types of intermolecular forces. Dipole-dipole interactions are the second main type of intermolecular forces. The dipole moment of the polar molecule interacts with the dipole moment of another polar molecule in this case. In addition, hydrogen bonding, London dispersion forces, and van der Waals forces are examples of intermolecular forces.

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If 1.50 × 1024 molecules of oxygen are burned in a combustion reaction. The mass of O2 consumed in the reaction is 80.0 g.

The balanced chemical equation for the combustion of oxygen (O2) is:

2 O2 + energy → 2 O

This equation tells us that for every 2 molecules of O2 that are burned, 2 molecules of O are produced.

We are given the number of molecules of O2, which is 1.50 × 10^24. To determine the mass of O2 consumed in the reaction, we need to use the molar mass of O2 and stoichiometry.

The molar mass of O2 is 32.00 g/mol (2 × 16.00 g/mol). We can use this molar mass to convert the number of molecules of O2 to its mass:

1.50 × 10^24 molecules O2 × (1 mol O2 / 6.022 × 10^23 molecules O2) × (32.00 g O2 / 1 mol O2) = 80.0 g O2

Therefore, the mass of O2 consumed in the reaction is 80.0 g.

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This type of reaction between potassium carbonate (k2co3) and nitric acid (HNO3) is Acid-base neutralization reaction.

2HNO3+K2CO3⇒ 2KNO3+H2O+CO2

Potassium carbonate is a weak base whereas Nitric acid is a very strong acid. The reaction between them neutralizes each other forming water. The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.

Molecular ratio of reactants is 2 : 1.

All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).

The reaction is an acid-base neutralization reaction.

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Answer:

Explanation:

Driving a car (burning gas is a chemical change) and almost all the plastics we use are made by chemical reactions of different components.

Approximately 289 mL of a 1.75 M NaF solution is required to make 681 mL of a 0.234 M NaF solution.

To calculate the volume of the 1.75 M NaF solution needed, we use the dilution formula:

C₁V₁ = C₂V₂

where C₁ and V₁ represent the concentration and volume of the initial solution, and C₂ and V₂ represent the desired concentration and volume of the final solution. Rearranging the formula to solve for V₁, we have:

V₁ = (C₂V₂) / C₁

Substituting the given values, we get:

V₁ = (0.234 M * 681 mL) / 1.75 M ≈ 289 mL

Therefore, approximately 289 mL of the 1.75 M NaF solution is required to make 681 mL of a 0.234 M NaF solution.

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The amount of Ag⁺ present at equilibrium is approximately 9.66 x 10⁻²⁰ moles.

To calculate the amount, in moles, of Ag⁺ present at equilibrium when excess AgI(s) is added to 15.0 mL 0.88 M NaI(aq), follow these steps:

Step 1: Determine the moles of I- ions in the solution.
moles of I⁻ = volume × concentration
moles of I⁻ = 0.015 L × 0.88 mol/L = 0.0132 mol

Step 2: Write the balanced equilibrium equation and expression for Ksp of AgI.
AgI(s) ⇌ Ag⁺(aq) + I⁻(aq)
Ksp = [Ag⁺][I⁻]

Step 3: Use the Ksp value to find the concentration of Ag⁺ at equilibrium.
Ksp = 8.51 x 10⁻¹⁷ = [Ag⁺][I⁻]

Since there's an excess of AgI(s), all I⁻ ions will react to form AgI, and their concentration at equilibrium will be equal to the initial concentration of I⁻ ions (0.0132 mol). Plug this value into the Ksp expression and solve for [Ag⁺]:

8.51 x 10⁻¹⁷ = [Ag⁺](0.0132)
[Ag⁺] = (8.51 x 10⁻¹⁷) / 0.0132

Step 4: Calculate the amount of Ag⁺ in moles.
[Ag⁺] = 6.44 x 10⁻¹⁸ mol/L
moles of Ag⁺ = [Ag⁺] × volume
moles of Ag⁺ = 6.44 x 10⁻¹⁸ mol/L × 0.015 L = 9.66 x 10⁻²⁰ mol

Thus, the amount of Ag⁺ is approximately 9.66 x 10⁻²⁰ moles.

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