Answer: all options presetend by the question apply to indicate that a chemical reaction has taken place
Explanation:
The question requires us to choose the signs to identify that a chemical reaction has taken place.
When a chemical reaction happens, some changes in the system can occur indicating that the reactants were converted into products. Some of these changes are:
- formation of gas (or bubbling) when a gas is one of the products of the reaction;
- formation of a solid, also called precipitate, when the product formed is in solid form;
- change in temperature, indicating that the reaction absorbed (decreased temperature) or released (increased temperature) heat;
- change in color, indicating that a product with different color from reactants was formed;
- change in odor.
Therefore, all options presetend by the question apply to indicate that a chemical reaction has taken place.
what r variable's :) :) :) :) :)
Answer: an element, feature, or factor that is liable to vary or change.
"there are too many variables involved to make any meaningful predictions"
Explanation:
Answer:
A variable is any characteristics, number, or quantity that can be measured or counted.
Explanation:
Your little sister asks you a scientific question: "Does chocolate milk come from brown cows?" In order to answer the question, you decide to form a hypothesis.
Explain whether or not the following statements are effective hypotheses.
i. Brown cows produce chocolate milk.
ii. Brown cows never produce chocolate milk.
iii. Brown cows produce white milk.
A hypothesis is a proposed explanation or prediction based on limited evidence or observations, which can be tested through further investigation or experimentation. It should be specific, testable, and based on existing knowledge.
Now, let's evaluate each statement as a hypothesis:Brown cows produce chocolate milk.This statement can be considered an effective hypothesis as it proposes a relationship between the color of cows and the color of milk they produce. It is specific and testable, as one could observe and analyze the milk produced by brown cows to see if it is indeed chocolate milk. However, based on existing knowledge, we can confidently say that this hypothesis is not accurate, as the color of a cow does not determine the color of the milk it produces.Brown cows never produce chocolate milk.This statement can also be considered an effective hypothesis because it makes a specific claim that can be tested. However, based on existing knowledge, we can say that this hypothesis is not accurate. While the color of a cow does not determine the color of the milk, it is possible for chocolate milk to be produced by adding chocolate syrup or cocoa powder to regular white milk.Brown cows produce white milk.This statement is not an effective hypothesis as it is a general statement that aligns with existing knowledge. It does not propose any specific relationship or prediction to be tested. In the context of this question, the statement is not accurate as milk produced by cows is typically white, regardless of their coat color.For such more question on hypothesis
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An experiment shows that 113 mL gas sample at pressure of 721mmHg changed to 901 mmHg.
What is the new volume?
Answer:
90.4 mL
Explanation:
Step 1: Given data
Initial volume of the gas (V₁): 113 mLInitial pressure of the gas (P₁): 721 mmHgFinal volume of the gas (V₂): ?Final pressure of the gas (P₂): 901 mmHgStep 2: Calculate the final volume of the gas
According to Boyle's law, the volume of a gas is inversely proportional to the pressure. We can calculate the final volume of the gas using the following expression.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 721 mmHg × 113 mL / 901 mmHg
V₂ = 90.4 mL
what percentage of a sample is remaining if you use the decimal (0.2536) and the fraction (3/7) of that sample
The percentage left is 57%.
What is the percentage remaining?We know that a fraction is a part of a whole. Let us in this case take the whole as one and then the fraction that we remove out of it is 3/7. We now have to find the percentage that remains.
Thus'
Fraction that remains = 1 - 3/7 = 4/7
Hence;
Percentage that is left = 4/7 * 100
= 57%
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For each of these pairs of half-reactions, write the balanced equation for the overall cell reaction and calculate the standard cell potential. Express the reaction using cell notation. You may wish to refer to Chapter 20 to review writing and balancing redox equations.
1.
Pt2+(aq)+2e-Pt(s)
Sn2+(aq)+2e-Sn(s)
2.
Co2+(aq)+2e-Co(s)
Cr3+(aq)+3e-Cr (s)
3.
