vital role of maritime english among seaferers

From what my research concluded, true

Za answa iz:

True

Twust meh

Answer: B the first person to propose the heliocentric model of the solar system was Nicolaus Copernicus

Explanation:

Answer:

byee byee bbbbbbbbbbbb

A) Select the Search icon and enter the term into the search field. A definition will show up in the Key Terms section of the search results.

Key Terms are words or phrases used to describe a concept or idea. They are often used in the field of academia to help define the scope of a particular study or research project. Key Terms are also used in business and legal documents to provide a concise and precise description of a concept or idea. By providing clear definitions for each key term, it helps to ensure that all parties involved in a discussion or agreement are on the same page.

C) Select the Table of Contents or the Navigation icon and navigate to the Glossary.
D) Select the key term in your eText and a pop-up definition will appear.

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A public class in object-oriented programming is any part of the program that uses the member name to access or update its members.

All other classes are able to see public members. This indicates that a public field or method can be accessed by any other class. In addition, public fields can be modified by other classes unless the field is declared final. members are public; anyone outside the class can reach them. private: members cannot be viewed or accessed outside of the class. protected: members cannot be accessed outside the class, but they can be accessed within inherited classes.

System.out.println("Welcome to Java"); public class Exercise01_01, public static void main(String[] args), and

"Welcome to Computer Science" in System.out.println;

"Programming is fun" is printed in System.out.println;

}

}

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Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

\(\huge{\orange}\fcolorbox{purple}{cyan}{\bf{\underline{\green{\color{pink}Answer}}}} \)

It is true what technician b said about some ei systems allowing the clearance between the pickup coil and reluctor to be adjusted by moving the crankshaft sensor.

A device that manages a bank of switches is a relay controller. Logic-controlled magnetic coils are turned on and off using relay controllers.

The magnetic field quickly collapses and a high voltage is induced in the primary winding when the primary current flow is stopped (CEMF Counter electromotive Force).

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Answer:

The answer is below

Explanation:

The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.

The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.

Answer:

V = 20.6 m/s

Explanation:

Given that the temperature of the neon molecules = 356 Kelvin

Pressure = 0.9 bar

The mass number of Neon = 21.

Using the formula below

1/2 m v^2 = (3kT)/2

Where

T = temperature = 356 k

K = Bolzmann constant

= 1.38 × 10^-23jk^-1

NA = 6.02214076×10²³ mol⁻¹

Where NA = Avogadro number

Substitute all the parameters Into the formula

1/2 × 21/NA × v^2 = (3 × k × 356)/2

1.744×10^-23V^2 = 7.3692 × 10^-21

Make V^2 the subject of formula

V^2 = (7.37×10^-21)/1.744×10^-23

V^2 = 422.55

V = sqrt( 422.55)

V = 20.55

Therefore, the average (root mean square) velocity (m/s) of Neon molecules at 356 Kelvins and 0.9 bars is 20.55 m/s

Answer:

To calculate the coolant boiling point with a 15 psi pressure cap, we need to consider the base boiling point of water, the increase in boiling point due to the 50-50 mix of coolant, and the increase in boiling point per psi of pressure.

Base Boiling Point of Water: 100°C

Increase in Boiling Point due to Coolant Mix: 6°C

Increase in Boiling Point per psi: 17°C

Calculation for a 15 psi pressure cap:

Base Boiling Point + Increase due to Coolant + (Pressure Increase × Increase per psi)

= 100°C + 6°C + (15 psi × 17°C/psi)

= 100°C + 6°C + 255°C

= 361°C

Therefore, with a 15 psi pressure cap, the cooling system boiling point would be 361°C.

Now let's calculate the boiling point with a 12 psi pressure cap:

Base Boiling Point + Increase due to Coolant + (Pressure Increase × Increase per psi)

= 100°C + 6°C + (12 psi × 17°C/psi)

= 100°C + 6°C + 204°C

= 310°C

With a 12 psi pressure cap, the cooling system boiling point would be 310°C.

