Answer: (0, 5/7)
Step-by-step explanation:
The y intercept is when x = 0
\(10*0+7y=5\\7y=5\\y=5/7\)
alice ate 5 cookies and 2 carrots for a total of 590 calories; bob ate 3 cookies and 4 carrots for a total of 410 calories. how many calories are in one cookie?
Since, Alice ate 5 cookies and 2 carrots for a total of 590 calories; bob ate 3 cookies and 4 carrots for a total of 410 calories. Therefore, In a cookie there are 110 calories.
A calorie is a unit of energy that food and drink provide. we can usually find out how many calories are listed in foods, and wearables like the best fitness trackers let you monitor how many calories you're burning in different activities. Certain foods, such as processed foods, tend to be high in calories. Other foods, such as fresh fruits and vegetables, tend to be low in calories. there is not. Calories are needed to give you enough energy to move, keep warm, grow, work, think, and play. Our circulation and digestion also need to work well with the energy we get from calories.
Let x = calories in cookies.
y = calories in carrots.
Now, according to the question:
5x + 2y = 590 --------------------------------------- (1)
3x + 4y = 410 -------------------------------------- (2)
Multiplying equation(1) by 3 and equation(2) by 5:
15x + 6y = 1770 ---------------------------(3)
15x + 20y = 2050 ---------------------------(4)
Solving we get:
y = 280/14
or, y = 20 units.
Putting the value of y = 20 in equation (2)
3x + 4y = 410
⇒ 3x + 4 × 20 = 410
⇒ 3x = 410 - 80
⇒ x = 330/3
⇒ x = 110 Units
Therefore, the calories of cookies is 110 units .
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A triangle has two sides of length 1 and 4. What is the largest possible whole-number length
for the third side?
Using the triangle inequality theorem, the largest possible whole-number length for the third side is 4.
How to Apply the Triangle Inequality Theorem to Find the Length of the Third Side of a Triangle?The third side of a triangle must be shorter than the sum of the other two sides and longer than the difference between the other two sides.
So, for a triangle with sides of length 1, 4, and x (where x is the length of the third side), we have:
1 + 4 > x
4 + x > 1
1 + x > 4
Simplifying these inequalities, we get:
5 > x
x > 3
x > -3 (this inequality is always true)
The largest possible whole-number length for the third side is 4, since it is the largest integer that satisfies the above inequalities.
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Un panadero usó 1/2 de libra de harina para elaborar un pan, 1/4 de libra para hacer rosquillas y 1/3 de libra de harina para hacer galletas. Sí tenía 2 libras de harina, ¿Cuánta harina le sobró? Ayuda pls
Answer:
hsvxnosh jwydtko isgrekon dtdorny
What is the largest n for which one can solve within a day using an algorithm that requires f(n) bit operations with the given function f(n)?
Part A f(n) = 1000n2 and each bit operation is carried out in 10–11 seconds
Part B f(n) = 2n and each bit operation is carried out in 10–12 seconds
Part C f(n)=22nf(n)=22n and each bit operation is carried out in 10–4 seconds
For the algorithm that requires f(n) bit operations with the given function f(n), Thus, the largest n for which one can solve within a day using an algorithm that requires f(n) bit operations with the given function f(n) are:Part \(A: n ≈ 3,166Part B: n ≈ 96Part C: n ≈ 11\)
Hence, the number of bit operations in a day will be\((24 * 60 * 60 * (10^11)) / (10^-11) = 8.64 × 10^21.For f(n) = 1000n^2\),
the number of bit operations is \(f(n) = 1000n^2.If we set f(n) equal to 8.64 × 10^21,\)
we can solve for n:\(8.64 × 10^21 = 1000n^2n^2 = 8.64 × 10^18n ≈ √(8.64 × 10^18 / 1000)n ≈ 3,166\)Part B:For the algorithm that requires f(n) bit operations with the given function f(n), the largest n can be solved within a day is 96 using the given function \(f(n) = 2^n\), where each bit operation is carried out in 10-12 seconds.
Hence, the number of bit operations in a day will be \((24 * 60 * 60 * (10^4)) / (10^-4) = 8.64 × 10^10.\)
For\(f(n) = 22n,\)
the number of bit operations is\(f(n) = 22n.\)
If we set f(n) equal to \(8.64 × 10^10\), we can solve for n:\(8.64 × 10^10 = 22nn ≈ log2(8.64 × 10^10) / log2(2^2)n ≈ 11\)
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A circle with radius 12 cm has a segment with a central angle of 60. What is the area of the segment?
