ve scientific reasons.

It is not possible to get a perfect machine in our practice, why?​

The prove of  Angle XYZ- Angle NYM is given below:

Note that from the image given;

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

The Horizontal distance is 43.22 and tmax is Δttot = 2tmaxb) vf = vi + gΔttotc) vf = vi + 9.81(Δttot/2) × [h + (vi × Δttot/2) - 0.5g(Δttot/2)²] / h1) . Horizontal distance travelled can be found by multiplying the time taken to travel by the horizontal velocity. The time is obtained by considering the vertical motion and then applying it to the horizontal motion of the ball.

Here are the steps to calculate the distance horizontally; Initial speed: Vo = 22.2 m/s, Launch angle: θ = 20.6 degrees above horizontal, Initial vertical velocity: Vo * sinθInitial horizontal velocity: Vo * cosθg = - 9.81 m/s² (gravitational acceleration is negative as it is directed downwards)

Horizontal distance, x = Vx * t = (22.2 * cos20.6°) * (2 * 22.2 * sin20.6° / 9.81) = 43.22 m

Answer: x = 43.22 m

2)Given the variables, we have to express vf in terms of vi, which means final velocity in terms of the initial velocity.

Here are the steps to obtain vf in terms of vi;

a) We know that the total time of flight is given by:Δttot = 2tmax

b) The velocity of the ball right before it hits the ground is given by the equation:vf = vi + gΔttot, where g = 9.81 m/s²

c) Here is how we can express vf in terms of vi; Δttot = 2tmax, Therefore, tmax = Δttot/2∴ vf = vi + g(Δttot/2) × [h + (vi × Δttot/2) - 0.5g(Δttot/2)²] / h

Answer:a) Δttot = 2tmaxb) vf = vi + gΔttotc) vf = vi + 9.81(Δttot/2) × [h + (vi × Δttot/2) - 0.5g(Δttot/2)²] / h

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The mass of the object is 2,500 kg according to Newton's second law of motion.

Newton's second law of motion states that the force acting on an object is equal to the product of its mass and acceleration. Mathematically, F = ma, where F is the force, m is the mass of the object, and a is its acceleration.

If a force of 25,000 N is applied to an object, and the object is accelerating at a rate of \(10 m/s^2,\)  then the mass of the object can be calculated using Newton's second law of motion:

F = ma

where F is the force, m is the mass of the object, and a is its acceleration.

Rearranging this equation, we get:

m = F/a

Plugging in the values given in the problem, we get:

\(m = 25,000 N / 10 m/s^2 = 2,500 kg\)

Therefore, the mass of the object is 2,500 kg

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Answer:

The speed with which a rock would have to be thrown to put it in 234 Ida's orbit, near its surface is approximately 12.917 m/s

Explanation:

The given parameters are;

The mass of Ida, M = 4 × 10¹⁶ kg

The radius of 234 Ida, r = 16 km = 16,000 m

The speed, v, required to put a rock in 234 Ida's orbit near its surface is given by the orbital velocity equation as follows;

\(v = \sqrt{{\dfrac{G \times M}{r} } }\)

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Substituting the known values gives;

\(v = \sqrt{{\dfrac{6.67408 \times 10^{-11} \times 4 \times 10^{16}}{16,000} } } \approx 12.917\)

Therefore, the speed required to put a rock in 234 Ida's orbit near its surface = v ≈ 12.917 m.

The movement of a positive charge particle all along electric field, either from greater potential to lower potential. That is a drop in the charge's electric potential energy.

Potential energy being a form of battery bank that depends on how various system elements interact with one another. A spring's potential energy rises when it is crushed or stretched. Potential energy is something that is not transformed to kinetic energy.

Everything with mass naturally possesses potential energy, which is a product of matter. But an elastomeric or gravitation force is needed to add energy potential into the substance. Without forces, gravitational potential wouldn't exist.

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The magnitude of the change in linear momentum of the ball is 2 kg•m/s to the left.

When the ball strikes the wall, it experiences a sudden change in momentum due to the impulse provided by the wall. Since the wall is vertical, it does not move and therefore does not exert any horizontal force on the ball.

This means that the horizontal component of the ball's momentum is conserved, and the only change in momentum is in the vertical direction.

Using the principle of conservation of momentum, the initial momentum of the ball in the horizontal direction is:

p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s

The final momentum in the horizontal direction is the same as the initial momentum, since there are no external forces acting in that direction.

