YES both sides of the single magnet attracted to the metal surface because metals are not paramagnetic magnets, temporary magnetism can be induced in metal by bringing a magnet close to it . The pole of metal surface will be such that it is attracted by the magnet.
From result: A1 and A2 both side of magnet attract to metal surface.
when one magnet is removed from stack, magnetic poles of stack will not change because stack consist of many mgnet , after removing one magnet from stack pole strength of stack will reduce but pole of stack will remain same.
From result:
When A side of To know more about standard light intensity visit : https://brainly.com/question/13003361
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Initial most propble speed Vi= \(\sqrt 2RT/M\)
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Why is the oort cloud important for understanding the formation of the solar system?
The Oort cloud is the proximate source of observed nearly parabolic, so-called 'new' comets entering the planetary region, and is also the presumed source of the long-period comet flux and the majority of Halley-type comets (HTCs).
The oort cloud is important for understanding the formation of the solar system.
What is oort cloud?It is believed to be an important source of comets that can provide valuable information about the conditions and processes that were present in the early solar system.
Here,
The Oort Cloud is important for understanding the formation of the solar system because it is believed to be a reservoir of icy bodies that formed early in the solar system's history. These icy bodies, which include comets, are thought to have played a key role in the early evolution of the solar system by delivering water and other volatile materials to the inner solar system, including the early Earth.
By studying the composition and properties of comets from the Oort Cloud, scientists can gain insights into the formation and evolution of the solar system and learn more about the conditions that were present in the early solar system.
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A projectile is fired vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile
ANSWER
\(1841.84\text{ m}\)EXPLANATION
Parameteters given:
Initial velocity = 190 m/s
To find the maximum height, we apply the formula for the maximum height of a projectile:
\(H=\frac{u^2\sin ^2\theta}{2g}\)where u = initial velocity
θ = angle with the horizontal
g = acceleration due to gravity = 9.8 m/s²
From the question, the projectile is fired vertically upward. This means that the projectile will make a 90° angle with the horizontal.
Therefore, we have that the maximum height of the projectile is:
\(\begin{gathered} H=\frac{190^2\cdot\sin ^2(90)}{2\cdot9.8} \\ H=1841.84\text{ m} \end{gathered}\)Answer:
Height is equal to 1841.8367m
Explanation:
KE = GPE
Write out the formula
1/2(m)(v^2) = mgh
Fill it with the information you have
1/2(190^2) = (9.8)(h)
Solve
1/2(36100) = 9.8h
18050 = 9.8h
1841.83673 = h
Write the complete answer out
Maximum height is equal to 1841.8367m (meters)
water flows in a pipe of a terminal of A1=0.02 m2 with a speed of V1=2 m/s. At the second end of the pipe A2=0.04 m2, the speed of flow is V2=_______m/s
some foods, such as _____, are usually classified as solid fats even though they are liquid or soft at room temperature.
Some foods, such as coconut oil, are usually classified as solid fats even though they are liquid or soft at room temperature.
Some foods, such as butter, margarine, and shortening, are usually classified as solid fats even though they are liquid or soft at room temperature. This is because they are high in saturated and/or trans fats, which are solid at room temperature. These types of fats have been linked to increased risk of heart disease, so it is recommended to limit intake of solid fats and choose healthier fats, such as unsaturated fats found in nuts, seeds, and oils like olive and canola.
Additionally, it is important to check food labels for the amount of saturated and trans fats in a product and choose lower fat options when possible.
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When viewed edge-on, a spiral galaxy often?
When we view our galaxy from edge on, we get to see that our galaxy is bend towards earth.
A spiral galaxy typically has a rotating disc with spiral 'arms' that curve out from a dense central region. The Milky Way is a spiral galaxy. Four classes are used to classify galaxies: spiral; barred spiral; elliptical and irregular. The Milky Way is a large barred spiral galaxy. All the stars we see in the night sky are in our own Milky Way Galaxy. Our galaxy is called the Milky Way because it appears as a milky band of light in the sky when you see it in a really dark area. Generally, the dust and whirling arms of spiral galaxies such as the Milky Way look flat when seen edge-on, because they are oriented differently toward Earth.
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Explain the operation of a simple circuit made of logic gates
and design the following combinational circuit.
Answer:
A combinational logic circuit is a circuit whose outputs only depend on the current state of its inputs. In mathematical terms, the each output is a function of the inputs. These functions can be described using logic expressions, but is most often (at least initially) using truth tables.
Why is the use of carbon- 14 dating limited?
Answer:
because carbon 14 has only a short half life, rather than other elements with longer half lives.
