V2 Problem 2.4 In the turbine of a gas turbine unit the gases flow through the turbine at 17kg/s and the power developed by the turbine is 14 000kW. The specific enthalpies of the gases at inlet and outlet are 1200 kJ/kg and 360 kJ/kg respectively, and the velocities of the gases at inlet and outlet are 60 m/s and 150 m/s respectively. Calculate the rate at which heat is rejected from the turbine. Find also the area of the inlet pipe given that the specific volume of the gases at inlet is 0.5m³/kg. Solution​

Answers

Answer 1

The rate at which heat is rejected from the turbine is 14,000kW and the area of the inlet is 0.1417m²

Solution to Thermodynamic Problem

To find the heat rejected from the turbine, we apply the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

Mathematically,

    ΔU = Q - W

where

ΔU = change in internal energy,

Q = heat added to the system,

W = work done by the system.

Assuming the gas turbine unit operates under steady-state conditions, the change in internal energy of the gases passing through the turbine is negligible. With that we can say, the heat rejected by the turbine is equal to the work done by the turbine:

    Q = W = 14,000 kW

Therefore, the rate at which heat is rejected from the turbine is 14,000 kW.

To find the area of the inlet pipe, we can use the continuity equation:

m = ρ * A * V

but we are given:

m = mass flow rate = 17kg/s

V= velocity = 60m/s

v = specific volume = 0.5m³/kg

ρ = density =  1/v = 1/0.5 = 2kg/m

By making A the subject of the formula we have,

A = m / (ρ * V)

A = 17 / (2 * 60)

A = 0.1417 m²

Therefore, the area of the inlet pipe is approximately 0.1417 m².

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Related Questions

2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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describe the relationship between the direction of the velocity vector and the direction of the acceleration for a body moving in a circle at coinstant speed

Answers

Answer:

a = v²/r

Explanation:

The acceleration of a body moving in a circular path is known as the centripetal acceleration. This is the acceleration of a body that keeps the body within the circular path. It is written in terms of the linear velocity v and the radius of the circle of rotation as shown;

a = v²/r where

v is the linear velocity

r is the radius

a is the centripetal acceleration

You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.

Answers

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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Which switches must be pressed to make bulb x come on

Answers

Answer:

Did you forget to attach the image?

Explanation:

So far, we're not sure that you even HAVE a bulb or any switches.

If you had them, you probably would have included a diagram of the circuit you built with them. THEN we could look at the diagram and answer this question.

Right now, we can't.  We haven't seen such a diagram.

1 point
4. When mass is in kilograms and velocity is in meters per second then
momentum is in kilograms-meters per second.
True
Ο Ο
False

Answers

Answer:

true

Explanation:

momentum = kg (m/s)

momentum = mass × velocity

A capacitor is formed from two square plates of edge length a and separation d, with d <

Answers

Answer:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Explanation:

A capacitor is formed from two square plates of edge length a and separation d, with d <

A closed, rigid container holding 0.2 moles of a monatomic ideal gas is placed over a Bunsen burner and heated slowly, starting at a temperature of 300 K. The initial pressure of the ideal gas is atmospheric pressure, and the final pressure is four times the initial pressure.

Determine the following:
a. the change in the internal energy of the gas.
b. the work done by the gas.
c. the heat flow into or out of the gas.

Answers

Answer:

a) 2250 J

b) 0 J

c) 2250 J

Explanation:

a) Since, the process is isochoric

the change in internal energy

\(\Delta U = n C_v(T_f-T_i)\)

Here, n = 0.2 moles

Cv = 12.5 J/mole.K

We have to find T_f so we can use gas equation as

\(\frac{P_1V_1}{P_2V_2} =\frac{T_i}{T_f}\\Since, V_1=V_2 [isochoric/process]\\\Rightarrow \frac{P_{atm}}{4P_{atm}} = \frac{300}{T_f} \\\Rightarrow T_f = 1200 K\)

So,  \(\Delta U= 0.2\times12.5(1200-300)\\=2250 J\)

b) Since, the process is isochoric no work shall be done.

c) By first law of thermodynamics we have

\(\Delta U = Q-W\\Since, W = 0\\\Delta U = Q\\Therefore, Q = 2250 J\)

Since, Q is positive 2250 J of heat will flow into the system.

A truck initially traveling at 20m/s decelerated at 1.50m/s2. Find (a) how long it takes to stop (b) how far it moves in that time and (c) how far the truck moves in the third second after the brakes are applied

Answers

vf² = vi² + 2ad

vf = vi +at

vf = final velocity

vi = initial velocity

decelerated = a = - (negative)

a. stop ⇒ vf = 0

vf = vi+at

0 = 20 - 1.5t

1.5t=20

t = 13.3 s

b. vi = 20 m/s

0 = 20² - 1.5d

1.5d = 20²

1.5d = 400

d =266.67 m

c. d = vi.t -1/2at²

d = 20.3 - 1/2.1.5.3²

d = 53.25 m

What essential nutrient is so important and makes up approximately 80% of the body.

