Valentina, an astronaut, has a mass of 46 kg. She is floating motionless, 21 meters away from her spaceship. She throws her 2.5 kg camera in the opposite direction of the spaceship with a velocity of 12 m/s.

A. How fast will Valentina be moving back towards the spaceship?

B. How long will it take her to eventually reach the spaceship?

1.44*10^-3N  is the force on each other. when 33 centimeters separates one charge from another charge. They both have charges of 1.2 x 10-5 coulombs.

Charge on the first sphere, q 1​ =1.2 x 10^-5  C

Charge on the second sphere, q 2 =1.2 x 10^-5  C

Distance between the spheres, r=30cm=0.3m

F= 4πε

​ q 1 q 2/  r2

​Where, ε 0

​ = Permittivity of free space 4πε 0

=9×10^9Nm2

F= (0.33) 2

1.2 x 10^-5 * 1.2 x 10^-5  C = 1.44*10^-3N

Hence, force between the two small charged spheres is 1.44*10^-3N.

The charges are of same nature. Hence, force between them will be repulsive.

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Answer:

The car that is hald as massive

Explanation:

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

It would take approximately 1.03 nanoseconds for the signal to travel 0.200 m through the optical fiber.

To calculate the time required for a signal to travel through an optical fiber, we can use the formula:

t = d / v

Where:

t is the time in seconds,

d is the distance traveled by the signal,

v is the velocity of light in the fiber.

The velocity of light in a medium is given by the formula:

v = c / n

Where:

c is the speed of light in a vacuum,

n is the refractive index of the medium.

The speed of light in a vacuum is approximately \(3.00 x 10^8\) meters per second (m/s).

Plugging in the given values:

\(v = (3.00 x 10^8 m/s) / 1.55\\v ≈ 1.94 x 10^8 m/s\)

Now we can calculate the time:

\(t = (0.200 m) / (1.94 x 10^8 m/s)\)

\(t ≈ 1.03 x 10^(-9) seconds\)

Converting to nanoseconds:

t ≈ 1.03 nanoseconds

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While some waves refract, others reflect. Since the refracted waves reacted in the direction of the normal, they must have gone into a denser material. The reflected wave obeys the law of reflection by bouncing off in a new direction at an equal angle. The right response is (b).

The two outcomes that can occur when waves collide with a barrier between two mediums with varying densities are accurately described by this statement.

Refraction and reflection are two different types of wave action. If the waves refract in the direction of the normal, they will go into a denser material.

The law of reflection, which stipulates that the angle of incidence is equal to the angle of reflection with regard to the normal at the point of reflection, is another principle that the reflected wave abides by.

Therefore, option (b) is the one that should be chosen.

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Answer:

C. 3.2 x 10^8 Ω•m

Explanation:

An insulator is a material that resists the flow of electricity.

In the given data the material with the highest resistivity is the best insulator

3.2 x 10^8 Ω•m

(a) The speed of the block when it leaves the spring is 3.87 m/s.

(b) The speed of the block the moment it first become airborne is 2.28 m/s.

(c) The speed of the block when it hits the ground is 5.88 m/s.

(d) The largest mass of the block that will still allow it to reach the ground is 459.3 g.

The speed of the block when it leaves the spring is calculated by applying the principle of conservation of energy.

¹/₂mv² = ¹/₂kx²

mv² = kx²

v² = kx²/m

v = √(kx²/m)

where;

v = √(200 x 0.15²/0.3)

v = 3.87 m/s

The moment the block moves upwards, gravity will set in. The speed of the block the moment it first become airborne is calculated as follows;

v² = u² - 2gh

where;

v² = 3.87² - 2(9.8 x 0.5)

v² =  5.18

v = √5.18

v = 2.28 m/s

The speed of the block when it hits the ground is calculated as follows;

v² = u² + 2gh

where;

v² = 2.28² + 2(9.8)(1.5)

v² = 34.598

v = √34.598

v = 5.88 m/s

The maximum potential energy of the spring is calculated as;

U(max) = ¹/₂kx²

U(max) = ¹/₂ x 200 x 0.15²

U(max) = 2.25 J

The minimum speed required to cross the 1.5 m of the ramp from a height of 1 m.

v = √2gΔh

v = √(2 x 9.8 x 0.5)

v = 3.13 m/s

Apply the principle of conservation of energy and determine the largest mass required to cross the 1.5 m ramp from a height of 1 m.