If pure water is used instead of a 50-50 mix of coolant, the boiling point would remain at 100°C since there would be no additional increase in boiling point due to the coolant mix.

As for the freezing point, the presence of the coolant mix or the pressure cap does not directly affect the freezing point of water. The freezing point of water is generally 0°C, regardless of the coolant mix or pressure conditions.

Explanation:

Device Guard and Credential Guard require "D. Virtual Secure Mode" in order to operate effectively. Virtual Secure Mode (VSM) is a hardware-based security feature implemented in Windows 10 and Windows Server 2016 that provides an additional layer of protection for sensitive system components.

VSM isolates critical security components, like Credential Guard and Device Guard, from the rest of the operating system by running them in a separate virtualized environment. This isolation prevents potential attackers from accessing or tampering with these critical security components, thus enhancing the overall security of the system.

The other options mentioned, such as Virtual Smart Cards, Credential Manager, and Home Groups, are not directly related to the functioning of Device Guard and Credential Guard.

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Answer:

Let's break down the given information to deduce the signal:

a) () is a real signal.

This tells us that the signal is not complex.

b) () is periodic with period = 4, and it has Fourier series coefficients.

This means that the signal can be represented by its Fourier series.

c) = 0 for || > 1.

This means that the signal is zero outside the interval [-1, 1].

d) The signal with Fourier coefficients = −/2− is odd.

This tells us that the signal is odd, meaning that () = −(), where () is the Fourier series coefficients.

Putting all the information together, we can write the Fourier series of the signal as:

() = /2 + ∑ (−1)^n+1 /n sin(nπ/2) e^(j nω_0 t)

where ω_0 = 2π/4 = π/2.

Now, we can deduce the signal within a sign factor:

() = -1 + sin(π/2)t - sin(3π/2)t + sin(5π/2)t - ...

Therefore, the signal () is a square wave with period 4 and amplitude 2, alternating between -2 and 0 at the odd half-integers.

there is no smoke its a electric train

Answer:

  Conductor

Explanation:

Current is carried by a conductor.

__

The purpose of a dielectric and/or insulator is to prevent current flow. An electrostatic field may set up the conditions for current flow, but it carries no current itself.

Answer:

for 13

Explanation:

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Answer:

i have no idea

Explanation:

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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BOD or Biological Oxygen Demand is a measure of the amount of dissolved oxygen consumed by microorganisms during the decomposition of organic matter in water. Organic matter in wastewater comes from a variety of sources, including human waste, food, and industrial effluents. The BOD test provides a way to estimate the amount of organic matter present in the wastewater, which in turn gives an indication of the overall level of pollutants.

Since BOD measures the amount of organic matter present in the wastewater, it can serve as an indicator of the strength of sewage. In other words, a high BOD value indicates a high concentration of organic matter and thus a strong wastewater stream.Furthermore, wastewater treatment plants use BOD as a measure of their efficiency. A treatment plant reduces the BOD level of the wastewater it receives by using a combination of physical, chemical, and biological processes. The goal of the treatment process is to reduce the BOD level to a point where the water can be safely discharged into the environment without harming aquatic life or human health.

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Answer:

\(\| \vec A \| = 6.163\,m\)

Explanation:

Sean A, B y C vectores coplanares tal que:

\(\vec A = (\| \vec A \|\cdot \cos \theta_{A},\| \vec A \|\cdot \sin \theta_{A})\), \(\vec B = (\| \vec B \|\cdot \cos \theta_{B},\| \vec B \|\cdot \sin \theta_{B})\) y \(\vec C = (\| \vec C \|\cdot \cos \theta_{C},\| \vec C \|\cdot \sin \theta_{C})\)

Donde \(\| \vec A \|\), \(\| \vec B \|\) y \(\| \vec C \|\) son las normas o magnitudes respectivas de los vectores A, B y C, mientras que \(\theta_{A}\), \(\theta_{B}\) y \(\theta_{C}\) son las direcciones respectivas de aquellos vectores, medidas en grados sexagesimales.