Hg2+(aq)+2e-Hg (I)
Cr2+(aq)+2e-Cr (s)
please help out
1. For the pair of half-reactions:
Pt2+(aq) + 2e- → Pt(s) ... (1)
Sn2+(aq) + 2e- → Sn(s) ... (2)
To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:
2(Pt2+(aq) + 2e-) → 2(Pt(s))
Sn2+(aq) + 2e- → Sn(s)
Combining the equations, we have:
2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)
The cell notation for this reaction is:
Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)
To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:
E°(Pt2+/Pt(s)) = +1.20 V
E°(Sn2+/Sn(s)) = -0.14 V
The overall cell potential (E°cell) is the difference between the reduction potentials:
E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V
Therefore, the standard cell potential for this reaction is +0.14 V.
2. For the pair of half-reactions:
Co2+(aq) + 2e- → Co(s) ... (3)
Cr3+(aq) + 3e- → Cr(s) ... (4)
To balance the number of electrons transferred, equation (4) can be multiplied by 2:
2(Co2+(aq) + 2e-) → 2(Co(s))
Cr3+(aq) + 3e- → Cr(s)
Combining the equations, we have:
2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)
The cell notation for this reaction is:
Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)
To calculate the standard cell potential (E°), we refer to the standard reduction potentials:
E°(Co2+/Co(s)) = -0.28 V
E°(Cr3+/Cr(s)) = -0.74 V
The overall cell potential (E°cell) is the difference between the reduction potentials:
E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V
Therefore, the standard cell potential for this reaction is -0.46 V.
3. For the pair of half-reactions:
Hg2+(aq) + 2e- → Hg (l) ... (5)
Cr2+(aq) + 2e- → Cr(s) ... (6)
The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:
2(Hg2+(aq) + 2e-) → 2(Hg (l))
Cr2+(aq) + 2e- → Cr(s)
Combining the equations, we have:
2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)
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Consider a solution which is 0.10M in NH3 and 0.20M in NH4Cl. Choose ALL of the following that are false. If a small amount of NaOH is added, the pH becomes slightly more basic. If HCl is added, the H ions react with the NH3. If a small amount of HCl is added, the pH becomes slightly more basic. If NaOH is added, the OH- ions react with the NH3. If NH4NO3 is added, the pH becomes more basic.
Answer:
The incorrect or the false options are -
(B) - If NH4NO3 is added, the pH becomes more basic.
(D) - If a small amount of HCl is added, the pH becomes slightly more basic.
(E) - If NaOH is added, the OH- ions react with the \(NH_3\).
Explanation:
The given solution the buffer basic .
When a small amount of either is added, the hydrogen ion reacts with the ammonium ion, raising the pH slightly.When a small amount of HCl is added, the hydronium ion reacts with the ammonia, raising the pH slightly.Therefore , the options A ( If a small amount of NaOH is added, the pH becomes slightly more basic.) and C ( If HCl is added, the H+ ions react with the NH3.) All other B , D , E are false .
True or False
When calculating the average atomic mass of an element, the average atomic mass value falls closest to that of the least percentage abundance (least common) isotope.
Answer:
true
Explanation:
Consider an ion with the symbol X2+ formed from a representative element. (5.2, 5.3)a. What is the group number of the element?b. What is the electron-dot symbol of the element?c. If X is in Period 3, what is the element?d. What is the formula of the compound formed from X and the nitride ion?
Answer:
a) the element belongs to group 2
b) see image attached
c) Magnesium
d) X3N2
Explanation:
Any ion with the formula X^2+ was derived from group 2 elements. The group two element found in period 3 is magnesium alone.
Since the nitride ion has a valency of -3 and X^2+ has a valency of +2 , then a compound formed between X^2+ and the nitride ion will have the formula X3N2.
a. The group number of the element can be determined by knowing the charge of the ion. In the ion X2+ has a charge of 2+. Since representative elements typically form ions with charges equal to their group numbers, we can conclude that the group number of the element X is 2.
b. The electron-dot symbol, also known as Lewis dot symbol, represents the valence electrons of an element. Since X is a representative element in Group 2, it has two valence electrons.
c. If X is in Period 3, it could be one of the elements from Group 2 in that period. The most likely element would be Magnesium (Mg), as it is the representative element in Group 2 of Period 3.
d. The nitride ion has a charge of 3-. To form a neutral compound, the charges of X and the nitride ion must balance out. Since X has a charge of 2+ and the nitride ion has a charge of 3-, we need two X ions to balance the charge of three nitride ions. Therefore, the formula of the compound formed from X and the nitride ion is X3N2.