¹/₂mv² = U(max)

m = 2U/v²

m = (2 x 2.25) / (3.13²)

m = 0.4593 kg

m = 459.3 g

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The current is 3.33A, the resistance is 36.03 Ohm, and the peak voltage is 169.68V.

Given information:

The power rating of the resistive element (P) = 400 W

Voltage supplied by the outlet (V) = 120 VAC (RMS)

a) To find the current flowing through the element, the formula:

Power (P) = Voltage (V) × Current (I)

Current (I) = Power (P) / Voltage (V)

Substituting the given values:

Current (I) = 400 W / 120 VAC

= 3.33 A

b) To find the resistance of the element, Ohm's Law can be used :

Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 120 VAC / 3.33A

= 36.03 Ohm

c) To find the peak voltage, it is required to convert the RMS voltage to peak voltage. For an AC voltage, the relationship between RMS voltage (\(V_{rms\)) and peak voltage (\(V_{peak\)) is given by:

\(V_{peak} = V_{rms} \times \sqrt2\)

Substituting the given RMS voltage:

Peak voltage  = \(120 \times \sqrt2\)

= 169.68 V

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Answer:

  96 m

Explanation:

The average velocity over those 4 seconds is the velocity after 2 seconds:

  30 m/s -(2 s)(3.0 m/s^2) = 24 m/s

The displacement is the product of this average velocity and the duration of the acceleration:

  d = (24 m/s)(4 s) = 96 m

The boat covered 96 m while being accelerated.

A group of proteins that act as electron carriers make up the electron transport chain.

All of the electrons that enter the transport chain come from NADH and FADH2 molecules created during the glycolysis, pyruvate oxidation, and citric acid cycle, which are early phases of cellular respiration.

Electrons are transferred from one molecule to another in the electron transport chain, and the energy released during these electron transfers is utilised to create an electrochemical gradient. The energy held in the gradient is utilized in chemiosmosis to produce ATP.

NAD +start superscript, plus, end superscript (nicotinamide adenine dinucleotide, as illustrated below) and FAD are two forms of electron carriers that are particularly significant in cellular respiration (flavin adenine dinucleotide).

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true because

brick: solid

milk: liquid

ice cube: solid

Answer:

1.83 meters

Explanation:

1 meter = 100 cm

183cm/100cm= 1.83 meters

Answer:

a driver is driving a car, the car will keep moving unless the rider or driver applies a frictional force through the brakes to stop it as he is driving he then throws a ball thrown onto the ground exerts a downward force; in response, the ground exerts an upward force on the ball and it bounces then while watching the ball movement his car crashes

Explanation:

1st law (inertia) force is applied to the car

2nd law f = m x a the car crash

3rd law the ball bounce ( for every action there is an opposite reaction)

The velocity of the trolley system with the block in it is 1.33 m/s.

Weight of the block, W = 30 N

Mass of the block, m = W/g

m = 30/10 = 3 kg

Mass of the trolley, M = 6 kg

Initial velocity of the trolley, u = 2 m/s

According to law of conservation of momentum,

In an isolated system, when two objects collide, the combined momentum before and after the collision is constant. Due to the fact that the momentum gained by one object equals the momentum lost by another, this occurs.

So, the momentum of the trolley system before and after dropping the block to it are equal.

Mu = (M + m)v

Therefore, the velocity of the trolley system with the block in it,

v = Mu/(M + m)

v = 6 x 2/(6 + 3)

v = 12/9

v = 1.33 m/s

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Answer:

The atomic number of phosphorus is 15.

Explanation:

It’s found after Si(Silicon) and before S(sulphur)

You may need to walk a different distance to reach the point of maximum intensity for each frequency, far do you need to go to find point of maximum intensity.

The distance you need to walk to reach the point of maximum intensity (constructive interference) in front of you, you need to consider the principles of wave interference.

