Water, made of 1 oxygen atom bonded with 2 hydrogen atoms, is what

In an aqueous solution, two different forms of a particular d-aldohexose (such as galactose) would be present in equilibrium.

This occurs due to a phenomenon called mutarotation, which involves the interconversion between the α- and β-anomers of the sugar molecule. The α- and β-anomers differ in the orientation of the hydroxyl group on the anomeric carbon, which is the first carbon in aldohexoses.

When dissolved in water, the sugar molecules undergo a spontaneous, reversible ring-opening process, allowing them to switch between the α- and β-forms. This results in an equilibrium mixture of both forms, which is responsible for the unique optical rotation properties of the sugar solution.

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Answer:

B) attract a bonding pair of electron's toward itself

Explanation:

I had this question and the correct answer'(s) were A and B

Answer:

The energy contained in its molecules movement and vibration

Explanation:

See above

Answer:

The mole fraction is the number of moles of something divided by the number of total moles present. First, let us work out the number of moles of KCl present. A 26.3% w/w solution would contain 26.3 g of KCl per 100 g of solution. Hence, 26.3 g of KCl is 26.374.5513 = 0.353 moles

Explanation:

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Sorry this question is incomplete.

The maximum height above the point of release that the block reaches is approximately 11.32 meters.

To determine the maximum height above the point of release that the block reaches, we need to analyze the conservation of mechanical energy.

Given:

Mass of the block (m) = 0.243 kg

Force constant of the spring (k) = 4,950 N/m

Compression of the spring (x) = 0.104 m

Potential Energy of the Spring:

The potential energy stored in the compressed spring can be calculated using the formula:

Potential energy (PE) = (1/2) × k × x²

Substituting the given values:

PE = (1/2) × 4,950 N/m × (0.104 m)²

PE = 27.027 J (Joules)

Maximum Potential Energy at the Highest Point:

At the highest point, the block momentarily comes to rest, converting all its potential energy into gravitational potential energy.

Gravitational potential energy (GPE) = m × g × h

At the highest point, the velocity of the block is zero, so its kinetic energy is zero.

Substituting the known values:

GPE = m × g × h

27.027 J = 0.243 kg × 9.8 m/s² × h

27.027 J = 2.3886 kg·m²/s² × h

Simplifying the equation:

h = 27.027 J ÷ (2.3886 kg·m²/s²)

h ≈ 11.32 m

Therefore, the maximum height above the point of release that the block reaches is approximately 11.32 meters.

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The cost performance index (CPI) for the project is 0.89, and the schedule performance index (SPI) is 1.09. These indices indicate that the project is behind schedule but slightly under budget.

The CPI is calculated by dividing the earned value (EV) by the actual cost (AC). In this case, EV is $19,450 and AC is $21,870, resulting in a CPI of 0.89. A CPI less than 1 indicates that the project is over budget. However, since the CPI is close to 1, it suggests that the project is slightly under budget.

The SPI is calculated by dividing the EV by the planned value (PV). With an EV of $19,450 and a PV of $17,800, the SPI is 1.09. An SPI greater than 1 indicates that the project is ahead of schedule. In this case, the SPI value indicates that the project is slightly behind schedule.

Overall, the project is performing slightly better in terms of cost management than in schedule management. The project is under budget but slightly behind schedule. Further analysis and corrective actions may be required to improve the project's schedule performance.

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Answer:

Frequency of wave is given 1.25 × 10²⁰ Hz

We have been asked to determine the wavelength of that wave ( in metres) .

We Know the speed of light in air/vacuum is

c = 3 × 10⁸ m/s

❍\(\\{\underline{\boxed{\green{\bf{f = \dfrac{c}{ \lambda} }}}}}\)

Put the value we obtain

\(\sf \implies \: 1.25 \times {10}^{20} = \dfrac{3 \times {10}^{8} }{ \lambda} \\ \\ \sf \implies \lambda \: = \dfrac{3 \times {10}^{8} }{1.25 \times {10}^{20} } \\ \\ \sf \implies \lambda = \dfrac{3}{1.25 \times {10}^{12} } \\ \\ \sf\implies \lambda = 2.4 \times {10}^{ - 12} m \)

So, the wavelength of the wave is 2.4 × 10⁻¹² m

It would be Gamma Ray .

Answer:

They are called homogenous mixtures. If you put sand into a glass of water, it is considered to be a mixture. You can always tell a mixture, because each of the substances can be separated from the group in different physical ways. You can always get the sand out of the water by filtering the water away.

Answer:

Sifter

Explanation: They are called homogenous mixtures. If you put sand into a glass of water, it is considered to be a mixture. You can always tell a mixture, because each of the substances can be separated from the group in different physical ways. You can always get the sand out of the water by filtering the water away.

The idea of the atomic nature of matter was first developed by John Dalton.