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In table below, there are descriptions of an experiment on samples of three different chemical compounds. Decide whether the compound is ionic or molecular, if you can. If there is not enough information to decide, choose can't decide in the third column.
Compound Description Ionic or molecular?
can't decide
1 Compound 1 is a hard grayish-white solid. A small 250. mg
sample of it is put into a quartz tube and heated strongly.
It starts to melt at 1055. °C.
2 Compound 2 is a hard grayish-white solid. When tapped
gently with a small hammer, a sample fractures into
fragments and a whitish powder. The powder is soluble in
water, and when 15 g are dissolved in 100 mL of water,
the solution conducts electricity well.
3 Compound 3 is a soft waxy white solid that can be easily
shaped and molded by hand. When the flame of an ordinary
laboratory burner is held about 10 cm away from the solid,
it rapidly and extensively melts into a clear liquid.
Answer:
Compound 1- ionic solid
Compound 2- can't really decide
Compound 3- molecular solid
Explanation:
An ionic solid has a very high melting point. It is hard but not brittle. It's solution or melt but not it's solid conducts electricity. Compound 1 is an ionic solid.
We can't really decide on compound 2 since it is brittle yet it's solution conducts electricity.
Lastly, compound 3 is a molecular solid since it has a low melting point.
Answer:
Compound 1- ionic solid
Compound 2- can't really decide
Compound 3- molecular solid
Explanation:
How should I write balanced net ionic equation for this reaction?
0.10 M Cu(NO3)2 + 0.010 M Cu(NO3)2
Because they're the same compound, I'm not sure how to write a net ionic equation for them. Any help is appreciated!
Answer:
Explanation:
Assumptions
They would ionize completely, or you must assume that. The volumes must be the same as well.0.11M Cu(NO3)2 ===> 0.11MCu2+ + 0.22 NO3-Note
The concentrations would merely add. All things change if the assumptions I've made are not true.
You weighed out 0.020 g of your crude aspirin product in order to determine the amount of salicylic acid impurity. Following the procedure outlined in the manual, you dissolved the solid and diluted the solution to a final volume of 10.0 mL. If the absorbance of your sample solution was 1.07, what was the percent salicylic acid in your product?
a. 6.4%.
b. 10%.
c. 7.8%.
d. 92%.
e. none of the above.
Answer:
7.8%
Explanation:
Given that:
The initial mass amount of aspirin = 0.020g
The standard molar mass of aspirin = 240 g/mol
Thus, the number of moles = mass/molar mass
= 0.020/240
= 0.0000833 moles
Now, the molarity of aspirin in the solution(diluted) \(C_1\) = \(\dfrac{8.33 \times 10^{-5}}{0.01}\)
= \(= 8.33 \times 10^{-3} \ M\) (provided the volume v = 0.01 L)
The absorbance of the sample solution A =1.07
The path length (b) = 1 cm
From the standard value of salicylic acid, the coefficient (e)= 139.322 /M/cm
Now; according to Beer's law, the concentration of aspirin is:
A = e×b×c
\(c = \dfrac{A}{eb}\)
\(c = \dfrac{1.07}{139.322 \times 1}\)
c = 0.00768 M
Finally, relating the concentration of the aspirin, the percentage of salicylic acid the product \(= \dfrac{0.00833-0.00768}{0.00833} \times 100\)
= 7.8%
9. A 125.0-g sample of metal is heated to 100.0 °C and placed in a calorimeter that contains 250.0 g
of water. The temperature rises from 24.3 °C to 27.2 °C. What is the specific heat capacity of the
metal? Ignore the calorimeter in your analysis.
10. A 750.0-g sample of a metal is heated to 100.0 °C and placed in a calorimeter that contains
1,000.0 grams of water. The temperature starts out at 24.9 °C and ends at 26.5 °C. If the
calorimeter has a heat capacity of 1,101 J/°C, what is the specific heat of the metal?
9. The specific heat capacity of the metal is approximately 0.47 J/g°C, 10. The specific heat of the metal is approximately 0.52 J/g°C.