Answer:
Exact Area = 24pi square cm
Approximate Area = 75.36 square cm (when using pi = 3.14)
Note: "square cm" can be abbreviated to "cm^2" without quotes.
=============================================================
Explanation:
Let's find the area of the full circle with radius r = 12
A = pi*r^2
A = pi*12^2
A = 144pi
This is the exact area of the full circle in terms of pi. To get the approximate area, you would replace pi with something like 3.14 (though you could use more decimal digits in pi to get a more accurate area).
We found the area of the full circle, but we only want a pie slice of it. Each slice is 60 degrees, out of 360 total. So that means we want 60/360 = 1/6 of the full area.
In other words, there are 6 slices because 360/60 = 6, which means we'll divide the area we got by 6
(144pi)/6 = (144/6)pi = 24pi
The exact area of the pie slice is 24pi square cm
If you used the approximation pi = 3.14, then that leads to an approximate answer of 24*pi = 24*3.14 = 75.36 square cm
a diver was collecting water samples from a lake. he collected a sample at every 3m, starting at 5m below water surface. the final sample was collected at a depth of 35m.how many sample did he collected
The diver collected water samples at every 3 meters, starting from 5 meters below the water surface, up to a final depth of 35 meters.
We can find the number of samples collected by dividing the total depth range by the distance between each sample and then adding 1 to include the first sample.
The total depth range is:
35 m - 5 m = 30 m
The distance between each sample is 3 m, so the number of samples is:
(30 m) / (3 m/sample) + 1 = 10 + 1 = 11
Therefore, the diver collected a total of 11 water samples.
IM AWARDING POINTS AND BRAINLIEST ITS DUE ASAP
The expression (3x^7)^4 is equivalent to cx^n. What is the value of c?
Answer:
the answer would be c=81x^28-n I hope it helps!
Answer:
c=81x^28-n
Step-by-step explanation:
\(c=81x^{28-n}\)
write a differential formula that estimates the change in the volume v=πr^2h of a right circular cylinder when the radius changes from r0 to r0 dr and the height does not change.A. dV = πrh0 dh B. dV = 2πr0h dr C. dV = πr2 0h dr D. dV = 2πrh0 dh
The correct answer is C. dV = πr^2 0h dr. This is because the formula for the volume of a right circular cylinder is V = πr^2h. To estimate the change in volume, we take the derivative with respect to r:dV/dr = 2πrh
To estimate the change in volume when the radius changes from r0 to r0 dr, we multiply both sides by dr:
dV = 2πrh0 dr
Since the height does not change, we can substitute h0 for h:
dV = 2πr0h0 dr
Finally, we can use the formula for the volume of a cylinder to substitute πr^2 for h0:
dV = πr^2 0h dr
Therefore, the correct answer is C.
The differential formula that estimates the change in the volume (dV) of a right circular cylinder when the radius changes from r0 to r0 + dr and the height does not change is:
dV = 2πr0h dr
So, the correct answer is B. dV = 2πr0h dr.
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The population of the world was about 5.3 billion in 1990. Birth rates in the 1990s range from 35 to 40 million per year and death rates range from 15 to 20 million per year. Let's assume that the carrying capacity for world population is 100 billion. Use the logistic model to predict the world population in the 2,450 year. Calculate your answer in billions to one decimal place. (Because the initial population is small compared to the carrying capacity, you can take k to be an estimate of the initial relative growth rate.)
Answer:
24.1 billion
Step-by-step explanation:
One way to write the logistic function is ...
P(t) = AB/(A +(B-A)e^(-kt))
where A is initial value (P(0)), and B is the carrying capacity (P(∞)). We are told to use relative population growth in the 1990s as the value for k.
In billions, we have ...
A = 5.3
B = 100
k = 0.02/5.3 ≈ 0.003774 . . . . . relative growth rate at 20 M per year
t = 2450 -1990 = 460
\(P(t)=\dfrac{530}{5.3+94.7e^{-0.003774t}}\\\\P(460)=\dfrac{530}{5.3+94.7e^{-1.73604}}\approx \boxed{24.1\quad\text{billion}}\)
Work your brain today y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100.00. I had another $7.00. How much did I have? Right answer will get delete I won against: Rose
Hey there! I'm happy to help!
We start out with 3.