He introduced the atomic theory, which proposed that matter was made up of tiny, indivisible particles called atoms. This theory was based on his observations and experiments on the behavior of gases

.Dalton's atomic theory had several postulates that helped explain the properties of matter. These postulates were:

All matter is made up of atoms, which are tiny, indivisible particles

.Each element is composed of atoms that are identical in size, shape, and chemical properties.

Atoms of different elements have different sizes, shapes, and chemical properties.

Atoms combine in fixed ratios to form compounds, and the ratios of their masses are related by whole numbers.

Atoms are indestructible and cannot be created or destroyed in chemical reactions

.However, Dalton's atomic theory was later modified and expanded upon by other scientists, including J.J. Thomson, Ernest Rutherford, and Niels Bohr, as new discoveries about the structure and behavior of atoms were made.

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Answer:

A.) A cinder cone vocano

Explanation:

Cinder cone volcanos give off more ash, rather then an explosion, hense the name "cinder cone".

Answer:

Cinder Cone Volcano

Explanation:

Answer:

20 km

Explanation:

he walks 10 km + another 10 km so 20 :)

Answer:

6

Explanation:

there always has to be the same number of atoms on both sides of the equation

Answer:

THE NORMAL BOILING POINT OF A SOLUTION CONTAINING 64.5 g OF QUINOLINE IN 500 g OF BENZENE IS 82.6 C

Explanation:

Boiling point = old boiling point + molarity * boiling point constant (Kb)

First, you calculate the number of moles of quinoline in the solution

number of moles = mass / molar mass

Since the molar mass of quinoline has been given as 129 g/mol

number of moles = 64.5 g / 129 g/mol

number of moles = 0.5 moles.

Next is to determine the molarity:

molarity = number of moles of solute / kilogram of solvent

molarity = 0.5 moles / 500/1000 kg

molarity = 0.5 / 0.5

molarity = 1 M

The new boiling point can then be calculated using the formula:

B. P = old B.P + Kb * molarity

B.P = 80.10 + 2.50 * 1

B.P = 80.10 + 2.50

B.P = 82.6 degree celsius

Answer:

1) all matter is made up of atoms and molecules 2) these tiny particles are always in motion; the higher the temp. the faster they move 3) at the same temp., heavier particles move more slowly then small particles

Explanation:

Answer:

it's rn and the atomic number is 86 if u needed that

Explanation:

:)

pluses and negatives

D) because it has negative and positive signs

Answer:

D. This D one model best illustrates Thomson explanation of atom

Explanation:

Balanced nuclear equation by giving the mass number, atomic number, and element symbol for the missing species is ¹⁰B + ⁴He → ¹⁴N + 1¹H

The missing species in the given nuclear equation is ¹⁴N and 1¹H.

Let's write the mass number, atomic number, and element symbol for the missing species:

Mass number of ¹⁴N = 14

Atomic number of ¹⁴N = 7

Element symbol of ¹⁴N = N (since the atomic number of nitrogen is 7)

Mass number of 1¹H = 1Atomic number of 1¹H = 1

Element symbol of 1¹H = H (since the atomic number of hydrogen is 1)Therefore, the main answer of the balanced nuclear equation is: ¹⁰B + ⁴He → ¹⁴N + 1¹H.

In order to balance a nuclear equation, it is essential that the total mass number and the total atomic number is conserved.

Balancing nuclear equations requires both the knowledge of atomic structure as well as knowledge of the laws of conservation of mass and charge.

A balanced nuclear equation is essential in understanding nuclear reactions and in predicting the outcomes of nuclear reactions.The balanced nuclear equation for the given nuclear equation is:¹⁰B + ⁴He → ¹⁴N + 1¹H. Conclusion:Thus, the missing species in the given nuclear equation is ¹⁴N and 1¹H.

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It takes approximately 100.704 years (since 1964) until only 9 percent of the original amount of radioactive strontium-90 absorbed remains.

The half-life of radioactive strontium-90 is given as 29 years, which means that every 29 years, the amount of radioactive strontium-90 is reduced by half.

To find the number of years it takes until only 9 percent of the original amount remains, we can set up the following equation:

(0.5)^(t/h) = 0.09

Where:

t represents the number of years since 1964 (the initial time),

h represents the half-life of 29 years, and

0.09 represents 9 percent.

Let's solve for t:

(0.5)^(t/29) = 0.09

Taking the natural logarithm (ln) of both sides:

ln[(0.5)^(t/29)] = ln(0.09)

Using the logarithmic property: ln(a^b) = b × ln(a):

(t/29) × ln(0.5) = ln(0.09)

Dividing both sides by ln(0.5):

t/29 = ln(0.09) / ln(0.5)

t = 29 × (ln(0.09) / ln(0.5))

Using a calculator, we can find the value of t:

t = 29 × (-2.40794561 / -0.69314718)

t = 100.704

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Answer:

high

Explanation:

Given that the reaction A — → Products is second-order with respect to A. We need to determine the true statements among the given statements. When [A] doubles, the rate quadruples. This is true because the rate of a second-order reaction varies directly as the square of the concentration of the reactant. The correct options are options (A) and (B).