Answers

Protein

it's the main component of muscles, bones, organs ext.

3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?​

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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How much force does it take to give a 70 kg object an acceleration of 20 mls2

Answers

Answer:

heyy

Explanation:how r uuu

Write the equation in standard form for the circle with center (3,10) and radius 2. hxhtojuqat , ​

Answers

The standard form equation for the circle with center (3, 10) and radius 2 is: \(\rm 2.x^{2} + y^{2} - 6x - 20y + 105 = 0.\)

What are the seven components of a circle?

The radius, diameter, circumference, arc, chord, secant, tangent, sector, and segment are all parts of a circle.

A circle is a round figure with no corners or edges. A circle is a closed shape, a two-dimensional shape, and a curved shape in geometry.

A circle with center (h, k) and radius r has the following standard form equation:

\(\rm (x-h)^{2} + (y-k)^{2} = r^{2}\)

Substituting the values of center and radius:

\(\rm (x-3)^{2} + (y-10)^{2} = 2^{2}\)

Simplifying the equation:

\(\rm x^{2} - 6x + 9 + y^{2} - 20y + 100 = 4\)

\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)

\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)

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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 32.0o above the snow. The tension in the rope is 105.0 N. How much work is done on the toboggan by the tension force?

Answers

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)

Answers

The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:

F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².

Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.

The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.

Therefore, we have:

m₁ = 50 kg

m₂ = 7 × 10²² kg

r = 380,000,000 m

G = 6.7 × 10⁻¹¹ N m²/kg²

Substituting these values into the formula, we get:

F = (G × m₁ × m₂) / r²

F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²

F = 1.15 N

Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.

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The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond ?​?

Answers

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

If a giant molecular cloud is a distance of 21 pc away from Earth and drifts at a speed of 21 km/s toward Earth, how long (in years) would it take to reach Earth if the Sun remained at its current position?

Answers

The time it would take it to reach Earth if the Sun remained at its current position is 978,349.5 years.

What is the time of motion of the giant molecular cloud?

The time of motion of the giant molecular cloud is the time take for the giant molecular cloud to reach the earth.

Mathematically, the time taken for the giant molecular cloud to reach the earth is given as;

time = distance / speed

where;

the distance = 21 pc = 6.48 x 10¹⁴ kmspeed of the cloud = 21 km/s

time of motion = (6.48 x 10¹⁴ km) / (21 km/s)

time of motion = 3.086 x 10¹³ seconds = 978,349.5 years.

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During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 26.0 kg and its horizontal component of velocity is 8.50 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball

Answers

Answer:

the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.

Explanation:

mass of the cannon ball, m₁ = 26 kg

initial velocity of the cannon ball, u₁ = 8.5 m/s

mass of the elderly performer, m₂ = 65 kg

Let the velocity of the elderly performer after catching the cannon ball = u₂

Apply the principle of conservation of linear momentum to determine the velocity of the elderly performer after catching the cannon ball.

m₁u₁ = m₂u₂

\(u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{26 \times 8.5}{65} \\\\u_2 = 3.4 \ m/s\)

Therefore, the velocity of the elderly performer after catching the cannon ball is 3.4 m/s.

The motion of a ball on an inclined plane is described by the equation Ax = 1/2a(At)^2. This statement implies which of the following quantities has a value of zero?​

Answers

Answer: Initial Velocity

Explanation:

The formula is:

Δx = Vit + 1/2at^2

Therefore the initial velocity is zero

You apply a very small force, say 0.001 newtons, to a very large truck, with a mass of 2000 kilograms. What can you say for sure about what will happen to the truck?
The truck will accelerate (move from rest to motion) as long as that tiny force is larger than any force of friction that opposes it.

The truck will not move because small forces cannot move large objects.

The truck will accelerate (move from rest to motion) as long as the small applied force is large enough to overcome the inertia of the truck.

An extremely small force can never accelerate such a large truck. The truck will not move under any circumstance.

Answers

Answer:

it will stay still. unless its in space.

Explanation:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Answers

Student 1 is feeling hot and sweaty because the body is trying to regulate its internal temperature through the process of thermoregulation. When we exercise or engage in physical activity, our muscles produce heat

Student 2's red cheeks are a result of vasodilation. When we exercise, our body needs more oxygen and nutrients to fuel the muscles. Student 3 is breathing hard because the body needs more oxygen to fuel the muscles during physical activity.

What happens when we exercise?

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

How does gravity affect your ability to live on a planet?