9-To determine the specific heat capacity of the metal, we can use the formula:
q = mmetal × cmetal × ΔTmetal + mwater × cwater × ΔTwater
where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
cmetal = q/(mmetal × ΔTmetal)
q = mwater × cwater × ΔTwater = (250.0 g) × (4.184 J/g°C) × (27.2°C - 24.3°C) = 3111.8 J
mmetal = 125.0 g
ΔTmetal = 27.2°C - 100.0°C = -72.8°C
cmetal = 3111.8 J/(125.0 g × -72.8°C) ≈ 0.47 J/g°C
10- To solve for the specific heat of the metal, we need to account for the heat capacity of the calorimeter as well. The heat transferred from the metal to the water is given by:
q = (mmetal × cmetal + Ccalorimeter) × ΔT + mwater × cwater × ΔT
cmetal = (q - Ccalorimeter × ΔT)/(mmetal × ΔT)
q = (1000.0 g) × (4.184 J/g°C) × (26.5°C - 24.9°C) = 1253.44 J
Ccalorimeter = 1101 J/°C
mmetal = 750.0 g
ΔT = 26.5°C - 100.0°C = -73.5°C
cmetal = (1253.44 J - 1101 J/°C × -73.5°C)/(750.0 g × -73.5°C) ≈ 0.52 J/g°C
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How much kinetic energy does a 6.08 kg ball have if it's moving with a speed of 1.14 m/s?
Answer: KE = 8.6917248 J
I'm not for sure but I am pretty positive this is the answer
hello, can you help me identify the name of these 4 molecules as well as the structural formula and the skeletal formula? thank you
Answer:1. metyletevinyl
4. (Z)-3-hydroxypropenal
Explanation:
Which of the following Noble Gases has only 2 valence electrons because it only has 1 energy level?
Helium (He)
Neon (Ne)
Argon (Ar)
Krypton (Kr)
Answer:
it is he
Explanation:
beacuse Noble gases have 2 volence
What is the de broglie wavelength associated with a cricket ball weighing 0.4kg thrown at a speed of 25m/s?
Considering the definition of De Broglie wavelength, De Broglie wavelength is 6.62×10⁻³⁵ m.
De Broglie wavelengthDe Broglie predicted that a particle with mass m and velocity v (i.e. linear momentum p) should exhibit the behavior of a wave with wavelength value λ. Thus, Louis de Broglie suggested that matter also had characteristics of waves and particles, and proposed to relate a wavelength to the particles of matter.
So he related the wavelength, λ, to the momentum of the particle, using the formula:
λ= h ÷(m×v)
where:
λ is the wavelength associated with a particle of mass m moving at speed v.h is Planck's constant.De Broglie wavelength in this caseIn this case, you know that:
h= 6.62×10⁻³⁴ J.sm= 0.4 kgv= 25 m/sReplacing in the definition of De Broglie wavelength:
λ= 6.62×10⁻³⁴ J.s ÷(0.4 kg× 25 m/s)
Solving:
λ= 6.62×10⁻³⁵ m
Finally, De Broglie wavelength is 6.62×10⁻³⁵ m.
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what are nanofluids and how they work?
Answer:
What is nanofluids?
Nanofluids are engineered suspensions of nanometer-sized solid particles in a base fluid. Suspending small solid particles in the energy transmission fluids can improve their thermal conductivity and provides an effective and innovative way to enhance their heat transfer characteristics significantly.
How nanofluids work?
Nanofluid refers to the dispersion of metal or non-metal nano-powder into traditional heat exchange media such as water, alcohol, and oil to prepare a uniform, stable and high thermal conductivity. The traditional heat exchange medium has a low thermal conductivity and has been unable to meet the growing demand for industrial engineering heat exchange. The thermal conductivity of some metal or non-metal nanoparticles is often hundreds of times higher than that of heat-conducting media. For example, common silicon carbide nanoparticles have a thermal conductivity of 170-270 W/m•K. The researchers found that if the nanoparticles can be uniformly and stably dispersed in the heat transfer medium, the thermal conductivity of the nanoparticles will be greatly improved.
