Wday is the area in square inches of the floor in the scale drawing

Answer:

\(\huge\boxed{\boxed{49}}\)

Step-by-step explanation:

Hello.

In order to simplify this expression, we need to add

2+5, which is equal to 7

Multiply that times 7:

49

And we're done!

I hope it helps & have an outstanding day!

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Answer:

The rate of change is 28.

Step-by-step explanation:

The equation is in slope-intercept form,  y = mx + b, where m is the slope, and b is the y-intercept.

Answer:

B

Step-by-step explanation:

48-19=29x2=58 so yeah thats how you do dat

Answer:

Step-by-step explanation:

2x - 5y = -11

ordered pair:  (-5, -1)

x = -5 y = -1

plug into the equation.

2(-5) - 5(-1) = -11

a negative x a positive = a negative

2 x -5 = -10

a negative x a negative = a positive

-5 x -1 = 5

-10 + 5 = -11

5 ≠ 11

therefore its NOT solution.

Answer:

Slope = 1, y-intercept = (0,7)

Step-by-step explanation:

Answer:

D is the best one to buy

Step-by-step explanation:

A: 1.25/10=0.125

B: 1.47/12=0.1225

C: 1.68/14=0.12

D:1.84/16=0.115

Using proportions, it is found that the better buy is given by:

d. Brand D

A proportion is a fraction of a total amount.

In this problem, the better buy will be given by the lowest ratio of price to ounces.

Hence:

1.25/10 = 0.125

1.47/12 = 0.1225

1.68/14 = 0.12

1.84/16 = 0.115

Hence brand D is the better buy.

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Answer:

\(\sf\longmapsto \: x = 6\)

Step-by-step explanation:

\(\sf\longmapsto \: 2x = 14 - 2\)

\(\sf\longmapsto \: 2x = 12\)

\(\sf\longmapsto \: x = \frac{12}{2} \)

\(\sf\longmapsto \: x = 6\)

Answer:

x = 6

Step-by-step explanation:

Hey there,

\(2x =14-2\\2x=12\\\frac{2x}{2}=\frac{12}{2} \\x = 6\)

Hope this helps you.

Let me know if you have any other questions :-)

Answer:

The answer is most likely A.

The reason why, is because since the earning in 6 hours is $94.50, so the hourly wage would be, $15.75 because:

94.50/6 = 15.75

Graph B, for the first hour, the amount of dollars is correct, but in 11 hours, it says 25.75, which is not correct so Graph B cannot be it.

Graph C, shows that at hour 1, that it is 15.75 dollars, but at hour 2 16.75, as well with hour 3, 17.75. The graph is showing an increase of 1 dollar per hour, which is not correct so graph C is not it.

Graph D shows that at hour 6, there is $94.50, which is correct, but at hour 12, its 100.50. This is not true because , the hour has increased by 6, and when it increased by 6, the amount of pay increased by 6 as well, which is not the right way in which you would do so.

Option A is correct!

Step-by-step explanation:

Hope it helps! =D

Answer:

I think option c is the best answer but i am not surely ok

Answer:here's the correct answer for this question

Step-by-step explanation:edge2023

Answer:

Below in bold.

Step-by-step explanation:

300 degrees - reference angle is |360 - 300 |= 60 degrees

225 = 225 - 180 = 45 degrees

480 = 480 - 360 = 120 so it is 180 - 120 = 60 degrees.

-210 = |-210 + 180| = 30 degrees.

For angle 300° the reference angle is 60°.

In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the x-axis.

Given that,

When θ=300°, Φ=

When θ=225°, Φ=

When θ=480°, Φ=

When θ=-210°, Φ=

Now,

For 300° reference angle is |360 - 300|= 60°

For 225° reference angle is |225-180|= 45°

For 480° reference angle is |480-360|= 120°

So, 180-120= 60°

For -210 = |-210+180|= 30°

Therefore, for θ=300° the reference angle is 60°.