When two waves of the same frequency interfere with each other, the resulting wave can be either larger (constructive interference) or smaller (destructive interference) than the individual waves, depending on the phase difference between the waves. If the waves are in phase (i.e., if the crest of one wave coincides with the crest of the other wave), then the resulting wave will be larger than either of the individual waves (constructive interference). If the waves are out of phase (i.e., if the crest of one wave coincides with the trough of the other wave), then the resulting wave will be smaller than either of the individual waves (destructive interference). In the case of two speakers separated by a distance of 26 meters, the point of maximum intensity (constructive interference) will be located halfway between the speakers, or 13 meters from either speaker. If you start walking towards one of the speakers, you will need to walk a total of 13 meters to reach the point of maximum intensity in front of you.

It's important to note that the point of maximum intensity (constructive interference) will only be located 13 meters from each speaker if the speakers are emitting monotone sounds with a single frequency. If the speakers are emitting sounds with multiple frequencies, the point of maximum intensity (constructive interference) will vary for each frequency, and you may need to walk a different distance to reach the point of maximum intensity for each frequency.

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The accelerations for each problem are:

1. 2.22m/\(s^{2}\)

2. 7m/\(s^{2}\)

3. 1.45m/\(s^{2}\)

4. 20m/\(s^{2}\)

The acceleration which is gained by the object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/\(s^{2}\). Acceleration due to gravity is a vector, which means it has both magnitude and direction. The acceleration due to gravity at the surface of the Earth is represented by letter g. It has standard value defined as 9.80665 m/s2 (32.1740 ft/s2). However, actual acceleration of a body in free fall varies with location.

1. Initial velocity=0 km/h

Final velocity=24 km/h= 6.66m/s

Time=3 seconds

acceleration =\(\frac{6.66-0}{3}\)=2.22m/\(s^{2}\)

2. Initial velocity=0 km/h

Final velocity=35 m/s

Time=5 seconds

acceleration = \(\frac{35-0}{5}\)=7m/\(s^{2}\)

3. Initial velocity=20 km/h=5.55\(m/s^{2}\)

Final velocity=60 km/h= 20m/\(s^{2}\)

Time=10 seconds

acceleration= \(\frac{20-5.55}{10}\)= 1.45m/\(s^{2}\)

4. Initial velocity=50 m/s

Final velocity=150 m/s

Time=5 seconds

acceleration= \(\frac{150-50}{5}\)= 20m/\(s^{2}\)

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Kamil can expect to observe differences in the rate of salt dissolution between samples with different particle sizes, with smaller particles dissolving faster due to their larger surface area-to-volume ratio.

During his experiment, Kamil can expect to observe differences in the rate of salt dissolution between the three samples of salt with different particle sizes. In general, smaller particles tend to dissolve more quickly than larger particles due to their larger surface area-to-volume ratio.

Therefore, Kamil can expect the beaker containing the salt sample with small particles to dissolve the fastest, followed by the beaker containing the sample with medium particles, and finally, the beaker containing the sample with large particles. This is because the smaller particles have more surface area in contact with the water, which allows them to dissolve more quickly. On the other hand, larger particles have less surface area in contact with the water, which slows down their dissolution.

Additionally, Kamil should expect the temperature of the water to remain constant during the experiment, as the amount of salt added to each beaker is the same, and the beakers all contain the same volume of water. Furthermore, Kamil should not stir or agitate the beakers during the experiment, as this could introduce additional variables that might affect the rate of salt dissolution. By carefully controlling these variables, Kamil can accurately measure and compare the rate of salt dissolution for each sample, providing valuable insight into the properties of different types of salt particles.

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A 1.3 kg raven flying horizontally at 5.0 m/s collides with a 4.5 kg square wooden gate hanging vertically from a frictionless pivot at its centre and bounces back at 1.5 m/s. The angular speed of the gate just after the collision is to be determined.

