v = 84.304 m/s
d = ?
+= 24.6s

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

The vacuum of space

Heat management problems

The difficulty of re-entry

Orbital mechanics

Micrometeorites and space debris

Cosmic and solar radiation

The logistics of having restroom facilities in a weightless

Explanation:

Answer:

v = ( 6.41 i^ + 8.43 j^ + 2.63 k^ ) m/s

Explanation:

We can solve this problem using the kinematic relations, we have a three-dimensional movement, but we can work as three one-dimensional movements where the only parameter in common is time (a scalar).

X axis.

They indicate the initial position x = 8 m, its initial velocity v₀ = 5.5 m / s, the force Fx₁ = 220 N x₁ = 14 m, now the force changes to Fx₂ = 100 N up to the point xf = 17 m. The final speed is wondered.

As this movement is in three dimensions we must find the projection of the initial velocity in each axis, for this we can use trigonometry

the angle fi is with respect to the in z and the angle theta with respect to the x axis.

               sin φ = z / r

                Cos φ = r_p / r

               z = r sin φ

               r_p = r cos φ

the modulus of the vector r can be found with the Pythagorean theorem

               r² = (x-x₀) ² + (y-y₀) ² + (z-z₀) ²

               r² = (14-8) 2 + (-21 + 30) 2+ (-7 +4) 2

               r = √126

               r = 11.23 m

Let's find the angle with respect to the z axis (φfi)

                φ = sin⁻¹ z / r

                φ = sin⁻¹ ( \(\frac{-7+4}{11.23}\) )

                φ = 15.5º

Let's find the projection of the position vector (r_p)

                r_p = r cos φ

                r_p = 11.23 cos 15.5

                r_p = 10.82 m

This vector is in the xy plane, so we can use trigonometry to find the angle with respect to the x axis.

                 cos θ = x / r_p

                 θ = cos⁻¹ x / r_p

                 θ = cos⁻¹ ( \(\frac{14-8}{10.82}\))  

                 θ = 56.3º

taking the angles we can decompose the initial velocity.

               sin φ = v_z / v₀

               cos φ = v_p / v₀

               v_z = v₀ sin φ

               v_z = 5.5 sin 15.5 = 1.47 m / z

               v_p = vo cos φ

               v_p = 5.5 cos 15.5 = 5.30 m / s

               cos θ = vₓ / v_p

                sin θ = v_y / v_p

                vₓ = v_p cos θ

                v_y = v_p sin θ

                vₓ = 5.30 cos 56.3 = 2.94 m / s

                v_y = 5.30 sin 56.3 = 4.41 m / s

we already have the components of the initial velocity

                v₀ = (2.94 i ^ + 4.41 j ^ + 1.47 k ^) m / s

let's find the acceleration on this axis (ax1) using Newton's second law

                Fₓx = m aₓ₁

                aₓ₁ = Fₓ / m

                aₓ₁ = 220/100

                aₓ₁ = 2.20 m / s²

Let's look for the velocity at the end of this interval (vx1)

Let's be careful if the initial velocity and they relate it has the same sense it must be added, but if the velocity and acceleration have the opposite direction it must be subtracted.

                 vₓ₁² = v₀ₓ² + 2 aₓ₁ (x₁-x₀)

let's calculate

                 vₓ₁² = 2.94² + 2 2.20 (14-8)

                 vₓ₁ = √35.04

                 vₓ₁ = 5.92 m / s

to the second interval

they relate it to xf

                   aₓ₂ = Fₓ₂ / m

                   aₓ₂ = 100/100

                   aₓ₂ = 1 m / s²

final speed

                    v_{xf}²  = vₓ₁² + 2 aₓ₂ (x_f- x₁)

                    v_{xf}² = 5.92² + 2 1 (17-14)

                    v_{xf} =√41.05

                    v_{xf} = 6.41 m / s

We carry out the same calculation for each of the other axes.