A Sample of an Organic Compound Contain
0.624 Carbon, 0.065 hydrogen, 0·028 oxygen
(a) what is the Emperical formuler of the Compound.
(b) If the relative molecular mass of the Compound Is 1940 what is the moleculer
formular of the compound (C=12₁ H=1
N = 14,0= 16)
(a) The empirical formula of the compound is \(C_{29}H_ {36}O\)
(b) The molecular formula of the compound is approximately \(C_{8}H_{118}O_{3}\)
To determine the empirical formula of the organic compound, we need to find the simplest whole-number ratio of the elements present.
(a) The given percentages of carbon, hydrogen, and oxygen can be converted into moles by dividing them by their respective atomic masses:
Carbon: 0.624 g / 12.01 g/mol = 0.052 mol
Hydrogen: 0.065 g / 1.008 g/mol = 0.064 mol
Oxygen: 0.028 g / 16.00 g/mol = 0.0018 mol
Next, we divide each of the mole values by the smallest mole value (0.0018 mol in this case) to obtain the mole ratio:
Carbon: 0.052 mol / 0.0018 mol ≈ 29
Hydrogen: 0.064 mol / 0.0018 mol ≈ 36
Oxygen: 0.0018 mol / 0.0018 mol = 1
Therefore, the empirical formula of the compound is \(C_{29}H_ {36}O\)
(b) To find the molecular formula, we need the relative molecular mass of the compound, which is given as 1940 g/mol. The empirical formula mass can be calculated by summing the atomic masses in the empirical formula:
Empirical formula mass: (29 × 12.01 g/mol) + (36 × 1.008 g/mol) + (1 × 16.00 g/mol) = 588.94 g/mol
To find the multiplier, we divide the relative molecular mass by the empirical formula mass:
Multiplier: 1940 g/mol / 588.94 g/mol ≈ 3.29
Rounding to the nearest whole number, the molecular formula of the compound is approximately 3 times the empirical formula, resulting in \(C_{8}H_{118}O_{3}\).
In summary, the empirical formula of the compound is\(C_{29}H_ {36}O\), and the molecular formula is approximately \(C_{8}H_{118}O_{3}\).
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The irreversible isomerization A
B was carried out in a batch reactor and the following concentration time data were obtained:
Time vs Concentration data in a Batch reactor
t 0 3 5 8 10 12 15 7.5
mol/h 4 2.89 2.25 1.45 1.0 0.65 0.25 0.07
Determine the reaction order,
, and the specific reaction a rate constant, k, using any method of your choice.
The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.
The term "kinetics" refers to the study of reaction rates, which are determined by measuring the concentration of reactants and products as a function of time.Kinetics experiments can be used to determine the reaction rate and order of reaction. A chemical reaction's rate is defined as the change in the concentration of a reactant or product per unit time. The order of a reaction refers to the number of molecules that must react to produce a product. The order of reaction can be determined by measuring the initial rate of the reaction as a function of concentration.Methods for determining the reaction rate order include the initial rate method, the half-life method, and the integrated rate method. The initial rate method determines the reaction order by measuring the initial rate of the reaction at different reactant concentrations. The half-life method determines the reaction order by measuring the time it takes for the reactant concentration to decrease by half.The integrated rate method determines the reaction order by measuring the concentration of the reactant or product at different times.The specific rate constant can be determined by using the Arrhenius equation, which relates the rate constant to the activation energy, temperature, and frequency factor. The frequency factor can be determined by measuring the rate constant at different temperatures.For such more question on polymerization
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you dissolved the 19g of sugar in 100ml of distilled water. calculate the molarity of the solution you mixed in procedure 1
The molarity of the solution after mixing 19g of sugar in 100ml of distilled water is 5.56×10⁻⁴/ml
The molarity is characterized as the complete number of moles of solute present in a given arrangement for each liter. It is otherwise called "molar focus" and is perused as "molar." It is addressed by the letter "M," and its unit is mol/L. The molarity of an answer is supposed to be one molar in the event that one mole of the solute disintegrates in one liter of the arrangement. The molarity of an answer relies upon the volume of the arrangement yet not the volume of the dissolvable. As the volume of the arrangements changes with the adjustment of states of being of the framework, the molarity of the given arrangement relies upon the actual properties of the framework, like pressure and temperature, in contrast to mass.
