validity of newton's generalization of kepler's third law
Answers
The validity of Newton's generalization of Kepler's Third Law is well-established through empirical evidence, theoretical consistency, and its predictive power in describing the motion of celestial bodies under the influence of gravity.
Newton's generalization of Kepler's Third Law extended the scope of Kepler's original law, which was applicable to the motion of planets around the Sun, to cover any two bodies orbiting around their common center of mass.
By applying these laws, Newton showed that the motion of celestial bodies can be accurately described using his generalized form of Kepler's Third Law.
Some factors that support the validity of this generalization include:
1. Empirical evidence: Observations of various celestial bodies, such as planets, moons, and binary star systems, have consistently supported the predictions made by Newton's generalization of Kepler's Third Law.
2. Theoretical consistency: The generalization is consistent with Newton's laws of motion and his Law of Universal Gravitation, which have been well-established and proven to accurately describe the motion of objects under the influence of gravity.
3. Predictive power: Newton's generalization has been successfully used to predict the existence and properties of celestial bodies, such as the discovery of Neptune based on deviations in the orbit of Uranus.
In conclusion, through empirical proof, theoretical consistency, and its ability to accurately anticipate how celestial bodies would move when subjected to gravity, Newton's generalisation of Kepler's Third Law is proven to be correct.
For similar question on Kepler's Third Law
https://brainly.com/question/16705471
#SPJ11
Related Questions
a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.
Answers
It is 1.93 metres away from the post.
for vertical motion
\(S= u t + \frac{1}{2} g t^{2}\)
S = 0 + \(\frac{1}{2} g t^{2}\)
1.7 = \(\frac{1}{2} 9.8 t^{2}\)
t = 0.589 sec
using law of conservation of momentum, on the horizontal motion
\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)
\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)
\(v_{tin}\) = 3.273 m/s
S = \(v_{tin} \ t\)
= 3.273 m/s * 0.589 s
= 1.93 m
To know more about momentum
brainly.com/question/29113044
#SPJ4
a device is defined as a unit of an electrical system, other than a conductor, that carries or ? electric energy as its principal function.
Answers
A device is defined as a unit of an electrical system, other than a conductor, that carries or transfers electric energy as its principal function.
In electrical engineering, a device refers to a component or unit within an electrical system that performs a specific function.
Devices can be classified based on their function, behavior, or physical characteristics. This definition can be applied to a variety of devices commonly used in electrical systems such as transformers, generators, motors, switches, and more. These devices are designed to convert and transfer electrical energy in various ways to power different systems and devices.
For more such questions on conductor, click on:
https://brainly.com/question/492289
#SPJ11
An object's speed is 0.8 m/s, and its momentum is 200 kg-m/s What is the mass of the object?
A. 250kg
B. 200kg
C.160kg
D.128kg
Answers
Answer:
A: The mass would be 250kg
Explanation:
In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity. The equation illustrates that momentum is directly proportional to an object's mass and directly proportional to the object's velocity.
p= mv
m= p/ v
The explanation to that is:
momentum = mass× velocity
mass= momentum / velocity
THE ANSWER IS A
Hope this helps!
Would Lincoln, Nebraska or San Diego, California have a smaller range in average monthly temperatures
Answers
Answer: San diego
Because it is closer to the ocean
A pan containing 0. 750 kg of water which is initially 13 °Cis heated by electric hob. 35 kj of thermal energy is put into the water and its temperature rises. You can assume that all the energy supplied by the hob goes into raising the temperature of the water. Thee specific heat capacity of water is 4200 J/kg °C
To the nearest °C, what is the final temperature of the water?
Answers
A pan containing 0. 750 kg of water which is initially 13 °Cis heated by electric hob. 35 kj of thermal energy is put into the water and its temperature rises. the final temperature of the water, to the nearest °C, is approximately 24°C.
To determine the final temperature of the water after receiving 35 kJ of thermal energy, we can use the equation for heat transfer:
Q = mcΔT
Where Q is the thermal energy transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
In this case, the mass of water, m, is given as 0.750 kg, the thermal energy, Q, is 35 kJ (which can be converted to 35,000 J), and the specific heat capacity of water, c, is 4200 J/kg°C.