Axis y

acceleration (a_{y1})

                      a_{y1} = F_y / m

                      a_{y1} = 460/100

                      a_[y1} = 4.60 m / s²

the velocity at the end of the interval (v_{y1})

                      v_{y1}² = v_{oy}² + 2 a_{y1{ (y₁ -y₀)

                      v_{y1}2 = 4.41² + 2 4.60 (-21 + 30)

                      v_{y1} = √102.25

                       v_{y1} = 10.11 m / s

second interval

acceleration (a_{y2})

                      a_{y2} = F_{y2} / m

                      a_{y2} = 260/100

                      a_{y2} = 2.60 m / s2

final speed

                     v_{yf}² = v_{y1}² + 2 a_{y2} (y₂ -y₁)

                     v_{yf}² = 10.11² + 2 2.60 (-27 + 21)

                      v_{yf} = √ 71.01

                      v_{yf} = 8.43 m / s

here there is an inconsistency in the problem if the body is at y₁ = -27m and passes the position y_f = -21 m with the relationship it must be contrary to the velocity

z axis

first interval, relate (a_{z1})

                      a_{z1} = F_{z1} / m

                      a_{z1} = -200/100

                      a_{z1} = -2 m / s

the negative sign indicates that the acceleration is the negative direction of the z axis

the speed at the end of the interval

                    v_{z1}² = v_{zo)² + 2 a_{z1} (z₁-z₀)

                    v_{z1}² = 1.47² + 2 (-2) (-7 + 4)

                    v_{z1} = √14.16

                    v_{z1} = -3.76 m / s

second interval, acceleration (a_{z2})

                    a_{z2} = F_{z2} / m

                    a_{z2} = 210/100

                    a_{z2} = 2.10 m / s2

final speed

                    v_{fz}² = v_{z1}² - 2 a_{z2} | z_f-z₁)

                    v_{fz}² = 3.14² - 2 2.10 (-3 + 7)

                     v_{fz} = √6.94

                     v_{fz} = 2.63 m / s

speed is     v = ( 6.41 i^ + 8.43 j^ + 2.63 k^ ) m/s

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

See below

Explanation:

F = ma       net force is 300 N upward

300 = 306  * a         a = .980 m/s^2

The resultant force is obtained by taking into account the magnitude and direction of all the forces involved.

Motion refers to change in position with respect to time. The instantaneous velocity is the velocity at a given time during motion.

Since force is a vector quantity, we must note that the net force will point in a given direction after taken all other forces into account. The net/resultant force is the force tat will have the same effect in magnitude and direction as all the forces taken together.

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Answer:

Unbalanced Forces.

Explanation:

Answer:

Unbalanced

Explanation:

Unbalanced forces are not equal and they always cause the motion of an object to change the speed and or direction of the object.

Balanced forces are equal and will not cause the motion of an object to change.

From Newton's law of inertia "an object will continue in its state of rest or of uniform motion unless acted upon by an external force".

The net force for a body with unbalanced forces is greater than zero.

For a body with balanced forces, the net force is zero

With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.

We can use the kinematic equations of motion to solve this issue.

Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:

x=1.68 m and v0x=3.04 m/s

Δx = v0x * t

calculating t:

t = 1.68 m / 3.04 m/s because x / v0x.

t = 0.5526 s

Thus, the swimmer enters the water in 0.5526 seconds.

"y" equals "v0y*t" plus "(1/2)*a*t2"

replacing the values with:

Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²

Δy = -1.70 m

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From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

Matter is a substance made up of various types of particles that occupies physical space and has inertia.

A matter must have mass and occupy space.

Examples of matter include the following;

Thus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

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Answer:

They are inversely related

Explanation:

The mass of an object and its ability to pick up speed or accelerate is inversely proportional.

According to newton's second law of motion "the force on an object is the product of its mass and acceleration".

force  = mass x acceleration

 So;  for an object to pick up speed faster, it must have a lower mass. The higher the mass of a body, the lower its acceleration.

At constant speed, there is no acceleration and the mass of the body is not relevant to the motion.

Answer:

you increase the force on the mass and then it will hit the acceleration u seet for it

Explanation:

The correct answer is Self-critical.

Why is self-improvement?

Self-critical:

Self-critical causes them to always strive for self-improvement and never to see accomplishing a goal as good enough.

The characteristic of a turbulent person causes them to always strive for self-improvement and to never see accomplishing a goal as good enough is Self-critical.