In the vertical direction, the initial momentum is:

p₁ = m₁v₁ = (0.5 kg)(6 m/s) = 3 kg•m/s

After rebounding, the ball is moving in the opposite direction, so its velocity is -4 m/s. Therefore, the final momentum in the vertical direction is:

p₂ = m₁v₂ = (0.5 kg)(-4 m/s) = -2 kg•m/s

The change in momentum is the difference between the final and initial momentum in the vertical direction:

Δp = p₂ - p₁ = (-2 kg•m/s) - (3 kg•m/s) = -5 kg•m/s

Since the question asks for the magnitude of the change in momentum, we take the absolute value, which gives:

|Δp| = |-5 kg•m/s| = 5 kg•m/s

However, the question asks for the direction of the change in momentum as well. Since the final momentum is in the opposite direction of the initial momentum, the change in momentum is to the left.

Therefore, change in linear momentum is 2 kg•m/s to the left.

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Answer:

Explanation: F = m * a F = 20 kg * 3 m/s 2 F = 60 N Newtons are a derived unit, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second

The problem involves a bat striking a baseball with given initial and final velocities. The goal is to find the x- and y-components of the average force on the ball.

To find the x- and y-components of the average force on the ball, we need to analyze the change in momentum of the ball. The change in momentum is given by the mass of the ball multiplied by the change in velocity.

The initial momentum of the ball in the x-direction is given by the product of its mass and initial velocity (0.145 kg * 30.0 m/s). The final momentum in the x-direction is the product of the mass and the final velocity's x-component (0.145 kg * 52.0 m/s * cos(30°)). Subtracting the initial momentum from the final momentum gives us a change in momentum in the x-direction.

Similarly, for the y-direction, the final momentum is the product of the mass and the final velocity's y-component (0.145 kg * 52.0 m/s * sin(30°)). The change in momentum in the y-direction is the difference between the final and initial momenta.

Finally, to find the average force, we divide the change in momentum by the time of contact (1.75 ms). The x-component of the average force is the change in momentum in the x-direction divided by the time, and the y-component of the average force is the change in momentum in the y-direction divided by the time.

To summarize, the x-component of the average force on the ball is calculated by subtracting the initial and final momenta in the x-direction and dividing it by the time of contact. The y-component of the average force is found by subtracting the initial and final momenta in the y-direction and dividing by the time. Learn more about the concepts of momentum and force by referring to SPJ11.

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Answer:

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

Explanation:

La masa de agua contenida dentro de la botella es igual a la diferencia entre la masa pesada totalmente llena y la masa pesada totalmente vacía, es decir:

\(m_{w} = 86.55\,g-24.25\,g\)

\(m_{w} = 62.3\,g\)

Ahora, de acuerdo con la definición de densidad, la masa es directamente proporcional a la densidad, entonces, podemos calcular la densidad del solvente mediante la siguiente relación:

\(\frac{m_{x}}{m_{w}} = \frac{\rho_{x}}{\rho_{w}}\) (1)

Donde:

\(m_{x}\) - Masa del tetracloruro de carbono, en gramos.

\(m_{w}\) - Masa del agua, en gramos.

\(\rho_{x}\) - Densidad del tetracloruro de carbono, en gramos por centímetro cúbico.

\(\rho_{w}\) - Densidad del agua, en gramos por centímetro cúbico.

Si sabemos que \(m_{x} = 123.95\,g\), \(m_{w} = 62.3\,g\) y \(\rho_{w} = 1\,\frac{g}{cm^{3}}\), entonces la densidad del tetracloruro de carbono es:

\(\rho_{x} = \left(\frac{m_{x}}{m_{w}} \right)\cdot \rho_{w}\)

\(\rho_{x} = 1.990\,\frac{g}{cm^{3}}\)

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

The correct answer is 29883.3m/s

The pace at w.hich an object's position changes in relation to a frame of reference is known as its velocity, which is a time-dependent quantity. The speed and direction of an object's motion are its velocity. The rate at which an object's velocity changes in relation to time is defined as its acceleration.

The following kinematic equation can be used to connect velocity and acceleration:

v_1=v_0+at

Where v_1 denotes the ultimate velocity, v_0 denotes the starting velocity, a denotes the acceleration, and t is the passing of time.

Calculate the length of the Earth's orbit around the Sun to get started. For this issue, a circle rather than an ellipse can be used to represent the Earth's orbit.