3
Our mom gives us 10.
3+10=13
Our dad gives us 30.
13+30=43
Our aunt and uncle give us 100.
43+100=143
And we have another 7.
143+7=150
Therefore, we have $150 now.
Have a wonderful day! :D
question what is the hundreds digit of the integer z? (1) 10z > 25,670 (2) z rounded to the nearest hundred is 2,600.
Part a: 10z > 25,670; infinite integer.
Part b: Range = 2550 to 2649.
Explain the term integer?All whole numbers including negative numbers are considered integers. This means that if we combine negative numbers with whole numbers, a collection of integers results. An integer, which can comprise both positive and negative integers, including zero, is a number without a decimal or fractional portion. Integers include things like -5, 10, 21, 15, 18, 97, and 343.Part a: 10z > 25,670
Divide the inequality on both sides by 10.
z > 2,567
Thus, there are infinite number which are greater than 2567.
Part b: z rounded to the nearest hundred is 2,600.
Range = 2550 to 2649.
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Helpppppppp pleaseeeeeeee and can you give an explenations also?
Answer:
B
Step-by-step explanation:
A(-3 , 3) -> A'(-9 , 9)
B(3 , 3) -> B'(9 , 9)
C(3 , 0) -> C'(9 , 0)
A'B'C' is a dilation of ABC about the origin with factor of 3
ΔA'B'C' ~ ΔABC: all the corresponding angles are the same measurement
Given: abcd is a parallelogram ∠gec ≅ ∠hfa and ae ≅fc.
prove △gec ≅ △hfa.
In the given problem, we are given a parallelogram ABCD with the conditions that ∠GEC is congruent to ∠HFA and AE is congruent to FC. We need to prove that triangle GEC is congruent to triangle HFA.
To prove that triangle GEC is congruent to triangle HFA, we can use the Side-Angle-Side (SAS) congruence criterion.
Given that AE ≅ FC and ∠GEC ≅ ∠HFA, we have two sides and the included angle that are congruent.
Now, since ABCD is a parallelogram, opposite sides are parallel and congruent. Therefore, AD ≅ BC and AB ≅ DC.
By using the corresponding parts of congruent triangles, we can conclude that EG ≅ HF (opposite sides of a parallelogram) and EC ≅ FA (opposite sides of a parallelogram).
Now, we have all three sides of triangle GEC congruent to the corresponding sides of triangle HFA, satisfying the SAS congruence criterion.
Therefore, by the SAS congruence criterion, we can conclude that triangle GEC is congruent to triangle HFA.
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Determine the intercepts of the line. y=−3x+12
Answer:
Step-by-step explanation:
y=−3x+12
when x=0 then y=12 , the y intercept is (0,12)
when y=0 then -3x+12=0, -3x=-12, x=12/3=4
x intercept =(4,0)
The x and y intercepts of the line are (4, 0) and (0, 12).
What is a y-intercept?In Maths, an intercept is a point on the y-axis, through which the slope of the line passes. It is the y-coordinate of a point where a straight line or a curve intersects the y-axis. This is represented when we write the equation for a line, y = mx+c, where m is slope and c is the y-intercept.
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
When y=0, we get
x=4
So, x-intercept is (4, 0)
When x=0, we get
y=12
So, y-intercept is (0, 12)
Therefore, the x and y intercepts of the line are (4, 0) and (0, 12).
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The figure below shows parallelograms ABCE, PQRS, and TNLM on a coordinate plane.
• Points S, P, Q, and Rare midpoints of ABCE
• T, N, L, and Mare midpoints of PQRS
Write the equation of line ML. Show your work.
Answer:
ML = √[¼ (EC)²]
Step-by-step explanation:
ML² = ½(QR)²
QR² = ½(EC)²
so, ML² = ¼ (EC)²
=> ML = √[¼ (EC)²]
The equation of the line ML is given by \(ML = \frac{AC}{2\sqrt{2} }\) .
Concept:We will find the length of SE and ER.Then we will find the length of SR by using the Pythagoras theorem in Δ ESR.Then, we will find the length of MR and RL and hence, again using the Pythagoras theorem in Δ MRL and find the length of ML.How to solve the given question?Since, S is the midpoint of AE.Thus, the equation of the line ML is given by \(ML = \frac{AC}{2\sqrt{2} }\) .