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Answer:

If two vectors are equal, their components are also equal. For example, vector A and B both share the same x, y, and z components. By having the same components, the magnitude and direction does not change, which attest to how the vectors are identical.

So, if two vectors are equal, their components are also equal.

In vector mathematics, when two vectors are equal, it means their corresponding components are also equal. Thus, the magnitude and direction of the two vectors must be identical.

In the world of mathematics, specifically vector mathematics, if two vectors are equal, that means their corresponding components are also equal. A vector is typically described by its individual components which are its magnitude (size) and direction.

For example, if vector A and vector B are equal, and vector A = \((x_1, y_1)\) and vector B = \((x_2, y_2)\), then\(x_1 = x_2\) and \(y_1 = y_2\). This applies to vectors in two-dimensional and three-dimensional spaces as well. Therefore, equality in vectors involves the same direction and magnitude causing the corresponding components to be equal.

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Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

Explanation:

some car crashes only produce minor injuries because the car crash isn't that bad.

Answer:

2144.7

Explanation:

The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

Q=45 degrees

Generally, the equation for Force is  mathematically given as

\(\frac{mg}{sin \theta}\)

Therefore

\(F=\frac{17.1*10^{-3}*9.8}{sin45}\)

F=0.237N

Considering horizontal axis or plane

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

\(tan\theta= 30/30\\\\tan\theta=1\\\\\theta=45\)

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Answer:

48N

Explanation:

because as the distance is halfed. the force on the two objects are quadrupled.

Answer:

The final speed of electron=\(5.93\times 10^6m/s\)

Explanation:

We are given that

Initial velocity, u=0

Potential, V=100 V

We have to find the final speed.

Mass of electron, \(m=9.1\times 10^{-31} kg\)

Charge on electron, q=\(1.6\times 10^{-19}C\)

We know that

\(qV=\frac{1}{2}mv^2-\frac{1}{2}mu^2\)

Using the formula

\(1.6\times 10^{-19}\times 100=\frac{1}{2}\times 9.1\times 10^{-31} v^2-0\)

\(v^2=\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}\)

\(v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}}\)

\(v=5.93\times 10^6m/s\)

Hence, the final speed of electron=\(5.93\times 10^6m/s\)

Answer: 0m

Explanation: if you need help with directions just use what I use

N(ever)

W(affles) E(at)

S(oggy)

Try to remember it like how you remembers pemdas, say Never Eat Soggy Waffles

3m east cancels out 3m west

2m north cancels out 2m south

So you’ll remain back where you started once you’re finished

Hope I helped

The substance that loses electrons is being oxidized and is the reducing agent. 

When thermal conduction is occurring within a solid, the particles vibrate faster. (option C)

When thermal conduction occurs within a solid, the particles of the solid undergo certain changes. Here is a step-by-step explanation:

Thermal conduction:

Thermal conduction is the transfer of heat energy within a solid material due to the movement of its particles. It occurs when there is a temperature gradient within the solid, where one end is at a higher temperature and the other end is at a lower temperature.

Particle motion:

In a solid material, the particles are closely packed and held in a fixed position by intermolecular forces. However, when thermal energy is supplied to the solid, the particles gain kinetic energy and begin to vibrate.

Increased kinetic energy:

The transfer of heat energy causes the particles to gain kinetic energy, which results in increased vibrational motion. The particles oscillate around their equilibrium positions more vigorously.

Vibrational motion:

As the particles vibrate faster, their amplitude of vibration increases. This increased vibrational motion allows the particles to pass on their kinetic energy to neighboring particles through collisions.

Transfer of heat:

The faster vibration of particles enables the transfer of heat energy from higher temperature regions to lower temperature regions within the solid. The particles with higher kinetic energy collide with neighboring particles, transferring the thermal energy.

In summary, during thermal conduction within a solid, the particles do not move in the same direction, move past each other, or slow down. Instead, they vibrate faster around their equilibrium positions, enabling the transfer of heat energy through the solid material.

Therefore, the correct answer is C. They vibrate faster.

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(a) Using the right-hand rule, the force on wire 2 due to wire 1 will be directed downwards, in the negative y-axis direction.