Circumference = C=πD=2πR

=2π(1.5×10km)

=9.424π×10^8

Do a dimensional analysis to convert the speed of the Earth around the Sun from miles per hour to metres per second:

s_earth= 9.424π×10^8/1year × (1year×100m×1day×1hour×1min)/(1km×365days×24hours×3600seconds)

=29883.3m/s

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The correct option is C, When a conductor mounted on an insulating stand is charged and left for some time, the conductor eventually loses all its charges. This is because the charges on the conductor are neutralized by opposite charges from the surrounding air.

A conductor is a material that allows the flow of electric charge. Specifically, a conductor is a material in which some or all of the electrons in its atoms are free to move, allowing for the transfer of electric charge through the material. Metals, such as copper and aluminum, are good conductors because they have many free electrons that can move easily through the material when a voltage is applied. Other materials, such as carbon and some semiconductors, can also conduct electricity under certain conditions.

The ability of a material to conduct electricity is measured by its electrical conductivity, which is a property that describes how easily an electric charge can flow through the material. Conductors are essential components in many electrical devices and systems, including wires, circuits, and electronic components. The properties of conductors are important in understanding the behavior of electricity and the design of electrical systems.

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Complete Question:

When a conductor mounted on an insulating stand is charged and left for some time, the conductor eventually loses all its charges. This is because the

A. electric charges evaporate from the surface of the conductor

B. charges are connected to the earth

C. charges on the conductor are neutralized by opposite charges from the surrounding air

D. charges ionize the surrounding air

If the observed variation in flux is due to a variation in the intrinsic luminosity of the quasar, what was the variation timescale at the time the light was emitted will be found and Rmax is equals to 1.3*10^15 cm.

In particle physics experiments the energy available for the production of new effects is the most important parameter. The required large centre of mass energy can only be provided with colliding beams where little or no energy is lost in the motion of the centre of mass system (cms).

Besides the energy the number of useful interactions (events), is important. This is especially true when rare events with a small production cross section σp are studied.

The quantity that measures the ability of a particle accelerator to produce the required number of interactions is called the luminosity and is the proportionality factor between the number of events per second dR/dt and the cross section σp.

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Answer:

B

Explanation:

Answer:

b the motion of molecules

Explanation:

i just took the test and it makes the most sense

If a standardized measuring system were not established, several problems could arise such as Lack of uniformity, Inefficiency and errors, Safety concerns and Economic impact.

Lack of uniformity: Without a standardized system, different regions or communities might develop their own measurement units, leading to confusion and inconsistency in communication and trade. It would be challenging to compare and reconcile measurements across different contexts.

Inefficiency and errors: A lack of standardized measurements could result in inefficiency in various sectors, such as construction, engineering, and manufacturing. Precision and accuracy would be compromised, leading to errors in calculations, designs, and product quality.

Safety concerns: Standardized measurements play a crucial role in ensuring safety, particularly in areas like medicine, transportation, and infrastructure. Without a common system, it would be difficult to establish safety standards, monitor compliance, and ensure uniformity in critical aspects like dosage, weight limits, and structural integrity.

Economic impact: Inconsistent measurement systems would hinder international trade and commerce. Harmonized measurements facilitate smooth transactions, accurate pricing, and quality control, leading to a stable and efficient economy. Without a standardized system, business operations and global collaborations would be significantly hindered.

In conclusion, a lack of a standardized measuring system would result in confusion, inefficiency, safety concerns, and economic setbacks, emphasizing the importance of establishing and adhering to universally accepted measurements.

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Answer:

Hola, veo que quieres la respuesta, así que todo lo que tienes que hacer es traducir esto, EHHHHH me encontraste y la respuesta es un

Explanation:

ps this is a real answer

Answer:

3.5+35

1.5+1.2

20+22

42 + 16

= 58 ¹²

Answer:

values of gravitational force and gravitational constant become same or equal when product of masses involved equals the square of distance between them

Explanation:

Given:

The initial height of the ball, h=1.6 m

The initial speed of the ball, u=14 m/s

To find:

a) The time of flight of the ball.

b) The range of the ball.

Explanation:

As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.

Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.

The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.

a)

From the equation of motion,

Where g is the acceleration due to gravity and t is the time of flight of the ball.

On substituting the known values,

b)

The range of the ball is given by,

On substituting the known values,

Final answer:

a) The time of flight of the ball is 0.57 s

b) The range of the ball is 7.98 m

Contact angle between mercury and glass is 140.6 degrees.

The difference in heights of mercury inside the tube and outside the tube is 5 cm. Using the formula h = 2T cos θ / ρgr, where h is the height difference, T is the surface tension of mercury, θ is the contact angle, ρ is the density of mercury, g is the acceleration due to gravity, and r is the radius of the tube, we can solve for θ. Substituting the given values, we get θ = 140.6 degrees.