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21) Which expression is equivalent to 6(7x − 4)? A) 13x − 10 B) 13x − 24 C) 42x − 10 D) 42x − 24
Answer:
Answer is D) 42x − 24
Step-by-step explanation:
Opening the expression given in question
6(7x − 4)
6 will be multiplied by both items present inside parenthesis.
it can be written as
={(6 * 7x) - (6*4)}
=42x-24
Hope that clears the question.
An automobile insurance company has determined the probabilities for various claim amounts for drivers ages 16 through 21. Calculate the expected value to the nearest dollar. Amount of Claim $0 $2000 $4000 $6000 $8000 $10000 Probability 0.70 0.15 0.08 0.05 0.01 0.01
The expected value to the nearest dollar is 4895.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events.
The probability of all the events occurring need to be 1.
Given that Amount of Claim $0 $2000 $4000 $6000 $8000 $10000
Probability 0.70 0.15 0.08 0.05 0.01 0.01
Therefore, Expected value E(x) = Σx * p(x)
E(x) = - 5(0.999999) + 4899999995(0.000001)
E(x) = - 4.999995 + 4899.999995
E(x) = 4895
Hence, expected value is 4895
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Find the Surface area of the trapezoid
please help
show work
Answer:
259.5
Step-by-step explanation:
8.1*12=97.2
Area of trapiezium = 1/2(b+a)h
(2.8+8.1)=10.9
10.9*3/2=16.35
16.35*2=32.7
2.8*12=33.6
33.6+32.7+97.2=163.5
4*12*2=96
163.5+96=259.5
Julie and Barry Spinos purchased a house for $96,400. They made a 25 percent down payment and financed the remaining amount at 5. 50 percent for 30 years. Their monthly payment is $410. 66. How much of the first monthly payment is used to reduce the principal?
The first monthly charge has about $78.78 allotted in the direction of reducing the principal.
The total buy charge of the house is $96,400 and the Spinoses made a 25% down payment, because of this they paid $96,400 x 0.25 = $24,100 in advance.
Therefore, the final quantity that they financed is $96,400 - $24,100 = $72,300.
They financed this amount at 5.50% for 30 years, which gives us the following method for calculating the monthly payment (P):
P = (r * PV) / (1 - (1 + r)^(-n))
in which:
r = month-to-month interest rate PV = present value n = overall range of paymentsSubstituting the values, we get:
P = (0.00458 * 72,300) / (1 - (1 + 0.00458)^(-360))
P ≈ $410.66
We recognise that the monthly payment is $410.66 and we will calculate the interest portion of the primary monthly price as follows:
interest = balance * monthly interest price
interest = $72,300 * (5.50% / 12) ≈ $331.88
To calculate the amount of the primary monthly charge this is used to lessen the fundamental, we subtract the interest component from the total monthly payment:
$410.66 - $331.88 ≈ $78.78
Thus, the first monthly charge has about $78.78 allotted in the direction of reducing the principal.
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5.) A woman put $580 into a savings account for one year. The rate of interest on the account was 6.5%. How much was the interest for the vear in dollars and cents? (Round to the nearest cent) 6.) Pamela bought an electric drill at 85% of the regular price. She paid $32.89 for the drill. What was the regular price? (Round to the nearest cent)
The amount of interest for the year was 3,770 cents, and the regular price of the electric drill that Pamela bought before the discount was 21,927 cents
To find the interest we can use this following formula:Interest = P x R x T.
Where:
P = Principal amount (the beginning balance).
R = Interest rate
T = Number of time periods
In this case, we are given that;
Principal amount (P) = $580
Interest rate (R) = 6,5 %
Time = 1 year
Hence, The amount of the interest = 6,5% of $580
= 0.065 × $580
= $37.7
1 dollar = 100 cents
Hence, $37.7 = 37.7 × 100 cents equal to 3,770 cents
To find the regular price of the electric drill, we can use this following formula:P = (1 – d) x
Where,
P = Price after discount
D = discount rate
X = regular price
In this case, we are given that:
P = $32.89
D = 85% = 0,85
Hence, the regular price:
P = (1 – D) x
32.89 = (1 – 0.85) X
32.89 = 0.15X
X = 32.89/0.15
X= 219.27
1 dollar = 100 cents
Hence, $219.27 = 219.27 × 100 cents equal to 21,927 cents
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Which measures are used in the five-number summary? A. Standard deviation B. Minimum value C. First quartile D. Median
The minimum value and median are used in the five-number summary.