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The domain and the range of the piecewise function in this problem are given as follows:

The function in this problem is defined for all values of x between -6 and 2, except x = 0, and assumes all values of y between 0 and 6, except y = 1, hence the domain and range are given as follows:

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we are given an initial value of 14 and we are told that the value of f(x + 1) is always 49.9 times as large as the value of f(x). The correct expression is: b. \(14(49.9)^x\)

To understand why this is the correct expression, we need to look at how the function is changing.

We know that f(x + 1) is 49.9 times as large as f(x).

This means that:

f(x + 1) = 49.9 f(x)

We can use this information to find f(1), which will help us find the expression for f(x).

f(1) = 49.9 f(0) (since f(1) = f(0 + 1))

\(f(2) = 49.9 f(1) = 49.9(49.9f(0)) = (49.9)^2f(0)f(3) = 49.9\)

\(f(2) = 49.9(49.9)^2\)

\(f(0) = (49.9)^3f(0)\)

We can see that the function is growing exponentially by a factor of 49.9 each time we increase x by 1.

This means that we can represent the function with the following expression:

\(f(0) = (49.9)^3f(0)\)

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Answer:

58 members of the House of Representatives, and 28 members of the senate.

Step-by-step explanation:

We can find the answer to this by simply subtracting:

86 - 58 = 28

So, there are 58 members of the House of Representatives, and 28 members of the senate.

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After evaluating the given integral by changing to polar coordinates we get \(7 e^8-31\)

As per the details shared in the above question it is given that,

\($x^2+y^2=64$\)

\((x, y)=r(\cos \theta, \sin \theta)\)

\(d A=r d r d \theta.\)

Further solving above we get,

\(r^2=64 \\\Rightarrow & r=8 . \\0 \leq r \leq 8 ; & 0 \leq \theta \leq \pi / 2\)

The polar coordinate,

\(\iint_{R} y e^x d A=\int_0^{\frac{\pi}{2}} \int_0^8 r^2 \sin \theta e^{r \cos \theta} d r d \theta\)

\(& =\int_0^8 \int_0^{\frac{\pi}{2}} r^2 \sin \theta e^{r \cos \theta} d \theta ; \\& =\int_0^8\left[-r e^{r \cos \theta}\right]_0^{\pi / 2} d r\)

\(=\int_0^8 r\left[-e^{r \cos \left(\frac{\pi}{2}\right)}+e^\alpha\right] d r .\)

\(=\int_0^8 r e^r d r-\left.\frac{r^2}{2}\right|_0 ^8\)

Now substituting the value we get,

\(7 e^8-31\)

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Note the correct question should be ,

Evaluate the given integral by changing to polar coordinates.

\(\iint_R y e^x d A\) , where R is the region in the first quadrant enclosed by the circle  \(x^2+y^2=64\).

The complex number  -7i into trigonometric form is 7 (cos (90) + sin (90) i) and  3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have a complex number shown in the picture:

-7i(3 + 3i)

= -7i

In trigonometric form:

z = 7 (cos (90) + sin (90) i)

= 3 + 3i

z = 4.2426 (cos (45) + sin (45) i)

\(\rm 7\:\left(cos\:\left(90\right)\:+\:sin\:\left(90\right)\:i\right)4.2426\:\left(cos\:\left(45\right)\:+\:sin\:\left(45\right)\:i\right)\)

\(\rm =7\left(\cos \left(\dfrac{\pi }{2}\right)+\sin \left(\dfrac{\pi }{2}\right)i\right)\cdot \:4.2426\left(\cos \left(\dfrac{\pi }{4}\right)+\sin \left(\dfrac{\pi }{4}\right)i\right)\)

\(\rm 7\cdot \dfrac{21213}{5000}e^{i\dfrac{\pi }{2}}e^{i\dfrac{\pi }{4}}\)

\(\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}\)

=21-21i

After converting into the exponential form:

\(\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}\)

From part (b) and part (c) both results are the same.