We know that molarity is given by the formula
M=number of moles of solute/volume of solution in ml
Here solute is sugar.For finding the moles of solute we need to find the molecular weight of sugar which is calculated as
Sugar(C₁₂H₂₂O₁₁)=12ˣ12 + 22ˣ1 + 16ˣ11=342g
Therefore,number of moles=19/342
Now,we have volume of solution in ml=100
Therefore,molarity=(19/342) /100
=>Molarity=19/34200
=>Molarity=5.56×10⁻⁴/ml
Hence,molarity is 5.56×10⁻⁴/ml
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Explain what occurs in photgraphy reaction???
Answer:
Explanation:. A photograph is an image made by a photo-chemical reaction which records the impression of light on a surface coated with silver atoms. The reaction is possible due to the light-sensitive properties of silver halide crystals.
Answer:
when exposed to like a chemical reaction darkens the film to produce an image.
Explanation:
When exposed to light, a chemical reaction darkens the film to produce an image. ... When film containing Ag+ and Cl- is exposed to light energy, the chlorine ion's extra electron is ejected and then captured by a silver ion.
Which of would be The acid-base pair that can create NaCL with water?
A)LiCland NaOH
B)HCl and NaOH
C)Cl2 and KaI
D)BaO + KO
Answer:
i
Explanation:
Answer:1
Explanation:v
40 grams of KCI are dissolved in 100 mL of water at 45C. How many additional grams of KCI are needed to make the solution saturated at 80 C?
According to the question 32 g of KCI are needed to make the solution saturated at 80 C
What is solution saturated?Solution saturated is a term used to describe a solution that has reached its maximum solute concentration and can no longer dissolve any more solute. This occurs when the number of solute particles in the solution is equal to the number of solvent molecules. When the solution is saturated, any additional solute added to it will simply form a precipitate or settle out of the solution.
At 80°C, the saturation point of KCl is approximately 132 g/L, so in order to make the solution saturated, you need to add an additional 32 g of KCl. To calculate this, you can use the following equation:
(Saturation concentration at 80°C - Initial concentration at 45°C) x Volume = Additional grams of KCl
(132 g/L - 40 g/L) x 100 mL = 32 g.
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The solution in a titration experiment whose concentration is
known is called the
a standard solution
b acid
c indicator
d base
Answer: It is indeed A.Standard Solution.
Hope this helps you!
You have plenty of salts that are in front of you and you are trying to figure out which salts are soluble in water, and which ones of their products are soluble in water. For the following equation, provide the net ionic equation. KI+ Pb(NO3)2 =
First, we need to find the chemical equation:
\(2KI+Pb(NO_3)_2\to PbI_2+2KNO_3\)We can identify that the reactants gives a precipitation reaction which mean that there's a product that doesn't dissolve in water.
The net ionic equation shows only the chemical species involved in the reaction.
You can see it by separating the elements of a compound, like this:
\(2K^++2I^-+Pb^{2+}+2N^{}O^{2-}_{^{}3^{}}\to PbI_2+2K^++2NO^{2-}_3^{}\)The NO3 looks the same because it doesn't suffer any change during the reaction, while the other reactants do.
which the following optically active alcohol is treated with hbr, a racemic mixture of alkyl bromides is obtained
(S)-2-butanol will undergo an SN2 reaction with HBr to produce a racemic mixture of alkyl bromides. Here option B is the correct answer.
When optically active alcohol is treated with HBr, the reaction follows an SN1 or SN2 mechanism. In the case of SN1, a carbocation intermediate is formed, and in SN2, a backside attack by the nucleophile occurs. The stereochemistry of the product depends on the configuration of the intermediate and the direction of attack.
In the case of (S)-2-butanol, the hydroxyl group is attached to the second carbon atom, which makes it a primary alcohol. When treated with HBr, it undergoes an SN2 reaction, where the hydroxyl group is replaced by the bromine atom. The nucleophile attacks from the backside of the molecule, leading to an inversion of configuration.
This results in the formation of a racemic mixture of alkyl bromides, as both enantiomers have an equal chance of being attacked from either side. On the other hand, (R)-2-butanol, being the enantiomer of (S)-2-butanol, will also undergo the same reaction and produce the same racemic mixture of alkyl bromides.