What is the box-and-whisker plot?A box and whisker plot displays a "box" with its left edge at Q₁, right edge at Q₃, "center" at Q₂ (the median), and "whiskers" at the maximum and minimum.
Given:
A five-number summary.
That means minimum value, lower quartile (Q1), median value (Q2), upper quartile (Q3), and maximum value.
From the given choices:
The minimum value and median are the required measures.
Therefore, the minimum value and median are the required measures.
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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that rn(x) → 0. ] f(x) = ln x, a = 9
Taylor series is \(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)
To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have
f(x) = ln(x)
\(f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }\)
.
.
.
Since we need to have it centered at 9, we must take the value of f(9), and so on.
f(9) = ln(9)
\(f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }\)
.
.
.
Following the pattern, we can see that for \(f^{n}(x)\),
\(f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}\)
This applies for n ≥ 1, Expressing f(x) in summation, we have
\(\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}\)
Combining ln2 with the rest of series, we have
\(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)
Taylor series is \(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)
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Two pulleys, one with radius r 1r1 and the other with radius r 2r2, are connected by a belt. The pulley with radius r 1r1 rotates at omega 1ω1 revolutions per minute, whereas the pulley with radius r 2r2 rotates at omega 2ω2 revolutions per minute. Show that StartFraction r 1 Over r 2 EndFraction equals StartFraction omega 2 Over omega 1 EndFraction r1 r2
Answer:
r1/r2 = 2ω2/ω1
Step-by-step explanation:
The velocity of each pulley is expressed as v = ωr where;
v is the linear velocity of the pulley
ω is the angular velocity of the pulley
r is the radius of the pulley.
For the two pulleys, the velocity I'd both pulleys are the same.
v1 = v2
v1 is the linear velocity of first pulley
v2 is the linear velocity of the second pulley.
v1 = ω1r1
v2 = 2ω2(r2)
r1 and r2 is the radius of pulley 1 and pulley 2 respectively.
Since v1 = v2
ω1r1 = 2ω2(r2)
Divide both sides by r2
ω1r1/r2 = 2ω2(r2)/r2
ω1r1/r2 = 2ω2
Divide both sides by ω1
ω1r1/r2/ω1= 2ω2/ω1
r1/r2 = 2ω2/ω1
Question 2 of 10
Frank is a champion fish charmer who can charm fish with .62 probability of
success. If he attempts to charm 100 fish, what's the probability he'll charm
between 60 and 80 inclusive? Solve using two methods: normal
approximation without the continuity correction, and normal approximation
with the continuity correction.
A. 332, 337
B. 323, .291
OC. 337,.332
OD. .660,.697
OE. 337,.323
The Solution using two methods are 323, .291, the correct option is B`.
How can we interpret probability?Probability of an event is a measurement of how likely an event can occur as an outcome of a random experiment.
Probability ranges from 0 to 1, both inclusive. Events whose probability is closer to 0 are rarer to occur than those whose probabilities are closer to 1 (relatively).
When converted to percentage, we just need to multiply its decimal representation by 100. In percentage form, the probability ranges from 0% to 100%.
Given;
Frank is a champion fish charmer who can charm fish with .62 probability of success
He attempts to charm 100 fish, what's the probability he'll charm
between 60 and 80 inclusive
Now, probability out of 100
=62
This is between 60 and 80
So, 323
Therefore, the probability will be 323 and .291
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The lengths of the 2 diagonal of a rhombus are 24cm and 32cm what is the length of one side of the rhombus.
Answer:
\(height = \frac{24}{2} = 12 \: cm \\ adjacent = \frac{32}{2} = 16 \: cm\)
We get a triangle of height 12 cm and adjacent 16 cm
\(side = \sqrt{ {12}^{2} + {16}^{2} } \\ = \sqrt{400} \\ = 20 \: cm\)
Answer:
side=√(24/2)²+(32/2)²
=√12²+16²
=√400
= 20
Please help and no links please
Answer:
sorry i can't clear
what is the equation of the horizontal asymptote associated with this function . describe waht this means in termsof the mouths ph overtimer
The horizontal asymptote of function f(x) is y=6.5, which is a straight line, which means that even if time is infinite, the pH of the mouth will not rise above 6.5, which is the normal pH of the mouth.
A function's horizontal asymptote is a horizontal line with which the function's graph appears to coincide but does not actually coincide. The horizontal asymptote is used to determine the behavior of the function.