Rearranging the equation, we have:
ΔT = Q / (mc
Substituting the given values:
ΔT = 35,000 J / (0.750 kg * 4200 J/kg°C)
ΔT ≈ 11.11 °C
Since the water was initially at 13°C, we can calculate the final temperature by adding the change in temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 13°C + 11.11°C
Final temperature ≈ 24.11°C
Therefore, the final temperature of the water, to the nearest °C, is approximately 24°C.
The calculation is based on the principle of heat transfer. The thermal energy transferred to the water is directly proportional to the change in temperature and the mass of the substance. By using the specific heat capacity of water, we can relate the amount of thermal energy to the change in temperature. In this case, 35 kJ of energy is added to the water, resulting in a change in temperature of approximately 11.11°C. Adding this change to the initial temperature of 13°C gives us the final temperature of approximately 24.11°C.
Learn more about heat transfer here:
https://brainly.com/question/31778162
#SPJ11
55.A body of mass m falls through a liquid. If Vis the viscous force and the upthrust, then at the termi- nal velocity A. V = mg/U C. V+ mg = U 200 B. V-U = mg D. V + U = mg
Answers
The terminal velocity is B. V-U = mg D.
Terminal velocity explained.Terminal velocity is the constant speed that a freely falling object eventually reaches when the resistance of the medium through which it is falling prevents further acceleration. This occurs when the gravitational force pulling the object downward is balanced by the opposing force of air resistance or other fluid resistance acting in the opposite direction. At terminal velocity, the net force acting on the object becomes zero, and the object continues to fall at a constant speed without any further acceleration.
The terminal velocity of an object depends on its mass, shape, and surface area as well as the density and viscosity of the fluid it is falling through
When a body of mass m falls through a liquid, it experiences a viscous force (V) and an upthrust force (U) in addition to its weight (mg). At terminal velocity, the net force on the body becomes zero, so:
V + U + mg = 0
Rearranging this equation, we can solve for the terminal velocity (V):
V = -U - mg
Therefore, the correct answer is option B: V-U = mg.
Learn more about terminal velocity below.
https://brainly.com/question/12903433
#SPJ1
What is the effect of_on_?
Answers
skin cancer and it cause to lost transportating process
the possible ways used to remove a truck that is stuck in mud
Answers
Straight wheels while slowly depressing the gas pedal. Then, whether in drive or reverse, rock the automobile back and forth. If the wheels begin to spin, stop and turn around. If your transmission has a winter mode, use it.
What is meant by angular acceleration?The rate of change in angular velocity over time is represented by angular acceleration.
How swiftly something is accelerating or decelerating is another method to consider this. acceleration () is equal to t/. Rads/s² or degrees/s² are the units.
To maintain straight wheels while slowly depressing the gas pedal. Then, whether in drive or reverse, rock the automobile back and forth. If the wheels begin to spin, stop and turn around. If your transmission has a winter mode, use it.
Use the weight of the car to gain some traction while applying gentle pressure to the accelerator and moving as slowly as you can.
To learn more about angular acceleration, refer to:
https://brainly.com/question/21278452
#SPJ9
Which substance has a melting point greater than room temperature?
A.
oxygen
B.
aluminum
C.
mercury
D.
water
Answers
Answer:
I think the answer is D.)
Explanation:
If it means something needs to melt into liquid i would have gone with B.) or C.) but since it doesn't specifiy. I thought D.) since all you have to do is heat it and it melts or boils.
a car accelerates from rest to 30m/s while traveling a distance of 20m what was its acceleration
Answers
Answer:
22.5 m/s²
Explanation:
The final velocity, initial velocity, distance traveled and acceleration are related by the equation
v² = u² - 2ad [1]
where
v = final velocity
u = initial velocity
a = acceleration
d = displacement
We can manipulate the above equation [1] to solve for a in terms of the other parameters
a = (v² - u²)/2d
Given v = 30 m/s, u = 0 m/s, d = 20 m.
a = (30² - 0²)/(2 x 20)
a = 900/40
a = 22.5 m/s²
What best describes electrons
Answers
Answer: A negatively charged particle that is found in atoms.
Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Answers
Hi there!
Recall the equation for momentum:
\(\large\boxed{p = mv}\)
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
We can calculate each object's momentum and compare.
Cement truck:
\(p = 20000 \cdot 5 = 100000kg\frac{m}{s}\)
Race car:
\(p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}\)
Since 100,000 > 90,000, the cement truck has the greater momentum.
After a storm, a hospital may have to rely on backup generators to power some equipment. Which is the energy conversion provided by the generators?
A. mechanical to electrical energy
B. thermal to mechanical energy
C. nuclear to mechanical energy
D. thermal to electric energy
Answers
Answer:
in a generator mechanical energy is a device that converts a form of energy into electricty
The energy conversion provided by the generators is: mechanical to electrical energy. Hence, option (A) is correct.
What is working principle of electric generators?An electric generator is a device that generates electric energy, which can either be immediately delivered to houses, businesses, and other structures or stored in batteries. Electromagnetic induction is the basis for how electric generators operate.
A horseshoe-shaped magnet's poles are quickly rotated around a conductor coil, which is a copper coil that has been tightly wound onto a metal core. An armature is made up of a conductor coil and a core. The armature is rotated by a mechanical energy source, such as a motor, by means of a shaft connection.
The magnetic field that exists between the magnet's two poles is broken off when the coil turns. The conductor's electrons will interact with the magnetic field, causing an electric current to flow through it.
Learn more about electric generator here:
https://brainly.com/question/15277088
#SPJ2
8. A solution contains a mixture of two volatile substances A and B.
The mole fraction of substance A is 0. 35. At 32°C the vapor pressure
of pure A is 87 mmHg, and the vapor pressure of pure B is 122
mmHg. What is the total vapor pressure of the solution at this
temperature?
a) 110 mmHg
b) 209 mmHg
c) 99. 3 mmHg
d) 73. 2 mmHg
Answers
The total vapour pressure of a solution is 110mmHg which is calculated using Raoult's law. The mole fraction of substance A is given as 0.35, and the vapour pressures of pure A and B are given as 87 mmHg and 122 mmHg.
According to Raoult's law, the partial pressure of a component in a solution is proportional to its mole fraction. The mole fraction of substance A is 0.35, which means that it constitutes 35% of the solution. Therefore, the contribution of substance A to the total vapour pressure is 0.35 times its vapour pressure, which is 0.35 * 87 mmHg = 30.45 mmHg.
Similarly, the contribution of substance B can be calculated as 0.65 times its vapour pressure, which is 0.65 * 122 mmHg = 79.3 mmHg.
To find the total vapour pressure, we add the partial pressures of A and B: 30.45 mmHg + 79.3 mmHg = 109.75 mmHg.
Rounding this value to the nearest whole number, we get 110 mmHg. Therefore, the correct answer is option a) 110 mmHg.
Learn more about Raoult's law here:
https://brainly.com/question/28304759
#SPJ11
what was the launch speed of the object in terms of h, the mass and radius of the earth, m and r, respectively, and the gravitational constant, g?
Answers
The launch speed of the object in terms of h, the mass and radius of the earth, m and r, respectively, and the gravitational constant, g is v = √(2 * a * h).
To find the launch speed of an object in terms of h (height above the Earth's surface), the mass and radius of the Earth (m and r, respectively), and the gravitational constant (g), proceed as follows:
1. First, we need to find the gravitational force acting on the object at height h.
The formula for gravitational force (F) is:
F = G * (m₁ * m₂) / d²
where G is the gravitational constant, m₁ is the mass of the Earth, m₂ is the mass of the object, and d is the distance between the centers of the two masses (which is r + h).
2. Next, we need to find the acceleration of the object due to gravity at height h.
To do this, we'll use the formula:
F = m₂ * a
where F is the gravitational force and a is the acceleration due to gravity.
Solve for a:
a = F / m₂
3. Now, we can find the launch speed (v) of the object by using the following formula:
v² = 2 * a * h
Solve for v:
v = √(2 * a * h)
By combining information in 1-3, we can express the launch speed of the object in terms of h, m, r, and g.