Explanation:
✨science✨
A solenoid of radius 2. 30 cm has 640 turns and a length of 25. 0 cm. (a) Find its inductance. MH (b) Find the rate at which current must change through it to produce an emf of 70. 0 mV. (Enter the magnitude. ) A/s
To find the inductance (L) of the solenoid, we can use the formula:L = (μ₀ * N² * A) / l, where μ₀ is the permeability of free space (4π × 10^(-7) T·m/A), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.
Given:
Radius of the solenoid, r = 2.30 cm = 0.023 m,
Number of turns, N = 640,
Length of the solenoid, l = 25.0 cm = 0.25 m.
The cross-sectional area of the solenoid, A, can be calculated as:
A = π * r²
= π * (0.023)²
≈ 0.001663 m².
Now we can calculate the inductance:
L = (μ₀ * N² * A) / l
= (4π × 10^(-7) * 640² * 0.001663) / 0.25
≈ 0.133 mH.
Therefore, the inductance of the solenoid is approximately 0.133 mH.
To find the rate at which the current must change through the solenoid to produce an emf (ε) of 70.0 mV, we can use Faraday's law of electromagnetic induction:ε = -L * (dI/dt), where ε is the induced emf, L is the inductance, and (dI/dt) is the rate of change of current.
Given:
Inductance, L = 0.133 mH = 0.133 × 10^(-3) H,
Induced emf, ε = 70.0 mV = 70.0 × 10^(-3) V.
Rearranging the equation, we can solve for (dI/dt):
(dI/dt) = -ε / L
= -(70.0 × 10^(-3)) / (0.133 × 10^(-3))
= -70.0 / 0.133
≈ -526.32 A/s.
Since the question asks for the magnitude of the rate of change of current, the answer is approximately 526.32 A/s.
Therefore, the magnitude of the rate at which the current must change through the solenoid to produce an emf of 70.0 mV is approximately 526.32 A/s.
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suppose a planisphere star rises at 8pm (pst) tonight. what time did that same star rise one month ago? g
The vertical impulse by the lift force during this time is 4.15 by minutes for Newton second.
We have a demon That there is a force of 52 down cause of 15. Right? This is what we have you in the questions and acting on the bill. Be both masked by Graham of Mars five g. No. In the meantime. And travelers given that the time and develop acting on this fourth, you should humanists. But we need to find the impulse England's. They seem to not advise you actually. This is what we need to find. So we know that false change in momentum much time. So basically impulses change momentum, but you find impulses changing moment also jay so G is false in campaign so we can put forth here. The forces to do time 59 1 dime. That's Spanish for -5. This was with 15 to 10 days to four minutes, five Newton and two times three seconds Volunteers. They will get 15 into 10 days to the R -4. 15 10 by minus for Newton's second.
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Calculate the energy transferred by an appliance using mains electricity (230v) if the charge is 150c. Give your answer in kilojoules.
The energy transferred by an appliance using mains electricity is 34500 Joule.
What is energy?
In physics, energy is the ability to perform work. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another. Energy is always assigned based on its nature once it has been transmitted.
Given that: charge of the particle: Q = 150 C.
Potential difference applied: V = 230 V.
Hence, the potential energy of the particle: E = QV
= 150 × 230 Joule
= 34500 Joule.
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How many moles are there in a 2,500 cm 'sample of oxygen at a temperature of 24 °C and a pressure
of 125 kPa?
Explanation:
using the formula pv=nRt where p= pressure =125 v= volume =2500= 25.oom3 to meter n = mumber of moles =? T= temperature = 24 =24+273=297k
\(molarity \: \: constant \: = 8.3j mol {}^{- 1} {k}^{- 1} \)
which is given as R so inputting the values we have 125×25=n×8.3×297 3125=2465.1n dividing all with the coefficient of n we have
\( \frac{3125}{2465.1} = 2465.1 \24651\)
1.27= n therefore no of moles =1.27The no of moles are there in a 2,500 cm sample of oxygen at a temperature of 24 °C and a pressure of 125 kPa will be 1.27.
What is ideal gas equation?It is the relationship between the pressure,volume and the temperature. Ideal gas equation is found as;
pv=nRt
Given data is;
p(pressure) =125
v(volume) =2500 cm = 25.m³
n(number of moles) =?
T(temperature) = 24°C =24+273=297k
From Ideal gas equation ;
pv=nRt
125×25=n×8.3×297
3125=2465.1 n
n=1.27
Hence,the no of moles will be 1.27.
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Need help immediately please
a 5 kg box on a rough surface being pulled to the right by a string. The coefficient of kinetic friction between the box and the surface is 0.30.
What is the magnitude of the frictional force acting on the 5 kg box?
15 N
16.7 N
50 N
1.5 N
The magnitude of the frictional force acting on the 5 kg box will be 15 N
The coefficient of kinetic friction is defined as the ratio of force of kinetic friction to the normal reaction between the two surfaces in contact.