Thus, the complex number  -7i into trigonometric form is 7 (cos (90) + sin (90) i) and  3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)

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The graphs of the functions f(x) and g(x) are attached with the answer.

       \(${\displaystyle G=\{(x,f(x))\mid x\in X\}.}\)

Given are the functions f(x) and g(x).

The given functions are -

f(x) = \($100(\frac{3}{5})^{x}\)

g(x) = \($100(\frac{2}{5})^{x}\)

Refer to the graphs of the function f(x) and g(x).

Therefore, the graphs of the functions f(x) and g(x) are attached with the answer.

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9514 1404 393

Answer:

  x = 15√3

  y = 30

Step-by-step explanation:

In a 30°-60°-90° "special" triangle, the ratios of side lengths are ...

  1 : √3 : 2

Your diagram shows the short side is 15, so the other sides can be found by multiplying the above ratio numbers by 15.

  1 : √3 : 2 = 15 : x : y = 15 : 15√3 : 30

  x = 15√3

  y = 30

Answer:

D. x = 22.5

Step-by-step explanation:

Answer:

(1, 2) is a solution

Step-by-step explanation:

In this question, we have to find if the coordinate (1, 2) is a solution to the equation.

To see if it's a solution, we would need to plug in the coordinate into the equation and solve.

Solve:

2x + 5y = 12

2(1) + 5(2) = 12

2 + 10 = 12

12 = 12

Since both sides are the same, which makes the equation true, the coordinates is a solution to the equation.

Answer:

1:500000

Step-by-step explanation:

1 mm ​(map) equals 500 m ​(actual) .

Let's convert 500 m to mm.

1m = 1000mm

500m = 500000 mm

So 1mm to 500000mm on a scale is

1:500000

So it's all about converting the metre to million metre then doing the ratio.

In this case we are not to divide anything because it's already in 1.

So it's 1mm on paper then 500000mm on actual.

Thank you

Answer:

Step-by-step explanation:

The standard deviation of the sampling distribution of sample means is given by the formula:

standard deviation = population standard deviation / sqrt(sample size)

Here, the population standard deviation is 0.8 years, and the sample size is 38. Substituting these values into the formula, we get:

standard deviation = 0.8 / sqrt(38)

standard deviation ≈ 0.13

Rounding to two decimal places, the standard deviation of the sampling distribution of sample means is approximately 0.13 years.

Answer:

f(x) = 5x - 30

Yes it is a function

Step-by-step explanation:

Because when you input 0 you get -30 we know it starts at 0 or (0,-30). This gives us b in the equation y = mx + b.

We know that for every 4 cars washed it increases by 20. So 20/4 is 5. This tells us m = 5.

Plug it all in and you get  y = 5x - 30 or f(x) = 5x - 30

Answer:

y=-2x-2

Step-by-step explanation:

Since this line is supposed to be parallel it will have the same slope.

y=-2x+b

no plug in the (0,-2)

-2=b

y=-2x-2

Answer:

7 hours

Step-by-step explanation:

here,

270/18=105/x

x=(105*18)/270

x=7

Chau made $270 for 18 hours of work. At the same rate,  Therefore Chau would have to work 7 hours at the same rate to make $105.

To find out how many hours Chau would have to work to make $105 at the same rate, we can set up a proportion using the given information:

Let x be the number of hours Chau needs to work to make $105.

We know that Chau made $270 for 18 hours of work, so the rate of earnings per hour is:

Rate = Total earnings / Number of hours

Rate = $270 / 18 hours

Rate = $15 per hour

Now, we can set up the proportion:

$15 per hour = $105 / x hours

To find x, we can cross-multiply:

$15 × x = $105

Now, solve for x:

x = $105 / $15

x = 7 hours

So, Chau would have to work 7 hours at the same rate to make $105.

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1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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