Learn more about speed:
https://brainly.com/question/13943409
#SPJ11
other quanto
Dalex when
the face
into that one dan
a Explains why fish can
Survive under
Horan
Answers
I'm not sure what you were trying to put here
A cannonball is shot from level ground with a velocity of 240.0 m/s at an angle of 32 degrees. How long does the ball take to hit the ground?
Answers
The time of flight is obtained as 25.9 seconds
What is the time of flight?The time of flight is the time taken to move the object that have been projected along the parabolic path. In this case, we have a cannonball that have been fired from level ground with a velocity of 240.0 m/s at an angle of 32 degrees.
We know that from the question
T = 2usinθ/g
T = time of flight
u = initial velocity
θ = angle of projection
g = acceleration
T = 2 * 240.0 m/s * sin 32 degrees/9.8 m/s^2
T = 25.9 seconds
Learn more about time of flight:https://brainly.com/question/21537210
#SPJ1
find the quotient 3^15 × 3^3
Answers
Answer:
3^15 / 3^3 = 3^12 * 3^3 / 3^3 = 3^12
The Law of Exponents applies here
3^15 x 3^3 is a product, not a quotient
3^15 x 3^3 = 3^18
two masses one with a mass m and the other with a mass 2m are place a distance r apart from each other as indicated above. what is the center of mass of the system relative to the center of the right mass?
Answers
The center of mass of the system relative to the center of the right mass is located at a distance of r/3 to the right of the right mass.
What is the relative position of the center of mass?The center of mass is a point that represents the average position of the mass distribution in a system. In this case, we have two masses, one with mass m and the other with mass 2m, placed at a distance r apart. To determine the center of mass relative to the center of the right mass, we need to consider the masses and their positions.
To find the center of mass of the system relative to the center of the right mass, considerthe mass of the left object is m and the mass of the right object is 2m. And thus the total mass of the system is m + 2m = 3m.
Now, let's consider the positions of the masses. .Consider the right mass as the reference point (0,0) and the left mass as being at a distance r from it.
By using formula to calculate the center of mass relative to the center of the right mass:
Center of mass = (m₁ · r₁ + m₂ · r₂) / (m₁ + m₂)
In this case,m₁ is the mass of the left object (m) and r₁ is the distance from the right mass to the left mass (r). m₂is the mass of the right object (2m), and r₂ is the distance from the right mass to itself, which is 0.
By putting the values:
Center of mass = (m . r + 2m . 0) / (m + 2m)
Simplifying further:
Center of mass = (m . r) / (3m)
The m's cancel out:
Center of mass = r / 3
Hence, The center of mass of the system relative to the center of the right mass is located at a distance of r/3 to the right of the right mass.
Learn more about Center of mass
brainly.com/question/8662931
#SPJ11
A rocket initially traveling straight up at a speed of 20. 0 m/s undergoes constant acceleration in the direction of travel to a speed of 30. 0 m/s over a distance of 40. 0 m. What is the magnitude of the rocket's acceleration?
0. 125
2. 50
6. 50
12. 5
Answers
The magnitude of the rocket's acceleration is 12.5 m/s².To find the magnitude of the rocket's acceleration, we can use the equation of motion: \(v^2 = u^2 + 2as\)
The above equation has v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Rearranging the equation, we have \(a = (v^2 - u^2) / (2s)\).Given that the initial velocity (u) is 20.0 m/s, the final velocity (v) is 30.0 m/s, and the distance traveled (s) is 40.0 m, we can substitute these values into the equation:
a = (30.0² - 20.0²) / (2 * 40.0)
= (900 - 400) / 80
= 500 / 80
= 6.25 m/s².
Therefore, the magnitude of the rocket's acceleration is 6.25 m/s².
Learn more about equation of motion here:
https://brainly.com/question/29278163
#SPJ11
As the ball rolls down the ramp, there are changes in kinetic and potential energy. How much kinetic energy does the
ball have when it reaches point B?
A) 0J
B) 25J
C) 50J
D)100J
Answers
The answer is C, 50J
Please mark brainliest Have a nice day :)
A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg·m/s backward. What is the momentum of the rocket?