In the case of (R)-1-phenyl ethanol and (S)-1-phenyl ethanol, they are secondary alcohols and can undergo either SN1 or SN2 reactions depending on the reaction conditions. However, the reaction mechanism will lead to the formation of a mixture of diastereomers, rather than a racemic mixture of enantiomers.
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Complete question:
Which of the following optically active alcohols, when treated with HBr, results in a racemic mixture of alkyl bromides?
a) (R)-2-butanol
b) (S)-2-butanol
c) (R)-1-phenyl ethanol
d) (S)-1-phenyl ethanol
Before running other simulations, try to think of solutions to this global energy dilemma. Write a paragraph in response to the following questions: Should we invest more heavily in renewables at a high up-front financial cost, and/or should we invest in finding more fossil fuels, and/or should we ignore the CO2 limit
Answer:
Yes, we should invest in renewable energies that decrease the levels of carbon dioxide in the atmosphere, that is, decrease the partial pressure of carbon dioxide in the environment since it is lethal for human life, in turn I consider that the exploitation of sources Oil was widely used but I think they should have an end, since they pollute oceans, oxygen, and fuels that are not necessary for today's technology since automobiles could be a base of electric or solar energy
Explanation:
Environmental pollution is a very serious current problem, since we should stop investing in oil sources and be able to keep those profits or that economy in another way or replace them with another resource, since if this greenhouse effect is not perceived as a current serious problem, we could run the risk of suffering natural catastrophes, systematic diseases, affections in the same life.
How force and motion alone with energy works?
What happens to dew or frost each day after the sun rises?
Evaporation causes the dew to vanish when the temperature of the atmosphere rises with the rising of the sun.
What is evaporation ?A kind of vaporization called evaporation takes place on the surface of a liquid as it transitions into the gas phase. When humidity impacts the rate of evaporation of water, for example, a high concentration of the evaporating material in the surrounding gas considerably slows down evaporation.
Similar to how perspiration evaporates from your body on a hot day to cool you down, dew evaporates as it cools the plant. This lessens heat exhaustion in extremely hot settings. Some species, particularly desert plants, are capable of directly absorbing water via their leaves.
Thus, Evaporation causes the dew to vanish when the temperature of the atmosphere rises with the rising of the sun.
To learn more about evaporation, follow the link;
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How many liters are there in 144g of H₂O (g)?
What is the mass of 200L at STP of H₂O₂ (g)?
Answer:
1. 179.2 L
2. 303.62 g
Explanation:
1. Determination of volume of H₂O (g).
We'll begin by calculating the number of mole in 144 g of H₂O. This is illustrated below:
Mass of H₂O = 144 g
Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol
Mole of H₂O =?
Mole = mass /Molar mass
Mole of H₂O = 144/18
Mole of H₂O = 8 moles
Finally, we shall determine volume of H₂O (g) as follow:
1 mole of any gas occupy 22.4L at stp.
Therefore, 8 moles of H₂O (g) will occupy =
8 × 22.4 = 179.2 L
Thus, 144 g of H₂O (g) occupies 179.2 L
2. Determination of the mass of H₂O₂ (g).
We'll begin by calculating the number of mole of H₂O₂ (g) that occupied 200 L at STP. this can be obtained as follow:
1 mole of any gas occupy 22.4 L at stp.
Therefore, Xmol of H₂O₂ (g) will occupy 200 L at STP i.e
Xmol of H₂O₂ (g) = 200/22.4
Xmol of H₂O₂ (g) = 8.93 moles
Thus, 8.93 moles of H₂O₂ (g) occupied 200 L at STP.
Finally, we shall determine the mass of H₂O₂ (g) as follow:
Mole of H₂O₂ (g) = 8.93 moles
Molar mass of H₂O₂ = (2×1) + (2×16) = 2 + 32 = 34 g/mol
Mass of H₂O₂ =?
Mole = mass /Molar mass
8.93 = mass of H₂O₂ /34
Cross multiply
Mass of H₂O₂ = 8.93 × 34
Mass of H₂O₂ = 303.62 g