F = normal force
fr = frictional force
mu = coefficient of kinetic friction
since ,
fr = mu * F
= mu * mg ( as N = mg)
= 0.30 * 5 * 9.8
= 14.7 N
≈ 15 N
The magnitude of the frictional force acting on the 5 kg box will be a) 15 N
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The distance between slits on a diffraction grating is 0.60
How large is the path difference?
mm, and one of the angles of diffraction is 0.30°. The
light forms a second-order bright band.
O 1047 nm
• 1571 nm
© 3142 nm
6284 nm
The path difference is 1.57 × 10⁻⁶ m
Distance is the amount of space between things. From distance, it is the hard to tell if someone's wearing the a vampire costume abd just a chic black outfit.
For constructive interference thai is formation of bright fringe through a diffraction grating is given by:
d sin θ = n λ
here, d is the distance between slits.
θ is the angle of diffraction
n is the order of fringe
and λ is the path difference.
λ = (d sin θ)/ n = (0.60 *10 ⁻³m) (sin 0.30°) ÷ 2 = 1.57 * 10⁻⁶ m
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Answer:
C is the answer
Explanation:
Jackson throws a football 30 meters at a speed of 15 m/s. How long was the football in the air before Laurence caught it for touchdown
Answer:
2s
Explanation:
Given parameters:
Distance = 30m
Speed = 15m/s
Unknown:
Time before Laurence caught it = ?
Solution:
To solve this problem;
Speed = \(\frac{disance }{time}\)
Time taken = \(\frac{distance }{speed }\) = \(\frac{30}{15}\) = 2s
The time it takes is 2s
Given:
30 metersSpeed of 15 m/sWe will solve:
Speed = \(\frac{distance}{time}\)
Time taken = \(\frac{distance}{time}\) = \(\frac{30m}{15m/s}\) = 2s
The time it takes is 2s
ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
\( -3.09 = 6.93*10^{-4} * V \)
\( V = \frac {6.93*10^{-4}}{-3.09} \)
Potential difference, V = -0.000224 Volts
3. A man heads up a trail going north to see a lake. The trail is 5 miles long and it takes him
2 hours to get there. What was his velocity?
Answer:
v = 2.5 mi/h
Explanation:
The velocity of an object is defined as the time rate of change of its position. In other words the velocity of an object is just a ration of displacement covered by the object to the time taken by the object, to cover that distance. So, in this case we will use the same formula or equation to calculate the velocity of the man. The formula is as follows:
v = s/t
where,
v = velocity of the man = ?
s = distance of the trail = 5 miles
t = time required to complete the trail = 2 h
Therefore,
v = 5 miles/ 2 h
v = 2.5 mi/h
Which type of box will best protect a fragile object by minimizing the force on the object
1. A 500.0 g metal block absorbs 5.875 × 103 J of heat to raise its temperature by 50.0 K. What is the substance? Show your work.
Specific Heats of Selected Substances
Substance
C [J/(kg·K)]
Water (ice)
2,060
Iron
450
Aluminum
897
Gold
130
Copper
385
Silver
235
Ammonia (liquid)
4,700
Water (liquid)
4,180
Water (steam)
2,020
Lead
128
The name of the substance is silver based on the specific heat capacity value.
What is the specific heat capacity of the substance?The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.
Q = mcΔθ
where;
m is the mass of the substancec is the specific heat capacity of the substanceΔθ is the change in temperaturec = Q / mΔθ
The specific heat capacity of the substance is calculated as;
c = (5875 J ) / ( 500 g x 50 )
c = 0.235 J/kgK
The substance that has the same specific heat capacity calculated above is silver.
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When is it safer to drive a heavier car over a lighter car?
a. When you crash into a wall
b. When you crash into a tree
c. When you crash into another car
d. It is never safe in a hevaier car
Answer:
I think it would be c, crashing into another car
What is the mean of 4, 6, 8, 20, 12?
10
00
5
Answer:
mean= sum of all values/ total no. of values
values given= 4,6,8,20,12
= 4+6+8+20+12/5
=50/5=10
HOPE IT HELPS
PLZ MARK AS BRAINLIEST
What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of
gravity only (9.8m/s²)?
Answer:
9800N
Explanation:
Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N
A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
Answer:
2.78m/s²
Explanation:
Complete question:
A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?