First, we can find the initial momentum of the raven:

p_initial = m_raven * v_initial = 1.3 kg * 5.0 m/s = 6.5 kg*m/s

When the raven bounces back, its momentum changes by:

Δp = p_final - p_initial = m_raven * (v_final - v_initial)

We know that the final velocity is 1.5 m/s in the opposite direction, so:

Δp = 1.3 kg * (-1.5 m/s - 5.0 m/s) = -9.75 kg*m/s

By the law of conservation of momentum, the gate must also experience a change in momentum of -Δp. Since the gate is initially at rest, its final momentum is:

p_final = -Δp = 9.75 kg*m/s

This means that the gate acquires an angular momentum of:

L = r * p_final = (1/2) * 1.5 m * 9.75 kg*m/s = 7.31 kg*m^2/s

Finally, we can find the angular speed of the gate by dividing its angular momentum by its moment of inertia. Since the gate is a square, its moment of inertia about the pivot point is:

I = (1/6) * m_gate * a^2 = (1/6) * 4.5 kg * (1.5 m)^2 = 3.38 kg*m^2

Therefore, the angular speed of the gate is:

ω = L / I = 7.31 kg*m^2/s / 3.38 kg*m^2 = 2.16 rad/s

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Explanation:

weight of the piano = mg

w = 99 x 10 =990 N

Answer:

Explanation:

In this problem we are expected to find the weight of the plastic tank and the weight of the equal volume of water

Given that

density of water = 1000 kg/m^3

volume of plastic tank is same as the volume of water= 0.18 m^3

we need to solve for the mass of the water

we know that density is = mass/volume

1000= mass/0.18

mass= 1000*0.18

mass= 180 kg

the total mass of the combined system is

4+180= 184 kg

the weight = mg (assuming g= 9.81 m/s^2)

weight = 184*9.81

weight= 1805.04 N

Answer:

Explanation:

The time taken can be found by using the formula

\( t = \frac{d}{v} \\ \)

d is the distance

v is the velocity

From the question we have

\(t = \frac{3.5}{4.8} \\ = 0.72916...\)

We have the final answer as

Hope this helps you

Answer: Transverse waves

Explanation:

Transverse waves cause the medium to move perpendicular to the direction of the wave. Longitudinal waves cause the medium to move parallel to the direction of the wave.

Answer:

I believe this problem is 60 divided by 3 = 20m/s

That’s the formula.

Explanation:

Answer:  Their temperature decreases dramatically, but their luminosity increases only slightly.

Explanation: Edmentum answer

The correct option is (b) 1.25

The CPI of the project is 1.25. Earned Value (EV) is divided by Actual Cost (AC) to determine CPI.

CPI is calculated as follows: EV / AC. In this case, 250 / 200 = 1.25.

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The position of the particle when t = 6 s if s = 5 m, t = 0 is calculated to be 9.58 m.

We know that the position is the anti-derivative of velocity. So, to find the expression of the position at time t, we integrate the velocity:

s(t) = ∫ v(t) dt

s(t) = ∫ (5/(4+t)) dt

s(t) = 5 ∫ (1/(4+t)) dt

s(t) = 5 ln(4 + t) + c

We use the beginning condition that s = 5 m when t = 0 to solve for the integration constant c.

s(0) = 5 ln (4+0) + c

5 = 5 ln (4) + c

c = 5 - 5 ln (4) = 1.93

So the displacement expression is,

s(t) = 5 ln (4+t) - 1.93

Thus, when t = 6s, the position is

s(6) = 5 ln (4+6) - 1.93 = 9.58 m

To solve this problem, the velocity function should be v = [5/(4+t)] m/s.

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Answer:

B

Explanation:

a force acting upon an object increases that objects acceleration

Answer:

B

Explanation:

In a minor collision at an intersection with no injuries and minimal vehicle damage, you should first ensure the safety of all involved by moving your vehicles to a safe location, if possible.

Even if there are no injuries and the vehicle damage is minor, it is important to follow certain steps after a collision. The first step is to move your vehicle to a safe place off the road, if possible. Then, exchange information with the other driver, including names, phone numbers, insurance information, and vehicle registration numbers. You should also take pictures of the damage to both vehicles and the surrounding area.

If there were any witnesses, it is a good idea to get their contact information as well. Finally, report the accident to your insurance company as soon as possible. Remember, even minor collisions can have long-term effects, so it is important to take all necessary precautions and document everything.

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It could be observed that the number of electrons escaping the film is increased.

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