Answers
The momentum of the rocket is 1,500 kg m/s forward.
Momentum is the amount of motion of a moving body measured as the product of its mass and velocity.
According to the law of conservation of momentum, which states that the total momentum of the system must be constant.
It means that the change in momentum of the system must be equal to zero. Here the system is the rocket and the gases. So, applying the law of conservation of momentum to this system,Momentum of Gas + Momentum of Rocket = 0
Taking, forward direction as positive and the backward direction as negative
Momentum of Rocket - Momentum of the gas = 0
Momentum of Rocket - 1500 = 0
Momentum of Rocket = 1500 kg-m/s
Therefore the momentum of rocket is 1500 kg-m/s in forward direction.
To know more about momentum here
https://brainly.com/question/24030570
#SPJ1
A box of mass m is initially at rest at the top of a ramp that is at an angle with the horizontal. The block is at a height h and length L
from the bottom of the ramp. The block is released and slides down the ramp. The coefficient of kinetic friction between the block and
the ramp is u. What is the kinetic energy of the box at the bottom of the ramp?
Answers
Hi there!
We can use the work-energy theorem to solve.
Recall that:
\(E_i = E_f\)
The initial energy equals the final energy (Conservation of Energy). However, we must take into account energy dissipated due to friction in this instance.
The energy lost due to friction is equivalent to the work done by friction. Recall the following:
Normal force on an incline: \(N = Mgcos\theta\)Force due to friction: \(F_f = \mu N = \mu mgcos\theta\)The work due to a force is:
\(W = F \cdot d \\\)
Since the displacement is in the same direction as the force, the dot-product becomes Fd.
The work due to friction then becomes:
\(W_f = \mu mgdcos\theta\)
The work due to friction is SUBTRACTED from the initial potential energy.
Initial energy = GPE = mgh
Final energy = KE
Therefore:
\(\boxed{mgh - \mu mgdcos\theta = KE}\)
A vector is any quantity that has no units of measurement
Answers
False. Velocity is a vector and is measured in m/s (in SI, anyway).
When released from rest: Potential energy = 100 J and Kinetic Energy would equal?
Answers
Answer:
0J
Explanation:
The kinetic energy would be zero. An object just released from rest will have no kinetic energy but the potential energy will be maximum.
Kinetic energy is the energy due to the motion of a body
Potential energy is the energy due to the position of a body.
The kinetic energy at the start will therefore be zeroAll the energy is stored as potential energy.Therefore, the kinetic energy is zero
A badger is trying to cross the street . It’s velocity v as a function of time t is given in the graph below where right wards is the positive velocity direction
Answers
The badger's displacement from t=2s to t=3s is -5m.
Displacement is the change in position of an object. From t=0s to t=1s, the badger's velocity increases from 0 m/s to 5 m/s, so its displacement during this time interval is:
Δx = vΔt = 5 m/s x 1 s = 5 mFrom t=1s to t=3s, the badger's velocity decreases from 5 m/s to -5 m/s. Its displacement during this time interval is:
Δx = vΔt = [(5 m/s + (-5 m/s))/2] x 2 s = 0 mFrom t=3s to t=6s, the badger's velocity remains constant at -5 m/s. Its displacement during this time interval is:
Δx = vΔt = -5 m/s x 3 s = -15 mTherefore, the total displacement of the badger from t=0s to t=6s is
5 m + 0 m - 15 m = -10 m.To find the displacement from t=2s to t=3s, we need to subtract the displacement from t=0s to t=2s from the displacement from t=0s to t=3s:
Δx = (-10 m from t=0s to t=3s) - (-5 m from t=0s to t=2s) = -5 mSo the badger's displacement from t=2s to t=3s is -5 m.
To learn more about displacement, here
https://brainly.com/question/30087445
#SPJ1
The complete question is:
A badger is trying to cross the street. Its velocity v as a function of time t is given in the graph below where rightwards is the positive velocity direction. A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5). A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5). What is the badger's displacement \Delta xΔxdelta, x from t=2\,\text st=2st, equals, 2, start text, s, end text to 3\,\text s3s3, start text, s, end text?