According to Newton's second law of motion:
\(\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\\)
Where:
\(\mu\) is the coefficient of friction
g is the acceleration due to gravity
Fm is the moving force acting on the body
Ff is the frictional force
m is the mass of the box
a is the acceleration'
Given
\(\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2\)
Required
acceleration of the box
Substitute the given parameters into the resulting expression above:
Recall that:
\(gsin\theta - \mu g cos\theta = a_x\\\)
9.8sin30 - 0.25(9.8)cos30 = ax
9.8(0.5) - 0.25(9.8)(0.866) = ax
4.9 - 2.1217 = ax
ax = 2.78m/s²
Hence the acceleration of the box as it slides down the incline is 2.78m/s²
A certain large wind turbine is able to transform 1,500,000J of mechanical energy into 1,000,000J of electrical energy every second. a. How much thermal energy does this turbine 'waste' each second? b. Calculate the efficiency of this turbine.
a. The amount of thermal energy 'wasted' by the turbine per second = 500,000 J
b. Efficiency of the turbine = 66.7%
What is energy?Energy is the ability to do work.
Energy is essential to sustain the material universe. Energy constantly flows in the universe and is transformed into various forms.
Th various forms of energy are:
mechanical energyelectrical energynuclear energysolar energyheat energysound energyWhen energy is lost in a system, it is usually converted to heat.
a. The amount of thermal energy 'wasted' by the turbine per second = 1,500,000 J - 1,000,000 = 500,000 J
b. Efficiency = (1,000,000/1,500,000) * 100%
Efficiency of the turbine = 66.7%
In conclusion, energy is usually lost in the form of heat or thermal energy during energy transformations.
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An airplane travels down a
runway for 4.0 seconds with an
acceleration of 9.0 m/s2. What
its change in velocity during
this
time?
Someone helpppp!!
Answer:
We can use the equation of motion of an object under constant acceleration to calculate the change in velocity during this time. The equation is:
Δv = at
Where:
Δv = change in velocity (m/s)
a = acceleration (m/s^2)
t = time (s)
Given that the acceleration of the airplane is 9.0 m/s^2 and the time it travels down the runway is 4.0 seconds we can substitute these values into the equation:
Δv = 9.0 m/s^2 * 4.0 s = 36 m/s
Therefore, the change in velocity of the airplane during this time is 36 m/s.
Please help me look at the image below
co-generation: a simple rankine cycle produces 40 mw of power, 50 mw of process heat and rejects 60 mw of heat to the surroundings. what is the utilization factor of this cogeneration cycle neglecting the pump work?
60 % is the utilization factor of this cogeneration cycle neglecting the pump work of a simple rankine cycle
data sent A straightforward Rankine cycle generates 40 MW of electricity, 50 MW of process heat, and 60 MW of heat waste that is released into the environment.
rankine cycle produces 40 MW of power,
50 MW of process heat
60 MW of heat to the surroundings
Total = 40 + 50 + 60 = 150 MW
Utilized = 50 + 40 = 90 MQ
Usefulness of this cogeneration cycle = 90/150 * 100= 60 %
Usefulness of this cogeneration cycle = 60 %
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A wave has a frequency of 450 Hz and a wavelength of 0.52 m. What is the speed of the wave?
Answer:
Explanation:
ave speed is always (frequency) x (wavelength)
Speed = (450 /sec) x (0.52 m)
= 234 m/sec .
The dose limits established for the OSL, TLD, film badge, and pocket dosimeter are valid for:
a. Alpha, beta, and x radiations
b. Beta, x-, and gamma radiations
c. Alpha,x-, and gamma radiations
d. All ionizing radiations
Option (a) is correct, the dose limits established for the OSL, TLD, film badge, and pocket dosimeter are valid for alpha, beta, and x radiations.
The OSL (Optically Stimulated Luminescence), TLD (Thermoluminescent Dosimeter), film badge, and pocket dosimeter are all commonly used devices for measuring and monitoring ionizing the radiation exposure.
Among the given options, alpha, beta, and x radiations are all forms of ionizing radiation. These devices are capable of measuring the dose of the radiation received from these types of the radiations, and their established dose limits are valid for the alpha, beta, and x radiations.
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The TSR is maximized for a 3 bladed wind turbine when the blade's velocity is divided by the wind speed and is between___ and ___. a. 5.2.6.4 b. 9.5 10.5 c. 15.2.0 d. 7.8.8.2
Blade speeds within the range of 9.5 to 10.5 are optimized to maximize TSR, which in turn maximizes wind turbine efficiency and power output. Here option B is the correct answer.
The TSR (Tip Speed Ratio) is an important parameter for wind turbines, which represents the ratio of the speed of the tip of the wind turbine blade to the speed of the wind. The TSR is a critical factor in determining the efficiency and power output of the wind turbine.
For a three-bladed wind turbine, the optimal range of TSR is typically between 5 and 10, depending on the specific design of the turbine. Within this range, the wind turbine is able to efficiently convert the kinetic energy of the wind into mechanical energy, which can then be converted into electrical power.
If the TSR is too low, the wind turbine will not be able to capture enough energy from the wind to generate significant power. On the other hand, if the TSR is too high, the wind turbine will experience excessive drag and will not be able to efficiently convert the wind energy into useful power.
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