Por definición de producto escalar, se encuentra que:

\(\vec A \,\bullet\, \vec B = \|\vec A \| \| \vec B \| \cos \theta_{B}\cdot \cos \theta_{A} + \|\vec A \| \| \vec B \| \sin \theta_{B}\cdot \sin \theta_{A}\)

\(\vec B \,\bullet\, \vec C = \|\vec B \| \| \vec C \| \cos \theta_{B}\cdot \cos \theta_{C} + \|\vec B \| \| \vec C \| \sin \theta_{B}\cdot \sin \theta_{C}\)

Asimismo, se sabe que \(\| \vec B \| = 5\,m\), \(\theta_{B} = 60^{\circ}\), \(\vec A \,\bullet \,\vec B = 30\,m^{2}\), \(\vec B\, \bullet\, \vec C = 35\,m^{2}\), \(\|\vec A \| = \| \vec C \|\) y \(\theta_{C} = \theta_{A} + 25^{\circ}\). Entonces, las ecuaciones quedan simplificadas como siguen:

\(30\,m^{2} = 5\|\vec A \| \cdot (\cos 60^{\circ}\cdot \cos \theta_{A} + \sin 60^{\circ}\cdot \sin \theta_{A})\)

\(35\,m^{2} = 5\|\vec A \| \cdot [\cos 60^{\circ}\cdot \cos (\theta_{A}+25^{\circ}) + \sin 60^{\circ}\cdot \sin (\theta_{A}+25^{\circ})]\)

Es decir,

\(30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})\)

\(35\,m^{2} = \| \vec A \| \cdot [2.5\cdot \cos (\theta_{A}+25^{\circ})+4.330\cdot \sin (\theta_{A}+25^{\circ}})]\)

Luego, se aplica las siguientes identidades trigonométricas para sumas de ángulos:

\(\cos (\theta_{A}+25^{\circ}) = \cos \theta_{A}\cdot \cos 25^{\circ} - \sin \theta_{A}\cdot \sin 25^{\circ}\)

\(\sin (\theta_{A}+25^{\circ}) = \sin \theta_{A}\cdot \cos 25^{\circ} + \cos \theta_{A} \cdot \sin 25^{\circ}\)

Es decir,

\(\cos (\theta_{A}+25^{\circ}) = 0.906\cdot \cos \theta_{A} - 0.423 \cdot \sin \theta_{A}\)

\(\sin (\theta_{A}+25^{\circ}) = 0.906\cdot \sin \theta_{A} + 0.423 \cdot \cos \theta_{A}\)

Las nuevas expresiones son las siguientes:

\(30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})\)

\(35\,m^{2} = \| \vec A \| \cdot [2.5\cdot (0.906\cdot \cos \theta_{A} - 0.423 \cdot \sin \theta_{A})+4.330\cdot (0.906\cdot \sin \theta_{A} + 0.423 \cdot \cos \theta_{A})]\)

Ahora se simplifican las expresiones, se elimina la norma de \(\vec A\) y se desarrolla y simplifica la ecuación resultante:

\(30\,m^{2} = \| \vec A \| \cdot (2.5\cdot \cos \theta_{A} + 4.330\cdot \sin \theta_{A})\)

\(35\,m^{2} = \| \vec A \| \cdot (4.097\cdot \cos \theta_{A} +2.865\cdot \sin \theta_{A})\)

\(\frac{30\,m^{2}}{2.5\cdot \cos \theta_{A}+ 4.330\cdot \sin \theta_{A}} = \frac{35\,m^{2}}{4.097\cdot \cos \theta_{A} + 2.865\cdot \sin \theta_{A}}\)