Electricity and Magnetism: Tutorial
Drag each balloon to the correct location on the chart.
Sort the balloons based on the kinds of charges they carry.
Not Charged
Positively Charged
Negatively Charged
Answers
Not charged - balloon A
Positively charged - balloon C
Negatively charged - balloon B and D.
What is charge?Charge is the property of an object which attracts or repels unlike and like charges respectively.
For balloon A, positive charges are equal to the negative charges. So, it is neutral or having no charge.
For balloon B and D, negative charges are greater than the positive charges. So, balloons are negatively charged.
For balloon C, positive charges are greater than the negative charges. So, balloons are positively charged.
Learn more about charge.
https://brainly.com/question/27171238
#SPJ1
I don't understand how my teacher got the amount of voltage in each resistor. Or more specifically where he got the 12 from.
(The equation I'm confused about reads 24=6+Pv+12 but I know how to solve from there.)
Answers
The solution to the equation is Pv = 6.
What is the solution of the equation?The equation you provided is:
24 = 6 + Pv + 12
To solve for the variable Pv, we can follow these steps:
Step 1: Combine like terms
Combine the constant terms on the right-hand side of the equation:
24 = 6 + Pv + 12
24 = 18 + Pv
Step 2: Isolate the variable
To isolate the variable Pv, we need to subtract 18 from both sides of the equation to move the constant term to the other side:
24 - 18 = 18 - 18 + Pv
6 = Pv
Learn more about equations here: https://brainly.com/question/2972832
#SPJ1
A machine consists of two metal plates of equal but unknown mass and a wooden bar that is 1.50 meters long. one plate is glued to each end of the bar. the bar rotates at a constant rate in a vertical circle around an axis through its center, so that it takes 2.50 seconds to complete one full rotation. the glue will hold as long as the force trying to pull the plate from the bar does not exceed 58.0 n.
required:
what is the maximum mass of the plate that can remain glued to the bar, under these conditions?
Answers
The maximum mass of the plate that can remain glued to the bar is approximately 24.68 kilograms.
What is mass?Generally, To find the maximum mass of the plate that can remain glued to the bar, you need to calculate the maximum force that can be applied to the plate without breaking the glue.
To do this, you can use the formula for centripetal force, which is given by:
F = mv^2/r
Where
F is the centripetal force, m is the mass of the plate, v is the velocity of the plate, and r is the radius of the circle around which the plate is moving.In this case, the radius of the circle is equal to the length of the wooden bar, which is 1.50 meters.
The velocity of the plate can be calculated by dividing the distance traveled (the circumference of the circle, which is 2pir) by the time it takes to travel that distance, which is 2.50 seconds.
Plugging these values into the formula, we get:
F = m*(2π1.50/2.50)^2/1.50
= m*(6/5π)^2/1.50
= m1.44*π^2 /6
The maximum force that can be applied to the plate without breaking the glue is 58.0 N, so we can set the above equation equal to that value and solve for m:
58.0 = m*1.44*π^2 /6
m = 58.06/((1.44*π^2) /6)
To find the value of the expression
m = 58.06/((1.44*π^2) /6),
we need to compute the value of (1.44*π^2) /6. The value of π is approximately 3.14159, and π^2 is the square of this value, or approximately 9.86960.
Therefore, 1.44*π^2 is approximately 14.00053.
Dividing this value by 6 gives us approximately 2.33342. Substituting this value back into the original expression, we get:
m = 58.06/2.33342
m=24.68.
Thus, the maximum mass of the plate that can remain glued to the bar is approximately 24.68 kilograms.
Read more about mass
https://brainly.com/question/19694949
#SPJ1
Trina conducted an experiment to determine the average amount of salt in 1 liter of ocean water by allowing the water to evaporate and measuring the remaining salt.
Her results are shown below.
Trial Salt
1 9.9 g
2 14.2 g
3 8.7 g
4 13.4 g
What is the mean weight of the salt precipitate?
A.
46.2 g
B.
11.7 g
C.
11.3 g
D.
11.5 g
Answers
Answer:
The answer is . A 46.2g