(b)  The magnetic field around wire 1 is in the clockwise direction when viewed from above the wire

To determine the direction of the force acting on the wires, we can use the right-hand rule.

Imagine curling the fingers of your right hand in the direction of the current in wire 1, which is into the page. The thumb of your right hand will point in the direction of the magnetic field created by wire 1 at the location of wire 2.

Next, imagine rotating your hand so that your thumb points in the direction of wire 2's current, which is towards the positive x-axis. The direction your fingers curl now indicates the direction of the force acting on wire 2 due to the magnetic field created by wire 1.

Thus, using this right-hand rule, we find that the force on wire 2 is directed downwards, in the negative y-axis direction

To determine the direction of the magnetic field around wire 1, we can use the right-hand grip rule.

Imagine gripping wire 1 with your right hand, so that your fingers wrap around the wire in the direction of the current, which is into the page. Your thumb will then point in the direction of the magnetic field lines around the wire.

Thus, using this rule, we find that the magnetic field around wire 1 is in the clockwise direction when viewed from above the wire.

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So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

Hi ! In this question, I will help you. This question will addopt the principle of final velocity in free fall. Free fall is vertical downward movement that occurs when any object dropped without initial velocity. In othee word, the object that falls is only affected by the presence of gravity and its initial high. In general, the final velocity in free fall can be expressed by this equation :

\( \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} \)

With the following condition :

We know that :

Note :

At this point (2.101 m above the ground), the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

Step by Step

\( \sf{v = \sqrt{2 \times g \times \Delta h}} \)

\( \sf{v = \sqrt{2 \times g \times (h_1 - h_2)}} \)

\( \sf{v = \sqrt{2 \times 9.8 \times (12.09 - 2.101)}} \)

\( \sf{v = \sqrt{19.6 \times 9,989}} \)

\( \sf{v \approx \sqrt{195.78}} \)

\( \boxed{\sf{v = 13.99 \: m/s \approx 14 \: m/s}} \)

So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

Answer:

\(\huge\boxed{\sf m=1.96 \ kg}\)

Explanation:

Speed = v = 15 m/s

Kinetic Energy = K.E. = 220 J

Mass = m = ?

\(\displaystyle K.E. = \frac{1}{2} mv^2\)

Put the givens

\(\displaystyle 220 =\frac{1}{2} m(15)^2\\\\\times 2 \ to \ both \ sides\\\\220 \times 2 = m (225)\\\\440 = m (220)\\\\Divide \ 220\ to \ both \ sides\\\\440/225 = m\\\\1.96 \ kg=m\\\\m=1.96 \ kg\\\\\rule[225]{225}{2}\)

Answer:

Explanation:

Average speed is distance traveled over time taken to do so

home to station

d = 60 km

t = 60 km/60 km/hr = 1 hr

station to shop

d = 60 km

t = 60 km / 120 km/hr = ½ hr

speed

s = (60 + 60) / (1 + ½) = 120/1.5 = 80 km/h

The net force on particle q₁ is 9.22 × 10^-13 N, and it points to the left.

The net force on particle q₁ due to particles q2 and q3 can be found using Coulomb's law.

Coulomb's law states that the force between two charged particles is given as

F= k * (q₁ * q₂) / r^2

Since q₁ and q₂ have the same charge, the force between them is repulsive, i.e., it points to the left. Using Coulomb's law, we can find the magnitude of this force:

F₁₂ = k * (q₁ * q₂) / r₁₂^2

F₁₂ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₁₂ = -4.61 × 10^-13 N

Here,  the force between q₁ and q₂ points to the left, and its magnitude is 4.61 × 10^-13 N.

The  force between q₂ and q₃ also points to the left, and its magnitude is given as

F₂₃ = k * (q₂ * q₃) / r₂₃^2

F₂₃ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₂₃ = -4.61 × 10^-13 N

Here,  the force between q₂ and q₃ also points to the left, and its magnitude is 4.61 × 10^-13 N.

F_net = -F₁₂ - F₂₃

F_net = -(-4.61 × 10^-13 N) - (-4.61 × 10^-13 N)

F_net = 9.22 × 10^-13 N

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