\(30\cdot (4.097\cdot \cos \theta_{A} + 2.865\cdot \sin \theta_{A}) = 35\cdot (2.5\cdot \cos \theta_{A}+4.330\cdot \sin \theta_{A})\)

\(122.91\cdot \cos \theta_{A} + 85.95\cdot \sin \theta_{A} = 87.5\cdot \cos \theta_{A} + 151.55\cdot \sin \theta_{A}\)

\(35.41\cdot \cos \theta_{A} = 65.6\cdot \sin \theta_{A}\)

\(\tan \theta_{A} = \frac{35.41}{65.6}\)

\(\tan \theta_{A} = 0.540\)

Ahora se determina el ángulo de \(\vec A\):

\(\theta_{A} = \tan^{-1} \left(0.540\right)\)

La función tangente es positiva en el primer y tercer cuadrantes y tiene un periodicidad de 180 grados, entonces existen al menos dos soluciones del ángulo citado:

\(\theta_{A, 1} \approx 28.369^{\circ}\) y \(\theta_{A, 2} \approx 208.369^{\circ}\)

Ahora, la magnitud de \(\vec A\) es:

\(\| \vec A \| = \frac{35\,m^{2}}{4.097\cdot \cos 28.369^{\circ} + 2.865\cdot \sin 28.369^{\circ}}\)

\(\| \vec A \| = 6.163\,m\)

Answer: 2.2GPa

Explanation:

Based on the information given, the bulk modulus of the water will be calculated as:

dv/v = 0.3% = 0.003

dP = 6.6MPa

Bulk modulus will now be:

= 6.6/0.003

= 2200

= 2.2GPa

Answer:

I hope it helps :)

Explanation:

It is useful to measure Height and Arm Span in tennis players. Body fat can be measured using the skinfold method. If this is not available, monitoring body weight changes would give an indication of body fat changes, assuming no

Answer:

A video camera with onboard storage(whether is a tape or digital memory) will record sound

The lighting fixtures should be waterproof and properly sealed.

Lighting fixtures installed above an indoor pool need to meet specific criteria to ensure safety and durability. These fixtures should be designed specifically for wet or damp environments and be rated as waterproof.

Water can create a hazardous situation if it comes into contact with electrical components, so the fixtures must have appropriate seals to prevent water ingress. Additionally, it's crucial to choose fixtures that are corrosion-resistant to withstand the humid environment around the pool.

The requirements for lighting fixtures in wet environments to ensure safety and longevity. Waterproofing and proper sealing are crucial to protect against electrical hazards and ensure the fixtures can withstand the pool's surroundings.

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The length of the uniform steel bar is; 1.077 m

A physical pendulum is defined as an extended object that, for small angular displacements, it can be modeled to move in simple harmonic motion about a pivot that does not go through the center of mass. The period of this motion is given by the formula;

T = 2π√(I/mgd)

where;

I is the moment of inertia of the object about an axis through the pivot.

d is the distance from the pivot to the center of mass of the object.

The period of the pendulum is given as t = 1.7 seconds

The moment of inertia of the same bar rotating about an axis through one end is gotten from the formula;

I = ¹/₃ML²

Where L is the length of the bar

Since the bar is uniform, the middle of mass is found in the middle and as such; d = L/2

Thus;

T = 2π√(2I/mgL)

Put  ¹/₃ML² for I into the period formula and we have;

L = 3gT²/8π²

Thus;

L = 3(9.81 * 1.7²)/8π²

L = 1.077 m

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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Answer:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

Explanation:

Given

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,\)

\(0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,\)

\(0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,\)

\(0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.\)

Required

Plot a steam and leaf display for the given data

Start by categorizing the data by their tenth values:

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.\)

\(0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\)

\(0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.\)

\(0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.\)

\(0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.\)

\(0.78.\)

The 0.3's is will be plotted as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}\)

The 0.4's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}\)

The 0.5's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}\)

The 0.6's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}\)

Lastly, the 0.7's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

The combined steam and leaf plot is:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)