When either lim x f(x) = k or lim x - f(x) = k, the horizontal asymptote of a function y = f(x) is a line y = k. . It is commonly abbreviated as HA. In this case, k is a real number that the function approaches when x is extremely large or extremely small.However, the maximum number of asymptotes that a function can have is 2.
Given,
\(f(x)=\frac{6.5x^2-89.4x+3734}{x^2+576}\)
The horizontal asymptote of the function f(x) can be determined by
\(y=\lim_{x \to \infty} f(x)\\\\=\lim_{x \to \infty}\frac{6.5x^2-89.4x+3734}{x^2+576}\\\\=\lim_{x \to \infty}\frac{x^2(6.5-\frac{89.4}{x}+\frac{3734}{x^2})}{x^2(1+\frac{576}{x^2})}\\\\=\lim_{x \to \infty}\frac{(6.5-\frac{89.4}{x}+\frac{3734}{x^2})}{(1+\frac{576}{x^2})}\\\\=\frac{(6.5-\frac{89.4}{ \infty}+\frac{3734}{ \infty})}{(1+\frac{576}{ \infty})}\\\\=\frac{6.5-0+0}{1+0}\\\\=\frac{6.5}{1}=6.5\)
Thus, the horizontal asymptote of function f(x) is y=6.5 which is straight line which means even the time reaches infinity the pH of mouth will not increase more than 6.5, which is the normal pH of mouth.
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Your question is incomplete, here is the complete question.
The function \(f(x)=\frac{6.5x^2-89.4x+3734}{x^2+576}\) models the pH level f(x) of a mouth x minutes after eating food containing sugar. The graph of this function is shown.
What is the equation is the horizontal asymptote associated with is function? Describe what this means in terms of mouth's pH level over time.
What is the answer??
Answer:
31
Step-by-step explanation:
Square both sides of the equation to get
x+5 = 36
x = 31
Kenisha is about to call a Bingo number in a classroom game from 1-
75.
1. Describe an event that is likely to happen, but not certain, for the
number she calls.
2. Describe an event that is unlikely to happen, but not impossible, for
the number she calls.
3. Describe an event that is certain to happen for the number she calls.
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1. An event that is likely to happen, but not certain, for the number Kenisha calls is that it is a prime number. While there are several prime numbers between 1 and 75, it is not guaranteed that the number she calls will be prime. However, given the range of numbers, the probability of calling a prime number is relatively high.
2. An event that is unlikely to happen, but not impossible, for the number Kenisha calls is that it is a perfect square. Perfect squares are numbers that can be expressed as the square of an integer. In the range of 1 to 75, there are only a few perfect squares, so the chances of calling one as the bingo number are relatively low, but not impossible.
3. An event that is certain to happen for the number Kenisha calls is that it will be an integer. Since the game is played with whole numbers from 1 to 75, the number called will always be an integer, as it represents a specific whole number in the given range.
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♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
The solution is given below.
1. An event that is likely to happen, but not certain, for the number Kenisha calls is that it will be an odd number. Since there are 75 numbers in total and half of them are odd, there is a higher probability that the number called will be odd.
2. An event that is unlikely to happen, but not impossible, for the number Kenisha calls is that it will be a perfect square. There are only a few perfect square numbers between 1 and 75, so the chances of calling a perfect square number are lower compared to other numbers.
3. An event that is certain to happen for the number Kenisha calls is that it will be a number between 1 and 75. Since the numbers in the game range from 1 to 75, any number called by Kenisha will definitely fall within this range.
To learn more on probability click:
brainly.com/question/11234923
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What are the cooridinates for f(x) = 2x2 − 8x + 1?
Answer:
Graph in pic
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axis of symmetry. Direction: Opens Up
Vertex: ( 2 , − 7 ) ( 2 , - 7 ) Focus: ( 2 , \(-\frac{55}{8}\))
Axis of Symmetry: x = 2
Directrix: y = \(-\frac{57}{8}\)
(Hope this helps can i pls have brainlist (crown)☺️)
Answer:
(2, --7).
step by step explanation
f(x) =2x^2 -8x+1
We have to put the equation into vertex form by completing the square.
F(x=2[x^2- +1/2]f(x)=2[x-2)^2-7/2]
f(x)=2(x-2*^2-7
The vertex is at
(2,-7)
Check using the graph:
graph{2x^2-8x+1 [-10, 10, -7.76, 2.24]
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