Therefore, when the concentration of A doubles, the rate of the reaction will be four times. The plot of [A]2 versus time gives a straight line with slope +k. This statement is true. The slope of the plot of [A]2 versus time gives a straight line with slope +k. This is because the rate constant is

k = slope/intercept.

A plot of [A] versus time gives a straight line with slope – k.

This statement is not true.

The plot of [A] versus time gives a straight line with slope –k.

This is because the rate constant is

k = -slope/intercept.

A plot of [A]– versus time gives a straight line with slope +k.

This statement is not true because the reaction is second-order with respect to A, not first-order with respect to A.

The plot of [A]– versus time gives a straight line with slope -k.

None of the statements above are true.

This statement is not true as the first and the second statement is correct, hence option (E) is incorrect.

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Answer:

22.4 Liters at STP

Explanation:

General Rule => Any (ALL) gas will occupy 22.4 Liters at Standard Conditions (STP).

Answer:

Explanation:

First, we need to find the limiting reactant between CuO and NH3. We can do this by calculating the moles of each reactant based on the given amount of CuO:

Moles of CuO = 14.4 mol CuO

Moles of NH3 = (2/3) x 14.4 mol CuO = 9.6 mol NH3

Since NH3 has a smaller mole value than CuO, it is the limiting reactant. Thus, we need to use the mole ratio between NH3 and N2 to find the moles of N2 produced:

Moles of N2 = (1/2) x 9.6 mol NH3 = 4.8 mol N2

Finally, we can use the molar mass of N2 to find the mass of N2 produced:

Mass of N2 = 4.8 mol N2 x 28 g/mol N2 = 134.4 g N2

Rounded to the nearest tenth, the answer is 134.4 g N2.

The balanced chemical equation tells us that 1 mole of carbon reacts with 2 moles of hydrogen to produce 1 mole of methane. Thus, we can use the mole ratio to find the moles of carbon needed:

Moles of C = 1/3 x 19.5 mol CH4 = 6.5 mol C

Finally, we can use the molar mass of carbon to find the mass of carbon needed:

Mass of C = 6.5 mol C x 12 g/mol C = 78 g C

Rounded to the nearest tenth, the answer is 78.0 g C.

We can use the molar mass of methane to convert the given mass to moles:

Moles of CH4 = 119.4 g CH4 / 16 g/mol CH4 = 7.5 mol CH4

Since the balanced chemical equation tells us that 1 mole of carbon reacts with 1 mole of methane, we need the same amount of moles of carbon:

Moles of C = 7.5 mol CH4

Rounded to the nearest tenth, the answer is 7.5 mol C.

Similar to the first question, we need to find the limiting reactant between CuO and NH3. We can do this by calculating the moles of each reactant based on the given mass of CuO:

Moles of CuO = 127.4 g CuO / 63.5 g/mol CuO = 2.0 mol CuO

Moles of NH3 = (2/3) x 2.0 mol CuO = 1.3 mol NH3

Since NH3 has a smaller mole value than CuO, it is the limiting reactant. Thus, we need to use the mole ratio between NH3 and N2 to find the moles of N2 produced:

Moles of N2 = (1/2) x 1.3 mol NH3 = 0.65 mol N2

Rounded to the nearest tenth, the answer is 0.7 mol N2.

Answer:

nucleus

Explanation:

It would take approximately 672 seconds or 11 minutes and 12 seconds to walk to school at an average speed of 2 m/sec.

The average speed is the total distance traveled divided by the total time taken to cover that distance. It is a measure of how fast an object or a person moves on average.

The unit of average speed is usually expressed in kilometers per hour (km/h) or miles per hour (mph) in the English system. For example, if a car travels a distance of 100 kilometers in 2 hours, its average speed is 50 km/h.

To calculate the time it would take to walk to school, we can use the formula:

time = distance / speed

where distance is the distance between home and school, and speed is the average walking speed.

Plugging in the given values, we get:

time = 1344 meters / 2 m/sec

time = 672 seconds

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Answer:

32°F

Explanation:

because lower then that it won't but 32°F and over will melt a solid

The possible reaction mechanism for the acid-catalyzed hydrolysis of glycosidic bonds in an oligosaccharide.

The acid-catalyzed hydrolysis of glycosidic bonds involves the cleavage of the bond between two monosaccharide units in an oligosaccharide, resulting in the formation of individual monosaccharides.

Here is a possible reaction mechanism for acid-catalyzed hydrolysis:

1. Protonation of the glycosidic bond:

In the presence of an acid catalyst, such as HCl, the acid donates a proton (H+) to the oxygen atom of the glycosidic bond, leading to the formation of a oxonium ion intermediate.

2. Nucleophilic attack:

A water molecule acts as a nucleophile, attacking the electrophilic carbon atom of the oxonium ion. This leads to the cleavage of the glycosidic bond, breaking the bond between the two monosaccharide units.

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hope you can read it. hope it's right too :).

All the best.

Answer:

B

IS THE CORRECT ANSWER