The contact angle is the angle between the tangent to the surface of the mercury where it meets the glass and the surface of the glass itself. This angle depends on the adhesive forces between the liquid and the solid, and the cohesive forces within the liquid. In this case, we have a mercury-glass interface. The formula used to solve for the contact angle is derived from the balance of forces acting on the mercury in the tube, which is caused by the competition between the surface tension of the mercury and the gravitational force acting on it. .

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The period T is 0.0100 seconds and the block takes 0.0050 seconds to travel from the point of maximum displacement to the opposite point of maximum displacement.

Part G: To find the period T, we need to first determine the fraction of a full wavelength that is covered when moving from point t = 0 to point K. Since the x-coordinate of point R is 0.12 m and the t-coordinate of point K is 0.0050 s, we can assume that point K is located at half a wavelength.
Step 1: Determine the fraction of a full wavelength (a)
Since point K is at half a wavelength, the fraction a is 1/2.
Step 2: Calculate the period T
We know that aT = 0.0050 s, and a = 1/2.
(1/2) * T = 0.0050 s
Now, divide by the fraction a (1/2) to find the period T.
T = 0.0050 s / (1/2)
T = 0.0100 s
Part H: To find the time t it takes for the block to travel from the point of maximum displacement to the opposite point of maximum displacement, we can use the period T calculated in Part G.
Since the block travels from one point of maximum displacement to the opposite point of maximum displacement in half a period:
Step 1: Calculate the time t
t = (1/2) * T
t = (1/2) * 0.0100 s
t = 0.0050 s

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The heat transfer rate by convection is given by the following equation: qcon v = h × A × (Tb - Ta)The heat transfer rate by radiation is given by the following equation: qra d = σ × A × [(Tb + 273)4 - (Ts + 273)4] × εEquating the above equations, we get,

The steady convective heat flux from the base plate to air is given by the following equation: qcon v = h × A × (Tb - T where, qcon v = steady convective heat flux from the base plate to air h = convective heat transfer coefficient A = area of the base plate.

Tb = temperature of the base plate Ta = temperature of the air. The heat transfer rate by convection is given by the following equation: qcon v = h × A × (Tb - T Use the definition of net radiative heat transfer and heat transfer rate equation for thermal radiation together with emissivity of steel ca0.5 to calculate the steady radiative heat flux from the base plate to the surrounding.

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Answer:

Time, t = 7.4 secs.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

\(Speed = \frac{distance}{time}\) ....equation 1

\(Time = \frac{distance}{speed}\) .....equation 2

Given the following data;

Speed = 0.5m/s

Distance = 3.7m

Substituting into equation 2;

\(Time = \frac{3.7}{0.5}\)

Time, t = 7.4 secs.

If your body resistance is 100,000 ohms, then the current which would flow would be: 120v/100,000Ω=0.0012 amperes, which equals 1.2mA.

The reason you only see fossils in sedimentary rock is that these set of rocks are formed in much lower pressure and temperature, compared to the other types of rocks like igneous rocks.

Hi there! So among the options, there are:

Organisms will lose their habitat

Groundwater in the area will be reduced

More wood will be available for building homes

Runoff will be reduced once the streets are paved

Think about it. This is asking how the water cycle will be affected.

It wouldn't have anything to do with organisms, this is about water. It wouldn't be involving wood, since we're talking about water.

A and C are no longer options.

The answer is B, Groundwater in the area will be reduced. It took me a bit on this one, too, since it's a bit tricky. I also got it right on my exam and I do FLVS, this is in Earth Space Science.

Have a lovely rest of your day!

When the speed of rear-drive car is increasing on horizontal road, then the direction of the frictional force on the tires is: backward on the front tires and forward on the rear tires.

The force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other is called friction. There are different types of friction. Dry friction is a force that opposes relative lateral motion of two solid surfaces in contact.

Friction is a force that resists the rolling of one solid object over another. The frictional force is said to be a contact force as frictional force occurs when two surfaces come in contact with each other.

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Answer:

nope the dog jumped over the river

Explanation:

To balance the forces. The tension and gravity are both in a downward motion when the thing is at the bottom. And . It is obvious that T at the bottom is heavier than T at the top by a factor of two.

When the particle is at the highest point of the circle, the tendency of the string to sag is greatest. The circular path's lowermost point experiences the most strain. The rope is most likely to break here.

Therefore, At the string's peak, there might be no tension. It is based on how quickly the rotating mass is moving. It will be slower at any given speed than at other locations in the “orbit.”

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