Answers

If we didn’t have it, we might just float into space. Or it would be hard to live with everything floating around
If it were too light, we would float off, too heavy, and then our bones would have to be extremely dense lest we want to get crushed by just existing

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3Which statement describes the transformation of

Answers

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.

A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in

Answers

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Please help with this! Thank you!

Please help with this! Thank you!

Answers

In an atom, the protons and neutrons are present in the nucleus and electrons revolve in shells .

What is an atom?

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

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(5%) Problem 13: Three uniform spheres are rolling without slipping Sphere A hat mau M and tadius R Sphere Bhas mass 2M and radius 28. Sphere C has maus Mind radius 2R 25% Part() The spheres are placed at the top of an incline and released from rest. Which one is first to reach the bottom of the incline? Choose the best answer Grade 5mmary OB Deduction 09 ΟΑ. Pot 1009 QC All three reach the bottom at the same time Salons Attempting per po 25% Part (6) The spheres are rolling on a flat surface with the same linear speed. Which one has the largest angular speed? Choose the best answer Grade Summary O A and Deductions Bande Potential 10095 All three spheres have the same angular speed ОА Submissions Attempts remaining per attempt detalii 25% Part() The spheres are rolling on a flat surface with the same angular speed. Which one has the largest linear speed? Choose the best answer Grade Summary O A and COAOA, B and C OB and Potes 100% Deduction 09 Submissions Attraps e top of an incline and released from rest. Which one is first to reach the bottom of the incline? Choose the best answer A 25% Part (b) The spheres are rolling on a flat surface with the same linear speed. Which one has the largest angular speed? Choose the best answer A 25% Part() The spheres are rolling on a flat surface with the same angular speed. Which one has the largest linear speed? Choose the best answer 4 239 Part (d) Which of the spheres has the largest moment of inertia? Choose the best answer OC Grade Summary Dedactice 09 ОА Potential All three spheres have the same moment of mettia Submit Attempt 100% OB

Answers

Based on the given question, A has highest angular speed, B and C has highest linear speed and B has highest moment of Inertia.

What are spheres?

A sphere is a geometrical object that is a three-dimensional analog to a two-dimensional circle. A sphere is a set of points that are all at the same distance r from a given point in three-dimensional space. That given point is the center of the sphere, and r is the sphere's radius.

From the given question,

\(m_{A} = M\\ m_{B} = 2M\\m_{C} = M\\R_{A} = M\\R_{B} = 2R\\R_{C} = 2R\\\\\)

a) The acceleration of a body along an inclined for rolling without slipping is given by -

\(a = \frac{ g sin \theta}{1 + \frac{I}{mR^{2} } }\)

For Spheres, I = 2/5 mR²

\(a_{A} = \frac{ g sin \theta}{1 + \frac{2}{5}mR^{2} } } =\frac{5g sin \theta}{7}\)

\(a_{B} = \frac{g sin \theta}{1 + \frac{\frac{2}{5}(2m)(2R^{2} ) }{(2m)(2R^{2} )} } = \frac{5g sin \theta}{7}\)

\(a_{C} = \frac{g sin \theta}{1 + \frac{\frac{2}{5}(m)(2R^{2} ) }{(m)(2R^{2} )} } = \frac{5g sin \theta}{7}\)

Since all three above values are same so they reach at same time.

b) Let the linear speed be V

We have angular speed ω  = V/R

ωA = V/R, ωB = V/2R, ωC = V/2R

A has highest angular speed

c) Let the angular speed be ω

VA =  ωR,

VB =  ω(2R)

VC =  ω(2R)

B and C has highest linear speed

D) Moment of Inertia for solid sphere = I = 2/5 mR²

⇒ IA = 2/5 mR²

IB = 2/5 (2m)(2R)² = 16/5 mR²

Ic = 2/5 (m)(2R)² = 8/5 mR²

B has highest moment of Inertia

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Which type of marco molecules help a cell break down food?

Answers

Answer: Each macromolecule is broken down by a specific enzyme. For instance, carbohydrates are broken down by amylase, sucrase, lactase, or maltase. Proteins are broken down by the enzymes pepsin and peptidase, and by hydrochloric acid. Lipids are broken down by lipases.

Explanation:

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Light travels slowest in high density media, faster in lower density media, and fastest in low density media.
Which wave behavior is observed when light passes through media of different densities?
A
diffraction
B
reflection
C
refraction
D
interference

Answers

Based on what we know, we can confirm that the wave behavior being observed when light passes through media of different densities is refraction.

What is refraction?

This is a term used to explain the behavior of light as it moves through distinct mediums. This behavior includes a change in direction of the light due to its change in speed.

Therefore, the wave behavior being observed when light passes through media of different densities is refraction.

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which force acts during projectile motion

Answers

Answer: Gravity

Explanation:A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

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